A Bicycle With 0.80 M Diameter Tires Is Coasting On A Level Road At 5.6 M/S. A Small Blue Dot Has Been Painted On The Tread Of The Rear Tire.The angular velocity of the tires is 14 rad/s.
When a bicycle is coasting on a flat road at 5.6 m/s and has 0.80 m diameter tires, the angular velocity of the tires and the speed of the blue dot when it is 0.80 m above the road are both determined. The angular velocity of the tires and the speed of the blue dot are found below.
At any point, the speed of a point on a tire that is a height h above the ground is given by the following equation:
v = v₀ + ωr
where
v₀ is the initial velocity
ω is the angular velocity
r is the distance between the point on the tire and the center of rotation.
The point on the tire where the blue dot is painted is 0.80 m above the ground, which is the same as the distance between the center of the tire and the ground.
The radius of the tire is half of the diameter, which is 0.80 m divided by 2 or 0.40
m.ω = v/rω = 5.6 m/s / 0.40 mω = 14 rad/s
The point on the tire that is 0.80 m above the ground has a velocity of:
v = v₀ + ωrv₀ = 0 because the tire is not moving at a height of 0.80
m.v = ωr = 14 rad/s × 0.40 m = 5.6 m/s
The speed of the blue dot is 5.6 m/s.
v = ωrv = 5.6 m/sr = 0.40 mω = v/rω = 5.6 m/s / 0.40 mω = 14 rad/s
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on the grid below sketch at least one complete cycle of a transverse wave with a 4.0 centimeter amplitude a freuqncy of 5.0 hertz
Draw the complete cycle of the wave by repeating the pattern of the peak, the equilibrium position, and the trough, with a distance of λ between each consecutive peak or trough. The number of cycles per second, or the frequency, should be 5.0 hertz.
What is Wave?
A wave is a disturbance that propagates through space and time, often transferring energy from one location to another without the physical transfer of matter. Waves can take many different forms, including sound waves, electromagnetic waves, and mechanical waves.
Draw a horizontal axis representing time, labeled in seconds or milliseconds.
Draw a vertical axis representing displacement or amplitude, labeled in centimeters or meters.
Choose a starting point for the wave, which represents the equilibrium position of the medium.
Draw the peak of the wave, which represents the maximum displacement of the medium from its equilibrium position. This should be 4.0 centimeters above the equilibrium position.
Draw the trough of the wave, which represents the minimum displacement of the medium from its equilibrium position. This should be 4.0 centimeters below the equilibrium position.
Determine the wavelength of the wave, which is the distance between two consecutive peaks or troughs. This can be calculated using the formula λ = v/f, where λ is the wavelength, v is the velocity of the wave, and f is the frequency. For a transverse wave on a string, the velocity is given by v = √(T/μ), where T is the tension in the string and μ is the linear mass density of the string.
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If you have just used a velocity selector for electrons and you wish to use it to choose
positrons with the same speed, do you have to change any settings which are related to
electric field and magnetic field on the velocity selector? Explain your answer with the aid
of labelled diagram
Answer:
Explanation:
Yes, the settings related to electric and magnetic fields need to be changed to select positrons with the same speed as electrons in a velocity selector.
A velocity selector is a device that selects charged particles of a specific speed. It consists of perpendicular electric and magnetic fields. The electric field accelerates charged particles, while the magnetic field deflects the particles in a circular path.
To select positrons with the same speed as electrons in a velocity selector, the direction of the magnetic field needs to be reversed, as positrons have the opposite charge to electrons and will therefore be deflected in the opposite direction.
The diagram below shows the setup of a velocity selector for electrons and how it needs to be modified to select positrons with the same speed:
Velocity Selector Diagram
In the original setup for electrons, the magnetic field is directed into the page, while the electric field is directed upwards. Electrons of a specific speed will travel in a circular path and exit the selector through a slit at the top.
To select positrons with the same speed, the direction of the magnetic field needs to be reversed, so that it is directed out of the page. This will cause the positrons to travel in a circular path in the opposite direction to electrons, and they will also exit through the slit at the top. The electric field can remain in the same direction, as it only serves to accelerate the charged particles.
A glass marble whose mass is 0.1 kg falls from a height of 40 m and rebounds to a height of 10 m. Find the impulse and the average force between the marble and the floor if the time during which they are in contact is 0.1 sec.
[Take g= 9.8 ms^-2]
(a) The impulse between the marble and the floor is -3.23 Ns.
(b) The average force F between the marble and the floor is -32.3 N.
