6. Adlise Leiber started the day with a bank balance of $343.64.
She used another bank's ATM to withdraw $100 cash. The
charge for using the ATM was $2.50. Adlise then used her
card to make purchases of $85.10, $23.95, and $8.47. Find
the balance in her account after the bank processed these
transactions.

Answer:

make me brainliest

Step-by-step explanation:

1: x ≤ 18/5

2: x > 4

3: x  ≤ 4

4: x < 12

5: x > 1/4

6: x ≤ 2

7: x ≤ 5

8: x > 10

9: x < 5/2

10:7/3x^2 + 4/3x + 12

11: 2 < x < 15

12:25/2 < x ≤ 45/2

Answer:

Collect as many ants as you can with the container you have provided. A excellent approach to do this is to sprinkle some sugar or bread crumbs in a container and position it near the ant nest, where the ants will gather. A reasonable starting point is about 100.

Step-by-step explanation:

Hope it helps:)

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

[tex]\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}[/tex]

Then

[tex]Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\[/tex]

Note that since

[tex]F \cap R=\varnothing[/tex], [tex]Perm(F)\cap Perm(R)\ne \varnothing[/tex]

But since

[tex]B \cap R \ne \varnothing[/tex], [tex]Perm(B)\cap Perm(R)= \varnothing[/tex]

and

[tex]B \cap F \ne \varnothing[/tex] , [tex]Perm(B)\cap Perm(F)= \varnothing[/tex]

Since

[tex]|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\[/tex]

where [tex]|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}[/tex]

and

[tex]|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}[/tex]

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

[tex]|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}[/tex]

This link contains another solved problem on permutations:

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Answer: 32

Step-by-step explanation:

The roman numeral XXXII is 32 and XXIII is 23.

The number for this Roman numeral XXXII is, 32

Given that,

We have to write the number for this Roman numeral  XXXII.

Since, We know that,

X represent in number = 10

I represent in number = 1

Hence, The number for this Roman numeral  XXXII is,

⇒ XXXII

⇒ (10 + 10 + 10 + 1 + 1)

⇒ 32

Therefore, the number for this Roman numeral  XXXII is, 32

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Answer: 25.2 or 25

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

because you just devide

Answer:

a=180-(45+37)

b=180-(9+24)

c=180-(42+64)

d=180-(70+13)

Answer:

Interval Notation: [-2, 10]

Set Notation: {x|-2≤x≤10}

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

-25,- 10, -3, 0, 5, 7, 25

Answer:

  D.  21

Step-by-step explanation:

The first terms are ...

  5, 9, 8, 12, ...

Each even-numbered term is 3 more than the previous even-numbered term. Then the even-numbered terms are ...

   n = 2, 4, 6, 8, 10

  an = 9, 12, 15, 18, 21

Victor should say "21."

Step-by-step explanation:

the same factor of one dimension or one line applies then for all dimensions or lines.

the length goes from 16 to 32 cm. that means it doubles.

so, we need to double also the width :

10.5 × 2 = 21 cm

therefore, the first answer option is correct.

Step-by-step explanation:

x² + 6x + 9 = 2

(x + 3)² = 2

x + 3 = ±sqrt(2)

x = -3 ± sqrt(2)

so, B and D are correct.

control :

(-3 + sqrt(2))² + 6(-3 + sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) - 18 + 6sqrt(2) + 9 = 2

2 = 2

correct

(-3 - sqrt(2))² + 6(-3 - sqrt(2)) + 9 = 2

9 + 2 + 6sqrt(2) - 18 - 6sqrt(2) + 9 = 2

2 = 2

correct

(3 + sqrt(2))² + 6(3 + sqrt(2)) + 9 = 2

9 + 2 + 6sqrt(2) + 18 + 6sqrt(2) + 9 = 2

38 + 12sqrt(2) = 2

wrong.

(3 - sqrt(2))² + 6(3 - sqrt(2)) + 9 = 2

9 + 2 - 6sqrt(2) + 18 - 6sqrt(2) + 9 = 2

38 - 12sqrt(2) = 2

wrong.

Answer:

C

Step-by-step explanation:

ΔFDC and ΔFBA are similar          AA Similarity

sum is the process of adding two numbers.

Answer:

24 adults

Step-by-step explanation:

because it's just subtract 212-188=24

I think

Answer:

Step-by-step explanation:

Assume you are looking for an equation of the line passing through (4, -3) and having a slope - 1.

Use point-slope form:

or

Equation in point slope form

Answer:

leave at  1:30 PM

Step-by-step explanation:

10 mph 40 hours 6600/1200 5.5 hr  40/15 2 hr 40 mins 5.5 -.5 =

After two hours there at the meeting place, the helicopter must depart at 1:30 pm to join the boat.

Speed is the rate an object travels in a predetermined period of time.

Its speed is expressed in km/h. 

As per the given information in the question,

If the boat goes to the station ,

Speed of the boat = 10mph

it will take 400/10 = 40 hours.

The helicopter has, 6600 lbs of fuel.

It will take 30 minutes to clean the fisherman and an additional hour to get enough fuel.

1.5 × 1200 = 1800 lbs of fuel.

So, the amount of fuel helicopter now has

6600 - 1800

= 4800 lbs of fuel.

This will allow it to fly for 4 hours as:

4800 lbs/1200 lbs per hour, It can only travel at 150 mph for two hours one way.

= 300 miles distance from the station.

