(4a+3b)(2a-5) expand

Answers

Answer 1
8a^2-14ab-15b if that’s what you mean
Answer 2

Answer:

6ab + 8a² - 15b - 20a

Step-by-step explanation:

Expand by using FOIL method

4(2a-5) + 3b(2a-5)

4a(2a) + 4a × -5 + 3b × -5

Simplify terms

8a² - 20a + 6ba -15b

6ab + 8a² - 15b - 20a


Related Questions

I would like to see the answer for number one. You don't need to solve the rest.

Answers

Answer:3/4

Step-by-step explanation:

tan^2+1=sec^2

15 POINTS!!! Please please help out!!! If you can!! I have other things on my account worth a lot of points so if you can help out that would be so helpful

Answers

Answer:

The maximum is -3

and the third one -3<f(x)≤ -3

Step-by-step explanation:

Let's start by expanding the exponent

-(x+7)²= -(x²+14x+49)= -x²-14x-49

simplify

-x²-14x-49-3= -x²-14x-52

To find the maximum/minimum take the first derivative

-x²-14x-52= -2x-14

set this equal to 0

-2x-14= 0

x= -7

We then plug in x= -7 into the equation to find the y value

Because the coeficcent for the degree is negative (it's -1) this is a maximum

-(-7+7)²-3 = -3

Because -3 is the highest point the graph's range is -∞<f(x)< -3

Therefore the maximum i

Find the set of values of k for which the line y=kx-4 intersects the curve y=x²-2x at 2 distinct points?

Answers

Answer:

[tex]-6 < k < 2[/tex]

Step-by-step explanation:

Given

[tex]y = x^2 - 2x[/tex]

[tex]y =kx -4[/tex]

Required

Possible values of k

The general quadratic equation is:

[tex]ax^2 + bx + c = 0[/tex]

Subtract [tex]y = x^2 - 2x[/tex] and [tex]y =kx -4[/tex]

[tex]y - y = x^2 - 2x - kx +4[/tex]

[tex]0 = x^2 - 2x - kx +4[/tex]

Factorize:

[tex]0 = x^2 +x(-2 - k) +4[/tex]

Rewrite as:

[tex]x^2 +x(-2 - k) +4=0[/tex]

Compare the above equation to: [tex]ax^2 + bx + c = 0[/tex]

[tex]a = 1[/tex]

[tex]b= -2-k[/tex]

[tex]c =4[/tex]

For the equation to have two distinct solution, the following must be true:

[tex]b^2 - 4ac > 0[/tex]

So, we have:

[tex](-2-k)^2 -4*1*4>0[/tex]

[tex](-2-k)^2 -16>0[/tex]

Expand

[tex]4 +4k+k^2-16>0[/tex]

Rewrite as:

[tex]k^2 + 4k - 16 + 4 >0[/tex]

[tex]k^2 + 4k - 12 >0[/tex]

Expand

[tex]k^2 + 6k-2k - 12 >0[/tex]

Factorize

[tex]k(k + 6)-2(k + 6) >0[/tex]

Factor out k + 6

[tex](k -2)(k + 6) >0[/tex]

Split:

[tex]k -2 > 0[/tex] or [tex]k + 6> 0[/tex]

So:

[tex]k > 2[/tex] or k [tex]> -6[/tex]

To make the above inequality true, we set:

[tex]k < 2[/tex] or [tex]k >-6[/tex]

So, the set of values of k is:

[tex]-6 < k < 2[/tex]

5 1 point In the standard form of a circle (x – h)^2 + (y - k)^2 = r^2, which of the following represents the center of the circle?
A:(h,k)
B:r
C:(x,y)
D:r^2​

Answers

Option C with h and k

see screenshot for an example

general formula is

r² = (x - x-center)² + (y - y-center)²

identify the solution to the following system of equations: 2x + 5y = 14 and x + 2y = 5

Answers

Answer:

(-3, 4)

Step-by-step explanation:

yeah

Does the set of numbers form a Pythagorean triple? Explain.

Answers

Explanation:

Pythagorean Triples are sets of whole numbers for which the Pythagorean Theorem holds true. The most well-known triple is 3, 4, 5. This means that 3 and 4 are the lengths of the legs and 5 is the hypotenuse.

