98. In Fig. 24-71, a metal sphere

with charge q = 5.00 uC and radius

r = 3.00 cm is concentric with a

larger metal sphere with charge Q =

15.0 uC and radius R = 6.00 cm. (a)

What is the potential difference be-

tween the spheres? If we connect the

spheres with a wire, what then is the

charge on (b) the smaller sphere and

(c) the larger sphere?

Answers

Answer 1

Answer:

(a) The potential difference between the spheres is 750 kVA

(b) The charge on the smaller sphere is 6.[tex]\overline 6[/tex] μC

(c) The charge on the smaller sphere, Q₁ = 13.[tex]\overline 3[/tex] μC

Explanation:

(a) The given parameters are;

The charge on the inner sphere, q = 5.00 μC

The radius of the inner sphere, r = 3.00 cm = 0.03 m

The charge on the larger sphere, Q = 15.0 μμC

The radius of the larger sphere, R = 6.00 cm = 0.06 m

The potential difference between two concentric spheres is given according to the following equation;

[tex]V_r - V_R = k \times q \times \left ( \dfrac{1}{r} - \dfrac{1}{R} \right)[/tex]

Where;

R = The radius of the larger sphere = 0.06 m

r = The radius of the inner sphere = 0.03 m

q = The charge of the inner sphere = 5.00 × 10⁻⁶ C

Q = The charge of the outer sphere = 15.00 × 10⁻⁶ C

k = 9 × 10⁹ N·m²/C²

Therefore, by plugging in the value of the variables, we have;

[tex]V_r - V_R = 9 \times 10^9 \times 5.00 \times 10^{-6} \times \left ( \dfrac{1}{0.03} - \dfrac{1}{0.06} \right) = 750,000[/tex]

The potential difference between the spheres, [tex]V_r - V_R[/tex] = 750,000 N·m/C = 750 kVA

(b) When the spheres are connected with a wire, the charge, 'q', on the smaller sphere will be added to the charge, 'Q', on the larger sphere which as follows;

[tex]Q_f[/tex] = Q + q = (5 + 15) × 10⁻⁶ C = 20 × 10⁻⁶ C

[tex]Q_f[/tex] = 20 × 10⁻⁶ C

From which we have;

Q₁/Q₂ = R/r

Where;

Q₁ = The new charge on the on the larger sphere

Q₂ = The new charge on the on the smaller sphere

[tex]Q_f[/tex] = 20 × 10⁻⁶ C = Q₁ + Q₂

∴ Q₁ = 20 × 10⁻⁶ C - Q₂ = 20 μC - Q₂

∴ (20 μC - Q₂)/Q₂ = 0.06/(0.03) = 2

20 μC - Q₂ = 2·Q₂

20 μC = 3·Q₂

Q₂ = 20 μC/3

The charge on the smaller sphere, Q₂ = 20 μC/3 = 6.[tex]\overline 6[/tex] μC

(c) Q₁ = 20 μC - Q₂ = 20 μC - 20 μC/3 = 40 μC/3

The charge on the smaller sphere, Q₁ = 40 μC/3 = 13.[tex]\overline 3[/tex] μC.

Answer 2

The potential difference is 7.5*10^5V and the charge on the smaller sphere is 6.67uC while the charge on the larger sphere is 13.34uC

Data;

q = 5.0 uCr = 3.0cm= 0.03mQ = 15.0uCR = 6.0cm = 0.06m

Potential Difference between the Spheres

for the inner sphere;

[tex]v_i = \frac{kq}{r} = \frac{(9*10^9)(5*10^-^6)}{0.03} \\v_i = 1.5*10^6V[/tex]

for the outer sphere;

[tex]v_o = \frac{KQ}{R} = \frac{(9*10^9)(15*10^-^6)}{0.06} = 2.25 * 10^6V[/tex]

The difference in potential is

[tex]\delta V = v_o - v_i = 2.25*10^6 - 1.5*10^6 = 7.5*10^5V[/tex]

Charge on the Smaller Plate

[tex]q + Q = 5 + 15 = 20 \mu C = 20*10^-^6C ..eq(i)[/tex]

The sharing of charge continues till they attain a point of equal potential

[tex]v_i = v_o \\\frac{kq}{r} = \frac{kQ}{R} \\\frac{q}{0.03} = \frac{Q}{0.06} \\Q= 2q ...eq(ii)\\[/tex]

let's solve for equation (i) and equation (ii)