What is the impulse of the marble and floor?We can use the principle of conservation of energy to find the velocity of the marble just before it hits the ground:
Initial potential energy = mgh = 0.1 kg × 9.8 m/s² × 40 m = 39.2 J
Final kinetic energy = (1/2)mv²
39.2 J = (1/2) × 0.1 kg × v²
v = √(2 × 39.2 J / 0.1 kg) = 88.4 m/s
When the marble hits the ground, it experiences a force due to the floor that changes its momentum. The impulse J of this force can be calculated as:
J = Δp = mΔv
where;
Δv is the change in velocity and m is the mass of the marble.The change in velocity is given by:
Δv = vf - vi
where;
vf is the final velocity of the marble just after rebounding and vi is its velocity just before hitting the floor.We know that vi = 88.4 m/s, and we can find vf using the conservation of energy principle again:
Final potential energy = mgh = 0.1 kg × 9.8 m/s² × 10 m = 9.8 J
Initial kinetic energy = (1/2)mv² = (1/2) × 0.1 kg × (88.4 m/s)² = 389.8 J
389.8 J = 9.8 J + (1/2)mvf²
vf = √(2 × (389.8 - 9.8) J / 0.1 kg) = 56.1 m/s
Therefore, the impulse is:
J = mΔv = 0.1 kg × (56.1 m/s - 88.4 m/s) = -3.23 N·s
The negative sign indicates that the impulse is in the opposite direction to the initial velocity.
The average force F between the marble and the floor can be found using the formula:
F = J / Δt
where;
Δt is the time during which the marble and the floor are in contact.In this case, Δt = 0.1 s, so:
F = J / Δt = (-3.23 N·s) / 0.1 s = -32.3 N
Again, the negative sign indicates that the force is in the opposite direction to the initial velocity.
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The specific sequence of spectral line series emitted by excited hydrogen atoms, in order of increasing wavelength range, is
The sequence of spectral line series emitted by excited hydrogen atoms, in order of increasing wavelength range, is as follows: Lyman series: This series contains spectral lines emitted by transitions of electrons from upper energy levels to the ground state, which is represented by n=1.
The spectral lines are in the ultraviolet region of the electromagnetic spectrum. This series is represented by the formula: n=1→(n=2,3,4,...). Balmer series: This series contains spectral lines emitted by transitions of electrons from upper energy levels to the first excited state, which is represented by n=2. The spectral lines are in the visible region of the electromagnetic spectrum. This series is represented by the formula: n=2→(n=3,4,5,...). Paschen series: This series contains spectral lines emitted by transitions of electrons from upper energy levels to the second excited state, which is represented by n=3. The spectral lines are in the infrared region of the electromagnetic spectrum. This series is represented by the formula: n=3→(n=4,5,6,...).
Brackett series: This series contains spectral lines emitted by transitions of electrons from upper energy levels to the third excited state, which is represented by n=4. The spectral lines are in the infrared region of the electromagnetic spectrum. This series is represented by the formula: n=4→(n=5,6,7,...). Pfund series: This series contains spectral lines emitted by transitions of electrons from upper energy levels to the fourth excited state, which is represented by n=5. The spectral lines are in the infrared region of the electromagnetic spectrum. This series is represented by the formula: n=5→(n=6,7,8,...). The spectral line series of hydrogen atoms represents a particular series of wavelengths that are emitted when an electron changes its energy level. This phenomenon can be used to study the properties of atoms and to understand the behavior of atoms under different conditions.
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Three bulbs_ two of which contain different gases and one of which is empty; are connected as shown in drawing (a). Which drawing (b) - (d) best represents the system after the stopcocks are opened and the system is allowed to come to equilibrium? drawing (d) drawing (b) drawing (c}
Drawing (d) best represents the system after the stopcocks are opened and the system is allowed to come to equilibrium, as it shows equal pressure in all three bulbs.
Since the two bulbs contain different gases, the pressures in each bulb will be different. When the stopcocks are opened, the gases will flow into the empty bulb until the pressures are equalized. The final state will have equal pressure in all three bulbs.
What is an equilibrium?
An equilibrium is a state of balance or stability achieved in a chemical reaction when the forward reaction rate is equal to the reverse reaction rate. In other words, it is the point at which the concentrations of reactants and products no longer change with time, because the rates of the forward and reverse reactions are equal.
At equilibrium, the amounts of reactants and products are governed by the equilibrium constant (K), which is a measure of the relative concentrations of the reactants and products at equilibrium.
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Just after launch from the earth, the space-shuttle orbiter is in the 42 x 153–mi orbit shown. At the apogee point A, its speed is 17246 mi/hr. If nothing were done to modify the orbit, what would its speed be at the perigee P? Neglect aerodynamic drag. (Note that the normal practice is to add speed at A, which raises the perigee altitude to a value that is well above the bulk of the atmosphere.) The radius of the earth is 3959 mi.
If nothing were done to modify the orbit, the speed of the space-shuttle orbiter at the perigee P would be approximately 17085 mi/hr
What is the speed of the space-shuttle?
We can use the principle of conservation of energy to determine the speed of the space-shuttle orbiter at the perigee P.
At the apogee point A, the potential energy of the space-shuttle orbiter is at a maximum, while its kinetic energy is at a minimum. Conversely, at the perigee point P, the kinetic energy is at a maximum, while the potential energy is at a minimum.
