Answer:
24g > 1,679mgGauri Spends 0.75 of her salary every month if she earns rs 12000 per month in how many months will she save rupees 39000
Answer:
13 months--------------------
If Gauri spends 0.75 of her salary every month, that means she saves 0.25 of her salary:
0.25 * 12000 = 3000Divide the total 39000 by her monthly savings:
39000 / 3000 = 13So it will take Gauri 13 months to save rupees 39000.
evaluate 5x - 2y + 4z when x=3 , y=2 and z=4 (a)5 (b) 16 (c) 27 (d) 20
When x = 3, y = 2, and z = 4, the value of the expression 5x - 2y + 4z is 27.
The correct answer is (c) 27.
To evaluate the expression 5x - 2y + 4z when x = 3, y = 2, and z = 4, we substitute the given values into the expression and perform the arithmetic calculations. Here's the step-by-step process:
Step 1: Replace x with 3, y with 2, and z with 4 in the expression:
5(3) - 2(2) + 4(4)Step 2:
Perform the multiplications first:
15 - 4 + 16
Step 3: Perform the additions and subtractions from left to right:
15 - 4 + 16 = 11 + 16 = 27.
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Math
Language arts
Seventh grade> Y.7 Circles: word problems P56
Submit
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millimeters
Y
The button on Jasmine's pants has a radius of 5 millimeters. What is the button's
diameter?
9
Answer:
10 millimeters
Step-by-step explanation:
The diameter of the button is twice the radius. Therefore, the diameter of Jasmine's pants button is 10 millimeters.
A spinner has 3 equal sections: red, white, and blue. John spins the spinner and tosses a coin. Which shows the sample space for spinning the spinner and tossing the coin?
The samples are {(H, R), (H, W), (H, B), (T, R), (T, W), (T, B)}. Thus, the correct option is D.
Given that:
A coin is tossed.
A spinner has 3 equal sections: Red, White, and Blue.
The samples are groups of clearly specified components. The number of items in a finite set is denoted by a curly bracket.
The total number of samples is calculated as,
Total samples = 2 x 3
Total samples = 6
The samples are {(H, R), (H, W), (H, B), (T, R), (T, W), (T, B)}.
Thus, the correct option is D.
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The graph of a sine function has an amplitude of 4, a midline of y=2, and a period of 10.
There is no phase shift. The graph is reflected over the x-axis.
What is the equation of this function?
The equation of the given sine function is y = 4 × sin((π/5)x) + 2.
The equation of the given sine function can be determined based on the given information. We know that the general form of a sine function is:
y = A × sin(Bx - C) + D,
where A represents the amplitude, B represents the frequency, C represents the phase shift, and D represents the vertical shift.
In this case, we are given the following information:
Amplitude (A) = 4: The amplitude is the distance between the maximum and minimum values of the function. Since the function is reflected over the x-axis, the amplitude is positive 4.
Midline (D) = 2: The midline is the horizontal line around which the graph oscillates. In this case, it is y = 2, indicating a vertical shift of 2 units upwards.
Period = 10: The period is the distance between two consecutive peaks (or troughs) of the function.
Given that there is no phase shift, the phase shift (C) is 0.
From the given information, we can deduce the values of A, B, C, and D to construct the equation.
A = 4 (amplitude)
D = 2 (vertical shift)
C = 0 (no phase shift)
To determine B, we use the formula:
B = 2π / Period
Plugging in the value for Period (10), we can calculate B:
B = 2π / 10 = π / 5
Therefore, the equation of the given sine function is:
y = 4 × sin((π/5)x) + 2.
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NO LINKS!! URGENT HELP PLEASE!!
O is the center of the regular dodecagon below. Find its area. Round to the nearest tenth.
Answer:
80.4 square units.
Step-by-step explanation:
solution Given:
apothem(a)=5
no of side(n)= 12
Area(A)-?
The area of a regular polygon can be found using the following formula:
[tex]\boxed{\bold{Area =\frac{1}{2}* n * s * a}}[/tex]
where:
n is the number of sidess is the length of one sidea is the apothemIn this case, we have:
n = 12s = ?a = 5First, we need to find S.
