18. determine the ph of a 0.22 m na solution at 25°c. the k, of hf is 3.5 x 10*-5
a.10.20 b.5.10 c.8.90 d.11.44 e.2.56

Answers

Answer 1

When NaF is in aqueous solution it dissociates into ions and reacts with water forming NaOH and HF.

The solution would be a mixture of a strong base and a weak acid. Both of these substances contribute to the pH of the solution. We calculate pH as follows: Ka + Kb = 1x10^-14 Kb = 1x10^-14 - 3.5x 10 ^-5mKb = 6.5 x10^-5Kb = [Na+] [OH-] / [NaF] We let x be the concentration of Na in equilibrium, Kb = (x) (x) /0.22 6.5 x10^-5 = x^2 /0.22 x = 3.78x10^-3 = [OH]pOH = -log [OH] pOH = 2.42 pH + pOH = 14  pH = 14 - pOH  pH = 14 - 2.42 pH = 11.58

Therefore, the pH of the solution would be 11.58.

Learn more about concentration here:

https://brainly.com/question/12970323

#SPJ11


Related Questions

²³⁵u undergoes fission by one neutron to produce ¹³³sb, three neutrons, and what other nuclide?

Answers

Nuclear reactions are those in which the identity or properties of an atomic nucleus are altered as a result of being bombarded with energetic particles. Here the nuclide produced is ¹⁰⁰Nb. The correct option is B.

Nuclear fission is the process by which an atom's nucleus breaks into two lighter nuclei during a nuclear reaction. This decay can occur naturally through spontaneous radioactive decay, or it can be artificially recreated in a lab setting by creating the right conditions (such as neutrino bombardment).

Here initially ²³⁵U undergoes fission as follows:

²³⁵U + ₀¹n → ²³⁶U

The atomic number of ²³⁶U is 92 and its mass is 236. One of the products formed here is ¹³³sb which has a mass of 133 and atomic number 51. 3 neutrons are also produced whose mass is 1 and atomic number is 0.

The atomic mass of the new product is:

236 -133 - 3 × 1 = 100

The atomic number of the new product is:

92 - 51 - 3 × 0 = 41

The new nuclide is ₄₁Nb¹⁰⁰.

The fission reaction is:

₉₂U²³⁵ + ₀¹n → ₅₁Sb¹³³+ ₄₁Nb¹⁰⁰ + 3₀¹n

Thus the correct option is B.

To know more about fission, visit;

https://brainly.com/question/10203508

#SPJ12

Your question is incomplete, but most probably your full question was,

²³⁵u undergoes fission by one neutron to produce ¹³³sb, three neutrons, and what other nuclide?

A. ¹⁰⁰Zr

B. ¹⁰⁰Nb

C. ¹⁰¹Nb

D. ¹⁰⁰Mo

E. ¹⁰²Mo

list two groups ( two or more members) of these diatomic molecules with the same number of electrons

Answers

Two groups of diatomic molecules with the same number of electrons are nitrogen (N2) and oxygen (O2), and chlorine (Cl2) and fluorine (F2).

Diatomic molecules are molecules that consist of two atoms of the same element. Nitrogen, oxygen, chlorine, and fluorine are all diatomic molecules, meaning they have two atoms in their structure. Nitrogen and oxygen each have 14 electrons in their outermost electron shell, while chlorine and fluorine each have 14 electrons in their outermost electron shell as well. Therefore, nitrogen and oxygen have the same number of electrons, and chlorine and fluorine have the same number of electrons.

Group 2: Both N2 and O2 molecules have a total of 14 electrons each. N2 has 5 electrons per nitrogen atom, and 2 shared electrons in the triple covalent bond, making a total of 14 electrons for the entire molecule. O2 has 6 electrons per oxygen atom and 2 shared electrons in the double covalent bond, also resulting in a total of 14 electrons for the entire molecule.

To know more about molecules visit :

https://brainly.com/question/19556990

#SPJ11

Calculate ΔGrxn under these conditions: PH2S=1.94 atm ; PSO2=1.39 atm ; PH2O=0.0149 atm . Express your answer with the appropriate units. Is the reaction more or less spontaneous under these conditions than under standard conditions?

Answers

ΔGrxn = -RT ln(Kp) + ΔnRT ln(Ptotal)  If ΔGrxn is positive, the reaction is less spontaneous under these conditions than under standard conditions.

where Kp is the equilibrium constant, Δn is the difference in moles of gas between products and reactants, R is the gas constant (8.314 J/K/mol), T is the temperature in Kelvin, and Ptotal is the total pressure.

Using this equation, we can calculate ΔGrxn for the reaction:

2H2S(g) + O2(g) → 2SO2(g) + 2H2O(g)

At standard conditions (1 atm pressure for all gases), the equilibrium constant Kp is 1.12 x 10^-23, and ΔGrxn is +109.3 kJ/mol.

At the given conditions (PH2S=1.94 atm ; PSO2=1.39 atm ; PH2O=0.0149 atm), the total pressure is Ptotal = PH2S + PSO2 + PH2O = 3.35 atm. The difference in moles of gas is Δn = (2 + 0) - (2 + 2) = -2. Plugging in these values and the temperature in Kelvin (not given), we can calculate the new ΔGrxn.

If ΔGrxn is negative, the reaction is more spontaneous under these conditions than under standard conditions. If ΔGrxn is positive, the reaction is less spontaneous under these conditions than under standard conditions.

Note: Without the temperature given, it is impossible to calculate the final value for ΔGrxn.

learn more about reaction here:

https://brainly.com/question/28984750

#SPJ11

What is the ph of a solution containing .12mol/l nh4cl and .03mol/l naoh?

Answers

To determine the pH of the solution, we first need to calculate the concentration of the resulting solution after the reaction between NH4Cl and NaOH.

The balanced chemical equation for the reaction is:

NH4Cl + NaOH → NaCl + NH3 + H2O

From the equation, we can see that NH4Cl reacts with NaOH to form NaCl, NH3, and H2O.

The NH3 produced will react with water to form NH4+ and OH- ions. Therefore, the resulting solution will contain NH4+, Cl-, Na+, and OH- ions.

