Solving for the circumference and using the formula for the circumference we got the radius as 74.95 feet
Mensuration of Flat ShapesGiven Data
1/4 of the circumference = 117.75 feet.
Let the circumference be x feet
1/4*x = 117.75
x/4 = 117.75
cross multiplying
x = 4*117.75
x = 471 feets
The expression for the circumference is given as
C = 2πr
471 = 2πr
Making r subject of formula we have
r = = 471/2*3.142
r = 471/6.284
r = 74.95 feet
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What is the greatest possible integer solution of the inequality 3.829x < 28.195?
Answer:
7
Step-by-step explanation:
..............,.,.,.,.,.,..,.
Answer:
B) 18
Step-by-step explanation:
Perimeter = 2 + 2 + 1 + 2 + 1 + 2 + 1 + 4 + 1 + 2
= 4 + 3 + 3 + 5 + 3
= 7 + 8 + 3
= 10 + 8
= 18
The correct option is (B) 18
Answer:
18, option B
Step-by-step explanation:
Draw a hashmark like I have done in my drawing for each side exposed to the white.
Then count up all those hashmarks and voila, you have your answer!
For the function f(x) = 6x + 9, find the value of x.so that f(x) = 3.
In a race, a bicyclist travels 3 miles in 1/4 hour. Determine the unit rate for the speed
in miles per hour.
3/4 miles per hour
16 miles per hour
11/4 miles per hour
12 miles per hour
Step-by-step explanation:
the standard measure for speed is
miles per hour.
now we got as measurement
3 miles per 1/4 hour.
to give the standard speed or "unit rate" we assume that the bicyclist maintains the same speed for a whole hour.
and the question is : how many miles is he traveling then in that 1 hour ?
to answer this we have to check how often the actually measured unit of time fits into 1 hour.
1/4 hour fits 4 times into 1 hour.
and that factor applies now also to the miles to keep the value of the rate or ratio unchanged :
miles/time × a/a = miles×a/(time×a)
so that (time×a) = 1 hour
and so, he traveled 3×4 = 12 miles per hour.
Does this image show an enlargement or a reduction?
17
Enter your answer in the first Blank
A
What scale factor was usada
Answer:
the image shows reduction
Step-by-step explanation:
the scale chosen is 1.7
plz answer fast
Which of the following expressions demonstrates the distributive property?
3 + 4 + 5 = 4 + 3 + 5
-2(5 + 7) = -2(7 + 5)
3(-8 + 1) = 3(-8) + 3(1)
6[(7)(-2)] = [(6)(7)](-2)
Answer:
3(-8+1) = 3(-8)+3(1)
Step-by-step explanation:
you multiply the value(s) in front of the parentheses to the values in them.
Answer:
3(-8+1) = 3(-8)+3(1)
Step-by-step explanation:
HOPETHISHOPES!!
A number has the digits 6, 8, and 2. To the nearest hundred, the number rounds to 900.
What is the number?
Answer:
862
Step-by-step explanation:
What is the relationship between the lines with the following equations? 6x+4y=−12 y=−3/2x−5 The lines are perpendicular. The lines are the same. The lines are neither parallel nor perpendicular. The lines are parallel.
Answer:
I think the answer is "The lines are parallel."
Step-by-step explanation:
Chris made $136 for 8 hours of work.
At the same rate, how many hours would he have to work to make $289?
Answer:
17 hours
Step-by-step explanation:
$136/8hr = $17 dollars an hour
$17/hr=$289/t
$17/hr t=$289
t=17 hours
Answer:
17 hours
Step-by-step explanation:
136 divided by 8 is 17, that is his hourly wages. Divide 289 by 17 = 17 hours
Which Judicial branch make the laws
Answer:The legislative branch
Step-by-step explanation:
Find the substitution 2x+3y=-5 and y=-x+5
Answer: x = 20, y = -15
Step-by-step explanation:
Since we already know that [tex]y=-x+5[/tex], we can just substitute in that value of y into the other equation:
[tex]2x+3y=-5\\2x+3(-x+5)=-5\\2x-3x+15=-5\\-x=-5-15\\-x=-20\\x=20[/tex]
with the value of x, we can find the value of y:
[tex]y=-x+5=-20+5=-15[/tex]
si el anteayer del pasado mañana de mañana del ayer del mañana de hace 2 dias es el pasado mañana del mañana del mañana del anteayer del mañana del lunes ¿que dia es el mañana del pasado mañana de ayer de ayer?
Si el día es jueves, entonces el mañana del pasado mañana de ayer de ayer es martes.
