Answer:
d = 52.20 miles
Explanation:
Given that,
Devon drove 50 miles west and then drove 15 miles north.
We need to find Devon's displacement. Let it is d. It can be calculated as follows :
[tex]d=\sqrt{50^2+15^2} \\\\=52.20\ \text{miles}[/tex]
Hence, Devon's displacement is 52.20 miles.
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questions
Cause and Effect Graphic Organizers
Describe how T-charts and Star Charts can be used to organize information into cause and effect relationships.
I
Answer:
A T-chart is used comparing two sides of a topic for example pros and cons or cause and effect. A star diagram is used for organizing the characteristics of a single topic, a central space is used for displaying the topic, with each point showing or listing an attribute about the topic.
An apple (mass = 0.25 kg) on a string 1 m in length is whirled above a student's head in a circle. The apple has a tangential speed of 12 m/s. What is the magnitude of the centripetal force on the apple?
Answer:
36N
Explanation:
Given parameters:
Mass of apple = 0.25kg
length of string = 1m
tangential speed = 12m/s
Unknown:
magnitude of centripetal force = ?
Solution:
The centripetal force keeps a body moving along a circular path.
It is mathematically derived using the expression below;
F = [tex]\frac{mv^{2} }{r}[/tex]
F is the centripetal force
m is the mass
v is the tangential speed
r is the radius
Now insert the parameters and solve;
F = [tex]\frac{0.25 x 12^{2} }{1}[/tex] = 36N
A jet aircraft is traveling at 219 m/s in horizontal flight. The engine takes in air at a rate of 77.9 kg/s and burns fuel at a rate of 4.19 kg/s. The exhaust gases are ejected at 934 m/s relative to the aircraft. Find the thrust of the jet engine. Answer in units of N. 019 (part 2 of 2) 10.0 points Find the delivered power. Answer in units of W
Answer: thrust [tex]-85905.24N[/tex]
delivered power [tex]= -18813247.56W[/tex]
Explanation:
given data:
horizontal speed = 219 m/s
rate of air intake = 77.9 kg/s
fuel combustion rate = 4.19 kg/s.
exhaust gases ejected = 934 m/s
solutuon:
Thrust of the engine
[tex]Fth = Ve * ( Mf - Ma ) - Vj *Ma[/tex]
[tex]= 934 * ( 4.19 - 77.9 ) - 219 *77.9[/tex]
[tex]= -68845.14 - 17060.1[/tex]
=[tex]-85905.24N[/tex]
delivered power
[tex]= Fth * Vj[/tex]
[tex]= -85905.24N * 219[/tex]
[tex]= -18813247.56W[/tex]
Given:
Horizontal speed = 219 m/sRate of air = 44.9 kg/sFuel combustion rate = 4.19 kg/sExhaust gas ejected = 934 m/sThrust of the engine will be:
→ [tex]F^{th} = Ve(Mf-Ms)-Vj\times Ma[/tex]
By putting the values, we get
[tex]= 934(4.19-77.9)-219\times 77.9[/tex]
[tex]= -68845.14-17060.1[/tex]
[tex]= -85905.24 \ N[/tex]
hence,
The delivered power will be:
= [tex]F^{th}\times Vj[/tex]
= [tex]-85905.24\times 219[/tex]
= [tex]-18813247.56 \ W[/tex]
Thus the solution above is right.
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On what does kinetic energy depend?
a. Mass and velocity b. Gravity and mass c. Gravity and height d.
Velocity and gravity
Answer:
b
Explanation:
Answer:
Gravity and Mass
Explanation:
Kinetic energy is the energy of something moving. To get a lot of kinetic energy, there has to be a situation where the gravity is moving in the way the object is moving. The heavier the object, the faster it'll move.
If you exert a force of 10.0 N to lift a box a distance of 0.75m, how much work do you do?
(4 Points)
0.075 J
7.5 J
10.75 J
75 J
Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m).
Work = Force × Distance.
W = 10 N × 0.75 m
W = 7.5 JA 15 N force is applied to a 12 kg box for 6 s. The box is initially at rest. What is the speed of the box at the end of the 6 s interval
Answer:
The speed of the box at the end of the 6 s interval is 7.5 m/s.
Explanation:
Given;
magnitude of the force, f = 15 N
mass of the box, m = 12 kg
initial velocity of the box, u = 0
time of the box motion, t = 6s
The applied force on the box is given by Newton's second law of motion;
f = ma
where;
a is the acceleration of the box
a = f / m
a = (15) / (12)
a = 1.25 m/s²
The final velocity of the box is calculated as;
v = u + at
v = 0 + (1.25 x 6)
v = 7.5 m/s.
Therefore, the speed of the box at the end of the 6 s interval is 7.5 m/s.
How has the magnet affected the block of material next to it?