To calculate the concentration of NH4+ and OH- ions, we need to use the following equations:

[tex]NH4Cl → NH4+ + Cl-[/tex]

[tex]NaOH → Na+ + OH-[/tex]

The NH4+ and OH- ions will react according to the following equation:

[tex]NH4+ + OH- → NH3 + H2O[/tex]

We can use the initial concentrations of NH4Cl and NaOH to calculate the concentration of NH4+ and OH- ions in the resulting solution:

[ NH4+ ] = 0.12 mol/L

[ OH- ] = 0.03 mol/L

To calculate the pH, we need to determine the concentration of H+ ions in the solution. Since NH4+ is a weak acid, it will undergo partial dissociation according to the following equation:

[tex]NH4+ + H2O ↔ NH3 + H3O+[/tex]

The equilibrium constant expression for this reaction is:

Ka = [ NH3 ][ H3O+ ] / [ NH4+ ]

Since NH4+ is the limiting reactant, we can assume that all of the NH4+ ions will react to form NH3 and H3O+ ions. Therefore, the concentration of NH3 and H3O+ ions will be equal to [ NH4+ ].

[ NH3 ] = [ NH4+ ] = 0.12 mol/L

Substituting the values into the equilibrium constant expression and solving for [ H3O+ ], we get:

[tex]Ka = 5.6 × 10^-10[/tex]

[tex][ H3O+ ] = sqrt( Ka × [ NH4+ ] ) = 1.34 × 10^-6 mol/L[/tex]

pH = -log [ H3O+ ] = -log ( 1.34 × 10^-6 ) = 5.87

Therefore, the pH of the solution is 5.87.

To know more about pH of the solution refer here

https://brainly.com/question/15163821#

#SPJ11

at 25°c, 35.66 mg of silver phosphate dissolves in 2.00l water to form a saturated solution. calculate the ksp of ag3po4 (s). the molar mass of ag3po4 = 418.6 g/mol.

Answers

The Ksp of silver phosphate (Ag₃PO₄) is 1.8 × 10^-18.

To calculate the Ksp of Ag₃PO₄ , first convert the mass of silver phosphate to moles:

moles of Ag₃PO₄  = 35.66 mg / 418.6 g/mol = 8.52 × 10^-5 mol

Next, calculate the molar solubility of Ag3PO4 in the solution:

molar solubility = moles of Ag₃PO₄  / volume of solution

molar solubility = 8.52 × 10⁻⁵ mol / 2.00 L = 4.26 × 10⁻⁵ M

Finally, use the molar solubility to calculate the Ksp using the expression:

Ag₃PO₄  (s) ⇌ 3 Ag+(aq) + PO₄(aq)

Ksp = [Ag+]^3[PO₄₃-]

Substitute the equilibrium concentrations:

Ksp = (3 × 4.26 × 10⁻⁵ M)³ (4.26 × 10⁻⁵ M)

Ksp = 1.8 × 10⁻18

Therefore, the Ksp of Ag₃PO₄ is 1.8 × 10⁻¹⁸

To learn more about equilibrium concentrations
https://brainly.com/question/16645766

#SPJ4

when considering the relationship among standard free energy change, equilibrium constants, and standard cell potential, the equation δg∘=−nfe∘cell is _______.

Answers

The equation δG° = -nFE°cell relates the standard free energy change (ΔG°), the number of moles of electrons transferred (n), and the standard cell potential (E°cell) of a redox reaction.

This equation is derived from the relationship between Gibbs free energy and the work done by a cell in a reversible process.

The equation shows that the standard free energy change is directly proportional to the number of moles of electrons transferred and the standard cell potential.

The negative sign indicates that the reaction is spontaneous when ΔG° is negative.

This equation is useful in predicting the feasibility of a redox reaction and can be used to calculate the equilibrium constant for the reaction using the relationship ΔG° = -RT ln K.

To know more about redox reaction, refer here:

https://brainly.com/question/13293425#

#SPJ11

A 0. 60 mol sample of PCl 3 (g) and a 0. 70 mol sample of Cl 2 (g) are placed in a previously evacuated 1. 0 L container, and the reaction represented above takes place. At equilibrium, the concentration of PCl 5 (g) the container is 0. 040 M. (a) Find the concentrations of PCl 3 and Cl 2 at the equilibrium

Answers

At equilibrium, the concentrations of PCl3 and Cl2 in the 1.0 L container are 0.40 M and 0.30 M, respectively.

To find the concentrations of PCl3 and Cl2 at equilibrium, we need to consider the stoichiometry of the reaction and use the given equilibrium concentration of PCl5.

From the balanced equation for the reaction:

PCl3 + Cl2 ⇌ PCl5

We can determine that one mole of PCl3 reacts with one mole of Cl2 to form one mole of PCl5.

Let's assume x represents the change in concentration for both PCl3 and Cl2.

At equilibrium, the concentration of PCl3 is given as 0.40 M. Since one mole of PCl3 reacts to form one mole of PCl5, the concentration of PCl5 at equilibrium is also 0.40 M.

Using the stoichiometry of the reaction, the change in concentration for Cl2 is also x.

The equilibrium concentration of Cl2 can be calculated by subtracting the change in concentration from the initial concentration:

[Cl2]equilibrium = [Cl2]initial - x = 0.70 M - x

From the given information, we know that the concentration of PCl5 at equilibrium is 0.040 M.

Using the stoichiometry of the reaction, the change in concentration for PCl3 is also x.

The equilibrium concentration of PCl3 can be calculated by subtracting the change in concentration from the initial concentration:

[PCl3]equilibrium = [PCl3]initial - x = 0.60 M - x

Since the stoichiometry of the reaction is 1:1 for PCl3 and Cl2, the concentration of PCl5 can be used to determine the value of x.

From the balanced equation, the initial concentration of PCl5 is zero, and at equilibrium, it is given as 0.040 M. This indicates that x has a value of 0.040 M.

Substituting the value of x in the expressions for [PCl3]equilibrium and [Cl2]equilibrium:

[PCl3]equilibrium = 0.60 M - 0.040 M = 0.56 M

[Cl2]equilibrium = 0.70 M - 0.040 M = 0.66 M

Therefore, at equilibrium, the concentrations of PCl3 and Cl2 in the 1.0 L container are 0.40 M and 0.30 M, respectively.

To learn more about balanced equation click here : brainly.com/question/31242898

#SPJ11

how many electrons, protons, and neutrons are in a neutral 197au197au atom? enter your answers numerically separated by commas.

Answers

The number of electrons, protons, and neutrons in a neutral 197Au atom is 79 electrons, 79 protons, and 118 neutrons.

How many electrons, protons, and neutrons are present in a neutral 197Au atom?

A neutral atom contains the same number of electrons as protons. The atomic number of gold (Au) is 79, which corresponds to the number of protons. To determine the number of neutrons, we subtract the atomic number from the atomic mass. In the case of gold-197 (197Au), the atomic mass is 197, and subtracting the atomic number (79) gives us the number of neutrons.

Hence, a neutral 197Au atom contains 79 electrons, 79 protons, and 118 neutrons.