10 POINTS!!! 1 to 16 please hurry and answer correctly

Answers

Answer:

1.false

2.true

3.true

4.true

5.120

6.105

7.85

8.100

9.115

10.40

11.13

12.30

13.36

14.65

15.35

16.75

algebra help please answer

Answers

Answer:

Answer is 1st and Last

Step-by-step explanation:

Because if you use logic you should know why

The two triangles are similar.
What is the value of x?
Enter your answer in the box HELP PLS

Answers

Solution for above problem :

The Above triangles are similar, Therefore the corresponding sides would be proportional.

that is : -

[tex] \dfrac{16}{12} = \dfrac{6x}{5x - 2} [/tex]

[tex]16 \times (5x - 2) = 12 \times 6x[/tex]

[tex]80x - 32 = 72x[/tex]

[tex]80x - 72x = 32[/tex]

[tex]8x = 32[/tex]

[tex]x = 32 \div 8[/tex]

[tex]x = 4[/tex]

[tex]\mathfrak{best \: \: of \: \: luck \: \: for \: \: your \: \: assignment}[/tex]

Prove that root 2 as irrational number​

Answers

To prove: √2 is an irrational number. Proof: Let us assume that √2 is a rational number. So it can be expressed in the form p/q where p, q are co-prime integers and q≠0. √2 = p/q. ...
Solving. √2 = p/q. On squaring both the side we get, =>2 = (p/q)2

Find the x-intercept of the graph of the linear equation y= - 1/3 x+3?

x-intercept =

Answers

Answer:

9

Step-by-step explanation:

Plug in 0 for y and solve for x.

0 = (-1/3)x + 3

(-1/3)x = -3

x = 9

N is a number such that N ÷ 18= 16. What is the value of N?

Answers

Answer:

288 po

Step-by-step explanation:

288 divided by 18 is 16

Geometry is fun or ducks like water

Answers

Answer:

i am a duck and i can confirm water is pretty poggers

Step-by-step explanation:

Ducks obviously come on now

Which of following equations have a solution y = 8. A:4y + 3 = 32. B:6 + 5y = 46. C:9y ÷ 4 = 8. D:10y ÷ 4 = 20. E:65 - 3y = 27​

Answers

B
5y = 46 - 6 = 49
y = 40/5 = 8

Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.
2 similar triangles. Triangle 1 has side lengths 16, 24, blank. Triangle 2 has side lengths 12, 18, blank.
a.
StartFraction 12 Over 24 EndFraction = StartFraction 18 Over 16 EndFraction = StartFraction 1 Over 2 EndFraction
b.
StartFraction 12 Over 18 EndFraction = StartFraction 16 Over 24 EndFraction = StartFraction 2 Over 3 EndFraction
c.
StartFraction 12 Over 16 EndFraction = StartFraction 18 Over 24 EndFraction = StartFraction 3 Over 4 EndFraction
d.
StartFraction 18 Over 12 EndFraction = StartFraction 24 Over 16 EndFraction = StartFraction 3 Over 2 EndFraction



Please select the best answer from the choices provided


A
B
C
D

Answers

Answer:

the correct answer is

C.

StartFraction 12 Over 16 EndFraction = StartFraction 18 Over 24 EndFraction = StartFraction 3 Over 4 EndFraction

Does 12, 24, 36 form a right triangle?

Answers

Answer:

no bc pythagorean

Step-by-step explanation:

the width of a rectangle is 2 inches less than its length , and the area is 35 sqaure inches. what are thd length and width of the rectangle

Answers

Answer:

length: 7in.

width: 5in.

Step-by-step explanation:

so we know that 7*5 is 35 yes? since we already know the area, which is just l*w, and that 5 is two less that 7, we can conclude that the length is 7 and the width 5

hope this helps! lemme know if you need more

9 2/5-3 4/10
yo anyone have the answer

Answers

Answer:

6

Step-by-step explanation:

9 and 2/5 is the equivilent to 9 and 4/10

9 4/10 - 3 4/10 = 6 0/10

What else would need to be congruent to show that ABC= DEF by ASA?
B
E
10
10
45
A
с
45
F
O A. ZBE ZE
B. AC = DF
C. ZA ZD
O D. BC = EF

Answers

Answer:

Option A

then you would have an angle, a side and another angle (ASA) next to each other

Opt.B would be a second sude (SAS)

Opt.C is already given

Opt.D seems to be like (A-S-S). no pun intended.

