a block weighing (Fg) 500 N is resting on a steel table ( us=0.74) the minimum force start this block moving is?

Answers

Answer 1

The minimum force required to start this block moving is 370 N.

The given parameters;

weight of the block, W = 500 Ncoefficient of static friction, [tex]\mu_s[/tex] = 0.74

The minimum force required to start this block moving is calculated as follows;

[tex]F= \mu_s F_n[/tex]

where;

[tex]F_n[/tex] is the normal force on the block which is equal to the weight of the block

[tex]F= \mu_s F_n \\\\F= \mu_s W\\\\F = 0.74 \times 500 \\\\F= 370 \ N[/tex]

Thus, the minimum force required to start this block moving is 370 N.

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Related Questions

A cyclist sitting still at the top of a hill displays gravitational potential energy. What makes it possible for the cyclist to have this type of energy?

Answers

Explanation:

because its speed (v) is 0

Suppose the gravitational force between two spheres is 30 N. If the magnitude of both masses doubles, and the distance between them tripled. What is the force between the masses?

Answers

If both masses double in size and their separation between them triples. 13..33 N will be the force between the masses.

What is gravitational force?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Given data:

The gravitational force = 30 N

Mass 1 =m₁

Mass 2=m₂

Distance between charges = R

Condition given:

Mass 1 = 2m₁

Mass 2= 2m₂

Distance  between charges = 3R

[tex]\rm F = \frac{Gm_1m_2}{R^2}[/tex]

Case 2;

[tex]\rm F'=\frac{G(2m_1)(2m_2)}{(3R)^2} \\\\ F'=\frac{4}{9} \frac{Gm_1m_2}{R^2} \\\\ F'=\frac{4}{9} F \\\\ F'=\frac{4}{9} \times 30 \\\\ F'=13.33 \ N[/tex]

Hence, the forces between the masses will be 13..33 N.

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Scientists are experimenting with a kind of gun that may eventually be used to fire payloads directly into orbit. In one test, this gun accelerates a 5.6-kg projectile from rest to a speed of 3.5 × 103 m/s. The net force accelerating the projectile is 2.5 × 105 N. How much time is required for the projectile to come up to speed?

Answers

Answer:

7.84 s

Explanation:

Ok, one step at a time. We know the mass of the projectile, we know the force. Acceleration is easily obtained from Newton second law:

[tex]\vec F = m\vec a[/tex][tex]2.5\times 10^5 = 5.6a \rightarrow a = (2.5/5.6) \times 10^5 = 4.46 \times 10^4 ms^-^2[/tex].

At this point, we know the acceleration, we know initial and final velocity, we can time the ammount of time it took to get there.

[tex]v= v_0 +at \rightarrow 3.5\times10^3 = 0 + 4.46\times10^4 t\\t= \frac{3.5\times10^3}{4.46\times10^4} = 7.84 s[/tex]

a girl runs once around a circular track with a radius of 100m at speed of 10m/s.
calculate her displacement​

Answers

Answer:

0 m

Explanation:

Displacement is the shortest distance from one ppont to another. Here, the girl returns to the same spot after running. Hence, displacement is 0 m.

In an exothermic reaction, energy is

the surroundings.


In an endothermic reaction, energy is

the surroundings.

Answers

In Exothermic reaction energy is Thrown/Relased to the surroundings.In endothermic reaction, energy is absorbed from the surroundings.

Trick to identify:-

Exothermic reaction has +∆H sign on product sideEndothermic reaction has -∆H sign on product side or +∆H sign on reactant side

Answer:

In an exothermic reaction, energy is

✔ released to

 the surroundings.

In an endothermic reaction, energy is

✔ absorbed from

 the surroundings.

Explanation:

10C of charge flow through a resistor in 4 seconds. What is the current?

Answers

Answer:

Very simple. The charge Q= 20 C. the formula for Q= I* t. now I= Q/t = 20/1s = 20 Amps.

Explanation:

The current given that the charge is 10C and the time is 4 seconds is gotten as Current = 2.5 Amps

Given Data

Charge = 10 Columbs

Time = 4 seconds

Current = ?

Current, charge and time Relationship

Electrical current is defined by how much electric charge has been transferred per second, giving the following relationship:

Charge = Current*Time

Rearranging this we get:

Current = Charge/Time

The symbol for charge is Q , it is measured in coulombs (C).