[tex]q+2q = 20\mu C\\q = 6.67 \mu C[/tex]

The charge on the smaller sphere is 6.67uC

The charge on the larger sphere

The charge on the larger sphere is

[tex]Q = 2q\\q = 6.67 \mu C\\Q = 2 * 6.67 = 13.34 \mu C[/tex]

The charge on the larger sphere is 13.34uC

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Related Questions

Sometimes, a crackling sound is heard while taking off a sweater during winters. Explain

Answers

Answer:

it is somewhat frozen

Explanation:

Which does energy never do?

it never grows

it never disappears

it never lessens

it never changes
PLZZ answer With THE CHOICES PROVIDED THANKS!!!!

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It never disappears I believe

What generally happens when a comet nears the sun?
A
It freezes.
B
Its gas burns up
С
It becomes an asteroid.
D
It becomes a meteorite.

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It's probably B or A

Answer:

B: its gas burns up

Explanation:

Because when it close to the sun it burns it gas of how hot the sun is.

A spring is hung vertically from a hook. A 500g mass is hung from the spring and the spring stretches 0.01m from equilibrium. If the mass is then pulled 0.02m MORE and released what will be the acceleration of the mass just as it is released? (show work)

Answers

Answer:

See the explanation below.

Explanation:

By means of Hooke's second law, we can calculate the spring constant with the initial conditions of the problem.

[tex]F=k*x[/tex]

where:

k = spring constant [N/m]

x = distance = 0.01 [m]

F = force or weight [N]

Weight can be calculated by means of the product of mass by gravitational acceleration.

m = mass = 500[g] = 0.5[kg]

[tex]W=F=m*g\\W = 0.5*9.81\\W= 4.905[N][/tex]

Now the spring constant can be calculated:

[tex]k=F/x\\k=4.905/0.01\\k = 490.5[N/m][/tex]

We must now use the same Hooke's law to determine the new spring force when stretching it 0.03 [m]

[tex]F_{new}=k*x\\F_{new}=490.5*0.03\\F_{new}=14.715[N][/tex]

Now we have to use Newton's second law to calculate acceleration. We must remember that Newton's Second Law tells us that the sum of forces is equal to the product of mass by acceleration.

[tex]F=m*a[/tex]

where:

F = Fnew = 14.715[N]

m = mass = 500 [g] = 0.5 [kg]

a = acceleration [m/s²]

Now replacing:

[tex]14.715=0.5*a\\a=14.715/0.5\\a=29.43[m/s^{2} ][/tex]

what is a work done on a body moving in a circular path ​

Answers

Zero

This is because, when a body moves in a circular path, then the centripetal force acts along the radius of the circle, and it is at right angles to the motion of the body.

Calculate the force between two objects that have masses of 70 kilograms and 2,000
kilograms separated by a distance of 1 meter.

Answers

Answer:

1. 9.338×10¯⁶ N

2. 5.28×10¯¹⁰ N

Explanation:

1. Determination of the force

Mass of 1st object (M₁) = 70 Kg

Mass of 2nd object (M₂) = 2000 Kg

Distance apart (r) = 1 m

Gravitational constant (G) = 6.67×10¯¹¹ Mm²/Kg²

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 70 × 2000 / 1²

F = 6.67×10¯¹¹ × 70 × 2000 / 1

F = 9.338×10¯⁶ N

2. Determination of the force.

Mass of 1st fruit (M₁) = 0.45 Kg

Mass of 2nd fruit (M₂) = 0.45 Kg

Distance apart (r) = sum of their radius = 0.08 + 0.08 = 0.16 m

Gravitational constant (G) = 6.67×10¯¹¹ Mm²/Kg²

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 0.45 × 0.45 / 0.16²

F = 6.67×10¯¹¹ × 0.45 × 0.45 / 0.0256

F = 5.28×10¯¹⁰ N

please fast if you solve this you will get 20 point

Answers

true
false
true
true
true

PLZ HELP ASAP THX


If scientists is designing a device to create high energy electromagnetic waves which type of wave would the device most likely create?


Microwaves

Infrared waves

Ultraviolet waves

Gamma ray waves

Answers

Answer:

Gamma ray waves

Explanation:

Gamma ray waves carry the most energy electromagnetic waves.

Hope this helps, thank you !!

