2. Lin solved a quadratic equation by factoring and found one solution to be x = 3/4.
Which of the following expressions could have been one of her factors?
A.x-3
B. 4x +3
C. 3x – 4
D. 3x +4

Answer:

<BAC=1/2 <BOC=1/2 X=X/2(INSCRIBED ANGLE IS HALF OF CENTRAL ANGLE)

What kind of math is this?

Answer:

[tex]P(B') = 0.77[/tex]

Step-by-step explanation:

Given

[tex]P(A) = 0.23[/tex]

[tex]P(A\ n\ B) = 0.12[/tex]

[tex]P(A\ u\ B) = 0.34[/tex]

Required

Find P(B')

First, we calculate P(B).

We have:

[tex]P(A\ n\ B) = P(A) + P(B) - P(A\ u\ B)[/tex]

Substitute values

[tex]0.12 = 0.23 + P(B) - 0.34[/tex]

[tex]0.12 = 0.23 - 0.34 + P(B)[/tex]

Collect like terms

[tex]P(B) = 0.12 - 0.23 + 0.34[/tex]

[tex]P(B) = 0.23[/tex]

P(B') is then calculated as:

[tex]P(B') = 1 - P(B)[/tex]

[tex]P(B') = 1 -0.23[/tex]

[tex]P(B') = 0.77[/tex]

Answer:

Buying Groceries, paying for a house, maybe in your job, doing schoolwork of course, and counting money.

Step-by-step explanation:

Answer:

1. you use it to calculate time (managing your day)

2. you use it while driving (use in angles and degrees)

3. you use it while drawing (again, use in angles and degrees)

4. you use it while cooking

5. you use it while banking (financial help)

Step-by-step explanation:

hope this helps:) please mark brainliest

Answer:

73

Step-by-step explanation:

Probably

Sure it good I have this question on my test

Step-by-step explanation:

$9 because 1 third of 3 third would be $3

Answer:

B. (3,2)

Step-by-step explanation:

Step 1) When shifting from A(1,2) to B(4,4), the point shifted 3 units to the right (which means x=3) and 2 units upwards (which means y=2).

Step 2) So when you apply the same movements to point C(0,0), the new point will be (3,2).

See the diagram below. Step 1 is the graph on the left. Step 2 is the graph on the right. The movement is colored in green. Hope this helps!

y=x^2
substitute the values into the original equation
0=4^2
0=16
No it does not satisfy the equation because 0 does not equal to 16

Answer:

2

Step-by-step explanation:

hope this helps

please give brainliest. Thanks! :)

Following order of operations:

3^2 = 9

(10-2) = 8

Now you have :

9 + 8 x 5 -4

Multiplication is next:

9 + 40 -4

Now just add and subtract from left to right:

9 + 40 = 49

49-4 = 45

The answer is 45

Step-by-step explanation:

So first you solve whats inside of the parenthesis 10 -2 aand get 8 then you figure 3^2 which is 9 then multiplie 8 times 5 and get 40. 9 + 40 - 4 is what it is so far then add 9 to 40 which is 49 then subtract 4 and get 45!

Answer:

45 dollar's ezzzzzzzzzzzzz

1 - 0.082 = 0.918
Multiply by 0.918

Answer:

3000

Step-by-step explanation:

100%-> 5000

60%->3000

Answer:

8(34a-1)

Step-by-step explanation:

Hope this helps :)

Answer:

8(34a-1)

Step-by-step explanation:

Step-by-step explanation:

whatever amount her bank account balance is at the same time frame when paying off her loan as only her bank knows

Answer:37.5

Step-by-step explanation:

Answer:

37.5

Step-by-step explanation:

Answer:

-26, -29, -32

Have a great day!

Step-by-step explanation:

Sorry don’t know
Joking so i will round to 1 sig fig
So 60 and 10 product is times
60x10=600
when estimating say what you are rounding to

Answer:

low

Step-by-step explanation:

Answer: TRUE!

Step-by-step explanation: Hope this helps!

Answer: True

Step-by-step explanation:

Answer:

-5 3/5

Step-by-step explanation:

John's error was in adding the whole number and fractional portions separately, the fractions must be converted to improper fractions with common denominators to be added or subtracted properly so

(-7 4/5) + (2 1/5), convert to improper fractions

-39/5 + 11/5, both fractions have common denominator so we can continue

-39 + 11 = -28, so -39/5 + 11/5 = -28/5, convert back to proper fractions

-28/5 = (-25/5) + (-3/5) = -5 3/5

Answer: Constant of proportionality is $6 for one pair and cost of dry cleaning 11 pairs of pants is $66.

11 pairs of pants would equal $66

$18/3=6
$6 per one pair of pants
6 times 11= 66
$66

Hope this helps! Have a great day :)

Answer:

b) 200

Step-by-step explanation:

The correct answer is b) 200

1) El IVA del balón es de $ 20.

2) El precio final del balón es $ 145.

1) El Impuesto al Valor Agregado (IVA) es un impuesto indirecto que se aplica sobre el precio de compra del artículo comprado, es decir, se trata de un impuesto indirecto al consumo.

