20 POINTS! NEED HELP!!!
When naming covalent bonds, do all of the following except?
1. use prefixes
2. write the left-most element first
3. add -ide to the end of the 2nd element
4. write the metal first

Answers

Answer 1

Answer:

number 2

Explanation:

even though i have never done this i still got it right

Answer 2

Because metals do not form covalent bonds, when naming covalent bonds, all the given rules apply except write the metal first; option 4.

What are covalent bonds?

Covalent bonds are bonds formed by the sharing of valence electrons between the atoms involved in the bonding.

In naming covalent bonds, the following rules are applied:

Name the non-metal furthest to the left on the periodic table by its elemental name.Name the other non-metal by its elemental name and an -ide ending.Use the prefixes mono-, di-, tri-, tetra etc. to indicate the number of that element in the molecule.If the first prefix is mono, it is not written add -ide to the end of the second element

For example, CO₂, is carbon dioxide.

Therefore, when naming covalent bonds, all the given rules apply except write the metal first because metals do not form covalent bonds.

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Related Questions

What types of energy do lamps give off?
Include how was your day in you answer.
Explain why/if the lamp gives off heat energy.

Answers

Answer:

When a lamp is turned on, it gives off light energy and heat energy.

My day was fantastic.

Explanation:

The lamp gives off heat energy because anything that gives off light energy gives off heat energy.


Several properties of water are shown. Classify each property as a physical property or a chemical property.

-can be split into hydrogen and oxygen
-is liquid at room temperature
-has a density of 1.0 g/cm³
-reacts with certain metals

ASAP

Answers

Chemical property:

Can be split into hydrogen and oxygenReacts with certain metals

Physical property:

Is liquid at room temperatureHas a density of 1.0 g/cm³

Determine if the bond between atoms in each example below is nonpolar covalent, polar covalent, or ionic a. H-H b. P-Cl c. F-F d. Na-Br e. N-F f. Mg-O g. C-H h. H-Cl

Answers

Answer:

a nonpolar covalent

b polar

c nonpolar

d ionic

e. polar

f. ionic

g polar

h polar

Explanation:

The image shown here is a good illustration of which law?

Answers

Answer:

A.) Newton's First Law

Explanation:

I'm pretty sure, I'm sorry if I'm wrong, I just looked it up on G o o g l e

I need help ASAP pls

Answers

Answer:

A  should be the swer n

Explanation:

plzzzzzzz help asap its just one question plzzzzz its in the file <3

Answers

Answer:

There are 6 atoms of oxygen in 2Ca(NO3)2

A heterogeneous ore mixture contains 35.0 % In2O3 by mass. How many tons of the ore must be mined to provide 325.0 kg of indium metal? (2000 lb = 1 ton, assume exact)

Answers

Answer:

1.2375 ton of ore

Explanation:

Mass of indium = 325

Formula = In2O3

Molar mass = 277.64 g/mol

Molar mass of indium = (2*114.8)g

229.6 indium is in 277.64 of In2O3

Mass of In2O3 required = 277.64/229.6 x 325

= 392.94kg

35 % In2O3 in ore

For 35 kg = 100 kg required

For 392.94,

100/35 x 392.94

= 1122.686 kg

1122.68 x 2.2

= 2469.9 pounds

2469.9/200

= 1.235 tons of ore

What does cellular respiration do?
Break down sugar and release energy for an
organism to use
Create sugar filled with energy
Deter predators
Form glucose from hydrogen, oxygen, and carbon
:D
help asap

Answers

I believe the answer is A the 1st one

what is valence electron configuration for group 4A (14)

Answers

Answer:

The group 14 elements all have ns2np2 valence electron configurations. All form compounds in which they formally lose either the two np and the two ns valence electrons or just the two np valence electrons, giving a +4 or +2 oxidation state, respectively

Explanation:

Answer:

The group 14 elements all have ns2np2 valence electron configurations. All form compounds in which they formally lose either the two np and the two ns valence electrons or just the two np valence electrons, giving a +4 or +2 oxidation state, respectively.

Explanation:

Compare and contrast electron behavior in Rutherford’s, Bohr’s, and the quantum models

Answers

Rutherford’s, Bohr’s, and the quantum models say that electrons behave as particles,  electron is negatively charged and electrons behave both particles and wave respectively.

What Rutherford’s, Bohr’s, and the quantum models say about electron?

Bohr model states that electrons behave as particles, Rutherford's model proposed that the negatively charged electrons surround the nucleus of an atom whereas quantum model explains that the electron has both particle and wave behavior.

So we can conclude that Rutherford’s, Bohr’s, and the quantum models say that electrons behave as particles,  electron is negatively charged and electrons behave both particles and wave respectively.

