(A) The spring constant of the spring is 4.94 N.
(B) The speed of the cart after pushing it is 0.47 m/s.
(C) The force applied to the cart is 0.75 N.
Spring constant
ω = √k/m
where;
ω is angular frequencyk is spring constantm is mass0.5 rev/s = 0.5(2π) rad/s = π rad/s = 3.142 rad/s
ω² = k/m
k = mω²
k = 0.5 x (3.142)²
k = 4.94 N/m
Energy stored in the springE = ¹/₂kA²
where;
A is amplitude
E = ¹/₂(4.94)(0.15)²
E = 0.056 J
Speed of the cartE = ¹/₂mv²
2E = mv²
v² = 2E/m
v² = (2 x 0.056)/(0.5)
v² = 0.224
v = √0.224
v = 0.47 m/s
Force exerted on the cartE = ¹/₂FA
2E = FA
F = 2E/A
F = (2 x 0.056)/(0.15)
F = 0.75 N
Thus, the spring constant of the spring is 4.94 N. The speed of the cart after pushing it is 0.47 m/s. The force applied to the cart is 0.75 N.
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What did the universe's thermal radiation spectrum consisted mostly of when it was 380,000 years old?
When the universe was 380,000 years old, its thermal radiation spectrum was mostly composed of microwaves.
What is radiation?Radiation is the emission of energy from any source that is capable of producing electromagnetic radiation such as light, X-rays, gamma rays and radio waves. Radiation is a form of energy that can be beneficial or harmful depending on the type and dose.
This is because at this point in its history, the universe had cooled enough that its thermal radiation spectrum was mostly in the microwave region of the spectrum. These microwaves are known as the Cosmic Microwave Background Radiation (CMBR). This radiation is believed to have been emitted by the hot, dense early universe shortly after the Big Bang.
The CMBR is one of the most important pieces of evidence for the Big Bang theory. It is uniform across the sky and is detected in all directions. Its temperature is approximately 2.7 Kelvin, which is about -270.45 degrees Celsius. This radiation is also believed to be the oldest light in the universe, as it has been travelling through space for billions of years.
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How much work is done by the environment in the process shown in the figure? Express your answer with the appropriate units
Wext is negative So energy is transferred from the system to the environment.
What is Work Done?
Energy can be transferred by the use of force. Work done refers to the amount of energy used by a force to move an object. As a result, there is a direct connection between Work and Energy.
The sum of the displacement and the component of the applied force of the object in the displacement direction is the work done by a force.
Using energy conservation
Ki + Ui + Wext = Kf + Uf + dEth
Using given values in graph
4 + 1 + Wext = 1 + 2 + 1
Wext = 4 - 5
Wext = -1 J
Since Wext is negative So energy is transferred from the system to the environment.
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A Rock is thrown Straight upward with an initial velocity of 24.5m/s where the downward acceleration due to gravity is 10.0 metre per second Square, What is the rocks displacement after 1.0 seconds
The rock was thrown upward with an initial velocity and it's displacement after one second is 19.5 m.
How does the second law of motion work?According to Newton's second law, an object's acceleration is determined by its mass and the net force that is acting on it. The body's acceleration is inversely related to its mass and directly proportional to the net force acting on it.
The displacement-time relation,
X(t) - x = vt -1/2 gt^2
X(t) = Position of object after time t
x = Initial position of object
v = Initial velocity = 24.5 m/s
g = Acceleration due to gravity = - 10.0 m/s2 (Downward)
t = time = 1 s
The displacement of rock after 1 s => X(t) - x => (24.5 x 1) - 1/2 ( 10 x 1 x 1)
=> 19.5 m
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The ΔH∘f of TiI3(s) is -328 kJ/mol and the ΔH∘ for the reaction 2Ti(s)+3I2(g)→2TiI3(s) is -839 kJ Calculate the ΔH of sublimation of I2(s), which is a solid at 25 ∘C.
The ΔH of sublimation of I2(s) is, ΔHsublimation is -366.3 kJ/mol.
