A 2.00 kg copper pot is placed on a glass shelf and then one side of the shelf falls so that it becomes angled at 35.0° to the horizontal. The coefficient of static friction between copper and glass is 0.680 and the coefficient of kinetic friction is 0.530. Will the pot slide, and if so, what is its acceleration?​

Answer:

We conclude that the capacity of the computer of performing more than one task at the same time is called the versatility of the computer.

Explanation:

We know that when a PC or laptop is capable of doing multiple tasks at the same time, this particular characteristic of a computer is termed as the versatility of the computer.

In other words, the versatility of the computer makes sure the computer or PC can do multitasking at the same time.

The versatility of a computer makes sure the machine can perform different types of works completed at the same time.

For example, using a computer, we can listen to music while playing games at the same time.

Therefore, we conclude that the capacity of the computer of performing more than one task at the same time is called the versatility of the computer.

Answer:

I think C 250 it is correct

Answer:

The entry level is the basic part of any text or power point which needs to be pushed to the higher levels for reading the entire content

Answer:

60 watts

Explanation:

Given that

Mass of the animal, m = 5 kg

Velocity of the animal, v = 10 m/s

Distance moved by the animal, d = 10 m

Drag force, F(d) = 12 N

Time taken, t = 2 seconds

To start with, we need to find the power output in itself before proceeding to find the average power output. And as such, we have

Power = Force * Distance/Time

But Distance/Time is velocity, so

Power = Force * Velocity

Power = 12 * 10

Power = 120 W.

We then use this power gotten to find the average power output.

Power(avg) = P/t

Power(avg) = 120 / 2

Power(avg) = 60 Watts.

Therefore, the average power output is found to be 60 Watts

Answer:

One bulb could go out and the strand will stay on.

Explanation:

In series circuit, there is only one path provided for the current to flow. So, all the lights are required to be in working condition, for the others to work. And if anyone light bulb goes out, the circuit will become incomplete and the rest of the strand will also go out. Because there is only one path for current flow which is now broken.

On the other hand, in parallel circuits, each light bulb has a separate connection with the source. Current path to each bulb is independent of the others. Therefore, if one bulb goes out, the rest of the strand will stay on.

So, the correct option is:

One bulb could go out and the strand will stay on.

Answer:

6.8 m/s

Explanation:

To solve this, we would use the Doppler's Effect. Doppler's effect is represented by the formula

f = [(g + vr)/(g + vs)].fo, where

f = observed frequency, 408 Hz

g = speed of sound in air, 340 m/s

vr = velocity of the receiver

vs = velocity of the source, 0 m/s

fo = source frequency, 400 Hz

Now, applying the values to the equation, we have

408 = [(340 + vr)/(340 + 0) * 400

408/400 = (340 + vr)/340

1.02 * 340 = 340 + vr

346.8 = 340 + vr

vr = 346.8 - 340

vr = 6.8 m/s

Therefore the speed at which the boy is riding his bicycle towards the wall is 6.8 m/s

An object that absorbs all radiation falling on it, at all wavelengths, is called a black body. When a black body is at a uniform temperature, its emission has a characteristic frequency distribution that depends on the temperature. Its emission is called black-body radiation

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Answer:

1-As winds rise up the windward side of a mountain range, the air cools and precipitation falls.

2-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls.

3-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks.

4-Rain shadow deserts are formed because tall mountain ranges prevent moisture-rich clouds from reaching areas on the lee, or protected side, of the range.

5-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

6-Mountains and mountain ranges can cast a rain shadow. As winds rise up the windward side of a mountain range, the air cools and precipitation falls. On the other side of the range, the leeward side, the air is dry, and it sinks. So there is very little precipitation on the leeward side of a mountain range.

Explanation:

#6 and 5 are the same

Answer:

Land pollution touches essentially every area of the living world, including: Water that isn't safe to drink. Polluted soil, which leads to a loss of fertile land for agriculture. Climate change, which causes an onslaught of disastrous problems, including flash floods and irregular rainfalls.

