15 points!!! Help!! Find x. Round to the nearest tenth

Answer: 24 coconuts

Step-by-step explanation:

Let the number of coconuts that were originally on the tree be represented by x.

The information given in the question can then be presented to an equation as:

25% × x = 6

25/100 × x = 6

0.25 × x = 6

0.25x = 6

x = 6/0.25

x = 24

Therefore, 24 coconut were originally on the tree.

Answer: 24 coconuts

Step-by-step explanation:

Answer:

A) length = 9cm, width = 4 cm

Step-by-step explanation:

The key word "times" refers to multiplication, so if you're trying to find dimensions at 1/4 times its original size, you need to multiply the original dimensions by 1/4.

l = 36

new l = 36 (1/4)

          = 36/4

          = 9 cm

w = 16

new w = 16 (1/4)

            = 16/4

            = 4 cm

um are you ok dude/ma'am?

Answer:

th correct center is in B

Answer:

356 hope this is correct :)

Step-by-step explanation:

Answer:

0.281 ; 0.864

Step-by-step explanation:

1.)

p decreases as n increases (n increases, p--> 0)

λ ≥ 0

P(x = x) = (e^-λ * λ^x) ÷ x!

λ for Ford = 1.27

B) zero problems :

P(x = 0) :

(e^-1.27 * 1.27^0) ÷ 0! = 0.281

P(x = 0) = 0.281

Two or fewer problems :

P(x ≤ 2) = p(x = 0) + p(x = 1) + p(x = 2)

P(x ≤ 2) = 0.281 + 0.357 + 0.226

P(x ≤ 2) = 0.864

D.) It allows for early detection and thus adequate curtailment of the problem at an a stage in which it seems easier to curb.

Answer:

Im not sure but i think its  10.4 if im wrong im so sry

Step-by-step explanation:

Answer:

3.590ft

Step-by-step explanation:

We know what the circumference of the circle is, and we need to find its diameter. Therefore, we need to find an equation that links the two together.

Well, what comes to mind is the fact that the circumeference, [tex]c[/tex], is equal to [tex]\pi[/tex] multiplied by the diameter, [tex]d[/tex]. We can express this like so:

[tex]c = \pi d[/tex].

In this scenario, we know what [tex]c[/tex] is, so we need to rearrange the formula to make [tex]d[/tex] the subject. Dividing both sides by [tex]\pi[/tex] will accomplish this, and gives us:

[tex]\frac{c}{\pi} = d[/tex].

So if we divide the circumference by [tex]\pi[/tex], we will find the diamater. Well,

[tex]\frac{11.277}{\pi} = 3.58958...[/tex]

and so to 3 decimal places we get the answer

[tex]d = 3.590\text{ft}[/tex].

Answer:

A

Step-by-step explanation:

Answer:

equalities

Please put the Brainlest

Answer:

numbers dont do into math please move this to englash

Step-by-step explanation:

it posted Wong

Answer:

The solution has infinitely many solutions.

Step-by-step explanation:

Correct option is - The solution has infinitely many solutions.

The expression is of the form -

ax + b = ax + b

In the expression , any value of x will satisfy

So, we get infinitely many solution

For example -

for x = 1

a(1) + b = a(1) + b

⇒ a + b = a + b

satisfied.

for x = 2

a(2) + b = a(2) + b

⇒ 2a + b = 2a + b

satisfied.

Hereon, for any value of x , it satisfies.

Answer:

The speed of the jet with no wind is 240 miles per hour.

Step-by-step explanation:

The speed of the jet with no wind is equivalent to the speed of the jet relative to wind. Physically speaking, we have the following system of linear equations under the assumption that both speeds of wind and jet are constant:

In favor of wind

[tex]\frac{s}{t_{F}} = v_{W}+v_{J/W}[/tex] (1)

Against wind

[tex]-\frac{s}{t_{A}} = v_{W} -v_{J/W}[/tex] (2)

Where:

[tex]s[/tex] - Travelled distance, measured in miles.

[tex]t_{F}[/tex], [tex]t_{A}[/tex] - Time, measured in hours.

[tex]v_{W}[/tex] - Wind speed, measured in miles per hour.

[tex]v_{J/W}[/tex] - Jet speed relative to wind, measured in miles per hour.

If we know that [tex]t_{F} = 5\,h[/tex], [tex]t_{A} = 7\,h[/tex], [tex]v_{W} = 40\,\frac{mi}{h}[/tex], then the speed of the jet with no wind is:

[tex]\frac{s}{5} = 40 + v_{J/W}[/tex] (3)

[tex]-\frac{s}{7} = 40-v_{J/W}[/tex] (4)

[tex]\frac{s}{5}-40 = 40 +\frac{s}{7}[/tex]

[tex]\frac{s}{5}-\frac{s}{7} = 80[/tex]

[tex]\frac{7\cdot s - 5\cdot s}{35} = 80[/tex]

[tex]2\cdot s = 2800[/tex]

[tex]s = 1400\,mi[/tex]

From (3), we find that speed of the jet with no wind is:

[tex]v_{J/W} = \frac{s}{5}-40[/tex]

[tex]v_{J/W} = \frac{1400}{5}-40[/tex]

[tex]v_{J/W} = 240\,\frac{mi}{h}[/tex]

The speed of the jet with no wind is 240 miles per hour.

b Answer:

Step-by-step explanation:

Answer:

y = 0.8x

Step-by-step explanation:

y = x-0.2x

y=x(1-0.2)

y=x(0.8)

hence y = 0.8x

Step-by-step explanation:

2x - y = 5

-y = 5 - 2x

.........

