2.
Which of the following is the common difference of the arithmetic
sequence 4, 7, 10, 13, ...?
0
b. 1
c. 2
d. 3
a.
What is the correct answer​

Answer:

She should use 1.875 cups of sugar

Step-by-step explanation:

Find the ratio by cross multiplying

Answer:

I think it is 0.3

Step-by-step explanation:

Because, 3/4 divided by 2.5= 0.3

Answer:

B

Step-by-step explanation:

We know that 351 loaves were baked in six hours and 15 minutes.

First, let's convert the time to minutes. 6 hours is 360 minutes, so 6 hours and 15 minutes is 360 + 15 = 375 minutes.

Therefore, we can write the following ratio:

[tex]\frac{351\text{ loaves}}{375\text{ minutes}}[/tex]

We want to estimate how many loaves were baked in one hour or 60 minutes. So, we can write the following proportion:

[tex]\frac{351\text{ loaves}}{375\text{ minutes}}=\frac{x\text{ loaves}}{60\text{ minutes}}[/tex]

Note that the loaves and time align horizontally, while the rates align vertically.

Since we're estimating, let's change 351 to 350 (I'm also going to remove the words, since they're not necessary). So:

[tex]\frac{350}{375}=\frac{x}{60}[/tex]

We can reduce the left by dividing by 25. This yields:

[tex]\frac{14}{15}=\frac{x}{60}[/tex]

Cross multiply:

[tex]15x=60(14)[/tex]

Multiply and solve for x. So:

[tex]15x=840\\\Rightarrow x=56\approx55\text{ loaves}[/tex]

Therefore, approximately 55 loaves were baked in one hour.

So, our answer is B.

And we're done!

Answer:

Step-by-step explanation:

given

351 loaves baked in 6 hrs and 15 min.

15 min x (1 hr / 60 min) = 0.25 hr

find:

Estimate how many loaves were baked in one hour.

its a ratio and proportion:

351 loaves  =    x loaves       ( just cross multiply)

 6.25 hr               1 hr.

x loaves = 351 loaves ( 1 hr.)  

                        6.25 hr.

               = 56 ------->>> say 55

Answer:

[tex]n = \frac{1}{3}[/tex]

Step-by-step explanation:

I hope this helps!

Answer:

the better one to buy is a box of 36 pens for $5.76. because it is cheaper per pen.

Step-by-step explanation:

4.32 / 24 = 0.18 cents a pen

5.76 / 36 = 0.16 cents a pen

Answer:

a and b must be positive integers

Step-by-step explanation:

for example- a= (+1)x(+2)

                       = (+2)

                       = (+2)>0

                       = axb>0

Thank U

Answer:

X =1/(b2x+2b)

Step-by-step explanation:

bx2 +2x +1/b = 0

bx2+2x=1/b

bx2(b) +2bx = 1

x(b2x+2b)=1

x=1/(b2x+2b)

Answer:

y = 7 - 2x

Step-by-step explanation:

Step 1:

2x + y = 7               Equation

Step 2:

y = 7 - 2x          Subtract 2x on both sides

Answer:

y = 7 - 2x

Hope This Helps :)

Given:

Per month fee = $55

One-time recital fee = $165

The equation represents the $495 total cost that Barbara paid to Dance Unlimited.

[tex]495=165+55m[/tex]

To find:

We need to find the number of month Barbara receive dance lessons from Dance Unlimited.

Solution:

We have,

[tex]495=165+55m[/tex]

Here, m is number of months. We need to isolate m.

Subtract 165 from both sides.

[tex]495-165=55m[/tex]

[tex]330=55m[/tex]

Divide both sides by 55.

[tex]\dfrac{330}{55}=m[/tex]

[tex]6=m[/tex]

The value of m is 6. So, the required number of month Barbara receive dance lessons from Dance Unlimited is 6.

Answer: -7

Step-by-step explanation:

2X + 4= -10

2X= -10 -4

2X= -14

X= -7

Answer:

That will be 0.00512

here I am! dunno if this is the question you meant but you haven't gotten an answer here yet.

Answer:

B) Exactly one solution. (-3.5)

Step-by-step explanation:

5x + 8 - 7x = -4x + 1

combine like terms

5x - 7x + 8 = -4x + 1

-2x + 8 = -4x + 1

add 4x to both sides

-2x + 4x + 8 = -4x + 1 + 4x

2x + 8 = 1

subtract 8 from both sides

2x + 8 - 8 = 1 - 8

2x = -7

divide both sides by 2.

x = -3.5

3.5, clearly, is only one number.

Answer:

Y= 12.5+X

Step-by-step explanation:

Y=43.75

X=1.25x25=31.25

so 43.75 minus 31.25= 12.5

he spent 12.5 on fair addmition

Answer: C. Rickys rate was 0.25 more per hour" .

Step-by-step explanation:

Susan received $27 for 6 hours of work. Susan's rate we hour will be:

= $27/6

= $4.5

Ricky received $14.25 for 3 hours of work. Ricky's rate will be:

= $14.25/3

= $4.75

From the option given, the correct option is C "Rickys rate was 0.25 more per hour" .

This is because $4.75 - $4.5 = $0.25

If y = x and y = z, then by substitution we can say x = z.

In this case, substitution gives us

-1/2 x - 2 = -3/2 x + 2

and we can solve for x :

3/2 x - 1/2 x = 2 + 2

x = 4

then solve for y :

y = -1/2 x - 2

y = -1/2 * 4 - 2

y = -2 - 2

y = -4

Divide the corresponding sides

3/6 = 0.5

5/4 = 1.25

6/8 = 0.75

We get different results, so the sides are not in the same ratio or proportion.

