If a cylindrical container with a cross-sectional area of 64.2 cm2 holds a fluid of density 776 kg/m3 The depth of the fluid in the cylindrical container is 2.56 meters.
We can use the hydrostatic equation to find the depth of the fluid in the cylindrical container:
ΔP = ρgh
where:
ΔP = difference in pressure (Pa)
ρ = density of fluid (kg/m3)
g = acceleration due to gravity (9.81 m/s2)
h = height or depth of fluid (m)
First, let's convert the cross-sectional area from cm2 to m2:
64.2 cm2 = 0.00642 m2
Next, let's find the difference in pressure:
ΔP = 121 kPa - 101 kPa = 20 kPa = 20,000 Pa
Now, let's plug in the values we have into the hydrostatic equation and solve for h:
ΔP = ρgh
20,000 Pa = (776 kg/m3)(9.81 m/s2)h
h = 2.56 meters
Therefore, the depth of the fluid in the cylindrical container is 2.56 meters.
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If a cylindrical container with a cross-sectional area of 64.2 cm2 holds a fluid of density 776 kg/m3 The depth of the fluid in the cylindrical container is 2.56 meters.
We can use the hydrostatic equation to find the depth of the fluid in the cylindrical container:
ΔP = ρgh
where:
ΔP = difference in pressure (Pa)
ρ = density of fluid (kg/m3)
g = acceleration due to gravity (9.81 m/s2)
h = height or depth of fluid (m)
First, let's convert the cross-sectional area from cm2 to m2:
64.2 cm2 = 0.00642 m2
Next, let's find the difference in pressure:
ΔP = 121 kPa - 101 kPa = 20 kPa = 20,000 Pa
Now, let's plug in the values we have into the hydrostatic equation and solve for h:
ΔP = ρgh
20,000 Pa = (776 kg/m3)(9.81 m/s2)h
h = 2.56 meters
Therefore, the depth of the fluid in the cylindrical container is 2.56 meters.
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A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. How much energy is lost? Group of answer choices 0.5 J 0.88 J 0.29 J 1 J
Answer: A 60 g golf ball is dropped from a level of 2 m high. It rebounds to 1.5 m. Energy loss will be 0.29J
Explanation: To find the correct answer, we have to know more about the Gravitational potential energy.
What is gravitational potential energy?The energy possessed by a body by virtue of its position in gravitational field of earth is called gravitational potential energy.The gravitational potential energy of a body at a height h with respect to the height h will be,[tex]U=mgh[/tex]
Expression for gravitational potential energy loss will be,[tex]E=U_i-U_f[/tex]
How to solve the problem?The total energy before the ball dropped will be,[tex]U_i=mgh_i=60*10^-3kg*9.8m/s^2*2m=1.176 J[/tex]
The total energy after when the ball rebounds to 1.5m will be,[tex]U_f=mgh_f=60*10^-3kg*9.8m/s^2*1.5m=0.882J[/tex]
The total energy loss will be,[tex]E=1.176-0.882=0.294J[/tex]
Thus, we can conclude that, the energy loss will be,0.294J.
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Generating electricity has its risks, no matter what type of fuel is used. Identify which consequences are associated with generating electricity in a coal-fired power plant and which accompany nuclear power. Some risks may belong in both categories.
Power generation has to do with the process by which electricity is generated from various sources.
What are the risks of power generation?Power generation has to do with the process by which electricity is generated from various sources. Now we know that electricity is almost the driving force of several economies globally.
A coal fired power plant will lead to the burning of fossil fuels and the consequent release of CO2 into the atmosphere which leads to global warming. Also, the possibility of the release of SOx from the burring of coal could lead to acid rain.
In the case of nuclear sources, the disposal of the spent nuclear fuel presents a huge risk as well as the possibility of radioactive fallout and possible accident that could release tremendous amount of radiation.
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The measure of arc ed is 68°. what is the measure of angle efd? 34° 68° 112° 132°
The measure of the angle EFD = 34°. That is option A.
Calculation of an angle of an intercepted arcThe radii of the given circle are CE and CD.
The measure of the given angle of the arc is = 68°
But the central angle of an intercepted arc measure the double of the inscribed angle by the same arc.
Therefore, the measure of angle of an intercepted arc is 68/2 = 34°
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Answer:
34
Explanation:
edge 2023
The diagram shows a device that uses radio waves. Two radio towers. The towers are equal distance apart with an arrow between them. The left tower is labeled X. The right tower is labeled Y. The arrow is pointing from Tower X to Tower Y. What is the role of the part in the diagram labeled Y
capture, amplify, and demodulate waves
Question is incomplete and image is not attached in the question. The required image is attached below, so the complete question is:
What is the role of the part in the diagram labeled Y?
modulate, amplify, and send out waves
capture, amplify, and demodulate waves
change the amplitude and frequency of waves
change the pulse and phase of waves.