The potential energy of the space-shuttle orbiter at any point in its orbit can be calculated as:
U = - G M m / r
where;
G is the gravitational constant, M is the mass of the Earth, m is the mass of the orbiter, and r is the distance between the Earth's center and the orbiter.The kinetic energy of the orbiter can be calculated as:
K = (1/2) m v^2
where;
v is the velocity of the orbiter.Since the sum of the kinetic energy and potential energy remains constant throughout the orbit, we can set the total energy E equal to the sum of the kinetic and potential energies at the apogee point A:
E = U(A) + K(A)
At the perigee point P, the total energy is the same, so we can write:
E = U(P) + K(P)
Equating these two expressions for E, we get:
U(A) + K(A) = U(P) + K(P)
Substituting the expressions for potential and kinetic energy, we get:
G M m / r(A) + (1/2) m v(A)² = - G M m / r(P) + (1/2) m v(P)²
Canceling out the mass of the orbiter and multiplying both sides by -1, we get:
G M / r(A) - (1/2) v(A)² = G M / r(P) - (1/2) v(P)²
Solving for v(P), we get:
v(P) = √[2 G M / r(P) - (1/2) v(A)² + 2 G M / r(A)]
Now we can substitute the given values and solve for v(P):
v(A) = 17246 mi/hr
r(A) = 3959 + 153 = 4112 mi
r(P) = 3959 + 42 = 4001 mi
G M = 1.327 × 10^11 m^3/s^2
Converting units to SI, we get:
v(A) = 7742.6 m/s
r(A) = 6617.6 km
r(P) = 6400.2 km
G M = 3.986 × 10¹⁴ m³/s²
Substituting these values, we get:
v(P) = √[2 (3.986 × 10¹⁴) / (6400.2 × 1000) - (1/2) (7742.6)² + 2 (3.986 × 10¹⁴) / (6617.6 × 1000)]
= 7640.7 m/s
Converting back to miles per hour, we get:
v(P) = 17085 mi/hr (rounded to the nearest mile per hour)
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Person A stands on the ground, train B with proper length L moves to the right at speed 3c/5, and person C runs to the right at speed 4c/5. C starts behind the train and eventually passes it. Let event E1 be "C coincides with the back of the train," and let event E2 be "C coincides with the front of the train." Find the Delta t and Delta x between the events E1 and E2 in the frames of A, B, and C, and show that c2 Delta t2 - Delta x2 is the same in all three frames.
The Delta t and Delta x between the events E1 and E2 in the frames of A, B, and C, and show that c2 Delta t2 - Delta x2 is the same in all three frames. The Space time interval in all frames is [tex]\frac{144}{25}L^2[/tex].
In the following we will find out the time interval and space interval between the two events E1 and E2 with respective to A, B and C.
Simultaneously we will find out space time interval in each case and finally show that they are the same.
In the frame of reference of C
The time interval is the time it takes for ( to Cover the contracted length of B.
with respect to C, B will have a relative velocity Ux' = (-5/13)C (we had already found out it.Only the sign changes)
Then the contrasted length of B with respect to C.
would be L' = [tex]L\sqrt{1 - \frac{Ux^2}{C^2}} = L\sqrt{1 - \frac{25}{169}}[/tex]
L' = (12/13)L
So dt = L'/un\x' =(12/13)L / (-5/13)C = (12/5)(L/C)
dx =0 as E1, and E2 occurs at the same point with respect to C. Now space time Interval is Cdt^2 = dx^2 =
[tex]C^2 \frac{144}{25}\frac{L^2}{C^2}-0 = \frac{144}{25}L^2[/tex]
The quantity of time between two given instances is referred to as time interval. In other words, it is the amount of time that has surpassed among the beginning and end of the event. it is also called elapsed time. interval of time is measured in special units. every unit describes a one of a kind quantity of time. some units are better appropriate to specific durations of time.
As an instance, if you were baking a cake within the oven, you will select to measure the time in minutes or perhaps in hours. in case you were calculating the time on your birthday from a particular date, you will choose to measure the time in days, weeks, or months (relying on how far away it became).
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The back emf in a motor is 72 V when operating at 1800 rpm. What would be the back emf at 2500 rpm if the magnetic field is unchanged?
The back emf at 2500 rpm if the magnetic field is unchanged is 100 V for the back emf in a motor is 72 V when operating at 1800 rpm.
The back emf in a motor is proportional to the speed of the motor. Therefore, we can use the following formula to determine the back emf at 2500 rpm:
E2 = E1 × (N2 / N1)
where E1 is the back emf at 1800 rpm, N1 is the speed at which the back emf was measured, E2 is the back emf at 2500 rpm, and N2 is a new speed.
Plugging in the values we get:
E2 = 72 V × (2500 rpm / 1800 rpm)
E2 = 100 V
Therefore, the back emf at 2500 rpm of the motor would be 100 V if the magnetic field is unchanged.
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An observer counts 4 complete water waves passing by the end of a dock every 10 seconds. What is the
frequency of the waves?
a) 4,0 Hz
b) 0.40 Hz
() 40 Hz
d) 2.5 Hz
The frequency of the water wave is 0.4Hz (option B).
How to calculate frequency?Frequency is the quotient of the number of times (n) a periodic phenomenon occurs over the time (t) in which it occurs.
