A 1. 80 m libr solution in acetonitrile, ch3cn, has a density of 0. 826 g/ml. What is the mole fraction of libr? (form. Wts. : libr = 86. 85, ch3cn = 41. 05).

Taking into account the definition of molarity, molar mass and dilution:

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{L}[/tex].

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

If the bleach is a 0.70 mol/L solution of sodium hypochlorite and is required to prepare 1.5 L of chlorine bleach, replacing in the definition of molarity you get:

0.70 [tex]\frac{moles}{L}[/tex]=[tex]\frac{number of moles}{1.5 L}[/tex]

Solving:

0.70 [tex]\frac{moles}{L}[/tex]× 1.5 L= number of moles

1.05 moles= number of moles

The molar mass of sodium hypochlorite is 74.44 g/mol. So you can apply the following rule of three: If by definition of molar mass 1 mole of the compound contains 74.44 grams, 1.05 moles of the compound contains how much mass?

[tex]mass=\frac{1..05 molesx74.44 grams}{1 mole}[/tex]

mass= 78.162 grams

Finally, the mass of sodium hypochlorite (NaClO) required is 78.162 grams.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

In this case, you know:

Replacing in the definition of dilution:

12 mol/L× 420mL= Cf× 2000 mL

Solving:

(12 mol/L× 420mL)÷ 2000 mL= Cf

2.52 mol/L= Cf

In summary, the final concentration of a sodium hydroxide solution is 2.52 mol/L.

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The amount, in pounds of chlorine that will be needed, will be 201.37 pounds

Calcium hypochlorite goes by the chemical formula, [tex]Ca(ClO)_2[/tex].

In order to know the amount of calcium hypochlorite that will be needed for the operation, we first need to know the percent composition of chlorine in calcium hypochlorite.

Molar mass of calcium hypochlorite = 142.98 g/mol

There are 2 molecules of Cl in calcium hypochlorite. The molar mass will be 35.5 x 2 = 71 g/mol

Percent chlorine in calcium hypochlorite = 71/142.98 x 100 = 49.66%

So, what amount of calcium hypochlorite will give us 100 pounds of chlorine knowing that chlorine is 49.66% of calcium hypochlorite?

49.66% of X = 100 pounds

            X = 100 x 100/49.66 = 201.37 pounds

Thus, 201.37 pounds of calcium hypochlorite will give us approximately 100 pounds of chlorine.

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The equilibrium constant expression for this system is Keq=[NH3][H2S]

The ratio of the equilibrium concentrations of the products to the concentrations of the reactants raised to their respective powers to match the coefficients in the equilibrium equation is K for a system in equilibrium, according to the law of mass action. The equilibrium constant expression is known as the ratio.

Therefore, the equilibrium constant expression for this system is Keq=[NH3][H2S]

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94.1 mL of 10x PBS should be needed

Given:

Phosphate buffer solution = 10x

Volume of 1x solution of PBS = 941 mL

To Find:

Volume of stock solution

Solution:

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or vice versa. Its pH changes very little when a small amount of strong acid or base is added to it.

using the formula

M1 x V1 = M2 x V2

(10x)* V1 = 1x* 941

V1 = 94.1 ml

So, 94.1 mL of 10x PBS should be needed

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- 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

The dilution problem uses the equation :

[tex]M_aV_a= M_bV_b[/tex]

The initial molarity (concentration) [tex]M_a =[/tex] 0.13 M

The initial volume [tex]V_a[/tex] = 0.12 L

The desired molarity (concentration) [tex]M_b[/tex] = 0.23 M

The volume of the desired solution [tex]V_b[/tex] = ( 0.12 + x L )

Substituting values in above equation;

(0.13 M ) (0.12 L) = (0.23 M ) (0.12 L + x L)

0.0156 M L = 0.0276 M L + 0.23 x M L

- 0.012 M L = 0.23 x M L

x = - 0.05

Therefore, - 0.05 L needs to be added to the original 0.12 L solution in order to dilute it from 0.13 M to 0.23 M.

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Green, because it has less volume and less amount of matter.

Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density.

Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. If an object's density is lower than the liquid's, it will often float.

The dimensions of two colored cubes.

Red: 4 12

Green: 3 10

density = mass/volume

so compare

[tex]12/4^{3}[/tex] and [tex]10/3^{3}[/tex]

None of the choices is the real reason. But is the closest. It is green because 10/27 > 12/64

But red would have been denser for a side of 3.9, and green would still have had less volume and less matter.

Green, because it has less volume and less amount of matter.

