[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]
[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]
3. What is the velocity of a collision if a railway train with a mass of 6000 kg is moving to the right at 2.0 [tex]{12{\frac{m}{s}}}[/tex] and collides with an empty freight train with a mass of 3000 kg which ia moving to the left on the same track at 3.0 [tex]{12{\frac{m}{s}}}[/tex][tex]\huge\underline{\sf{\red{Given:}}}[/tex]
[tex]\quad\quad\quad\quad\sf{mass \: 1 \: = \: 6000 \: kg}[/tex]
[tex]\quad\quad\quad\quad\sf{velocity\: 1\: = \: 2.0\: m/s}[/tex]
[tex]\quad\quad\quad\quad\sf{mass \: 2\: = \: 3000 \: kg}[/tex]
[tex]\quad\quad\quad\quad\sf{velocity\: 2\: = \: 3.0\: m/s}[/tex]
[tex]\huge\underline{\sf{\red{Fomula:}}}[/tex]
[tex]\quad\quad\quad\quad\boxed{\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}}[/tex]
[tex]\huge\underline{\sf{\red{Solution:}}} [/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{ \small{m }\tiny{1} \small{v} \tiny{1} \small{ \: + \: m} \tiny{2} \small{v} \tiny{2}}{( \small{m} \tiny{1}\small{ \: + \: m} \tiny{2} \small{)} }}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(6000 \: kg)(2.0\:m/s)+(3000\:kg)(3.0\:m/s)}{(6000\:kg)+(3000\:kg)}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{(12,000kgm/s)+(9,000\:kgm/s)}{(9,000kg)}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \: kgm/s}{9000kg}}[/tex]
[tex]\quad\quad\quad\quad\sf{vf\: = \frac{21,000 \cancel{ \red{ kg}}m/s}{9000 \cancel{ \red{kg}}}}[/tex]
[tex]\quad\quad\quad\quad \sf{vf\: = \boxed{ \sf{ 2.33 \:m /s}}}[/tex]
[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]
[tex]\huge\quad\quad \underline{ \sf{\boxed{ \sf{ \red{ 2.33 \:m /s}}}}}[/tex]
[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: } [/tex]
[tex]\sf{\red{︎✰}ShineBrighter\red{︎✰}}[/tex]
[tex]\sf{✍︎ C.Rose\red{❀}}[/tex]
ฅ^•ﻌ•^ฅ
Can someone help me? Which of the following verifies that triangle YXZ is similar to triangle QPR?
Answer:
a
Step-by-step explanation:
log2 1 is defined
True
False
Answer: True
Through the change of base formula, we can say,
[tex]\log_{2}(1) = \frac{\log(1)}{\log(2)} = \frac{0}{\log(2)} = 0[/tex]
So in short,
[tex]\log_{2}(1)=0[/tex]
It turns out that
[tex]\log_{b}(1) = 0[/tex]
for real numbers b such that b > 0 and [tex]b \ne 1[/tex]
An unknown number y is 10 more than an unknown number x. The number y is also x less than 3. The equations to find x and y are shown
below.
y = x + 10
y=-x+3
Which of the followine statements is a correct step to find x and y?
A add the equations to eliminate x
B multiply the equations to eliminate y
C write the points where the groans of the equation intersect the x axis
D write the points where the graphs equation intersect the y axis
Answer:
a. add the equations to eliminate x
Step-by-step explanation:
this is called process of elimination
Plz solve this question correctly.
Show the steps needed to solve it.
Answer: 378y^3
Step-by-step explanation:
the formula for volume is V = L * w * h , where V=volume, L=length, W=width, and H=height
if we plug the numbers from the picture in, the formula would look like this:
V = 9y * 7y * 6y
to solve you just multiply them together
V = 378 y^3
Two friends Vicky and Micky start a business together. They decided to share their capitals depending up on the variable expenditure. The capital of the two partners together is given by polynomial 6x² + 11x – 35 which is the product of their individual share factors.
a-The value of x, when their total share is equal to 0?
b-The total expenditure of Vicky and Micky when x = 10 is (in Rs
c-The sum of their expenditure is
Answer:
a- x = 5/3, or x = -7/2
b- 675
c - 5·x + 2
Step-by-step explanation:
The polynomial representing the capital of the two partners = 6·x² + 11·x - 35
a. The total share is the capital of the two partners together = 6·x² + 11·x - 35
∴ When their total share is equal to 0, we have;
6·x² + 11·x - 35 = 0
Factorizing the above equation with a graphing calculator gives;
(3·x - 5)·(2·x + 7)
Therefore;
x = 5/3, or x = -7/2
b- The total expenditure, when x = 10 is given by substituting the value of x in the polynomial 6·x² + 11·x - 35, as follows;
When x = 10
6·x² + 11·x - 35 = 6 × 10² + 11 × 10 - 35 = 675
The total expenditure of Vicky and Micky when x = 10 is 675
c - The sum of their expenditure is (3·x - 5) + (2·x + 7) = 5·x + 2
PLZ HELP ILL GIVE BRAINLIEST IF RIGHT!!!
