Answer:
Explanation:
Momentum conservation:
10,000 x 2 = (10,000 + 30,000) x v
so
v = 0.5 m/s
The speed after collision will be = 0.5m/s
What is conservation of momentum ?The conservation of momentum states that the amount of momentum remains constant , momentum is neither be created nor be destroyed but only changes through the actin of forces as described by newton's law of motion
since , momentum should be conserved before and after the collision
so , from momentum conservation we can write ,
m1 = mass of moving freight car = 10000kg
v1 = speed of moving freight car = 2m/s
m2 = mass of stationary freight car = 30000 kg
v2 = speed of stationary freight car = 0 (since , at rest )
M = mass of coupled cars after collision
V = velocity coupled cars after collision
momentum before collision = momentum after collision
m1*v1 + m2*v2 = MV
10000 * (2) + 30,000 * 0 = (10000 + 30000) V
20000 = 40000V
V = 0.5 m/s
The speed after collision will be = 0.5m/s
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How is the speed of an object related to the amount of
kinetic energy the object has?
Answer:
directly proportional to the square of its speed.
Explanation:
;)
Based on the levels of processing memory model, place in order how deeply the following information about dogs will be encoded, from the shallowest to the deepest.
From the question, the order of information processing from the shallowest to the deepest is;
A person glances at a magazine and sees a picture of a dog.A person can remember all the breeds of dogs because she knows a song that lists them.A person dog-sits and spends the weekend walking and playing with a dog A person who grew up with a dog enjoyed walking in the woods with her pet.What is information processing?
The term information processing means the way in which we deal with information. It is the process by which information is encoded into our memory.
The following is the order of information processing from the shallowest to the deepest;
A person glances at a magazine and sees a picture of a dog.A person can remember all the breeds of dogs because she knows a song that lists them.A person dog-sits and spends the weekend walking and playing with a dog A person who grew up with a dog enjoyed walking in the woods with her pet.Learn more about memory processing: https://brainly.com/question/24863946
What is a way to boost your self-esteem.
Worry about others opinions
Exhibit risky behaviors
Maintain a negative attiude
From close relationships
20 points
Answer:
I say...D!~
Explanation:
I think you mean form*
Hope it helps~ (Sorry if you get it wrong-)
~The Confuzzeled homan
Which statement describes the influence of latitude on temperature?
Latitudes are angles that range from zero degrees at the equator to 90 degrees North or South at the poles.
Temperature is inversely related to latitude. As latitude increases, the temperature falls, and vice versa.
Generally, around the world, it gets warmer towards the equator and cooler towards the poles.
A small object with mass m, charge q, and initial speed v0 = 5.00 * 103 m>s is projected into a uniform electric field between two parallel metal plates of length 26.0 cm (Fig. P21.78). The electric field between the plates is directed downward and has magnitude E = 800 N>C. Assume that the field is zero outside the region between the plates. The separation between the plates is large enough for the object to pass between the plates without hitting the lower plate. After passing through the field region, the object is deflected downward a vertical distance d = 1.25 cm from its original direction of motion and reaches a collecting plate that is 56.0 cm from the edge of the parallel plates. Ignore gravity and air resistance. Calculate the object’s charge-to-mass ratio, q>m
Answer:
q/m = 2177.4 C/kg
Explanation:
We are given;
Initial speed v_o = 5 × 10³ m/s = 5000 m/s
Now, time of travel in electric field is given by;
t_1 = D_1/v_o
Also, deflection down is given by;
d_1 = ½at²
Now,we know that in electric field;
F = ma = qE
Thus, a = qE/m
So;
d_1 = ½ × (qE/m) × (D_1/v_o)²
Velocity gained is;
V_y = (a × t_1) = (qE/m) × (D_1/v_o)
Now, time of flight out of field is given by;
t_2 = D_2/v_o
The deflection due to this is;
d_2 = V_y × t_2
Thus, d_2 = (qE/m) × (D_1/v_o) × (D_2/v_o)
d_2 = (qE/m) × (D_1•D_2/(v_o)²)
Total deflection down is;
d = d_1 + d_2
d = [½ × (qE/m) × (D_1/v_o)²] + [(qE/m) × (D_1•D_2/(v_o)²)]
d = (qE/m•v_o²)[½(D_1)² + D_1•D_2]
Making q/m the subject, we have;
q/m = (d•v_o²)/[E((D_1²/2) + (D_1•D_2))]
We have;
E = 800 N/C
d = 1.25 cm = 0.0125 m
D_1 = 26.0 cm = 0.26 m
D_2 = 56 cm = 0.56 m
Thus;
q/m = (0.0125 × 5000²)/[800((0.26²/2) + (0.26 × 0.56))]
q/m = 312500/143.52
q/m = 2177.4 C/kg
The ratio of the charge to mass of the object will be equal to:
[tex]\dfrac{q}{m}=2177.4\ \frac{C}{kg}[/tex]
what is electric field?