Understanding the composition of atoms and the distribution of subatomic particles is fundamental to the study of atomic structure and the properties of elements.

Learn more about neutral atom

brainly.com/question/29235711

#SPJ11

each of the following compounds are dissolved in pure water. which will result in the formation of a solution with a ph greater than 7? select all that apply.

Answers

Compounds that will result in the formation of a solution with a pH greater than 7 are Na₂CO₃, KI, NaCl, and KC₂H₃O₂.

The pH of a solution is determined by the concentration of hydronium ions (H₃O⁺) present in the solution. A solution with a pH greater than 7 is basic and has a lower concentration of H₃O⁺ ions. Therefore, we need to identify the compounds that will form basic solutions when dissolved in water.

Na₂CO₃, KI, NaCl, and KC₂H₃O₂ are all ionic compounds that dissociate into their respective ions when dissolved in water. The cations and anions in these compounds can either be acidic, basic, or neutral. In this case, the basicity of the anions determines the basicity of the solution.

Na₂CO₃ contains the carbonate ion (CO₃²⁻), which is a weak base. When it reacts with water, it produces hydroxide ions (OH⁻) which increases the pH of the solution.

KI and NaCl contain iodide and chloride ions, respectively, which are neutral and do not affect the pH of the solution.

KC₂H₃O₂ contains the acetate ion (CH₃COO⁻), which is a weak base. When it reacts with water, it produces hydroxide ions (OH⁻) which increases the pH of the solution.

Therefore, Na₂CO₃, KI, NaCl, and KC₂H₃O₂ will result in the formation of a solution with a pH greater than 7.

To know more about ionic compounds refer here:

https://brainly.com/question/17217225#

#SPJ11

Complete Question:

Each of the following compounds are dissolved in pure water. Which will result in the formation of a solution with a pH greater than 7? Select all that apply. CaBr2 Na2CO3 NH4Cl KI NaCl KC2H3O2 MgF2

chromium(iii) hydroxide is amphiprotic. write a balanced chemical equation showing how an aqueous suspension of this compound reacts to the addition of a strong acid. use h to represent the strong acid.

Answers

The balanced chemical equation for the reaction of an aqueous suspension of chromium(III) hydroxide with a strong acid, represented by "H," is: Cr(OH)₃(s) + 3H⁺(aq) → Cr³⁺(aq) + 3H₂O(l)

How does chromium(III) hydroxide react with a strong acid?

When a strong acid is added to an aqueous suspension of chromium(III) hydroxide, the hydroxide ions (OH⁻) from the hydroxide compound react with the hydrogen ions (H⁺) from the acid to form water (H₂O). The chromium(III) ions (Cr³⁺) are released into the solution.

Chromium(III) hydroxide, Cr(OH)₃, is amphiprotic, meaning it can act as both an acid and a base. In this case, it acts as a base by accepting protons from the strong acid. The resulting reaction produces water and dissolved chromium(III) ions.

Therefore, the reaction of an aqueous suspension of chromium(III) hydroxide with a strong acid produces chromium(III) ions and water.

To know more about aqueous suspension, refer here:
https://brainly.com/question/24807081
#SPJ4

Calculate each of the following quantities: Molarity of a solution prepared by diluting 37.00 mL of 0.250 M potassium chloride to 150.00 mL Molarity of a solution prepared by diluting 25.71 mL of 0.0706 M ammonium sulfate to 500.00 mL Molarity of sodium ion is a solution made by mixing 3.58 mL of 0.348 M sodium chloride with 500. mL of 6.81 times 10^-2 M sodium sulfate (assume volumes are additive)

Answers

In each case, the molarity is calculated by dividing the number of moles of solute by the liters of solution. The resulting value represents the concentration of the solute in the solution in molarity.  

a. Molarity of a solution prepared by diluting 37.00 mL of 0.250 M potassium chloride to 150.00 mL:

Molarity = (moles of solute/liters of solution)

Molarity = (0.250 moles of KCl/150 mL)

Molarity = 0.0167 molar

b. Molarity of a solution prepared by diluting 25.71 mL of 0.0706 M ammonium sulfate to 500.00 mL:

Molarity = (moles of solute/liters of solution)

Molarity = (0.0706 moles of [tex]NH_4SO_4[/tex] / 500 mL)

Molarity = 0.0014 molar

c. Molarity of sodium ion is a solution made by mixing 3.58 mL of 0.348 M sodium chloride with 500. mL of 6.81 times 10^-2 M sodium sulfate (assume volumes are additive):

Molarity of Na+ ions = (moles of solute/liters of solution)

Molarity of Na+ ions = (0.348 moles of NaCl/500 mL)

Molarity of Na+ ions = 0.0007 molar

Learn more about molarity visit: brainly.com/question/30404105

#SPJ4

How many of the following elements can form compounds with an expanded octet? I, O, Cl, Xe

Answers

Out of the four elements given, only two elements, namely Cl (chlorine) and Xe (xenon), can form compounds with an expanded octet.

This is because they have vacant d-orbitals in their valence shell, which allows them to accommodate more than eight electrons and form compounds with an expanded octet. On the other hand, I (iodine) and O (oxygen) already have a complete octet in their valence shell and cannot form compounds with an expanded octet.
Out of the elements you mentioned (I, O, Cl, Xe), two elements can form compounds with an expanded octet. These are Iodine (I) and Xenon (Xe). They can accommodate more than 8 electrons in their valence shell due to the availability of empty d-orbitals in their respective electron configurations.

To know more about octet visit:

https://brainly.com/question/10535983

#SPJ11

what is the structure of n-phenyl-n-propyl-2,3-dimethylbutanamide?

Answers

N-phenyl-n-propyl-2,3-dimethylbutanamide is a compound that belongs to the family of amides.

Its structure consists of a butanamide chain, which is made up of four carbon atoms with two methyl groups attached to the third and fourth carbon atoms.

The nitrogen atom in the amide group is bonded to a propyl group, which in turn is bonded to a phenyl group.

The phenyl group is a six-membered aromatic ring made up of six carbon atoms, with a hydrogen atom attached to each carbon atom.

The molecule has a linear structure, with the butanamide chain and the phenyl group extending from the nitrogen atom in opposite directions.

To know more about amides, refer here:

https://brainly.com/question/31673282#

#SPJ11

If 7.40 g of O3 reacts with 0.670 g of NO, how many grams of NO3 will be produced? Identify the limiting reagent from the reaction.


2O3 + 3NO → 3NO3


O3 produces _____0.72____ grams of NO2


NO produces ________ grams of NO2


The limiting reagent (reactant) is-

Answers

The grams of NO3 produced in the reaction will be 0.72 g. The limiting reagent is NO.

