A certain computer can perform 109 calculations per second. How many calculations can it perform in
10 seconds? Write your final answer in exponential form.

Answer:

 10

Step-by-step explanation:

[tex]\mathrm{Apply\:rule}:\quad \:a-\left(-b\right)=a+b[/tex]

[tex]-6-\left(-16\right)=-6+16[/tex]

[tex]=-6+16[/tex]

[tex]\mathrm{Add\:the\:numbers:}\:-6+16=10[/tex]

Hence, Answer = 10

~Lenvy

Answer: 9x + 3y = 12

Alternative forms: y = 0.4 OR y = [tex]2/3^{2}[/tex]

Answer:

80%

Step-by-step explanation:

Answer:

The answer is 1=5% so 5 × 16 = 80

Answer:

vertical angles - angle 2 and 4, angle 1 and 3

adjacent angles- angle 2 and 3, angle 1 and 4

Concluimos que a partir de 21 piezas se gana más en la empresa B.

Si definimos el número de piezas vendidas como x, la cantidad que le pagan en la empresa A es:

A(x) = $6000 + $20*x

Y lo que le pagan en la empresa B es:

B(x) = $6000 + x^2

Queremos ver para que valor de x, se da que B(x) > A(x).

Entoces resolvamos esa inequación.

6000 + 20*x < 6000 + x^2

20x < x^2

20 < x

x debe ser más grande que 20, entonces concluimos que a partir de 21 piezas se gana más en la empresa B.

Sí quieres aprender más sobre inecuaciones, puedes leer:

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Answer:

Step-by-step explanation:

Answer:

  No Solution

Step-by-step explanation:

You can use the expression for y provided by the first equation to substitute for y in the second equation.

  y = x +1

  x -(x +1) = 1

  -1 = 1

There are no values of the variables x and y that will make this equation true. The system has No Solution.

__

Additional comment

Solving the second equation for y gives ...

  y = x -1

This graphs as a line parallel to the line representing the first equation. A system describing parallel lines has no solution, because the lines never meet, and the solution is the point where they meet.

Answer:

no possible answer.

Step-by-step explanation:

1. y = x+1

2. x-y = 1

3. x = 1+y

Substitute equation 3 into the x in equation 1:

y = (1+y)+1

y = 2+y

y-y = 2

0=2

"0 = 2" isn't valid, thus there is no possible answer to this question.

Answer:

5√7 or 15.652

Step-by-step explanation:

is the numbers (-6,5) (8-2) or is it (-6.5) because of it's -6.5 i do not understand how to get that answer (-6,5) the answer is 5√7

Answer:

104/1000

Step-by-step explanation:

If she tries two each week you will need to know how many weeks are in a year.Now about 52 weeks are in a year so you would multiply 52 by 2 and get 104.

Here, we need to find the fraction of recipes she would have tried in the book after 1 year

The fraction of recipes she would have tried in the book after 1 year is 13/125

Total recipes in the book

[tex] = \frac{Total recipe she tried in a year}{Total recipes in the book } [/tex]

= 1,000

Recipe tried each week = 2

Find the fraction of recipe she would have tried after 1 year

There are 52 weeks in 1 year

she tried 2 recipes each week

Total recipe she tried in a year

=

[tex] = total \: number \: of \: weeks \: in \: a \: year \: \times number \: of \: recipe \: tried \: per \: week[/tex]

[tex] = 52 \times 2[/tex]

[tex] = 104[/tex]

fraction of recipe she would have tried after 1 year

[tex] = \frac{Total recipe she tried in a year}{Total recipes in the book } [/tex]

= [tex] \frac{104}{1000} [/tex]

Divide by 8

= 13/125

Read more:

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Answer:

[ ] = 3¹³

Step-by-step explanation:

3¹⁷ - 3¹⁵ + 3¹³ = [ ] x 73

3¹³ [3⁴ - 3² + 1] = [ ] x 73

3¹³ [81 - 9 + 1] = [ ] x 73

3¹³ x 73 = [ ] x 73

[ ] = 3¹³ [It says 3^13 if it is not clear/visible]

Answer:

4+(64x1/8)=4+8=12

[tex]4 \times (4 + ( {2}^{6} \times {2}^{ - 3})) = [/tex]

[tex]4 \times (4 + ( {2}^{6 - 3})) = [/tex]

[tex]4 \times (4 + ( {2}^{3} )) = [/tex]

[tex]4 \times (4 + (8)) = [/tex]

[tex]4 \times (4 + 8) = [/tex]

[tex]4 \times (12) = 48[/tex]

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The correct answer is (( A )) .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

1,8,-3,-15

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

frequency is the students and most of them (10) study 5-6 hours ♡

Answer: line is never ending in both directions

ray is never ending in one direction

Step-by-step explanation:

Answer:

The answer is

→ [tex]A.)[/tex] [tex]2\frac{1}{4}[/tex]

Step-by-step explanation:

Option A is the answer because the line after letter B should be 2.5, and were talking about the one between 2 and 2.5. Which means that, Option A should be your correct answer.

Answer:

the diameter of the base is 15cm. Find the curved surface area of cone. Solution: Given that, Slant height: l = 20cm

Slant = root of 30^2 + 40^2 = 50

Curved surface area = pi *r*l

pi*15*50

= 750*pi = 750*3.14

= 2355 cm ^2

Answer:

2.30

Step-by-step explanation:

Answer:

x> -200

Step-by-step explanation:

Answer:

see

Step-by-step explanation:

1.