The electric field is defined as the whenever an atom carries a charge whether positive or negative the their influence of force is spread around the charge at a particular distance this effect of force is called as the electric field.
We are given;
Initial speed [tex]V_o[/tex] = 5 × 10³ m/s = 5000 m/s
Now, time of travel in electric field is given by;
[tex]t_1=\dfrac{D_1}{v_o}[/tex]
Also, deflection down is given by;
[tex]d_1=\dfrac{1}{2}at^2[/tex]
Now,we know that in electric field;
F = ma = qE
Thus, [tex]a=\dfrac{qE}{m}[/tex]
So;
[tex]d_1=\dfrac{1}{2}\times(\dfrac{qE}{m})(\dfrac{D_1}{v_o})^2[/tex]
Velocity gained is;
[tex]V_y=(a\timest_1)=(\dfrac{qE}{m})\times (\dfrac{D_1}{v_o})[/tex]
Now, time of flight out of field is given by;
[tex]t_2=\dfrac{D_2}{v_o}[/tex]
The deflection due to this is;
[tex]d_2=V_y\times t_2[/tex]
Thus, [tex]d_2=(\dfrac{qE}{m}\times (\dfrac{D_1}{v_o})\times(\dfrac{D_2}{v_o})[/tex]
[tex]d_2=(\dfrac{qE}{m})\times (\dfrac{D_1\times D_2}{(v_o)^2}[/tex]
Total deflection down is;
[tex]d=d_1+d_2[/tex]
[tex]d=[\dfrac{1}{2}\times(\dfrac {qE}{m}) \times (\dfrac{D_1}{v_o^2})]+[(\dfrac{qE}{m})\times (\dfrac{D_1\times D_2}{v_o^2}})][/tex]
Making q/m the subject, we have;
[tex]\dfrac{q}{m}=\dfrac{(d\times v_o^2)}{[E(\dfrac{D_1^2}{2})+(D_1\times D_2))]}[/tex]
We have;
E = 800 N/C
d = 1.25 cm = 0.0125 m
D_1 = 26.0 cm = 0.26 m
D_2 = 56 cm = 0.56 m
Thus;
[tex]\dfrac{q}{m}=\dfrac{(0.0125\times 5000^2)}{[800((\dfrac{0.26^2}{2})+(0.26\times 0.56))]}[/tex]
[tex]\dfrac{q}{m}= 2177.4[/tex]
Hence the ratio of the charge to mass of the object will be equal to:
[tex]\dfrac{q}{m}=2177.4\ \frac{C}{kg}[/tex]
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If the orbit of a rocket is a circle around the earth with a radius
= 8 x 106m, and the mass of the earth is 5.97 x 1024 kg while
that of the rocket is 0.5 x 106 kg, then what is the speed of the
rocket under uniform circular motion (in m/s, G = 6.67 * 10-11 N
(m/kg) ?)?
Speed of the rocket under uniform circular motion is 4.97 × [tex]10^7[/tex] m/s.
What is centrifugal force?A fictitious force that moves in a circle and is directed away from the center of the circle is called centrifugal force. When measurements are taken in an inertial frame of reference, the force does not exist. It only becomes relevant when we switch from a ground/inertial reference frame to a rotating reference frame.
As the rocket is in uniform circular motion, the gravitational force due to earth and centrifugal force must be equal in magnitude.
The magnitude of gravitational force due to earth, [tex]F_G = \frac{G M m}{R^2}[/tex]
And, the magnitude of centrifugal force, [tex]F_C = \frac{mv^2}{R}[/tex]
Where,
G = universal gravitational constant = 6.67 * 10-11 N (m/kg)².
M = the mass of the earth = 5.97 x [tex]10^{24[/tex] Kg.
m = the mass of the rocket = 0.5 x [tex]10^6[/tex]kg.
R = the orbit of the rocket = [tex]{8*10^6}[/tex]m.