Which vector has an x-component with a length of 3?
А. С.
B. d
C. a
D. b

Answers

Answer:

B.d

mark me as brainlist

Answer:

D. b

Explanation:

the endpoint of vector b is at 3, which means the length is 3

Who thinks this a ufo? The following images are from a rare footage.

Answers

Answer:

That might be a sled ngl but it looks like a ufo but it's definitely not

Answer:

the reptilians gave there tech to the nazis and the reptilians are currently living underground in Antarctica but id'k about that pic

Explanation:

Which of the following technologies would produce the most energy in light
waves?
A. Infrared sensor on a DVD player
B. Wireless communications transmitter
C. Microwave industrial drying equipment
D. Compact fluorescent lightbulb

Answers

Answer:

D. Compact fluorescent lightbulb

Explanation:

Compact fluorescent lightbulb

A compact fluorescent light bulb would produce the most energy in light

waves, therefore the correct option is D.

What is electromagnetic radiation?

Electromagnetic radiation is a type of energy radiation produced by the propagation of electromagnetic waves that are produced for natural as well as anthropogenic reasons. This radiation does not need any kind of medium to propagate. The electromagnetic wave has components of light as well as heat in them.

Different kinds of electromagnetic radiation have varied levels of energy for example solar radiation is also a form of electromagnetic radiation and gamma radiation is electromagnetic radiation with very high energy.

Most energy in the form of the light wave is produced by the Compact fluorescent lightbulb, therefore the correct option is D.

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A crane drops a 0.25kg steel ball onto a steel plate. The ball's speeds just before impact and after are 5.0m/s and 4.7m/s, respectively. If the ball is in contact with the plate for 0.035s, what is the magnitude of the average force that the ball exerts on the plate during impact?

Answers

Answer:

2.14N

Explanation:

According to Newtons second law

F = ma

F = m(v-u)/t

m = 0.25kg

v= 5.0m/s

u = 4.7m/s

t = 0.035s

Substitute

F = 0.25(5-4.7)/0.035

F = 0.25(0.3)/0035

F = 0.075/0.035

F = 2.14N

Hence the required force is 2.14N

I need to find the total mechanical energy. I think the first one is correct but the second one is wrong

Answers

Answer:

di ko po alam ang sagot baka

po pang grade 9 po yan

Explanation:

sana po magets nyo po

A student that just received their driver’s license decides to buy a new car. He remembers from physics class that heat engines have a thermal efficiency that can be calculated. He asks the car dealer for a car that has a high thermal efficiency rating. The car dealer says he has a car that is 100% efficient.

Which law of thermodynamics best describes why the car cannot be 100% efficient?

Answers

Answer:

Second law of thermodynamics.

Explanation:

The second law of thermodynamics states that: "in all energy exchanges, if there is no energy entering or leaving the system, then it means the potential energy of that particular state will definitely be less than the potential energy it had at it's initial state."

Now, for a car to be 100% efficient, it means that there must be some form of heat transfer to the environment. However, this is a violation of the second law of thermodynamics and as such it can't be 100% efficient.

The law that  best describes why the car cannot be 100% efficient is the second law of thermodynamics.

Thermodynamics is the study of heat. Heat is a form of energy that exists as a result of temperature difference between bodies.

According to the second law of thermodynamics, the conversion of energy  from one form to another is not 100% efficient. As such, the thermal efficiency of the engine can be calculated.

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Which of the following is part of the cycle of violence? (Select all that apply)
A. period of calm
B. violent episode
C. making up
D. tension-building

Answers

B,C,D i believe. Hope this help

The resistance of the coil of a
galvanometer is 9.3692 and a current of 0.0224 A causes it
to deflect full scale. The only shunt available has a
resistance 0.02522. What resistance must be connected in
series with the coil to make it an ammeter of range 0 - 20A?​

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Answer:

54 is the correct answer to this question

It is not important to check for a safe, flat surface prior to jumping rope

True
False

Answers

The answer is false because you always need to be safe before doing a physical activity around other people

Answer:

False

Explanation:

You wouldn't want to jump on a rocking uneven area where you could fall and hurt yourself would you? No, so you'd check for a flat surface

Please any one help me

Answers

Answer:

Which one are we supposed to do

Explanation:

Stored digital data are easily changed. How could this be a disadvantage?
A. Changing data results in too much data to be stored in most
computers
B. Easily changed data are difficult to protect with a security system.
c. Once a change is made, the change is permanent.
D. True information in the digital data can be changed to false
information
SUBMIT
I need help on this

Answers

The disadvantage of  easily changeable  digital data is: true information in the digital data can be changed to false information. Hence, option (D) is correct.

