$80 selling price 8% rate of sales tax. find the sales tax and the total cost

The mean of the sampling distribution will be 3.54. Thus, the correct option is C.

The population means is equal to the mean of the sampling distribution for all feasible samples of size 4. In this instance, 3.54 pounds is shown as the population means.

This suggests that the mean weight of the population of banana bunches will be 3.54 pounds if we pick several random samples of size four, compute the mean weight for each sample, and then average those sample means.

The Central Limit Theorem, which asserts that the sampling distribution of the sample means approaches a normal distribution centered on the population mean as the sample size grows, is a fundamental idea in statistics.

Thus, the correct option is C.

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Thomas can pack the items into a maximum of 20 bags, with each bag containing 24 items after calculated with greatest common divisor.

To find the maximum number of bags Thomas can pack, we need to find the greatest common divisor (GCD) of 120, 168, and 192. The GCD will represent the maximum number of items that can be packed into each bag.

To find the GCD, we can use the Euclidean algorithm. First, we find the GCD of 120 and 168:

168 = 1 * 120 + 48

120 = 2 * 48 + 24

48 = 2 * 24 + 0

Therefore, the GCD of 120 and 168 is 24.

Next, we find the GCD of 24 and 192:192 = 8 * 24 + 0

Therefore, the GCD of 120, 168, and 192 is 24.

So, Thomas can pack 24 items into each bag. To find the maximum number of bags he can get, we divide the total number of items by 24:

Total number of items = 120 + 168 + 192 = 480

Number of bags = 480 / 24 = 20

Therefore, Thomas can get a maximum of 20 bags.

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[tex] \Large{\boxed{\sf C = 31.40 \: inches}} [/tex]

[tex] \\ [/tex]

The circumference of a circle can be calculated using the following formula:

[tex] \Large{\sf C = 2 \pi r } [/tex]

Where:

[tex] \\ [/tex]

Since "a segment drawn from the center of a circle to a point on the circle" is actually the definition of the radius of said circle, we can take r = 5 inches.

[tex] \\ [/tex]

Applying our formula and using 3.14 for π, we get:

[tex] \sf C = 2 \times 3.14 \times 5in \\ \\ \implies \boxed{\boxed{\sf C = 31.4 \: inches = 31.40 \: inches}} [/tex]

Answer:

31.40 inches

Step-by-step explanation:

The circumference of a circle can be calculated using the formula:

Given:

Substitute the given value into the formula:

Simplifying the expression:

[tex]\therefore[/tex] The circumference of the circle is 31.40 inches.

1. cost of 3 1/10 mile for the taxi service charges: $0.40.

2. Relation is explained as direct proportional.

The top number of an improper fraction is greater than (or equal to) that bottom number.

Using the example:

The steps below can be used to change a mixed fraction into an improper fraction:

Fixed taxi charge = $1.00 for the first 1/10 mile

Additional charge = $0.10 mile

1. cost of 3 1/10 mile

covert mixed into improper = (30 +1)/10 = 31/10

The cost of 31/10 miles.

= $1.00 * 1/10 + (31/10 - 1/10)*$0.10

= $0.100 + 30/10*$0.10

= $0.100 + $0.30

= $0.40

2. As the distance increases the price also increases.

Relation is explained as direct proportional.

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Answer:

The second figure.

Step-by-step explanation:

The first figure's perimeter is:

70 in + 42 in + 56 in = 168 inches.

And the second figure's perimeter is:

42 in + 33 in + 33 in + 64 in = 172 inches.

Therefore, Figure 1 < Figure 2.

A, C, and D. The angles that have a measure of 180-x are angles that have a measure of 180 minus the value of x. In this case, x is equal to mz1, so the angles that have a measure of 180-x are √3, √5, and √10.

Angle is a mathematical concept that is used to measure the amount of rotation of a line or a plane around a point. An angle is typically measured in degrees, which is the unit of angular measurement. Angles are used in many different fields of mathematics, such as geometry, trigonometry, and calculus. In geometry, angles are used to measure the size of a triangle, the size of a circle, or the angle between two lines. In trigonometry, angles are used to solve problems involving the length of sides and the measure of an arc. In calculus, angles are used to measure the rate of change of a function.

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The dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 19 in. by 11 in. by cutting congruent squares from the corners and folding up the sides are 6.33 in. x 3.33 in. x 5.33 in. The volume of the box is 113.78 in³.