We can find the length of one side using the following formula:
[tex]\boxed{\bold{s = 2 * a * tan(\frac{\pi}{n})}}[/tex]
substituting value:
[tex]\bold{s = 2 * 5 * tan(\frac{\pi}{12})=2.679}[/tex] here π is 180°
To find the area substituting value in the above area's formula:
[tex]\bold{Area = \frac{1}{2}* 12 * 2.679 * 5=80.37\: sqaure\: units}[/tex]
in nearest tenth 80.4 square units.
Therefore, the area of the regular polygon is 80.4 square units.
Answer:
80.4 square units (nearest tenth)
Step-by-step explanation:
The given diagram shows a regular dodecagon (12-sided polygon) with an apothem of 5 units.
The apothem of a regular polygon is the distance from the center of the polygon to the midpoint of one of its sides.
We can calculate the side length of a regular polygon given its apothem using the following formula:
[tex]\boxed{\begin{minipage}{5.5cm}\underline{Apothem of a regular polygon}\\\\$a=\dfrac{s}{2 \tan\left(\dfrac{180^{\circ}}{n}\right)}$\\\\where:\\\phantom{ww}$\bullet$ $s$ is the side length.\\ \phantom{ww}$\bullet$ $n$ is the number of sides.\\\end{minipage}}[/tex]
Substitute n = 12 and a = 5 into the equation to create an expression for s:
[tex]5=\dfrac{s}{2 \tan \left(\dfrac{180^{\circ}}{12}\right)}[/tex]
[tex]s=10\tan \left(15^{\circ}\right)[/tex]
Now we can use the standard formula for an area of a regular polygon:
[tex]\boxed{\begin{minipage}{6cm}\underline{Area of a regular polygon}\\\\$A=\dfrac{n\cdot s\cdot a}{2}$\\\\where:\\\phantom{ww}$\bullet$ $n$ is the number of sides.\\ \phantom{ww}$\bullet$ $s$ is the length of one side.\\ \phantom{ww}$\bullet$ $a$ is the apothem.\\\end{minipage}}[/tex]
Substitute the found expression for s, n = 12 and a = 5 into the formula and solve for A:
[tex]A=\dfrac{12 \cdot 10\tan \left(15^{\circ}\right) \cdot 5}{2}[/tex]
[tex]A=\dfrac{600\tan \left(15^{\circ}\right)}{2}[/tex]
[tex]A=300\tan \left(15^{\circ}\right)[/tex]
[tex]A=80.3847577...[/tex]
[tex]A=80.4\; \sf square\;units\;(nearest\;tenth)[/tex]
Therefore, the area of a regular dodecagon with an apothem of 5 units is 80.4 square units, rounded to the nearest tenth.
Please solve this question
The solution to the given composite function is calculated as: 12
How to solve Composite functions?Composite functions are defined as when the output of one function is used as the input of another. If we have a function f and another function g, the function f of g of x is said to be the composition of the two functions.
We are given the functions:
f(x) = 2[tex]x^{\frac{1}{3} }[/tex]
g(x) = -[tex]x^{\frac{4}{3} }[/tex]
Thus:
(f - g)(-8) = 2[tex]x^{\frac{1}{3} }[/tex] + [tex]x^{\frac{4}{3} }[/tex]
= 2∛-8 + (∛-8)⁴
= (2 * -2) + (-2)⁴
= -4 + 16
= 12
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What is the value of x? Show all your work.
Please help. 100 points.
Answer:
12 cm
Step-by-step explanation:
By hypotenuse theorem,
x² + 35² = 37²
x² + 35*35 = 37*37
x² + 1225 = 1369
x² = 1369 - 1225
x² = 144
x² = 12*12
x² = 12²
x = 12 cm
Donna is thinking about buying a house that costs $125,000. If she puts down $25,000 and is able to get a 5 percent mortgage, she wants an estimate of her total monthly housing expenses. The average annual cost for owning a house, beyond the 5% cost of mortgage interest, is 4.09 percent of the value of the house. Not including the opportunity cost of the down payment, amortization on the loan, or any tax benefits from homeownership, what will be her monthly cost the first month?
A. $206.25
B. $279.60
C. $842.71
D. $746.43
Donna can expect her total monthly housing expenses to be approximately $842.71 for the first month after purchasing the house, assuming no tax benefits or amortization on the loan.