Explanation:

HOPE THIS HELPS!!!!!!

Answer:

Look at any ecosystem and there could be multiple forms of contamination—streams full of toxic chemicals from industrial processes, rivers overloaded with nutrients from farms, trash blowing away from landfills, city skies covered in smog. Even landscapes that appear pristine can experience the effects of pollution sources located hundreds or thousands of miles away.

Pollution may muddy landscapes, poison soils and waterways, or kill plants and animals. Humans are also regularly harmed by pollution. Long-term exposure to air pollution, for example, can lead to chronic respiratory disease, lung cancer and other diseases. Toxic chemicals that accumulate in top predators can make some species unsafe to eat. More than one billion people lack access to clean water and 2.4 billion don’t have adequate sanitation, putting them at risk of contracting deadly diseases.

Air pollution brings to mind visions of smokestacks billowing black clouds into the sky, but this pollution comes in many forms. The burning of fossil fuels, in both energy plants and vehicles, releases massive amounts of carbon dioxide into the atmosphere, causing climate change. Industrial processes also emit particulate matter, such as sulfur dioxide, carbon monoxide and other noxious gases. Indoor areas can become polluted by emissions from smoking and cooking. Some of these chemicals, when released into the air, contribute to smog and acid rain. Short term exposure to air pollution can irritate the eyes, nose and throat and cause upper respiratory infections, headaches, nausea and allergic reactions. Long-term exposures can lead to chronic respiratory disease, lung cancer, and heart disease. Long-term exposures also can lead to significant climatic changes that can have far reaching negative impacts on food, water and ecosystems. #SAVE OUR WORLD

Answer:

I =  1.27×105 kg⋅m2

Explanation:

Answer:

The force between the charged spheres is 1,223.75 N

The force is attractive because opposite charges mutually attract.

Explanation:

Coulomb's Law

The electrical force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.

Expressing the above as a formula:

[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]

Where:

[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]

q1, q2 = the objects' charge

d= The distance between the objects

The copper spheres have charges of:

[tex]q_1=+2.2\cdot 10^{-4}\ c[/tex]

[tex]q_2=-8.9\cdot 10^{-4}\ c[/tex]

Note the charges have opposite signs.

They are separated by d=1.2 m

Applying Coulomb's formula:

[tex]\displaystyle F=9\cdot 10^9\frac{2.2\cdot 10^{-4}\cdot 8.9\cdot 10^{-4}}{1.2^2}[/tex]

[tex]\displaystyle F=9\cdot 10^9\frac{1.958\cdot 10^{-7}}{1.44}[/tex]

F = 1,223.75 N

The force between the charged spheres is 1,223.75 N

The force is attractive because opposite charges mutually attract.

Answer:

D

Explanation:

If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: a stationary object stays still a moving object continues to move at the same speed and in the same direction Remember that an object can be moving, even if there are no forces acting on it.

The forces acting on an object are balanced, then it must have a constant velocity. Hence, option D is correct.

A strain is a phenomenon that can change an object's velocity in physics. A force can change or increase an excess object's velocity. It makes logical sense to use pushing or pulling to express force. Being vector quantities, energies have both size and direction. Utilizing the SI system, it is calculated in newtons (N). The letter F stands for force.

When forces acting on an item are balanced (or absent), the following occurs: a static object remains still while a moving object maintains its direction and speed. Do not forget that an item can be moving even in the absence of external forces.

When the forces are in equilibrium then it will move in a particular direction also it will move at a constant speed.

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Answer:

Lubrication reduces friction and allows moving machine parts to slide smoothly past each other. Selecting the appropriate lubrication solution can help reduce premature bearing failures and increase machine uptime, productivity and energy efficiency.