Definición del día mediante equivalencia aritméticaSea el día actual (lunes) el día 0, el día anterior tiene equivalencia de -1 y el día posterior tiene equivalencia de +1. A continuación, traducimos matemáticamente la expresión:
Si el anteayer (-2) del pasado mañana (+2) de mañana (+1) del ayer(-1) el mañana (+1) de hace 2 días (-2) es el pasado mañana (+2) del mañana (+1) del mañana (+1) del anteayer (-2) del mañana (+1) del lunes (0). ¿qué día es el mañana (+1) del pasado mañana (+2) de ayer (-1) de ayer (-1)?
SimplificaciónSi (-1) es (+3). ¿Qué día es (+1)?
Si el día es jueves, entonces el mañana del pasado mañana de ayer de ayer es martes.
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A. Differentiate the following functions using product rule and quotient rule.
B. Differentiate the following using Chain Rule.
The following results by product rule and quotient rule are listed below:
[tex]f'(x) = 3\cdot x^{2}-15\cdot x - 9[/tex][tex]f'(x) = \frac{15}{2} \cdot x^{4}-6\cdot x^{3}+\frac{45}{2}\cdot x^{2}-\frac{81}{2} \cdot x +13[/tex][tex]f'(x) = \frac{90\cdot x^{2}-45\cdot x^{2}-40\cdot x +72}{25\cdot x^{4}-80\cdot x^{2}+64}[/tex][tex]f'(x) = \frac{\left(9\cdot x^{2}-18\cdot x-6\right)\cdot \left(\frac{x^{2}}{2}+7\cdot x-8 \right)-\left(3\cdot x^{3}-9\cdot x^{2}-6\cdot x +1 \right)\cdot \left(\frac{2}{3}\cdot x+7 \right)}{\left(\frac{x^{2}}{2}+7\cdot x-8 \right)^{2}}[/tex]
The following results by chain rule are listed below:
[tex]f'(x) = 3\cdot (2\cdot x^{2}-2\cdot x +1)^{2}\cdot (4\cdot x-2)[/tex][tex]f'(x) = \frac{15\cdot x^{2}-16\cdot x+9}{2\cdot \sqrt{5\cdot x^{3}-8\cdot x^{2}+9\cdot x-6}}[/tex][tex]f'(x) = \frac{2\cdot \left(6\cdot x-\frac{2}{3}-4\cdot x^{-5} \right)}{3\cdot \sqrt[3]{3\cdot x^{2}-\frac{2}{3}\cdot x +x^{-4} } }[/tex]How to apply product rule and quotient rule to obtain the derivative of function
In this part we must apply the following rules to calculate the derivatives:
Product rule[tex]\frac{d}{dx}[f(x)\cdot g(x)] = f'(x) \cdot g(x) + f(x) \cdot g'(x)[/tex] (1)
Quotient rule
[tex]\frac{d}{dx}\left[\frac{f(x)}{g(x)} \right] = \frac{f'(x)\cdot g(x)-f(x)\cdot g'(x)}{[g(x)]^{2}}[/tex] (2)
Now we proceed to obtain each expression:
1) [tex]f'(x) = 3\cdot x\cdot (x-6)+3\cdot x-9[/tex]
[tex]f'(x) = 3\cdot x^{2}-15\cdot x - 9[/tex] [tex]\blacksquare[/tex]
2) [tex]f'(x) = \left(\frac{9}{4}\cdot x^{2}-4\cdot x+\frac{1}{4}\right)\cdot (2\cdot x^{2}-2\cdot x + 4) + \left(\frac{3}{4}\cdot x^{3}-2\cdot x^{2}+\frac{x}{4}-6\right)\cdot (4\cdot x-2)[/tex]
[tex]f'(x) = \frac{9}{2}\cdot x^{4}-8\cdot x^{3}+\frac{1}{2}\cdot x^{2}-\frac{9}{2}\cdot x^{3}+8\cdot x^{2}-\frac{x}{2}+9\cdot x^{2}-16\cdot x+1 +3\cdot x^{4}-8\cdot x^{3}+x^{2}-24\cdot x-\frac{3}{2}\cdot x^{3}+4\cdot x^{2}-\frac{x}{2} +12[/tex]
[tex]f'(x) = \left(\frac{9}{2}+3 \right)\cdot x^{4}+\left(-8-\frac{9}{2}+8-\frac{3}{2} \right)\cdot x^{3} + \left(\frac{1}{2}+8+9+1+4 \right)\cdot x^{2} + \left(-16-24-\frac{1}{2} \right)\cdot x + \left(1+12\right)[/tex]
[tex]f'(x) = \frac{15}{2} \cdot x^{4}-6\cdot x^{3}+\frac{45}{2}\cdot x^{2}-\frac{81}{2} \cdot x +13[/tex] [tex]\blacksquare[/tex]
3) [tex]f'(x) = \frac{-9\cdot (5\cdot x^{2}-8)-(-9\cdot x+4)\cdot (10\cdot x)}{(5\cdot x^{2}-8)^{2}}[/tex]