El porcentaje por concepto del impuesto varía de país en país. No obstante, el valor más común en países hispanoparlantes se ubica en torno al 16 % del precio de compra del artículo.

El IVA del balón se determina mediante la siguiente operación aritmética:

[tex]\Delta C = 0.16\cdot (125)[/tex]

[tex]\Delta C = 20[/tex]

El IVA del balón es de $ 20.

2) El precio final del producto es la suma del precio de compra y el IVA, es decir:

[tex]C = 125 + 20[/tex]

[tex]C = 145[/tex]

El precio final del balón es $ 145.  

Para aprender más sobre impuestos, invitamos cordialmente a ver esta pregunta verificada: https://brainly.com/question/24907444

Nota - El enunciado reporta numerosos errores tipográficos y está incompleto, el enunciado correcto y completo es el siguiente:

Un balón de fútbol tiene un precio de $ 125 + IVA.

1) ¿Cuánto es el IVA del balón? a) 20, b) 145, c) 325

2) ¿Cuál es el precio final con IVA del balón? a) 125, b) 200, c) 145

Answer:

for stunt performers and this is lady's work ( paragraph 6)

Answer:

d = 17

Step-by-step explanation:

The given arithmetic sequence is :

31, 48, 65, 82, ...

We need to find the common difference for this sequence.

First term, a₁ = 31

Second term, a₂ = 48

Common difference = a₂-a₁

= 48-31

= 17

So, the common difference for this arithmetic sequence is equal to 17.

Answer:

red

Step-by-step explanation:

1/2 is larger than 1/4, 1/6, and 1/12 meaning the chance of pulling red is greater than getting blue, green, or yellow.

hope i helped you!

Answer:

x_<2

Step-by-step explanation:

its shaded in so you have to flip it

Answer:

The answer is

x_<2

The circle is shaded and the arrow is going to the left hand side

Answer:

[tex]\displaystyle \frac{1}{144}arctan(\frac{9x}{2}) + \frac{x}{8(81x^2 + 4)} + C[/tex]

General Formulas and Concepts:

Alg I

Terms/CoefficientsFactorExponential Rule [Dividing]: [tex]\displaystyle \frac{b^m}{b^n} = b^{m - n}[/tex]

Pre-Calc

[Right Triangle Only] Pythagorean Theorem: a² + b² = c²

a is a legb is a legc is hypotenuse

Trigonometric Ratio: [tex]\displaystyle sec(\theta) = \frac{1}{cos(\theta)}[/tex]

Trigonometric Identity: [tex]\displaystyle tan^2\theta + 1 = sec^2\theta[/tex]

TI: [tex]\displaystyle sin(2x) = 2sin(x)cos(x)[/tex]

TI: [tex]\displaystyle cos^2(\theta) = \frac{cos(2x) + 1}{2}[/tex]

Calc

Integration Rule [Reverse Power Rule]:                                                                [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

IP [Addition/Subtraction]:                                                             [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

U-Substitution

U-Trig Substitution: x² + a² → x = atanθ

Step-by-step explanation:

Step 1: Define

[tex]\displaystyle \int {\frac{dx}{(81x^2 + 4)^2}}[/tex]

Step 2: Identify Sub Variables Pt.1

Rewrite integral [factor expression]:

[tex]\displaystyle \int {\frac{dx}{[(9x)^2 + 4]^2}}[/tex]

Identify u-trig sub:

[tex]\displaystyle x = atan\theta\\9x = 2tan\theta \rightarrow x = \frac{2}{9}tan\theta\\dx = \frac{2}{9}sec^2\theta d\theta[/tex]

Later, back-sub θ (integrate w/ respect to x):

[tex]\displaystyle tan\theta = \frac{9x}{2} \rightarrow \theta = arctan(\frac{9x}{2})[/tex]

Step 3: Integrate Pt.1

[Int] Sub u-trig variables:                                                                                 [tex]\displaystyle \int {\frac{\frac{2}{9}sec^2\theta}{[(2tan\theta)^2 + 4]^2}} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                           [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[(2tan\theta)^2 + 4]^2}} \ d\theta[/tex][Int] Evaluate exponents:                                                                                [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4tan^2\theta + 4]^2}} \ d\theta[/tex][Int] Factor:                                                                                                      [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4(tan^2\theta + 1)]^2}} \ d\theta[/tex][Int] Rewrite [TI]:                                                                                              [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{[4sec^2\theta]^2}} \ d\theta[/tex][Int] Evaluate exponents:                                                                                [tex]\displaystyle \frac{2}{9} \int {\frac{sec^2\theta}{16sec^4\theta} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                          [tex]\displaystyle \frac{1}{72} \int {\frac{sec^2\theta}{sec^4\theta} \ d\theta[/tex][Int] Divide [ER - D]:                                                                                         [tex]\displaystyle \frac{1}{72} \int {\frac{1}{sec^2\theta} \ d\theta[/tex][Int] Rewrite [TR]:                                                                                            [tex]\displaystyle \frac{1}{72} \int {cos^2\theta} \ d\theta[/tex][Int] Rewrite [TI]:                                                                                              [tex]\displaystyle \frac{1}{72} \int {\frac{cos(2\theta) + 1}{2}} \ d\theta[/tex][Int] Rewrite [Int Prop - MC]:                                                                          [tex]\displaystyle \frac{1}{144} \int {cos(2\theta) + 1} \ d\theta[/tex][Int] Rewrite [Int Prop - A/S]:                                                                          [tex]\displaystyle \frac{1}{144} [\int {cos(2\theta) \ d\theta + \int {1} \ d\theta][/tex]  