A. The domains in the end of the block farthest from the magnet are aligned with its magnetic field.
B. The domains in the end of the block closest to the magnet are aligned with its magnetic field.
C. The domains in the center of the block are aligned with the magnetis magnetic field
D. The domains in the entire block are aligned with the magnets magnetic field
Answer: (APE X) B
Explanation: I am taking it and I just got it right
The magnetic characteristics of a substance are determined by the magnetic moments of its atoms, the domains which are closest to the magnet are aligned with its magnetic field, hence option b is correct.
What is the effect of a magnet?Long-range alignments of magnetic moments in ferromagnetic materials, known as domains, include magnetic moments that all point in the same direction.
This indicates that the atoms' individual magnetic moments are lined up with one another and pointing in the same general direction.
Therefore, a magnetic substance will get magnetized if it is placed close to a magnet. Magnetism is the name for this kind of electricity, hence option b is correct.
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what is the momentum of an object that is not moving?
Answer:
The momentum of any object that is at rest is 0. Objects at rest do not have momentum..
If The density of this stainless steel is7.85 g/cm3,specific heatis 0.5 J/g.K, melting pointis 1673K, heat of fusion s0.260J/kg. How much energy is required to re-melt this tube completely from room temperature
Answer:
[tex]\Delta H=687.4 J[/tex]
Explanation:
Hello!
In this case, for this melting process, we can identify two sub-processes in order to take the stainless steel from solid to liquid:
1. Heat up from 298.15 K to 1673 K.
2. Undergo the phase transition.
Both process have an associated enthalpy as shown below:
[tex]\Delta H_1=1g*0.5\frac{J}{g*K} (1673K-298.15K)=687.4J[/tex]
[tex]\Delta H_2=0.001kg*\frac{0.260J}{kg} =0.00026J[/tex]
Therefore, the required heat is:
[tex]\Delta H=\Delta H_1+\Delta H_2\\\\\Delta H=687.4J+0.00026J\\\\\Delta H=687.4J[/tex]
Notice the problem is not providing neither the mass or volume, that is why we assumed the mass is 1 g; however, it can be changed to the mass you are given.
Best regards!
Which change to an object would double its potential energy?
OA. Increasing its mass to four times its original value
O B. Reducing its mass to one-half of its original value
OC. Reducing its height to one-half of its original value
OD. Increasing its height to twice its original value
HELPPPPP!!! PLZ
Answer: The answer is D! Hope this helps!
Explanation:
Answer:
It’s D for ape.x
Explanation:because I’m smarttttttt
Roughly speaking, the radius of an atom is about 10,000 times greater than that of its nucleus. If an atom were magnified so that the radius of its nucleus became 2.0 cm, about the size of a marble, what would be the radius of the atom in miles
Answer:
0.124 miles
Explanation:
Since the radius of the atom R = 10000r where r = radius of nucleus. Now, if r = 2.0 cm = 0.02 m,
R = 10000r
= 10000 × 0.02 m
= 200 m
We know that 1 mile = 1609 m.
So the radius of the atom in miles is R = 200 m × 1 mile/ 1609 m = 0.124 miles
So, the radius of the atom in miles is 0.124 miles
An object in space has altitude of 2210 km, velocity of 7000 m/s and flight path angle of 20 degrees. Find the eccentricity, semi-major axis, angular momentum/mass, and kinetic and potential energies/mass
Answer:
Eccentricity = 0.0557
Semi-major axis = 9,095 km
Angular momentum/mass = 60,116 [tex]\frac{km^{2} }{Sec}[/tex]
Kinetic energies/mass = 24,500 KJ
Potential energies/mass = 21,673 KJ
Explanation:
Eccentricity
To find the eccentricity use the following formula
Eccentricity = [ Altitude from the earth x ( [tex]Velocity^{2}[/tex] / Gravitational parameter for the Earth ) ] - 1
Where
Altitude from the earth radius = Radius of the earth + Altitude of the earth from radius = 6,378 km + 2,210 km = 8,588 km
Velocity = 7,000 m/s
Gravitational parameter for the Earth = 3.986004418 × [tex]10^{14}[/tex]
Eccentricity = ?