The frequency of a wave can be calculated by dividing the number of occurrence by time as follows;
f = n/t
Where;
f = frequencyn = number of times of occurrencet = timeAccording to this question, an observer counts 4 complete water waves passing by the end of a dock every 10 seconds. The frequency can be calculated as follows:
f = 4/10
f = 0.4Hz
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The electric potential energy of a charged particle is the work of carrying any charge from an infinite distance to a point in an electrostatic field.The following pieces of information are given below:The charge is Q=+16.1 nCThe distance of A from Q is X1=1.3 cm.The distance of B from Q is Y=1.3 cm.The distance of C from Q is X2=3.8 cm.The objective of the question is to find the following:D. The change in potential energy, force, and acceleration when the electron is replaced by a proton
When the electron is replaced by a proton, the change in potential energy is [tex]ΔU = -5.13 \times 10^-3 J[/tex], the force is [tex]F = 6.45 \times 10^-3 N[/tex], and the acceleration is [tex]a = 3.85 \times 10^24 m/s^2.[/tex]
The electric potential energy of a charged particle is the work done in carrying any charge from an infinite distance to a point in an electrostatic field.
Given the following information:
charge, Q=+16.1 nC; distance of A from Q, X1=1.3 cm; distance of B from Q, Y=1.3 cm; distance of C from Q, X2=3.8 cm.
The objective is to find the change in potential energy, force, and acceleration when the electron is replaced by a proton.
The potential energy of a particle with charge Q located at a point (X,Y,Z) in an electrostatic field is given by U=kQ/r, where k is Coulomb's constant, and r is the distance between the point and the charge.
Therefore, the change in potential energy, ΔU, can be calculated by subtracting the potential energy of the electron from the potential energy of the proton.
ΔU = kQ/rproton - kQ/relectron
Since charge is a constant, ΔU can be simplified to ΔU = (1/rproton - 1/relectron) * kQ.
Substituting the given values for X1, Y, and X2, the change in potential energy is:
[tex]ΔU = (1/1.3 - 1/3.8) \times 8.99 \times 10^9 \times 16.1 \times 10^-9
ΔU = -5.13 \times 10^-3 J[/tex]
The force F is the negative derivative of the potential energy with respect to the distance between the charges, which is given by F= -dU/dr.
The force between the electron and the proton is:
[tex]F = -dU/dr = -(1/rproton^2 - 1/relectron^2) \times kQ[/tex]
Substituting the given values for X1, Y, and X2, the force is:
[tex]F = -(1/1.3^2 - 1/3.8^2) \times 8.99 \times 10^9 \times 16.1 \times 10^-9
F = 6.45 \times 10^-3 N[/tex]
The acceleration, a, of the particle can be determined using Newton's second law, F=ma, which gives a = F/m. Since the mass of the proton is greater than the mass of the electron, the acceleration will be less than it was before the replacement.
Substituting the force and the mass of the proton, the acceleration is:
[tex]a = F/m = 6.45 \times 10^-3 N / 1.67 \times 10^-27 kg
a = 3.85 \times 10^24 m/s^2[/tex]
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Derive a formula for the efficiency of the Diesel cycle, in terms of the compression ratio �
1
/
�
2
V 1
/V 2
and the cutoff ratio �
3
/
�
2
.
V 3
/V 2
. Show that for a given compression ratio, the Diesel cycle is less efficient than the Otto cycle. Evaluate the theoretical efficiency of a Diesel engine with a compression ratio of 18 and a cutoff ratio of 2.
The theoretical efficiency of a Diesel engine with a compression ratio of 18 and a cutoff ratio of 2 is 0.94.
The efficiency of the Diesel cycle, denoted by η, can be expressed as a function of the compression ratio (r)
and the cutoff ratio (r_c)
as follows:
[tex]η = 1 - 1/(r^(r_c-1))[/tex]
This equation shows that as the compression ratio increases, the efficiency of the Diesel cycle increases.
When comparing the efficiency of the Diesel cycle to that of the Otto cycle, it can be seen that for a given compression ratio, the Diesel cycle is less efficient than the Otto cycle. To evaluate the theoretical efficiency of a Diesel engine with a compression ratio of 18 and a cutoff ratio of 2, we can use the equation above to calculate the efficiency as:
[tex]η = 1 - 1/(18^(2-1))[/tex]
η = 1 - 1/18
η = 0.94
Therefore, the theoretical efficiency of a Diesel engine with a compression ratio of 18 and a cutoff ratio of 2 is 0.94.
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a banked curve is safer than a flat curve because the ___ force required to keep the car from skidding is supplied by the horizontal component of the ___ force instead of friction.
Answer:
centripetal, normal
What is the frequency of blue light that has a wavelength of 448 nm?
Answer:
The frequency of light can be calculated using the following formula:
frequency = speed of light / wavelength
where the speed of light is approximately 299,792,458 meters per second.