The additional information need to be added to show the given triangles congruent is angle B = angle E

What are congruent triangles?

Triangles are said to be congruent if their corresponding sides and angles are congruent.

Given is a pair of triangles, Δ ABC and Δ DEF, in this angle A = angle D and AB = DE = 10,

We need to find one more reason to make them congruent by ASA rule,

In ASA rule of congruence, we have two corresponding angles congruent in the triangles and a side between them need to be congruent,

Here, the pair of two angles should be ∠ A and ∠ D and ∠ B and ∠ E, because the congruent sides AB and DE are in mid of them.

Hence, the additional information need to be added to show the given triangles congruent is angle B = angle E

Learn more about triangles congruent click;

https://brainly.com/question/22062407

#SPJ7

Complete the proof. PROVE:△VWY≅△UXY

Answers

Answer:

D.) SAS or Side angle Side

osjdjaidbsojaanod

Which ratios are equal to cos(B)? Choose the TWO ratios that apply.

Answers

Answer:2 and 5

Step-by-step explanation:

The ratios that are equal to [tex]cos(B)[/tex] : [tex]\bold{\frac{BC}{AB}}[/tex] and [tex]\bold{\frac{EF}{DE}}[/tex]

What are similar triangles?

"Two triangles are said to be similar

- if corresponding angles are equal and the sides

- if corresponding sides of the triangles are in proportion."

What is cosine angle?

In a right triangle,

cos(Ф) = (adjacent side of angle Ф) ÷ hypotenuse

For given example,

Triangles ABC and DEF are similar triangles.

This means, ∠A = ∠D, ∠B = ∠E, ∠C = ∠F

And, [tex]\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF}[/tex]               ..............(i)

For a right triangle ABC,

the cosine of angle B is,

[tex]cos(B)=\frac{BC}{AB}[/tex]

From (i),

[tex]\frac{BC}{AB}=\frac{EF}{DE}[/tex]

So, the cosine of angle B is,

[tex]cos(B)=\frac{EF}{DE}[/tex]

Therefore, the ratios that are equal to [tex]cos(B)[/tex] : [tex]\frac{BC}{AB}[/tex] and [tex]\frac{EF}{DE}[/tex]

Learn more about similar triangles here:

https://brainly.com/question/25882965

#SPJ2

find the volume of this cone. round to the nearest tenth. l=10 r-6

Answers

Answer:

376.8

Step-by-step explanation:

Formula Volume Cone = πr² * h/3

Volume = 3.14 * 36 * 3 1/3

Volume ≈ 376.8

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer: 301.6

-------------------

answer above isn't right this is, trust me.

If a number is chosen at random from the numbers 1 to
20 inclusive, what is the probability that a single-digit
number will be picked? ( give your answer in simplified
fractions eg. 2/5 when necessary)

Answers

Answer:

1/20

Step-by-step explanation:

only a single number can be chosen out of 20. And 1/20 is the most simplified it can get.

How do i solve 1+1=0

Answers

Answer:

Logically that's not possible but if you want to prove it then, you have to use a trick.

Step-by-step explanation:

1 + 1 = 1 + [tex]\sqrt{1}[/tex]

        = 1 + [tex]\sqrt{(-1) * (-1)}[/tex]  

        = 1 + [tex]\sqrt{(-1)}[/tex] * [tex]\sqrt{(-1)}[/tex]

        = 1 + [tex]\sqrt{i^2}[/tex] * [tex]\sqrt{i^2}[/tex]

        = 1 + i * i  

        = 1 + i^2

        = 1 + (-1)

        = 1 - 1

        = 0

So, 1 + 1 = 0

Hope this will help. Please give me brainliest.

Which of the following sets of numbers could not represent the three sides of a right triangle?

Answers

Answer:

25, 32, 40 can not form a right angle triangle.

