A (17cm X 17cm) square loop lies in the xy plane The magnetic field in this region of space is B=(0.31t i + 0.55t^2 k)T where t is in seconds.
1) What is the E induced loop at 0.5s
2)What is the E induced loop at 1.0s
Express your answer to two significant figures and include the appropriate units.

Answers

Answer 1

The induced EMF in the loop at t = 1.0 s is 0.55 V.

The induced EMF in a loop is given by Faraday's law of electromagnetic induction, which states that the EMF is equal to the rate of change of magnetic flux through the loop.

The magnetic flux through the loop can be calculated using the formula:

Φ = ∫∫ B · dA

where B is the magnetic field, dA is the differential area vector, and the integral is taken over the area of the loop.

Since the loop is a square lying in the xy plane, the differential area vector is given by dA = dx dy k, where k is the unit vector in the z direction.

At t = 0.5 s:

The magnetic field is B = (0.31t i + 0.55t^2 k) T.

Substituting t = 0.5 s:

B = (0.31(0.5) i + 0.55(0.5)^2 k) T

B = (0.155 i + 0.1375 k) T

The magnetic flux through the loop is:

Φ = ∫∫ B · dA = ∫∫ (0.155 i + 0.1375 k) · (dx dy k)

The loop has dimensions of 17 cm x 17 cm, so we can integrate over the limits of x from 0 to 0.17 m and y from 0 to 0.17 m:

Φ = ∫∫ (0.155 i + 0.1375 k) · (dx dy k)

Φ = ∫0.17 ∫0.17 (0.155 dx + 0.1375 dy) = 0.0445 Wb

The EMF induced in the loop is given by:

E = -dΦ/dt

Taking the derivative with respect to time:

dΦ/dt = 0

E = 0 V

Therefore, the induced EMF in the loop at t = 0.5 s is 0 V.

At t = 1.0 s:

The magnetic field is B = (0.31t i + 0.55t^2 k) T.

Substituting t = 1.0 s:

B = (0.31(1.0) i + 0.55(1.0)^2 k) T

B = (0.31 i + 0.55 k) T

The magnetic flux through the loop is:

Φ = ∫∫ B · dA = ∫∫ (0.31 i + 0.55 k) · (dx dy k)

Again, we can integrate over the limits of x from 0 to 0.17 m and y from 0 to 0.17 m:

Φ = ∫∫ (0.31 i + 0.55 k) · (dx dy k)

Φ = ∫0.17 ∫0.17 (0.31 dx + 0.55 dy) = 0.1525 Wb

The EMF induced in the loop is given by:

E = -dΦ/dt

Taking the derivative with respect to time:

dΦ/dt = -0.55 Wb/s

E = 0.55 V

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