First, we need to convert the given wavelength from nanometers to meters:
448 nm = 448 × 10^-9 m
Now we can plug in the values and solve for frequency:
frequency = (299,792,458 m/s) / (448 × 10^-9 m)
frequency = 6.69 × 10^14 Hz
Therefore, the frequency of blue light with a wavelength of 448 nm is approximately 6.69 × 10^14 Hz.
A slingshot consists of a light leather cup attached between two rubber bands. It takes a force of 33 N to stretch the bands 1.3 cm.A) What is the equivalent spring constant of the rubber bands? Answer in n/m.B) How much force is required to pull the cup of the slingshot 4.2 cm from its equilibrium position? Answer in units of N.
The force needed to pull the cup of the slingshot 4.2 cm from its equilibrium position is 2667N/m.
From the Hook's law, the spring constant may be expressed as follows:
k=F / x
wherein F=32N is the elastic pressure (which is identical to the applied one if rubber bands do no longer flow after stretching), and x=1.2cm=0.012m is the elongation of the bands.
k= 32N / 0.012m ≈ 2667N/m
A slingshot is a handheld projectile weapon that uses elastic materials, such as rubber bands or natural fibers, to propel small projectiles. It consists of a Y-shaped frame with two rubber bands attached to the forks of the frame. The user stretches the bands back with their fingers, placing a projectile such as a small rock or ball in a pouch or cradle, and then releases the bands to launch the projectile.
Slingshots have been used for hunting and recreation for thousands of years, and are still popular today. They are relatively inexpensive and easy to make, and can be used for target shooting, small game hunting, and even self-defense in some situations.
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Why does the safety curtain need to be loosely draped?
The safety curtain needs to be loosely draped so that it will move easily with the movement of the actors. This will prevent any potential safety hazards from occurring, such as the curtain becoming stuck or snagging on any props or scenery.
Additionally, it is important for the curtain to not be too tight as this could prevent it from falling properly.
The safety curtain needs to be loosely draped so that it can fall easily in case of an emergency.What is a safety curtain?A safety curtain is a fire-resistant metal or asbestos curtain that is suspended above the stage of a theater. In the case of a fire, the curtain is designed to descend quickly and close off the stage area, preventing flames from spreading to the auditorium and providing an escape route for the actors and stage crew.
In the case of an emergency, the safety curtain must drop down without difficulty. That is why the safety curtain must be loosely draped. The safety curtain is supported by a counterweight and a rope system that is positioned over the stage's proscenium arch.
The safety curtain, for example, is used in theatres to protect the audience in the event of a fire. It's also used as a barrier between the stage and the audience. A fire-resistant cloth or metal shutter that, in the event of a fire, may be lowered to cut off the stage from the rest of the theatre is known as a safety curtain.
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Describe what would happen to that balance if the temperature of a star suddenly dropped. What would happen if the temperature suddenly rose? What would happen if the density suddenly increased without a change in temperature? What would happen if the cloud gained a little bit of mass?
The cloud would begin to collapse if the temperature abruptly dropped as would the pressure, giving gravity the upper hand.
The pressure would rise with a rise in temperature, and the fog would start to grow.
The cloud would start to collapse if it gained a little mass because gravity would dominate.
What is the relationship between pressure, temperature, and gravity in a molecular cloud?In a molecular cloud, pressure, temperature, and gravity are all interconnected and play crucial roles in determining the cloud's properties and evolution.
Gravity is the force that holds the molecular cloud together and determines its overall shape and density. The more massive the cloud, the stronger its gravitational force and the tighter it can hold onto its gas and dust.
Temperature is related to the thermal energy of the gas and dust within the cloud. As the gas and dust particles move around, they collide with each other, transferring energy in the form of heat.
The pressure of a molecular cloud is determined by the temperature and density of the gas and dust within it. As the temperature increases, the pressure also increases. Similarly, as the density of the gas and dust increases, the pressure also increases.
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Complete question:
Suppose pressure and gravity are perfectly balanced within a certain molecular cloud. Describe what would happen to that balance if the temperature suddenly dropped. What would happen if the temperature suddenly rose? What would happen if the density increased without a change in temperature? What would happen if the cloud gained a little bit of mass?
Help with 2 Kirchoff law exercises
1-For the circuit in the figure below, find V₁ and V2.
2-Find the currents and voltages in the following circuit.
Answer:
v1 = 8V; v2=12Vi1=9/7A, i2=13/14A, i3=5/14A, v1=18/7V, v2=52/7V, v3=10/7VExplanation:
You want the voltages in each circuit, and also the currents in the second circuit.
1. Voltage dividerIn this series circuit, the voltage is divided in proportion to the resistance.
v1 = 2/5(20V) = 8V
v2 = 3/5(20V) = 12V
2. Current equationsThe sum of voltages around a loop is 0, so we can write the equations ...
2·i1 +8·i2 = 10
8·i2 -4·i3 = 6
i1 -i2 -i3 = 0
The attachment shows the calculation of the currents. Those are used to find the corresponding voltages.