First, we need to calculate the moles of O3 and NO using their molar masses. The molar mass of O3 is approximately 48 g/mol, and the molar mass of NO is approximately 30 g/mol.

The moles of O3 can be calculated by dividing the given mass of O3 (7.40 g) by its molar mass, which gives approximately 0.154 moles.

Similarly, the moles of NO can be calculated by dividing the given mass of NO (0.670 g) by its molar mass, which gives approximately 0.0223 moles.

Next, we can use the stoichiometric coefficients from the balanced equation to determine the moles of NO3 that can be produced from each reactant. According to the balanced equation, 2 moles of O3 react with 3 moles of NO to produce 3 moles of NO3.

From the calculated moles, we find that O3 can produce approximately 0.231 moles of NO3 (0.154 moles O3 × 3 moles NO3 / 2 moles O3).

On the other hand, NO can produce approximately 0.0335 moles of NO3 (0.0223 moles NO × 3 moles NO3 / 3 moles NO).

To convert the moles of NO3 to grams, we multiply by the molar mass of NO3, which is approximately 62 g/mol.

Thus, O3 produces approximately 0.72 grams of NO3 (0.231 moles NO3 × 62 g/mol).

Since NO produces a lesser amount of NO3 (0.0335 moles NO3 or approximately 2.08 grams), it is the limiting reagent in this reaction. The amount of NO3 produced is determined by the amount of NO available, and any excess O3 is left unreacted.

To learn more about molar mass click here : brainly.com/question/31545539

#SPJ11

if the aka of a monoprotic weak acid is 4.1×10−6,4.1×10−6, what is the phph of a 0.17 m0.17 m solution of this acid?

Answers

The pH of a 0.17 M solution of this weak acid is approximately 2.99, To determine the pH of a 0.17 M solution of a monoprotic weak acid, we can use the acid dissociation constant (Ka) and the equilibrium expression: Ka = [H+][A-] / [HA].

where [H+] is the concentration of hydrogen ions, [A-] is the concentration of the conjugate base, and [HA] is the concentration of the weak acid.

Assuming that the acid dissociates to a negligible extent, we can make the approximation [HA] ≈ initial concentration of the acid, and [A-] ≈ 0. Then, the equilibrium expression becomes:

Ka = [H+]² / [HA]

Solving for [H+], we get:

[H+] = sqrt(Ka x [HA])

[H+] = sqrt(4.1 x 10⁻⁶ x 0.17)

[H+] = 1.01 x 10⁻³ M

To find the pH, we can use the equation:

pH = -log[H+]

pH = -log(1.01 x 10⁻³)

pH = 2.99

To know more about pH refer here :-

https://brainly.com/question/2288405#
#SPJ11

consider 1h81br as a rigid rotor when the molecule is in the j = 8 state

Answers

The concept of a rigid rotor is an important tool for understanding the behavior of molecules and their rotational motion. By applying this model to specific molecules like 1h81br, we can gain insights into their physical properties and behavior.

In physics and chemistry, a rigid rotor is a model used to describe the motion of a molecule. It assumes that the molecule behaves like a rigid body and does not deform or change shape as it rotates. The rigid rotor model is often used to describe the rotational motion of diatomic molecules.
In the case of 1h81br, this is a diatomic molecule consisting of one hydrogen atom and one bromine atom. When the molecule is in the j = 8 state, it means that it has a specific amount of angular momentum. The higher the j value, the faster the molecule is rotating.
The behavior of a rigid rotor can be described using the Schrödinger equation, which predicts the energy levels and wavefunctions of the molecule. The energy levels of a rigid rotor depend on the moment of inertia of the molecule, which is a measure of how difficult it is to rotate the molecule.
For 1h81br, the moment of inertia depends on the masses of the hydrogen and bromine atoms, as well as the distance between them. By solving the Schrödinger equation for the j = 8 state, we can determine the energy level and wavefunction of the molecule.

To know more about molecule visit :

https://brainly.com/question/28060128

#SPJ11

T/F. oxygen debt refers to the oxygen required to make creatine phosphate

Answers

The statement is False. Oxygen debt refers to the oxygen required to restore metabolic processes back to their resting state after exercise, not to make creatine phosphate.

During exercise, the body's muscles require more energy than can be supplied by aerobic metabolism alone. As a result, the muscles switch to anaerobic metabolism, which produces lactic acid as a byproduct. Lactic acid can build up in the muscles, causing fatigue and limiting exercise performance.

After exercise, the body needs to restore the metabolic processes back to their resting state, which requires oxygen. This oxygen is used to convert the accumulated lactic acid back into glucose through a process called the Cori cycle. This process is what is known as oxygen debt, and it can persist for several minutes or even hours after exercise has stopped.

Creatine phosphate, on the other hand, is a high-energy molecule that can be used to regenerate ATP, the primary energy source for muscle cells. While the production of creatine phosphate does require oxygen, it is not directly related to oxygen debt, which is focused on restoring the body's metabolic processes back to their resting state after exercise.

To learn more about Cori cycle click here : brainly.com/question/14318858

#SPJ11

3.43 without referring to a pka table, determine if water is a suitable proton source to protonate the following compound. explain why or why not.

Answers

In order to determine if water is a suitable proton source to protonate the given compound, we need to compare the pka values of the two species. The pka value of water is 15.7, while the pka value of the given compound is not provided. However, we can make an estimate based on the functional groups present in the compound.

If the compound contains a strong acid group with a low pka value (such as a carboxylic acid or a phenol), water would not be a suitable proton source as the compound would be more acidic and would not accept a proton from water. However, if the compound contains a weaker acid group (such as an alcohol or an amine), water could potentially be a suitable proton source.
Assuming that the compound contains a weaker acid group, we need to compare its pka value to that of water. A difference in pka values of more than 4 units indicates that the proton transfer reaction is unfavorable. In this case, the difference in pka  values between water and the compound is greater than 12 units, indicating that water is a highly unsuitable proton source.
Therefore, based on the large difference in pka values, we can conclude that water is not a suitable proton source to protonate the given compound. The compound is likely too basic to be protonated by water.

For more such question on pka values

https://brainly.com/question/31962641

#SPJ11

At equilibrium in a 10 L vessel, there are 7.60x 10-2 moles of SO2, 8.60x102 moles of O2, and 8.20x102 moles of SO3. What is the equilibrium constant Ke under these conditions? 2SO,(g)+ 0,(g) 2SO, (g) (A) 12.5 (B) 13.5 (C) 125 (D) 135

Answers

Finally, Ke = 1358. Therefore, none of the provided options (A, B, C, or D) is the correct answer. The equilibrium constant Ke under these conditions is approximately 1358 in pressure.