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Aqueous sulfuric acid (H2SO4) will react with solid sodium hydroxide (NaOH) to produce aqueous sodium sulfate (Na2SO4) and liquid water (H2O). Suppose 5.88g of sulfuric acid is mixed with 6.3 g of sodium hydroxide. Calculate the maximum mass of water that could be produced by the chemical reaction. Round your answer to 3 significant digits

Answers

Answer:

2.16 g H₂O

Explanation:

Since we are not given the limiting reagent, we need to convert both reactants into the product. The actual amount of product will be the smaller mass produced.

To find the answer, we need to (1) convert grams reactant to moles reactant (via molar mass), then (2) convert moles reactant to moles H₂O (via mole-to-mole ratio from balanced equation coefficients), and then (3) convert moles H₂O to grams H₂O (via molar mass). It is important to arrange the ratios in a way that allows for the cancellation of units.

The balanced equation:

1 H₂SO₄(aq) + 2 NaOH(s) -----> 1 Na₂SO₄(aq) + 2 H₂O(l)

Molar Mass (H₂SO₄): 2(1.008 g/mol) + 32.065 g/mol + 4(15.998 g/mol)

Molar Mass (H₂SO₄): 98.073 g/mol

Molar Mass (NaOH): 22.990 g/mol + 15.998 g/mol + 1.008 g/mol

Molar Mass (NaOH): 39.996 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol

Molar Mass (H₂O): 18.014 g/mol

5.88 g H₂SO₄           1 mole              2 moles H₂O            18.014 g
----------------------  x  -----------------  x  ------------------------  x  -----------------  =  
                                98.073 g            1 mole H₂SO₄           1 mole

=  2.16 g H₂O

6.3 g NaOH            1 mole              2 moles H₂O              18.014 g
--------------------  x  -----------------  x  --------------------------  x  ----------------  =
                              39.996 g           2 moles NaOH            1 mole

=  2.84 g H₂O

Since H₂SO₄ produces the smallest amount of product, it is the limiting reagent. In this case, H₂SO₄ is completely used up before NaOH has the chance to react totally. Therefore, the actual amount of H₂O produced is 2.16 g.

What color does red cabbage juice make when mixed with a citrus cleaner?
What color does red cabbage juice make when mixed with a dishwasher soap?
(WILL MARK BRAINLIEST!!!)

Answers

Answer:

Explanation:

green

What kind of reactions takes place between Calcium and EDTA?

Answers

Answer:

Explanation:

:Determination of total calcium and magnesium Ion concentration

Answer:

Ca2+ ions react to form a stronger complex with the EDTA

Explanation:

As a result, when the calcium ion–PR complex is titrated with EDTA the Ca2+ ions react to form a stronger complex with the EDTA. For the titration, the indicator is added to the sample solution containing the calcium ions and forms the pink/red calcium ion-indicator complex (Ca-PR).

A neutral atom has high electronegativity.

Describe what happens to this atom during ionic bond formation.

Answers

Please get it cleared and stored into your cerebrum that a cation is formed when a neutral atom loses one or more electrons from its valence electron shell.

However too, on other hand an anion is formed when a neutral atom gains one or more electrons in its outermost electron shell.

A cation means a positive ion

An anion means a negative ion

What is electronegativity?

Electronegativity is one of physical periodicity and property of elements that describes the tendency of an atom to attract electrons toward itself.

Generally, electronegativity of an atoms of elements in a particular trend is affected by both its atomic number and the distance that its valence electrons reside from the charged nuclei.

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What’s this answer help me out

Answers

Sorry my guy no idea try googling

A methane molecule, CH4, in the stratosphere or (2) a CH3 molecule and a hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH4 molecule.

Answers

The methane molecule in the stratosphere has a higher potential energy than the CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule.

The complete question is:

For each of the following situations, you are asked which of two objects or substances has the higher energy. Explain your answer with reference to the capacity of each to do work and say whether the energy that distinguishes them is kinetic energy or potential energy.

a. (1) A methane molecule, CH4, in the stratosphere or (2) a CH3 molecule and a hydrogen atom formed from breaking one of the carbon-hydrogen bonds in a CH4 molecule.

Which have a higher energy?

The methane molecule in the stratosphere is a stable molecule and possesses chemical potential energy.

The CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule are unstable molecules and possesses kinetic energy. However, some of their energy has been used in breaking the bond.

Thus, the methane molecule in the stratosphere has a higher potential energy than the CH₃ molecule and the hydrogen atom formed from breaking one of the carbon‐hydrogen bonds in a CH₄ molecule.

In conclusion, the energy in the methane molecule is higher.