Explanation:

Answer:

[tex]-0.288\ \text{rad/s}[/tex]

Explanation:

x = Distance of observer from the initial location of the rocket = 150 m

y = Vertical displacement of the rocket from the ground = 200 m

r = Distance between observer and rocket

[tex]\dfrac{dy}{dt}[/tex] = Rate of change in height of rocket = 12 m/s

[tex]\dfrac{dx}{dt}[/tex] = Rate of change in x = 0

Distance between observer and rocket at y = 200 m

[tex]r=\sqrt{x^2+y^2}\\\Rightarrow r=\sqrt{150^2+200^2}\\\Rightarrow r=250\ \text{m}[/tex]

[tex]\tan\theta=\dfrac{y}{x}[/tex]

Differentiating with respect to time

[tex]\sec^2\theta\dfrac{d\theta}{dt}=\dfrac{y\dfrac{dx}{dt}-x\dfrac{dy}{dt}}{x^2}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{\dfrac{y\dfrac{dx}{dt}-x\dfrac{dy}{dt}}{x^2}}{\sec^2\theta}\\\Rightarrow \dfrac{d\theta}{dt}=\dfrac{\dfrac{0-150\times 12}{150^2}}{(\dfrac{250}{150})^2}\\\Rightarrow \dfrac{d\theta}{dt}=-0.288\ \text{rad/s}[/tex]

The rate of change of the angle of elevation is [tex]-0.288\ \text{rad/s}[/tex].

Answer:

F = 385.56 N

Explanation:

Given that,

Mass, m = 37.8 kg

He applies a horizontal force and cross the wooden floor.

We need to find the force that must be applied to move a dog with a constant speed of 1 m/s.

The coefficient of kinetic friction between the dog in the floor is 1.02.

The net force acting on it is given by :

F = f- μmg

f is force due to constant speed, f = 0 (since, a = 0)

F = μmg

= 1.02 × 37.8 × 10

= 385.56 N

Hence, the required force is 385.56 N.

Answer:

27.95[kW*min]

Explanation:

We must remember that the power can be determined by the product of the current by the voltage.

[tex]P=V*I[/tex]

where:

P = power [W]

V = voltage [volt]

I = amperage [Amp]

Now replacing:

[tex]P=110*8.47\\P=931.7[W][/tex]

Now the energy consumed can be obtained mediate the multiplication of the power by the amount of time in operation, we must obtain an amount in Kw per hour [kW-min]

[tex]Energy = 931.7[kW]*30[days]*10[\frac{min}{1day} ]=279510[W*min]or 27.95[kW*min][/tex]

Answer:

1. t = 5.89 s

2. h = 170 m

3. Vf = 57.8 m/s

Explanation:

1.

First, we analyze the horizontal motion of the golf ball. Assuming the air friction to be negligible, the horizontal motion will be uniform. So, e can use the following equation:

[tex]s = vt[/tex]

where,

s = horizontal distance covered by the golf ball = 471 m

v = horizontal speed of golf ball = 80 m/s

t = time taken by the golf ball in air = ?

Therefore,

[tex]471\ m = (80\ m/s)t\\\\t = \frac{471\ m}{80\ m/s}\\\\[/tex]

t = 5.89 s

2.

Now, we analyze the vertical motion. Using 2nd equation of motion:

[tex]h = v_{i}t + \frac{1}{2}gt^2[/tex]

where,

h = height of cliff = ?

vi = vertical component of initial speed of ball = 0 m/s(ball was shot horizontally)

g = acceleration due to gravity = 9.81 m/s²

t = time of flight = 5.89 s

Therefore,

[tex]h = (0\ m/s)(5.89\ s) + \frac{1}{2}(9.81\ m/s^2)(5.89\ s)^2[/tex]

h = 170 m

3.