What are Radio wave?An example of electromagnetic radiation is radio waves. The wavelength of a radio wave is substantially greater than that of visible light. Radio waves are widely used by people for communication. Both rectangular and circular antennas are used by this radio tower to send and receive radio frequency energy.
The radio receiver, also known as component Y in the figure, is what captures, amplifies, and demodulates radio waves.
The radio receiver uses an antenna to separate the necessary radio frequency signals and consists of an amplifier to boost the strength of the receiving signal. The information from the modulated wave is ultimately recovered by demodulators found in receivers.
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An airplane is flying on a bearing of 170° at 495 mph. Find the component form of the velocity of the airplane. Be sure to show and explain your work.
The horizontal component of the plane's velocity is 85.96 mph and the vertical component of the plane's velocity is 487.5 mph.
Component form of the velocity of the airplane
The component form of the velocity of the airplane includes both horizontal and vertical velocity and it is calculated as follows;
Vx = V cosθ
Vy = V sinθ
where;
Vx is horizontal component of the velocityVy is vertical component of the velocityθ is the angle of the velocity measured with respect to horizontal axisθ = 170 - 90 = 80⁰
Horizontal component of the velocityVx = 495 mph (cos 80)
Vx = 85.96 mph
Vertical component of the velocityVy = 495 mph (sin 80)
Vy = 487.5 mph
Thus, the horizontal component of the plane's velocity is 85.96 mph and the vertical component of the plane's velocity is 487.5 mph.
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In a series lrc circuit, the frequency at which the circuit is at resonance is f0. If you double the resistance, the inductance, the capacitance, and the voltage amplitude of the ac source, what is the new resonance frequency?.
When you double capacitance and inductance, the new resonance frequency becomes halved.
What is Resonance frequency?
It is the natural frequency of an object where it tends to vibrate at a higher amplitude.
The resonance frequency of the LC series circuit is the frequency at which the capacity reactance is equal to inductive reactance.
The formula resonance frequency:
[tex]f_{0} = \frac{1}{2\pi \sqrt{LC} }[/tex]
where;
f0 is the resonance frequency
L is the inductance
C is the capacitance
here, if the capacitance and inductance are doubled, the new resonance frequency becomes;
[tex]f = \frac{1}{2\pi \sqrt{2L2C} }\\f = \frac{1}{2\pi \sqrt{4LC} }\\f = \frac{1}{2*2\pi \sqrt{LC} }\\f=\frac{1}{2} \frac{1}{2\pi \sqrt{LC} }\\f = \frac{1}{2} f_{0}[/tex]
Thus from the above equation for frequency,
When you double capacitance and inductance, the new resonance frequency becomes f(0) / 2.
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A bungee jumper jumps from a bridge and starts accelerating towards a lake below. What energy transfer is he experiencing?
Group of answer choices
a. Elastic potential to kinetic
b. Kinetic to elastic potential
c. Kinetic to gravitational potential
d. Gravitational potential to kinetic
D. The energy transfer he is experiencing is Gravitational potential to kinetic.
Energy transferred experienced by the bungee jumper
The bungee jumper possesses gravitational potential energy due to his position above the ground level (on a bridge).
As he starts accelerating towards a lake below, his gravitational potential energy will be converted into kinetic energy.
Thus, the energy transfer he is experiencing is Gravitational potential to kinetic.
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Two forces of magnitude 10n and 20n acting at an angle of 30 degree. what will be the x component of their resultant force?
The resultant of the forces is 29 N. Option D
What is the resultant force?The resultant force is the force that acts in a given direction. Now we have two forces as enumerated in the question.
Thus;
Resultant = √(10)^2 + (20)^2 - [2 * 10 * 20 * cos (60 - 30))
Resultant = 29 N
Thus, the resultant of the forces is 29 N.
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Missing parts;
Two forces of magnitude 10N and 20N act on a body in directions making angles 30° and 60° respectively with x-axis what is the resultant force
A.17N
B. 19N
C. 23N
D. 29N
E. 37N
If a car increases its velocity from +6 m/s to +30 m/s in 6 seconds, its acceleration in m/s2 is__________.