Placing values in the formula
Eccentricity = [ ( 8,588 km x 1000 ) x ( [tex]7000^{2}[/tex] / 3.986004418 × [tex]10^{14}[/tex] ) ] - 1
Eccentricity = 0.0557
Semi-major axis
Total Distance = Semi-major axis x ( 1 - Eccentricity )
Where
Total Distance = 8,588 km
Eccentricity = 0.0557
8,588 x 1,000 m = Semi-major axis x ( 1 - 0.0557 )
8,588,000 m = Semi-major axis x 0.9443
Semi-major axis = 8,588,000 m / 0.9443
Semi-major axis = 9,094,567.40 m
Semi-major axis = 9,094.56740 km
Semi-major axis = 9,095 km
Angular momentum/mass
L = MVR
L/M = VR
Where
V = Velocity = [tex]\frac{7,000 m/s}{1000}[/tex] = 7 km/s
R = Total Radius = Radius of Earth + Altitude = 6,378 km + 2,210 km = 8,588 km
Placing values in the formula
L/M = 7 km/s x 8,588 km = 60,116 [tex]\frac{km^{2} }{Sec}[/tex]
Kinetic energies/mass
Ke = I [tex]W^{2}[/tex]
Ke = [tex]\frac{1}{2} mr^{2}[/tex] [tex]W^{2}[/tex] ( Where I = [tex]mr^{2}[/tex] )
[tex]\frac{ke}{m}[/tex] = [tex]\frac{r^2}{2}[/tex] [tex]W^{2}[/tex]
[tex]\frac{ke}{m}[/tex] = [tex]\frac{r^2}{2}[/tex] [tex]\frac{V^2}{r^2}[/tex] ( [tex]W^{2}[/tex] = [tex]\frac{V^2}{r^2}[/tex] )
[tex]\frac{ke}{m}[/tex] = [tex]\frac{V^2}{2}[/tex]
[tex]\frac{ke}{m}[/tex] = [tex]\frac{7000^2}{2}[/tex]
[tex]\frac{ke}{m}[/tex] = 24,500,000 J
[tex]\frac{ke}{m}[/tex] = 24,500 KJ
Potential energies/mass
PE = mgh
[tex]\frac{PE}{m}[/tex] = gh
Where
g = 9.807 [tex]\frac{m}{s^2}[/tex]
h = 2,210 km x 1,000 = 2,210,000 m
Placing values in the formula
[tex]\frac{PE}{m}[/tex] = 9.807 [tex]\frac{m}{s^2}[/tex] x 2,210,000 m
[tex]\frac{PE}{m}[/tex] = 21,673,470 J
[tex]\frac{PE}{m}[/tex] = 21,673.470 KJ
[tex]\frac{PE}{m}[/tex] = 21,673 KJ
hello what is a major theme of this speech?
please write the definition of instantaneous speed, velocity and acceleration and solve problems on them please show workings
Answer:
instantaneous speed: The instantaneous speed is the speed of an object at a particular moment in time. And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time.
velocity: the speed of something in a given direction.
acceleration: a vehicle's capacity to gain speed within a short time.
solve problems: Problem solving consists of using generic or ad hoc methods in an orderly manner to find solutions to problems.
Explanation:
A fire truck emits an 880Hz siren. As the truck approaches an observer on the sidewalk, he perceives the pitch to be 950Hz. Approximately what pitch does he hear after the truck passes and is moving away?
Answer:
The pitch that he hears after the truck passes and is moving away is 819.6 Hz.
Explanation:
The pitch that he hears after the truck passes and is moving away can be calculated using the following equation:
[tex] f = f_{0}*\frac{v_{s} \pm v_{o}}{v_{s} \pm v_{f}} [/tex]
Where:
[tex]f[/tex]: is the perceived frequency
[tex]f_{0}[/tex]: is the emitted frequency
[tex]v_{s}[/tex]: is the speed of sound = 340 m/s
[tex]v_{o}[/tex]: is the speed of the observer = 0 (he is not moving)
[tex]v_{f}[/tex]: is the speed of the fire truck
First, we need to find the speed of the fire truck. When it approaches the observer we have:
[tex] f = f_{0}*\frac{v_{s} + v_{o}}{v_{s} - v_{f}} [/tex]
[tex] 950 Hz = 880 Hz*\frac{340 m/s}{340 m/s - v_{f}} [/tex]
[tex] v_{f} = 340 m/s - \frac{880 Hz*340 m/s}{950 Hz} [/tex]
[tex] v_{f} = 25.05 m/s [/tex]
Hence, the speed of the fire truck is 25.05 m/s.
Now, we can calculate the pitch that the observer hears after the truck passes:
[tex] f = f_{0}*\frac{v_{s} - v_{o}}{v_{s} + v_{f}} [/tex]
[tex] f = 880 Hz*\frac{340 m/s}{340 m/s + 25.05 m/s} [/tex]
[tex] f = 819.6 Hz [/tex]
Therefore, the pitch that he hears after the truck passes and is moving away is 819.6 Hz.
I hope it helps you!
Which has a stronger force binding the nucleus together Hydrogen and Helium
Answer:
Explanation:
Nucleus
Which electromagnetic waves have the shortest wavelength and the highest frequency?
i tried gamma and it said it was inncorect plz help
pls tell the answer
Just flip one of the batteries to connect one's positive terminal to others negative terminal.
come in my free candy van located at Skellerupvej 43, 8600 Silkeborg, Denmark
Answer:
Did you think you could pull that off-
:I
I live in Japan anyway so.. ウーフ-
A mixture contains salt, sand, pebbles, and grass. Which part of this mixture is soluble in water?