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In the balanced equation 2C₂H6+ 702 -->4CO2 +6H2O, if 10g of C₂H6 react with
42.5g O₂, what is the limiting reactant?
02
CO₂
H₂O
C₂H6

Answers

Answer:

02

Explanation:

The basic concept of getting this right is to divide the individual coefficient of the reactant by the giving mass. the one with the least value scores the limiting reactant or reagent

Draw the structures of organic compounds A and B. Indicate stereochemistry where applicable The starting material is ethyne, a carbon carbon triple bond where each carbon is bonded to a hydrogen. Step 1 is N a N H 2 followed by 1 equivalent of C H 3 C H 2 C H 2 B r to form compound A. Compound A reacts with hydrogen and lindlar's catalyst to form compound B. COmpound B reacts with H 2 O and H 3 O Plus to form a 5 carbon chain with a hydroxy substituent on carbon 2.

Answers

Answer:

See explanation below

Explanation:

In this case we have the starting reactant which is the ethine, In the first step reacts with NaNH₂, a strong base. This base will substract the hydrogen from one of the carbon of the ethine, and form a carbanion. This will react with the propane bromide, displacing the bromine and forming a 5 carbon chain with the triple bond on the carbon 1 and 2.

In the second step, reacts with the lindlar catalyst to do a reduction, and form a double bond between carbon 1 and 2. In essence, compound A is similar to compound B.

Finally B reacts with water in acid and makes a addition reaction, and form an alcohol.

The whole process can be seen in the picture below.

Hope this helps

Select the correct answer.

A 20.0-liter flask contains a mixture of argon at 0.72 atmosphere and oxygen at 1.65 atmospheres. What is the total pressure in the flask?

A. 0.93 atm
B. 2.37 atm
C. 8.44 atm
D. 18.6 atm​

Answers

Answer:

2.37 atm

Explanation:

0.72+1.65 = 2.37 atm

Write the equation for the acid dissociation, write the Ka expression, solve for Ht concentration, then do an ICE chart. Put the values into the Ka expression (the one you solved for Ht and find Ht, convert to pH and input that to 2 decimal place. Or use the Henderson-Hasselbalch equation:
pH = pka, + log ( Base/Acid)
Calculate the pH of a buffer solution consisting of 0.39 M HA (Ka = 8.8 x 10^-6) and 0.2 M NaA.

Answers

Answer:

The pH of the buffer is 4.77

Explanation:

Using Henderson-Hasselbalch equation we can solve the pH of the buffer:

pH = pKa + log [A⁻] / [HA]

Where pH is the pH of the buffer

pKa is -log Ka = 5.056

[A⁻] = [NaA] = 0.2M

[HA] = 0.39M

Replacing:

pH = 5.056+ log [0.2] / [0.39]

pH = 4.77

The pH of the buffer is 4.77

Explain three types eye protection and their appropriate uses ​

Answers

Answer:

safety glasses, safety goggles, face shield, they protect your eyes from harmful liquids, bright lights

A rock displaces 1.65 L of water. The volume of the rock is:

Answers

Answer:

If a rock displaces 1.65L of water, its volume must be 1.65L.
If you want to convert that to cm^3 it's 1000 cm^3 per liter...so 1650 cm^3

Explanation:

Enthalpy of reaction of nitrogen dioxide (use Hess Law)

N2(g) + 2O2(g) → 2NO2(g)

N2 + O2 → 2NO Hr= +180 kJmol-1
2NO + O2 → 2NO2 Hr= -112 kJmol-1

Starting Point Ending point
N2 (g) + 2O2 (g) → 2NO2 (g)

+180kJ -112kJ
2NO2 + O2 (g)

Use the information to calculate the H and explain how you got your answer.

Answers

Considering the Hess's Law, the enthalpy change for the reaction is 68 kJ/mol.

Hess's Law

Hess's Law indicates that the enthalpy change in a chemical reaction will be the same whether it occurs in a single stage or in several stages. That is, the sum of the ∆H of each stage of the reaction will give us a value equal to the ∆H of the reaction when it occurs in a single stage.

Enthalpy of reaction of nitrogen dioxide

In this case you want to calculate the enthalpy change of:

N₂ + 2 O₂ → 2 NO₂

which occurs in two stages.

You know the following reactions, with their corresponding enthalpies:

Equation 1: N₂ + O₂ → 2 NO     ΔH = 180 kJ/mol

Equation 2: 2 NO + O₂ → 2 NO₂     ΔH = –112 kJ/mol

Because of the way formation reactions are defined, any chemical reaction can be written as a combination of formation reactions, some going forward and some going back.

In this case, first, to obtain the enthalpy of the desired chemical reaction you need one mole of N₂ on reactant side and it is present in first equation so let's write this as such.

In the same way, you need two moles of NO₂ on product side and it is present in second equation so let's write this as such.

Finally, in this way the two moles of NO cancel.

Then, it is not necessary to modify the given equations. So, adding or canceling the reactants and products as appropriate, and adding the enthalpies algebraically, you obtain:

N₂ + 2 O₂ → 2 NO₂     ΔH= 68 kJ/mol

Finally, the enthalpy change for the reaction is 68 kJ/mol.

