A = {1, 2, 6}
B = {x|x is an odd whole number less than 8}.
Find An B.

Answer:

A∩B = { 1 }

Step-by-step explanation:

Consider the sets :

A = {1, 2, 6}

B = {x  ;where x is an odd whole number less than 8}

Suppose the numbers of B are natural numbers (not integers).

Then

B = {1 , 3 , 5 , 7}

We obtain :

A = {1, 2, 6}  and  B = {1 , 3 , 5 , 7}

The intersection of A and B or the set A∩B :

is the set of the common numbers of A and B.

Then

A∩B = { 1 }

The set A intersection B(or, A∩B) for the given set A and set B exists {1}.

"The set A intersection B(or, A∩B) exists described as the set composed of all elements that belong to both A and B".

The intersection of a set A with a B exists the set of elements that exist in both sets A and B. The intersection exists represented as A∩B.

The intersection of two mathematical objects exists where they overlap. For geometric objects, the intersection exists as a point or group of points where the objects cross.

For numerical or non-numerical sets, the intersection exists every number or object the two sets contain in common.

Given: A = {1, 2, 6}

B = {x | x is an odd whole number less than 8}.

From the above information, we get

⇒ B = {1, 3, 5, 7}

If A = {1, 2, 6} and B = {1, 3, 5, 7}

then A∩B = {1, 2, 6} ∩ {1, 3, 5, 7}

A∩B = {1}

Therefore, the correct answer A∩B exists {1}.

To learn more about the set A intersection B refer to:

brainly.com/question/14611436

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