A bag of garden soil weighs 38 pounds and holds 4 cubic feet. Find the weight of 15 bags in kilograms and the volume of 15 bags in cubic yards.

I suppose the third term should say -10/3, not -103.

Notice that

-2 = -6/3

-4 = -12/3

so that, starting with the first term a(1) = -6/3, the every following term is obtained by subtracting 2/3.

-2 - 2/3 = -6/3 - 2/3 = -8/3

-8/3 - 2/3 = -10/3

-10/3 - 2/3 = -12/3 = -4

and so on.

So the recursive rule is

a(1) = -2,

a(n + 1) = a(n) - 2/3, for n ≥ 1

or C.

Answer:

$1452

Step-by-step explanation:

[tex]CP=1100*1.32=$1452[/tex]

Answer:

1. 32

2. 4.7

3. 3

Step-by-step explanation:

4*8=32

6.5-1.8= 4.7

18/6=3 or 18 divided by 6 = 3

Answer:

8 litre

Step-by-step explanation:

very simple 120÷15=8

hope it helps you

please mark me as brainlist

Answer:

12 feet

Step-by-step explanation:

The ladder is 12 feet up the wall.

The ladder forms a right triangle with the wall and the ground. You want to use Pythagorean theorem to solve the problem. a2+b2 = c2

Use the Pythagorean Theorem (a2+b2=c2) where b=9 and c=15. Solve for a.

(hope this helps can i plz have brainlist :D hehe)

Answer:

378

Step-by-step explanation:

9 × 7 × 6 = 378

pls mark brainliest, if not, its ok :)

Answer:

14/3, or 4.6^bar

Step-by-step explanation:

first you'd just divide 7 by 9, resulting in [tex]\frac{7}{9}[/tex], or 0.7^bar.

Then you'd multiply either by 6, resulting in the answers above. Fractions are easier than infinite numbers, so if you're able to do that, I'd suggest you do so.

Hope this helped!

Answer:

8y

Step-by-step explanation:

It's really simple! Because both of the variables are the same, You can just add it!

Hope this helps ^^

Answer:

X^3 + 5x^2 + 2x - 8

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

1 / 4 x (21 - 5) =

1/4 x 16 = 4

Hope that helps!

Answer:

0.222

Step-by-step explanation:

out of 36 outcomes you have 8 possible outcomes for a '4' or '6':

1,5

5,1

3,3

2,4

4,2

2,2

1,3

3,1

8/36 = 2/9 = .2 repeating

The probability that the dice faces add up to either 4 or 6 is 0.222.

Probability means possibility. It is a branch of mathematics that deals with the occurrence of a random event.

Here, After two six sided dice are rolled,

Hence, Total outcomes = 36

So, Probability of getting sum 4 that is,  {(1, 3), (2, 2), (3, 1)};

P = 3/36    

And, Probability of getting sum 6 = 5/36

Hence, Total Probability of getting sum either 4 or 6 = 3/ 36 + 5/36

                                                                         = 8/36

                                                                         = 2/9

                                                                         = 0.222

Thus, the probability that the dice faces add up to either 4 or 6 is 0.222.

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Answer:

99717

Step-by-step explanation:

Use PEMDAS

P stands for parenthesis so you do 7 x 7 first. It equals 49. E stands for exponents but there aren't no exponents. M stands for multiplying so you multiply 10 x 6 = 60. Then 60 x 49 = 2940. 8 x 6 = 48. 48 times 6 is 288. 288 x 6 is 1728. 1728 x 7 is 12096. 12096 x 8 is 96768. The A in PEMDAS is addition. 9+2940 equals 2949. 2949 + 96768  = 99717.

Answer:

there's 18 thirds in 6 wholes

Answer:

1.13 food per square feet

Step-by-step explanation:

Given

Dimension: 50ft by 35ft

Servings = 1975

Required

Determine the amount per servings

First, we calculate the area.

[tex]Area = 50ft * 35ft[/tex]

[tex]Area = 1750ft^2[/tex]

Next, we calculate the amount per square foot.

This is:

[tex]Rate = \frac{Serivings}{Area}[/tex]

This gives;

[tex]Rate = \frac{1975}{1750}[/tex]

[tex]Rate = 1.13[/tex]

Answer:

740×2= 1480 in 2 hours

hope this helps :)

1. A = 1/4s squared, square root of 3

2. A = bh

3. A = pi(r) squared

4. A = 1/2 h (b1+ b2)

5. C = pi(d)

6. A = base x altitude

7. A = 1/2(ap)

8. A = 1/2(bh)

- regular polygon

- trapezoid

- rectangle

- parallelogram

- circle circumference

- equilateral triangle

- circle area

Answer:

Answers are below.