For uniform circular motion,
[tex]\frac{G M m}{R^2}[/tex] = [tex]\frac{mv^2}{R}[/tex]
⇒ v² = [tex]\frac{GM}{R}[/tex]
⇒v² =[tex]\frac{6.67 * 10^{-11 } *5.97 x 10^{24 } }{8*10^6}[/tex]
⇒ v = 4.97 × [tex]10^7[/tex] m/s.
Hence, the speed of the rocket is 4.97 × [tex]10^7[/tex] m/s.
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a 3000 kg car accelerates uniformly from 15 m/s to 60 m/s in 5 seconds. determine the net force on the car during this time
Answer:
F = 2700 N
Explanation:
Given that,
Mass of a car, m = 3000 kg
Initial velocity, u = 15 m/s
Final velocity, v = 60 m/s
Time, t = 5 s
We need to find the net force on the car during this time . The net force on an object is given by the product of mass and acceleration. So,
F = ma
a is acceleration, a = (v-u)/t
[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{3000\times (60-15)}{5}\\\\F=27000\ N[/tex]
So, 27000 N is the net force on the car during this time .
1.which of the following terms is the measure of the distance between two neighboring Crest or trough?
A.wavelength
B.amplitude
C.hertz
D.Frequency
2.What wave can travel space?
A.mechanical
B.transverse
C.longitude
D.elctromagnet
3.what is being transferred by a wave?
A.energy
B.matter
C.particles
D.light
4.what is the speed of a wave with a frequency of sound?
A.645 m/s
B.576 m/s
C.875 m/s
D.975 m/s
Paki Sagot po
Answer:
A
D
A
Is all the information here?
If so than I do not know
The first 3 are correct though
Explanation:
What is the symbol that is used to indicate the fulcrum in a lever?
A triangle is the symbol used to indicate a fulcrum in a lever, a triangle has three sides and three vertices.
What is a fulcrum?A fulcrum is a pivot that has a base and a point that serves as a balance for a lever.
What is a lever?Basically a lever is a simple machine that is a beam with two sides pivoted to fulcrum.
A lever has Load, Effort and the last part is fulcrum
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Explain the disadvantage
of precision
Answer:
The disadvantages are listed below for the defined term.
Explanation:
The initial costs of introducing this method are high, so a long-term solution to agriculture should have been in place. To completely develop a functioning system, it often takes many years to gather data and you'll have to be vigilant about gathering and reviewing data to create a level playing field.What is the reactance of a 60.0- mH inductor when connected to an AC current source that has a frequency of 180 Hz
Answer:
67.9 Ω
Explanation:
L = 60 mH = 60 x 10⁻³ H = 0.060 H
f = 180 Hz, ω = 2πf = 1131 rad/s
reactance = ωL = 1131 x 0.060 = 67.9 Ω
Theweight ofof body is 420N .Calculate its mass
Answer:
42.87
Explanation:
OR
420/9.8 which equals 42.87.
Your friend has been hired to design the interior of a special executive express elevator for a new office building. This elevator has all the latest safety features and will stop with an acceleration of g/3 in the case of an emergency. The management would like a decorative lamp hanging from the unusually high ceiling of the elevator. He designs a lamp which has three sections which hang one directly below the other. Each section is attached to the previous one by a single thin wire, which also carries the electric current. The lamp is also attached to the ceiling by a single wire. Each section of the lamp weighs 7.0 N. Because the idea is to make each section appear that it is floating on air without support, he wants to use the thinnest wire possible. Unfortunately the thinner the wire, the weaker it is. Since he knows that you have taken a course in physics, he asks you to calculate the force on each wire in case of an emergency stop.
Required:
Calculate the force.
Answer:
Sorry, don't understand the question
Explanation:
Which scenario is an example of a scientific way of thinking ?
A example of a scientific way of thinking is making observations, forming questions, making hypotheses, doing an experiment, analyzing the data, and forming a conclusion.
The work done in holding a 60 kg object at a height of 2 m above the floor for 20 s is
Answer:
zero
Explanation:
The work done is zero because the object has no displacement
Assessment started: undefined.
Item 1
Select a word from the drop-down menu to correctly complete the statement.
The elements fluorine, chlorine, and iodine are all part of the same on the periodic table.
a.diagonal
b.group
c.piriod
d.row
Answer:
Option B: Group
Explanation:
The elements fluorine, chlorine, and iodine are commonly known as halogens.
