The power of the bulb with 75 W and the voltage is 120 V and the current flows through the bulb is 625mA.
From the given,
The power of the bulb = 75 W
the voltage for the bulb = 120 V
The power equals the voltage and current. P = VI, where V is the voltage and I is the current. The unit of power is Watt. Hence, the current
I = P/V
= 75/ 120
= 0.625
= 625 ×10⁻³A
Thus, the current is 625 mA.
The quantity that resists the current flow is called resistance and the resistance is inversely proportional to the current flow. By Ohm's law:
V =IR
R = V/I
voltage = 120 V
current = 0.625 A
Resistance = 120/0.625
= 192 Ω
Thus, the resistance is 192 Ω.
Resistance X is needed to reduce the current flow through the bulb is 0.3 A. By using Ohm's law:
R = V/I
= 120/0.3
= 400 Ω
Thus, the resistance of 400Ω is required to reduce the current flow of 0.3 A with a voltage is 120V.
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A population distribution shows _______. a. the distribution of age groups within a population b. the amount of organisms in a unit area c. the total number of organisms in a population d. where and in what arrangement organisms are located Please select the best answer from the choices provided A B C D
The answer would be D where and in what arrangement organisms are located.
Which of the following is correct? Multiple Choice When AP is rising, MC is falling, and when AP is falling, MC is rising. When MP is rising, MC is falling, and when MP is falling, MC is rising. There is no relationship between MP and MC. When MP is rising, MC is rising, and when MP is falling, MC is falling.
The statement which is correct is that when MP is rising MC is falling, and when MP is falling MC is rising and is denoted as option B.
What is MP?This is referred to as marginal product and is referred as the extra output derived as result of additional inputs.
MC on the other hand is known as marginal cost and they have an inverse relationship such that when MP is rising , MC is falling and vice versa thereby making it the most appropriate choice.
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Per professor trice's lecture, what has richard dyer written about stars?
Richard Dyer written about stars that a star must be represented simultaneously as, just like us (the audience/regular people), but also at the same time possess something we do not have and something that makes them special, different, extraordinary.
According to the question
Richard Dyer is a British media theorist, who discussed a star’s special place in the audiences’ lives.
He (similarly to Hall) suggests that a star’s meta-narrative impacts on the consumption by the audience. He argued that the star image is manufactured and artificial and that individual stars have their own unique selling point (brand values) in order to grab and hold our attention – for
example – Justin Bieber’s hair, JLS’ colour codes...
Hence, Richard Dyer written about stars that a star must be represented simultaneously as, just like us (the audience/regular people), but also at the same time possess something we do not have and something that makes them special, different, extraordinary.
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What force would require an 8-kg bowling ball to accelerate at a rate of 5 meters per second squared(m/s^2)?
Answer:
87 kph
Explanation:
what happens as a planet approaches the perihelion of its orbit around the sun?
the planet approaches to it's highest velocity
Since the Sun is not at the center of an elliptical orbit, the planet moves closer towards and further away from the Sun as it orbits.
What happens as a planet approaches the perihelion of its orbit around the sun ?The place where the planet is closest to the Sun is called perihelion. When the planet is furthest away from the Sun, it is at aphelion.
The words "aphelion" and "perihelion" come from the Greek language. In Greek, "helios" mean Sun, "peri" means near, and "apo" means away from.When Earth is at perihelion, it is about 147 million km (91 million miles) from the Sun. When it is at aphelion, it is 152 million km (almost 95 million miles) from the Sun.Learn more about Perihelion here:
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A person performs a bench press. The bar's mass is 40 kg. When this person's arms are extended, the bar is 0.6 m above the starting point. How much work did the person do to push the bar off his chest to full extension of his arms
The work done by the person is 235.2 J.
Work done by the person
The work done by the person is calculated as follows;
W = mgh
where;
m is mass of the barheight through which the bar is raisedW = 40 x 9.8 x 0.6
W = 235.2 J
Thus, the work done by the person is 235.2 J.
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A 500-turn solenoid is 8 cm long. When the current in this solenoid is increased from 0 A to th emagnitude of the induced EMG is 0.012 V. Find inductance
The inductance for a solenoid is 1.7 mH
What is Inductance?