Answer:

31

Step-by-step explanation:

Depth Changes:

1. down 25 feet

2. down 10 feet

3. up 7 feet

4. down 3 feet

If we form this into an equation, we get:

25+10-7+3 = 31

Answer:

The answer is D: Yes, BD = 7 and CE = 7

Step-by-step explanation:

B--> -5

D --> 2

-5 + BD = 2

BD = 7

C--> 0

E --> 7

0+CE=7

CE = 7

The answer is D

Answer:

(- 5, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

( [tex]\frac{x_{1}+x_{2} }{2}[/tex], [tex]\frac{y_{1}+y_{2} }{2}[/tex] )

Here (x₁, y₁ ) = (- 6, 1) and (x₂, y₂ ) = (- 4, 3) thus

midpoint = [tex]\frac{-6-4}{2}[/tex], [tex]\frac{1+3}{2}[/tex] ) = ( [tex]\frac{-10}{2}[/tex], [tex]\frac{4}{2}[/tex] ) = (- 5, 2 )

Answer:

1/3  of all the students called in to inform the school about missing school this day

Step-by-step explanation:

4/5 = students that call the school to inform the school office

only 7/12 attended Calvin Middle School

To get the number of students that missed Calvin Middle School = 1 -  number of students that attended Calvin Middle School

= 1 - 7/12 = (12-7) / 12

= 5 /12

The fraction of all students that called in to inform the school about missing school this day is:

5/12 x 4/5 = 1/3

Answer:

7556

Step-by-step explanation:

Can You Please give me a Brainlies or how ever you spell it

Answer:

5304

Step-by-step explanation:

80+1246√16

= 1326√16

= 5304.

Step-by-step explanation:

Do you mean?

[tex] \frac{ { \tan(x) }^{2} }{ \ { \sin(x) }^{2} } [/tex]

If so:

[tex]3 \sin(x) = 4 \cos(x) \\ \frac{3 \sin(x) }{ \cos(x) } = 4 \\ \frac{ \sin(x) }{ \cos(x) } = \frac{4}{3} \\ \tan(x) = \frac{4}{3} [/tex]

Did the question specify which quadrant? I'm just going to assume that it's the first

(as tangent = opp/adj)

hence

Hypotenuse:

[tex] \sqrt{{3}^{2} + {4}^{2} } = 5[/tex]

[tex] \sin(x) = \frac{4}{5} [/tex]

Finally,

[tex] \frac{ { \tan(x) }^{2} }{ { \sin(x) }^{2} } = \frac{ { \frac{4}{3} }^{2} }{ { \frac{4}{5} }^{2} } \\ = 2 \frac{7}{9} [/tex]

Answer:

759,602

Step-by-step explanation:

Evaluate (x^5 + 2) + x^2 where x = 15:

(x^5 + 2) + x^2 = 15^2 + (15^5 + 2)

| 1 | 5

× | 1 | 5

| 7 | 5

1 | 5 | 0

2 | 2 | 5:

225 + 2 + 15^5

15^5 = 15×15^4 = 15 (15^2)^2:

225 + 2 + 15 (15^2)^2

| 1 | 5

× | 1 | 5

| 7 | 5

1 | 5 | 0

2 | 2 | 5:

225 + 2 + 15×225^2

| | 2 | 2 | 5

× | | 2 | 2 | 5

| 1 | 1 | 2 | 5

| 4 | 5 | 0 | 0

4 | 5 | 0 | 0 | 0

5 | 0 | 6 | 2 | 5:

225 + 2 + 15×50625

| 5 | 0 | 6 | 2 | 5

× | | | | 1 | 5

2 | 5 | 3 | 1 | 2 | 5

5 | 0 | 6 | 2 | 5 | 0

7 | 5 | 9 | 3 | 7 | 5:

225 + 2 + 759375

| | | | 1 | 1 |  

| 7 | 5 | 9 | 3 | 7 | 5

| | | | 2 | 2 | 5

+ | | | | | | 2

| 7 | 5 | 9 | 6 | 0 | 2:

Answer: 759602

Answer:

759,602

Step-by-step explanation:

In this problem you would replace the x with 15 and break down the answer.

[tex]x^{2} +(2 + x^{5} )[/tex]  = [tex]15^{2} + (2 + 15^{5} )[/tex]

Now that you know the equation, break it down.

15² = 225

225 + (2 + [tex]15^{5}[/tex])

After rewriting the equation, do the work inside the parenthesis.

(2 + [tex]15^{5}[/tex]) = (2 + 759,375) = 759,377

The equation will now look like this.

225 + (759,377)

Solve!

759, 602

Answer:

The object hits the ground 8 seconds after launch.

Step-by-step explanation:

Let [tex]h(t) =-16\cdot t^{2}+96\cdot t + 256[/tex], where [tex]h[/tex] is the height of the object above the ground, measured in feet, and [tex]t[/tex] is time, measured in seconds. We notice that given expression is a second-order polynomial and hence, there are two roots, one of them corresponding to the instant when the object hits the ground. If [tex]h(t) = 0[/tex], we get the following expression:

[tex]-16\cdot t^{2}+96\cdot t +256 = 0[/tex] (Eq. 1)

Roots are found by applying the Quadratic Formula:

[tex]t_{1,2} = \frac{-96\pm\sqrt{96^{2}-4\cdot (-16)\cdot (256)}}{2\cdot (-16)}[/tex]

[tex]t_1 = 8\,s[/tex] or [tex]t_{2} = -2[/tex]

Only the first root offer a solution that is physically reasonable. Thus, the object hits the ground 8 seconds after launch.