A car is traveling at a steady speed. It travels 1 3/4 miles in 2 1/3 minutes. How far will it travel in 39 minutes ​? In 1 hour ​?

Answers

Answer 1
Answer: 45

Step-by-step explanation:  

1 and 3/4 miles               ???? miles

--------------------  = ---------------------

2 and 1/3 minutes         39 minutes

Cross multiplies:

(1 and 3/4) x 39 =   (2 and 1/3)  x    ?

7/4 x 39/1   = 7/3 x ?

273/4 = 7/3 x ?

? = 273/4 * 3/7 =  39*3/4   <---- 7 x 39 = 273

                        = 117/4

                         = 29 and 1/4

---------------------------------------------------------------

1 and 3/4 miles              ?

------------------ = ------------------

2 and 1/3 min             60 min

(1 and 3/4) * 60 = (2 and 1/3) * ?

7/4*60/1 = 7/3 * ?

105 = 7/3 * ?

? = 105*3/7

 = 315/7

 =  45


Related Questions

39 inches is the right answer just did the test on edge

Answers

Yup 39 is the correct answer good job :-)

Answer:

thanks have a nice day can you please mark me brainliest im trying to rank up and i  need 2 more brainlys

Step-by-step explanation:

The Murphin Company has 2,342 employees and the Galdstock Company has 1,750 employees. How many fewer people work at the Galdstock Company than at the Murphin Company?​

Answers

Answer:

592

Step-by-step explanation:

This is a subtraction problem.

2,342 - 1,750 = 592

simplify 5p - 3 p + p​

Answers

the answer is 3p

hope it helps!

Answer: 3p

Step-by-step explanation:

5 − 3 + =

3

Using lengths a, b, and c in the right triangle shown, how are the trigonometric functions of defined?

Answers

We need to see the triangle to answer this question.

Answer:

take a pic.of question

Step-by-step explanation:

gotta see the triangle

please help me solve this answer

Answers

Answer:it is a

Step-by-step explanation:

because it is only one under 3 miles

8 friends go to Subway and each get 1/2 of a sandwich. How many sandwiches did they get altogether?

Answers

8 sandwiches just half the size

A survey found that 73% of people use streaming services, of those who stream, 28% report that they download
movies,
Find the probability that a randomly selected person uses streaming services and downloads movies,
0.20
0.28
0.38
2.61

Answers

Answer:

0.20

Step-by-step explanation:

If 42,800 dollars is invested at an interest rate of 5 percent per year, find the value of the investment at the
end of 5 years for the following compounding methods.

What is the
Annual $
Semiannual $
Monthly $
Daily $
Continuously $

Answers

Answer:

Annual $54,624.85

Semiannual $54,787.62

Monthly $54,927.75

Daily $54,955.35

Continuously $54,955.35

Step-by-step explanation:

If 42,800 dollars are invested at an interest rate of 5 percent per year, to find the value of the investment at the end of 5 years for the following compounding methods, the following calculations must be performed:

Annual $54,624.85

42,800 (1 + 0.05 / 1)^5x1 = X = 54,624.85

Semiannual $54,787.62

42,800 (1 + 0.05 / 2)^5x2 = X = 54,787.62

Monthly $54,927.75

42,800 (1 + 0.05 / 12)^5x12 = X = 54,927.75

Daily $54,955.35

42,800 (1 + 0.05 / 365)^5x365 = X = 54,955.35

Continuously $54,955.35

42,800 (1 + 0.05 / 365)^5x365 = X = 54,955.35

Algebra Unit 2Part 2 Test please show work

Answers

This it the test please do as fast as posible and show work. thank you and sorry

A meteorologist stated that 1 foot of snowfall would melt to make 2 inches of water. Based on this rule, how much water should result from 84 inches of snowfall ?

Answers

80 I guess is the answer

The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8.3 cm. a. Find the probability that an individual distance is greater than 210.00 cm. b. Find the probability that the mean for 20 randomly selected distances is greater than 197.80 cm c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

Answers

Answer:

a) 0.1151 = 11.51% probability that an individual distance is greater than 210.00 cm.

b) 0.883 = 88.3% probability that the mean for 20 randomly selected distances is greater than 197.80 cm.

c) The distribution of the population is normal, which means that the sample size does not need to exceed 30.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8.3 cm.