It is the property of an electric conductor or circuit that causes an electromotive force to be generated by a change in the current flowing.
The formula for the inductance:
L = |e| / ( Δi / Δt )
Where,
L = inductance
e = induced emf = 0.012 V
Δi = change in current = 2.5-0 = 2.5 A
Δt = change in time = 0.35 s
Substituting the values in formula of Inductance,
L = 0.012 / ( 2.5/0.35 )
L = 1.7 * 10^-3 H
L = 1.7 mH
Hence
The inductance for a solenoid is 1.7 mH
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Your question is incomplete, but probably full question was:
A 500-turn solenoid is 8.0 cm long. When the current in this solenoid is increased from 0 to 2.5 A in 0.35 s, the magnitude of the induced emf is 0.012. Find the inductance.
1. Determine the energy released per kilogram of fuel used.
Given MeV per reaction, calculate energy in joules per kilogram of reactants.
Consider 1 mole of plutonium-239 to be a mole of “reactions” (molar mass = 239 grams).
2. Determine the mass of fuel required for the expected energy consumption in the United States for the next 10 years.
Energy use per person per year in the United States = 3.5 × 1011 joules.
Base your calculations on a current population of 310,000,000.
The formula for energy release per kilogram of fuel burned is energy release per kg=6.702*10-13. and 19. J 1 Mev = 1.602 X 10 T
Calculate the energy in joules per kilogram of reactants given MeV per reaction. Energy is the ability or capacity to perform tasks, such as the ability to move an item (of a certain mass) by exerting force. Energy can exist in many different forms, including electrical, mechanical, chemical, thermal, or nuclear, and it can change its form.
Think of a mole of plutonium-239 (molar mass: 239 grams) as a mole of "reactions."
Energy used in the US per person annually = 3-5 X 1011
Population (number of people) = 3.108The required mass of the fuel is 3.5x1011 x3-1x10 8x 10)/6.703 X1013 kg. the mass required: 1.62 x 1033 kg Mev in Joules 6 is equal to 101.60*I0-
19. J 1 Mev = 1.602 X 10 T, which translates to 1.602*1013/2.39x10-3 energy release per kilogram, or 6.702*10-13.
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A 6.0 mH inductor is in a circuit. At the instant the current is 5.0 A and its rate of change is 200 A/s, the rate with which the energy stored in the inductor is increasing is:
The rate with which the energy stored in the inductor is increasing at 6 Joule/s.
To find the answer, we need to know about the rate of change of energy in inductor.
What's the rate of change of energy of inductor?The energy stored in inductor (E)=(1/2)× L× I²The rate of change of energy (dE/dt) = L×I×(dI/dt)What's the rate of energy increased in the inductor, if rate of increasing current, L and I are respectively 200A/s, 6mH and 5 A respectively?Here , dI/dt = 200A/s, L=6mH, I = 5 ARate of energy increased= 6mH×5×200= 6 Joule/s
Thus, we can conclude that the rate of increasing energy is 6 Joule/s.
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A bodybuilder deadlifts a 215 kg weight to a height of 0.90 m above the ground. If he deadlifts this weight 10 times in a span of 45 seconds, how much power has he exerted?
Group of answer choices
a. 8,530 W
b. 421 W
c. 853 W
d. 4,210 W
A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)
What is power?In physics, power (P) is the work (W) done over a period of time.
Step 1. Calculate the work done by the bodybuilder each time.The bodybuilder lifts a 215 kg (m) weight to a height of 0.90 m (h). Being the gravity (g) of 9.81 m/s², we can calculate the work done in each lift using the following expression.
W = m × g × h = 215 kg × 9.81 m/s² × 0.90 m = 1.9 × 10³ N
Step 2. Calculate the work done by the bodybuilder over 10 times.W = 10 × 1.9 × 10³ N = 1.9 × 10⁴ N
Step 3. Calculate the power exerted by the bodybuilder.The bodybuilder does a work of 1.9 × 10⁴ N in a 45-s span.
P = 1.9 × 10⁴ N/45 s = 421 W
A bodybuilder deadlifts 215 kg to a height of 0.90 m. If he deadlifts this weight 10 times in 45 s, the power exerted is 421 W (b.)