To calculate the ΔH of sublimation of I2(s) we can use the following equation: ΔHsublimation = ΔHf (I2(s)) - ΔHf (I2(g))
We can use the information provided in the question to determine ΔHf (I2(s)) and ΔHf (I2(g)):
ΔHf (I2(s)) = -328 kJ/mol (ΔH∘f of TiI3(s)) + 2(-295.5 kJ/mol) (ΔHf of Ti(s))
ΔHf (I2(g)) = ΔHf (TiI3(s)) - 2 ΔHf (Ti(s)) - 3 ΔHf (I2(g))
The ΔHf of I2(g) is not given, so we can use the second equation to find it
-328 kJ/mol = -839 kJ/mol - 2(-295.5 kJ/mol) - 3 ΔHf (I2(g))
3 ΔHf (I2(g)) = -328 kJ/mol + 839 kJ/mol + 2(295.5 kJ/mol) = 212.5 kJ/mol
ΔHf (I2(g)) = 212.5 kJ/mol / 3 = 70.8 kJ/mol
Finally, the ΔH of sublimation of I2(s) is ΔHsublimation = -295.5 kJ/mol - 70.8 kJ/mol = -366.3 kJ/mol
Enthalpy of sublimation (ΔHsublimation):
ΔHsublimation is the heat absorbed or released when a substance changes from a solid to a gaseous state without passing through the liquid state.It is a measure of the strength of the forces holding the solid together and is usually expressed in units of energy per mole of a substance.The enthalpy of sublimation is typically a positive value, indicating that energy must be added to the substance to overcome the forces holding it in the solid state and causing it to sublimate.It is commonly used in thermodynamics and thermochemistry to calculate the energy changes in a chemical reaction.It is also a measure of the stability of a solid, the higher the enthalpy of sublimation the more stable the solid is.Learn more here:
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4. Which of the following statements is not accurate regarding identifying factors on the health pyramid?
O All three sides of the health triangle affect each other.
Personal actions are categorized on the health pyramid by the intended purpose of the initial actions.
O Physical health is the base of the triangle and is the most important part of the health triangle.
O Working out a gym would be categorized in the physical health category.
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On identifying aspects on the health pyramid, the statement "Physical health is a base of a health triangle and is the most essential part of the triangle" is inaccurate.
Describe the triangle.The triangle is just a three-sided polygon with three vertices. The triangle's internal angle, which is 180 degrees, is constructed. It implies that the internal angles in a triangle add up to 180 degrees. It is the polygon with the least amount of sides.
Define the terms right triangle, acute triangle, and obtuse triangle.All of a triangle's angles measure below 90 degrees in an acute triangle. One of the triangle's angles is more than 90 degrees in an obtuse triangle. One angle of a right triangle is 90 degrees, while the other two are acute.
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Give the color of the curve corresponding to an incident beam that is unpolarized red green blue
The color of the curve corresponding to an incident beam that is unpolarized is green.
What is unpolarized?Unpolarized light is light that has no specific polarization. It consists of a mixture of electric fields oscillating in random directions. Unlike polarized light, which vibrates in a single plane, unpolarized light vibrates in multiple planes. Unpolarized light is created naturally by the Sun and other light sources, and can be further produced by lenses and mirrors. It is used in a variety of applications such as in fiber optics, in optical communication, and in non-destructive testing.
This is because when the light is unpolarized, it is composed of an equal mix of both vertical and horizontal components, resulting in the green color. The green curve is created because the vertical and horizontal components are added together in the same direction, resulting in the green color. The green curve is usually seen when the light is incident on a surface at a perpendicular angle.
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A beam of charged particles can be deflected by:
an electric field only
neither a magnetic nor an electric field
both an electric field and a magnetic field
a magnetic field only
Both an electric field and a magnetic field can deflect a beam of charged particles
What is a Magnetic Field ?A magnetic field is any region or space where a magnetic force can be felt. The magnetic field strength is also known as magnetic field.
When a beam of charged particles pass through the magnetic field, the beam of the charged particle will be deflected by moving in a circle.