To calculate Donna's monthly housing expenses, we first need to determine the total amount of the mortgage. Since she puts down $25,000 on a $125,000 house, she will need to take out a mortgage for $100,000.
Next, we can calculate the annual cost of owning the house beyond the 5% cost of mortgage interest, which is given as 4.09% of the value of the house. So, 4.09% of $125,000 is:
0.0409 x $125,000 = $5,112.50
This means that Donna can expect to pay approximately $5,112.50 per year in additional expenses associated with owning the house.
To calculate the monthly cost, we simply divide this by 12:
$5,112.50 / 12 = $426.04
So, Donna can expect to pay approximately $426.04 per month in additional expenses associated with owning the house.
Adding the cost of the mortgage interest, we can calculate her total monthly housing expenses as follows:
Total monthly housing expenses = Mortgage interest + Additional annual costs / 12
Mortgage interest = 5% of $100,000 = $5,000 per year or $416.67 per month
Total monthly housing expenses = $416.67 + ($5,112.50 / 12) = $416.67 + $426.04 = $842.71
Hence, Donna can expect her total monthly housing expenses to be approximately $842.71
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a quadratic function is defined by f(x) = x*2 - 8x - 4.
Which expression also defines f and best reveals the max and mini of the function?
a) (x-4)*2 - 20
B) (x-4)*2 + 12
c) x(x-8) -4
d) (x-4)*2 + 20
The expression that best reveals the maximum and minimum of the function[tex]f(x) = x^2 - 8x - 4 is (x - 4)^2 - 20.[/tex] Option A
How to find the expressionThe vertex form of a quadratic function is given by[tex]f(x) = a(x - h)^2 + k[/tex] where (h, k) represents the coordinates of the vertex.
In the given quadratic function [tex]f(x) = x^2 - 8x - 4[/tex], we can rewrite it in the vertex form by completing the square:
[tex]f(x) = (x - 4)^2 - 16 - 4\\f(x) = (x - 4)^2 - 20[/tex]
From this expression, we can see that the vertex of the quadratic function is at the point (4, -20).
The term[tex](x - 4)^2[/tex] tells us that the vertex is at x = 4, and the constant term -20 indicates the y-coordinate of the vertex.
The expression that best reveals the maximum and minimum of the function[tex]f(x) = x^2 - 8x - 4[/tex] is [tex](x - 4)^2 - 20.[/tex]
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What is the interquartile range for data set? 27,4,54,78,27,48,79,64,5,6,41,71
The Interquartile range for the given data set is 51.
The interquartile range for a given data set, the values of the first quartile (Q1) and the third quartile (Q3). The interquartile range is the difference between Q3 and Q1.
First, let's arrange the data set in ascending order:
4, 5, 6, 27, 27, 41, 48, 54, 64, 71, 78, 79
To find Q1, which represents the lower quartile, we need to locate the median of the lower half of the data set. Since the data set has 12 values, the lower half consists of the first 6 values:
4, 5, 6, 27, 27, 41
The median of this lower half is the average of the middle two values, which are 6 and 27:
Q1 = (6 + 27) / 2 = 33 / 2 = 16.5
To find Q3, the upper quartile, we need to locate the median of the upper half of the data set. Again, since the data set has 12 values, the upper half consists of the last 6 values:
48, 54, 64, 71, 78, 79
The median of this upper half is the average of the middle two values, which are 64 and 71:
Q3 = (64 + 71) / 2 = 135 / 2 = 67.5
Finally, we can calculate the interquartile range by subtracting Q1 from Q3:
Interquartile range = Q3 - Q1 = 67.5 - 16.5 = 51
Therefore, the interquartile range for the given data set is 51.
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Can someone please answer and provide an explanation for these problems?
The center and radius for each equation are as follows:
40. Center: (3, 2), Radius: 8
41. Center: (-8, 4), Radius: 6
42. Center: (-4, 12), Radius: 2
43. Center: (4, -15), Radius: 3
What is the center and radius of the equations?The standard equations of a circle is given as (x - h)² + (y - k)² = r²
Where the center are (h, k) and the radius of the circle is r.
