Answer:
See explanation
Explanation:
When the complex ion Co(H2O)6 2+(aq) is placed in solution and chloride ions are added, the following equilobrium is set up;
Co(H2O)62+(aq) + 4 Cl-(aq) <=> CoCl42-(aq) + 6 H2O(g)
Co(H2O)6 2+(aq) solution is pink in colour while CoCl42-(aq) solution is blue in colour.
Since the solubility of CoCl42-(aq) is endothermic, heating the solution will move the equilibrium position towards the right (more CoCl42-(aq) is formed and the solution is blue in colour).
When the solution is cooled, more Co(H2O)62+(aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in colour.
When the solution is cooled, more [tex]Co(H_2O)_6^{2+}[/tex] (aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in color.
Balanced equation for the equilibrium:When the complex ion [tex]Co(H_2O)_6^{2+}[/tex] (aq) is placed in solution and [tex]CoCl_4^{2-}[/tex] are added, the following equilibrium is set up;
[tex]Co(H_2O)_6^{2+}(aq) + 4 Cl^-(aq) < = > CoCl_4^{2-}(aq) + 6 H_2O(g)[/tex]
[tex]Co(H_2O)_6^{2+}[/tex] (aq) solution is pink in color while [tex]CoCl_4^{2-}[/tex](aq) solution is blue in color. Since the solubility of [tex]CoCl_4^{2-}[/tex](aq) is endothermic, heating the solution will move the equilibrium position towards the right (more [tex]CoCl_4^{2-}[/tex] (aq) is formed and the solution is blue in color). When the solution is cooled, more [tex]Co(H_2O)_6^{2+}[/tex] (aq) is formed and the equilibrium position shifts towards the left and the solution becomes pink in color.
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Suppose you want to make an acetic acid/acetate buffer to a pH of 5.00 using 10.0 mL of 1.00 M acetic acid solution. How many milliliters of 1.00 M sodium acetate solution would you need to add? The pKa for acetate buffer is 4.75.
Answer:
Explanation:
Molarity of NaOAc needed
Using the Henderson-Hasselbalch Equation calculate base molarity needed given [HOAc] = 1.00M and pKa(NaOAc) = 4.75 and [HOAc] = 1.00m.
pH = pKa + log [NaOAc]/[HOAc]
5.00 = 4.75 + log[NaOAc]/[1.00M]
5.00 - 4.75 = log [NaOAc] - log[1.00M]
log [NaOAc] = 0.25 => [NaOAc] = 10⁰·²⁵ M = 1.78
Given 10ml of HOAc, how much (ml) 1.78M NaOAc to obtain a buffer pH of 5.00.
Determine Volume of Base Needed
(M·V)acid = (M·V)base => V(base) = (M·V)acid / (M)base
Vol (NaOAc) needed = (1.00M)(0.010L)/(1.78M) = 0.0056 liter = 5.6 ml.
Checking Results:
5.00 = 4.75 + log [1.78M]/[1.00M] = 4.75 + 0.25 = 5.00 QED.
The volume of 1.00 M sodium acetate solution needed to prepare an acetic/acetate buffer of pH 5.00 using 10.0 mL of 1.00M acetic acid solution is 17.8 mL.
We can find the volume of the acetate solution with the Henderson-Hasselbalch equation:
[tex]pH = pka + log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]})[/tex] (1)
Where:
[CH₃COOH] = 1.00 M
[CH₃COONa] =?
pH = 5.00
pKa = 4.75
From equation (1), we have:
[tex] log(\frac{[CH_{3}COONa]}{[CH_{3}COOH]}) = pH - pKa [/tex]
[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{pH - pKa} [/tex]
[tex] \frac{[CH_{3}COONa]}{[CH_{3}COOH]} = 10^{5.00 - 4.75} = 1.78 [/tex]
Now, the volume of the acetate solution is:
[tex]\frac{n_{CH_{3}COONa}/Vt}{n_{CH_{3}COOH}/Vt} = 1.78[/tex]
Since the total volume is the same, we have:
[tex]\frac{n_{CH_{3}COONa}}{n_{CH_{3}COOH}} = 1.78[/tex]
[tex] \frac{[CH_{3}COONa]_{i}*V_{b}}{[CH_{3}COOH]_{i}*Va} = 1.78 [/tex]
Solving for Vb
[tex] Vb = \frac{1.78*[CH_{3}COOH]_{i}*Va}{[CH_{3}COONa]_{i}} = \frac{1.78*1.00M*10.0mL}{1.00 M} = 17.8 mL [/tex]
Therefore, we need to add 17.8 mL of sodium acetate solution.
