100 POINTS IF YOU ANSWER THIS QUESTION


Match each front with its description. cold front when two cold fronts force a warm front up and block it from the surface warm front when a cold air mass and a warm air mass meet and do not move stationary front when a warm air mass slides over a cold air mass occluded front when a cold air mass slides under a warm air mass​

Answer:

080777056656:5 c

Answer:

a ,c ,b

esa son creo pero nose

The actual dimensions of the rectangular park are 500 cm by 600 cm and actual area of the park is 300,000 ft²

A scale is a set of levels or numbers which are used in a particular system of measuring things or are used when comparing things.

Given that, Blake drew a scale drawing of a rectangle shaped park and used a scale of 1 cm: 20 ft

We need to find the actual width if the width on the scale drawing of the city park is 25 cm, and actual area if the width on the scale drawing of the city park is 25 cm and the length is 30 cm,

a) The given measurement of width in the drawing is 25 cm,

We have,

1 cm = 20 ft

∴ 25 cm = 20 × 25

= 500 ft

b) The given measurement of the width on the scale drawing of the city park is 25 cm and the length is 30 cm,

Actual width = 500 ft

Actual length = 20 × 30 = 600 ft

Area of rectangle = length × width

Actual area = 500 × 600

= 300,000

Hence, the actual dimensions of the rectangular park are 500 cm by 600 cm and actual area of the park is 300,000 ft²

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Answer:

y[tex]\leq[/tex][tex]\frac{1}{2}[/tex]x-2

it is less than because it is shaded down, its less than or equal to because the line is solid.

Answer:

2y < - x - 4

Step-by-step explanation:

First find the equation of the line in the form y=mx+c (straight line)

The y-intercept is at -2 so c=-2.

For each 2 along the x-axis it goes 1 down the y-axis, so the gradient is -1/2, so m = -1/2

We now have y = -(1/2) x - 2

Try a coordinate, e.g. (0,0) one side of that line:

-(1/2) 0 - 2 = -2

-2 is less than 0, but we don't want (0,0) in the region, so we say

y < -(1/2)x - 2 or

2y < - x - 4

Answer:

Step-by-step explanation:

Given expression:

Simplify:

The answer choices:

Answer:

a)

Class width = 19.375

b)

Class Boundaries are;

19.5 - 39.5, 39.5 - 59.5, 59.5 - 79.5, 79.5 - 99.5, 99.5 - 119.5, 119.5 - 139.5, 139.5 - 159.5, 159.5 - 179.5.

Step-by-step explanation:

Given the data in the question;

Class width = Range / Number of classes

Range = maximum - minimum = 175 - 20 = 155

Number of classes = 8

so,

Class width = 155 / 8 = 19.375

∴ the class limits will be

20   - 39

40   - 59

60   - 79

80   - 99

100  - 119

120  - 139

140  - 159

160  - 179

Low class boundary = Lower class limit - 0.5

Upper class boundary = upper class limit + 0.5

so

Class Boundaries are;

19.5 - 39.5, 39.5 - 59.5, 59.5 - 79.5, 79.5 - 99.5, 99.5 - 119.5, 119.5 - 139.5, 139.5 - 159.5, 159.5 - 179.5.

3(3y-12)=0 divide both sides by 3

3y-12=0 add 12 to both sides

3y=12 divide both sides by 3

y=4

divide 72 in the ratio of 4: 5

= 16

8 quarters equal 2 dollars 11 dimes is a dollar and 10 cents so 3 dollars and 10 cents

Answer:

Step-by-step explanation:

If congruent the sides are equal

15x-9=7x+11

8x=20

x=20/8=2.5

Answer:

800 students failed

Step-by-step explanation:

Since 60% passed the class, 40% failed

This means that 40% of the 2,000 students are failures

[tex]\frac{40}{100} (2,000)= 800[/tex]

Answer:

27, 90 and 63

Step-by-step explanation:

Given

Ratio of triangle sides

[tex]Ratio = 3 : 10 : 7[/tex]

Required:

The length of each side

Triangles in a triangle add up to 180.

