12.48 + (-10.636)
1.814
As a decimal

Answer:

1360.78 mg

Step-by-step explanation:

3 pounds in grams is 1360.78 grams.

so, 1 mg per gram would mean the baby should recieve 1360.78 mg of the drug.

Answer:

743.1

Step-by-step explanation:

675.58 • 1.10 = 743.138

743.138 rounded to the nearest tenth is 743.1.

Step-by-step explanation:

multiply all the fractions together in your calculator :)

Answer:

secondary

Step-by-step explanation:

Answer:

[tex]m = 1.5\%[/tex]

Step-by-step explanation:

Given

The attached table

Required

Determine his percentage commission

To do this, we need to calculate the slope (m) of the table as follows:

[tex]m = \frac{P_2 - P_1}{x_2 - x_1}[/tex]

Where

[tex](x_1,P_1) = (7000,165)[/tex]

[tex](x_2,P_2) = (7500,172.5)[/tex]

[tex]m = \frac{P_2 - P_1}{x_2 - x_1}[/tex] becomes

[tex]m = \frac{172.5 - 165}{7500- 7000}[/tex]

[tex]m = \frac{7.5}{500}[/tex]

[tex]m = 0.015[/tex]

Convert to percentage

[tex]m = 0.015 * 100\%[/tex]

[tex]m = 1.5\%[/tex]

Hence, his percentage commission is 1.5%

Answer: 19

Step-by-step explanation:

Answer:

1, 2, and 4

Step-by-step explanation:

Answer:

0.057

0.6140

0.3158

0.0701

Step-by-step explanation:

Given that:

Let :

P(L) = Number transported by land = half = 50% = 0.5

P(S) = number transported by sea = 30% = 0.3

P(A) = Number transported by air = (100 - (50 + 30))% = 20% = 0.2

P(H) = highway transport = 40% of land transport = 0.4 * 0.5 = 0.2

P(R) = Rail shipment =(100- 40)% = 60% of land transport = 0.6 * 0.5 = 0.3

Percentage of damaged cargo :

Let probability of damage = P(d)

P(d | H) = 0.1

P(d | R) = 0.05

P(d | S) = 0.06

P(d | A) = 0.02

1) What percentage of all cargoes may be expected to be damaged

[P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

(0.1*0.2) + (0.05*0.3) + (0.06*0.3) + (0.02*0.2) = 0.057

(2) If a damaged cargo is received, what is the probability that it was shipped by ;

land?

([P(d | H)*p(H)] + [P(d | R)*p(R)]) / [P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

((0.1*0.2) + (0.05*0.3)) / (0.1*0.2) + (0.05*0.3) + (0.06*0.3) + (0.02*0.2)

= 0.035 / 0.057

= 0.6140

By sea?

[P(d | S)*p(S)] / [P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

(0.06 * 0.3) / 0.057

= 0.3158

By air?

[P(d | A)*p(A)] / [P(d | H)*p(H)] + [P(d | R)*p(R)] + [P(d | S)*p(S)] + [P(d | A)*p(A)]

(0.02 * 0.2) / 0.057

= 0.0701

Answer:

Let's simplify step-by-step.

−3x+7−(4x−8)

Distribute the Negative Sign:

=−3x+7+−1(4x−8)

=−3x+7+−1(4x)+(−1)(−8)

=−3x+7+−4x+8

Combine Like Terms:

=−3x+7+−4x+8

=(−3x+−4x)+(7+8)

=−7x+15

Answer:

=−7x+15

Step-by-step explanation:

Answer:

15+7x

Step-by-step explanation:

(−3x+7)−(4x−8)

To find the opposite of 4x−8, find the opposite of each term.

−3x+7−4x−(−8)

The opposite of −8 is 8.

−3x+7−4x+8

Combine −3x and −4x to get −7x.

−7x+7+8

Add 7 and 8 to get 15.

−7x+15

answer is 10

if not then im srry

Answer:

( 5  +  b )  ( 25  −  5 b  +  b 2 )

Step-by-step explanation:

 ( a  +  b  )  ( a ^2 −  a b  +  b ^2 )  where  a  =  5  and  b  =  b .

Answer:B; 4.35 • 10/4

Step-by-step explanation:

Answer:

98

Step-by-step explanation:

Average is the sum of all data points divided the number of data points.