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How many moles are in 2.5L of 1.75 M Na2CO3
Answer:
4.4 mol.
Explanation:
Hello!
In this case, since the formula for calculating the molarity is:
[tex]M=n/V[/tex]
Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:
[tex]n=V*M[/tex]
Thus, we plug in the given data to obtain:
[tex]n=2.5L*1.75mol/L=4.4mol[/tex]
Best regards!
Answer:
4.4 mol.
Explanation:
Have a great day
Help pls ASAP thank you!!
Answer:
Deer, Eagle, Raccoon, frog, turtle, fish, dragonfly.
Explanation:
They interact from the life cycle they eat each other...
What is the enthalpy change(Q) when 60.0 g of NaOH is dissolved in one litre of water, given that the temperature of the solution increased by 15.8 °C?
Answer:
ΔH = -44.029 KJ/mol
Explanation:
We are told that 60.0 g of NaOH is dissolved in one litre of water.
From conversion, 1 litre = 1000 g
From tables, specific heat capacity of water; c = 4.18 J/g/°C
We are given ΔT = 15.8 °C
Formula for the heat absorbed by the solution is given as;
Q = mcΔT
Where;
Q = Heat gained by the water
m = Mass of the water
c = Specific heat of water
ΔT = change in temperature
Thus;
Q = 1000 × 4.18 × 15.8
Q = 66044 J
The solution absorbed 66044 J and therefore it means that the dissolution of the salt gave off 66044 J.
Thus;
Enthalpy is; ΔH = -66044 J
Now, Mass of NaOH is 60 g.
We know that molar Mass of NaOH is 39.997 g/mol. Thus;
Converting to moles, we have;
n = 60/39.997
n = 1.5 mol
Now, enthalpy when 1.5 moles of NaOH are dissolved in water will be;
ΔH = -66044 J/1.5 moles
ΔH = -44029.33 J/mol
ΔH = -44.029 KJ/mol
Can someone please help me!!
Answer:
Less in the top
your well wisher
2) Calculate the percent composition of each element in Mgso,
3) Calculate the percentage of each element in Ag,o.
Answer:
2)
[tex]\% Mg=20.2\%\\\\\% S=26.6\%\\\\\% O=53.2\%[/tex]
3)
[tex]\% Ag=93.1\%\\\\\% O=6.9\%[/tex]
Explanation:
Hello!
2) In this case, since magnesium sulfate is MgSO₄, we can see how magnesium weights 24.305 g/mol, sulfur 32.06 g/mol and oxygen 64.00 g/mol as there is one atom of magnesium as well as sulfur but four oxygen atoms for a total of g/mol; thus the percent compositions are:
[tex]\% Mg=\frac{24.305}{120.36 } *100\%=20.2\%\\\\\% S=\frac{32.06}{120.36 } *100\%=26.6\%\\\\\% O=\frac{64.00}{120.36 } *100\%=53.2\%[/tex]
3) In this case, although the element seems to contain Ag and O, we infer its molecular formula is Ag₂O; thus, since we have two silver atoms weighing 215.74 g/mol and one oxygen atom weighing 16.00 g/mol for a total of 231.74 g/mol, we obtain the following percent compositions:
[tex]\% Ag=\frac{215.74}{231.74} *100\%=93.1\%\\\\\% O=\frac{16.00}{231.74} *100\%=6.9\%[/tex]
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Please help me thanks so much
Answer:
a switch
Explanation:
Answer:
a switch is the answer hope it helps
Help plz now !