The force that a substance applies to its surroundings as a function of area is known as pressure. It is a fundamental physical characteristic that is important to many branches of science, including as physics, chemistry, and engineering. The interaction of molecules or particles with a container's or surface's walls results in pressure. Units like pascals (Pa), atmospheres (atm), millimetres of mercury (mmHg), or pounds per square inch (psi) are frequently used to measure it. The behaviour and characteristics of gases, liquids, and solids are influenced by pressure, which also has an impact on processes including fluid flow, gas compression, chemical reactions, and atmospheric conditions. In many real-world scenarios, from industrial operations to medical equipment, understanding and managing pressure is crucial.

To calculate the equilibrium constant (Ke) for the given reaction:
2SO2(g) + O2(g) ⇌ 2SO3(g)

First, we need to find the equilibrium concentrations of each species by dividing the moles by the volume of the vessel (10 L):
[SO2] = [tex](7.60 x 10^(-2) moles) / 10 L = 7.60 * 10^(-3) M[/tex]
[O2] = [tex](8.60 * 10^2 moles) / 10 L = 8.60 * 10^1 M[/tex]
[SO3] = [tex](8.20 * 10^2 moles) / 10 L = 8.20 * 10^1 M[/tex]

Now, we can plug these concentrations into the equilibrium constant expression for the given reaction:
Ke =[tex][SO3]^2 / ([SO2]^2 * [O2])[/tex]

Note that the coefficients in the balanced equation become the powers in the equilibrium constant expression.

Ke = [tex](8.20 * 10^1)^2 / ((7.60 * 10^(-3))^2 * (8.60 * 10^1))[/tex]

Next, calculate the values:
Ke = (6724) / (5.76 x[tex]10^(-3)[/tex] 10^(-5) * 86)
Ke = 6724 / (4.95 x [tex]10^(-3)[/tex])

Finally, Ke ≈ 1358. Therefore, none of the provided options (A, B, C, or D) is the correct answer. The equilibrium constant Ke under these conditions is approximately 1358.

Learn more about pressure here:

https://brainly.com/question/29241728

#SPJ11

determine the theoretical yield and the percent yield if 21.8 g of k2co3is produced from reacting27.9 g ko2with 29.0 l of co2(at stp). the molar mass of ko2=71.10 g/mol and k2co3=138.21g/mol.

Answers

Theoretical yield: 33.4 g

Percent yield: 65.4%

How to  percent determine the theoretical yield?

The theoretical yield in this reaction is calculated by first determining the limiting reactant, which is the reactant that is completely consumed and determines the maximum amount of product that can be formed. In this case, we compare the number of moles of KO2 and CO2 and find that KO2 is the limiting reactant. Using the stoichiometric ratio between KO2 and K2CO3, we calculate the number of moles of K2CO3 produced. By multiplying the number of moles by the molar mass of K2CO3, we find the theoretical yield to be 33.4 g.

How to  percent determine the theoretical yield?

The percent yield is then determined by dividing the actual yield (given as 21.8 g) by the theoretical yield and multiplying by 100. The percent yield represents the efficiency of the reaction and indicates how much of the expected product was actually obtained. In this case, the percent yield is calculated to be 65.4%.

It's important to note that the percent yield can be influenced by various factors such as impurities, side reactions, and incomplete conversions. Achieving a high percent yield indicates a more efficient reaction with minimal loss of product.

Learn more about yield

brainly.com/question/1306952

#SPJ11

select all the statements that correctly describe the equilibrium constant kc for a general chemical change represented by the equation given below. aa (aq) bb (aq) ⇌ cc (aq) dd (aq)

Answers

The equilibrium constant (Kc) is a measure of the ratio of the concentrations of products to reactants at equilibrium for a given chemical reaction.

For the general chemical change represented by the equation aa (aq) bb (aq) ⇌ cc (aq) dd (aq), the equilibrium constant (Kc) can be defined as:

Kc = [C]^c[D]^d / [A]^a[B]^b

where [A], [B], [C], and [D] are the concentrations of reactants and products in mol/L at equilibrium and a, b, c, and d are the stoichiometric coefficients of the reactants and products in the balanced equation.
The following statements correctly describe the equilibrium constant Kc for the given chemical change:
1. Kc is constant for a given reaction at a specific temperature.
2. Kc is equal to the ratio of the concentrations of products to reactants at equilibrium.
3. Kc can be used to predict the direction in which the reaction will proceed towards equilibrium.
4. Kc can be used to calculate the equilibrium concentrations of reactants and products.

In summary, the equilibrium constant Kc is a fundamental concept in chemistry that describes the balance between forward and reverse reactions in a chemical system. It is a useful tool for predicting the direction and extent of chemical changes and for determining the equilibrium concentrations of reactants and products.

To learn more about chemical changes:

https://brainly.com/question/29762834

#SPJ11

what happens when h3po4 is added to a fecl4 solution

Answers

When H3PO4 (phosphoric acid) is added to a FeCl4 (iron(III) chloride) solution, a chemical reaction occurs, forming FePO4 (iron(III) phosphate) and HCl (hydrochloric acid) as products. The reaction can be represented as:

FeCl4- + 3H3PO4 → FePO4 + 4HCl + 2H2O

Step-by-step explanation:
1. H3PO4, a weak acid, is added to the FeCl4 solution.
2. The H3PO4 reacts with FeCl4 to form FePO4 and HCl.
3. Iron(III) phosphate (FePO4) precipitates out of the solution.
4. The remaining ions in the solution are chloride ions (Cl-) and hydrogen ions (H+) from the hydrochloric acid.

To know more about H3PO4 : https://brainly.com/question/3506521

#SPJ11

Describe the preparation used. Be sure to include any changes made in the scheme presented in the discussion. ethyl butyrate-CH3(CH2)2COOCH2CH3

Answers

Ethyl butyrate is an ester that is commonly used as a flavoring agent in foods and beverages. It has a fruity, sweet odor and taste, and is found naturally in many fruits, including apples, pineapples, and strawberries.

Ethyl butyrate is an ester that is commonly used as a flavoring agent in foods and beverages. It has a fruity, sweet odor and taste, and is found naturally in many fruits, including apples, pineapples, and strawberries.

There are several methods for preparing ethyl butyrate, but one common approach is the Fischer esterification reaction. This reaction involves the condensation of an alcohol with a carboxylic acid in the presence of an acid catalyst.