In this specific situation, the average test score, 91, is equal to the sum of Molly's four individual test scores divided by the number of test Molly had, 4.

(( 86 + 87  + 93  + x) / 4) = 91

86 + 87 + 93 + x = 91/4

86 + 87 + 93 + x = 364

x = 364 - 93 - 87 - 86 = 98

Answer: 27miles

Step-by-step explanation:

multiply192 by 0.13=27

Answer:

[tex]\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}}[/tex]

[tex]\huge\boxed{\dfrac{f(x+h)}{h}=\dfrac{2x^2-5}{h}+4x+2h}[/tex]

Step-by-step explanation:

[tex]f(x)=2x^2-5\\\\\dfrac{f(x+h)}{h}=\dfrac{2(x+h)^2-5}{h}=\dfrac{2(x^2+2xh+h^2)-5}{h}\\\\\dfrac{f(x+h)}{h}=\dfrac{2x^2+4xh+2h^2-5}{h}\\\\h\neq0[/tex]

Answer:

5.25 miles

Step-by-step explanation:

Answer:

There is 5.25 miles in 9,240 yards

Step-by-step explanation:

1 mile is equal to 1760 yards, so the equation would be

9240/1760 = 5.25

Answer:

8.652kg

Step-by-step explanation:

100 beach umbrellas = 865.2kg

1 beach umbrella = 865.2/100 kg

1 beach umbrella = 8.652kg (Ans)

Answer:

7

Step-by-step explanation:

A coefficient is the number before a variable (x, y, z...etc).

Answer:

Here is the answer also just for the future look up variable calculator :) hope it helps!

Step-by-step explanation:

7 inches = 17.78 cm

Step-by-step explanation:

I looked it up

Answer:

17.78

Step-by-step explanation:

Each inch is 2.54cm.

We will first multiply 2.54 into 7 inches, since it is asking us for the centimeters, then our work should now look like this: 2.54 x 7 = 17.78

We can check our work by dividing the sum by the number in our equation.

17.78/7= 2.54

Answer:

D. 18

Step-by-step explanation:

3÷5=0.6

0.6×30=18

x=18

please make me Brainliest and follow me

Answer:

The value of x in the equation below is 18.

Step-by-step explanation:

We can use proportions to solve this. Cross-multiply then divide.

[tex] \frac{3}{5} = \frac{x}{30} \\ \\ \frac{5x}{5} = \frac{90}{5} \\ \\ x = 18[/tex]

Answer:

0.27

0.1111111

Step-by-step explanation:

Given that:

X :

L1 = 40% = 0.4

L2 = 30% = 0.3

L3 = 20% = 0.2

L4 = 30% = 0.3

P(x) :

L1 = 0.2

L2 = 0.1

L3 = 0.5

L4 = 0.2

A.)

Σ(X * p(x))

(0.4 * 0.2) + (0.3*0.1) + (0.2*0.5) + (0.3 * 0.2) = 0.27

B.) Radartrap located at L2:

P(L2) = (L(x2) * p(L2)) / Σ(X * p(x))

= (0.1 * 0.3) / 0.27

= 0.1111111

Answer:

10

Step-by-step explanation:

lol

...its 10

Step-by-step explanation:

1+1+1+1+1= 5

1+1+1+1+1= 5

5+5=10

Answer:

Step-by-step explanation:

From this study:

The null hypothesis:

[tex]H_o : p_1 =p_2[/tex]

The altenative is:

[tex]H_a : p_1 \ne p_2[/tex]

This test is a two-tailed test.

However; we are told that the wives have 44 success out of 66, then the number of failures will be 22.

Then;

[tex]\hat p_1 = \dfrac{44}{66}[/tex]

[tex]\hat p_1 = 0.6667[/tex]

Similarly, the husbands have 18 success out of 46, then the number of failures will be 28

Then:

[tex]\hat p_2 = \dfrac{18}{46}[/tex]

[tex]\hat p_2 = 0.3913[/tex]

The pooled proportion [tex]p = \dfrac{18+44}{66+46}[/tex]

[tex]p = \dfrac{62}{112}[/tex]

p = 0.55357

The estimated standard error S.E is:

[tex]= \sqrt{\dfrac{ \bar p(1- \bar p)}{n_1} +\dfrac{ \bar p(1-\bar p)}{n_2}}[/tex]