Now, we can use 1st equation of motion:

[tex]v_{f} = v_{i} + gt\\v_{f} = 0 m/s + (9.81\ m/s^2)(5.89\ s)\\[/tex]

Vf = 57.8 m/s

Answer:

v₃ = 22.67 [m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of the quantity of linear momentum. Where momentum is conserved before and after the collision, i.e. remains the same.

The terms on the left of the equation represent the amount of linear momentum before the collision and the members on the right represent the momentum after the collision.

[tex](m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}*v_{3})+(m_{2}*v_{4})[/tex]

where:

m₁ = mass of the truck = 3000 [kg]

m₂ = mass of the car = 1000 [kg]

v₁ = velocity of the truck before the coliision = 25 [m/s]

v₂ = velocity of the car parked = 0 (without movement)

v₃ = velocity of the truck after the collision [m/s]

v₄ = velocity of the car after the collision = 7 [m/s]

Now replacing:

[tex](3000*25)+(1000*0)=(3000*v_{3})+(1000*7)\\75000-7000 = 3000*v_{3}\\v_{3}=22.67 [m/s][/tex]

Answer:

The value is [tex]\theta _2 = 0.08 \ arcsec[/tex]

Explanation:

From the question we are told that

   The first wavelength is  [tex]\lambda_1 = 660 \ nm = 660 *10^{-9 }[/tex]

   The  first angular size is  [tex]\theta_1 = 0.04 \ arcsec[/tex]

    The second wavelength is  [tex]\lambda _2 = 1320 \ nm = 1320 *10^{-9 } \ m[/tex]

Generally according to  Rayleigh Criterion we have that

          [tex]\theta= 1.22 * \frac{\lambda }{D}[/tex]

given every other thing remains constant we have that

         [tex]\theta = k * \lambda[/tex]

Here k  represented constant so

         [tex]k = \frac{\theta }{\lambda}[/tex]

=>      [tex]\frac{\theta_1}{ \lambda_1} = \frac{\theta_2}{ \lambda_2}[/tex]

=>      [tex]\frac{\theta_1}{ \theta_2} = \frac{\lambda_1}{ \lambda_2}[/tex]

So

        [tex]\frac{ 0.04}{ \theta_2} =0.5[/tex]

=>     [tex]\theta _2 = 0.08 \ arcsec[/tex]

Answer:

The answer is "[tex]W= 100.44 \ KJ\ \ \ \W_{win}=7.23 \ KJ[/tex]"

Explanation:

Please find the complete question in the attached file.

From of the ideal gas relation that initial and the last temperatures were determined:  

[tex]T_1 = \frac{P_1 V}{m R}[/tex]

    [tex]= \frac{100 \times 0.8}{1.54 \times 0.1889} \\\\ = 275 \ K[/tex]

[tex]T_2 = \frac{P_2 V}{m R}[/tex]

    [tex]= \frac{135 \times 0.8}{1.54 \times 0.1889} \\\\ = 317 \ K[/tex]

In the initial and final states, the internal energies for given temperatures are described from A-20 by means of intelmpolation and divided by the carlxon molar mass.  

[tex]u_1 = 141.56 \frac{KJ}{kg}\\\\u_2 = 206.78 \frac{KJ}{kg}[/tex]

The real job is just the difference between internal energies:  

[tex]W = m(u_2 - u_1) \\\\[/tex]

    [tex]= 1.54(206.78 -141.56) \ kJ \\\\ =100.44 \ kJ[/tex]

In the initial and final states, the zero entries are as determined as internal energies:

[tex]S_1^{\circ} =4.788 \frac{KJ}{kg K}\\\\S_2^{\circ} =5.0478 \frac{KJ}{kg K}[/tex]

From its energy increase, the minimum work required is determined:

[tex]W_{min} = m(u_2-u_1 - T_0(s_2 -S_1))\\\\=W-mT_0(S_2^{\circ}- S_1^{\circ} -R \In \frac{P_2}{P_1})\\\\= 100.44kJ -1.54 \times 298( 5.0478-4.788-0.1889 \In \frac{135}{100})\\\\=7.23\ KJ\\[/tex]

Answer:

B. Distance

Explanation:

When calculating speed, the value of the given distance is first entered on the calculator because it is in the numerator.