The dimensions of the box can be found with the following steps:

First, determine the side length of the square that is to be removed from each corner of the cardboard box. Since this will be done uniformly on all four corners, let the side length be x. The dimensions of the cardboard box can then be written as:

Length = 19 in. - 2x

Breadth = 11 in. - 2x

Height = x

After folding the cardboard along the creases, the base of the rectangular box will be (19 - 2x) in. by (11 - 2x) in. with the height of the box being x in. The volume of the box can then be found by multiplying the base and height of the box, i.e.,

Volume = (19 - 2x) (11 - 2x) x

Let V(x) be the volume of the rectangular box in terms of x. Then:

V(x) = (19 - 2x) (11 - 2x) x

Simplifying,

V(x) = 4x³ - 60x² + 209x

The maximum value of V(x) can be found by differentiating V(x) with respect to x and equating the result to zero. Therefore,

V'(x) = 12x² - 120x + 209 = 0

Solving, V(x) has a maximum value when x = 19/3 - 2(2/3)√14 or x = 19/3 + 2(2/3)√14. The value x = 19/3 - 2(2/3)√14 is the maximum value because x must be less than 5.5, which is the minimum of 11/2 and 19/2 divided by 3, the upper bound for x. Therefore, the dimensions of the box are

Length = 19 - 2(19/3 - 2(2/3)√14) = 6.33 in.

Breadth = 11 - 2(19/3 - 2(2/3)√14) = 3.33 in.

Height = 19/3 - 2(2/3)√14 = 5.33 in.

Thus, the dimensions of the box are 6.33 in. x 3.33 in. x 5.33 in. The volume of the box is:

V = 6.33 x 3.33 x 5.33 = 113.78 in³.

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Answer:

do you have the graph to solve it?

Total seats in plane: 186

108+64+14

5/7 of 14 is: 10

14÷7= 2

2x5= 10

5/16 of 64 is: 20

64÷16=4

5×4= 20

5/9 of 108 is: 60

108÷9= 12

12x5= 60

60+20+10=90

90/186 of seats are being used

simplified: 15/31

No

Answer:

yytyyyyy

Step-by-step explanation:

Let's assume that the length of the rectangle is x cm.

According to the problem, the width is 1/2 of the length. Therefore, the width is 1/2 x cm, or (1/2)*x cm.

The area of the rectangle is given as 388 square centimeters.

We know that the formula for the area of a rectangle is:

Area = Length x Width

So, we can plug in the values we have:

388 = x * (1/2)*x

Simplifying this equation:

776 = x^2

Taking the square root of both sides:

x = √776 ≈ 27.87 cm

Therefore, the length of the rectangle is approximately 27.87 cm, and the width is (1/2)*x, or approximately 13.94 cm.

So the dimensions of the rectangle are approximately 27.87 cm by 13.94 cm.

From the given data of hunters and do we find out there are 9 hunters and 15 dogs.

Let's assume that there were "h" hunters and "d" dogs.

Each hunter has two legs, and each dog has four legs, so the total number of legs can be expressed as:

2h + 4d = 78

We can simplify this equation by dividing both sides by 2:

h + 2d = 39

We also know that there were 24 heads in total, which includes the hunters and the dogs:

h + d = 24

We can now solve these two equations simultaneously to find the values of h and d.

First, we can solve for h in terms of d from the second equation:

h = 24 - d

We can substitute this expression for h in the first equation:

(24 - d) + 2d = 39

Simplifying and solving for d:

d = 15

Now that we know there were 15 dogs, we can substitute this value back into one of the equations to find the number of hunters:

h + d = 24

h + 15 = 24

h = 9

Therefore, there were 9 hunters and 15 dogs.

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The length of a side of the square is 8 cm.

What do you mean by perimeter of a rectangle and square?

When a wire is bent into the shape of a rectangle, its length becomes the perimeter of the rectangle. Similarly, when the wire is reshaped into a square, its length becomes the perimeter of the square.

The perimeter of a rectangle is given by the formula [tex]P=2(l+w)[/tex] , where [tex]l[/tex] is the length and [tex]w[/tex] is the width.

The perimeter of a square is given by the formula [tex]P=4s[/tex] , where [tex]s[/tex] is the length of a side.