[tex]f'(x) = \frac{-45\cdot x^{2}+72+90\cdot x^{2}-40\cdot x}{25\cdot x^{4}-80\cdot x^{2}+64}[/tex]
[tex]f'(x) = \frac{90\cdot x^{2}-45\cdot x^{2}-40\cdot x +72}{25\cdot x^{4}-80\cdot x^{2}+64}[/tex] [tex]\blacksquare[/tex]
4) [tex]f'(x) = \frac{\left(9\cdot x^{2}-18\cdot x-6\right)\cdot \left(\frac{x^{2}}{2}+7\cdot x-8 \right)-\left(3\cdot x^{3}-9\cdot x^{2}-6\cdot x +1 \right)\cdot \left(\frac{2}{3}\cdot x+7 \right)}{\left(\frac{x^{2}}{2}+7\cdot x-8 \right)^{2}}[/tex] [tex]\blacksquare[/tex]
How to apply chain rule to find derivativesLet be a function of the form [tex]f[u(x)][/tex], the derivative of this function is defined by the following rule:
[tex]\frac{d}{dx}[f[u(x)]] = \frac{df}{du}\cdot \frac{du}{dx}[/tex]
Now we proceed to present the following results:
1) [tex]f'(x) = 3\cdot (2\cdot x^{2}-2\cdot x +1)^{2}\cdot (4\cdot x-2)[/tex] [tex]\blacksquare[/tex]
2) [tex]f'(x) = \frac{15\cdot x^{2}-16\cdot x+9}{2\cdot \sqrt{5\cdot x^{3}-8\cdot x^{2}+9\cdot x-6}}[/tex] [tex]\blacksquare[/tex]
3) [tex]f'(x) = \frac{2}{3}\cdot \left(3\cdot x^{2}-\frac{2}{3}\cdot x+x^{-4} \right)^{-\frac{1}{3} } \cdot \left(6\cdot x-\frac{2}{3} -4\cdot x^{-5} \right)[/tex] [tex]\blacksquare[/tex]
[tex]f'(x) = \frac{2\cdot \left(6\cdot x-\frac{2}{3}-4\cdot x^{-5} \right)}{3\cdot \sqrt[3]{3\cdot x^{2}-\frac{2}{3}\cdot x +x^{-4} } }[/tex] [tex]\blacksquare[/tex]
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I need help with this can someone PLEASE HELP
go to 0 click on it then make it open circle and make the line go to the right
make the lin
which ratio is different from the other three A.8/20 B.12/30 C.6/10 D.14/35
Bella works at a popular clothing store. Last winter, her manager asked her to track the store's sweater sales. This box plot shows the results. Price of sweaters sold ($) 30 40 50 60 70 80 What fraction of the sweaters cost $50 or less?
Answer:
1/2
Step-by-step explanation:
I got it wrong then it gave me the right answer of 1/2
The fraction of the sweaters that cost $50 or less is 50% is 1/2.
What is a median?It is the middle value of the given set of numbers after arranging the given set of numbers in order.
We have,
From the box plot,
Median = $50
Now,
Median = $50
This means,
50% of the clothes are above $50 and 50% of the clothes are below $50.
Now,
The fraction of the sweaters that cost $50 or less is 50%.
So,
= 50/100
= 5/10
= 1/2
Thus,
The fraction of the sweaters that cost $50 or less is 50% is 1/2.
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BD is a perpendicular bisector of AC. The length of BA is 6d + 3, and the length of BC is 10d - 25. What are the lengths of BA and
BC? (1 point)
The length of BA is 30. The length of BC is 50.
The lengths of BA and BC are both 7.
The lengths of BA and BC are both 45.
The length of BA is 40. The length of BC is 50.
The lengths of BA and BC are both 45.
Step-by-step explanation:
Remember For two perpendicular lines, all four angles formed by the two lines are equal to 90° Perpendicular lines are said to be conguent o 45+45=90 thus your answer!
pls help me plss!!!!!!
Answer: 9 divided by 5 = 1 and 4/5
Step-by-step explanation:
9 divided by 5 = 1 and 4/5
For the diagram, you will have one box completely full, and another 4/5 full.