This means that [tex]\mu = 200, \sigma = 8.3[/tex]

a. Find the probability that an individual distance is greater than 210.00 cm.

This is 1 subtracted by the pvalue of Z when X = 210. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{210 - 200}{8.3}[/tex]

[tex]Z = 1.2[/tex]

[tex]Z = 1.2[/tex] has a pvalue of 0.8849

1 - 0.8849 = 0.1151

0.1151 = 11.51% probability that an individual distance is greater than 210.00 cm.

b. Find the probability that the mean for 20 randomly selected distances is greater than 197.80 cm

Now [tex]n = 20, s = \frac{8.3}{\sqrt{20}} = 1.8559[/tex]

This probability is 1 subtracted by the pvalue of Z when X = 197.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{197.8 - 200}{1.8559}[/tex]

[tex]Z = -1.19[/tex]

[tex]Z = -1.19[/tex] has a pvalue of 0.117

1 - 0.117 = 0.883

0.883 = 88.3% probability that the mean for 20 randomly selected distances is greater than 197.80 cm.

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The distribution of the population is normal, which means that the sample size does not need to exceed 30.

Find the area of this figure

Answers

52 is the answer to this question

Mr.moss has 4 gallons of paint. He painted 8 doors. How many benches can he paint with the paint that is left

Answers

Answer:

2

Step-by-step explanation:

I did 8 divided by 4 which is 2.

I hope this helps.

also (area O O O O O O​

Answers

Answer:

slide A= 6

slide B= 8

perimeter= 36

Area = 80

Step-by-step explanation:

Answer:

slide A= 6

slide B= 8

perimeter= 36

Area = 80

Step-by-step explanation:

Write the equation in standard form for the circle x^2 + y^2 + 16x + 28 = 0.

Answers

Answer:

( x + 8 ) ^2+ y^2= 36

Step-by-step explanation:

What is the perimeter of the triangle?

Answers

Answer: 3y + 5 cm

Step-by-step explanation: The perimeter of a triangle

is just the distance around the outside of the figure.

So just add up all the sides.

So we have y + y + y + 5 and we get 3y + 5.

5th grade math/// In the first week of a food drive, the 5th grade collected 2 3/4 bags of canned goods. The goal is to collect 2 1/2 times as many bags in the second week. How many bags is the 5th grade hoping to collect in the second week?

Answers

The number of bags that would be collected in the second week is 6 7/8 bags.

How many bags would be collected in the second week?

A mixed number is a number that is made up of an integer and a proper fraction. A proper fraction is a fraction that has a numerator that is less than the denominator. An example of a mixed number is 2 3/4.

In order to determine the number of bags that would be collected in the second week, multiply 2 3/4 by 2 1/2. Multiplication is the mathematical operation that is used to determine the product of two or more numbers.

Number of bags collected in the second week = 2 3/4 x 2 1/2

11/4 x 5/2 = 55/8 = 6 7/8 bags

To learn more about multiplication of fractions, please check: https://brainly.com/question/1114498

#SPJ1

Which equation shown below would have a solution set to the system shown below?
x+ 2y = 4
3x - y = -1
1. 6x-2y = -1
2. 3x - y = 4
3. -2x + 3y = 5
4. 4x + y = -4​

Answers

2 it is sorry if this is wrong

Solve the system by substitution.
2x + 3y = 32
y = x + 9

Answers

Answer:

x=1 and y=10 (1,10)

Step-by-step explanation:

2+30=32

10=1+9

The original cost is $25. The item has a discount of 20% off. What is the discount amount?

Answers

Answer:20 dollars.

not sure

Step-by-step explanation:

find the product 6 * 1/3​

Answers

Answer:

2

Step-by-step explanation:

Reduce the numbers with the greatest common factor which is 3

So.. 2

What is 4^2 - (3.1 + 6.4) + 4.5 pls show ur work

Answers

4^ 2-(3.1+6.4)+4.5

16 − ( 3.1 + 6.4 ) + 4.5

16 − 9.5 + 4.5

6.5 + 4.5

= 11
Answer: 11
How:
4^2 - (3.1 + 6.4) + 4.5
16 - 9.5 + 4.5
6.5 + 4.5
= 11

(-1)15 =
................