AD²+BD²=AB²

AD²+12²=15²

AD²+144=225

AD²=225-144

AD²=81

AD=√81

AD=9

2.

AC=AD+DC

AC=9+16

AC=25

3. I don't know what's the answer here.

Please give me brainlist.

Step-by-step explanation:

2x + y = 2         subtract 2x from both sides

2x - 2x + y = 2 - 2x

y = -2x + 2

(m = -2, b = 2)

-3x + y = 4        add 3x to both sides

-3x + 3x + y = 4 + 3x

y = 3x + 4

(m = 3, b = 4)

Answer:

3 &4

Step-by-step explanation:

The hyperbola with one focus point in common with the given hyperbola is:

[(y + 11)² / 10²] - [(x - 7)² / 15²] = 1

To find a hyperbola that shares one focus point with the given hyperbola, we need to find another hyperbola with the same focus point but different characteristics (e.g., eccentricity or axis length).

The equation of the given hyperbola is:

[(y + 11)² / 15²] - [(x - 7)² / 8²] = 1

The general equation of a hyperbola with its center at (h, k) is:

[(y - k)² / a²] - [(x - h)² / b²] = 1

The center (h, k) of the given hyperbola is (7, -11).

To share one focus point, we need to keep the center at (7, -11) but change the values of a and b. The eccentricity of a hyperbola is defined as e = c / a, where c is the distance from the center to the focus.

Let's assume the new hyperbola has an eccentricity different from the given hyperbola. We'll keep the same value of c and change the value of a to get a different eccentricity.

Let's say the new hyperbola has a value of a' = 10. Since the eccentricity is different, the value of b' will change accordingly. Let's calculate b' using the eccentricity formula:

e = c / a'

15 / 10 = 1.5

Now, we can find b' using the eccentricity:

e = c / a' = c / 10

c = e * a' = 1.5 * 10 = 15

Now, we have the center (7, -11), the value of a' = 10, and the value of c = 15. The equation of the new hyperbola with one focus point in common is:

[(y + 11)² / 10²] - [(x - 7)² / 15²] = 1

Learn more on hyperbola here;

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Answer:

Your answer is 7 so it's D

Step-by-step explanation:

Answer:

The correct answer would be C. The coordinates of the ENDPOINTS of the segment​

Step-by-step explanation:

It cannot be A, because the segment only moves. It does not change size.

It cannot be B, because the line of symmetry goes down the middle of the segment- the distance remains the same.

Therefore it is C. The coordinates of the ENDPOINTS of the segment​

Answer:

30

Step-by-step explanation:

So you do 4 x 2 for the top square, 2 x 6 for the middle square, and 6 x 2 for the bottom square and then add it all up. Hope this helps!

Hey there!

10x+y=7(x+y)=7x+7y

or 10x−7x=7y−y

or 3x=6y

or x=2y ........(1)

Number formed by reversing the digits is yx, i.e.,

10y+x=10x+y−18

Substituting x=2y, we get

10y+2y=10×2y+y18

or 2y=21y−18

or 21y−12y=18

or 9y=18

or y=2

∴x=2y=2×2=4

Therefore, the number is 42.

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let the two digit number be ' xy '

where, x is the ten's place digit, and y is one's place digit, now let's proceed further ~

The origin number can be written as :

[tex]\qquad \sf  \dashrightarrow \: 10x + y[/tex]

[ because x is at ten's place ]

of the digits are swapped, the new number will be :

[tex]\qquad \sf  \dashrightarrow \: 10y + x[/tex]

According to conditions provided in the question : -

[tex]\qquad \sf  \dashrightarrow \: 10x + y = 7 \times (x + y)[/tex]

[tex]\qquad \sf  \dashrightarrow \: 10x + y = 7x + 7y[/tex]

[tex]\qquad \sf  \dashrightarrow \: 10x - 7x + y - 7y= 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: 3x - 6y = 0 \: \: \: \: \: \: [/tex]

[tex]\qquad \sf  \dashrightarrow \: x - 2y = 0 \: \: \: \: \: \: - (1)[/tex]

here we got our first equation, let's find the other one ~

[tex]\qquad \sf  \dashrightarrow \: (10x + y) - 18= 10y + x[/tex]

[tex]\qquad \sf  \dashrightarrow \: 10x - x + y - 10y = 18[/tex]

[tex]\qquad \sf  \dashrightarrow \: 9x - 9y = 18[/tex]

[tex]\qquad \sf  \dashrightarrow \: x - y = 2 \: \: \: \: \: \: - (2)[/tex]

we got our second equation ~

Now it's time to subtract equation (1) from equation (2) :

[tex]\qquad \sf  \dashrightarrow \:( x - y ) - (x - 2y)= 2 - 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: \cancel{x }- y - \cancel{x} + 2y= 2 - 0[/tex]

[tex]\qquad \sf  \dashrightarrow \: y= 2 [/tex]

hence, value of y is 2, use this value in equation (2) to find x ~

[tex]\qquad \sf  \dashrightarrow \: x - y= 2 [/tex]

[tex]\qquad \sf  \dashrightarrow \: x - 2= 2 [/tex]

[tex]\qquad \sf  \dashrightarrow \: x = 4 [/tex]

Therefore, the required number is xy = 42

Answer:

B.

Step-by-step explanation:

3.7 × 30 = 111

then round down to 110

Answer:

cos(x) = StartFraction 9 Over 15.2 EndFraction

Step-by-step explanation:

That's it

Answer:

B. sin(x) = [tex]\frac{9}{15.2}[/tex]

Step-by-step explanation:

I trusted the other guy and got it wrong.

I hope this helps!