Rosa has already written 11 pages ,and she expects to write 3 pages for every additional hour spent writing. How many hours will Rosa have to spend writing this week in order to have written a total of 47 pages?
Answer:
12 hours
Step-by-step explanation:
pages total = pages written + pages per hour * number of hour
47 = 11 + 3*h
Subtract 11 from each side
47 -11 = 11 +3h -11
36 = 3h
Divide by 3
36/3 = 3h/3
12 = h
I need help, please!! I'll give a brainliest
Answer:
metals or metalloids
Step-by-step explanation:
I'm built different i dont know if im right about the question. im just not sure if i understood the question correctly
HELP PLZ
Possible values for the area A of the rectangle shown are 12 - As 36. Write and
solve a compound inequality to find the possible values of x. Are these values all
viable in this situation?
2x + 1
3
Answer:
i had the exact same question as this, dm me on discord so i can screenshare my answer
Step-by-step explanation:
jey0001 is my discord
The angle of elevation to a nearby tree from a point on the ground is measured to be 61 ∘ ∘ . How tall is the tree if the point on the ground is 59 feet from the tree? Round your answer to the nearest hundredth of a foot if necessary.
Answer:
106.44 ft
Step-by-step explanation:
tan = opp/adj
tan61 = opp/59
59*tan61 = opp
opp = 106.438817561014012
Rounded
106.44 ft
А
E
F
B1
2
2x
135°
750
2x -15°
12
G
H
I
C3
D
Determine the value of x.
i wonder this is math problem or code word for treasure
Answer:
Step-by-step explanation:
(2x-15) = 45
Step-by-step explanation:
When two angles lie on a straight line, they are supplementary
what this mean is that the add up to equal 180 degrees
Mathematically, we have this as:
(2x-15) + 135 = 180
(2x-15) = 180-135
(2x-15) = 45
CAN SOMEONE HELP ME OUT WITH THIS PLEASE AND THINK YOU
Answer:
[tex]10\frac{7}{18}[/tex]
Step-by-step explanation:
First revert it to improper fraction.
[tex]\frac{13}{2} +\frac{35}{9} \\\\[/tex]
Now put them to a common denominator.
[tex]\frac{187}{18}[/tex]
=> [tex]10\frac{7}{18}[/tex]
Michelle invested $10,000 for one year, part at 8% interest and the rest at 12% annual interest. Her total interest for the year was $944. How much money did she invest at 12% interest?
Step by step please.
Answer:
Michelle invested $ 6,400 at 8% and $ 3,600 at 12%.
Step-by-step explanation:
Given that Michelle invested $ 10,000 for one year, part at 8% interest and the rest at 12% annual interest, and her total interest for the year was $ 944, to determine how much money did she invest at 12% interest, the following calculation must be done:
10,000 x 0.08 + 0 x 0.12 = 800
8,000 x 0.08 + 2,000 x 0.12 = 880
4,500 x 0.08 + 5,500 x 0.12 = 1,020
6,000 x 0.08 + 4,000 x 0.12 = 960
6,500 x 0.08 + 3,500 x 0.12 = 940
6,400 x 0.08 + 3,600 x 0.12 = 944
Therefore, Michelle invested $ 6,400 at 8% and $ 3,600 at 12%.
HELP NEEDED ASAP!! Find the sine of B
Calculus 2. Please help
Answer:
[tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}}} \, dx = \infty[/tex]
General Formulas and Concepts:
Algebra I
Exponential Rule [Rewrite]: [tex]\displaystyle b^{-m} = \frac{1}{b^m}[/tex]Calculus
Limits
Right-Side Limit: [tex]\displaystyle \lim_{x \to c^+} f(x)[/tex]Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
Derivatives
Derivative Notation
Basic Power Rule:
f(x) = cxⁿf’(x) = c·nxⁿ⁻¹Integrals
Definite IntegralsIntegration Constant C
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
U-Substitution
U-Solve
Improper Integrals
Exponential Integral Function: [tex]\displaystyle \int {\frac{e^x}{x}} \, dx = Ei(x) + C[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx[/tex]
Step 2: Integrate Pt. 1
[Integral] Rewrite [Exponential Rule - Rewrite]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \int\limits^1_0 {\frac{e^{-x^2}}{x} \, dx[/tex][Integral] Rewrite [Improper Integral]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \int\limits^1_a {\frac{e^{-x^2}}{x} \, dx[/tex]Step 3: Integrate Pt. 2
Identify variables for u-substitution.