The side with ratio 3 is:

[tex]S_1 = \frac{3}{3 + 10 + 7} *180[/tex]

[tex]S_1 = \frac{3 *180}{20}[/tex]

[tex]S_1 = \frac{540}{20}[/tex]

[tex]S_1 = 27[/tex]

The side with ratio 10 is:

[tex]S_2 = \frac{10}{3 + 10 + 7} *180[/tex]

[tex]S_2 = \frac{10 *180}{20}[/tex]

[tex]S_2 = \frac{1800}{20}[/tex]

[tex]S_2 = 90[/tex]

Lastly:

The side with 7 as its ratio

[tex]S_3 = \frac{7}{3 + 10 + 7} *180[/tex]

[tex]S_3 = \frac{7 *180}{20}[/tex]

[tex]S_3 = \frac{1260}{20}[/tex]

[tex]S_3 = 63[/tex]

Hence, the angles are: 27, 90 and 63

9514 1404 393

Answer:

  cot(θ) = 24/7

Step-by-step explanation:

A suitable calculator can answer this nicely.

__

Perhaps you're expected to remember relevant trig identities.

  tan(θ)^2 = sec(θ)^2 -1

  cot(θ) = 1/tan(θ)

__

  cot(θ) = 1/√(sec(θ)^2 -1)

  cot(θ) = 1/√((25/24)^2 -1) = 24/√(25^2 -24^2) = 24/√49

  cot(θ) = 24/7

5% or 5percent can be thought of 5 per 100.

5 per 100 or 5 out of 100 can be written as 5/100 or 1/20.

An hour have 60 minutes and 1/20 of an hour is 60*1/20=3 minutes.

Therefore Sara can work 3 minutes every hour.

1. He collected 5 gallons of water.

2. We find this out by knowing 5 = 5.

Hope it helps! Good luck! :D

Step-by-step explanation:

(x, y) is a solution to y = 5/2X

(x, y) is a solution to y=x+3.

The ratio of Y/X is equivalent to 5/2

Point (x, y) is the same point as (5, 2).

A straight line through points (2, 5) and (x, y) will pass through the origin.

____________________________

 - We do this to make the problem easier to simplify. When expanded you can easily figure out what you need to find to make it a simplified equation.

 - We do this because it's the only thing we can find, that would make this a simplified problem.

So your answer is [tex]\bold{9x^2-3}[/tex].

____________________________

Answer:

Options C. -5/a

x =1/a is the solution for the given equation. Option D is correct.

Any mathematical statement that includes numbers, variables, and an arithmetic operation between them is known as an expression or algebraic expression. In the phrase 4m + 5, for instance, the terms 4m and 5 are separated from the variable m by the arithmetic sign +.

Let's simplify the equation first:

10 = 2 - 4(ax - 3)

10 = 2 - 4ax + 12 (distribute the negative 4)

10 = -4ax + 14 (combine like terms)

Now we can isolate the variable x by subtracting 14 from both sides and then dividing by -4:

10 - 14 = -4ax

-4 = -4ax

x = 1/a

Therefore, the solution to the equation is x = 1/a.

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Answer:

I dont know if you still need it but the area of the figure is 51.5 ft2.

The area of the given figure is equivalent to 39.5 square feet.

Area is a collection of two - dimensional points enclosed by a single dimensional line. Mathematically, we can write -

V = ∫∫F(x, y) dx dy

Given is to find the area of the given figure as shown in the image.

We can write the area of the given figure as -

A{total} = A{Rectangle} + A{Δ1} + A{Δ2}

A{total} = (8 x 4) + (1/2 x 3 x 3) + (1/2 x 3 x 2)

A{total} = 32 + 4.5 + 3

A{total} = 39.5 square feet

Therefore, the area of the given figure is equivalent to 39.5 square feet.

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Answer:

[tex]2.41351201 *10^2[/tex]

Step-by-step explanation:

hope this helps have a good rest of your day :) ❤

Answer:

The total change is £21.02 from the original amount of £78.98. Therefore, the percentage change is directly related to the original amount.

Divide the total change by the original amount to determine the percentage change the new amount represents.

21.02÷78.98=0.15219 which rounds up to two decimal places as 15.22%.

Answer:

50%.

Step-by-step explanation:

Given that a math class contains 40 students, and there are 18 females (two of whom speak Spanish) and 22 males (two of whom speak Spanish), in order to know the percent of Spanish speaking students that are male with respect to the total Spanish-speaking students, the following calculation has to be made:

2 + 2 = 4

2 / 4 = 0.5

Therefore, the percentage of Spanish speaking students that are male is 50%.