But when a beam of charged particles pass through the electric filed, the beam of charged particles will be deflected by moving in a parabolic path.
Therefore, a beam of charged particles can be deflected by both an electric field and a magnetic field.
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In (Figure 1), what value of Fmax gives an impulse of 9.0 Ns?
Express your answer to two significant figures and include the appropriate units.
The value of Fmax = 10-³/2 N
Fmax = 500N
Explanation:
Impulse is the area under force curve
The ramp up and down each have area 1/2*base*height
= 1/2 *2ms*Fmax areas for the combined area (2ms)Fmax
The middle rectangle has area = base * height
= (4ms)Fmax
So, total (6ms)Fmax is equal to 3Ns
Fmax = 3Ns/6ms = 10^3 /2 N
Fmax = 1000/2 = 500N
The value of Fmax gives an impulse of 9.0 Ns is found to be 2.25N
How are the force F, the impulse J, and the time t related?The term "impulse" describes how much of an influence a force has overall over the course of time. J = F t for a constant force. The continuous net force applied on an object throughout time and its duration are both factors that affect impulse.
For a constant force, J = F ⋅ Δ t
Impulse J => 9 Ns
F max at given impulse = 9/Δ t => 9/(6-2)
=> 2.25N
What does F in impulse stand for?F stands for the applied resultant force, t1 and t2 for the start and end of the impulse, respectively, m for the object's mass, v2 for the object's ultimate velocity at the conclusion of the time interval, and. When the time interval starts, the object's starting velocity is v1.
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A car of mass 2000 kg accelerates from rest to 20 m/s in 10 seconds. Calculate the average power output of its engine.
Answer: in kilowatt, 40,000 upon 1000 kilowatt, which is equal to 40 kilowatts.
Explanation: Here a car accelerates from rest to a velocity of 20 m/s In 10 seconds. And we have to find the power of the engine during this acceleration. So here we will use the work-energy theorem according to which work done is equal to the car's kinetic energy change. So work done by the engine is equal to half M V f squared minus V I square Mars is 2000. Could you? VF is the final velocity, which is 20 m/s, Initial Velocity VI is zero. So we get worked and equal to four into 10 to the power five jewels. Now power will be equal to work done by time. So work done is the 90s 10 seconds. So power is 40 1000 And in kilowatt, 40,000 upon 1000 kilowatt, which is equal to 40 kilowatts. So this is the correct option and this completes the solution.
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Explain how momentum is used to create baseball bats.
Momentum is used to create baseball bats by swinging them with force and power to build up momentum.
What is Momentum ?
Momentum is a concept in physics that describes the tendency of an object in motion to remain in motion. It is a measure of an object’s momentum, which is the product of its mass and velocity.
Momentum is a vector quantity, which means it has both magnitude and direction. Momentum is conserved, meaning that the total momentum of all objects in a closed system remains constant. Momentum is an important concept in classical mechanics, and its conservation has important implications for how objects interact.
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find the entropy change of the universe when 2 mol of water freezes at -10 ∘c.
The entropy change of the universe when 2 mol of water freezes at the temperature of -10°C is 0.2 J/Kmol
The amount of the water = 2 mol
The temperature of water = -10°C
The entropy change can be found using the formula,
S = Q/T
where S is the entropy
Q is the amount of water
T is the temperature
Entropy change is a phenomenon that measures changes in disorder or randomness in thermodynamic systems. It refers to converting heat or enthalpy into work. A highly random thermodynamic system implies high entropy.
Let us substitute the known values in the above equation, we get
S = 2 / -10
= -0.2 J/Kmol
Therefore, the entropy change of the universe is 0.2 J/Kmol
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Cathode-ray tubes (CRTs) are often found in oscilloscopes and computer monitors. In the figure(Figure 1) an electron with an initial speed of 6.50×106m/s is projected along the axis midway between the deflection plates of a cathode-ray tube. The potential difference between the two plates is 18.0 V and the lower plate is the one at higher potential.
a. What is the magnitude of the force on the electron when it is between the plates?
b. What is the magnitude of the acceleration of the electron when acted on by the force in part (a)?
c. How far below the axis has the electron moved when it reaches the end of the plates?
d. At what angle with the axis is it moving as it leaves the plates?