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A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward. If the velocity at the bottom of the drop is 10.0 m/s and the mass of the cart and passengers is 3.5 x 104 kg, how much potential energy was converted into thermal energy (heat)
The energies which is converted into thermal energy is
2280.9 × 10^4 J
According to the question when the ride will go upward then there will a potential energy acquired and when it comes down then kinetic energy starts to increase. since, the ride is starting from rest then kinetic energy will be maximum at lowest. So, now we will calculate P.E and K.E at various points.
Potential Energy at top when the vertical drop is 126.5 m is given as- P.E = m ×g× h
= 3.5 × 10^4 × 9.8 × 126.5
= 4338.95 × 10^4 J
Kinetic Energy at bottom when ride has velocity of 10 m/s then it is
given as -
K.E = 1/2 mv²
= 1/2 × 3.5×10^4 × 10²
= 175 × 10^4 J
Now the energy which converted to thermal energy is given as:
Thermal energy = Potential energy - kinetic energy
= 2455.9 × 10^4 - 175 × 10^4
= 2280.9 × 10^4 J
Thus, the ride Potential energy was converted to thermal energy is 2280.9 × 10^4 J.
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Cindy runs 2 kilometers every morning. She takes 2 minutes for the first 250 meters, 4 minutes for the next 1,000 meters, 1 minute for the next 350 meters, and 3 minutes for the rest.
Cindy’s average speed for the entire run is
meters per minute. One kilometer is the same as 1,000 meters.
Answer:
200 m / min
Explanation:
Total distance = 2000 m
Total time = 2+4+1+3 = 10 minutes
Average speed = 2000 m / 10 min = 200 m/min
The hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce. Stars over this limit tend to be surrounded by massive nebulae of material blasted off of their surfaces.
The hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity
What are stars?Stars are a fixed luminous point in the sky which is a large and remote incandescent body
So therefore, the hypothetical upper limit to the mass a star can be before it self-destructs due to the massive amount of fusion it would produce is apparently as a result of Eddington luminosity
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What is the angular momentum of the moon around the earth? the moon’s mass is 7.4 * 1022 kg and it orbits 3.8 * 108 m from the earth.
The angular momentum of the moon around the earth is 2.92 * [tex]10^{34}[/tex] kg [tex]m^{2}[/tex]/s
Angular momentum a vector quantity that is a measure of the rotational momentum of a rotating body or system, that is equal in classical physics to the product of the angular velocity of the body or system and its moment of inertia with respect to the rotation axis, and that is directed along the rotation axis.
m (mass of moon ) = 7.4 * [tex]10^{22}[/tex] kg
orbit = 3.8 * [tex]10^{8}[/tex] m
L = I ω
= m [tex]r^{2}[/tex]ω
= 7.4 * [tex]10^{22}[/tex] * [tex](3.8 *10^{8} )^{2}[/tex] * (2π / 27 * 24 * 3600)
= 2.92 * [tex]10^{34}[/tex] kg [tex]m^{2}[/tex]/s
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Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus , has a parallax of 0.042 arcseconds. What is its distance in parsecs
Answer: Sirius, the brightest star in the sky, is 2.6 parsecs (8.6 light-years) from Earth, giving it a parallax of 0.379 arcseconds. Another bright star, Regulus, has a parallax of 0.042 arcseconds. Then, the distance in parsecs will be,23.46.
Explanation: To find the answer, we have to know more about the relation between the distance in parsecs and the parallax.
What is the relation between the distance in parsecs and the parallax?Let's consider a star in the sky, is d parsec distance from the earth, and which has some parallax of P amount.Then, the equation connecting parallax and the distance in parsec can be written as,[tex]d=\frac{1}{P}[/tex]
We can say that,[tex]dP=constant.\\thus,\\d_1P_1=d_2P_2[/tex]
How to solve the problem?We have given that,[tex]d_1=2.6 parsecs.\\P_1=0.379arcseconds.\\P_2=0.042 arcseconds.\\d_2=?[/tex]
Thus, we can find the distance in parsecs as,[tex]d_2=\frac{d_1P_1}{P_2} =23.46 parsecs[/tex]
Thus, we can conclude that, the distance in parsecs will be, 23.46.
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Sketch the path that light would take through the slit. Show the beams that are incident on and reflected from the mirror. Draw arrowheads to indicate the direction that light travels.