The symbol for current is I , it is measured in amperes (A).

The symbol for time is T, it is measured in seconds (s).

Substituting our given Data into the expression we have

Current = 10/4

Current = 2.5 Amps

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Jose’s doctor recommends that he add more cardio to his exercise routine. Which exercise would be the BEST choice?
A.
ballet
B.
jogging
C.
bowling
D.
volleyball


PLEASE NO LINKS OR I WILL REPORT YOU

Answers

Jogging

Explanation:
I learned in PE

Answer:

jogging

Explanation:

Jogging is often defined as running at a pace less than 6 miles per hour (mph), and it has some significant benefits for people who want to improve their health without overdoing it.

Wire coils spinning between two magnets will produce …?



A: cold
B : electricity
C: chemicals
D: Steam

Answers

Answer:

B

Explanation:

I don't know but its b

The answer is B.

Magnetic fields can be used to make electricity
Moving a magnet around a coil of wire, or moving a coil of wire around a magnet, pushes the electrons in the wire and creates an electrical current. Electricity generators essentially convert kinetic energy (the energy of motion) into electrical energy.

Find the volume of this figure.
4 dm
2 dm
3 dm

Answers

Answer:

4×2×3= 24dm^3

.......................

I couldn't answer this question may someone please help me

Answers

Distance (s) =20 m

Initial velocity =0 m/s

g=10 m/s²

By using the formula:

v²= u²+ 2as

v²=0²+ 2×10×15

v²= 300

V= 10root over 3

[tex]10 \sqrt{3} [/tex]

For calculating time,

v= u+ at

10 root over 3 = 0+ 10t

10 root over= 10t

t = 1 root over 3

t = 1.73 s

[tex]1 \sqrt{3} [/tex]

The the stone will hit the ground with a velocity of 10 root over 3 m/s in 1 root over 3 sec.

The reading on a metronome indicates the number of oscillations per minute. What are the frequency and period of the metronome's vibration when the metronome is set at 180?​

Answers

Answer:

Period: 1/3= 0.33 seconds.

The frequency and period of the metronome's vibration when the metronome is set at 180 is 3Hz and 0.33 s.

What is the frequency?

Frequency is the number of oscillations per second.

The time period is the reciprocal of the frequency.

Given is the metronome set at 180.

The reading of metronome = frequency in seconds = 180 / 60 = 3 Hz

The time period of the metronome's vibration T = 1/3 = 0.33 seconds.

Thus, the frequency and the time period is 3Hz and 0.33 s.

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What is the kinetic energy of a 3-kilogram bali that is rolling at 2 meters per second

Answers

6 jules


hope this helps

Answer:

6J

Explanation:

simply apply kinetic energy definitoon:

[tex]k = \frac{1}{2} mv {}^{2} = \frac{1}{2} 3 \times 2 {}^{2} = 6[/tex]

At what tension, in newtons, must the D-string must be stretched in order for it to be properly tuned

Answers

The fundamental frequency, wavelength of the wave, and mass per unit

length of the string, determines the tension in the string.

The tension to which the D-string must be tuned is approximately 19.718 Newtons

Reasons:

From a similar question, we have;

Fundamental frequency, f₁ = 146.8 Hz

Oscillating length on the D-string, λ₁ = 0.61 m

Mass of the string = 1.5 × 10⁻³ kg.

We have;

[tex]\displaystyle f_1 \cdot \lambda _1 =\mathbf{ \sqrt{\frac{T}{m/L} }}[/tex]

Therefore;

[tex]\displaystyle T = \mathbf{\frac{f_1^2 \cdot \lambda _1^2 \cdot m }{L}}[/tex]

Which gives;

[tex]\displaystyle T = \frac{146.8^2 \times 0.61^2 \times 1.5 \times 10^{-3} }{0.61 } \approx \mathbf{19.718}[/tex]

The tension to which the D-string must be tuned, T ≈ 19.718 Newtons

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The parameters given in a similar question obtained online are;

The fundamental frequency of the tone, f₁ = 146.8 Hz

The oscillating length on the D-string, λ₁ = 0.61 m

The mass of the string = 1.5 × 10⁻³ kg.

given. force of 88N and an acceleration of 4 m/s 2 what is the mass?

Answers

Mass, m=22 kg
It is given that Force, F = 88N
Acceleration, a=4 m/s 2

The angular quantities L, omega, and alpha are vectors. The vectors point along the axis of rotation with a direction determined by __________.