Answers

The answer is -15 I’m pretty sure

please what is the answer? i need the steps too please help me

Answers

Do not write this one actually I have just give you one example

Please help me I’m desperateeee

Answers

Answer:

Step-by-step explanation:

First box: (0,1)

Second box: (0,-3)

Third box: (0,-4)

Kenneth runs 12 laps around a track in 15 min. How many minutes per a lap is that?



**choose your answer from the choices on Slide 2, but you must show how you got your answer on the chart, blank drawing space below, or explain in words**

Answers

Answer: 1.25 minutes per lap

Step-by-step explanation:

Her total time divided by total laps is 15 divided by 12, which is 1.25

Answer:

Kenith runs 0.8 laps a minute

Step-by-step explanation:

PLEASE HELP!!!!!! ILL GIVE BRAINLIEST *EXTRA 40 POINTS** !! DONT SKIP :((

Answers

Answer:

No

Step-by-step explanation:

(2, 6) is not a solution to the given system of linear equations.

y = 5x - 4 = 5*2 - 4 = 10 - 4 = 6

y = - 1/2x + 8 = - 1/2 * 2 + 8 = - 1 + 8 = 7

Since, point (2, 6) does not satisfy to equation 2.

Therefore, (2, 6) is not a solution to the given system of linear equations.

Answer:

no

Step-by-step explanation:

C/2 - 3 + 6/d when c=14 d=3

Answers

Answer:

6

Step-by-step explanation:

14/2 - 3 + 6/3

Divide 14 by 2 to get 7.

7−3+6/3

Subtract 3 from 7 to get 4.

4+6/3

Divide 6 by 3 to get 2.

4+2

Add 4 and 2 to get 6.

6

A photographer has a print that is 3.5 inches wide and 2.5 inches tall. If the photographer enlarges the print so that it is 7 inches wide, how tall will it be?
5 inches
6 inches
8 inches
12 inches

Answers

b. if it is 7 inches wide it will be 6 inches tall

Answer:

5 inches

Step-by-step explanation:

Hope I helped

Often, frequency distributions are reported using unequal class widths because the frequencies of some groups would otherwise be small or very large. Consider the following​ data, which represent the daytime household temperature the thermostat is set to when someone is home for a random sample of households. Determine the class​ midpoint, if​ necessary, for each class and approximate the mean and standard deviation temperature.
Temp Frequency Class Midpoint
61-64 34 63
65-67 68 66.5
68-69 196 69
70 191 70.5
71-72 122 72
73-76 81 75
77-80 52 79
The sample standard deviation is _____degrees°F.

Answers

Answer:

The sample standard deviation is 13.22°F

Step-by-step explanation:

Given - Often, frequency distributions are reported using unequal

            class widths because the frequencies of some groups would

            otherwise be small or very large. Consider the following​ data,

            which represent the daytime household temperature the

            thermostat is set to when someone is home for a random sample

            of households. Determine the class​ midpoint, if​ necessary, for

             each class and approximate the mean and standard deviation

             temperature.

Temp                    Frequency                        Class Midpoint

61-64                         34                                         63

65-67                         68                                         66.5

68-69                         196                                        69

70                              191                                         70.5

71-72                         122                                         72

73-76                          81                                           75

77-80                          52                                           79

To find - The sample standard deviation is _____degrees°F.

Proof -

Temp         Frequency(f)            Midpoint(m)           m×f        ( m - 70.73 )²×f

61-64                34                            63                   2142          2031.6

65-67                68                            66.5                4522           1216.7

68-69               196                            69                  13524          586.6

70                     191                           70.5               13465.5        10.1

71-72                122                           72                   8784             196.8

73-76                  81                            75                   6075             2224.4

77-80                  52                            79                    4108            3556.4

                   ∑f = 744                                    ∑m×f = 52620.5     ∑ = 9822.6

So, Mean = [tex]\frac{52620.5}{744}[/tex] = 70.73

Sample standard deviation = [tex]\frac{9822.6}{744 - 1} = \frac{9822.6}{743}[/tex] = 13.22

∴ we get

The sample standard deviation is 13.22°F

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