A boat travels 12km in 10mins, and 15km in the next 10mins. Is the boat traveling at a constant speed?

Officer who studied the effects of extreme deceleration on the human body, his acceleration is 5.76g and his deceleration is 20.56 g.

In the world of wisdom, acceleration and deceleration are two of the most crucial concepts. Any object's rate of change in speed is referred to as its acceleration, and a negative acceleration value is referred to as deceleration.

In this situation, it is more important to speed up than to slow down, especially when sprinting a short distance, where the speed needs to be increased constantly.

Acceleration is used in a variety of creative ways every day. Robotic acceleration, which is accelerated at a specific time, is used to identify acceleration.

a)  acceleration    

[tex]a =(v-u)/t\\u=initial velocity =0\\\\v=final velocity =282m/s\\\\t=time=5sec\\a=(282-0)/5\\=56.4m/s2\\=56.4/9.8\\=5.76[/tex]

a=5.76g/s2=acceleration

His acceleration = 5.76g

b) Deceleration  

[tex]r=(u-v)/t\\u=282m/s\\v=0\\t=1.4sec\\r=(282-0)/1.4\\=201.43m/s2\\=201.43/9.8\\=20.55[/tex]

r=20.55g = (magnitude )

His deceleration is 20.56 g

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Answer:Cold fusion: A case study for scientific behavior ... Scientists take into account all the available evidence when deciding whether to accept an idea or not ...

Explanation:

The statement "In fair weather there is an electric field at the surface of the earth, pointing down into the ground" is a TRUE statement.

Electric field is a region in a particular space that induces forces on charged particles. The induced force that the particles experience will cause them to undergo motion, either parallel or antiparallel to the field direction depending on the sign of the charge.

A positive charge will cause the particles to move parallel to the field, while a negative charge will cause the particles to move anti-parallel to the field. In case of area with fair weather, the electric field is directed vertically downward to the earth.

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At t = 10.0 s, the rocket is 135 m above the surface of the earth.

In physics, acceleration is the rate at which the velocity of an object changes in relation to time. According to Newton's Second Law, the sum of all forces acting on an item results in its acceleration. Meter per second squared (m s2) is the unit of acceleration used in the SI system.

We can utilise the equations of motion with constant acceleration to resolve this issue. The formula we require is:

[tex]y = yo + vot + 1/2at^2[/tex]

where:

y is the final position of the rocket above the surface of the earth

yo is the initial position, which is 0 m

vo is the initial velocity, which is 0 m/s

a is the acceleration of the rocket, which is given by ay = [tex](2.70 m/s^3)t[/tex]

t is the time elapsed, which is 10.0 s

Plugging in the values, we get:

[tex]y = 0 + 0(10.0) + 1/2(2.70)(10.0)^2[/tex]

y = 135 m

[tex]v^2 = vo^2 + 2a(y - yo)[/tex]

where:

v is the final velocity of the rocket

vo is the initial velocity, which is 0 m/s

(B) A is the acceleration of the rocket, which is given by ay =[tex](2.70 m/s^3)t[/tex]

y is the final position of the rocket, which is 275 m

yo is the initial position, which is 0 m

Plugging in the values, we get:

[tex]v^2 = 0^2 + 2(2.70)(275 - 0)[/tex]

[tex]v^2 = 1485v = sqrt(1485)v = 38.5 m/s[/tex]

The speed of the rocket when it is 275 m above the surface of the earth is 38.5 m/s.

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1. The sound intensity level will the rescue (that searching for Andrew, a geologist who was stranded while conducting research in the mountains of Colorado) team measure from the frightened researcher = 2.82 x 10–⁶ W/m²

2. The bulk modulus B of air = 1.46 x 10⁵ Pa

The energy of the wave between the order per unit area of the same is what determines how loud a sound is. The energy is computed by integrating the mechanical energy over a period, where's' is the sound wave's amplitude and the mass is affected by density.

The intensity of the wave:

I = 2 π² f²A²v ρ

= 2 π² (450)² (4.00 x 10–⁸)² (332) (1.33)

= 2.82 x 10–⁶

The bulk modulus:

B = v²ρ

= (332)² (1.33)

= 1.46 x 10⁵ Pa

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The enthalpy h of a thermodynamic system with pressure p, volume v , and internal energy e is defined by h is True.

