2. The equation of the line graphed below could be which of the following?
(1) y=-2x+7
(2) y = 4x+3
(3) y=1/2x-6
(4) y=3/2x-1

Answer:

Hope This Helps!!

it's not perfect.. but we get the idea...

Answer: He is Incorrect, It's 38

Work: For this question, I did the Cross-Product Method. The Cross Product Method is when you solve equation via to fractions. With the CPM, One one side of the fraction, I had x / 20 (Twenty being the whole number) and on the other side, I had 190/100 (190 being the percent) After setting this up, I made the equation. 190 times 20 is 3800, and the other multiplication is 100 times x which is 100x. So, the new equation is 3800 = 100x. I divided both sides by 100, and the answer is 38 = x

I hope this helps, and Happy Holidays! :)

Answer:

No, Marcus is not correct. He converted the percent to a decimal correctly and he multiplied correctly, but he put the decimal in the wrong place in the answer. There should be two decimal places in the answer, so the answer should be 38.

Step-by-step explanation:

I took the assingment in edge 2020

Answer: -1/2

Step-by-step explanation: whenever a line is perpendicular you take the opposite reciprocal of the current slope.

Hello!

Perpendicular lines have slopes that are opposite reciprocals.

It means we take a number, flop it over and then make it negative.

So if we have 2, we flop it over:

[tex]\frac{1}{2}[/tex]

Then, we make it negative:

[tex]-\frac{1}{2}[/tex]

That is the slope. Hope it helps

If you have any query, please ask me! :)

~A forlorn girlie

[tex]MagicalNature[/tex]

Answer: Andy completed 7 problems.

Step-by-step explanation:

Answer:

its 44

Step-by-step explanation:

180=46+90+x

180=136+x

44=x

Answer:

k=8

Step-by-step explanation:

For 2 lines to be parallel, they must have the same slope. First, let's isolate y.

5y=2x+2

y=2/5x+2/5

Now, in our second equation, we must make it so that the slope is 2/5.

5(4)=20

2(4)=k

k=8

y=8/20x+10

If you simplify that, then the slope will be 2/5.

Answer:

reflect over x axis

x+3  y+3

Step-by-step explanation:

Answer:

I think A  but if im wrong tell me sorry if it wrong

Step-by-step explanation:

Answer:

8 is 2 answers. the answer is A

Answer:

A: 0

B: pi/3

E: 5pi/3

Step-by-step explanation:

The solution to the trigonometric equation is 0 , π/3 , 5π/3

Trigonometry is the study of the relationships between the angles and the lengths of the sides of triangles

The six trigonometric functions are sin , cos , tan , cosec , sec and cot

Let the angle be θ , such that

sin θ = opposite / hypotenuse

cos θ = adjacent / hypotenuse

tan θ = opposite / adjacent

tan θ = sin θ / cos θ

cosec θ = 1/sin θ

sec θ = 1/cos θ

cot θ = 1/tan θ

Given data ,

Let the trigonometric equation be represented as A

sin ( x/2 ) + cos ( x ) - 1 = 0

sin ( x/2 ) - ( 1 - cos ( x ) ) = 0

On further simplification , we get

( 1 - cos ( x ) ) = 2sin² ( x/2 )

So , sin ( x/2 ) - 2sin² ( x/2 ) = 0

Taking sin ( x/2 ) as the common factor , we get

sin ( x/2 ) ( 1 - 2sin ( x/2 ) ) = 0

So , the solutions to the equation are

sin ( x/2 ) = 0

x = 0 , 2π

And , ( 1 - 2sin ( x/2 ) ) = 0

sin ( x/2 ) = 1/2

x = π/3 , 5π/3

Hence , the solutions are x = 0 , π/3 , 5π/3

To learn more about trigonometric relations click :

https://brainly.com/question/14746686

#SPJ2

Answer:

-70 so A

Step-by-step explanation:

Answer:

D) 70

Step-by-step explanation:

Here is the correct mathematical way of find a distance between two points on the number line.

Take the absolute value of the difference of their coordinates.

If the points on a number line correspond to coordinates a and b, the distance between the points is

|a - b|

Your problem:

|a - b| = |-57 - 13| = |-70| = 70

The distance is 70.

Answer: D) 70

Answer:

Step-by-step explanation:

              Statements                        Reasons

1). UW bisects ∠VUX               1). Given

2). UW bisects ∠VWX             2). Given

3). ∠VUW ≅ ∠WUX                 3). Definition of angle bisector

4). ∠UWV ≅ ∠UWX                 4). Definition of angle bisector

5). UW ≅ UW                           5). Reflexive property

6). ΔUVW ≅ ΔUXW                 6). ASA postulate of congruence

Answer:

!!!!!!!!!!!!!!!!!!!!!!

Step-by-step explanation:

Answer:

The scale factor is 152,064:1

Step-by-step explanation:

Scaling

The real distance of a race track in Pike is 2.4 miles.

One mile is equivalent to 63,360 inches, thus 2.4 miles = 152,064 inches.