Grass
Pebbles
Salt
Sand
Answer:
hey!
the answer is
salt
Explanation:
this is due to sand, grass and pebbles are not soluble (they do not dissolve in water)
pls put brainliest
How is the pressure of a gas related to its concentration of particles?
Answer:
Explanation:
Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.
Increasing the pressure of a gas is exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume. If you have the same mass in a smaller volume, then its concentration is higher.
Which of the following is a definition of motion?
Answer:
sorry I don't get it so pls can u repeat the question .
Movement of any object from one position to another position with respect to the observer is called as Motion. Motion Along a Straight Line: When an object moves along a straight line, the motion of the object is called rectilinear motion. For example; motion of a car on highway.
QUESTION:
Which of the following is a definition of motion?
ANSWER:
In physics, motion is the phenomenon in which an object changes its position over time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time.
Why dose a hot air balloon float
i need answers
100 points help me nowwww
Answer:
it is c trust me im smart
a rock falls for 4 seconds. How far did it fall
Answer:
d = 80 m
Explanation:
It is given that,
A rock falls for 4 seconds.
We need to find how far did it fall.
let it cover d distance.
Using equation of motion to find it :
[tex]d=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0 (at rest initially)
a = g
[tex]d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 10\times 4^2\\\\d=80\ m[/tex]
It will fall at a distance of 80 m.
The gravity on Earth is 9.8m/s2, the mass of a bowling ball is about 5kg. What is the weight of the bowling ball on the Earth?
Answer:
yo can someone answer i need this
Explanation:
1) A rock is thrown downward from the top of a 40.0-m-tall tower with an initial speed of 12 m/s. Assuming
negligible air resistance, what is the speed of the rock just before hitting the ground?
Answer:
By using [tex]v^{2}_{f} = v^{2}_{i} + 2a\Delta y[/tex], with [tex]v_{i} = -12m/s[/tex] and [tex]\Delta y = -40m[/tex]:
[tex]v^{2}_{f} = v^{2}_{i} + 2a/Delta y[/tex]
[tex]v^{2} = (-12m/s)^{2} + 2(-9.80m/s^{2})(-40m)[/tex]
[tex]v = -30m/s[/tex]
Explanation:
Hope this helped!
A rock is thrown downward from the top of a 40 m tall tower, with The speed of the rock just before hitting the ground will be equal to -30 m/s.
What is Friction?Friction is the resistance to a thing moving or rolling over another solid object. Although frictional forces can be advantageous, such as the traction required to walk while slipping, they also provide a significant amount of resistance to motion. In order to overcome frictional resistance in the moving parts, about 20% of an automobile's engine power is used.
The forces of attraction, also referred to as adhesion, between the contact zones of the surface, which are always minutely uneven, seem to be the main contributor to friction between metals.
From the given information in the question,
v²(f) = v²(i) + 2aΔy
v² = (-12 m/s)² + 2(-9.8)(-40)
v = -30 m/s.
Therefore, the velocity of the rock is -30 m/s.
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What is the speed of a car that traveled 56 m in 4 seconds?
Answer:
[tex]\boxed {\boxed {\sf 14 \ meters \ per \ second}}[/tex]
Explanation:
Speed is the rate of motion and can be found by dividing the distance by the time.
[tex]s=\frac{d}{t}[/tex]
The distance covered is 56 meters and the time taken is 4 seconds.
[tex]d= 56 \ m \\t= 4 \ s[/tex]
Substitute the values into the formula.
[tex]s=\frac{56 \ m}{4 \ s}[/tex]
Divide.
[tex]s= 14 \ m/s[/tex]
The speed of the car is 14 meters per second
_________________ Is how far an object has moved.
(5 Points)
Distance
Displacement
Velocity
Rate
Answer:
Distance Is how far an object has moved.
The maker of an automobile advertises that it takes 13 seconds to accelerate from 5 kilometers per hour to 65 kilometers per hour. Assuming constant acceleration, compute the acceleration in meters per second per second. Round your answer to three decimal places.
Answer: the acceleration is 1.282 m/s²
Explanation:
Given that;
Time t = 13 sec
Initial velocity U = 5 kmph = (5 × 1000)/(60 × 60) = 1.3888 m/s
final velocity V = 65 kmph = (65 × 1000)/(60 × 60) = 18.0555 m/s
Now we know that;
V = U + at
we substitute
18.0555 = 1.3888 + 13a
18.0555 - 1.3888 = 13a
13a = 16.6667
a = 16.6667 / 13
a = 1.282 m/s²
Therefore the acceleration is 1.282 m/s²