The carboxylic acid, butyric acid, and the alcohol, ethanol, are mixed together in a round-bottomed flask. A small amount of concentrated sulfuric acid is added to the mixture to serve as a catalyst.

The mixture is heated under reflux, which means that it is boiled in a condenser that is connected to the flask, so that the vapors condense and return to the flask. This helps to ensure that the reaction proceeds to completion.

The ester product, ethyl butyrate, is separated from the water and any other impurities by distillation. The ester has a boiling point of 121-123°C, so it can be easily separated from the lower-boiling water and other byproducts.

There are several modifications that can be made to this basic scheme, depending on the desired purity and yield of the product. For example, the reaction may be carried out in the presence of a drying agent, such as calcium chloride, to help remove any water that is formed during the reaction.

Alternatively, the esterification may be carried out in two stages, with the addition of a base catalyst after the initial acid-catalyzed step, to help drive the reaction to completion.

For more such questions on ester visit;

https://brainly.com/question/28118164

#SPJ11

electrolysis of an nacl solution with a current of 2.02 a for a period of 203 s produced 59.3 ml of cl2 at 652 mmhg and 27 ∘c . calculate the value of the faraday from these data.2.00 A * 200 s = 400CN = P1V1RTN= (650/760) (.0596L)/ (.0821 L*ATM/Mol*K ) (300K)N=.00207mol Cl.00207 * 2 = .004139 Cl2400C /.004139 mol = 96638 Faraday

Answers

Therefore, the value of the Faraday from these data is approximately 96,638 Faraday.

Based on the information provided, the electrolysis of an NaCl solution with a current of 2.02 A for a period of 203 s produced 59.3 mL of Cl2 at 652 mmHg and 27 °C. To calculate the value of the Faraday from these data, we can use the following equation:
Faraday = (number of moles of Cl2 produced) / (amount of charge passed)
First, we need to determine the number of moles of Cl2 produced. We can use the ideal gas law to do this:
PV = nRT
where P is the pressure in atm, V is the volume in L, n is the number of moles, R is the gas constant (0.0821 L*atm/mol*K), and T is the temperature in Kelvin.
Converting the given pressure of 652 mmHg to atm and the given volume of 59.3 mL to L, we have:
P = 652 mmHg / 760 mmHg/atm = 0.858 atm
V = 59.3 mL / 1000 mL/L = 0.0593 L
T = 27 + 273 = 300 K
Substituting these values into the ideal gas law equation, we get:
n = (P * V) / (R * T)
n = (0.858 atm * 0.0593 L) / (0.0821 L*atm/mol*K * 300 K)
n = 0.00207 mol Cl2
Next, we need to calculate the amount of charge passed in Coulombs (C). We can use the formula:
Q = I * t
where Q is the amount of charge, I is the current in amperes, and t is the time in seconds.
Substituting the given values, we get:
Q = 2.02 A *203 s
Q = 410.06 C
Finally, we can calculate the value of the Faraday using the equation mentioned earlier:
Faraday = (number of moles of Cl2 produced) / (amount of charge passed)
Faraday = 0.00207 mol / 410.06 C
Faraday = 0.000005055 mol/C = 96,638 Faraday (rounded to the nearest whole number)
Therefore, the value of the Faraday from these data is approximately 96,638 Faraday.
From the given data, electrolysis of an NaCl solution with a current of 2.02 A for 203 seconds produced 59.3 mL of Cl2 at 652 mmHg and 27°C. To calculate the value of Faraday, we can follow these steps:

1. Calculate the total charge passed: 2.02 A * 203 s = 410.06 C
2. Convert pressure, volume, and temperature to appropriate units and apply the ideal gas law to find moles of Cl2 produced:

N = (P1V1)/(RT) = (652/760 atm) * (0.0593L) / (0.0821 L*atm/mol*K) * (300K) = 0.00211 mol Cl2

3. Calculate the moles of electrons transferred (2 electrons per mole of Cl2):

0.00211 mol Cl2 * 2 = 0.00422 mol of electrons

4. Determine the value of Faraday using the total charge and moles of electrons:

Faraday = 410.06 C / 0.00422 mol = 97200 C/mol (approximately)

So, the value of Faraday from these data is approximately 97200 C/mol.

To know more about Faraday visit:-

https://brainly.com/question/31604460

#SPJ11

cell cathode anode cell potential(V)
1&4 1 4 0.041
1&5 1 5 0.078
1&6 1 6 0.103
I. Cu in 1.0 M Cu(NO3)2
4. Cu in 0.1 M Cu(NO3)2
5. Cu in 0.01M Cu(NO3)2
6.Cu in 0.001 M Cu(NO3)2
=> Calculate the concetration cell
use the nernst equation and concentrations of Cu2+ to calculate the cell potentials for the cells that were constructed in the table using cell compartment 1 with each of cell compartments 4,5 and 6. in each case, compare the calculated cell potentials to the measured values. discuss any differences in sigh or magnitude.

Answers

The cell potential for the reaction is: 1&4 = 0.25 V 1&5  = 0.16 V.

To calculate the cell potential using the Nernst equation, we can use the following equation:

Ecell = E°cell - (RT/nF)ln(Q)

Where Ecell is the cell potential, E°cell is the standard cell potential, R is the gas constant (8.314 J/K mol), T is the temperature in Kelvin, n is the number of electrons transferred in the reaction, F is the Faraday constant (96,485 C/mol), and Q is the reaction quotient.

For the reactions given, we have:

1&4: Cu2+ (0.1 M) + 2e- → Cu (s)

1&5: Cu2+ (0.01 M) + 2e- → Cu (s)

1&6: Cu2+ (0.001 M) + 2e- → Cu (s)

The standard reduction potential for Cu2+/Cu is +0.34 V.

Using the Nernst equation, we can calculate the cell potential for each reaction as follows:

1&4: Ecell = 0.34 - (0.0257/2)ln(0.1) = 0.25 V

1&5: Ecell = 0.34 - (0.0257/2)ln(0.01) = 0.16 V

1&6: Ecell = 0.34 - (0.0257/2)ln(0.001) = 0.07 V

Comparing the calculated cell potentials to the measured values in the table, we can see that there are differences in both sign and magnitude.

For example, for the 1&4 cell, the measured potential is positive (+0.041 V), indicating that the reaction is spontaneous. However, the calculated potential is larger (+0.25 V), indicating that the reaction is even more spontaneous than predicted. This could be due to a number of factors, such as experimental error, deviation from ideal conditions, or incomplete understanding of the reaction mechanism.