Calculating the length of a side of the square:

The length of the rectangle is 11 cm and the width is 5 cm.

Therefore, the perimeter of the rectangle is [tex]P=2(11+5)=32[/tex] cm.

Since the wire is reshaped into a square, the perimeter of the square is also 32 cm.

Using the formula [tex]P=4s[/tex], we can solve for the length of a side of the square:

[tex]32 = 4s[/tex]

[tex]s = 32/4[/tex]

[tex]s = 8[/tex]

Therefore, the length of a side of the square is 8 cm.

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Answer:

8×21=168? That would make it 168=168? Or you could multiply even more to make 8×25 or somethin?

Step-by-step explanation: I don't know what answer ur looking for but there's some help

Answer:

x < 21.

Step-by-step explanation:

Given the equation: 8x < 168, solve the inequality.

First, make it as if it was an equality and solve x:

8x = 168  (Divide both sides by 8)

x = 21

That means x < 21.

If the rectangle is 40 cm long, 30 cm wide, and 20 cm high, then its volume will be given as 24000 cubic centimeter.

Volume is defined as the space enclosed by the three dimensional figure in itself. No two dimensional object can have volume as volume can be determined only when the length, breadth and height of the figure is known and the value of height is missing in two dimensional figures.

The formula for volume of a cuboid which has rectangular faces is given as follows:

Volume of cuboid = Length × Breadth × height

Volume of cuboid = 40 × 30 × 20

Volume = 24000 cubic centimeter

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Refer to complete question below:

Find the volume of a rectangular cuboid whose dimensions are given as 40 cm long, 30 cm wide, and 20 cm high.

Answer:

x = 4

Step-by-step explanation:

Alternative interior angles means these angles are equal in magnitude and sign

[tex]{ \tt{(20x + 10) = (10x + 50)}} \\ \\ { \tt{20x - 10x = 50 - 10}} \\ \\ { \tt{10x = 40}} \\ \\ { \tt{x = 4}}[/tex]

The null hypothesis (H0) proposed by the friend is H0: p^ = 0.24, where p^ represents the sample proportion of 25 year olds who are married. The alternative hypothesis (Ha) is Hα: p^ ≠ 0.24.

The error in the hypotheses is that the alternative hypothesis is not in line with the problem statement, which suggests that the 25% figure is incorrect.

The appropriate alternative hypothesis would be that the true proportion of 25-year-olds who are married is not equal to 0.25. Therefore, the correct alternative hypothesis would be Ha: p^ ≠ 0.25.

In summary, the correct set of hypotheses for this problem would be:

H0: p^ = 0.25 (Null hypothesis)

Ha: p^ ≠ 0.25 (Alternative hypothesis)

We would use a significance level and statistical test to determine whether we have enough evidence to reject the null hypothesis in favor of the alternative hypothesis.

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Answer:

Step-by-step explanation:

5+3x/4 = 7/12

[(5*4)+3x]/4 = 7/12

(20+3x)/4 = 7/12

20+3x = 7/12*4

20+3x = 7/3

3x = 7/3 - 20

3x = [7-(20*3)]/3

3x = (7-60)/3

3x = -53/3

x = -53/3/3/1 ( reciprocal )

x = -53/3*1/3

x= -53/9

An inequality representing the amount that the island of Martinique can received for hurricane relief efforts, where x is the number of days is y ≤ 32,000 + 4,500x.

Inequality is an algebraic statement that two or more mathematical expressions are unequal.

Inequalities can be represented as:

The total amount received by the island = $32,000

The daily receipt of donations = $4,500

Let the number of days = x

Let the funds raised for aid = y

y ≤ 32,000 + 4,500x

Thus, the inequality for the funds that the island can fundraise for hurricane relief aid by the end of the month is y ≤ 32,000 + 4,500x.

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The approximate area under the curve f(t) = 1/t when found between 1 and 3 is equivalent to option D: 1.1.

Calculating an integral is called integration. Mathematicians utilize integrals to determine a variety of useful quantities, including areas, volumes, displacement, etc. Usually, when we talk about integrals, we mean definite integrals. One of the two primary calculus topics in mathematics, along with differentiation, is integration.