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In Universe L , recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quantum mechanics works just as it does in our universe, except that there are four d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the third and fourth elements in the first transition series in Universe L .

Answers

Answer:

See explanation

Explanation:

The third element in the first transition series is Vanadium

The fourth element in the first transition series is chromium

Given that we have four d orbitals in universe L instead of five as we have on earth;

The electronic configuration of Vanadium in universe L is;

Ar 3d3 4s2

The electronic configuration of chromium in universe L is;

[Ar] 3d4 4s2

QUESTION 17
A mixture of hydrogen, helium and chlorine gases are in a container. The hydrogen has a partial pressure of 0.74 atm, the helium has a partial
pressure of 1.96 atm, and the chlorine has a partial pressure of 409 mmHg. What is the total pressure of the mixture, in atm?

Answers

Answer:

3.25 atm

Explanation:

convert   409 mm to atm, then add them all :

 409mm  / 760mm/atm   +   .74     + 1.96 = 3.24 atm

The total pressure of the mixture, in atm, is 3.25 atm

A container contains a mixture of hydrogen, helium, and chlorine gases. The partial pressures of the three gases are as follows: 0.74 atm for hydrogen, 1.96 atm for helium, and 409 mmHg for chlorine. 3.25 atm is the mixture's total pressure.

then multiply 409 mm by 1.0 atm, and then combine them all for total pressure :

409mm  / 760mm/atm   +   .74     + 1.96 = 3.24 atm

When more than one gas is present in a container, each gas exerts pressure, which is how atmospheric pressure is defined. Its partial pressure refers to the pressure of any gas inside the container.


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What is the mass of 2.2 moles of magnesium chloride? With work shown

Answers

MgCl2 =24+2*35.5 = 95 g/mol
Mass MgCl2 = (2.2 mol) (95g/mol) =209 g
Can u mark brainliest?
Not sure
m=Mn
m=2.2(no. Of moles)*24.305(from the periodic table)
m=53.471

Why do particles with different masses have the same kinetic energy when at the same temperature?

Answers

Answer: Because Kinetic energy depends on temperature and not mass

Explanation:

Average kinetic energy is defined as the average of the kinetic energies of all the particles present in a system. It is determined by the equation:

[tex]K.E=\frac{3RT}{2}[/tex]

where K.E = Kinetic energy

R= gas constant

T= temperature in kelvin

It is visible that kinetic energy is dependent on the temperature of the system and not on the mass of the system. Thus particles with different masses have the same kinetic energy when at the same temperature

Determine the freezing point depression of a solution that contains 2 moles of NaCl in 200 g of water. ( Kf = 1.86°C/m and Kb = 0.512°C/m.)

Answers

The freezing point depression of a solution that contains 2 moles of NaCl in 200 g of water (Kf = 1.86 °C/m) is 18.6 °C.

What is the freezing point depression?

It is a decrease in the freezing point of a solution, in comparison with the pure solvent.

Step 1. Determine the molality of the solution.

The solution contains 2 moles of NaCl in 200 g of water.

b = moles NaCl / Kg water = 2 mol/0.200 kg = 10 m

Step 2. Calculate the freezing point depression.

Given the cryoscopic constant (Kf) is 1.86 °C/m for water, the freezing point depression (ΔT) is:

ΔT = Kf × b = 1.86 °C/m × 10 m = 18.6 °C

The freezing point depression of a solution that contains 2 moles of NaCl in 200 g of water (Kf = 1.86 °C/m) is 18.6 °C.

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an analyst prepared a sucrose solution by weighing 1kg of water and add 1.5kg sucrose. estimate the concentration of the resultant solution in degree brix

Answers

The concentration of the solution is 60 degrees Brix.

What is degree Brix?

Degrees Brix is the sugar content of an aqueous solution. One degree Brix is 1 gram of sucrose in 100 grams of solution and represents the strength of the solution a as percentage by mass.

Mass percent refers to the percentage of solute present in the solution.

The concentration of the substance can be expressed in mass percent.

we have to first calculate mass percent.

So, we can write,

Mass percent = mass of solute / mass of solution x 100.

Mass of solution = mass of solute + solvent.

Here, sucrose is the solute and the water is the solvent.

The mass of the solute is 1.5Kg and the mass of the solvent is 1Kg.

Mass of solution = 1.5 + 1 = 2.5 Kg.

Mass percent = 1.5/2.5x100

Mass percent is 60%.

Here, 1% = 1 degree brix.

So here, 60% = 60 degree brix.

Hence, the concentration of the solution is 60 degree brix.

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Which substance is not a solid at 20˚C and one atmosphere of pressure?
A. Kr
B. U
C. K
D. Ag

Answers

Choose A, Kr is noble gas
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