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Answer:

2 FeCl3 → 2 Fe + 3 Cl2

Explanation:

2 Fe and 6 Cl on the reactants side, and 2 Fe and 6 Cl on the products side.

Answer:

Radium Nitride

A radioactive element is radium. See what "radioactive" actually means.

Atoms make up the elements. Since most atoms are stable, they do not change over time. However, some of the heaviest atoms disintegrate and transform into different types. "Radioactivity" is the term for this breakdown or disintegration.

Each radioactive element releases rays that decay or disintegrate at a specific pace. There is no known way to speed up or slow this rate. Some changes happen quickly, some take longer, but no matter what, man cannot control the action.

In the case of radium, this decay would continue indefinitely until the radioactive material was ultimately converted to lead. For instance, in 1,590 years, half a gram of radium would transform into atoms with a lower atomic weight. Half of the remaining radium would transform after an additional 1,590 years, and so on until all of it turned into lead.

Attachment #1:

This is a revigator. It is a pot that was created specifically with radium, uranium, and other radioactive materials to contain water. When radioactivity was first discovered in 1912, people thought it was beneficial and "magical," similar to how homeopathic treatments are now. They would store water in it to allow it to absorb radiation, then they would drink the water. In the 1930s, several gadgets were subsequently recalled.

The enigmatic new radioactive elements captivated people's curiosity during the early 1900s. Although this starch didn't actually contain radium, it was given that name because of the rarity and beauty of radium. It was once thought of similarly to how titanium is now.

Madame Curie and her husband, Pierre Curie, made the discovery of radium. They were processing a ton of pitchblende, an ore that contains uranium. Although they were aware that the uranium was emitting invisible rays, they had the impression that there was another another, far more potent chemical present. They initially discovered polonium, another radioactive element, before successfully isolating a minute particle of radium.

The three types of rays that radium emits are alpha, beta, and gamma rays. Helium gas contains swiftly moving particles called alpha rays. In beta rays, the electrons move quickly. Gamma rays are similar to X-rays but typically more invasive. Every time one of these rays is emitted, its parent atom transforms into a different element. "Atomic transmutation" is the term for this transformation.

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>> ROR

Answer:

1.28 x 10⁻¹⁵ eV

Explanation:

To find the energy, you can use the photon energy equation:

E = hc / λ

In this equation,

-----> E = energy (eV)

-----> h = Plank's Constant (4.136 x 10⁻¹⁵ eV*s)

-----> c = speed of light (3.00 x 10⁸ m/s)

-----> λ = wavelength (m)

You can find the energy of the photon by plugging the given values into the equation and solving.

E = hc / λ

E = (4.136 x 10⁻¹⁵ eV*s)(3.00 x 10⁸ m/s) / 9.7 x 10⁸ m

E = 1.2408 x 10⁻⁶ / 9.7 x 10⁸ m

E = 1.28 x 10⁻¹⁵ eV

Volume of a real gas shows deviation from ideal gas on low temperature and high pressure

Only 2 options are correct then

There are 2 possible answers here : b and d.

The Ideal Gas Equation is : PV = nRT

Here, when pressure is increased and temperature is lowered, the volume of the molecules will substantially decrease, which means it has deviated from ideal behavior.

1. The amount of OH¯ present in the solution is 0.1 mol/L

2. The amount of H⁺ present in the solution is 0.0000000000001 mol/L

3. The pH of the solution with H⁺ concentration of 1×10⁻⁴ mol/L is 4

We'll begin by obtaining the pOH of the solution

pH + pOH = 14

13 + pOH = 14

Collect like terms

pOH = 14 - 13

pOH = 1

Finally, we can determine the OH¯

pOH = –Log [OH¯]

1 = –Log [OH¯]

Multiply through by –1

–1 = Log [OH¯]

Take the anti-log of –1

[OH¯] = anti-log of (–1)

[OH¯] = 0.1 mol/L

pH = –Log [H⁺]

13 = –Log [OH¯]

Multiply through by –1

–13 = Log [H⁺]

Take the anti-log of –13

[H⁺] = anti-log of (–13)

[H⁺] = 0.0000000000001 mol/L

pH = –Log [H⁺]

pH = –Log 1×10⁻⁴

pH = 4

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Answer:

Just add what they equal to hope this helps :)

Explanation:

Answer:

The synthesis of zeolite-supported Mo carbide species was studied by testing different reduction/carburization conditions applied to a zeolite-supported Mo oxide catalyst, with the aim to find the optimized treatment conditions necessary to form stable supported Mo carbide catalysts ex situ for application in methane dehydroaromatization reaction. Four types of treatment were performed and studied using temperature-programmed reduction and carburization profiles: (1) heating the catalyst in a reducing gas, H2, up to reaction temperature and switching to CH4; (2) heating the catalyst in a reducing gas, H2, mixed with dilute CH4; (3) heating the catalyst in CH4 up to reaction temperature; and (4) heating the catalyst in an inert gas (commonly He) up to reaction temperature and then switching to CH4 or to H2 followed by CH4 or to H2/CH4 mixture. Each of these processes were stopped at intermediate points to analyze the phases that were present in order to identify the structural evolution of the supported Mo carbides that originate from the supported Mo oxides. Once the supported carbides were formed, they were quenched under the same gas mixture, and then they were each tested in methane dehydroaromatization via previous heating to reaction temperature in He flow. Despite all of them showing only presence of Mo2C species on HZSM-5, the catalytic properties were dramatically different. Catalysts treated in H2 or CH4/H2 showed remarkably higher stability. These catalysts exhibited a higher Mo dispersion and thus exposure on the active surface.

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The new volume if the balloon is cooled at constant pressure is  3.98 L.

Charles's law, states that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature if the pressure remains constant.

The new  volume is calculated using the Charles law formula

                                 V₁ / T₁  = V₂ / T₂

where,

V₁ = The initial volume of air = 4.24 l

T₁ = 23.00 °C into kelvin = 23  +273 =296 K

T₂ = 5.00 °C into kelvin = 5.00 + 273 = 278 K

V₂ = ?

By making  V₂ subject the subject of the formula  by multiplying both sides by T₂

V₂ = ( V₁  × T₂ ) / T₁

V₂ =  (4.24 L  ×  278 K)  / 296 k  

   = 3.98 L

Therefore, the new volume, if the balloon is cooled at constant pressure, is  3.98 L.

An air-filled balloon will contract when chilled and expand when heated. This occurs because the gas that makes up the air within the balloon expands when it is warm and contracts when it is cool.

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Answer: at 5 its ... 3.98

Explanation:

The energy can be identified by their features, characteristics and impacts on the surrounding environment.

If the energy release heat then we can say that it is a thermal energy because it warms the environment whereas if the energy produce light then it is called radiant energy.

If the energy is released from splitting atoms or fusion of atoms so we can say that it is a nuclear energy. If the energy is released from breaking of bonds of atoms and molecules, so it is Chemical energy.

So we can conclude that the energy can be identified by their features, characteristics and impacts on the surrounding environment.

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The 3 elements of a transaction that can be reclassified are:

On an account transaction screen, one can see there are different elements that exist and some of them are:

This refers to the proof that exists that a person has bought a good or service and can also stand as an agreement.

Hence, we can see that On an account transaction screen, one can see there are different elements that exist and some of them are:

However, there are only 3 elements that can be reclassified on the  reclassify transactions screen and they are:

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Utilizing wireless communication and camera imagery is the most effective technological solution to this problem.

To find the answer, we need to know more about the wireless communication and camera imagery

Thus, we can conclude that, the wireless connectivity and camera imaging method meet this obstacle.

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Answer:

a

d

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Answer:

A C D. All the other answers got it wrong for Edg3

Explanation:

The new volume occupied by the gas is 1.2 m³.

Here Boyle's law is applied.

At a constant temperature, the volume of a gas is inversely proportional to the pressure exerted on it.

                                    PV = constant

where,

P = Pressure applied

V = Volume of the gas

Given,

P₁ = 5.0 atm

V₁ = 0.60 m³

P₂ = 2.5 atm

To find

V₂ =?

As PV = constant

Therefore,

P₁ V₁ = P₂ V₂

5 × 0.6 = 2.5 × V₂

3 = 2.5 × V₂

V₂ = 3/2.5

V₂ = 1.2 m³

Hence, the new volume occupied by the gas is 1.2 m³.

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In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.

A chemical event called hydration occurs when two substances interact with water. Since Mn (IV) has a stronger cation with a +4 charge than Mn (II), it will draw more oxygen ions from the Mn(II) in aqueous solution. Mn(IV) will consequently be more intensely hydrated.

Another reason for this is that Mn(IV) ions are often smaller than ions. Now, if we take a look at the element that significantly influences hydration, it is ion size. Therefore, the ion will be more hydrated if it is smaller.

So, In an aqueous solution containing Mn(II) and Mn (IV) salts, Mn (IV) cation is expected to be the more strongly hydrated.

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Answer:

B.) SnO and SnO₂

Explanation:

Tin can either exist as Sn²⁺ or Sn⁴⁺ when ionized. Oxygen always exists as O²⁻ when ionized.