This is the path of light through slits.
what are incident light ?
The light that hits a topic is called as incident light. It may originate from an artificial source or from a natural source, like as the sun. Incident light is also light that reflects off a reflector or another surface.
what is light ?
The region of the electromagnetic spectrum that the human eye sees as light, or visible light, is composed of electromagnetic radiation. The Sun is the primary source of natural light on Earth. Fire has historically been a major source of light for people, from ancient campfires to modern kerosene lamps. Electric lighting has largely taken the place of firelight as a result of the development of electric lights and power systems.
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What is the average power supplied by a 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s?
Group of answer choices
a. 670 W
b. 560 W
c. 610 W
d. 380 W
A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).
What is power?Power is the work done over a period of time.
A secretary with a mass (m) of 60.0 kg runs up a 4.0 m (d) tall flight of stairs. Given gravity (g) is 9.81 m/s², the work (W) done is:
W = m × g × d = 60.0 kg × 9.81 m/s² × 4.0 m = 2.35 × 10³ J
They do 2.4 × 10³ J of work in 4.2 s (t). The average power (P) is:
P = W / t = 2.35 × 10³ J / 4.2 s = 560 W
A 60.0 kg secretary running up a 4.0 m tall flight of stairs in 4.2 s has an average power of 560 W (Option b).
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Cindy's eye exam reveals that the reason she cannot get a sharp focus is that she has ___, an uneven curvature of the cornea or lens that prevents a sharp focus of an image on her retina.
Answer: Cindy's eye exam reveals that the reason she cannot get a sharp focus is that she has Astigmatism, an uneven curvature of the cornea or lens that prevents a sharp focus of an image on her retina.
Explanation: To find answer, we need to know more about the Astigmatism.
What is astigmatism?It is the defect of vision in which a person cannot simultaneously see both the vertical and horizontal views of an object with the same clarity.It is due to the irregular curvature of cornea, or the lens prevents a sharp focus of an image on retina.It can be corrected using a cylindrical lens.Thus, from the above explanation, we can conclude that, the reason she cannot get a sharp vision is due to Astigmatism.
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If p(a)=0.07692, p(b)=0.25, and probability of a and b. =0.01923, what is probability of a or b. to four decimal places? select one.
Answer:
p(a) * p(b) = .01923
p(b) = .01923 / .07692 = .2500
The probability of a or b will be equal to 0.30769.
What is probability?Probability is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
The probability of the total sample points in A U B is P(A U B). The probabilities of sample points in A and B are now added together as P(A) + P(B). To get the total of probabilities in (A U B), which is P, we need to subtract once because we added the sample points in (A B) twice (A U B).
Given that p(a)=0.07692, p(b)=0.25, and probability of a and b. =0.01923. The probability will be calculated by using the formula below:-
P(A) = 0.07692
P(B)=0.25
P(A[tex]\cap[/tex]B) = 0.01923
P(AUB) = P(A) + P(B) - P(A[tex]\cap[/tex]B)
P(AUB) = 0.07692 + 0.25 - 0.01923
P(AUB) = 0.30769
Therefore, the probability of a or b will be equal to 0.30769.
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How does enormous energy get released from the sun?
Enormous energy get released from the sun due to fusion reaction.
How does enormous energy get released from the sun?
Sun can generate enormous energy due to nuclear fusion. In this process, high temperature and pressure in the core of the sun force the nuclei to separate from their electrons which results in the formation of one Helium atom releasing a large amount of energy.
So we can conclude that enormous energy get released from the sun due to fusion reaction.
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Asymmetric dimethylarginine, endocan, pentraxin 3, serum amyloid A, soluble urokinase plasminogen activator receptor, total oxidant status and total antioxidant status, galectin-3
relationship between these inflammatory markers and infection.