What is digital data?

Digital data, in information theory and information systems, is information represented as a string of discrete symbols, each of which can take on one of only a finite number of values from some alphabet, such as letters or digits.

An example is a text document, which consists of a string of alphanumeric characters. The most common form of digital data in modern information systems is binary data.

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Answer:  The answer is  D.  

Explanation:   I took the test

m/s
3. A ferryboat accelerates from rest at a rate of 0.500 m/s2.
a. What is the velocity of the boat after it has traveled 4.75 m?
b. What is the velocity if the boat has traveled 50 m?

Answers

Answer:

a. Final velocity, V = 2.179 m/s.  

b. Final velocity, V = 7.071 m/s.

Explanation:

Given the following data;

Acceleration = 0.500m/s²

a. To find the velocity of the boat after it has traveled 4.75 m

Since it started from rest, initial velocity is equal to 0m/s.

Now, we would use the third equation of motion to find the final velocity.

[tex] V^{2} = U^{2} + 2aS [/tex]

Where;

V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square. S represents the displacement measured in meters.

Substituting into the equation, we have;

[tex] V^{2} = 0^{2} + 2*0.500*4.75 [/tex]

[tex] V^{2} = 4.75 [/tex]

Taking the square root, we have;

[tex] V^{2} = \sqrt {4.75}[/tex]

Final velocity, V = 2.179 m/s.

b. To find the velocity if the boat has traveled 50 m.

[tex] V^{2} = 0^{2} + 2*0.500*50 [/tex]

[tex] V^{2} = 50 [/tex]

Taking the square root, we have;

[tex] V^{2} = \sqrt {50}[/tex]

Final velocity, V = 7.071 m/s.

A student passed a current of 0.6 A through copper sulfate solution for 300 s

Calculate the charge flow through the solution.

Answers

737328644737727363743773784
q = I t

q = (0.6) (300)

q = 180 C

A student drops a ball out of a helicopter flying 40.0m/s horizontally at an altitude (height) of 77.0m. Neglect drag.
How long did the ball remain in the air?
How far did the ball travel horizontally before striking the ground?

Answers

Step by step explanation :the ball remained 45 seconds

Fill in the blanks:
1. When a spring is pulled, the _____ is proportional to the ______ ( called ____ law.
2.Weight is the force of ____ on an object due to the pull of the _____
3. Weights and other forces are measured in ______
4. Here on Earth, the pull of gravity on a mass of 1 kg is ______ Newtons
5. Weight is measured by a _____ balance and _______ from place to place
6. Newton's first law says: every mass stays at _______ or moves at constant _______ in a _______ line unless a resultant _______ acts on it
7. To move in a _______ orbit, an object must have a _______ force on it

Answers

Answer:

st8tif7u

Explanation:

t996w4sia74a85e8srz

define monsoon.....? ​

Answers

Answer:

A monsoon is traditionally a seasonal reversing wind accompanied by corresponding changes in precipitation but is now used to describe seasonal changes in atmospheric circulation and precipitation associated with the asymmetric heating of land and sea

Explanation:

A boat has a porthole window, of area 0.00849 m^2, 6.25 m below the surface. The density of sea water is 1027 kg/m^3. The air inside the boat is at 1 atm. What is the net force on the window?

Answers

Answer:

[tex]325.65\ \text{N}[/tex] outward.

Explanation:

[tex]\rho[/tex] = Density of water = [tex]1027\ \text{kg/m}^3[/tex]

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

h = Height of the water = 6.25 m

A = Area of the window = [tex]0.00849\ \text{m}^2[/tex]

[tex]P_i[/tex] = Internal pressure of the boat = [tex]1\ \text{atm}=101325\ \text{Pa}[/tex]

Pressure by the water on the window

[tex]P=\rho gh\\\Rightarrow P=1027\times 9.81\times 6.25\\\Rightarrow P=62967.9375\ \text{Pa}[/tex]

Net pressure on the window

[tex]P_n=P-P_i=62967.9375-101325=-38357.0625\ \text{Pa}[/tex]

Force is given by

[tex]F=P_nA\\\Rightarrow F=-38357.0625\times 0.00849\\\Rightarrow F=-325.651460625\ \text{N}[/tex]

Net force on the window is [tex]325.65\ \text{N}[/tex] outward.