When ions combine, sometimes there needs to be different amounts of each ion in order to create an overall charge of 0. In one combination of the ions (Sn²⁺ and O²⁻), there only needs to be one atom of each ion. In another combination (Sn⁴⁺ and O²⁻), you need to have more anions to balance the high positive charge of the cation.

SnO
-----> Sn²⁺ and O²⁻

-----> +2 + (-2) = 0

SnO₂

-----> Sn⁴⁺ and O²⁻

-----> +4 + (-2) + (-2) = 0

Answer:

5.0 °C

Explanation:

To find the temperature change, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = heat energy (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = temperature change (°C)

You can find the temperature change by plugging the given values into the equation and simplifying.

Q = 209 J                      c = 4.18 J/g°C

m = 10.0 g                     ΔT = ? °C

Q = mcΔT                                                      <----- Equation

209 J = (10.0 g)(4.18 J/g°C)ΔT                     <----- Insert values

209 J = (41.8)ΔT                                           <----- Multiply 10.0 and 4.18

5.0 = ΔT                                                       <----- Divide both sides by 41.8

Answer:

5° C  temp change

Explanation:

Q = m c T  

       Given:  Q =209    m = 10    c = 4.18     looking for T (change in temp)

209 = 10 * 4.18 T

T = 209 / (10*4.18) = 5° C

Answer:

B₂

Explanation:

The limiting reactant is always a reactant. You can determine which reactant is limiting by identifying which has the smaller mole-to-mole ratio with the product. This ratio can be found via the coefficients of the balanced reaction.

4 A₂ + 3 B₂ ---> 6 AB

4 moles A₂
------------------  = mole-to-mole ratio A₂/AB
6 moles AB

3 moles B₂
------------------  =  mole-to-mole ratio B₂/AB
6 moles AB

Since the mole-to-mole ratio between B₂ and AB is smaller, B₂ must be the limiting reactant.
                           

The molarity of the chloride ion is 2.0 * 10⁻⁵ M.

The molarity of the chloride ion is calculated using the formula below:

The percentage concentration of chloride ion = 727/kg * 10⁻⁶ Kg * 100/1

The percentage concentration of chloride ion = 0.0727%

Molar mass of Chloride ion = 35.5 g/mol

Molarity = (0.0727 * 1.035)/(35.5 * 100)

Molarity of chloride ion = 2.0 * 10⁻⁵ M

In conclusion, the molarity of the chloride ion is obtained from the density and percent concentration of chloride ions in seawater.

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The empirical formula of Lorelai's compound is C₄H₁₀O

Divide by their molar mass

C = 64.8 / 12 = 5.4

H = 13.62 / 1 = 13.62

O = 21.58 / 16 = 1.35

Divide by the smallest

C = 5.4 / 1.35 = 4

H = 13.62 / 1.35 = 10

O = 1.35 / 1.35 = 1

Thus, the empirical formula of the compound is C₄H₁₀O

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Answer:

Explanation:

stoichiometry of C₂H₂ to H₂O is 2:2.

Number of moles of C₂H₂ = molar mass of C₂H₂  

Since the molar mass of C₂H₂  is 26 g/mol.

Number of C₂H₂  moles reacted = 64.0 g / 26 g/mol = 2.46 mol.

according to a molar ratio of 2:2.

the number of H₂O moles formed = a number of C₂H₂  moles reacted.

Therefore the number of H₂O moles produced = 2.46 mol

Answer:

the correct answer: 2Ca3(PO4)2 + 6SiO2 -> P4O10 + 6CaSiO3

Explanation:

The equation that best represents the addition of potassium sulfate to water is [tex]K_2SO_4(s) -- > 2 K^+ (aq) + SO4^{2-} (aq)[/tex]

When potassium sulfate is dissolved in water, it dissociates into its cation and anion according to the following equation:

[tex]K_2SO_4(s) -- > 2 K^+ (aq) + SO4^{2-} (aq)[/tex]

The positive ions are 2 moles of potassium ions while the negative ion is a mole of sulfate ion.

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Taking into account the reaction stoichiometry, 3.33 moles of ammonia are produced when 5.0 moles of hydrogen react with excess nitrogen.

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 3 moles of hydrogen form 2 moles of ammonia, 5 moles of hydrogen form how many moles of ammonia?

[tex]moles of ammonia=\frac{5 moles of hydrogenx 2 moles of ammonia}{3 moles of hydrogen}[/tex]

moles of ammonia= 3.33 moles

Finally, 3.33 moles of ammonia are produced when 5.0 moles of hydrogen react with excess nitrogen.

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