Answer:
4m/s^2Explanation:
v = 30m/s, u = 6m/s, t = 6s
Change in velocity = v(final velocity) - u (initial velocity)
v-u = 30-6 = 24m/s
acceleration = (v-u)/t
(24m/s)/6s = 4m/s^2
Why is it so much easier to determine the length of the day on mars than on venus?
The thick cloud cover of Venus makes it difficulty in visibility because of impenetrable in visible light which has made it tough for astronomers to measure the length of the planet's day . Whereas Mars have clear atmosphere which do not hinder visibility
The most important reason of why is it difficult to measure the length of the day on Venus is tougher than in mars is that Mars' atmosphere is generally clear because of which their is no visibility issue on mars but due to the thick cloud covering of Venus makes it impenetrable in visible light , due which visibility is not that clear and it become tough to observe the length of the day on Venus.
Mars is much larger than Venus in size which makes easier to observe
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In a given neuron, the current membrane potential is 60 mv. what does this tell you about the current potential compared to the resting membrane potential of 70 mv?
The membrane is depolarized compared to the resting membrane potential.
Through conformational changes from closed, nonconducting states to an open, current-conducting state, membrane depolarization activates sodium channels. Na+ channels open slowly and change from an open state to a nonconducting, rapidly inactivated state as a result of delayed openings, which contribute to the declining fraction of INa induced by prolonged depolarization. Additionally, sodium channels can move swiftly from the closed state to the fast-inactivated state. When the membrane is depolarized, inactivated channels are prevented from opening.
The distribution of channels between the closed and slow-inactivated states, however, limits the number of excitable sodium channels as a function of the membrane potential since slow inactivation acts at greater negative potentials than fast inactivation.
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6 latter word and it has a s and a I and it has mass (9.______________liquids, and gases all have mass.)
Answer:
Solids
Explanation:
Solids, liquids, and gases all have mass.
____________ is the unit that measures the pressure or force that pushes the flow of electrons forward through a conductor.
Volt is the unit that measures the pressure or force that pushes the flow of electrons forward through a conductor.
When there is a circuit having a cell / battery , that cell/battery forms an electric field due to difference in voltages , and set a voltage of value equals to the difference in the voltage of two end of that cell/ battery . Because of which a electric field got set up in the conductor , which pushes electron to move inside the conductor . Unit of voltage is volt .
VOLT - A unit of electrical pressure (or electromotive force) which causes current to flow in a circuit. One volt is the amount of pressure required to cause one ampere of current to flow against one ohm of resistance. VOLTAGE - That force which is generated to cause current to flow in an electrical circuit.
Voltage is the pressure from an electrical circuit's power source that pushes charged electrons (current) through a conducting loop, enabling them to do work such as illuminating a light. In brief, voltage = pressure, and it is measured in volts (V).
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Voltage is the unit that measures the pressure or force that pushes the flow of electrons forward through a conductor.
Voltage is the electrical potential, potential difference and electromotive force in meter , kilogram, second system.The standard unit of measurement used for the expression of voltage is volt which is represent by symbol "V".
High voltage cable is used for electric power transmission at high voltage.A cable that includes conductor and insulation. cable which are considered to be fully interested. That means that they have fully rated insulted system that will consist of insulation , semi-con layers.
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Which of these can happen to energy in a system? Select all that apply.
Group of answer choices
a. It can be converted.
b. It can remain constant.
c. It can be destroyed.
d. It can be created.
A. What can happen to energy in a system is that it can be converted.
What is the principle of conservation of energy?The principle of conservation of energy states that energy can neither be created nor destroyed but can be converted from one form to another.
The energy of a system can be converted from one form to another.
Thus, what can happen to energy in a system is that it can be converted.
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Find the minor measurement of the vernier scale by taking 49, 1mm divisions of the main scale and dividing it into 50 vernier divisions.
length of V-50 = 49mm
length of V-1 = 49/50mm
= 0.98mm
so,
minor measurement = (M-1) - (V-1)
= 1mm -0.98mm
= 0.02mm
☆ Therefore,
The minor measurement of the vernier scale is 0.02mm.
☆...hope this helps...☆
_♡_mashi_♡_
. A coil is wrapped with 400 turns of wire on the perimeter of a circular frame of radius 8.5cm. Each turn has the same area, equal to that of the frame. A uniform magnetic field is turned on perpendicular to the plane of the coil. This field changes at a constant rate from 10.0 to 80.0mT in a time of 20.0ms. What is the magnitude of the induced emf in the coil at the instant the magnetic field has a magnitude of 50.0mT
The emf in the coil when the magnetic field is 50.0 mT is 31.78 V.