Answer:

AC=13.6

Step-by-step explanation:

let the triangle is ABC

radius =6  , diameter =6*2=12

therefore AB=12

since BC is a tangent

therefore angle B =90 degrees

BC=6.4

[tex]\sqrt (AB)^2+(BC)^2 =AC[/tex]

AC=13.6

Answer:

y = 84/5 or 16 4/5

Step-by-step explanation:

12/5 = y/7

cross-multiply to get 5y = 84

y = 84/5

Answer:

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8.

This means that [tex]\mu = 3, \sigma = 0.8[/tex]

What proportion of the population used to develop the test has scores below 1.7?

This is the pvalue of Z when X = 1.7. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1.7 - 3}{0.8}[/tex]

[tex]Z = -1.63[/tex]

[tex]Z = -1.63[/tex] has a pvalue of 0.063

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

Between 1.7 and 2.1?

This is the pvalue of Z when X = 2.1 subtracted by the pvalue of Z when X = 1.7.

X = 2.1

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2.1 - 3}{0.8}[/tex]

[tex]Z = -1.13[/tex]

[tex]Z = -1.13[/tex] has a pvalue of 0.1292

X = 1.7

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{1.7 - 3}{0.8}[/tex]

[tex]Z = -1.63[/tex]

[tex]Z = -1.63[/tex] has a pvalue of 0.063

0.1292 - 0.063 = 0.0662

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

Answer:

The distance between the pole and point A is 35.2m

Step-by-step explanation:

First, we have to illustrate the problem. I can't draw as of the moment but I'll try my best to describe the drawing as best as I can. You can draw this in a scratch paper to have a better understanding.

Now that you have drawn this. There should be two triangles formed now namely triangle DCB and DAB.

TRIANGLE DCB

By Pythagorean Theorem, we can write an equation for the height of the pole.

[tex]h^{2} = {53}^{2} - {x}^{2} [/tex]

TRIANGLE DAB

By Pythagorean Theorem, we can write an equation for the height of the pole.

[tex] {h}^{2} = {85}^{2} - {(40 + x)}^{2} [/tex]

Since we only have one pole, this means that we can equate the two equations.

[tex] {53}^{2} - {x}^{2} = {85}^{2} - {(40 + x)}^{2} \\ {53}^{2} - {85}^{2} = {x}^{2} - ( {x}^{2} + 80x + 1600) \\ - 4416 = - 80x - 1600 \\ 80x = 4416 - 1600 \\ 80x = 2816 \\ x = \frac{2816}{80} \\ x = 35.2[/tex]

Answer:

x^2 = 49

Step-by-step explanation:

Notice that the polynomial on the left of the equation can be factored out as:

x^2 - 2 x - 35 = (x - 7) (x + 5)

Then the equation:   x^2 - 2 x - 35 = = 0

gives two solutions as follows:

(x - 7) (x + 5) = 0 Then either binomial factor must be zero, and therefore, x = 7 or x = -5

Since we are told that x is POSITIVE, the x = 7, and its square is 7^2 = 49.

Answer:

[tex]\frac{v - u}{a} = t[/tex]

Step-by-step explanation:

Given

[tex]v = u + at[/tex]

Required

Solve for t

[tex]v = u + at[/tex]

Subtract u from both sides

[tex]v - u = u - u + at[/tex]

[tex]v - u = at[/tex]

Divide both sides by 1

[tex]\frac{v - u}{a} = \frac{at}{a}[/tex]

[tex]\frac{v - u}{a} = t[/tex]

[tex]t = \frac{v - u}{a}[/tex]

Step-by-step explanation:

step 1. f(4) = 3(4) + K = 7 (plug in values)

step 2. K = -5 (subtract 12 from each side)

step 3. therefore f(x) = 3x - 5

step 4. f(2) = 3(2) - 5 = 1 (plug in x= 2)

Answer:

The population is:

D. All shoppers at the discount store during a year's time.

Step-by-step explanation:

Since the discount store wants to determine the average yearly income of its shoppers, the population of interest here is all the shoppers that visit the discount store during a year's time.  The population includes all the individual shoppers.  However, this number may be too difficult to obtain and work on their data.  This is the researcher can choose a sample, calculating its statistics to approximate the population parameters.