Step 4: Identify Sub Variables Pt.2

Determine u-sub for trig int:

u = 2θ

du = 2dθ

Step 5: Integrate Pt.2

[Ints] Rewrite [Int Prop - MC]:                                                                       [tex]\displaystyle \frac{1}{144} [\frac{1}{2} \int {2cos(2\theta) \ d\theta + \int {1 \theta ^0} \ d\theta][/tex][Int] U-Sub:                                                                                                     [tex]\displaystyle \frac{1}{144} [\frac{1}{2} \int {cos(u) \ du + \int {1 \theta ^0} \ d\theta][/tex][Ints] Integrate [Trig/Int Rule - RPR]:                                                             [tex]\displaystyle \frac{1}{144} [\frac{1}{2} sin(u) + \theta + C][/tex][Expression] Back Sub:                                                                                 [tex]\displaystyle \frac{1}{144} [\frac{1}{2} sin(2 \theta) + arctan(\frac{9x}{2}) + C][/tex][Exp] Rewrite [TI]:                                                                                           [tex]\displaystyle \frac{1}{144} [\frac{1}{2}(2sin(\theta)cos(\theta)) + arctan(\frac{9x}{2}) + C][/tex][Exp] Multiply:                                                                                                 [tex]\displaystyle \frac{1}{144} [sin(\theta)cos(\theta) + arctan(\frac{9x}{2}) + C][/tex][Exp] Back Sub:                                                                                             [tex]\displaystyle \frac{1}{144} [sin(arctan(\frac{9x}{2}))cos(arctan(\frac{9x}{2})) + arctan(\frac{9x}{2}) + C][/tex]

Step 6: Triangle

Find trig values:

[tex]\displaystyle tan\theta = \frac{9x}{2}[/tex]

[tex]\displaystyle \theta = arctan(\frac{9x}{2})[/tex]

tanθ = opposite / adjacent; solve hypotenuse of right triangle, determine trig ratios:

sinθ = opposite / hypotenuse

cosθ = adjacent / hypotenuse

Leg a = 2

Leg b = 9x

Leg c = ?

Sub variables [PT]:                                                                                         [tex]\displaystyle 2^2 + (9x)^2 = c^2[/tex]Evaluate exponents:                                                                                      [tex]\displaystyle 4 + 81x^2 = c^2[/tex][Equality Property] Square root both sides:                                                  [tex]\displaystyle \sqrt{4 + 81x^2} = c[/tex]Rewrite:                                                                                                           [tex]c = \sqrt{81x^2 + 4}[/tex]

Substitute into trig ratios:

[tex]\displaystyle sin\theta = \frac{9x}{\sqrt{81x^2 + 4}}[/tex]

[tex]\displaystyle cos\theta = \frac{2}{\sqrt{81x^2 + 4}}[/tex]

Step 7: Integrate Pt.3

[Exp] Sub variables [TR]:                                                                               [tex]\displaystyle \frac{1}{144} [\frac{9x}{\sqrt{81x^2 + 4}} \cdot \frac{2}{\sqrt{81x^2 + 4}} + arctan(\frac{9x}{2}) + C][/tex][Exp] Multiply:                                                                                                 [tex]\displaystyle \frac{1}{144} [\frac{18x}{81x^2 + 4} + arctan(\frac{9x}{2}) + C][/tex][Exp] Distribute:                                                                                             [tex]\displaystyle \frac{1}{144}arctan(\frac{9x}{2}) + \frac{x}{8(81x^2 + 4)} + C[/tex]

Answer:

The bullet reaches a height of 4000 feet after 6.49 seconds, and then, coming back down, after 38.5 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]\bigtriangleup = b^{2} - 4ac[/tex]

The height of the bullet after t seconds is given by:

[tex]h(t) = -16t^2 + 720t[/tex]

When does the bullet reach a height of 4,000 feet?

This is t for which [tex]h(t) = 4000[/tex]. So

[tex]4000 = -16t^2 + 720t[/tex]

[tex]16t^2 - 720t + 4000 = 0[/tex]

Dividing by 16

[tex]t^2 - 45t + 250 = 0[/tex]

So [tex]a = 1, b = -45, c = 250[/tex]

[tex]\bigtriangleup = b^{2} - 4ac = (-45)^2 - 4(1)(250) = 1025[/tex]

[tex]t_{1} = \frac{-(-45) + \sqrt{1025}}{2} = 38.5[/tex]

[tex]t_{2} = \frac{-(-45) - \sqrt{1025}}{2} = 6.49[/tex]

The bullet reaches a height of 4000 feet after 6.49 seconds, and then, coming back down, after 38.5 seconds.

Answer:

300

Step-by-step explanation:

if you mean, 245.320