40. (x - 3)² + (y - 2)² = 64
Center: (3, 2)
Radius: √64 = 8
41. (x + 8)² + (y - 4)² = 36
Center: (-8, 4)
Radius: √36 = 6
42. (x + 4)² + (y - 12)² = 4
Center: (-4, 12)
Radius: √4 = 2
43. (x - 4)² + (y + 15)² = 9
Center: (4, -15)
Radius: √9 = 3
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the third term of an arithmetic sequence is 7 and the twelfth term in 106. what is the one hundredth term of the sequence
Answer:
a₁₀₀ = 1074
Step-by-step explanation:
the nth term of an arithmetic sequence is
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
given a₃ = 7 and a₁₂ = 106 , then
a₁ + 2d = 7 → (1)
a₁ + 11d = 106 → (2)
solve the equations simultaneously to find a₁ and d
subtract (1) from (2) term by term to eliminate a₁
(a₁ - a₁) + (11d - 2d) = 106 - 7
0 + 9d = 99
9d = 99 ( divide both sides by 9 )
d = 11
substitute d = 11 into (1) and solve for a₁
a₁ + 2(11) = 7
a₁ + 22 = 7 ( subtract 22 from both sides )
a₁ = - 15
Then
a₁₀₀ = - 15 + (99 × 11) = - 15 + 1089 = 1074
Using the image below, answer the following question: you are asked to pick 2
marbles out of the bag, what is the probability of picking a blue marble and then a
green marble, without replacing the blue one?
PLEASE URGENT
The probability of picking a blue marble and then a green marble without replacing the blue one is 4/45.
We have,
We see that there are 10 marbles.
Now,
Number of blue marbles = 2
Number of green marbles = 4
Now,
The probability of picking a blue marble first is 2/10, as there are 2 blue marbles out of 10 in total.
After picking a blue marble, there will be 9 marbles left in the bag.
The probability of picking a green marble second, without replacing the blue one, is 4/9, as there are 4 green marbles remaining out of the 9 marbles in total.
Now,
P(blue marble and green marble) = P(blue marble) x P(green marble)
= (2/10) x (4/9)
= 8/90
= 4/45.
Therefore,
The probability of picking a blue marble and then a green marble without replacing the blue one is 4/45.
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100 Points! Geometry question. Photo attached. Please show as much work as possible. Thank you!
Answer:
SRTZ is not a parallelogram.
Slope of SZ:
[tex]m = \frac{ - 2 - 1}{1 - ( - 2)} = - 1[/tex]
Slope of RT:
[tex]m = \frac{0 - 3}{2 - 1} = - 3[/tex]
Since the slopes of SZ and RT are not equal, SRTZ is not a parallelogram.
Find the area of the stained glass window shown if the diameter of the semi-circle is 61 inches. Use 3.14 for , round your answer to the nearest square inch, and enter the number only.
Answer:
1460 square inches
Step-by-step explanation:
You want the area of a semicircle with diameter 61 inches.
AreaThe area of a circle is given by ...
A = (π/4)d²
The area of a semicircle is half that, so is ...
A = (π/8)d²
A = (3.14/8)(61 in)² ≈ 1460 in²
The area of the semicircular window is about 1460 square inches.