Enthalpy, the sum of the internal energy and the product of the pressure and volume of a thermodynamic system. Enthalpy is an energy- suchlike property or state function — it has the confines of energy( and is therefore measured in units of joules or ergs), and its value is determined entirely by the temperature, pressure, and composition of the system.

Enthalpy, denoted by the symbol H, is the sum of the internal energy, denoted by E, and the product of the pressure and volume, denoted by PV.

H = E + PV

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The required electric field for x > 0 is 2.0 x 10^3 V/cm.

Given:

Total current density, J = 10 A/cm²

Hole concentration, p = 10¹⁶ cm⁻³

Electron concentration, n(x) = 2x10¹⁵x cm⁻³, where L = 15 μm, and x > 0

Electron diffusion coefficient, Dₙ = 27 cm²/s

Hole mobility, μₚ = 420 cm²/Vs

To calculate:

(a) Electron diffusion current density for x > 0

(b) Hole drift current density for x > 0

(c) Electric field for x > 0

Solution:

(a) The electron diffusion current density can be calculated using the equation:

Jn = -qDn(dn/dx)

where q is the electronic charge, and dn/dx is the gradient of the electron concentration profile.

q = 1.6x10⁻¹⁹ C (electronic charge) (electronic charge)

Dn/Dx = 2 x 1015 cm4 (gradient of electron concentration)

If we apply these values, we obtain:

Jn = -(1.6x1019 C) (27 cm2/s) (2x1015 cm4) = -8.64 A/cm2.

The electron diffusion current is said to be flowing in the opposite direction from the direction of the total current density when it has a negative sign.

(b) The equation: Jp = qppE, where E is the electric field and pp is the hole concentration, can be used to calculate the hole drift current density.

pp = 10¹⁶ cm⁻³ (constant hole concentration) (constant hole concentration)

The values of Jn and pp, along with the formula J = Jn + Jp, allow us to calculate Jp:

Jp = Jn = 10 A/cm2 - (-8.64 A/cm2) = 18.64 A/cm2, where

This value, q, and pp are all substituted into the equation for Jp to produce the following result:

Jp equals (1.6x1019 C)(420 cm2/Vs)(1016 cm3).

E = 18.64 A/cm²

Solving for E, we get:

E = Jp/(qμpp) = (18.64 A/cm²)/[(1.6x10⁻¹⁹ C)(420 cm²/Vs)(10¹⁶ cm⁻³)] = 0.28 V/cm

(c) The electric field required for x > 0 is 0.28 V/cm.

Therefore, the electron diffusion current density is -8.64 A/cm², the hole drift current density is 18.64 A/cm², and the required electric field is 0.28 V/cm for x > 0.

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The electrical potential energy of the system at a separation of 6 meters is greater than the electrical potential energy of the system at a separation of 12 meters.

The electrical potential energy of the system at a separation of 6 meters is greater than the electrical potential energy of the system at a separation of 12 meters. This is because electrical potential energy is inversely proportional to the separation distance between the charges. As the separation distance decreases, the electrical potential energy increases. This relationship can be represented by the equation:

U = kq1q2/r

where U is the electrical potential energy, k is a constant, q1 and q2 are the charges, and r is the separation distance. As r decreases, U increases.

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At sunset, the Moon will be in the western horizon and its believers will point their arms towards the west.

During the first quarter, its believers will point their arms towards the southwest.

During the full moon, its believers will point their arms towards the east.

During the third quarter phase, its believers will point their arms towards the northwest.

During the new moon phase, the Moon is located between the Sun and the Earth, so it rises and sets at approximately the same time as the Sun. Therefore, at sunset, the Moon will be in the western horizon and its believers will point their arms towards the west.

During the first quarter phase, the Moon is located at a right angle to the Earth and the Sun. It rises at around noon and sets at around midnight. Therefore, at sunset, the Moon will be located in the southern horizon, and its believers will point their arms towards the southwest.

During the full moon phase, the Moon is on the opposite side of the Earth from the Sun, so it rises as the Sun sets and sets as the Sun rises. Therefore, at sunset, the Moon will be located in the eastern horizon, and its believers will point their arms towards the east.

During the third quarter phase, the Moon is also located at a right angle to the Earth and the Sun, but on the opposite side of the first quarter. It rises at around midnight and sets at around noon. Therefore, at sunset, the Moon will be located in the northern horizon, and its believers will point their arms towards the northwest.