Set: [tex]\displaystyle u = -x^2[/tex]Differentiate [Basic Power Rule]: [tex]\displaystyle \frac{du}{dx} = -2x[/tex][Derivative] Rewrite: [tex]\displaystyle du = -2x \ dx[/tex]Rewrite u-substitution to format u-solve.
Rewrite du: [tex]\displaystyle dx = \frac{-1}{2x} \ dx[/tex]Step 4: Integrate Pt. 3
[Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {-\frac{e^{-x^2}}{x} \, dx[/tex][Integral] Substitute in variables: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} -\int\limits^1_a {\frac{e^{u}}{-2u} \, du[/tex][Integral] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}\int\limits^1_a {\frac{e^{u}}{u} \, du[/tex][Integral] Substitute [Exponential Integral Function]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(u)] \bigg| \limits^1_a[/tex]Back-Substitute: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-x^2)] \bigg| \limits^1_a[/tex]Evaluate [Integration Rule - FTC 1]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{1}{2}[Ei(-1) - Ei(a)][/tex]Simplify: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \lim_{a \to 0^+} \frac{Ei(-1) - Ei(a)}{2}[/tex]Evaluate limit [Limit Rule - Variable Direct Substitution]: [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx = \infty[/tex]∴ [tex]\displaystyle \int\limits^1_0 {\frac{1}{xe^{x^2}} \, dx[/tex] diverges.
Topic: Multivariable Calculus
Help me with this question too
Answer:
The one on the right
Step-by-step explanation:
Because it is 4 then 3
Answer:
the second one (the one to the right)
Step-by-step explanation:
Play the four digit 3,5,7,and 9 into the boxes pure in the position that would give the greatest results in the true numbers are multiplied
- 73X95
- 79X53
-97X35
-93X75
- 9 3 x 7 5
Step-by-step explanation:To get the combination that would yield the greatest result if the true number are multiplied,
i. multiply each given combination
73 x 95 = 6935
79 x 53 = 4187
97 x 35 = 3395
93 x 75 = 6975
ii. get the largest result from the results calculated above in (i)
The greatest of the results is 6975, therefore the digits should be placed like so;
9 3
7 5
Louise begins factoring the polynomial, which has four terms. 8x3+24x2+10x+30 2(4x3+12x2+5x+15) 2[4x2(x+3)+5(x+3)] Which is the completely factored form of her polynomial? 8x2(x + 3)2 2x(4x2 + 5) 2(4x2 + 5) (x + 3) 2(4x2 + 5) (x + 3)2
Answer:
[tex]8x3+24x2+10x+30= 2[(4x^2+5)(x+3)][/tex]
Step-by-step explanation:
Given
[tex]8x3+24x2+10x+30= 2(4x^3+12x^2+5x+15)[/tex]
[tex]8x3+24x2+10x+30= 2[4x^2(x+3)+5(x+3)][/tex]
Required
The complete factored form
We have:
[tex]8x3+24x2+10x+30= 2[4x^2(x+3)+5(x+3)][/tex]
Factor out x + 3
[tex]8x3+24x2+10x+30= 2[(4x^2+5)(x+3)][/tex]
The above represents the completely factored form
Answer:
C on edge
Step-by-step explanation:
I took the test
please help me 2 The two lines shown below are perpendicular. If the slope of the red line is 5 what is the slope of the green line? Use a slash mark (/) as a fraction bar if necessary. 15 O A. O OB. 5 min O c. O c tole D. O
Answer:
-5/2
Step-by-step explanation:
Perpendicular slope is always the negative reciprical. This basically means the opposite sign and the nubers are flipped.
A trained stunt diver is diving off a platform that is 15 m high into a pool of water that is 45 cm deep. The height, h, in meters, of the stunt diver above the water, is modeled by h=-4.9t^2+12t+5, where t is the time in seconds after starting the dive.
a) How long is the stunt diver above 15 m?
b) How long is the stunt diver in the air?