Oscilloscopes and computer monitors typically contain cathode-ray tubes (CRTs):
A vacuum tube called a cathode-ray tube (CRT) has one or more electron rifles, and the beams from these rifles are adjusted to project images onto a phosphorescent screen.
Radar targets, electric waves (oscilloscope), images (television, computer monitor), and other events can all be represented by images.
An electron is projected between the deflection plates of the cathode-ray tube with an initial velocity of 6.80 106 m/s. The axis between the cathode-ray tube recording plates is depicted with an initial electron traveling at a speed of 7 x 106 m/s:
The same, high, 1000 V/m electric field exists between the plates.
F is equal to 1.6 x 10-16 N, and an is equal to 1.76 x 1014 m/s2.
The lower plate is the strongest, and the difference between the two plates that could exist is 18.0 V:
between two plates with the identical field
E = - V / s or
V = U / q 0
E = -∆ V / ∆ s
The possible difference is solely dependent on the plates and NOT on any shipping fees.
The amount of effort required is determined by the billing process' size. More significant than the actual worth of electricity is the prospective difference in electricity.
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A cylindrical bucket of liquid (density rho) is rotated about its symmetry axis, which is vertical. If the angular velocity is ω, show that the pressure at a distance r from the rotation axis is
P=P0+1/2rhoω2r2,
where P0 is the pressure at r=0
Showing the pressure at a distance, it generate the equation dP=1/2rhoω^2r^2dr.
How do you get the given equation?The pressure at a point in a fluid is given by the hydrostatic equation, which states that the pressure is equal to the density of the fluid multiplied by the acceleration due to gravity, and the height of the fluid above that point. In a rotating cylinder of liquid, there is an additional centrifugal force acting on the fluid, which must be taken into account.
To find the pressure at a distance r from the rotation axis, we can use the following equation:
P = P0 + 1/2 * rho * ω^2 * r^2
Where P0 is the pressure at the center of the cylinder (r=0), rho is the density of the fluid, and omega is the angular velocity of the cylinder.
This equation can be derived by considering the force balance in the radial direction. The pressure difference dP between two points at radius r and r+dr due to centrifugal force is dP=1/2rhoω^2r^2dr. Integrating this over the radius gives the above equation
Therefore, the correct answer is as given above
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in the doppler effect, do frequency, wavelength, and/or wave speed change?
In the Doppler effect, the frequency, wavelength, and wave speed of sound or light waves can change depending on the relative motion of the source of the waves and the observer.
When the source of the waves is moving toward the observer, the frequency of the waves will appear to be higher than the actual frequency, and the wavelength will appear to be shorter. This is referred to as a "blue shift".
Conversely, when the source of the waves is traveling away from the observer, the wavelength will appear to be longer and the frequency will appear to be lower than it actually is. This is referred to as a "redshift."
The Doppler effect, however, does not alter the wave speed, which stays constant.
It is significant to remember that the Doppler effect affects not only sound waves but also electromagnetic waves like light waves. The Doppler shift is another name for the Doppler effect.
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C/P: What kind of image is formed by the lenses of the glasses worn by a 68-year-old male who sees an object 2 m away?
Focal length of glasses worn (cm): -50
A) Real and enlarged
B) Real and reduced
C) Virtual and enlarged
D) Virtual and reduced
Option D is the correct answer. Virtual and reduced image is formed by the lenses of the glasses worn by a 68-year-old male who sees an object 2m away.
negative focal length = DIVERGING lenses thus it must always be virtual and reduced
Positive focal length = converging lens
Virtual images can be either upright or inverted. Virtual images can be magnified in size, reduced in size, or the same size as the object.
A pair of looking glasses is an optical instrument that helps a person with defective eyes to see an object as if it was being viewed with normal vision.
When a person is far-sighted, the looking glasses should have converging lenses. When a person is near-sighted, he or she should wear a pair of looking glasses fitted with diverging lenses.