They all have 7 valence electrons in their outermost shell and thus they all belong to group 7A in the periodic table.
Correct Answer is: Group
Answer:
Explanation:
Group hope this helps
is there gravity in water?
Gravity works the same way in water that it works in air or a vacuum -- but you have to consider the force of gravity on the water as well as on the object you put into it
Do you think it’s ethical for tech companies to use your personality type, browsing habit,and online behavior to personalize your experience
Answer:
Yes. Yes. Yes
Explanation:
Answer Is yes
Two students are discussing how the speed of the car compares to the speed of the truck when both vehicles are in front of the house. Student 1 says, "The distance traveled by the car and the truck is the same, and the time is the same, so they must have the same speed." Student 2 says, "I don’t see how that can be. The car catches up to the truck, so the car has to be going faster."
a. Which aspects of Student 1’s reasoning, if any, are correct? Support your answer in terms of relevant features of your graphs in part (a).
b. Which aspects of Student 2’s reasoning, if any, are correct? Support your answer in terms of relevant features of your graphs in part (a).
c. Derive an expression for the acceleration of the car. Express your answer in terms of D and vt
d. Determine the time at which the speed of the car is equal to the speed vt of the truck. Express your answer in terms of tD. Justify your answer.
Answer:
a) Student 1 is right in the way he calculates the speed cid d of the truck, since going at constant speed
b) Student 2 is right that for the car to reach the truck it must have some relationship,
c) t = √d/a
Explanation:
In this exercise you are asked to analyze the movement in a mention using kinematics.
a) Student 1 is right in the way he calculates the speed cid d of the truck, since going at constant speed he can use the equation
v = d / t
b) Student 2 is right that for the car to reach the truck it must have some relationship, which is given by
v = v₀ + a t
x = v₀ t + ½ a t²
c) let's use the equations
v = d / t
v = v₀ + at
d / t = vo + at
If we can assume that the car starts from rest, so v₀ = 0
d / t = a t
t² = d / a
t = √d / a
if the speed of the car is not zero the result is a little more complicated
d = vo t + a t²
at² + vo t - d = 0
let's solve the quadratic equation
t = [-v₀ ± √ (v₀² + 4a d)] / 2a
Hi. If a body with a positive charge touches another with a positive charge, do any of them lose electrons?
The perimeter the sphere is the extreme to which they can go. If ... But what happens if a positively charged object is touched to a neutral object? ... The metal sphere loses electrons.
A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest order maximum that will appear? A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest order maximum that will appear? 5 6 2 8 5.3A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest order maximum that will appear? A diffraction grating has 300 lines per mm. If light of wavelength 630 nm is sent through this grating, what is the highest order maximum that will appear? 5 6 2 8 5.3
Answer:
The order of maximum is [tex]n = 5[/tex]
Explanation:
From the question we are told that
The diffraction grating is k = 300 lines per mm = 300000 lines per m
The wavelength is [tex]\lambda = 630 \ nm = 630 *10^{-9} \ m[/tex]
Generally the condition for constructive interference is mathematically represented as
[tex]dsin \theta = n * \lambda[/tex]
Here n is the order maximum
d is the distance the grating which is mathematically represented as
[tex]d = \frac{1}{k}[/tex]
=> [tex]d = \frac{1}{300000}[/tex]
=> [tex]d = 3.3*10^{-6}\ m [/tex]
So
[tex]n = \frac{dsin \theta}{ \lambda}[/tex]
at maximum [tex]sin\theta = 1[/tex]
[tex]n = \frac{d}{\lambda}[/tex]
=> [tex]n = \frac{3.3*10^{-6}}{630 *10^{-9}}[/tex]
=> [tex]n = 5[/tex]
A car travels 100 m in 4 s on a highway going east. What is the velocity of the car?
Answer:
velocity =25Explanation:
Average velocity =total displacement /time e takenso,average velocity =total displacement
total time taken
100m/4 =25
velocity =25Think of a person standing still at the end of a diving board, getting ready to make a dive into a pool. When the diver is ready, the diver will make 3 small jumps on the diving board, and then dive into the water. Where is the amount of potential energy increasing? Where is the amount of potential energy decreasing and the amount of kinetic energy increasing? Where are the points of maximum kinetic energy? Where are the points of maximum potential energy?
Answer:
The amount of potential energy is increasing when they jump on the board. The amount of potential energy is decreasing and the amount of kinetic energy is increasing when they are falling towards the water. The point of maximum kinetic energy is right before they splash into the water. The point of maximum potential energy is when they jump the highest into the air.