Speed is the rate of change of distance with time;

       Speed  = [tex]\frac{distance}{time}[/tex]  

The value of the distance is inputted first before that of the time is entered.

This way the division sign evaluates for the speed.

Answer:

a) [tex]v(2.5\,s) = 40\,\frac{m}{s}[/tex], b) [tex]v(3.5\,s) = -60\,\frac{m}{s}[/tex], c) [tex]v(4.5\,m) = 0\,\frac{m}{s}[/tex], d) [tex]v(7.5\,s) = 60\,\frac{m}{s}[/tex]

Explanation:

Mathematically speaking, the instantaneous velocity is the slope of the curve, which can be estimated by means of the definition of secant line, equivalent to the definition of average velocity:

[tex]v(t) = \frac{x(t+0.5\,s)-x(x-0.5\,s)}{(t+0.5\,s)-(t-0.5\,s)}[/tex] (1)

Where:

[tex]x(t+0.5\,s)[/tex], [tex]x(t-0.5\,s)[/tex] - Position of the particle at [tex]t +0.5\,s[/tex] and [tex]t-0.5\,s[/tex], measured in meters.

[tex]t[/tex] - Time, measured in seconds.

Now we proceed to calculate each instantaneous velocity:

a) [tex]t = 2.5\,s[/tex]

[tex]v(2.5\,s) = \frac{x(3\,s)-x(2\,s)}{3\,s-2\,s}[/tex]

[tex]v(2.5\,s) = \frac{120\,m-80\,m}{1\,s}[/tex]

[tex]v(2.5\,s) = 40\,\frac{m}{s}[/tex]

b) [tex]t = 3.5\,s[/tex]

[tex]v(3.5\,s) = \frac{x(4\,s)-x(3\,s)}{4\,s-3\,s}[/tex]

[tex]v(3.5\,s) = \frac{60\,m-120\,m}{1\,s}[/tex]

[tex]v(3.5\,s) = -60\,\frac{m}{s}[/tex]

c) [tex]t = 4.5\,s[/tex]

[tex]v(4.5\,s) = \frac{x(5\,s)-x(4\,s)}{5\,s-4\,s}[/tex]

[tex]v(4.5\,s) = \frac{60\,m - 60\,m}{1\,s}[/tex]

[tex]v(4.5\,m) = 0\,\frac{m}{s}[/tex]

d) [tex]t = 7.5\,s[/tex]

[tex]v(7.5\,s) = \frac{x(8\,s)-x(7\,s)}{8\,s-7\,s}[/tex]

[tex]v(7.5\,s) = \frac{0\,m - (-60\,m)}{1\,s}[/tex]

[tex]v(7.5\,s) = 60\,\frac{m}{s}[/tex]

Answer:

The value is      [tex]A = 39315 \ m^2[/tex]

Explanation:

From the question we are told that

    The velocity which the rover is suppose to land with is  [tex]v = 1 \ m/s[/tex]

    The  mass of the rover and the parachute is  [tex]m = 2270 \ kg[/tex]

     The  drag coefficient is  [tex]C__{D}} = 0.5[/tex]

      The atmospheric density of Earth  is  [tex]\rho = 1.2 \ kg/m^3[/tex]

     The acceleration due to gravity in Mars is  [tex]g_m = 3.689 \ m/s^2[/tex]

Generally the Mars  atmosphere density is mathematically represented as

          [tex]\rho_m = 0.71 * \rho[/tex]

=>        [tex]\rho_m = 0.71 * 1.2[/tex]

=>        [tex]\rho_m = 0.852 \ kg/m^3[/tex]

Generally the drag force on the rover and the parachute  is mathematically represented as