Similarly, for the 1&5 and 1&6 cells, the calculated potentials are lower than the measured values, indicating that the reactions are less spontaneous than predicted. This could also be due to experimental error, or it could suggest that there are other factors influencing the reactions that are not accounted for in the Nernst equation.

To know more about cell potential follow the link:

https://brainly.com/question/10470515

#SPJ4

Calculate the molarity of a MgSO4 solution prepared by adding 0. 4 moles of MgSO4 to enough water to make 6. 6 L of solution. Answer in units of M

Answers

To calculate the molarity (M) of the MgSO4 solution, we need to use the formula Molarity (M) = moles of solute / volume of solution (in liters).

In this case, we are given that 0.4 moles of MgSO4 are added to enough water to make 6.6 liters of solution.

Molarity = 0.4 moles / 6.6 L

Molarity = 0.0606 M

Therefore, the molarity of the MgSO4 solution is 0.0606 M.

It's important to note that molarity represents the amount of solute (in moles) dissolved in a given volume of solution (in liters).

In this case, the molarity tells us the concentration of MgSO4 in the solution, with 0.0606 moles of MgSO4 present per liter of the solution. A compound's molar mass is just the total molar weight of the individual atoms that make up its chemical formula. It is also known as the ratio of a substance's mass to its molecular weight.

Learn more about molarity here

https://brainly.com/question/30216315

#SPJ11

at 145.0 kpa and 207.0 °c, an ideal gas occupies 3.63 m3. find the number of moles of the gas.

Answers

The number of moles of the gas is 150.9 mol.

We can use the ideal gas law, which relates the pressure (P), volume (V), temperature (T), and number of moles (n) of an ideal gas through the equation PV = nRT, where R is the gas constant. Rearranging this equation, we get n = PV/RT.

We are given P = 145.0 kPa, V = 3.63 m³, T = 207.0°C + 273.15 = 480.15 K, and R = 8.3145 J/(mol·K) for an ideal gas. However, we need to convert the temperature to kelvin to use the ideal gas law.

Substituting the given values into the equation and solving for n, we get n = (145.0 × 10³ Pa) × (3.63 m³) / [(8.3145 J/(mol·K)) × (480.15 K)] = 150.9 mol. Therefore, the number of moles of the gas is 150.9 mol.

To know more about ideal gas law refer here:

https://brainly.com/question/28257995#

#SPJ11

Give the oxidation state of the metal species in each complex. [Co(NH3)5Cl]Cl2 [Ru(CN)3(CO)2]3− :

Answers

The oxidation state of cobalt in [Co(NH3)5Cl]Cl2 is +3, while the oxidation state of ruthenium in [Ru(CN)3(CO)2]3− is +2.

In [Co(NH3)5Cl]Cl2, there are five ammonia (NH3) ligands and one chloride (Cl-) ligand, with two chloride counterions. Each ammonia ligand is neutral and has a charge of 0. The chloride ligand has a charge of -1, and there are two of them, giving a total charge of -2 for the complex. Since the overall charge of the complex is 0, the oxidation state of cobalt must be +3, as it contributes three positive charges to balance out the negative charges.

In [Ru(CN)3(CO)2]3−, there are three cyanide (CN-) ligands and two carbonyl (CO) ligands. Each cyanide ligand has a charge of -1, and each carbonyl ligand has a charge of 0. There is also a charge of -3 on the complex due to the three negative charges from the cyanide ligands. Therefore, the oxidation state of ruthenium must be +2, as it contributes two positive charges to balance out the negative charges.

learn more about oxidation here:

https://brainly.com/question/9496279

#SPJ11

Luis prepares a carbonated beverage using CO2 gas, solid sugar (C12H22O11) and liquid water. Identify the only solutes.

Answers

The solutes in Luis's carbonated beverage are solid sugar (C12H22O11) and CO2 gas.

In the context of a solution, solutes are substances that are dissolved in a solvent. In this case, the solvent is liquid water, which is the main component of the carbonated beverage. The solutes in the beverage are solid sugar (C12H22O11) and CO2 gas.

Solid sugar (C12H22O11) dissolves in water to form a solution. The sugar molecules break apart and disperse throughout the water, becoming evenly distributed. This dissolved sugar contributes to the sweetness of the beverage.

CO2 gas dissolves in water to form carbonic acid (H2CO3), which gives the beverage its characteristic carbonation. When CO2 gas is dissolved in water, it reacts with the water molecules to form carbonic acid. This reaction produces carbon dioxide ions (CO3^2-) and hydrogen ions (H+), which contribute to the carbonation and acidity of the beverage.

Therefore, the solutes in Luis's carbonated beverage are solid sugar (C12H22O11) and CO2 gas.

Learn more about C12H22O11 here:

https://brainly.com/question/30398451

#SPJ11

Explain how delta T would be affected if a greater amount of surrounding solvent (water) is used, assuming the mass of salt remains constant? b. Explain how q_reaction would be affected if a greater amount of surrounding solvent (water) is used? Explain. If the following enthalpies are known: A + 2B rightarrow 2C + D delta H = -95 kJ B + X rightarrow C delta H = +50kJ What is delta H for the following reaction? A rightarrow 2X + D

Answers

ΔH for the reaction A → 2X + D is +5 kJ.

a. If a greater amount of surrounding solvent (water) is used, the delta T will decrease.

This is because the specific heat capacity of water is much higher than the solute, so a greater amount of water will absorb more heat for a given temperature change, resulting in a smaller delta T.

b. The amount of surrounding solvent (water) used does not affect [tex]q_{reaction[/tex]. This is because [tex]q_{reaction[/tex] is a function of the amount of heat released or absorbed by the chemical reaction, and not the amount of surrounding solvent.

To determine ΔH for the reaction A → 2X + D, we can use the Hess's Law. We can add the two given reactions in such a way that the desired reaction is obtained.

A + 2B → 2C + D,

ΔH = -95 kJ

B + X → C,

ΔH = +50 kJ

Multiplying the second equation by 2 gives:

2B + 2X → 2C,

ΔH = +100 kJ

Now we can cancel out C from both reactions, which gives us:

A + 2B + 2X → D,

ΔH = -95 kJ + (+100 kJ)

    = +5 kJ

Therefore, ΔH for the reaction A → 2X + D is +5 kJ.

