1. If 5x + 6 = 10, what is the value of 10x + 3?

Answers

Answer 1
Here the question is simple.
All because, we only need to find the value of x.
We are given two equations.
5x + 6 = 10 and 10x + 3 =?
So, we will find the the value of x in the first equation, so that we can substitute the value of x in the second one and there we are with the answer.
5x + 6 = 10
For finding the value of x, all we have to do is,
Transpose the number 6 to 10
Therefore. 5x = 10 - 6 ( Take the equal sign as The Magic Bridge on which if anyone crosses it , will change its sign.)
So we have,
5x = 4
So x = 4/5 ( Multiplication will change to division after crossing the equal sign)
( Doubtful? Substitute the value of x and try!)
Now that we got the value of x,
We can just simply substitute the value of x in the second equation.
10x + 3 = ?
x = 4/5
10*4/5 +3 => 5 and 10 get canceled to 2 at the numerator.
By normal multiplication and then addition, we will get,
8 + 3 = 11
Hope this helps!!!! :)
Answer 2

Answer:

11

Step-by-step explanation:

5x+6=10

-6 -6

5x=4

-------

5 5

x=4/5

10(4/5)+3

8+3=11


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Answers

Answer:

Her error was that the half should have been multiplied by m, instead

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Step-by-step explanation:

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C - The One-half should be multiplied by m.

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Step-by-step explanation:

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Step-by-step explanation:

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he gets 104$

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Step-by-step explanation:

Times means multiple so 26 x 4 and that equals 104. $104 dollars would be your answer.

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Step-by-step explanation:

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Hope this helps you out :)

2 in.
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5 in.
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Answers

Answer:

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Answer:

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[tex]X\begin{bmatrix}1&-1&2\\3&0&1\end{bmatrix}=\begin{bmatrix}-5&-1&0\\5&-2&5\end{bmatrix}[/tex]

[tex]X\begin{bmatrix}1&-1&2\\3&0&1\end{bmatrix}\begin{bmatrix}1&-1&2\\3&0&1\end{bmatrix}^\top=\begin{bmatrix}-5&-1&0\\5&-2&5\end{bmatrix}\begin{bmatrix}1&-1&2\\3&0&1\end{bmatrix}^\top[/tex]

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[tex]\begin{bmatrix}1&-1&2\\3&0&1\end{bmatrix}^\top=\begin{bmatrix}1&3\\-1&0\\2&1\end{bmatrix}[/tex]

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[tex]X\begin{bmatrix}6&5\\5&10\end{bmatrix}\begin{bmatrix}6&5\\5&10\end{bmatrix}^{-1}=\begin{bmatrix}-4&-15\\17&20\end{bmatrix}\begin{bmatrix}6&5\\5&10\end{bmatrix}^{-1}[/tex]

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[tex]\begin{bmatrix}6&5\\5&10\end{bmatrix}^{-1}=\frac1{60-25}\begin{bmatrix}10&-5\\-5&6\end{bmatrix}=\begin{bmatrix}2/7&-1/7\\-1/7&6/35\end{bmatrix}[/tex]

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Answers

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Step-by-step explanation:

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Answers

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Answers

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Answers

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