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A candle is sitting in front of a concave mirror at a distance of 12.2 cm. It is found that an image of the candle appears at 25.0 cm. What is the focal length of the mirror?
Answer:
Focal length (f) = 1/2 (Object distance + Image distance)
f = 1/2 (12.2 cm + 25.0 cm)
f = 18.6 cm
water flows with speed v through a horizontal, cylindrical pipe. which of the following changes in the geometry of the pipe will double the speed of the water in the pipe?
The cross-sectional area is halved, the speed of the liquid becomes doubles or 2v .
There will be a commensurate rise or fall in velocity for every change in flow rate. Greater amounts of the liquid come into touch with the pipe when it is smaller, which increases friction. Velocity is also impacted by pipe size. If the flow rate is constant, shrinking the pipe size raises the velocity, which raises friction. As the fluid moves through the length of the pipe, the friction losses add up. The friction losses will increase as the distance increases.
Pressure losses rise as the average velocity rises. Flow rate and velocity are directly connected.
Av = constant according to the continuity equation.
The second pipe in this instance has a cross-sectional area that is twice as large.
Consequently, if the cross-sectional area is halved, the speed of the liquid becomes doubles or 2v.
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A light ray in air strikes the right-angle prism shown in the figure (Figure 1) (?B= 23.4?). This ray consists of two different wavelengths. When it emerges at face AB, it has been split into two different rays that diverge from each other by 8.50? .
Find the index of refraction of the prism for each of the two wavelengths.
Enter your answers in ascending order separated by a comma.
What is the speed of light for these two wavelengths in the prism?
The index of refraction of the prism for each of the two wavelengths are 1.07 and 1.08.
Given the the angle at which the light ray strikes the prism ∠B = 23.4
Let the refractive index of first wavelength = n1
The index of refraction from second wavelength = n2
The light ray emerges at face AB, it has been split into two different rays.
The angle of diffraction of two rays = 8.50
We use snell's law to calculate the refractive indices. From this, the angle of incidence is the same as the angle of reflection in the air ∠i = ∠r.
Let the angle formed by first wavelength = θ1 = 90-23.4 = 66.6 + 12 = 78.6
From snells law n1 sin i = n2 sin θ1
Here n1 is the refractive index of first wave and n2 is refractive index of air = 1 and i = 66.6 while θ1 = 78.6
Then n1 = 1 x sin 78.6/sin 66.6 = 0.98/0.91 = 1.07
The normal and the other refracted beam make an angle of θ2 = 78.6 + 8.5 = 87.1
n1' sin i = n2 sin θ2
n1' = 1 x sin 87.1/sin 66.6 = 0.99/0.91 = 1.08
Hence the refractive indices of prism of two wavelengths are 1.07 and 1.08.
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If 63Li is struck by a slow neutron, it can form 42He and another nucleus a. What is the second nucleus? (This is a method of generating this isotope.) b. How much energy is released in the process? Express your answer to four significant figures and include the appropriate units.
The second nucleus of 63Li is 21H when struck by a slow neutron and also form 42He. The energy is released in the process is 4.784 MeV.
What substance is exposed to neutron irradiation?Although uranium-238 does not fission, it does absorb neutrons when blasted, turning them into plutonium-239. Plutonium-238 is created when uranium-235 absorbs neutrons.
What or who does a neutron strike?There is no charge on a neutron. Through physical collisions with nuclei, they communicate (target nuclei). Together, g and the nucleus. The probability and types of reactions that can occur depend on the neutron kinetic energy. The nucleus recoils as a result of the collision when the neutron impacts it. Some of the atomic electrons are removed as the nucleus passes through the nearby atoms. Ionization occurs along the route of the nucleus when it recoils as a result of the impact.
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At a given instant, the gear racks have the velocities and accelerations shown.
Determine the acceleration of point A.
Enter the x and y components of the acceleration
Determine the acceleration of point B.
Enter the x and y components of the acceleration
The acceleration of both points A and B can be determined from the given velocities and accelerations of the gear racks.