          [tex]F__{D}} = m * g_{m}[/tex]

=>       [tex]F__{D}} = 2270 * 3.689[/tex]  

=>       [tex]F__{D}} = 8374 \ N[/tex]  

Gnerally this drag force is mathematically represented as

         [tex]F__{D}} = C__{D}} * A * \frac{\rho_m * v^2 }{2}[/tex]

Here A is the frontal area

So  

         [tex]A = \frac{2 * F__D }{ C__D} * \rho_m * v^2 }[/tex]

=>       [tex]A = \frac{2 * 8374 }{ 0.5 * 0.852 * 1 ^2 }[/tex]

=>       [tex]A = 39315 \ m^2[/tex]

Answer:

Solids

Is this what your looking for, It might tell you the answer?

Answer:

Current will increase

Explanation:

In Ohm's law the equation for current is current = voltage / resistance.

In order to explain how current is effected when resistance decreases while voltage stays the same, lets represents the situations with some possible inputs.

Let's compare 3 different closed circuits all with a voltage of 10V.

In circuit 1, the resistance is 5 ohm.

In circuit 2, the resistance is 2 ohms.

In circuit 3, the resistance is 1 ohms.

The current of:

Circuit 1 = Voltage / Resistance = 10 V / 5 ohms = 2 Amps

Circuit 2 = Voltage / Resistance = 10V / 2 ohms = 5 Amps

Circuit 3 = Voltage / Resistance = 10V / 1ohm = 10 Amps

As you can see in this representation, as the resistance in a circuit increases while the voltage is constant, the total current is increased.

As the resistance decreases, the amount of current increases.

Ohm's law states that the current through a conductor between two points is directly proportional to the voltage across the two points.

Ohm's law is represented by the equation

I = V/R

Ohm's Law tells us that the electrical current in a circuit can be calculated by dividing the voltage by the resistance.

As the current change if the resistance is decreased,

In this case, there is a inverse relationship between the two variables. As the resistance increases, the current decreases, provided all other factors are kept constant.  

In other words, the current is directly proportional to the voltage and inversely proportional to the resistance.

As the current is directly proportional to the voltage and inversely proportional to the resistance.

So,

an increase in the voltage will increase the current as long as the resistance is held constant.

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Answer:

The value is  [tex]k = 51.34 \ N/ m[/tex]

Explanation:

From the question we are told that

   The  mass is  [tex]m = 1.3 \ kg[/tex]

   The needed oscillation time is  [tex]T = 1 \ s[/tex]  

 Generally the spring constant is mathematically represented  as

         [tex]k = \frac{4 \pi^2 * m }{ T^2}[/tex]

=>      [tex]k = \frac{4* 3.142^2 * 1.3 }{ 1^2}[/tex]

=>      [tex]k = 51.34 \ N/ m[/tex]

Answer:

Reference point.

Explanation:

Motion can be defined as a change in location (position) with respect to a reference point.

This ultimately implies that, motion would occur as a result of a change in location (position) of an object with respect to a reference point or frame of reference i.e where it was standing before the effect of an external force.

In this scenario, three runners compete in a 400m race on an oval-shaped running track. At a certain time, one runner is 15m away from the finish line. Thus, the term which best describes the finish line is a reference point.

A reference point can be defined as a fixed point that typically marks the position from which a body starts its motion or change its location.

Answer:

because trains are bigger and heavier than cars.

Explanation:

Answer:

If there is a system of magnets being held in place, there is potential energy. When you let go the potential energy makes to kinetic energy and the magnets move.

Magnets cause objects to have kinetic energy as a result of the magnetic

force present in it.

Magnets is a material which has a strong metallic field which attracts

ferromagnetic substances such as steel, iron etc.

When  the magnets are put near these substances , the magnets attract them and causes them to move towards its direction . The magnets causes the conversion of the potential energy into kinetic energy through the strong metallic field.

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