<95141404393>
Please help due soon
Stmt of cash flows problem
Balance Sheet for Stand Corp Dec 31st:
Cash
Accounts Receivable
Inventory
Total Current Assets
2022
$177,000
$180,000
$100,000
$457,000
2021
$78.000
$185.000
$100.000
$363,000
Investments
Equipment
Accumulated Deprec
Total Non-Current Liabs
$52,000
$298,000
($106,000)
$244.000
$74,000
$240,000
($89.000)
$225,000
Total Assets
$701.000
$588.000
Current Liabilities
$134.000
$151.000
Common Stock
Retained Earnings
$260.000
$307,000
$260,000
$177,000
Total Liabs & Equity
$701.000
$588,000
OTHER INFORMATION:
-Investments were sold in 2022 at a loss of $10.000
-No equipment was sold in 2022
-Cash dividends were paid in 2022
-Net Income for 2022 was $160,000
REQUIRED:Prepare the Statement of Cash Flows:
1. Prepare the Statement of Cash Flows
2. Calculate Free Cash Flow
The Free Cash Flow based on the information given will be $115,000
How to explain the cash flowStatement of Cash Flows for Stand Corp for the year ended December 31, 2022
Cash flows from operating activities:
Net income $160,000
Adjustments to reconcile net income to net cash provided by operating activities:
Depreciation expense $17,000
Loss on sale of investments $10,000
Changes in current assets and liabilities:
Increase in accounts receivable ($5,000)
Increase in inventory ($20,000)
Increase in accounts payable $17,000
Increase in accrued expenses $11,000
Net cash provided by operating activities $190,000
Cash flows from investing activities:
Sale of investments $52,000
Purchase of equipment ($75,000)
Net cash used in investing activities ($23,000)
Cash flows from financing activities:
Payment of cash dividends ($25,000)
Net cash used in financing activities ($25,000)
Net increase in cash $142,000
Cash at beginning of year $78,000
Cash at end of year $220,000
Free Cash Flow = Net cash provided by operating activities - Purchase of equipment
Free Cash Flow = $190,000 - $75,000
Free Cash Flow = $115,000
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If Shawn rides his bike ¾ mile every ½ hour, how many miles does he bike per hour?
Answer:
1 1/2 miles per hour
Step-by-step explanation:
We can use a ratio to solve
3/4 mile
--------------
1/2 hour
Double the top and the bottom to get to 1 hour
3/4 * 2 miles
--------------
1/2 *2 hours
1 1/2 miles
-------------------
1 hours
1 1/2 miles per hour
Answer:1 1/2 mile or 6/4 mile
Step-by-step explanation:
Every half hour he rides 3/4Just multiply 3/4 by 2 which equals 6/4 or 1 1/2.
Cual es la distancia que recorrió luis en su bicicleta rodada 20p (2.54) después que las llantas dieran 50 vueltas completas
porfaaa
Luis traveled approximately 31,736.8 inches on his bicycle.
We have,
To find the distance that Luis traveled on his bicycle, we need to calculate the circumference of the tires and then multiply it by the number of complete turns.
Given:
Radius of the tires (r) = 20p (2.54) inches
Number of complete turns (n) = 50
The circumference of a circle can be calculated using the formula:
Circumference = 2πr
Substituting the given radius into the formula, we have:
Circumference = 2π * (20p) inches
Now we can calculate the distance traveled (d):
Distance = Circumference x Number of complete turns
Distance = 2π x (20p) x 50 inches
To simplify the calculation, we can approximate π as 3.14:
Distance ≈ 2 x 3.14 x (20 x 2.54) x 50 inches
Calculating this expression, we find:
Distance ≈ 31736.8 inches
Therefore,
Luis traveled approximately 31,736.8 inches on his bicycle.
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The complete question.
What is the distance that Luis traveled on his bicycle rolled 20p (2.54) after the tires gave 50 complete turns
What is the domain of f(x)? {x | 1 < x < 5} {x | 1 < x < 5} {y | −4 < y < 1} {y | −4 < y < 1}
The domain of function f(x) is given as follows:
{x | 1 ≤ x < 5}.
How to define the domain and range of a function?The domain of a function is defined as the set containing all possible input values of the function, that is, all the values assumed by the independent variable x in the context of the function.The range of a function is defined as the set containing all possible output values of the function, that is, all the values assumed by the dependent variable y in the context of the function.The values of x of the function given at the end of the answer are as follows:
Starts at x = 1(closed interval).Ends at x = 5 (open interval).Hence the domain is given as follows:
{x | 1 ≤ x < 5}.
Missing InformationThe function is given by the image presented at the end of the answer.
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Answer:
A - {x | 1 < x < 5}
Step-by-step explanation:
took the Quiz
Sobre una embarcación de 160 kg que está en reposo con su proa apuntando a la orilla, comienza a caminar una persona de 70 kg desde la proa hacia la popa, a 0.80 m/s respecto a la embarcación. ¿Cuáles son las velocidades de la embarcación y de la persona respecto a la orilla? Desprecia la resistencia del agua al movimiento.
The velocities of the boat and the person relative to the shore are 1.337 m/s and 2.896 m/s, respectively.