What is Inflammatory markers ?Recognised inflammatory biomarkers play important roles in the management of patients with for example, diagnosis, follow-up, assessment of treatment response and risk stratification
Asymmetric dimethylarginine, endocan, pentraxin 3, serum amyloid A, soluble urokinase plasminogen activator receptor, total oxidant status and total antioxidant status, galectin-3 were considered among the emerging inflammatory markersWell-known inflammatory markers included complete blood count, C-reactive protein, albumin, cytokines and erythrocyte sedimentation rate.Learn more about Inflammatory markers here:
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Match each term with its definition.
malleability
metallic bond
alloy
ductility
electron sea theory
the bond formed when metal atoms
share many mobile electrons
metals bond to other metals by
sharing many "floating electrons
the ability of metals to be shaped by
hammering or pounding
the ability of metals to be formed into
wires
a mixture of the atoms of a metal with
another element
The correct matches are as follows:
malleability - the ability of metals to be shaped by hammering or poundingmetallic bond - the bond formed when metal atoms share many mobile electronsalloy - a mixture of the atoms of a metal with another elementductility - the ability of metals to be formed into wireselectron sea theory - metals bond to other metals by sharing many "floating electronsWhat are metals?Metals are elements which form positive ions by loss of electrons.
Metals are usually shiny, malleable and ductile.
Metal atoms combine are bonded to each other by metallic bonds.
Electron sea theory describe how mobile electrons surround positive atomic nucleus.
Alloys refer to a mixture of metals.
In conclusion, metal atoms form metallic bonds.
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What is kinetic energy? A. stored energy B. the energy of motion C. the energy of light D. the energy at the top of a roller coaster
Answer:
B. the energy of motion
Explanation:
Energy of motion. Kinetic energy is essentially the release of potential energy which is when an object has the potential to do work, due to it's position or molecular composition.
A 25. 00 ml sample of acetic acid containing phenolphthalein indicator is titrated with 0. 1067 m naoh. The solution changes color after 30. 07 ml naoh has been added. What is the concentration of the acetic acid before titration?.
The concentration of the acetic acid:
The concentration of the acetic acid before titration is 0.128M
Reaction of phenolphthalein with NaOH:
The sodium hydroxide will start interacting with phenolphthalein as soon as enough sodium hydroxide has been added to the acetic acid such that there is no longer any unreacted acetic acid. Pink solution is produced when phenolphthalein and sodium hydroxide combine.
Calculation:
The balanced equation:
CH₃COOH + NaOH ⇒ CH₃COONa + H₂O
Given:
Quantity of NaOH = 0.1067 M
Volume of NaOH = 30.07 ml
= 30.07 / 1000
= 0.03007 L
For weak acid and strong base titration = Moles of acetic acid = moles of NaOH
Moles of NaOH = concentration X volume
0.1067 X 0.03007 = 0.0032
Thus, moles of acetic acid = 0.0032mole,
By employing the formula,
Concentration = Moles/Volume
= 0.0032/0.025
= 0.128M
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How does the fur of the polar bear help it to live in the arctic region?
Answer:
It has 2 uses
1. Polar bears have white fur so that they can camouflage into their environment. Their coat is so well camouflaged in Arctic environments that it can sometimes pass as a snow drift.
2. They have a thick layer of body fat, which keeps them warm while swimming, and a double-layered coat that insulates them from the cold Arctic air.
A car is stopped at a traffic light. When the light turns green at t=0, a truck with a constant speed passes the car with a 20m/s velocity. The car uniformly accelerates to the velocity 35m/s in 20 seconds, the moves at a constant speed for 5 seconds. How long will it take for the car to catch up to the truck.
Answer:
At [tex]t = (70 / 3) \; {\rm s}[/tex] (approximately [tex]23.3 \; {\rm s}[/tex].)
Explanation:
Note that the acceleration of the car between [tex]t = 0\; {\rm s}[/tex] and [tex]t = 20\; {\rm s}[/tex] ([tex]\Delta t = 20\; {\rm s}[/tex]) is constant. Initial velocity of the car was [tex]v_{0} = 0\; {\rm m\cdot s^{-1}}[/tex], whereas [tex]v_{1} = 35\; {\rm m\cdot s^{-1}}[/tex] at [tex]t = 20\; {\rm s}\![/tex]. Hence, at [tex]t = 20\; {\rm s}\!\![/tex], this car would have travelled a distance of:
[tex]\begin{aligned}x &= \frac{(v_{1} - v_{0})\, \Delta t}{2} \\ &= \frac{(35\; {\rm m\cdot s^{-1}} - 0\; {\rm m\cdot s^{-1}}) \times (20\; {\rm s})}{2} \\ &= 350\; {\rm m}\end{aligned}[/tex].