What is the circumference, in centimeters, of the circle? Use 3.14 for π. Enter your answer in the box.
Answer:
The parameters are not complete
Step-by-step explanation:
Please check the question, radius was not given, and we can't just determine the circumference without our radius.
THANKS.
given:-x-4=9 prove:c=-13
Statements Reasons
1. -x-4=9 1. Given
2. -x=13 2.
3. x= -13 3. Divison Property of Equality
a. addition property of equality
b. subtraction property of equality
c. divison property of equality
d. multiplication property equality
Answer:
a. addition property of Equality
Is it possible to build a triangle with the side lengths of 9,7, and 16?
Please help! 11pts!!
Answer:
False
Step-by-step explanation:
To be able to build a triangle, the sum of the lengths of any 2 sides must be greater than the length of the third side.
With lengths 9, 7, and 16, 9 + 7 = 16.
You would need 9 + 7 > 16.
Therefore, these sides cannot be used for a triangle.
Ok, so Jay has a goal of saving money to buy a handheld game console. Jay has reached 10% of his goal and saved $12. complete the bar
Answer:
if he reaches 20% he will make 22
In a survey, 150 people said they prefer shopping online. 75% said they prefer shopping online. How many people were surveyed?
A. 300
B. 225
C.200
D. 125
The sum of two consecutive integers is – 175. Find the two integers.
Answer:
-88 and -87
Step-by-step explanation:
Since the two unknown integers are consecutive, one will be one more than the other. This means we can express them as x and x+1, so we only have one unknown in our equation. Since they add to -175, we can now write our equation:
x+(x+1) = -175
Take away brackets and combine like terms:
2x+1 = -175
Now we just need to isolate x which we can do by subtracting 1 from both sides and then dividing both sides by 2:
2x+1-1=-175-1
2x = -176
2x/2 = -176/2
x = -88
And our other number is -88+1 = -87
So our two numbers are -88 and -87 which are consecutive and add to 176:
-88+(-87) = -175
Hope this helped!
What is the slope of a line that is perpendicular to the graph of y = 2x + 5? A-² B 72 C2 D-2
What is the equation of the line through (-2, -3) with a slope of 0
Step-by-step explanation:
Hey there!
The point is; (-2,-3) and slope is 0.
Use one point formula.
(y-y1) = m(x-x1)
Put all values.
(y+3) = 0(X+2)
y+3 = 0
y= -3
Therefore, the equation is y = -3.
Hope it helps...
For a school fundraiser, Elena will make pirate masks. She will order masks and print graphics on them. Elena must spend $349 on the printer before she can print any masks and then $4.80 on each mask. If she has $997 how many masks can she print? Answer as a number!
Answer:
135 masks
Step-by-step explanation:
i hope my math is right lol
Answer:
135 masks
Step-by-step explanation:
First, we take $997 and subtract that by $349
$997 - $349 = $648
To find how many masks Elena can print, we divide $648 dollars by $4.80. Since one mask is equivalent to $4.80
$648 ÷ $4.80 = 135
135 masks
1.9x-0.8y=10 what is x
Answer: x = 0.421053y+5.263158
Step-by-step explanation:
x = 0.421053y+5.263158
Answer:
x=0.042105y+10/19
Step-by-step explanation:
Let's solve for x.
19x−0.8y=10
Step 1: Add 0.8y to both sides.
19x−0.8y+0.8y=10+0.8y
19x=0.8y+10
Step 2: Divide both sides by 19.
19x/19=0.8y+10/19
x=0.042105y+10/19
. Peggy is p years old.
Maggie is 1 year less than ¼ of Peggy’s age. What is Maggie’s age in terms of p?
a. ¼p - 1
b. 1 - ¼p
c. ¼p + 1
d. ¼p
Answer:
Step-by-step explanation:
Peggy is p years old.
¼ of Peggy’s age is ¼p
1 year less than ¼ of Peggy’s age is ¼p - 1
so answer is A
A scientist measures the velocity of a major ever at various depths. After collecting and analyzing the data, the scientist determines that the equation y = -0.1140 + 1.658, where I represents the
depth in feet and y represents the velocity of the river, in feet per second can be used to model the data. The linear model has a correlation coeficient or 0.964
Part
Explain what the slope and intercept of the equation mean in terms of the context
Part 8
Explain what the correlation concient indicates about the relationship between the two varables
Answer:
Hi to be in the morning and evening and I'm so happy to have you ever been a while back and watch it again this week is over and see the light of day of the 2