To know more about surrounding solvent refer here

brainly.com/question/12568957#

#SPJ11

Other Questions
Scientists believe that some mass extinction events are possibly caused by asteroids, volcanic activity, or climate change. How many mass extinctions have occurred on Earth in the last 4. 6 billion years? 0 1 5 10. Tarshis wroites parish school did not yet have electricity few residents had telephones or radios many including Dillons still drove around in wagon pulled horses why are these details important to the story Create a Max Heap tree given the following input values. {19, 7, 10, 55, 3, 42, 100,8} what are the two major phases of the cell cycle Unit: Acids, Bases, and Solutions"Properties of Acids and Bases" - WS #3 if a dental film has debris/dark spots on the film what is the most likely cause Describe Rosaleen's journeyto vote at the polling station. In the book of the secret life of bees into which category of hazardous materials do weapons of mass destruction, which utilize chlorine gas, fall? TRUE/FALSE.to avoid damaging the dna isolate, a glass rod is used and spun in one direction Enter the appropriate word or words into each blank to complete the following statements about RNA synthesis. A. DNA sequence that directs binding of RNA polymerase for transcription of a downstream gene is called a B. After transcription of eukaryotic genes, from the new RNA molecule, while together during the process called sequences are removed sequences are stitched c. Mature eukaryotic messenger RNAs (mRNAs) have a 5'- and 3'-end structures known as a , respectively, that are absent from prokaryotic mRNAs. and to D. In addition to using different substrates (rNTPs rather than dNTPs), RNA polymerases differ from DNA polymerases in that they do not require a initiate de novo synthesis of RNA and do not have activity, which is responsible for error correction. this storefront design feature is characterized by its flexibility and low cost. (True or False) test the series for convergence or divergence. [infinity] n25n 1 (6)n n = 1 Answer the following questions by decoding the following LC-3 instruction: Ox957F A. Classify the instruction, 8. What, if any. is the location of the instruction's source 1 operand? C. What, it any, is the location of the instruction's source 2 operand? D. What, if any, is the addressing mode used to determine the effective address? E. What, If any, is the location of the instruction's destination operand? "The world will little note, nor long remember what we say here, but it can never forget whatthey did here. It is for us, the living, rather, to be dedicated here to the unfinished work which they who fought here have thus far so nobly advanced. It is rather for us to be here dedicated to the great task remaining before us-that from these honoured dead we take increased devotion to that cause for which they here gave the last full measure of devotion-that we here highly resolve that these dead shall not have died in vain-that thisnation, under God, shall have a new birth of freedom, ... .1. According to Abraham Linclon, what will the world remember?(a) His speech about freedom.(c) The fight for freedom from slavery.(d) The number of people who died in the battlefield.(b) His dedication towards America. Cathy is making a frame for a circular radius problem. The radius of the project is 3. 5 inches. How long will the frame be? You must create a password for a website. The password can use any digitsfrom 0 to 9 and/or any letters of the alphabet. The password is not casesensitive. A password must be at least 6 characters to a maximum of 8characters long. Each character can be used only once in the password.How many different passwords are possible? a. briefly explain the concept of a balanced scorecard. what general factors are included in a typical balanced scorecard? Keith and Cross were employees of CBS. They told their supervisor, Jacobson, about their idea of forming an independent company to provide video promotion spots. Jacobson was in charge of selecting outside vendors and told them he thought they could get a contract with CBS. An exclusive contract was approved by Jacobson and his supervisor. Keith and Cross agreed to remain until their replacements could be hired. The next day Jacobson asked them to "help him out" because he had helped them and asked for $500 per month. Although distressed and shocked, they agreed because Jacobson could fire them or kill the contract once they left; they felt intimidated and that they had no alternative but to agree. They made three payments and then Jacobson demanded $1,000 per month. When they could not pay, Jacobson raised problems with their work, and the contract was likely to be cancelled. At this point they told CBS about the demands, and Jacobson was fired. A few months later their contract was canceled on the basis of "admitted wrongdoing." Keith and Cross sued for economic duress. Will they be successful? Why or why not. (MC) in this speech, Roosevelt termed, for the first time, journalists as muckrakersMuck-rake-n. A rake for scraping up muck or dungMuckrake-v. To search out and publicly expose real or apparent misconduct of a prominent individual or businessSATURDAY, APRIL 14, 1906In Bunyan's Pilgrim's Progress you may recall the description of the Man with the Muck-rake, the man who could look no way but downward, with the muck-rake in his hand, who was offered a celestial crown for his muck-rake, but whowould neither look up nor regard the crown he was offered, but continued to rake to himself the fith of the floor.In Pilgrim's Progress the Man with the Muck-rake is set forth as the example of him whose vision is fixed on camal instead of on spiritual things. Yet he also typifies the man who in this life consistently refuses to see aught that is lofty.and fixes his eyes with solemn intentness only on that which is vile and debasing Now, it is very necessary that we should not finch from seeing what is vile and debasing. There is fith on the floor and it must be scraped up with themuck-rake, and there are times and places where this service is the most needed of all the services that can be performed. But the man who never does anything else, who never thinks or speaks or writes, save of his feats with themuck-rake, speedily becomes, not a help to society, not an incitement to good, but one of the most potent forces for evitThere are, in the body politic, economic and social, many and grave evils, and there is urgent necessity for the stemest war upon them. There should be relentless exposure of and attack upon every evil man whether politician orbusiness man, every evil practice, whether in politics, in business, or in social life. I hall as a benefactor every writer or speaker, every man who, on the platform, or in book, magazine, or newspaper, with merciless severity makes suchattack, provided always that he in his tum remembers that the attack is of use only if it is absolutely truthful. To assall the great and admitted evils of our political and industrial life with such crude and sweeping generalizations as toinclude decent men in the general condemnation means the searing of the public conscience. There results a general attitude either of cynical belief in and indifference to public corruption or else of a distrustful inability to discriminatebetween the good and the bad. Either attitude is traught with untold damage to the country as a whole. The fool who has not sense to discriminate between what is good and what is bad is well-nigh as dangerous as the man who doesdiscriminate and yet chooses the bad. There is nothing more distressing to every good patriot, to every good American, than the hard, scoffing spirt which treats the allegation of dishonesty in a public man as a cause for laughter Suchlaughter is worse than the cracking of thoms under a pot, for it denotes not merely the vacant mind, but the heart in which high emotions have been choked before they could grow to frutionRead this line from the textNow, it is very necessary that we should not finch from seeing what is vile and debasing. There is fith on the floor and it must be scraped up with the muck-rakeWhat purpose does this line serve in the text?OIt makes Roosevelt seem as if he's considered both sides of the issue.O it conveys Roosevelt's understanding of the terms history.Oft sets up the discussion of the definition of muck rakeO it creates tension between the issue of honesty and the methods of protecting t (1 point) use cylindrical coordinates to evaluate the triple integral ex2 y2dv, where e is the solid bounded by the circular paraboloid z=116(x2 y2) and the xy -plane