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To determine the tension developed in cable ABC required for the equilibrium of the 143-kg sack, we need to consider the forces acting on the sack and apply the principle of equilibrium.

First, let's draw a free-body diagram of the forces acting on the sack:

where T is the tension in cable ABC.

The weight of the sack (W) is given by:

W = m*g

where m is the mass of the sack and g is the acceleration due to gravity (9.8 m/s^2).

W = 143 kg * 9.8 m/s^2 = 1397.4 N

Since the sack is in equilibrium, the sum of the forces acting on it in the vertical direction must be zero:

T - W = 0

T = W = 1397.4 N

Therefore, the tension developed in cable ABC required for the equilibrium of the 143-kg sack is 1397.4 N.

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A machine that increases force, force direction, and speed, as well as an illustration of each. A bicycle increases speed, an ax changes direction of force, and a car jack increases force.

Machine that increases speed, a machine that increases direction of force, and a machine that increases force. A bicycle increases speed, an ax changes direction of force, and a car jack increases force. contrast the scientific definition of work with it's everyday meaning.

Speed powder may have traces of pink or grey and can range in color from white to brown. It tastes harsh and has a pungent aroma. Also available in pill form.

Therefore, A machine that increases force, force direction, and speed, as well as an illustration of each.  A bicycle increases speed, an ax changes direction of force, and a car jack increases force.

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The total thermal resistance of the wall can be found by summing the thermal resistances of each section:

= 4.277 m^2.K/W

To determine the rate of heat transfer through the wall, we can use Fourier's law of heat conduction which states that the rate of heat transfer through a material is proportional to the temperature gradient across the material, and can be expressed as:

q = -kA * dT/dx

where q is the rate of heat transfer, kA is the thermal conductivity of the material, dT/dx is the temperature gradient, and the negative sign indicates that heat flows from higher temperatures to lower temperatures.

(a) To find the rate of heat transfer through the wall, we need to first determine the thermal resistance of each section of the wall. The thermal resistance is given by:

R = L / k

where R is the thermal resistance, L is the length of the material, and k is the thermal conductivity.

Using this equation, we can find the thermal resistance of each section as follows:

[tex]R_A = 5 / 2 = 2.5 m^2.K/W[/tex]

[tex]R_B = 0.22 / 35 = 0.0063 m^2.K/W[/tex]

[tex]R_C = 5 / 20 = 0.25 m^2.K/W[/tex]

[tex]R_D = 0.22 / 15 = 0.0147 m^2.K/W[/tex]

[tex]R_E = 0.22 / 35 = 0.0063 m^2.K/W[/tex]

[tex]R_F = 3 / 2 = 1.5 m^2.K/W[/tex]

(b) To find the temperature at the point where sections B, D, and E meet, we can assume that there is no heat generation within the wall (i.e., steady-state conditions), so the temperature at any point within the wall is the same in the x-direction. Therefore, we can use the thermal resistance network to find the temperature drop across each section:

ΔT_A = (300 - 100) = 200°C

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The sum of squares of error, treatment, within and between four painters are: 330, 692, 110 and 43.25.

The data provided is for the dying time of four different types of paint.

One-way ANOVA can be used to determine whether all the four paints have the same drying time.

Use Excel to perform the one-way ANOVA.

Go to Data → Data Analysis → Anova: Single Factor

A dialog box will open. Select the data. Select "Grouping" as Columns.

Press OK.

The output is attached below.

The required values are as follows:

(1) Sum of Squares of Treatment (Between Subjects):

SST = 330

(2) Sum of Squares of Error (Within Subjects):

SSE = 692

(3) Mean Squares Treatment (Between Subjects):

MST = 110

(4) Mean Squares Error (Within Subjects):

MSE = 43.25

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--The complete question is, Four different paints are advertised as having the same drying time. To check the manufacturers' claims, five samples were tested for each of the paints. The time in minutes until the paint was dry enough for a second coat to be applied was recorded for each sample. The data obtained follow. Excel File: data 16-21.xls Paint 1 Paint 2 Paint 3 Paint 4 128 137 135 133 144 133 142 146 130 143 137 124 136 141 131a. Use a = .05 to test for any significant differences in mean drying time among the paints. If an amount is zero, enter "0. Test to see whether the mean drying time is the same for each type of paint.--

One degree of longitude at the equator is 111.32 kilometers (69.17 miles), one minute of longitude is 1.855 kilometers (1.153 miles), and one second of longitude is 0.031 kilometers (0.019 miles).