(i1, i2, i3) = (9/7, 13/14, 5/14)A
(v1, v2, v3) = (18/7, 52/7, 10/7)V
__
Additional comment
A T-circuit as in figure 2 can usually be solved handily by making use of Norton's equivalents for the sources. The left source can be replaced by a 5A current source in parallel with 2Ω. The right source can be replaced by a 1.5A current source in parallel with 4Ω. Then the circuit degenerates to a 6.5A source in parallel with 8/(4+1+2) = 8/7Ω. So, the voltage v2 is ...
v2 = (6.5A)(8/7Ω) = 52/7V
Then {v1, -v3} = {10, 6} -v2 ⇒ (v1, v3) = (18/7, 10/7)
The currents are found by dividing the voltage by the resistance:
{i1, i2, i3} = {18/7, 52/7, 10/7}÷{2, 8, 4} = (9/7, 13/14, 5/14) . . . . as above
Note that these calculations can all be done without the aid of calculator.
Parallel resistors that are multiples of one another can be thought of as some number of resistors in parallel. Here, the 2Ω resistor can be thought of as 4 8Ω resistors in parallel. Similarly, the 4Ω resistor is effectively 2 8Ω resistors in parallel. Thus the parallel combination of 2Ω, 8Ω, and 4Ω is effectively 4+1+2 = 7 8Ω resistors in parallel, or 8/7Ω. No calculator required.
A 509g mass oscillates with an amplitude of 13.0cm on a spring whose spring constant is 20.0N/m . A. Determine the period T= ....... s B. Determine the maximum speed Vmax= ...... m/s C. Determine the total energy Wtotal= ........ J
Period (T):
T = 2π√(m/k)
where m is the mass of the object and k is the spring constant.
Maximum speed (Vmax):
Vmax = Aω
where A is the amplitude of oscillation and ω is the angular frequency, which is given by ω = √(k/m).
Total energy (Wtotal):
W total = 1/2 kA^2
where k is the spring constant and A is the amplitude of oscillation.
Given:
m = 509g = 0.509 kg
A = 13.0 cm = 0.13 m
k = 20.0 N/m
A. Determine the period T:
T = 2π√(m/k)
T = 2π√(0.509 kg / 20.0 N/m)
T = 0.798 s
Therefore, the period of oscillation is 0.798 s.
B. Determine the maximum speed Vmax:
ω = √(k/m) = √(20.0 N/m / 0.509 kg) = 8.05 rad/s
Vmax = Aω = 0.13 m * 8.05 rad/s = 1.05 m/s
Therefore, the maximum speed of the oscillating mass is 1.05 m/s.
C. Determine the total energy W total:
Wtotal = 1/2 kA^2 = 1/2 * 20.0 N/m * (0.13 m)^2 = 0.135 J
Therefore, the total energy of the oscillating mass is 0.135 J.
What is energy ?Energy is a physical property of objects that can be transferred to other objects or converted into different forms, but cannot be created or destroyed. It is often defined as the ability to do work, where work is the product of a force and the distance through which it acts.
Energy exists in many different forms, including mechanical energy associated with motion and position of objects, thermal energy associated with the temperature of objects, electromagnetic energy associated with electric and magnetic fields chemical energy associated with chemical reactions), and nuclear energy associated with the energy released during nuclear reactions.
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The compressions in a sound wave are far apart and more energy is supplied by the vibrating source. Which statement best describes how this will affect the wave and what you hear?
A: The wavelength will increase, and the sound will become louder.
B: The amplitude will increase, and the sound will become louder.
C: The frequency will increase, and the pitch will become higher.
D: The intensity will increase, and the pitch will become higher.
The sound will get louder and the amplitude will rise. The separation between compressions in a sound wave indicates that the wave's wavelength has grown.
What happens when a sound wave is compressed and rarefied?When particles travel in close proximity to one another, compression occurs, creating areas of intense pressure. In contrast, when particles are separated from one another in low-pressure locations, rarefactions take place. As the tines of a vibrating tuning fork move back and forth, compressions and rarefactions are produced.
What does it signify when a longitudinal wave's compressions are spaced widely apart?Compressions and rarefactions are terms used to describe where a medium's particle distribution spreads out farther from one another.
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Problem 23.13 One type of antenna for receiving AM radio signals is a square loop of wire, 0.16 m on a side, that has 20 turns. Part A If the magnetic field from the radio waves changes at a rate of 8.4 × 10-4 T/s and is perpendicular to the loop, what is the magnitude of the induced emf in the loop? Express your answer to two significant figures and include appropriate units. Value Units Submit My Answers Give Up back Continue
The induced emf by the formula that we have can be obtained as 4.3 * 10^-4 V.
What is the induced emf?The induced emf (electromotive force) is the voltage that is generated in a conductor when there is a change in the magnetic field that surrounds the conductor. This phenomenon is known as electromagnetic induction and was discovered by Michael Faraday in the 19th century.
The induced emf is created by the interaction between the magnetic field and the moving charges in the conductor. When the magnetic field changes, it creates an electric field that pushes the charges in the conductor, creating a current flow.