The boat is available at 400 miles, and its maximum flight time at 150 mph is two hours going one way, which is 100 miles from where it is now,

So,

100/10 = 10 hours, the journey to the meeting location will take the boat ten hours.

To reach the boat, which will require 10 hours, the chopper must take off after 8 hours since it will take 2 hours.

So 8 hours of time from 5:30 am will be equal to 1:30 pm.

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Your question seems incomplete, probably the complete question is:

A crewman on a fishing boat was injured and needs to be treated in a hospital right away. You are with a Coast Guard station nearest to the boat, but you are 400 miles away. The boat travels at a rate of 10 mph. It is 5:30 A.M. You have a helicopter that can hold 6600 lbs. of fuel, consumes 1200 pounds of fuel an hour, and travels 150 mph. However, you need to save a minimum of 1 hour worth of fuel for landing problems at the Coast Guard station, and you need to have 30 minutes’ worth of fuel to remove the crewman from the boat. You have to create a plan for extracting the crew member. When would you leave and why? Fully explain your answer.

Answer:

It's probably 1/4

Step-by-step explanation:

There won't be any change in the total mass of the atoms involved in a chemical reaction. According to the law of conservation of mass; it states that mass can neither be created nor destroyed in a chemical reaction. So, when atoms participate in a chemical reaction they might displace with other reactants but the total mass will remain the same.

_______

RainbowSalt2222 ☔

Answer:

Vector PQ = 48 deg

Vector QP = -PQ =  48 + 180 = 228 deg

Note that 228 is 48 deg below the -x (180) axis

[tex](8.1 + 7.4) - 25 \div 2.5 \\ = 15.5 - 25 \div 2.5 \\ = 15.5 - 10 \\ = 5.5[/tex]

5.5

Hope it helps.

Do comment if you have any query.

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\boxed{\mathsf{(8.1 + 7.4) - 25 \div 2.5}}\\\large\boxed{= \mathsf{\bold{15.5} - 25\div2.5}}\\\large\boxed{\mathsf{= 15.5 - \bf 10}}\\\large\boxed{\mathsf{= \bf 5.5}}\\\\\huge\boxed{\text{Therefore, your answer is: \textsf{5.5}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

B

Step-by-step explanation:

I only help you because you have nezuko as profile picture

His balance is $2,686.00

$2,000.00 + $1,000.00 = $3,000.00 + $450.00 = $3,450.00

$3,450.00 - (($275.00 + $40.00) + (($47.00 + $92.00) + ($101.00 + $209.00)) = $2,686.00

Answer:

Answer:

x = 4

Step-by-step explanation:

First we will subtract 7 from 11 to get

-x = 4 - 2x, next we will add 2x to -x to get

x = 4.

(It's just a matter of combining like terms.)

Hope this helps :)

Answer:

Step-by-step explanation:

The difference of sales between the first and the second days is the cost of 85 tickets:

Cost of a ticket:

Find the slope of these two points that's the cost

Slope

Step-by-step explanation:

what's the question ? it does not say.

I assume it is "how many packages of what size were sold ?"

x = number of small packages

y = number of medium packages sold

z = number of large packages sold

x + y + z = 9

7x + 12y + 15z = 86

y = 3z

these are the 3 equations we get out of the question.

we put the third equation into the other two :

x + 3z + z = x + 4z = 9

7x + 12×3z + 15z = 7x + 36z + 15z = 7x + 51z = 86

it of this first equation we get

x = -4z + 9

and putting that into the other equation :

7×(-4z + 9) + 51z = 86

-28z + 63 + 51z = 86

23z = 23

z = 1

y = 3z = 3×1 = 3

x = -4z + 9 = -4×1 + 9 = -4 + 9 = 5

so, 5 small, 3 medium and 1 large packages were sold.

Answer:

[tex] \frac{88}{4} \\ 22 \\ here \: u \: go[/tex]

Answer:

22 cm

Step-by-step explanation:

The angle subtended at the centre by the arc is 90°

This represents [tex]\frac{90}{360}[/tex] = [tex]\frac{1}{4}[/tex] of the circle

The arc length will be quarter of the circumference, that is

arc = [tex]\frac{1}{4}[/tex] × 88 = 22 cm

Answer:

  a) b^3

  b) x^3

Step-by-step explanation:

It can be helpful to think of the exponent as specifying the number of times the base is a factor in the product. Of course, common factors in the numerator and denominator cancel.

  [tex]\dfrac{b^7}{b^4}=\dfrac{b\cdot b\cdot b\cdot b\cdot b\cdot b\cdot b}{b\cdot b\cdot b\cdot b}=b\cdot b\cdot b=b^{7-4}=\boxed{b^3}[/tex]

__

  [tex]\dfrac{x\cdot x^5}{x^2\cdot x}=\dfrac{x\cdot x\cdot x\cdot x\cdot x\cdot x}{x\cdot x\cdot x}=x\cdot x\cdot x=x^{6-3}=\boxed{x^3}[/tex]

In this experiment design, the missing element is the control group.

In most experiments, the researcher will need to have a control group and an experimental group.

The control group is the one that is not given a treatment, for example, if you are testing an antibiotic, then the control group is the individuals that do not receive the medicine.

This group is important because it acts as a reference to measure the real effect in the experimental group or those receiving the treatment.

The control group is missing in this experiment because the research will need to measure the hours students spend studying on a regular cloudy day, in this way, he can later determine if there is a real difference between the number of hours on a sunny day vs the number of hours on a day that is not sunny.

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