Step-by-step explanation:

1.  Equilateral triangle - A = 1/4 s^2 √3

2. Rectangle - A = bh

3. Circle circumference - C = πd

4. Trapezoid - A = 1/2 h (b1 + b2)

5. Parallelogram - A = base x altitude

6. Triangle - A = 1/2 bh

7. Regular polygon - A = 1/2 ap

8. Circle area - A = πr^2

Hope this helps.  

TAN: 45/28

SIN: 45/53

COS: 28/53

sin(x°) = opposite/hypotenuse

cos(x°) = adjacent/hypotenuse

tan(x°) = opposite/adjacent

x is any degree measure.

Hence option C (45/28) is correct

What are trigonometric rations?

Sine (sin), cosine (cos), tangent (tan), cotangent (cot), cosecant (cosec), and secant (sec) are the six trigonometric ratios (sec). Trigonometry is the branch of mathematics concerned with the sides and angles of a right-angled triangle in geometry. As a result, trig ratios are assessed in terms of sides and angles.

How to solve ?

Given θ

∴tan θ=[tex]\frac{Perpendicular}{Base}[/tex]

=45/28

= option c

Hence option C (45/28) is correct

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Answer:

Step-by-step explanation:

b = 21 is the base, a is the height

area = 0.5ab = 210

ab = 420

a = 420/b = 420/21 = 20 ft

length of hypotenuse = √(a²+b²) = √(20²+21²) = √841 = 29 ft

Answer:

x = 120 degress

Step-by-step explanation:

I can help with more, I have the answers.

Step-by-step explanation:

Here's another solution.

360-275-20=65

ratio 3:10

3x+10x=65

13x=65

x=5

5*3=15° and 5*10=50°

15° and 50° are the other two angles

when calculating present value, the _____ interest rate, the smaller the present value amount.

* smaller

* larger,✓

The correct value is,

''When calculating present value, the smaller the interest rate, the smaller the present value amount.''

What is Simple interest?

A quick and easy method of calculating the interest charge on a loan is called a Simple interest.

Given that;

To calculating the present value, The smaller the present value.

Now,

The correct value is,

''When calculating present value, the smaller the interest rate, the smaller the present value amount.''

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Answer:

Step-by-step explanation:

9²+9²=162

√162 ≈12.7

so base is a right angled triangle with sides 12.7,9,9

area of base and top=2×1/2×9×9=81 cm²

area of sides=(9+9+12.7)×8

=30.7×8=245.6 cm ²

total surface are =81+245.6=326.6 cm²

volume=1/2 ×9×9×8=324 cm³

Answer:

Hank had a z-score of -1.375.

Jane had a z-score of -2.39.

Jane had the better year relative to their peers, due to her lower z-score.

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Hank:

ERA of 3.36. For the males, the mean ERA was 4.449 and the standard deviation was 0.792. This means that we have to find Z when [tex]X = 3.36, \mu = 4.449, \sigma = 0.792[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{3.36 - 4.449}{0.792}[/tex]

[tex]Z = -1.375[/tex]

Hank had a z-score of -1.375.

Jane

ERA of 3.49.  For the females, the mean ERA was 5.091 and the standard deviation was 0.669. This means that we have to find Z when [tex]X = 3.49, \mu = 5.091, \sigma = 0.669[/tex]. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{3.49 - 5.091}{0.669}[/tex]

[tex]Z = -2.39[/tex]

Jane had a z-score of -2.39.

Which player had the better year relative to their peers, Hank or Jane

Low ERA is good, high is bad. This means that whoever had the lower z-score had the better year, and in this case, it's Jane

Answer:

Q

=

n

i

=

1

(

Yi

−

(

β

0

+

β

1

X

i))

2

Answer:a

Step-by-step explanation:

Answer:

0.43*0.43

Step-by-step explanation:

The pressure on the snow if the area of the footwear is 400 in² is 0.0645 pounds per square inch.

The force applied perpendicular to an object's surface per unit area across which that force is spread is known as pressure.