Using emf = NAdB/dt
= 20 * (0.16)^2 * 8.4 × 10-4 T/s
4.3 * 10^-4 V
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Please Use microsoft excel
A pair of identical coils, each having a radius of 50 cm, are
separated by a distance equal to their radii, i.e. 50 cm. These
'Helmholtz Coils', are coaxial and carry equal currents such that
their axial fields point in the same direction. Assume the current in
each is 20 A, and there are 500 turns in each coil. Calculate, and
plot, the axial magnetic field for - 3m < z < +3m.
Answer:
Explanation:
Sure, we can use Microsoft Excel to calculate and plot the axial magnetic field for the given Helmholtz Coils.
Here's how we can proceed:
Create a new Excel workbook and open a new worksheet.
Label the first column as "z (m)" and enter the values from -3m to +3m in increments of 0.01m. This can be done by entering -3 in the first cell, and then dragging the fill handle down to fill the cells with the desired values.
Label the second column as "B (T)".
Use the following formula to calculate the axial magnetic field at each point:
B = (μ0 * n * I * R^2) / (2 * (R^2 + z^2)^(3/2))
where μ0 is the magnetic constant (4π x 10^-7 T·m/A), n is the number of turns per coil (500), I is the current in each coil (20 A), R is the radius of each coil (0.5 m), and z is the distance along the axis of the coils.
To apply this formula in Excel, enter the following formula in the second row of the "B (T)" column, and then drag the fill handle down to fill the rest of the column:
=(4PI()10^(-7)500200.5^2)/(2((0.5)^2+(A2)^2)^(3/2))
This formula calculates the magnetic field at the corresponding value of z in the first column. Note that the cell reference "A2" refers to the first value of z in the first column.
Once the "B (T)" column is filled with values, we can create a line graph to plot the axial magnetic field as a function of distance along the axis of the coils. To do this, select the "z (m)" and "B (T)" columns, including the column headings, and then click on the "Insert" tab and select "Line" from the "Charts" section. Choose the "Line with markers" style for the graph and format it as desired.
The resulting graph will show the axial magnetic field as a function of distance along the axis of the coils, which should resemble a symmetrical bell-shaped curve with a maximum value at the center of the coils.
Calculate the mass in kg of a ball at a height of 3m above the ground with a potential energy of 120J.
The mass of the ball at a height of 3m above the ground with a potential energy of 120J can be calculated using the equation:
Mass = Potential Energy/Gravity * Height
Mass = 120J/(9.81m/s² * 3m)
Mass = 4.1 kg
Answer:
4 kg
Explanation:
Using,
Energy/ Work done = Force x Distance (Height)
E = F • s
But recall, that F = mg
Therefore,
E = m • g • s
Making mass (m), the subject of the formula
m = E / (g • s)
m = 120 / (10 • 3)
m = 120 / 30
m = 4 kg
But if g = 9.8 ms-¹
Then,
m = 120 / (9.8 • 3)
m = 120 / 29.4
m = 4.08 kg
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Thanks
2. What is the missing piece for the energy transformation for a flashlight? *
Chemical > Electrical > BLANK
& Thermal
The missing piece for the energy transformation for a flashlight is "Light" or "Radiant" energy. Chemical > Electrical > light & Thermal
What is meant by energy transformation?Energy transformation is also known as energy conversion. It is the process of changing energy from one form to another. In physics, energy is a quantity that provides capacity to perform work or moving or provides heat.
The complete energy transformation for a flashlight is as :
Chemical (stored in the battery) > Electrical (when the battery powers the bulb) > Light/Radiant (when the bulb emits light) & Thermal (some of the energy is lost as heat due to resistance in the bulb and the circuit).
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Two pieces of clay, one white and one gray, are thrown through the air. The
m
white clay has a momentum of 25 kg, and the gray clay has a
S
momentum of -30 kg immediately before they collide.
What is the magnitude and direction of their final momentum immediately
after the collision?
Your answer should have one significant figure.
h
kg.
m
-
m
S
S
we can't give a specific direction for the final momentum.
What is momentum?
Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. Mathematically, momentum is expressed as:
Momentum (p) = mass (m) x velocity (v)
p = m x v
To solve this problem, we need to apply the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.
The initial total momentum of the system is:
p_initial = p_white + p_gray = 25 kg m/s - 30 kg m/s = -5 kg m/s
Since there are no external forces acting on the system, the total momentum of the system after the collision must also be -5 kg m/s. Therefore, the final momentum of the system is:
p_final = -5 kg m/s
The direction of the final momentum can be found by looking at the directions of the initial momenta. Since the white clay has positive momentum and the gray clay has negative momentum, we can say that the white clay is moving to the right and the gray clay is moving to the left before the collision.
During the collision, the two clays will exert forces on each other, causing them to change direction and possibly even break apart. Without more information about the collision, we can't say for sure what the direction of the final momentum will be. It could be to the left or to the right, or some combination of the two. Therefore, we can't give a specific direction for the final momentum.
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An unbalanced force is applied to accelerate the object to a final kinetic energy of 400.0 J. What is the change in the object's speed?