Point A:
x-component of acceleration = 0 m/s^2
y-component of acceleration = 6 m/s^2
Point B:
x-component of acceleration = 0 m/s^2
y-component of acceleration = -6 m/s^2
The acceleration of both points A and B can be determined from the given velocities and accelerations of the gear racks. The x-component of the acceleration of both points is equal to 0 m/s^2 since the gear racks are not moving horizontally. The y-component of the acceleration of both points is equal to 6 m/s^2 in the upward direction for point A, and -6 m/s^2 in the downward direction for point B. Therefore, the acceleration of point A is (0, 6) m/s^2 and the acceleration of point B is (0, -6) m/s^2.
The complete question is:
At a given instant, the gear racks have the velocities and accelerations shown.
Determine the acceleration of points A and B.
Enter the x and y components of the acceleration
the complete question is :
At a given instant, the gear racks have the velocities and accelerations shown ( attached below ).
Determine the acceleration of point A.
Enter the x and y components of the acceleration
Determine the acceleration of point B.
Enter the x and y components of the acceleration
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What is the average (or mean) of the following set of numbers?
23 29 24 24 25
A. 20.2
B. 25
C. 105
D. 24
Answer:
B
Explanation:
How to find the average:
Step 1.) Add all the numbers
Step 2.) Divide the total from all the number by how many numbers there are.
Ex:
23+29+24+24+25
=125
125÷5= 25
Answer: 25
Why is the entropy change for process 2 larger than that for process 1? Match the words in the left column to the appropriate blanks in the sentences on the right: Make sure the sentences are complete before submitting your answer: Reset Help gas to liquid The substance changes from solid in process 1 and from liquid process 2. The volume and motional freedom of the greater phase causes AS for gas vaporization to (always) be larger than 4 S for fusion: larger less solid to gas liquid to gas smaller solid to liquid Submit Request Answer
The answer is: 1. Solid to Liquid; 2. Liquid to Gas; 3. Larger; 4. Greater; 5. Gas;
The substance changes from solid to liquid in 1, from liquid to gas in 2. The larger volume and greater motional freedom of the gas phase causes AS for vaporization to (always) be larger than AS for fusion.
We can define entropy as the degree of randomness or the possible states of a substance. As we go from solid to liquid to gas, the entropy increases. If the entropy change for 2 is larger than for 1, this probably means that 1 is a solid to liquid process, while 2 is a liquid to gas process. Moreover, we can define fusion as the phase change process between solid and liquid states.
Question:
Why is the entropy change for 2 larger than that for 1? Match the words in the left column to the appropriate blanks in the sentence on the right. Make the sentence is complete before submitting your answer.
gas
solid
liquid
gas to liquid
solid to liquid
liquid to gas
greater
smaller
less
solid to gas
larger
The substance changes from _____ in 1, from _____ in 2.
The _____ volume and _____ motional freedom of the _____ larger than AS for fusion. phase causes AS for gas vaporization to (always) be larger than AS for fusion.
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You are in the year where the earth has no more land available for houses you decide to build an apartment up and need things to survive in each earths 5 layers (troposphere,stratosphere, mesosphere, thermosphere, exosphere) Question: what things would you need to survive the thermosphere(really hot it is 2000 degrees fahrenheit)
pls help me:) this is due tmrw:)
The thermosphere is really hot it is 2000 degrees Fahrenheit. But you would need to survive from extreme cold temperature, harmful solar radiation, low air pressure in the thermosphere.
What is thermosphere?One of the layers of the earth's atmosphere that spreads outward is the thermosphere. The thermosphere layer, which is above the mesosphere and below the exosphere layer and covers a significant portion of the ionosphere.
Molecules in this layer are photoionized by ultraviolet radiation, which means that ions are produced in this layer of the atmosphere when a photon interacts with an atom or molecule.
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A cylinder with a 16-cm-diameter piston contains gas at a pressure of 3.0atm.
a) How much force does the gas exert on the piston?
b) How much force does the environment exert on the piston?
c) The gas expands at constant pressure and pushes the piston out 10cm. How much work is done by the environment?
d) How much work is done by the gas?