How to calculate the velocityWe can use the conservation of momentum equation:
(mboat + mperson) * vboat = mperson * vperson
(160 kg + 70 kg) * vboat = 70 kg * (0.80 m/s + vperson)
230 kg * vboat = 56 kg * (0.80 m/s + vperson)
vboat = (56/230) * (0.80 m/s + vperson)
vperson = 0.80 m/s + vboat
vperson = 0.80 m/s + (56/230) * (0.80 m/s + vperson)
(174/115) * vperson = (504/115) * m/s
Dividing both sides by (174/115), we get:
vperson = 2.896 m/s
vboat = (56/230) * (0.80 m/s + vperson)
Substituting the value of vperson, we get:
vboat = 1.337 m/s
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On a 160-kg boat that is at rest with its bow pointed to the shore, a 70-kg person begins to walk from the bow to the stern at 0.80 m/s relative to the boat. What are the velocities of the boat and the person relative to the shore? Neglect the resistance of water to motion.
100 Points! Geometry question. Photo attached. Determine whether the pair of triangles is similar. If so, write a similarity statement. If not, what would be sufficient to prove the triangles similar? Explain your reasoning. Please show as much work as possible. Thank you!
Answer:
∆TSU ~ ∆PJM by SAS since 10/14 = 5/7 and 15/21 = 5/7, and angle S is congruent to angle J.
Select the values that are solutions to the inequality x2 + 3x – 4 > 0.
Answer: To solve the inequality x^2 + 3x - 4 > 0, we can use the method of factoring.
First, we can factor the quadratic expression:
x^2 + 3x - 4 = (x + 4)(x - 1)
Now we can find the values of x that make the expression greater than zero by looking at the sign of the expression for each factor and applying the sign rules of multiplication:
If both factors are positive, the expression is positive.If both factors are negative, the expression is positive.If one factor is positive and one factor is negative, the expression is negative.
Using this method, we can create a sign chart:
x x + 4 x - 1 x^2 + 3x - 4
-4 0 -5 +6
-1 + - -
1 + + +
0 + - -
2 + + +
From the sign chart, we can see that the expression is greater than zero for x < -4 or x > 1. Therefore, the solutions to the inequality are all real numbers x such that x < -4 or x > 1. We can write this as:
x < -4 or x > 1
Angel works at a small shop that sells candy
bars. She oversees ordering more boxes of
candy bars. A box of candy bars (p) costs
$64 and Angel has no more than $230 to
spend on the order. What inequality
represents her situation?
Op 64 >= 230
Op 64 <= 230
O p/64 <= 230
O p/64 >= 230
Answer:
p/64 <= 230
Step-by-step explanation:
The inequality that represents Angel's situation is:
p/64 <= 230
This inequality states that the number of boxes of candy bars, represented by p, divided by 64 (the cost of each box), is less than or equal to 230 (the maximum amount Angel has to spend on the order).
Find the value for the side marked below. Round your answer to the nearest tenth 210 37 degrees
Using the cosine ratio, the value of the marked side in the image given below is approximately: y = 167.7.
How to Find the Value of the Marked Side Using the Cosine Ratio?The cosine ratio is defined as the ratio of the length of the hypotenuse of the right triangle over the length of the side that is adjacent to the reference angle. It is given as:
cos ∅ = length of hypotenuse/length of adjacent side.
From the image attached below, we have the following:
Reference angle (∅) = 37°
length of hypotenuse = 210
length of adjacent side = y
Plug in the values:
cos 37 = y/210
210 * cos 37 = y
y = 167.7
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Use the figure to answer the following.
a. What is the surface area of the cylinder? Leave your answer in terms of x.
b. Suppose the diameter and the height of the cylinder are cut in half. How does this affect the surface area of the cylinder? Explain
The diameter of the cylinder is 8 and the height is 11
a. The surface area of the cylinder is 120π square units.
b. Assuming the diameter and the height of the cylinder are cut in half, the surface area of the cylinder would be reduced by a scale factor of 1/4.
How to calculate surface area of a cylinder?In Mathematics and Geometry, the surface area (SA) of a cylinder can be calculated by using this mathematical equation (formula):
SA = 2πrh + 2πr²
Where:
h represents the height.r represents the radius.Note: Radius = diameter/2 = 8/2 = 4 m.