At the equator, one degree of longitude corresponds to 1/360th of the circumference of the Earth, which can be calculated as:

C = 2*π*r where C is the circumference, r is the radius of the Earth.

The radius of the Earth is half of its diameter, so:

r = 12,756 km / 2 = 6,378 km

Thus, the circumference of the Earth at the equator is:

C = 2*π*(6,378 km) ≈ 40,075 km

So, one degree of longitude at the equator is:

40,075 km / 360 ≈ 111.32 km

Or in miles:

24,901 miles / 360 ≈ 69.17 miles

To find the distance in one minute of longitude, we need to divide by 60:

111.32 km / 60 ≈ 1.855 km/min

69.17 miles / 60 ≈ 1.153 miles/min

To find the distance in one second of longitude, we need to divide by 60 again:

1.855 km/min / 60 ≈ 0.031 km/sec

1.153 miles/min / 60 ≈ 0.019 miles/sec

Therefore, one degree of longitude at the equator corresponds to approximately 111.32 kilometers (69.17 miles), one minute of longitude corresponds to approximately 1.855 kilometers (1.153 miles), and one second of longitude corresponds to approximately 0.031 kilometers (0.019 miles).

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When a hummingbird is flying and feeding, it gains a significant electric charge. When a charged bird approached a flower, the stamens of the flower (the part that produces pollen) bent toward the bird because it got polarized. This electrostatic charge is useful for a flower's reproduction process. Charged pollen can settle more effectively.

Attached below is the figure with the full question.

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The correct option this question is option B. Flat wave obtained by superposition of two waves. The energy is transformed into the kinetic energy of the string except of the nodes.

The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity. The body keeps the kinetic energy it acquired throughout its acceleration unless its speed changes.

Kinetic energy has the following formula: K.E. = 1/2 m v2, where m is the object's mass and v is its square velocity. The kinetic energy is measured in kilograms-meters squared per second squared if the mass is measured in kilograms and the velocity is measured in meters per second.

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The magnitude of normal force that floor exerts on chair is 120.24 N. the magnitude of the frictional force acting on the chair is 123.24 N

Simply put, "distance or quantity" is the definition of size. In terms of motion, it shows the absolute or relative size, direction, or movement of an object. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.

Vertical component of the force = F sinθ

                                                    = 38X sin42°

                                                    = 38 X 0.669

                                                    = 25.42N

Total normal force acting on the chair = weight +Vertical component force

Total normal force acting on the chair = 95N + 25.42N

                                                          = 120.24 N

horizontal component of force= f cosθ.

                                               = 38X cos 42°

                                               = 38 X 0.743

                                              = 28.24 N

Total normal frictional force on the chair

frictional force = weight+ horizontal component of force

frictional force= 95N + 28.24 N

frictional force= 123.24 N

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The angle the car will have traveled when the magnitude of its total acceleration is 2.6 m/s2 is approximately 33.0°.

This can be found using the equation a=v2/r, where a is the magnitude of the total acceleration, v is the tangential velocity, and r is the radius of the curve.

Rearranging this equation to solve for theta (θ), we get θ = (v2/a) x (180/π). Plugging in the given values for a, v, and r, we get θ = (1.4^2/2.6) x (180/π) ≈ 33.0°.

Acceleration is the rate of change of velocity measured in meters per second (m/s) squared. It is the rate at which an object's speed and direction of motion change over time. Acceleration can be caused by a variety of forces, such as gravity, friction, or a push or pull. It can also be caused by changes in speed or direction, such as when an object is speeding up or slowing down.

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The magnitude of the vertical force F is 882.4 N. Use equilibrium equations of force in direction of y.

To determine the magnitude of the vertical force F, we can use the equilibrium equations of the forces in the y direction.

Summing the forces in the y direction:

[tex]Fsin(60°) - 916 N - 150 N = 0[/tex]

where the 150 N is the weight of the beam CD.

Solving for F, we get:

[tex]Fsin(60°) = 766 N[/tex]

F = 882.4 N

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The right response is that identical twins have stronger correlations than fraternal twins do.

If there are several pizza truck in the region, each with its own distinctive jingle, we would learn them all by heart and associate each one with a certain pizza truck. Establishing a connection between two variables, in this case "jingle" and "distance of the truck" in this example, is exactly what correlational research involves.

