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Kam Scheela MARIO MARTINEZ-HTPhysics.pdf
Test BGK
HW#10
Question: A pinball machine's plunger has a spring constant of 22
N/m and is compressed by 0.04 m to start a 0.006 kg pinball.
1. What is the elastic potential energy before the ball is released?
2. What is the kinetic energy of the pinball the instant it leaves the
spring?
3. What is the speed of the pinball the instant it leaves the spring?
4. If the pinball is moving at 1.3 m/s as it is deflected horizontally
across the top of the pinball machine, how much higher above the
ground is this part of its path when compared to its starting
position?
Squation
Drawing
Ta
Signature
Instructions.
Answers
Answer:
1. The elastic potential energy is 0.0176 Joules
2. The kinetic energy of the pinball the instant it leaves the spring is 0.0176 Joules
3. The speed of the pinball the instant it leaves the spring is approximately 2.42212 m/s
4. The height of the part where the pinball is located on the machine above the ground is approximately 0.213 meters
Explanation:
The spring constant of the pinball machine's plunger, k = 22 N/m
The amount by which the pinball machine's plunger is compressed, x = 0.04 m
The mass of the pinball ball, m = 0.006 kg
1. The elastic potential energy, P.E. = 1/2·k·x²
By substitution, we get;
P.E. = 1/2 × 22 N/m × (0.04 m)² = 0.0176 J
The elastic potential energy, P.E. = 0.0176 J
2. At the instant the pinball leaves the spring, the plunger and therefore the force of the plunger no longer acts on the pinball
Since there are no external forces acting on the pinball to increase the speed of the pinball after it leaves the spring, the velocity reached is its maximum velocity, and therefore, the kinetic energy, K.E. is the maximum kinetic energy which by the conservation of energy, is equal to the initial potential energy
Therefore;
K.E. = P.E. = 0.0176 J
The kinetic energy of the pinball the instant it leaves the spring, K.E.= 0.0176 J
3. The kinetic energy, K.E., is given by the following formula;
K.E. = 1/2·m·v²
Where;
v = The speed or velocity of the object having kinetic energy K.E.
Therefore, from K.E. = 0.0176 J, and by plugging in the values of the variables, we have;
K.E. = 0.0176 J = 1/2 × 0.006 kg × v²
v² = 0.0176 J/(1/2 × 0.006 kg) = 88/15 m²/s²
v = √(88/15 m²/s²) ≈ (2·√330)/15 m/s ≈ 2.42212 m/s
The speed of the pinball the instant it leaves the spring, v ≈ 2.42212 m/s
4. The height of the pinball is given by the following kinematic equation of motion;
[tex]v_h[/tex]² = u² - 2·g·h
Where;
[tex]v_h[/tex] = The velocity of the pinball at the given height = 1.3 m/s
u = v ≈ 2.42212 m/s (The initial velocity of the pinball as it the spring)
g = The acceleration due to gravity ≈ 9.8 m/s²
h = The height of the pinball above the ground
We get;
[tex]v_h[/tex]² = 1.3² = 2.42212² - 2 × 9.8 × h
∴ h = (2.42212² - 1.3²)/(2 × 9.8) ≈ 0.213
The height of the part where the pinball is located on the machine above the ground, h ≈ 0.213 m
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A sharpening wheel is traveling at 5 rad/s, it slows down to rest in 30 seconds while sharpening an axe. What is its angular acceleration?
Answers
Answer:
Angular acceleration [tex]= 0.167[/tex] rad/s^2
Explanation:
Given
Initial Angular velocity (w1) [tex]= 5[/tex] rad/s
Final Angular velocity (w2) [tex]= 0[/tex] rad/s
Time taken to change velocity from w1 to w2 [tex]= 30[/tex] seconds
Angular acceleration is equal to the change in angular velocity to the time taken for making thing change
Hence, Angular acceleration
[tex]\frac{w_2 -w_1}{t} \\\frac{5-0}{30}\\0.167[/tex]rad/s^2
PLEASE HELP! WILL MARK BRAINLIEST!
Two kids are roller skating. Amy, with a mass of 55 kg, is traveling forward at 3 m/s. Jenny, who has a mass of 40 kg, is traveling in the opposite direction at 5 m/s. They crash into each other and hold onto each other so that they move as one mass. How fast are they traveling? How would you find your answer?