The force exerted on the piston is F = 6.11 × 10³N.
The force delivered perpendicularly to an object's surface per unit area across which that force is dispersed is known as pressure. In comparison to the surrounding pressure, gauge pressure is the pressure. The force that an object, fluid, etc., in contact with a surface exerts onto it is measured in a variety of units, such as the pressure of earth against a wall. Physics. force per square inch. pressure express
Given,
diameter = 16cm
= 0.16m
Pressure = 3 atm = 3 × 1.013 × 10⁵ Pa
= 3.039 × 10⁵ Pa
a) F = PA
⇒ F = P πr²
⇒ F = Pπ (d/2)²
⇒ F = 3.039 × 10⁵ Pa × 3.14 × (0.16/2)²
⇒ F = 6.11 × 10³N
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During a tug-of-war, team A does 2.20 105 J of work in pulling team B 8.00 m. What force was team A exerting?
According to the given statement 27500 N of force was team A exerting.
How many types are forces?Cohesive forces & act at such a distance forces are the two different types of forces. Your daily use of force is evident. Basically, push and pull are forces. You exert force on an item when you push against it or pull against it. Nuclear force, gravity force, kinetic friction, electrostatic flux, electromagnetic interaction, spring force, and others are a few examples of forces.
Since the definition of work is the result of force and displacement, we will have
W = F . d
so here we know that
W = 2.20 * 10⁵ J
also we know that
d = 8.00 m
now we will have
2.20 * 10⁵ J = F(8.00)
F = 2.20 * 10⁵ / 8
F = 27500 N
so, it will be under 27500 N of force.
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A copper wire is 20 m long on a winter day when the temperature is ?12?C.
According to the question, the wire will be 20.00034 m long when the temperature is 24°C.
What is temperature?
Temperature is a measure of the average kinetic energy of the particles in a substance. It is typically measured in degrees Celsius, Fahrenheit, or Kelvin. Temperature is an important physical property as it can affect the state of a substance and the rate at which reactions occur. At a given pressure, the temperature of a substance determines its phase.
If the temperature increases to 24°C, the length of the wire will change. Copper is a metal that expands when heated, so the wire will increase in length and become longer. According to the coefficient of linear expansion of copper, the wire will increase in length by 0.000017 m/°C. Therefore, the wire will be 20.00034 m long when the temperature is 24°C.
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A light block of mass (m) and a heavy block of mass (M) are attached to the ends of a rope. A student holds the heavier block and lets the lighter block hang below it. Then she lets go. Air resistance can be neglected.
a. what is the tension in the rope while the blocks are falling, before either hits the ground?
b.would your answer be different if she had been holding the lighter block initially?
The tension in the rope while the blocks are falling, before either hits the ground is zero and it would be the same even if she had been holding the lighter block initially.
Given the mass of light block = m
The mass of heavy block = M
acceleration due to gravity = g
Let the tension in the rope be T
From Newtons second law of motion we know that F = ma where a is acceleration of the system.
In that situation, gravity is the sole external force that is important to us. Fnet = Fg = m(sys)a
The total mass of system = m+M. Then
(m+M)g = (m+M)a
Therefore, the blocks must be falling with the acceleration of free fall at a = g. Here, the lighter system is fastened to a heavy block. Gravity pulls it lower as it falls, so any strain would be upward.
Fnet = Fg - T = ma where m is the mass of the lighter block.
mg - T = ma. This is only accurate if T = 0. The string is therefore not under any tension.
Hence the tension will not change even if the order of blocks is reversed.
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1. A particular organic molecule forms an electric dipole by possessing an effective charge separation of 0.197 nm for a pair of ±1.60×10−19 C charges. What is the magnitude of the molecule's electric dipole moment?
2. Find the magnitude of the torque that acts on the molecule when it is immersed in a uniform electric field of 2.87×105 N/C with its electric dipole vector at an angle of 29.5∘ from the direction of the field.