Answer: 534.6 N

Explanation:

This answer works for Acellus!

Complete the sentences to describe the difference between speed and velocity.
Speed describes how fast an object moves. Speed is described by
with
Velocity is described by
Tand time
and time. Velocity is speed

Answers

Answer:

velocity =displacement/time

and speed =distance/time

Answer:
a) Distance

b) Direction

c) Displacement

Explanation:

jus did it on edeg

A negative charge of -2 C and a positive charge of 5 C are separated by 84,752 m. What is the force between the two charges?

Answers

Answer:

F = 12.52 N

Explanation:

Given that,

Charge, q₁ = -2 C

Charge, q₂ = 5 C

The distance between charges, d = 84,752 m

We need to find the force between the two charges. The force between two charges is given by :

[tex]F=k\dfrac{q_1q_2}{d^2}\\\\F=9\times 10^9\times \dfrac{2\times 5}{(84752)^2}\\F=12.52\ N[/tex]

So, the force between charges is 12.52 N.

example of nuclear fission​

Answers

Answer:

In nuclear power plants, energetic neutrons are directed into a sample of the isotope uranium-235. ... A common fission reaction produces barium-141 and krypton-92. In this particular reaction, one uranium nucleus breaks into a barium nucleus, a krypton nucleus, and two neutrons

From base camp, a park ranger drives 27 meters at 32 degrees East of North, then 40 meters at 58 degrees West of North, and finally 39 meters directly West in an attempt to rescue a lost hiker.

Answers

Answer:

R = 73.34 m,   θ = 37º North of West

Explanation:

In this exercise you are asked to find the distance traveled.

The best way to do this is with a Cartesian coordinate system, let's use a system where the x axis coincides with the West - East direction), to decompose the trajectories

First trajectory

distance d₁ = 27 m

Direction 32 East of North, this angle is measured from the vertical direction (y-axis)

           cos 32 = y₁ / d₁

           sin 32 = x₁ / d₁

           y₁ = d₁ cos 32

           x₁ = d₁ sin 32

           y₁ = 27 cos 32 = 22.90 m

           x₁ =  27 sin 32 = 14.31 m

second trajectories

distance d2 = 40 m

direction 58 West from North, the angle is measured with respect to the y axis, towards the negative side of the x axis

            cos 58 = y₂ / d₂

            sin 32 = x₂ / d₂

            y₂ = d₂ cos58

            x₂ = d₂ sin 58

            y₂ = 40 cos 58 = 21.20 m

            x₂ = 40 sin 58 = -33.92 m

The negative sign of the x coordinate is due to the fact that the displacement is towards the West (negative of the x axis)

third trajectory

distance d₃ = 39 m

West direction, negative part of x-axis

             x₃ = - 39 m

the total distance is

            = x₁ + x₂ + x₃

            X_{total}l = 14.30 - 33.92 -39

            X_{total}X_total = -58.6 m

           

            Y_{total} = y₁ + y₂

             Y_{total}= 22.90 + 21.20

             Y_{total} = 44.1 m

we give the result in the form of module and angle

we use the Pythagorean theorem

              R = [tex]\sqrt{X_{total}^2 + Y_{total}^2 }[/tex]

              R =\sqrt58.6^2 + 44.1^2 }

              R = 73.34 m

we use trigonometry

               tan θ =

               θ = tan⁻¹ \frac{  Y_{total} }{ X_{total} }

θ = tan⁻¹ \frac{ 44.1 }{ 58.6 } (44.1 / 58.6)

            θ = -37º

this angle is in the second quadrant, given in the form of cardinal coordinates is

              θ = 37º North of West

Laura puts her file cabinet on a small cart with wheels which will occur. A Laura will increase the amount of friction. B Laura will reduce the force she needs C Laura will decrease the amount of motion D Laura will increases the force she needs

Answers

Answer: b

Explanation:

Laura will increase the force she needs. When Laura puts her file cabinet on a small cart with wheels, the cart will experience less friction compared to the file cabinet directly resting on the ground. The correct answer is option D.

The presence of wheels reduces the contact area between the cart and the ground, leading to lower frictional forces. As a result, it becomes easier for the cart to move. However, the file cabinet still possesses its original mass, so to accelerate the cart (and the cabinet) to a certain speed or maintain a constant velocity, Laura will need to exert a greater force on the cart due to the reduction in friction. Therefore, the correct answer is D - Laura will increase the force she needs.

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