Step-by-step explanation:

By Pythagoras theorem,

⇒ (40)² = (25)² + (32)²

⇒ 1600 = 625 + 1024

⇒ 1600 ≠ 1689

Answer:

option b

Step-by-step explanation:

according to the pythagoras theorem to be right angled triangle the sum of square of two smaller sides must be equal to the square of hypotenuse.

so ,

20 and 21 are smaller sides and hypotenuse be 29

pythagoras theorem

a^2 + b^2 = c^2

20^2 + 21^2 = 29^2

400 + 441 = 841

841 = 841  (since both sides are equal it forms right angled triangle)

25 and 32 are smaller sides and 40 be hypotenuse

a^2 + b^2 = c^2

25^2 + 32^2 = 40^2

625 + 1024 = 1600

1649 = 1600 (both sides are not equal so it does not form right angle triangle)

30 and 72 are smaller sides whereas 78 is hypotenuse

a^2 + b^2 = c^2

30^2 + 72^2 = 78^2

900 + 5184 = 6084

6084 = 6084 (since both sides are equal it forms right angled triangle )

32 and 60 are smaller sides and 68 is hypotenuse

a^2 + b^2 = c^2

32^2 + 60^2 = 68^2

1024 + 3600 = 4624

4624 = 4624  (since both sides are equal it forms right angled triangle )

Joshua wants to buy a flat-screen TV that’s costs $625.he save $62.50 each week to buy the TV. In how many weeks will he have enough money to make his purchase?

Answers

Answer:

in 10 weeks because if you multiply 62.50 10 times you get 625

Answer:

The answer is 10

I hope this helps

In 2001 , a youth clubs total income was £1000 the club spent 60% of its total income on renting a hall it further spent £250 on prizes work out the ratio

The amount spent on hall : amount spent on prizes

Answers

Answer:

12:5

Step-by-step explanation:

To calculate the ratio, we must first find the values of the two expenditures. The amount spent on renting a hall was 60% of £1000. To represent percentages in decimals, we can simply divide the percentage by 100, resulting in 0.6 here. We can then multiply this value by 1000 to get the amount spent on renting a hall, which comes out to £600

The ratio is then 600 : 250,  60 : 25 (divide both sides by 10) , or 12:5 (divide both sides by another 5)

How much will this trash can hold? It is 4 feet tall and has a base radius of 1 foot.
_____ cubic feet​

Answers

Answer:

volume = 12.56 cubic feet

Step-by-step explanation:

[tex]volume = \pi r^2 \times h \\\\volume = 3.14 \times 1 ^2 \times 4 = 3.14 \times 4 = 12. 56 \ cubic \ feet[/tex]

A random experiment was conducted where a Person A tossed five coins and recorded the number of ""heads"". Person B rolled two dice and recorded the larger number out of the two dice. Simulate this scenario (use 10000 long columns) and answer questions 10 to 13.

Answers

Answer:

(10) Person B

(11) Person B

(12) [tex]P(5\ or\ 6) = 60\%[/tex]

(13) Person B

Step-by-step explanation:

Given

Person A [tex]\to[/tex] 5 coins (records the outcome of Heads)

Person [tex]\to[/tex] Rolls 2 dice (recorded the larger number)

Person A

First, we list out the sample space of roll of 5 coins (It is too long, so I added it as an attachment)

Next, we list out all number of heads in each roll (sorted)

[tex]Head = \{5,4,4,4,4,4,3,3,3,3,3,3,3,3,3,3,2,2,2,2,2,2,2,2,2,2,1,1,1,1,1,0\}[/tex]

[tex]n(Head) = 32[/tex]

Person B

First, we list out the sample space of toss of 2 coins (It is too long, so I added it as an attachment)

Next, we list out the highest in each toss (sorted)

[tex]Dice = \{2,2,3,3,3,3,4,4,4,4,4,4,5,5,5,5,5,5,5,5,6,6,6,6,6,6,6,6,6,6\}[/tex]

[tex]n(Dice) = 30[/tex]

Question 10: Who is likely to get number 5

From person A list of outcomes, the proportion of 5 is:

[tex]Pr(5) = \frac{n(5)}{n(Head)}[/tex]

[tex]Pr(5) = \frac{1}{32}[/tex]

[tex]Pr(5) = 0.03125[/tex]

From person B list of outcomes, the proportion of 5 is:

[tex]Pr(5) = \frac{n(5)}{n(Dice)}[/tex]