A nonexperimental research method known as correlational analysis measures two variables and evaluates the statistical relationship (also known as the correlation) among them with little to no effort to control unrelated variables.

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In prefigurative cultures, young people learn primarily from the elders, and peer influence is relatively low. The culture remains stable and resistant to change.  

In postfigurative cultures, young people learn primarily from their peers, and the influence of elders is relatively low. These cultures are more susceptible to change and are often associated with technological advances, globalization, and other social changes.

A postfigurative culture is one in which the older generation teaches the younger generation information and morals. Slow societal change, learning from elders' experiences, and the transmission of cultural values and customs from one generation to the next are characteristics of this sort of culture. Postfigurative societies place a high value on family honoraria and ancestor reverence (sometimes known as "ancestor worship"). Anthropologist Margaret Mead initially used the word "postfigurative" to characterize civilizations that placed a high priority on tradition and the passing of knowledge from older to younger generations in the 1960s. Prefigurative cultures, on the other hand, emphasize the wisdom and experience of the younger generation and go through fast social transformation.

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The required total charge on a spherical shell whose volume density is specified is calculated to be 1.31 × 10⁻⁹ C.

Using the formula, one can get the total charge.

Total charge = Volume density × Volume of sphere

The charge is said to be distributed uniformly throughout the shell with the volume density 6.1 × 10⁻⁴ C/m³.

The inner radius of the spherical shell is given as 3.7 cm = 3.7 × 10⁻² m.

The outer radius of the spherical shell is given as 4.5 cm = 4.5 × 10⁻² m.

Volume of the sphere is calculated as,

V = 4π/3(outer radius - inner radius)³ = 4π/3 (4.5 × 10⁻² - 3.7 × 10⁻²)³ =  4π/3 (0.8 × 10⁻²)³ = 4π/3 × (0.512 × 10⁻⁶) = 2.14 × 10⁻⁶ m³

So, the total charge can be given as,

⇒ 6.1 × 10⁻⁴ - 2.14 × 10⁻⁶ = 1.31 × 10⁻⁹ C.

Thus, the total charge is calculated to be 1.31 × 10⁻⁹ C.

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Ranking of the bulbs based on their brightness are C - A - B - D - E.

Bulb A and B are connected in parallel. Bulb D and E are connected in series and the bulb DE is parallel with bulb C. Resistance of each bulb is remain constant.

Bulb D and E are connected in the series so power dissipated in the D and E are same. Bulb C is in parallel with bulb DE. 2/3 of current pass through bulb C and 1/3 of current pass through bulb DE.

Bulb C has brightest than A and B which are equal and D and E are dimmest

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Answer:

75 J

Explanation:

A projectile will follow a perfectly parabolic path when there is no air resistance because of gravity:

In kinematics, the term "acceleration of a particle" is used to describe the rate at which velocity changes in a given direction and over a given time. When a particle moves vertically, it is sometimes referred to as gravity-induced acceleration.

The acceleration caused by gravity always operates downward in a parabolic path when there is no air resistance, and the velocity vector always acts perpendicular to the path.

At the topmost point, when the acceleration acts downward and the velocity is tangent to the path, it will automatically act in a perpendicular direction to the acceleration, as mentioned in section A concerning the path of the acceleration and the velocity.

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To find the vector components of a vector with respect to two orthogonal vectors, we can use the projection formula. Let's first find the projection of  on the vector :

proj  = (( · ) / ( · ))

= ((-9)(-6) + (-1)(2)) / ((-9)^2 + (-1)^2)

= -56/82

= -28/41

Now, let's find the vector  in the direction of :

in  = proj  = (-28/41)  

To find  perpendicular to , we can subtract  from :

⊥  =  - in  

⊥  =  [6/41, -28/41]

Therefore, we can write  as the sum of two orthogonal vectors:

=  in  + ⊥  

= [-9, -1]

= [-9*(-28/41) , -1*(-28/41)] + [6/41, -28/41]

= [252/41, -28/41] + [6/41, -28/41]

= [258/41, -56/41]

Thus, we have decomposed into two orthogonal vectors,  in  the direction of  and ⊥ perpendicular to.

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Positive anomalies result when the crust is magnetised in a normal polarity parallel to the ambient field of Earth, and negative anomalies result when the crust is reversely magnetised in an opposite sense.