We can find the approximate area using the concept of integration as follows:

[tex]\int\limits^3_1 {1/t} \, dt[/tex]

We generally know that:

[tex]\int\limits^a_b {x} \, dx[/tex]= ㏑(x)

Therefore,

[tex]\int\limits^3_1 {1/t} \, dt[/tex]

= ㏑ (3) - ㏑ (1)

= 1.1, more specifically it would be 1.09.

From the table of logarithm, you can verify is equivalent to 1.1.

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Correct question is:

In Exploration 3.1.1 you found the area under the curve f(t)=1/t

between 1 and 3. What was the approximate area that you came

up with?

A. 1.3

B. .9

C. .7

D. 1.1

Answer:

Below.

Step-by-step explanation:

Yes.

-9 = 3/4x - 3     -6 = 3/4 x     x = -8

-6 = 3/4x - 3    -3 = 3/4 x     x = -4  (there's a pattern!)

0 = 3/4x - 3    3 = 3/4 x     x = 4

3 = 3/4x - 3    6 = 3/4 x     x = 8

Hope this helps!

Any number b greater than -90 will satisfy the inequality. We can express the solution in interval notation as: b ∈ (-90, ∞)

An inequality is a mathematical statement that compares two values or expressions using the symbols "<" (less than), ">" (greater than), "<=" (less than or equal to), ">=" (greater than or equal to), or "≠" (not equal to).

Starting from the given inequality:

7 + (b/45) > 5

We can solve for b by first subtracting 7 from both sides:

b/45 > 5 - 7

Simplifying the right-hand side:

b/45 > -2

Multiplying both sides by 45 to isolate b:

b > -2 * 45

b > -90

Therefore, any number b greater than -90 will satisfy the inequality. We can express the solution in interval notation as:

b ∈ (-90, ∞)

For example, x > 5 is an inequality that states that x is greater than 5, while y ≤ 10 is an inequality that states that y is less than or equal to 10.

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You poured approximately 0.267 liters of cooking oil from the entire large bottle into the smaller bottle.

To find out how much of the entire large bottle of cooking oil was poured into the smaller bottle, we need to multiply the fraction of the large bottle that was poured into the smaller bottle by the total amount of cooking oil in the large bottle.

Given that you have [tex]\frac{4}{9}[/tex] of the large bottle of cooking oil, the fraction of the large bottle that you poured into the smaller bottle is [tex]\frac{3}{5}[/tex] of [tex]\frac{4}{9}[/tex]. We can find this fraction by multiplying [tex]\frac{3}{5}[/tex] by [tex]\frac{4}{9}[/tex]:

[tex]\frac{3}{5} * \frac{4}{9} = \frac{12}{45}[/tex]

Simplifying this fraction by dividing both numerator and denominator by 3, we get:

[tex]\frac{12}{45}= \frac{4}{15}[/tex]

Therefore, you poured [tex]\frac{4}{15}[/tex] of the entire large bottle of cooking oil into the smaller bottle. To find the actual amount, you can multiply this fraction by the total amount of cooking oil in the large bottle. For example, if the large bottle contains 1 liter of cooking oil, then you poured:

[tex]\frac{4}{15} * 1 = 0.267[/tex] liters.

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Probability of D2 being sunny = 0.78.

On day 1, which is called D1, the probability of sunny is 0.9. It is also given that a sunny day follows a sunny day with 0.8 chance, and a sunny day follows a rainy day with 0.6 chance.

Therefore, we need to find the chances that D2 is sunny.

There are two possibilities for D2: either it can be a sunny day, or it can be a rainy day.

Now, Let us find the probability of D2 being sunny.

We have the following possible cases for D2.

D1 = Sunny; D2 = Sunny

D1 = Sunny; D2 = Rainy

D1 = Rainy; D2 = Sunny

D1 = Rainy; D2 = Rainy

The probability of D1 being sunny is 0.9.

When a sunny day follows a sunny day, the probability is 0.8.

When a sunny day follows a rainy day, the probability is 0.6.

Therefore, the probability of D2 being sunny is given by the formula:

Probability of D2 being sunny = (0.9 × 0.8) + (0.1 × 0.6) = 0.72 + 0.06 = 0.78.

Therefore, the probability that D2 is sunny are 0.78 or 78%.

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The dimensions of the box to minimize the cost of materials are 3.16 cm x 3.16 cm x 3.16 cm.