Answer:

Let the amounts be 2x and 3x.

Then 2x+3x=60

So, 5x=60

So, x=60/5=12

So, amounts are

2x=2*12=24

And 3x=3*12=36

Hope this helps you!

Step-by-step explanation:

9514 1404 393

Answer:

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

Step-by-step explanation:

The applicable derivative formula is ...

  d(u/v) = (v·du -u·dv)/v²

__

  f'(x) = ((-x² -5x -2)(4x +4) -(2x² +4x -3)(-2x -5))/(-x² -5x -2)²

  f'(x) = (-4x³ -24x²-28x -8 +4x³ +18x² +14x -15)/(x² +5x +2)²

  f'(x) = (-6x² -14x -23)/(x² +5x +2)²

__

Similarly, the second derivative is the derivative of f'(x).

  f''(x) = ((x² +5x +2)²(-12x -14) -(-6x² -14x -23)(2(x² +5x +2)(2x +5)))/(x² +5x +2)⁴

  f''(x) = ((x² +5x +2)(-12x -14) +2(6x² +14x +23)(2x +5))/(x² +5x +2)³

  f''(x) = (12x³ +42x² +138x +202)/(x² +5x +2)³

Answer:

19

Step-by-step explanation:

1 x 4 = 4

15 + 4 = 19

Try this out, hope it helps!

Answer:

equation for how tall sunflower would be after 'w' weeks: y = 15 + w

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

You should not base your reasons on a chocolate bar.

Answer:

There isn’t any question sry

Step-by-step explanation:

Step-by-step explanation:

step 1. f(0) = 0/(0^2 + 1) = 0/1 = 0

step 2. -f(x) = -x/(x^2 + 1)

step 3. f(9) = 9/(9^2 + 1) = 9/82.

A function is defined as a relation between a set of inputs having one output each. The values can be written as shown below.

A function is defined as a relation between a set of inputs having one output each. In simple words, a function is a relationship between inputs where each input is related to exactly one output. Every function has a domain and codomain or range. A function is generally denoted by f(x) where x is the input.

Given function is f(x) = [tex]\frac{x}{x^{2} +1}[/tex], therefore, the values can be found by as shown below. Therefore, we can write,

(a) f(0) = 0/0+1 = 0

(e) – f(x) = - [ x / (x²+1)]

(b) f(9) = 9/(81 + 1) = 9/82

(f) f(x + 1) = (x + 1)/(x² + 2x + 2)

(c) f(-9) = - 9/(81 + 1 ) = -9/82

(g) f(3x) = 3x/(9x² + 1)

(d) f(-x) = -x/(x² + 1)

(h) f(x + h) = (x + h) / [(x+h)²+1]

For more about Function here:

https://brainly.com/question/12431044

#SPJ2

Answer: NUMBER 3

Step-by-step explanation:

Answer:

c=6√2

Step-by-step explanation:

yh I know but not at the moment srry

Answer:

if anyone is looking at this it's warm front is when a warm air mass slides over a cold air mass and stationary front is when a cold air mass and a warm air mass me and do not move and a cold front when a cold air mass slides under a warm air mass and it included front is when two cold fronts force a warm front up and block it from the surface

Warm front formation is different from that of occluded type such that warm air mass rises above a cold air mass during a warm front, but two cold air masses surround a warm air mass during an occluded front.

This can be defined as the transition zone between two different air masses at the Earth's surface.

here, we have,

The warm front and occluded front form under different conditions which is mentioned above and makes option A the most appropriate choice.

so, we get,

Warm front formation is different from that of occluded type such that warm air mass rises above a cold air mass during a warm front, but two cold air masses surround a warm air mass during an occluded front.

Read more about Front formation here

brainly.com/question/18347829

#SPJ5

Complete question:

How is warm front formation different from occluded front formation?

A. A warm air mass rises above a cold air mass during a warm front, but two cold air masses surround a warm air mass during an occluded front.

B. Two cold air masses surround a warm air mass during a warm front, but a cold air mass moves against a warm air mass during an occluded front.

C. A cold air mass moves faster than a warm air mass during a warm front formation, but a cold air mass is pushed upward during an occluded front.

D. A warm air mass and a cold air mass form a boundary during a warm front, but water condenses between two air masses during an occluded front.

Por ejemplo, vamos a hacer la descomposición factorial en números primos del número 24. Ahora buscamos un número primo que sea divisor de 24. Como 24 es un número par, sabemos que un divisor es 2. ... Dividimos 12 entre 2 y el resultado es 6

Answer:

803%

Step-by-step explanation:

365*2.2