3. Consider all possible angles between the electric field and the electric dipole vector. What is the greatest magnitude max of torque that the electric field can exert on this molecule?
A particular organic molecule forms an electric dipole, the magnitude of the molecule's electric dipole moment
3.152 x 10^-29 C4.45458171*10^{-24} NmThe max torque that the electric field can exert on this molecule is the same as the torque found in question 2.What is an electric field vector?Generally, The magnitude of the electric dipole moment (p) is given by the product of the charge separation (d) and the magnitude of the charges (q):
p = dq
Therefore, the magnitude of the electric dipole moment of the molecule is:
p = (0.197 nm)(1.60 x 10^-19 C)
= 3.152*10^{-20}Cm
2) The magnitude of the torque (τ) that acts on the molecule in a uniform electric field (E) is given by the vector cross product of the electric dipole moment vector (p) and the electric field vector (E):
τ = p x E
The magnitude of the torque is given by the formula:
τ = pE sin(θ)
where
θ is the angle between the electric dipole moment vector and the electric field vector
Therefore, the magnitude of the torque that acts on the molecule in the given electric field is:
τ = (3.152 x 10^-29 Cm)(2.87 x 10^5 N/C) sin(29.5°)
= 4.45458171*10^{-24} Nm
3)The torque exerted on a dipole*in an electric field is dependent on the angle between the direction of the electric field and the dipole moment.
The torque is maximum when the angle between the direction of the electric field and the dipole moment is 90 degrees and the torque will be zero when it's parallel with the field.
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At right is a graph of force versus position for a block attached to spring. Consider the interval during which the block moves from x = 0.5 m to x = 0.1 m.
a. During this interval, what is the sign and absolute value of the work done on the block by the spring? Explain b. The spring is replaced by a rope that pulls with a constant force of magnitude F0. What must the value of F0 be so that the work done by the rope as the block moves from x = 0.5 m to x = 0 1 m is the same as the work done the spring as the work done by the spring as the block moves from x = 0.5 m to x = 0.1 m? Explain
The work done by the spring as the block moves from x = 0.5 m to x = 0.1 m is negative and equal in absolute value to the area under the graph bounded by the x-axis and the line connecting x = 0.5 m and x = 0.1 m. The value of F0 required for the work done by the rope to be equal to the work done by the spring is equal to -50 N.
a. During the interval of the block moving from x = 0.5 m to x = 0.1 m, the work done on the block by the spring is negative and equal in absolute value to the area under the graph bounded by the x-axis and the line connecting x = 0.5 m and x = 0.1 m. This area is shaded in the graph.
b. The value of F0 required for the work done by the rope to be equal to the work done by the spring is equal to the average force exerted on the block by the spring during the interval. This can be found by calculating the average of the force values at the two positions, which is equal to the average of the y-values of the graph at x = 0.5 m and x = 0.1 m. This results in F0 = -50 N.
The work done by the spring as the block moves from x = 0.5 m to x = 0.1 m is negative and equal in absolute value to the area under the graph bounded by the x-axis and the line connecting x = 0.5 m and x = 0.1 m. The value of F0 required for the work done by the rope to be equal to the work done by the spring is equal to -50 N.
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given the fact that the wire is floating at rest, derive an expression for b.
The dB = 0/4 Idl r/r2 for a conductor segment of length and orientation dl carrying a current i. According to Biot-Savart law, the magnetic field generated by a minute current
The sine of the angle formed by the current's direction and the line connecting it to a point, and it is also inversely proportional to the square of the current. According to the Biot-Savart law, "the magnetic field due to a current-carrying conductor at a distance point is directly proportional
The Biot-Savart law expresses the partial B field contribution of a current in a conductor from a tiny conductor segment. dB = 0/4 Idl r/r2 for a conductor segment of length and orientation dl carrying a current i.
The complete question is- Express the magnitude of the magnetic force in terms of the current Z length L and the Part (c) Given the fact that the Wire is floating at rest; derive magnctic ficld B an expression tOr Part (d) Calculate the numerical value of B in tesla .
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