Answers

The vectors point along the axis of rotation with a direction determined by an arrow.

What is a vector?

There are two types of physical quantity one is a scaler and another one is a vector.

The quantity that requires only megnitude to define is known as the scalar quantity. While the vector quantities need both megnitude and the direction to define.

The vector quantity is represented by an arrow. The vectors point along the axis of rotation with a direction determined by an arrow.

The angular quantities L, omega, and alpha are vector quantities.

Hence arrow is the correct answer for the blank.

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The direction of the vectors of angular momentum and L, angular velocity omega and the mass alpha is determined using the right hand rule.

What is right hand rule?

Righthand rule in physics states that, when we curl our right hand fingers, the direction of the angular momentum and velocity will be in the direction of thumb and curl of fingers determine the axis of rotation.

Angular momentum is a vector quantity defined as the product of moment of inertia and angular velocity where, the angular velocity ω is the rotational analogue of linear velocity i.e.. product of the linear velocity and radius of rotational path.

Therefore, the angular quantities L, angular velocity ω along the axis of rotation can be determined using the right hand rule. Where direction of thump represents the direction of vector components.

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3.
If the specific heat of iron = 0.46 J/g Cº, how much heat is needed to warm 50 g of
iron from 20° C to 100° C?

Answers

Answer:

1.84 kJ  (kilojoules)

Explanation:

A specific heat of 0.46 J/g Cº means that it takes 0.46 Joules of energy to raise the temperature of 1 gram of iron by 1 Cº.

If we want to heat 50 g of iron from 20° C to 100° C, we can make the following calculation:

Heat = (specific heat)*(mass)*(temp change)

Heat = (0.46 J/g Cº)*(50g)*(100° C -  20° C)

[Note how the units cancel to yield just Joules]

Heat = 1840 Joules, or 1.84 kJ

[Note that the number is positive:  Energy is added to the system.  If we used cold iron to cool 50g of 100° C water, the temperature change would be (Final - Initial) or (20° C - 100° C).  The number is -1.84 kJ:  the negative means heat was removed from the system (the iron).

A truck with a mass of 1500 kg is decelerated at a rate of 5m/s2.how much force did this require ?

Answers

Answer:

6500N

Explanation:

F = ma so therefore Were given mass (m) = 1500 kg, acceleration (a) = 5 m/s2, well have to calculate the force to be:

1500 x 5 = 6500 N

Fill out the material order form with the Quantity (number of each item) and total cost for
that item (Cost Quantity). Add the totals to ensure you do not exceed $100.
YOU HAVE $100 TO SPEND. NO BONUS POINTS FOR SAVING S.
Use the materials carefully, as they will not be replaced if you damage
them.
Material
Cost ($) Quantity
Cost x Quantity
Straw
2
Paperclip (large)
2.
String (12")
3
Tooth pick
3
Cup
5
Rubber band
5
7
Tape (0.5 m)
7
Paper (8.5" x 11")
Tissue Paper
10
Duct Tape
(.25m)
).
10
Cotton ball
12
Balloon
15
Paper plate
15
Total Cost =

Answers

Answer:

Explanation:

Material:                 Cost ($):          Quantity:       Cost x Quantity:

Straw                          2$                    2x                   2$ x 2

Paperclip                   2$                     2x                   2$ x 2

String                          3$                    1x                    3$ x 1

Toothpick                  3$                      1x                   3$ x 1

Cup                            5$                      1x                    5$ x 1

Rubber band              5$                     1x                    5$ x 1

Tape                            7$                    1x                    7$ x 1

Paper                          7$                     1x                    7$ x 1

Tissue Paper             10$                    1x                   10$ x 1

Duct Tape                  10$                    1x                    10$ x 1

Cotton ball                 12$                    1x                     12$ x 1

Balloon                       15$                    1x                    15$ x 1

Paper Plate                15$                     1x                   15$ x 1

                                                                            total:  100$

hope this really helped!!

mark me brainliest :D

Tiny mass of 67kg and tubby mass of 83 kg are now on the opposite ends of a see saw and are both 1.4m from the balance point where should their sister teeny whose mass is 32 kg sit so the see saw balances

Answers

Answer:

0.7 m between the balance point and Tiny

Explanation:

It's intuitive to say she sould be on the side the smaller mass is placed. How far from the balance point?

