A balloon rises at the rate of 10 ft/sec from a point on the ground 100 feet from an observer. Find the rate of change of the angle of elevation of the balloon from the observer when the balloon is 100 feet above the ground.

Answers

Answer 1

When the balloon, rising at 10 ft/sec, rises to 100 feet, the rate of change of the angle of elevation is 0.05 rad/sec

How can the rate of change of the angle of elevation be found?

The rate at which the balloon rises = 10 ft/sec

Horizontal distance of the balloon from the observer, d = 100 feet

Therefore;

[tex] \frac{dy}{dt} = 10[/tex]

The angle of elevation can be presented as follows;

[tex] tan(\theta) = \frac{y}{100} [/tex]

[tex] y = 100 \times tan(\theta) [/tex]

Therefore;

[tex] \frac{dy}{dt} = \mathbf{ 100\cdot sec^2 \frac{d \theta}{dt}} [/tex]

Which gives;

[tex] \frac{d \theta}{dt}= \frac{ \frac{d y}{dt}}{100} \times cos^2 \theta [/tex]

[tex] \mathbf{ \frac{d \theta}{dt}} = \frac{ 10}{100} \times cos^2 \theta [/tex]

When the balloon is 100 ft. from the ground, we have;

cos(theta) = 100/(√(100²+100²) = 1/(√2)

Therefore;

[tex] \frac{d \theta}{dt}= \frac{ 10}{100} \times \left(\frac{1}{\sqrt{2}} \right)^2 [/tex]

[tex] \frac{ 10}{100} \times \left(\frac{1}{\sqrt{2}} \right)^2 = \frac{ 1}{20} [/tex]

Which gives;

[tex] \frac{d \theta}{dt}=\frac{ 1}{20} = 0.05 [/tex]

The rate of change of the angle of elevation when the balloon is 100 feet from the ground is 0.05 rad/sec

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Answer:

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Step-by-step explanation:

Here's the complete question:

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Answers

Answer:

The cost to rent each chair is $1.25 and the cost to rent each table is $8.50

Step by step:

A party rental company has chairs and tables for rent. The total cost to rent

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1 Expert Answer

By:

Best

Edward C. answered • 02/10/15

TUTOR 5.0 (377)

Caltech Grad for math tutoring: Algebra through Calculus

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Let C = cost to rent each chair

Let T = cost to rent each table

4C + 8T = 73

2C + 3T = 28

Multiply the 2nd equation by (-2) and then add the equations together

4C + 8T = 73

-4C - 6T = -56

2T = 17

T = 17/2 = 8.5

Plug this in to the 1st equation to solve for C

4C + 8(17/2) = 73

4C + 68 = 73

4C = 5

C = 5/4 = 1.25

So the cost to rent each chair is $1.25 and the cost to rent each table is $8.50

The cost to rent each chair and each table are $1 and $8.5 respectively.

Suppose the price of one chair =x

The price of one table =y

What is a linear equation?

Any equation of the form ax+by+c=0 is called a linear equation where a, b, c∈ R.

According to the question, the total cost to rent 5 chairs and 2 tables is $22.

5x+2y=22

Multiplying it by 4 on both sides

20x+8y=88.......(1)

The total cost to rent 3 chairs and 8 tables is $71.

3x+8y=71.........(2)

Subtracting (2) from (1)

17x=17

x=1

So, y=8.5

So, the price of 1 chair =$1

the price of 1 table =$8.5

Hence, the cost to rent each chair and each table are $1 and $8.5 respectively.

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Step-by-step explanation:

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you were correct

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