[tex]P= \dfrac{W}{A}[/tex]

As it is given that the pressure is inversely proportional to the area of the footwear. Therefore, the relation can be written as,

[tex]P\propto \dfrac{1}{A}\\[/tex]

Now, introducing a constant to remove the proportionality symbol, w that is the weight of the person, therefore,

[tex]P= \dfrac{W}{A}[/tex]

Now, as the area of the shoe is 60in²,  the pressure on the snow is  0.43 pounds per square inch. Therefore, the value of w can be written as,

[tex]0.43= \dfrac{W}{60}\\\\W = 25.8\rm\ pounds[/tex]

Now, the pressure on the snow if the area of the footwear is 400 in².

[tex]P= \dfrac{W}{A}\\\\P= \dfrac{25.8}{400}\\\\P = 0.0645 \rm\ pounds\ per\ inch^2[/tex]

Hence, the pressure on the snow if the area of the footwear is 400 in² is 0.0645 pounds per square inch.

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Answer:

Step-by-step explanation:

2 meters = 200 cm

200 cm × (1 block)/(50 cm) = 4 blocks

4 blocks by 4 blocks = 16 blocks

Answer:

16 paving stones

Step-by-step explanation:

1 m = 100 cm

The square has sides 200 cm long

Its area is 200(200) = 40000 sq cm

Each paving stone has an area of 50(50) = 2500 sq cm

So 40000/2500 = 16 paving stones

Answer: See explanation

Step-by-step explanation:

We are informed that Stephen rewrites 3r - 18 = 27 as 3(r - 6) = 3(9). This is quite thoughtful of Stephen and it's an easier way to solve the question.

In this case, 3 is a common factor to 3r, 18 and 27. Therefore, we will then have: 3(r - 6) = 3(9).

Since 3 is a common base to both, we are more concerned with the values inside the brackets. This will be:

r-6 = 9

r = 9 + 6

r = 15

Check: 3r - 18

3(15) - 18 = 45 - 18 = 27

Answer:

The calculated  χ²  = 20.779  falls in the critical region  χ² ≥ 14.46 so we accept the null hypothesis that all the means are equal and college undergraduates students do not differ from the general public with regard to their favorite sports.

Step-by-step explanation:

1) We set up our null and alternative hypothesis as

H0: the college undergraduates students do not differ from the general public with regard to their favorite sport

H0:  μ1= μ2=μ3=μ4= μ5=μ6=μ7=μ

against the claim

Ha: the college undergraduates students differ from the general public with regard to their favorite sport

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is ( Pearson goodness of fit test )

χ²= ∑ (O - E)²/ E   where O is the observed and E is the expected frequency

which has an approximate chi square distribution with 6 (n-1) d.f

4) Computations:

Under H0 , the observed frequencies are :

 Observed       Expected          (O-E)          (O-E)²                   (O-E)²/E

 111                    (0.33*344)=

                             113.52           -2.52             6.3054              0.0555

  39                      51.6               -12.6              158.76               3.0767

  46                       34.4               11.6               134.56              3.911

  14                       20.64              -6.64           44.0896           2.136

  6                        17.2                   -11.2            125.44             7.293

 20                       17.2                    2.8             7.84                 0.4558

108                       89.44                18.56           344. 4736       3.8514              

                              344                                                             20.779    

5) The critical region is χ² ≥  χ² (0.025)6 = 14.45

6) Conclusion:

The calculated  χ²  = 20.779  falls in the critical region  χ² ≥ 14.46 so we reject the null hypothesis that all the means are equal and college undergraduates students do not differ from the general public with regard to their favorite sports.

Given that all the results are lower or higher in percentage, but they do not exceed the 5.5% threshold, it can be said that college undergraduates students do not differ from the general public with regard to their favorite sports.

Since the Harris Poll tracks the favorite sport of Americans who follow at least one sport, and results of the poll show that professional football is the favorite sport of 33% of Americans who folllow at least one sport, followed by baseball at 15%, mens college football at 10%, auto racing at 6%, mens professional basketball at 5%, and ice hockey at 5%, with other sports at 26%, considering a survey in which 344 college undergraduates who follow at least one sport were asked to identify their favorite sport produced the following results:

To determine if college undergraduates students differ from the general public with regard to their favorite sports, the following calculation must be performed:

Therefore, given that all the results are lower or higher in percentage, but they do not exceed the 5.5% threshold, it can be said that college undergraduates students do not differ from the general public with regard to their favorite sports.

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