By substituting the side lengths into the formula for the surface area (SA) of a cylinder, we have the following;
Surface area = 2πrh + 2πr²
Surface area = 2(π)(4)(11) + 2(π)(4²)
Surface area = 120π square units.
Part b.
Assuming the diameter and the height of the cylinder are cut in half, we have:
Surface area = 2(π)(4/2)(11/2) + 2(π)((4/2)²)
Surface area = 2(π)(2)(5.5) + 2(π)(2²)
Surface area = (π)(2)(11) + 2(π)(4)
Surface area = 22π + 8π
Surface area = 30π square units.
Scale factor = 30π/120π
Scale factor = 1/4.
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Note: "The diameter of the cylinder is 8 and the height is 11"
Solve: log 3 (3x) + log 3 (3) = 5
Answer: x=27
Step-by-step explanation:
Assumption the 3's are the bases
[tex]log_{3} 3x +log_{3} 3=5[/tex] >combine using multiplication log rule (logs with
same base, that are being added can be
combined with multiplication)
[tex]log_{3}( 3x)(3) =5\\[/tex] >simplify
[tex]log_{3}( 9x) =5\\[/tex] >rewrite into exponent form
[tex]3^{5} = 9x[/tex] >simplify
243 = 9x
x=27
Answer:
x = 27
Step-by-step explanation:
using the rules of logarithms
• [tex]log_{b}[/tex] b = 1
• [tex]log_{b}[/tex] x = n ⇒ x = [tex]b^{n}[/tex]
then
[tex]log_{3}[/tex] (3x) + [tex]log_{3}[/tex] 3 = 5
[tex]log_{3}[/tex] (3x) + 1 = 5 ( subtract 1 from both sides )
[tex]log_{3}[/tex] (3x) = 4
3x = [tex]3^{4}[/tex] = 81 ( divide both sides by 3 )
x = 27
Answer and why!!!!!!
The expression (yx + y + px + p) / (5x² + 10x +5) * (10x + 10) / (y² + yp) is simplified to obtain
2/y
How to simplify the expressionThe given expression is
(yx + y + px + p) / (5x² + 10x +5) * (10x + 10) / (y² + yp)
The expression is simplified individually, using different each equation in the expression
yx + y + px + p
= y(x + 1) + p(x + 1)
= (y + p)(x + 1)
5x² + 10x +5
= 5(x² + 2x + 1)
= 5(x² + 1)
(10x + 10)
= 10(x + 1)
(y² + yp)
= y(y + p)
bringing the equations together and simplifying further
(y + p)(x + 1) / 5(x² + 1) * 10(x + 1) / y(y + p)
= 10(x + 1)(x + 1) / 5y(x² + 1)
= 10(x² + 1) / 5y(x² + 1)
= 2/y
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Write and solve an equation to find the value of x.
En el laboratorio de análisis de minerales unas pequeñas gotas de ácido Nítrico (HNO3); cae sobre la piel de un analista y le produce una quemadura. ¿Cuántas moléculas de HNO3 provocaron la quemadura si las gotas presentan una masa de 0,49 g?
Entonces n is 0,00779 moles,
Los casi 5 sextillones (5 con 21 ceros) de moléculas de HNO3 provocaron la quemadura en la piel del analista.
Para responder a esta pregunta, necesitamos saber la masa molar de HNO3, que es 63,01 g/mol. Usando esta información, podemos calcular el número de moles de HNO3 en los 0,49 g de gotas usando la fórmula: n = m/M, donde n es el número de moles, m es la masa y M es la masa molar.
Como un mol contiene el número de moléculas de Avogadro (6,022 x 10^23), podemos calcular el número de moléculas de HNO3 en las gotas que causaron la quemadura: 0,00779 moles x 6,022 x 10^23 moléculas/mol = 4,69 x 10^21 moléculas .
Es importante recordar que los ácidos concentrados como el HNO3 pueden ser extremadamente peligrosos y pueden causar quemaduras graves, por lo que siempre se deben tomar las precauciones de seguridad adecuadas en un entorno de laboratorio.
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