Answer:
Explanation:
Assuming the mass of the object remains constant, we can use the formula for kinetic energy:
KE = (1/2)mv^2
where KE is the final kinetic energy, m is the mass of the object, and v is the final speed.
Let's rearrange the equation to solve for v:
v = sqrt(2KE/m)
We don't know the mass of the object, but we can use the formula for force:
F = ma
where F is the net force applied to the object, m is the mass of the object, and a is the acceleration.
We can rearrange this equation to solve for the mass:
m = F/a
Now we can substitute this expression for mass into the formula for final speed:
v = sqrt(2KE/(F/a))
v = sqrt(2aKE/F)
We don't know the value of the force or the acceleration, so we can't calculate the final speed.
use energy methods to calculate the speed of the 6.00 kg k g block after it has descended 1.50 m m .
To calculate the speed of the 6.00 kg block, we can use the principle of conservation of energy. Initially, the block has potential energy due to its position and no kinetic energy. As it falls, its potential energy is converted to kinetic energy. At the bottom of its fall, all of the potential energy has been converted to kinetic energy.
The potential energy of the block at the top of its fall is given by:
PEi = mgh
where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the fall. Plugging in the given values, we get:
PEi = (6.00 kg)(9.81 m/s^2)(1.50 m) = 88.29 J
At the bottom of the fall, all of the potential energy has been converted to kinetic energy:
KEf = 1/2mv^2
where v is the velocity of the block at the bottom of the fall. Equating the two expressions for energy, we get:
PEi = KEf
(6.00 kg)(9.81 m/s^2)(1.50 m) = 1/2(6.00 kg)v^2
Solving for v, we get:
v = sqrt[(2(6.00 kg)(9.81 m/s^2)(1.50 m))/6.00 kg] = 7.67 m/s
Therefore, the speed of the 6.00 kg block after it has descended 1.50 m is 7.67 m/s.
work done on an object will increase that amount of energy the object has. the increase in energy can come from increases in blank .
The increase in energy can come from increases in work.
when a ball is thrown upward at an angle what happens to the vertical component of its velocity as it rises as it falls
As the ball is thrown upward at an angle, the vertical component of its velocity will decrease as it rises and increase as it falls. This is because of the gravitational force which acts in the opposite direction.
The vertical component of the velocity decreases as the ball rises and increases as the ball falls back to the ground. When an object is thrown upward, it has an initial velocity composed of both a horizontal and a vertical component. The horizontal component of the velocity is constant, while the vertical component of the velocity changes due to the force of gravity.
The vertical component of the velocity decreases as the ball rises due to the force of gravity. When the ball reaches its maximum height, the vertical component of the velocity is zero. As the ball falls back to the ground, the vertical component of the velocity increases due to the force of gravity until it reaches its maximum velocity just before hitting the ground.
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two forces of 433 n and 275n act at a point. the resulatant force is 516n. findt he angle between the forces
The angle between two forces of 433N and 275N is found using the formula θ = cos-1 (F1 x F2 / |F1| x |F2|), where F1 and F2 are the magnitudes of the two forces and θ is the angle between the forces.
In this case, we have |F1| = 433N, |F2| = 275N and the resultant force (F1 + F2) = 516N.
Substituting these values in the formula gives us:
θ = cos-1 (433 x 275 / 433 x 275) = cos-1 (1) = 0°Therefore, the angle between the two forces is 0°. Given, Two forces of 433 N and 275 N act at a point. The resultant force is 516 N. To find: The angle between the forces. Formula used: The angle between two forces is given by the formula,Tanθ = (F1 - F2) / F3where F1 and F2 are the magnitudes of the two forces and F3 is the magnitude of the resultant force, θ is the angle between the two forces. Substituting the given values,F1 = 433 NF2 = 275 NF3 = 516 NTanθ = (F1 - F2) / F3Tanθ = (433 - 275) / 516Tanθ = 0.3062θ = tan-1 (0.3062)θ = 17.64°The angle between the two forces is 17.64°.Hence, option B is the correct answer.
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If the Kelvin temperature of an object is doubled, the amount of radiant energy emitted each second is _________ the original amount:a) 1/16thb) halfc) the same asd) 2 timese) 16 time
When the Kelvin temperature of an object is doubled, the amount of radiant energy emitted each second is E. 16 times the original amount.
The amount of energy emitted by a body of the Kelvin temperature varies according to the fourth power of its absolute temperature, according to Stefan's law. Radiant energy is emitted by a heated object because of the vibration of its particles. As a result, as the temperature of the body rises, so does the energy emitted from it. The energy radiated by a body is directly proportional to the temperature raised to the fourth power.
Therefore, the amount of energy radiated by a body is proportional to the fourth power of its absolute temperature, according to Stefan's law. Suppose the initial temperature of the object is T and the energy emitted per second is E. If the temperature of the object is doubled, the new temperature will be 2T. As a result, the amount of energy radiated by the object each second (E') would be calculated by: E' = E(2T /T )4E' = E(16)The amount of radiant energy emitted each second is 16 times the original amount when the Kelvin temperature of an object is doubled.
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