Let's call x that distance. and assume that the contraption is "oriented" so that being on the side with tiny (and teeny) gives you a positive distance from the balance point, and negative on the other side.

At equilibrium, the sum of all momentums (momenta?) will be zero:

[tex]67\times 1.4 +32\times x + 83 \times (-1.4) = 0\\32x -16(1.4) = 0 \rightarrow 2x=1.4 x= 0.7[/tex]

In layman's term, she has to be halfway between the balance point and Tiny.

2. If Joe rides his bicycle in a straight line for 15 min with an average velocity of 12.5 km/h south, how far has he ridden?

Answers

Answer:

3.125 Kilometers

Explanation:

To answer this you just multiply 12.5 by .25 (since 15 minutes is a quarter of an hour) to get 3.125 kilometers ridden.

What kind of force could cause this ball to not be at rest anymore, or cause it to move?

Answers

Answer:

friction

Explanation

Answer:

Friction

Explanation:

What force prevents an object at rest?

Sliding Friction While static friction keeps an object at rest, sliding friction slows down an object that slides. If you push an object across a room, you notice the sliding friction between the bottom of the object and the floor. You have to keep pushing to overcome the force of sliding friction.

if you have 3 moles of iron, how many grams of iron do you have?

Answers

Answer:

55.84 look at periodic table

so 55.84*3= 167.52gFe

How much force is required to move a tractor 60m, when using 250J of work?

Answers

Answer:

Work done,W= 250J

Displacement , s = 60

We know that, Work done = Force x displacement

i.e , W = Fxs

250 J = F x 60m

F = 250/60

=4.16 N

Hence , 4.16 N of Force is applied on the body.

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

A mass of 5.00 kg in a gravitational field of 7.00 n/kg. What force acts on the mass?

Answers

Answer:

35N

Explanation:

force=mass×gravity

the mass is 5 and the gravity is 7 therefore:

force=7×5

=35N

I hope this helps

Which of toby's answers is a correct description of what happens when a 1-kg cart traveling at 1 m/s collides inelastically with another 1-kg cart at rest?.

Answers

Answer:

hi I don't know sorry sorry forgive me

Explanation:

sorry

Can Hotspots can be found at the edges of tectonic plates?

Answers

Answer:

No.

Explanation:

Hot spots don't appear at the barriers of tectonic plates, instead, they originate at hot centres known as mantle plumes. Mantle plumes exist below the tectonic plates and may develop a string of volcanoes on the Earths surface.

Give an example of when a conscientious objector might exercise their right:

Answers

Am sorry what can you be more specific

What is the relationship between momentum and kinetic energy.

Answers

Answer:

constant object, momentum increases directly with speed

Explanation:

whereas kinetic energy increases the square of the velocity due to energy momentum

Describe the steps in solving the problem below.
A red cart of mass 4 kg slides to the right on a frictionless track with a velocity of +4 m/s. It collides with the stationary blue cart of mass 1 kg. After the collision, the blue cart has a velocity of +8 m/s. Calculate the velocity of the red cart after the collision. ;)


Answers

The velocity of the red cart after the collision is 2 m/s

From the law of conservation of momentum, initial momentum of system = final momentum of system.

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄ where m₁ = mass of red cart = 4 kg, v₁ = velocity of red cart before collision = + 4 m/s, v₃ = velocity of red cart after collision, m₂ = mass of blue cart = 1 kg, v₂ = velocity of blue cart before collision = 0 m/s (since it is initially at rest) and v₄ = velocity of blue cart after collision = + 8 m/s.

Substituting the values of the variables into the equation, we have,

m₁v₁ + m₂v₂ = m₁v₃ + m₂v₄

4 kg × 4 m/s + 1 kg × 0 m/s = 4v₃ + 1 kg × 8 m/s

16 kgm/s + 0 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s =  4v₃ + 8 kgm/s

16 kgm/s - 8 kgm/s =  (4 kg)v₃

(4 kg)v₃ = 8 kgm/s

Divide both sides by 4 kg, we have

v₃ = 8 kgm/s ÷ 4 kg

v₃ = 2 m/s

The velocity of the red cart after the collision is 2 m/s.

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Global warming means that

Answers

Answer:

The earth is heating up.

Explanation:

This is due to human activities, primarily fossil fuel burning, which increases heat-trapping greenhouse gas levels in Earth's atmosphere.

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