= [tex]\sqrt{ 0.55357(1-0.55357) \Big( \dfrac{1}{66} + \dfrac{1}{46} \Big)}[/tex]

[tex]=\sqrt{ 0.55357(0.44643) \Big(0.01515 + 0.021739 \Big)}[/tex]

[tex]=\sqrt{ 0.00911638798}[/tex]

= 0.0955

The Z test statitics can now be computed as:

[tex]Z = \dfrac{ \hat p_1 - \hat p_2}{\sqrt{\dfrac{ \bar p(1- \bar p)}{n_1} +\dfrac{ \bar p(1-\bar p)}{n_2}}}[/tex]

[tex]Z = \dfrac{0.6667 -0.3913}{0.0955}[/tex]

Z = 2.88

Th p -value from the test statistics is:

p-value = 2P(Z > 2.88)

p- value = 2 P (1 - Z < 2.88)

p-value = 2 ( 1 - 0.998)

p-value = 2 ( 0.002)

p -alue = 0.004

Decision Rule:

Thus, at 0.01 significance level, we reject the null hypothesis because, p-value is less than that (i.e. significance level)

Conclusion:

We conclude that there is a significant  difference between the proportions.

Answer:

Step-by-step explanation: 0.15 and 0.2 are the slope of the line on the graph. The graph of the equation reading y = 0.20x + 25 would show a steeper line bc the bigger the slope the steeper the line.

Answer:

a+2b-d=1, 3, 5, 7

Step-by-step explanation:

(ax^2+bx+3)(x+d)

ax^3+bx^2+3x+adx^2+bdx+3d

ax^3+bx^2+adx^2+3x+bdx+3d=x^3+6x^2+11x+12

ax^3=x^3, a=1

bx^2+adx^2=6x^2

x^2(b+ad)=6x^2

b+ad=6

b+(1)d=6

b+d=6

------------

3x+bdx=11x

x(3+bd)=11x

3+bd=11

-----------------

b=6-d

3+(6-d)d=11

3+6d-d^2=11

3-11+6d-d^2=0

-8+6d-d^2=0

d^2-6d+8=0

factor out,

(d-4)(d-2)=0

zero property,

d-4=0, d-2=0

d=0+4=4,

d=0+2=2

b=6-4=2,

b=6-2=4.

------------------

a+2b-d=1+2(2)-2=1+4-2=5-2=3

-------------------

a+2(4)-4=1+8-4=9-4=5

-----------------------

a+2(2)-4=1+4-4=5-4=1

-----------------------

a+2(4)-2=1+8-2=9-2=7

Answer:

[tex]a+2b-d=1[/tex]

Step-by-step explanation:

We are given that:

[tex](ax^2+bx+3)(x+d)=x^3+6x^2+11x+12[/tex]

And we want to determine:

[tex]a+2b-d[/tex]

So, we will determine our unknowns first.

We can distribute our expression:

[tex]=(ax^2+bx+3)x+(ax^2+bx+3)d[/tex]

Distribute:

[tex]=ax^3+bx^2+3x+adx^2+bdx+3d[/tex]

Rearranging gives:

[tex]=(ax^3)+(bx^2+adx^2)+(bdx+3x)+3d[/tex]

Factoring out the variable yields:

[tex]=(a)x^3+(b+ad)x^2+(bd+3)x+d(3)[/tex]

Since we know that our expression equals:

[tex]x^3+6x^2+11x+12[/tex]

This means that each of the unknown terms in front of each variable corresponds with the coefficient of the resulting equation. Therefore:

[tex]\begin{aligned} a&=1\\ b+ad&=6\\bd+3&=11\\3d&=12\end{aligned}[/tex]

Solving the first and fourth equation yields that:

[tex]a=1\text{ and } d=4[/tex]

Then the second and third equations become:

[tex]b+(1)(4)=6\text{ and } b(4)+3=11[/tex]

And solving for b now yields that:

[tex]b=2\stackrel{\checkmark}{=}2[/tex]

Therefore, we know that:

[tex]a=1, b=2\text{ and } d=4[/tex]

For the equation:

[tex](x^2+2x+3)(x+4)=x^3+6x^2+11x+ 12[/tex]

Then the expression:

[tex]a+2b-d[/tex]

Can be evaluated as:

[tex]=(1)+2(2)-4[/tex]

Evaluate:

[tex]=1+4-4=1[/tex]

Hence, our final answer is 1.