Which statement explains why a chemical equation must be balanced?
A. It must show the reactants and products on the correct sides of
the reaction arrow.
B. It must show that the mass of each element involved is conserved
by a chemical reaction.
C. It must show how each chemical formula is written to accurately
represent each substance.
D. It must show that coefficients and subscripts can be used in
chemical formulas.
Answer: B. It must show that the mass of each element involved is conserved by a chemical reaction.
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.
The correct statement why a chemical equation must be balanced is It must show that the mass of each element involved is conserved by a chemical reaction.
Answer:
B. It must show that the mass of each element involved is conserved
by a chemical reaction.
Explanation:
a p e x, just took the quiz
How many sulfur atoms are in 3.7 mol of SO2?
× 10 S atoms
Answer: 22.3 *10^23 S atoms
Explanation:
A cylinder of oxygen (O2) gas at STP has a volume of 2.75 L. How many oxygen molecules does it contain?
Answer:
7.40×10²² molecules.
Explanation:
From the question given above, the following data were obtained:
Volume of oxygen = 2.75 L
Number of molecules of oxygen =?
Next, we shall determine the number of mole of oxygen present. This can be obtained as follow:
22.4 L contains 1 mole of oxygen at STP.
Therefore, 2.75 L will contain = 2.75 / 22.4 = 0.123 mole of oxygen at STP.
Finally, we shall determine the number of molecules of oxygen present. This can be obtained as follow:
From Avogadro's hypothesis:
1 mole of oxygen = 6.02×10²³ molecules
Therefore,
0.123 mole of oxygen = 0.123 × 6.02×10²³
0.123 mole of oxygen = 7.40×10²² molecules.
Thus, the cylinder contains 7.40×10²² molecules of oxygen.
In a single replacement reaction, the chloride ion in NaCl can be replaced
by
a. potassium
b. carbon
c.fluorine
d.neon
Answer:
c. fluorine
Explanation:
A single replacement reaction is defined as the chemical reaction in which a strong molecule replaces the weak molecule from a compound.
In a single replacement reaction, the chloride ion in NaCl can be replaced by fluorine and gives Sodium fluoride as fluorine (F) is stronger than chlorine (Cl) and from other given molecules also. So the single replacement reaction between NaCl and F will be:
NaCl + F2 => NaF + Cl2
Hence, the correct answer is "c. fluorine".
Hydrogen can be produced according to the following word equation
=zinc +hydrochloric acid =zinc chloride +hydrogen [zn^+2]
Write a complete balanced chemical equation for this chemical reaction?
Answer:
Zn + 2HCl → ZnCl₂ + H₂
Explanation:
First we write the equation using the molecular formulas instead of words:
Zn + HCl → ZnCl₂ + H₂We know zinc chloride is ZnCl₂ as the problem tells us the oxidation state of zinc in the products is +2, and chloride means Cl⁻¹.
Now we proceed to balance the reaction:
There are 2 Cl atoms and 2 H atoms on the right side, so we add a coefficient of 2 to HCl on the left side:
Zn + 2HCl → ZnCl₂ + H₂HELP PLEASE I NEED HELP THANKS I LOVE U
How many moles of potassium nitrate (KNO3) are there in 0.300 L of a 2 molar solution?
Answer:
0.500-Molarity solution
Explanation:
The moles of the compound is given as the number of atomic mass unit in the compound. The moles of potassium nitrate in the solution are 0.6 mol
What is molarity?The molarity is the concentration unit, and it can be defined as the moles of compound present in the liter of solution.
The molarity can be expressed as:
[tex]\rm Molarity=\dfrac{Moles}{Volume(L)}[/tex]
The given potassium nitrate solution has, molarity = 2 M
The volume of the solution is 0.3 L.
Substituting the values for the moles of the compound:
[tex]\rm 2\;M=\dfrac{Moles}{0.3\;L} \\\\Moles=2\;\times\;0.3\;mol\\Moles=0.6\;mol[/tex]
The moles of potassium nitrate in 2 M solution is 0.6 mol.