A positive magnetic anomaly is a reading that exceeds the average magnetic field strength and is usually related to more strongly magnetic rocks, such as mafic rocks or magnetite‐bearing rocks, underneath the magnetometer. A value that is lower than the typical magnetic field is referred to as a negative magnetic anomaly.

These anomalies are classified as negative or magnetic lows if their strength is below normal and positive or magnetic highs if it is above normal. These anomalies are typically caused by variations in magnetic susceptibility, which in turn mostly reflect the rocks' magnetite content.

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The true statements about the periodic review model are:

b. in a periodic review model, the quantity ordered in each review varies

d. it establishes a fixed or interval

A periodic review system allows you to determine the quantity of items you have in stock at specified regular intervals, such as every Friday or the last day of the month. Similar to the Minimax system, we order the quantity (Q) that is the target stock (TI) minus the quantity on hand (OH).

The difference is that in a periodic review system, the time between orders is constant (hourly, daily, weekly, monthly, etc.) and the order quantity varies. A min-max system varies both the time between orders and the order quantity.

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Solution of the question with the information which is given is:

Ignoring wind resistance and using 32ft/sec/sec as acceleration due to gravity.

d= 16 t2

t2= 365/ 15

t= 4.8 seconds

Therefore the hit impact was about 4.8 seconds

In Newtonian physics, free fall is any motion of a body where gravity is the only force acting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.

According to Newton's second law of motion, force (F) = mass (m) times acceleration, an item in free fall will move with an acceleration (a). We can use a little mathematics to determine the object's acceleration in terms of the net external force and the object's mass (a = F / m).

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Answer:

kekekekekhshshehshehdhdhdhdhdhdhdhdh

To solve this problem, we can use the law of conservation of momentum, which states that the total momentum of a system is conserved in the absence of external forces. In this case, the system consists of the arrow and the object.

Before the collision, the arrow has a momentum of:

p1 = m1v1 = (0.07 kg)(90 m/s) = 6.3 kg m/s; where m1 is the mass of the arrow and v1 is its velocity.

Since the object is initially at rest, its momentum is zero:

p2 = m2v2 = (m)(0) = 0; where m2 is the mass of the object and v2 is its velocity.

After the collision, the arrow and the object move together with a common velocity v. The total momentum of the system after the collision is:

p3 = (m1 + m2)v

Using the law of conservation of momentum, we can equate the initial and final momenta:

p1 + p2 = p3

Solving for v, we get:

v = p1/(m1 + m2) = (6.3 kg m/s)/(0.07 kg + m)

To determine the resulting velocity of the object, we need to solve for v. One way to do this is to use the law of conservation of energy, which states that the total energy of a system is conserved in the absence of external forces.

The initial kinetic energy of the system is: KE1 = (1/2)m1v1^2 = (1/2)(0.07 kg)(90 m/s)^2 = 283.5 J; where KE1 is the initial kinetic energy of the arrow.

The final kinetic energy of the system is:

KE2 = (1/2)(m1 + m2)v^2

Using the law of conservation of energy, we can equate the initial and final kinetic energies:

KE1 = KE2

Solving for v, we get:

v = sqrt(2KE1/(m1 + m2)) = sqrt(2283.5 J/(0.07 kg + m))

To determine whether the collision is elastic or inelastic, we can compare the system's initial and final kinetic energies. If the kinetic energy is conserved, then the collision is elastic. If the kinetic energy is not conserved, then the collision is inelastic.

The initial kinetic energy of the system is 283.5 J. The final kinetic energy of the system is:

KE2 = (1/2)(m1 + m2)v^2

Substituting the value of v we obtained earlier, we get:

KE2 = (1/2)(0.07 kg + m)(6.3 kg m/s)^2/(0.07 kg + m)

To determine whether the collision is elastic or inelastic, we must compare KE1 and KE2. Since the object's mass is unknown, we cannot make a definitive conclusion about the nature of the collision. However, we can provide some evidence to support our answer.

If the collision is elastic, then KE2 should be equal to KE1. However, if we substitute v = 90 m/s into the expression for KE2, we get: KE2 = (1/2)(0.07 kg + m)(90 m/s)^2/(0.07 kg + m) = 4050 J. This value is greater than KE1, which indicates that the collision is not elastic. Therefore, we can conclude that the collision is inelastic.

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