At [tex]t = 20\; {\rm s}[/tex], the truck would have travelled a distance of [tex]x = v\, t = 20\; {\rm m\cdot s^{-1}} \times 20\; {\rm s} = 400\; {\rm m}[/tex].
In other words, at [tex]t = 20\; {\rm s}[/tex], the truck was [tex]400\; {\rm m} - 350\; {\rm m} = 50\; {\rm m}[/tex] ahead of the car. The velocity of the car is greater than that of the truck by [tex]35\; {\rm m\cdot s^{-1}} - 20\; {\rm m\cdot s^{-1}} = 15 \; {\rm m\cdot s^{-1}}[/tex]. It would take another [tex](50\; {\rm m}) / (15\; {\rm m\cdot s^{-1}}) = (10/3)\; {\rm s}[/tex] before the car catches up with the truck.
Hence, the car would catch up with the truck at [tex]t = (20 + (10/3))\; {\rm s} = (70 / 3)\; {\rm s}[/tex].
A mass m is attached to an ideal massless spring. When this system is set in motion, it has a period t. What is the period if the mass is doubled to 2m?.
If a mass m is attached to an ideal massless spring and has a period of t, then the period of the system when the mass is 2m is [tex]\sqrt{2}t[/tex].
Calculation:
Step-1:
It is given that a mass m is attached to an ideal massless spring and the period of the system is t. It is required to find the period when the mass is doubled.
The time it takes an object to complete one oscillation and return to its initial position is measured in terms of a period, or T.
It is known that the period is calculated as,
[tex]T=2 \pi \sqrt{\frac{m}{k}}[/tex]
Here m is the mass of the object, and k is the spring constant.
Step-2:
Thus the period of the system with the first mass is,
[tex]t=2 \pi \sqrt{\frac{m}{k}}[/tex]
The period of the system with the second mass is,
[tex]\begin{aligned}\\t^'&=2 \pi \sqrt{\frac{m}{k}}\\&=\sqrt{2}\times2 \pi \sqrt{\frac{2m}{k}}\\&=\sqrt{2}\times t\end{aligned}[/tex]
Then the period of the system with the second mass is [tex]\sqrt{2}[/tex] times more than the period of the system with the first mass.
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An ordinary flashlight battery has a potential difference of 1.2 V between its positive and negative terminals. How much work must you do to transport an electron from the positive terminal to negative terminal
The work done to transport an electron from the positive to the negative terminal is 1.92×10⁻¹⁹ J.
Given:
Potential difference, V = 1.2 V
Charge on an electron, e = 1.6 × 10⁻¹⁹ C
Calculation:
We know that the work done to transport an electron from the positive to the negative terminal is given as:
W.D = (Charge on electron)×(Potential difference)
= e × V
= (1.6 × 10⁻¹⁹ C)×(1.2 V)
= 1.92 × 10⁻¹⁹ J
Therefore, the work done in bringing the charge from the positive terminal to the negative terminal is 1.92 × 10⁻¹⁹ J.
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An object is at a position of 15 cm from a diverging lens with a virtual focal point of 8 cm. The location of the image is
Answer: The location of the image is -5.2cm
A player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
At the highest point in its trajectory, the ball's acceleration is zero but its velocity is not zero.
What's the velocity of the ball at the highest point of the trajectory?At the highest point, the ball doesn't go more high. So its vertical velocity is zero.However, the ball moves horizontal, so its horizontal component of velocity is non - zero i.e. u×cosθ. u= initial velocity, θ= angle of projectionWhat's the acceleration of the ball at the highest point of projectile?During the whole projectile motion, the earth exerts the gravitational force with a acceleration of gravity along vertical direction. But as there's no acceleration along vertical direction, so the acceleration along vertical direction is zero.Thus, we can conclude that the acceleration is zero and velocity is non-zero at the highest point projectile motion.
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Question: Player kicks a soccer ball in a high arc toward the opponent's goal. At the highest point in its trajectory
A- neither the ball's velocity nor its acceleration are zero.
B- the ball's acceleration points upward.
C- the ball's acceleration is zero but its velocity is not zero.
D- the ball's velocity points downward.
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