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Gravitational potential energy depends on the
Answer:
Gravitational potential energy depends on basically two factor;
Object’s position Mass of objectExplanation:
The distances between both the bodies, as well as the mass within each object, are factors that influence gravitational potential energy.
What does Ra Ra Ah Ah Ah Ro Ma Ro Ma Ma Ga Ga O La La mean?
Answer:
They are symbols of elements.
Ra is the symbol of the element Radium
Ah is the symbol of the element Arrhenium
Ma is the symbol of the element Molybdenum
Ga is the symbol of the element Gallium
La is the symbol of the element Lanthanum
Answer:
Ra is the symbol of the element Radium
Ah is the symbol of the element Arrhenium
Ma is the symbol of the element Molybdenum
Ga is the symbol of the element Gallium
La is the symbol of the element Lanthanum
Explanation:
They are elements
What is the mole fraction of KCI in a
mixture of 0.564 g NaCl, 1.52 g KCI,
and 0.857 g LiCl?
Molar Mass
NaCl: 58.44 g/mol
KCI: 74.55 g/mol
Lici: 42.39 g/mol
Answer:
Mole fraction of KCl = 0.4056
Explanation:
We'll begin by calculating the number of mole of each compound. This can be obtained as follow:
For NaCl:
Mass NaCl = 0.564 g
Molar mass of NaCl = 58.44 g/mol
Mole of NaCl =?
Mole = mass /Molar mass
Mole of NaCl = 0.564 / 58.44
Mole of NaCl = 0.0097 mole
For KCl:
Mass KCl = 1.52 g
Molar mass of KCl = 74.55 g/mol
Mole of KCl =?
Mole = mass /Molar mass
Mole of KCl = 1.52 / 74.55
Mole of KCl = 0.0204 mole
For LiCl:
Mass LiCl = 0.857 g
Molar mass of LiCl = 42.39 g/mol
Mole of LiCl =?
Mole = mass /Molar mass
Mole of LiCl = 0.857 / 42.39
Mole of LiCl = 0.0202 mole
Next, we shall determine the total mole in the mixture. This can be obtained as follow:
Mole of NaCl = 0.0097 mole
Mole of KCl = 0.0204 mole
Mole of LiCl = 0.0202 mole
Total mole =?
Total mole = Mole of NaCl + Mole of KCl + Mole of LiCl
Total mole = 0.0097 + 0.0204 + 0.0202
Total mole = 0.0503 mole
Finally, we shall determine the mole fraction of KCl in the mixture. This can be obtained as follow:
Mole of KCl = 0.0204 mole
Total mole = 0.0503 mole
Mole fraction of KCl =?
Mole fraction of KCl = Mole of KCl /Total mole
Mole fraction of KCl = 0.0204 / 0.0503
Mole fraction of KCl = 0.4056
Answer:
.4 is correct
Explanation:
You are given 127 g H2CO3 (Carbonic Acid) and a volume of 800 mL of water, what will the final concentration of your solution be? (The final unit is the Molar (M), but do not include it.) (Round to 3 decimal places.)
Answer:
2.562
Explanation:
First we convert 127 g of H₂CO₃ to moles, using its molar mass:
127 g ÷ 62 g/mol = 2.05 mol H₂CO₃Then we convert 800 mL to L:
800 mL / 1000 = 0.800 LFinally we can calculate the concentration of the solution as molarity:
molarity = moles / litersmolarity = 2.05 mol / 0.800 L = 2.562 MCu + 2AgNO3 → Cu(NO3)2 + 2Ag
If a 40. g sample of Copper is used with an excess of silver nitrate, calculate the theoretical yield of silver. What is the percent yield of the silver, if 120 g was collected?
Answer:
[tex]m_{Ag}=135.8gAg[/tex]
[tex]Y=88.4\%[/tex]
Explanation:
Hello there!