Answer:
a) 0 seconds.
b) The stunt diver is in the air for 2.81 seconds.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\Delta}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\Delta}}{2*a}[/tex]
[tex]\Delta = b^{2} - 4ac[/tex]
Height of the diver after t seconds:
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
a) How long is the stunt diver above 15 m?
Quadratic equation with [tex]a < 0[/tex], so the parabola is concave down, and it will be above 15m between the two roots that we found for [tex]h(t) = 15[/tex]. So
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
[tex]15 = -4.9t^2 + 12t + 5[/tex]
[tex]-4.9t^2 + 12t - 10 = 0[/tex]
Quadratic equation with [tex]a = -4.9, b = 12, c = -10[/tex]. Then
[tex]\Delta = 12^{2} - 4(-4.9)(-10) = -52[/tex]
Negative [tex]\Delta[/tex], which means that the stunt diver is never above 15m, so 0 seconds.
b) How long is the stunt diver in the air?
We have to find how long it takes for the diver to hit the ground, that is, t for which [tex]h(t) = 0[/tex]. So
[tex]h(t) = -4.9t^2 + 12t + 5[/tex]
[tex]0 = -4.9t^2 + 12t + 5[/tex]
[tex]-4.9t^2 + 12t + 5 = 0[/tex]
Quadratic equation with [tex]a = -4.9, b = 12, c = 5[/tex]. Then
[tex]\Delta = 12^{2} - 4(-4.9)(5) = 242[/tex]
[tex]x_{1} = \frac{-12 + \sqrt{242}}{2*(-4.9)} = -0.36[/tex]
[tex]x_{2} = \frac{-12 - \sqrt{242}}{2*(4.9)} = 2.81[/tex]
Time is a positive measure, so we take 2.81.
The stunt diver is in the air for 2.81 seconds.
How much almond milk does James use per teaspoon of cashew butter
simplify the question
Answer:
=−4√2
I got this when simplified.
PLS I beg someone to finish ALL of this :(. I’ve stayed up all night to do this but I couldn’t figure all of them out. Pls pls pls!!! ill mark you brainliest n I can give you a thank you such as 5 Stars in return. Please take your time and I hope you all have a amazing day!
Answer:
5. 2 hours 45 minutes 6. 7:23 7. 10:05 8. 1 hour 34 minutes
Step-by-step explanation:
I mean u gotta be lying about staying up all night to do these 4 problems but heres the answers
Answer:
5. 2 hours 45 mins
6. 7:23 start
7. 10:05
8. 1 hour 34 mins
Given the figure below as marked, which term best describes EF?
A. angle bisector
B. median
C. perpendicular bisector
D. altitude
Answer:
B
median
hope its help you
Answer: B. Median
Step-by-step explanation:
its the middle line.
căn bậc hai của (x^2-2x-3)
[tex]heres \: the \: answer \: i \: hope \: it \: help[/tex]
Simplify exponents. A, B, or C and explain.
Answer:
[tex]8^{-3}[/tex]
Step-by-step explanation:
[tex]\frac{8^3}{8^6}[/tex]
in division f the base are same u can subtract their exponents
8^3-6
8^-3
Find the equation of the line with slope -2 which goes through the point (9,-7).
Give your answer in slope-intercept form y = mx + b.
Evaluate (xy) ^-6 if x = 3 and y = -1.
A. 3
B. -1/729
C. 1/73
D. 1/729
If David walks 1/2 mile in 1/4 hour, then how fast does David walk in one hour? (In other words, what is David's "unit rate"?)
Which ordered pair is a solution of the equation y = -7x + 2
A. (1,2)
B. (8, -54)
C. (5, -35)
D. (1, -7)
Answer:
B. (8, -54)
Step-by-step explanation:
y = -7x + 2
Check to see if the point makes the equation true
A. (1,2) 2 = -7(1)+2 = -7+2 = 5 False
B. (8, -54) -54 = -7(8)+2 = -56+2 = -54 True
C. (5, -35) -35 = -7(5) +2 = -35+2 = -33 False
D. (1, -7) -7 =-7(1)+2 = --7+2 = -5 False
Complete the synthetic division to find the quotient of 3x^3-25x^2+12x-32 and x-8
Answer:
Explanation:
Hey there!
Please see your required solution in picture.
Quotient Q(X) = 3x²-x+4
Hope it helps!
Answer:
see image
Step-by-step explanation:
Plato/Edmentum