Answers
Answer:
They traveling at along the direction of 55 kg kid.
Step-by-step explanation:
Conservation of momentum-
Momentum of a system is constant if there are no external forces acting on the system.
As they crash into each other and hold onto each other so that they move as one mass and no other force is acting on them, so conservation of momentum can be applied here.
The final direction of velocity will be opposite to the assumed direction of the mass of 40 kg.
This is a conservation of momentum problem. The equation relevant here is
[tex]\[m_1v_1+m_2v_2=\left ( m_1+m_2 \right )v_f\][/tex]
where m is the mass and v is the velocity. Because Amy and Jenny move as one mass after crashing (or colliding) with each other, this is an inelastic collision. What we to find is the final velocity, [tex]v_f[/tex], of both Amy and Jenny as a single body.
[tex]v_f=\frac{m_1v_1+m_2v_2}{\left ( m_1+m_2 \right )} = \frac{(55)(3)+(40)(5)}{(55+40)} = \text{3.84 m/s}.[/tex]
As a cold air mass advances on a warm air mass, what usually comes before it?
Answers
Answer: A cold front occurs when a cold air mass advances into a region occupied by a warm air mass. If the boundary between the cold and warm air masses doesn't move, it is called a stationary front.
Explanation: Two types of occluded front exist: the warm-type and the cold-type. They’re distinguished by the relative temperatures of the air mass ahead of the occlusion – in other words, the air mass ahead of the original warm front – and the air mass behind the cold front. If the air behind the cold front is colder than the air ahead of the occlusion, it shoves beneath that air (because it’s denser) to form a cold-type occluded front. If the air behind the cold front is warmer than the air ahead, it rides over it to form a warm-type occluded front – which appears to be the more common case. In either situation, the lighter warm air representing the air mass originally between the warm and cold fronts sits above the boundary between the two cooler air masses.
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Question 4 (1 point)
How far does a sound wave travel in 3 seconds if the air temperature is 30 degrees
Celsius?
a) 114.33 m
b) 1047 m
c) 1029 m
d) 116.33 m
Answers
Answer:
B
Explanation:
v=349m/s
d=vt
d=349*3
d=1047m
WHY 349??
Because, velocity of sound increases about 0.6 m/s for every 1 degree celsius rise in temp.
Velocity of sound is about 343 m/s at 20 degrees C, so 0.6*10=6 more m/s, or 349 m/s. Kinda cool how temperature alters the speed of sound!
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Ob) vision
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Od) all of the above
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Answer:
D
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Answer:
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F = ma
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It can be clear from the above formula that the acceleration and the force are directly proportional to each other.
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Answer:
Step-by-step Explanation:
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Answer:
c.
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Answer
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Answer:
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A. Each nucleus formed has fewer protons than the original nucleus
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B. Nuclei with small masses combine to form nuclei with larger
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Answer:
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Features of Elements
Use the periodic table on the next page to complete the following
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Element and Chemicol Atomic Mass
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of
of
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isotope
number
Symbol.
number
notation
profons neutrons
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Answer:
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Answer:
V=3.57 × 10^6 m/s
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The speed of the proton in the magnetic field is 3.57×10⁶ m/s.
To determine the speed of the proton, we need to know about the magnetic force experienced by a charged particle in a magnetic field.
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Here, B= 4.20×10⁻²TF=2.40×10⁻¹⁴N
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Answers
Answer:
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Given that,
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We need to find the mass of the body. The formula for the kinetic energy of a body is given by :
[tex]K=\dfrac{1}{2}mv^2\\\\m=\dfrac{2K}{v^2}\\\\m=\dfrac{2\times 1000}{(10)^2}\\\\m=20\ kg[/tex]
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Explanation:
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Answer:
yes it does
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URGENT PLEASE HELP!!!! GIVING BRAINLIEST!! If you answer this correctly ill answer some of your questions you have posted! (30pts)
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Answer:
5
Explanation:
From the attachement,
M.A = Load(L)/Effort(E)
M.A = L/E...................... Equation 1
Where M.A = .Mechanical Advantage, L = Load, E = Effort.
Given: L = 500 N, E = 100 N
Substitute these values into equation 1
M.A = 500/100
M.A = 5.
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