On a map, that very same distance is represented as 1 inch. Thus the scale factor is 152,064:1

This means every inch on the map is equivalent to 152,064 inches on the race track.

Answer:

1.

Step-by-step explanation:

The line goes through positive 2

Answer:

2

Step-by-step explanation:

the slope has to intercept at y=2 and slope is rise over run so you would go up 1 and over 2.

Answer:

y=-1x-6

Step-by-step explanation:

you can also use y=-x-6 but its your choice

Answer:

C. Positive 6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

because we find the reciprocal and 9 divided by -3 and 8 divided by -4

9 divided by -3 is  -3 and 8 divided by -4 is -2

so -3 times -2 is 6

Answer:

-1/2 is m and 3 is b

Step-by-step explanation:

-1/2 is the slope and 3 is the y-intercept,

Answer:

Step-by-step explanation:

The slope m is -1/2

The y-int b is 3

Since the slope is negative the graph should start from the top left and should go down all the way down to the bottom right. The line should also pass the point (0,3) since 3 is the y-int

Answer:

x = 1

Step-by-step explanation:

Answer:

[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]

Therefore;

[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]

Step-by-step explanation:

Given that we have;

[tex]x^2 - 2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} }[/tex]

[tex]x^2 = 3 ^{\frac{2}{3} } + 3 ^{-\frac{2}{3} } + 2 = \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]

[tex]x^2 = 3 ^{-\frac{2}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )[/tex]

[tex]x = 3 ^{-\frac{1}{3} } \times \left ( 3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \sqrt{ \dfrac{3 ^{\frac{4}{3} } + 1 + 2 \times 3 ^{\frac{2}{3} }}{3 ^{\frac{2}{3} } } } = \left ( \dfrac{3 ^{\frac{4}{3} } + 2 \times 3 ^{\frac{2}{3} } + 1}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} }[/tex]

[tex]x = \left ( \dfrac{ \left (3 ^{\frac{2}{3} } + 1 \right ) ^2}{3 ^{\frac{2}{3} } } \right )^{\frac{1}{2} } =\dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} = 3 \cdot x + \dfrac{10}{3} = 3 \times \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } +\dfrac{10}{3} = \dfrac{ 3 ^{\frac{5}{3} } + 3 }{3 ^{\frac{1}{3} } } + \dfrac{10}{3}= \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } }[/tex]

[tex]\dfrac{9 \cdot x + 10}{3} =\dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{2}{3} }\times3+ 10 }{3 } } } = \dfrac{ 3 ^{\frac{7}{3} } + 3 ^{\frac{5}{3} }+ 10 }{3 } } } = \left ( \dfrac{ 3 ^{\frac{2}{3} } + 1 }{3 ^{\frac{1}{3} } } \right )^3 } = x^3[/tex]

Therefore;

[tex]x^3 = \dfrac{9 \cdot x + 10}{3}[/tex]

[tex]x = \sqrt[3]{\dfrac{9 \cdot x + 10}{3}}[/tex]

Answer:

Each piece weighed 1/10 of a pound.

Step-by-step explanation:

We have 3/5 of a pound and we want to divide it by 6 equal pieces for each student. 6 equal pieces is the same as 6/1.

In order to divide 3/5 by 6/1 we need to invert the 6/1 and multiply. So, it becomes 3/5 x 1/6. First, we multiply the numerators: 3x1=3 then we multiply the denominators: 5x6=30. The result is 3/30, which can be reduced by dividing both the numerator and denominator by 3. 3/3=1 and 30/3=10. So, the result is 1/10.

Answer:

Option A

Step-by-step explanation:

for right angle triangle a²+b²= c²

60²+80²= 10000

√10000= 100

hope it helps!

AAAAAAAAAAAAAAAAAAAA

The answer A.

A as in Apple.

Answer:

slope: 7/2

y-int: (0, -5)

(0, -5) (10/7, 0)

Answer:

8

Step-by-step explanation:

since u first do six + 8 which is 14. Then u do 14 - 4 which is 10

Plz mark as brainliest

Answer:

x=2

Step-by-step explanation:

x = the number

x + 6 = 6x - 4

Solve for x and get

5x = 10

Answer:

3.514 degrees per hour

Step-by-step explanation:

To find change per hour, you find the slope, which is change in output (temperature) over change in input (hours)

y2-y1 / x2-x1

-12.3 - 0 / 3.5

3.514 degrees per hour

Answer:

True

Step-by-step explanation:

ed 2020. I went back to check the answer so 100% right.

Answer:

tru

Step-by-step explanation:

Answer:

6 days

Step-by-step explanation:

Given that Reilly works every other day (This means that she works every 2 days) while Samantha works every third day. Today both of them are working together.

The next day none of them will be working, on the second day only Reilly would be working, on the third day only Samantha would be working, on the fourth day only Reilly would be working, on the fifth day none will be working and on the sixth day both Reilly and Samantha would be working.

This is the same as finding the least common multiple (LCM) of 2 days and 3 days which is 6 days