To minimize the cost of materials for the jewelry box with a square base, you will need to find the dimensions of the box. The volume of the box is 40 cm3. The sides of the box will be silver plated and cost $12 per cm2, while the top and bottom will be nickel plated and cost $1 per cm2.

Since the box has a square base, each of the sides has the same area and the total area of the box is four times the area of one side. To minimize cost, the sides of the box need to be as small as possible. The equation for the area of a square is A = l2.

We can use this equation to find the length of one side of the box. 40 cm3 = l2 x 4, so l2 = 10 cm2. The length of one side of the box is the square root of 10, which is approximately 3.16 cm.

Therefore, the dimensions of the box to minimize the cost of materials are 3.16 cm x 3.16 cm x 3.16 cm.

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In Bitcoin, when a merchant waits for n confirmation of a payment transaction before providing the product, there is a risk of a double-spend attack. In this situation, the network is aware of a branch crediting the merchant, which has n blocks on top of the one in which the fork started.

      By simulating m as a negative binomial variable, P(m) = (m + n - 1m)pnqm can be used to more precisely compute this probability for a given value of m.

           The attacker, on the other hand, has a branch with only m additional blocks. If we assume the honest network and the attacker have a proportion of p and q of the total network hash power, respectively, the probability of the attacker catching up when he is currently z blocks behind is given by az = paz+1 + qaz−1, where a is a constant.

          To calculate the probability more accurately, we can model m as a negative binomial variable.

          This is the number of successes (blocks found by the attacker) before n failures (blocks found by the honest network), with a probability q of success.

          The probability for a given value m is then given by P(m) = (m + n - 1m)pnqm.

         Thus, when dealing with a double-spend attack in Bitcoin, the probability that the attacker will be able to catch up is given by az = paz+1 + qaz−1, where a is a constant.

              This probability can be more accurately calculated by modeling m as a negative binomial variable, with the probability for a given value m given by P(m) = (m + n - 1m)pnqm.

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The total area under the curve for x ≥ 6 is 449/4500.

The area under the curve y = 2x-3 from x = 6 to x = t and its evaluation at t = 10 and t = 100The area under the curve y = 2x-3 from x = 6 to x = t can be calculated as follows:

We know that the area of the region under the curve f(x) between x = a and x = b is given by [tex]A = ∫abf(x)dx[/tex]

Since the given function is y = 2x-3, we can write it as y = 2x^(-3) by applying the power rule.

Hence,A = [tex]∫62x^(-3)dx = [-2x^(-2)]6t = -2/t^2 + 2/36[/tex]We need to evaluate this area for t = 10 and t = 100, so we get[tex]A = -2/10^2 + 2/36 = -1/25 + 1/18 = 7/450andA = -2/100^2 + 2/36 = -1/5000 + 1/18 = 449/4500[/tex]Total area under this curve for x ≥ 6

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Answer: FALSE

Step-by-step explanation:

                                   1500 decagram = 15 kg

                                      1 decagram = 0.01 kg

                                       1500 decagram = 1500/0.01 kg

                                                                   = 1500/100 kg

                                        1500 decagram = 15kg  

Answer:[tex]\frac{8}{9}[/tex]

Step-by-step explanation:

Four fifths=4/5

two ninths=2/9

[tex]\frac{4}{5} *5*\frac{2}{9}=\frac{8}{9}[/tex]

Assuming you meant ( four fifths ) * 5 * ( two ninths ), the answer would be 0.88888888888.

If you meant 4/5 x 5 and then x 2/9, the answer would be 8/9, because 4/5 x 5 is 4, and 4 x 2/9 is 8/9.

a. Yes, the sampling distribution of the sample mean is a normal distribution with a mean of $52000 and a standard error of $\frac{4800}{\sqrt{17}}$.

b. Yes, the sampling distribution of the sample mean is a normal distribution with a mean of $52000 and a standard error of $\frac{4800}{\sqrt{51}}$.

c. You would need to know that the population distribution of X, teacher salaries, is normal in order to answer the questions regarding any sample size.

d. Assuming a sample size of 51, the probability that the sampling error is within $1000 is approximately 0.84 or 84%.

e. Assuming a sample size of 51, the 90th percentile for the average teacher's salary is approximately $54488.

f. Assuming that teacher's salaries are normally distributed, the 90th percentile for an individual teacher's salary is approximately $56396.

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