[tex]Pr(5) = \frac{8}{30}[/tex]

[tex]Pr(5) = 0.267[/tex]

From the above calculations: [tex]0.267 > 0.03125[/tex] Hence, person B is more likely to get 5

Question 11: Person with Higher median

For person A

[tex]Median = \frac{n(Head) + 1}{2}th[/tex]

[tex]Median = \frac{32 + 1}{2}th[/tex]

[tex]Median = \frac{33}{2}th[/tex]

[tex]Median = 16.5th[/tex]

This means that the median is the mean of the 16th and the 17th item

So,

[tex]Median = \frac{3+2}{2}[/tex]

[tex]Median = \frac{5}{2}[/tex]

[tex]Median = 2.5[/tex]

For person B

[tex]Median = \frac{n(Dice) + 1}{2}th[/tex]

[tex]Median = \frac{30 + 1}{2}th[/tex]

[tex]Median = \frac{31}{2}th[/tex]

[tex]Median = 15.5th[/tex]

This means that the median is the mean of the 15th and the 16th item. So,

[tex]Median = \frac{5+5}{2}[/tex]

[tex]Median = \frac{10}{2}[/tex]

[tex]Median = 5[/tex]

Person B has a greater median of 5

Question 12: Probability that B gets 5 or 6

This is calculated as:

[tex]P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}[/tex]

From the sample space of person B, we have:

[tex]n(5\ or\ 6) =n(5) + n(6)[/tex]

[tex]n(5\ or\ 6) =8+10[/tex]

[tex]n(5\ or\ 6) = 18[/tex]

So, we have:

[tex]P(5\ or\ 6) = \frac{n(5\ or\ 6)}{n(Dice)}[/tex]

[tex]P(5\ or\ 6) = \frac{18}{30}[/tex]

[tex]P(5\ or\ 6) = 0.60[/tex]

[tex]P(5\ or\ 6) = 60\%[/tex]

Question 13: Person with higher probability of 3 or more

Person A

[tex]n(3\ or\ more) = 16[/tex]

So:

[tex]P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Head)}[/tex]

[tex]P(3\ or\ more) = \frac{16}{32}[/tex]

[tex]P(3\ or\ more) = 0.50[/tex]

[tex]P(3\ or\ more) = 50\%[/tex]

Person B

[tex]n(3\ or\ more) = 28[/tex]

So:

[tex]P(3\ or\ more) = \frac{n(3\ or\ more)}{n(Dice)}[/tex]

[tex]P(3\ or\ more) = \frac{28}{30}[/tex]

[tex]P(3\ or\ more) = 0.933[/tex]

[tex]P(3\ or\ more) = 93.3\%[/tex]

By comparison:

[tex]93.3\% > 50\%[/tex]

Hence, person B has a higher probability of 3 or more

PLEASE HELP ME FOR 15 POINTS AND BRAINLIEST QUICK! thanks.

Answers

Answer:

cumulative frequency

1

8

25

45

58

62

Answers:

Cumulative frequencies from top to bottom:

1825455862

Other answers:

There are 62 golfers total mode = 72Median is between slots  31   and  32   Median = 72

Refer to the diagram below

================================================

Explanation:

In the first row, the frequency is 1, so that's the cumulative frequency for that row. It's the total frequency so far.

In the second row, the cumulative frequency is now 8 because we add the two frequencies so far (1+7 = 8)

The third row will have a cumulative frequency of 1+7+17 = 25.

The rest of the rows will follow this pattern to fill out the table. Refer to the diagram below to see the filled out table.

----------------------------

At the very end, you should get 62 golfers total (the cumulative frequency for the bottom row).

The mode score is the most frequent value. In this case, that's the score 72 since it shows up the most times (ie has the largest frequency).

Because we have n = 62 people total, the median is between slots n/2 = 62/2 = 31 and 32

Go back to the table and note how 25 is the cumulative frequency for the third row. Since 25 is smaller than 31 and 32, this means that the median cannot be in the first three rows. Instead, it's in the fourth row because the frequency 17 here is more than enough to get us from slot 25 to slots 31 and 32.

In other words, the values 72 and 72 are in slots 31 and 32. The midpoint of which is 72.

The median is therefore 72.

Side note: the mode and median aren't always the same value.

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