Explanation:
The points of maximum potential energy when they jump highest into the air, their potential energy is at its highest.
What is potential energy?Potential energy develops in systems where the configuration, or relative position of the pieces, determines the amount of the forces they exert on one another. Potential energy directly proportional to height of object higher the object higher the potential energy with respect to same reference point.
When they jump onto the board, potential energy is building. When they are descending toward the sea, their potential energy is dwindling and their kinetic energy is rising. Just before they splash into the water is when they have the most kinetic energy. When they jump highest into the air, their potential energy is at its highest.
Potential energy is highest at its highest point of jump.
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What is the atomic number of this element?
Light travels fast and in a _______________.
straight line
compression wave
wavy line
blue line
{its for my sis shes stu!pd}
Answer:
Straight Line
Light travels in straight lines called rays. Light travels "at the speed of light." This speed is about 186,000 miles per second (670 million miles per hour), or about 300,000 kilometers per second.
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A 5-kilogram bowling ball is traveling down a lane with a velocity of 40ms. What is the kinetic energy and momentum of the bowling ball
The Kinetic energy of the bowling ball is 4000 J while the momentum of the ball is 200 kg m/s
what is kinetic energy?Kinetic energy, KE is the energy exerted by a body in motion. This is represented mathematically as half the product of mass, m and velocity, v squared.
Kinetic energy
KE = 1 / 2 m v^2
m = 5 kg
v = 40 m/s
KE = 0.5 * 5 *40 ^2
KE = 4000 J
Momentum, M
M = mass * velocity
M = 5 * 40
M = 200 kg m/s
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pls tell the answer asap
The small piston of a hydraulic lift has a crosssectional area of 2.87 cm2 and the large piston 314 cm2 . What force must be applied to the small piston for the lift to raise a load of 2.4 kN
Answer:
P1 = P2 pressure is uniform
F1 / A1 = F2 / A2
F1 = F2 (A1 / A2) = 2,400 N * (2.87 / 314) = 21.9 N
A plastic rod of length d = 1.5 m lies along the x-axis with its midpoint at the origin. The rod carries a uniform linear charge density λ = 3.5 nC/m. The point P is located on the postive y-axis at a distance y0 = 15 cm from the origin. The z-axis points out of the screen. 25% Part (a) By symmetry the electric field at point P has no component in the _____________. 25% Part (b) Choose the correct expression for the y-component of the electric field at P due to a thin slice of the rod of thickness dx located at point x. 25% Part (c) Integrate your correct choice in part (b) over the length of the rod and choose the correct expression for the y-component of the electric field at point P. 25% Part (d) Calculate the magnitude of the electric field at point P, in newtons per coulomb.
Answer:
a) The electric field at point P has no component in the x and z directions.
b) dEy = kλdxy₀ / (√( x² + y₀²))^3/2
c)Ey = = 2kλd / y₀( d² + 4y₀²))^1/2
d) Ey = 411.84 N/C
Explanation:
a)
from the uploaded image;
the electric field will only be in y-direction.
Therefore the electric field at P have no component in the x and z directions.
b)
dEy = dEsin θ
dE = kdq / r²
from figure
sinθ = y₀ / √( x² + y₀²)
r = √( x² + y₀²)
dq = λdx
dEy = kdq sinθ / r²
dEy = kλdxy₀ / (√( x² + y₀²))^3/2
c)
the net electric field at p is ,
Ey = ∫^d/2_-d/2 kλdxy₀ / (√( x² + y₀²))^3/2
= kλy₀ ∫^d/2_-d/2 dx / (√( x² + y₀²))^3/2
= 2kλd / y₀( d² + 4y₀²))^1/2
d)
let y₀ = 15 × 10⁻²m, λ = 3.5 nC/m , d = 1.5m
Ey = 2kλd / y₀( d² + 4y₀²))^1/2
Ey = 2(9×10⁹ N.m²/C²)(3.5×10⁻⁹m)(1.5m) / 0.15×(1.5)² + 4(0.15)²))^1/2
Ey = 411.84 N/C
A raging bull of mass 700 kg runs at 36 km/h .How much kinetic energy does it have ?
Answer:
Use equation for kinetic energy: Ek=mV²/2
m=700 kg
V=10m/s
Ek=700kg*100m²7s²/2
Ek=35000 J=35kJ
Explanation:
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