In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:
[tex]m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\ m_{Ag}=135.8gAg[/tex]
Next, given the actual yield of 120 g, we compute the percent yield via:
[tex]Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%[/tex]
Regards!
find the number of molecules in 35.20 g of nitrogen dioxide
Answer:
4.584*10^23 molecules
Explanation:
Find molar mass of nitrogen and oxygen on periodic table.
find molar mass of nitrogen dioxide
use this to find moles of nitrogen dioxide
multiply by avagadros number
How do the causes of surface and deep water currents differ?
A. Surface currents are caused by wind deep water currents are caused by difference in water density
B. Surface currents are caused by the Coriolis effect deep water currents are caused by differences in water density
C. Surface currents are caused by differences in water salinity deep water currents are caused by differences in water temperature
D. Surface currents are caused by differences in water density deep water currents are caused by wind
Answer:
The answer is A. Surface currents are caused by wind deep water currents are caused by difference in water density.
hi, if your looking for extra points (50+) and br ainiest here is ur chance, answer this question correctly plz
Answer:
it should be C. the filtering of ground water. have a good day!
What is the percent composition of a 16.75 g sample of a compound containing 14.02 g oxygen and 2.73 g hydrogen? Select the correct answer below: 83.7% oxygen, 16.3% hydrogen O 17% oxygen, 13% hydrogen O 68.2% oxygen, 31.8% hydrogen 89.5% oxygen, 10.5% hydrogen
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
Mass of compound = 16.75 g
Mass of Oxygen = 14.02 g
Mass of Hydrogen = 2.73 g
Percentage composition = Mass of element / Mass of compound 100%
Percentage composition of Oxygen = 14.02 g / 16.75 g * 100%
Percentage composition of Oxygen = 0.837 * 100 = 83.7%
Percentage composition of Hydrogen = 2.73 g / 16.75 g * 100%
Percentage composition of Hydrogen = 0.163 * 100 = 16.3%
The correct option is;
83.7% oxygen, 16.3% hydrogen
Answer:
83.7% oxygen, 16.3% hydrogen
Explanation:
To determine the percent composition we can divide, our mass by total mass and afterwards, multiply by 100.
(Mass of O / Total mass) . 100 = % O
(Mass of H / Total mass) . 100 = % H
Remember that:
% O + % H = 100
Mass of O / Total mass + Mass of H / Total mass = 1
(14.02 g / 16.75g) . 100 = 83.7 %
(2.73 g /16.75g) . 100 = 16.3 %
what makes a substance a good insulator
Answer:
zoo wee mama
Explanation:
The particles that make up an object are held together by bonds. Insulators have strong bonds that hold their particles rigidly in place. This prevents particles from gaining energy and increasing the temperature. Wool, dry air, plastics, and polystyrene foam are all examples of good insulators.
Please please help me please please help please please help me please please help please please help me
Answer:
AU9NJ-BLVHV-TCLJS-54YTB
Please answer this question
Answer:
K^2O
Explanation:
I remember a question like this one and I got it right its K^2O
(aka its C)
As the [h+] in a solution decreases, what happens to the [OH^-]?
А. It increases and the pH increases.
B. It increases and the pH decreases.
C. It increases and the pH stays constant.
D. It decreases and the pH increases.
E. It decreases and the pH decreases.
Explanation:
as the Hydrogen (acid) ion decreases there is a corresponding increase in the Hydroxide (basic) ion.
"A 4.75-kg cell phone is dropped from your second floor balcony (from rest). It hits the
ground at a speed of 40 m/s. Assuming air resistance can be ignored, calculate the
gravitational potential energy of the cell phone before it was dropped."
What is the IUPAC name for the following compound?
CH3-CH2-CH2-CH2-CH2-CH2 -CH2-CH3
Enter the name of the molecule.
Methods of Heat Transfer
Identify the following examples of heat transfer as conduction, convection, or radiation.
1. Touching a metal spoon that is sitting in a pot of boiling water.
Will mark brainliest
Answer:
1
Explanation:
touching a metal spoon ....................water.
The type of radioactive particle that can be stopped by a sheet of paper is the
A. alpha particle
B. beta particle
C. gamma ray
D. uranium