A box at rest is in a state of equilibrium half way up on a ramp. The ramp has an incline of 42° . What is the force of static friction acting on the box if box has a gravitational force of 112.1 N ?

70 N
80 N
75 N
85 N

Answers

Answer 1

Answer:

75 N

Explanation:

Given that,

The angle of incline of the ramp is 42°.

The gravitational force of the box, W = 112.1 N

We need to find the force of static friction on the box.

We have that the component of the gravitational force acting along the inclined plane i.e.

[tex]F=W\sin\theta\\\\F=112.1\times \sin(42)\\\\F=75\ N[/tex]

So, the force of static friction is equal to 75 N.


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A capacitor is an electronic component that stores and releases electricity in a circuit.

Un campo magn´etico uniforme B, con magnitud 1.2 mT, apunta verticalmente hacia arriba a lo largo del volumen del sal´on en que usted est´a sentado. Un prot´on de 5.3 MeV se mueve horizontalmente de sur a norte a trav´es de cierto punto en el salon. ¿Qu´e fuerza magn´etica deflectora act´ua sobre el prot´on cuando pasa por este punto? Cu´al es su aceleraci´on, la masa del prot´on es de 1.67x10−27 kg. Resp. 6.1x10−15 N; 3.7x1012 m/s2.

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Answer:

F = 6.12 10⁻¹⁵ N,    a = 3.66 10¹² m / s²

Explanation:

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as they indicate that the magnetic field is vertical the proton moves horizontally the angle is 90º

suppose that the energy of the proton is totally kinetic

        E = 5.3 MeV (10⁶ 1.6 10⁻¹⁹J / 1 eV) = 8.48 10⁻¹³ J

       E = K = ½ m v²

       v = [tex]\sqrt{2E/m}[/tex][tex]\sqrt{2 \ 8.48 \ 10^{-13} / 1.67 \ 10^{-27}}[/tex]

       v = [tex]\sqrt{2 \ 8.48 \ 10^{-13} / 1.67 \ 10^{-27}}[/tex]

       v = [tex]\sqrt{10.155 \ 10^{14}}[/tex]

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        F = 1.6 10⁻¹⁹  3.19 10⁷  1.2 10⁻³

        F = 6.12 10⁻¹⁵ N

       

The direction of this out is given by the right hand rule,

thumb in the direction of speed, south to north

fingers extended in the direction of the magnetic field, vertical

the probe points in the direction of the force for a positive charge,  East

To calculate the acceleration we use Newton's second law

        F = ma

        a = F / m

        a = 6.12 10⁻¹⁵ / 1.67 10⁻²⁷

        a = 3.66 10¹² m / s²

the direction of the acceleration is the same as the direction of the force

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Explanation:

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Answer:

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