What is emf?
According to Faraday's law of electromagnetism, the emf of a coil
is the negative of the rate of change of magnetic flux with respect to time.
The emf of a coil is given by the formula,
[tex]E=-\frac{d\phi}{dt}[/tex]
where E is the emf, dΦ is the change in flux and dt is the change in time.
Magnetic flux: The scalar product of the magnetic field B and the total area vector A perpendicular to it is called the magnetic flux. The magnetic flux for a circular coil with n number of turns is given by,
[tex]\phi=n\pi r^2B[/tex]
where r is the radius of the coil.
Substitute [tex]\phi=n\pi r^2B[/tex] in the above equation and solve it.
[tex]E=-\frac{d(n\pi r^2 B)}{dt}\\E=-n\pi r^2 \frac{dB}{dt}[/tex]
Where dB/dt is the rate of change in the magnetic field with respect to time.
Note: 1mT/ms= 1 T/s, 1 cm= 0.01 m and 1mT=0.001 T
Given the magnetic field changes from 10.0mT to 80.0mT, the change in magnetic field dB = 80-10=70mT. The time interval dt= 20.0ms. Therefore,
dB/dt = 70/ 20 =3.5mT/(ms)
dB/dt = 3.5 T/s
Substitute dB/dt= 3.5T/s, n=400, r=8.5 cm or r=0.085 m in the formula of E and solve it. Since the value of magnitude is positive, ignore the negative sign.
E=400*π*(0.085)^2*(3.5)
E=31.78 V
Since the rate of change of magnetic field is constant, so the magnitude of the emf of the coil will remain the same at all instants. Hence E=31.75 V when the magnitude of the magnetic field is 50.0 T
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Martha is late for class, so she races her 75 kg body up a 4.0 meter flight of stairs in only 2.3 seconds. What is Martha’s power?
Group of answer choices
a. 1,300 W
b. 6,800 W
c. 130 W
d. 680 W
Martha's power is 1,300 W and is denoted as option A.
What is Power?This is defined as the amount of energy used or transferred per unit time and the S.I unit is Watts.
Power = Work/ time
Work = force × distance
= F = ma = 75kg× 10m/s² = 750N
Work = 750N × 4m = 3000J
Power = work/time = 3000J/ 2.3s ≈ 1300W
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A military surveillance satellite is in circular orbit around the Earth at an altitude of 1,000 km above the surface. If the Earth's mass is 5.97 x 1024 kg and its radius is 6,370 km, what is the satellite's orbital speed in m/s
The orbital speed of the satellite is 7.35*10^3 m/s.
What is orbital speed?
The speed of the satellite in its orbit is termed the orbital speed.
The orbital speed is given by the formula,
[tex]v=\sqrt{\frac{GM}{r}}[/tex]
where G is the universal gravitational constant, M is the mass of the planet and r is the distance of the satellite from the center of the planet.
Here the distance of the satellite from the center of the planet is the sum of the planet's radius and the height attained by the satellite above the ground. So
r=6370 + 1000
r=7370 km
Given the mass of the planet is 5.97*10^24 kg and the value of the gravitational constant is 6.67*10^(-11) N m^2 kg^(-2), substitute these values in the formula of the orbital speed.
Note: 1 km=1000 m
[tex]v=\sqrt{\frac{6.67\times10^{-11}\text{ N m}^2\text{kg}^{-2}\times5.97\times10^{24} \text{ kg}}{7370 \text{ km}}} \\ v=\sqrt{\frac{6.67\times10^{-11}\text{ N m}^2\text{kg}^{-2}\times5.97\times10^{24} \text{ kg}}{7370\times 1000 \text{ m}}} \\ v= 7.35\times 10^3 \text{ m/s}[/tex]
Hence the orbital velocity of the satellite is 7.35*10^3 m/s.
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An object moving with 108 km/h moves 400 m in 8 seconds. find the velocity attained by the object.
Answer:50ms-1
Explanation:use the formula v=d/t
in order to find the velocity,devide the distance with time taken.
since distance is 400 meters devide it with seconds whiuch gives us 50.
A sky-diver jumps from a stationary balloon. His initial downwards acceleration is 10m/s².
Fig. 1.1 shows the directions of the air resistance and the weight of the sky-diver.
The mass of the sky-diver is 60 kg and his weight is 600 N.
(a) Explain, using ideas about the forces, why his initial downwards acceleration is 10m/s².
Explanation:
a. The force acting down is gravity, on Earth gravity is 10 m/s^2. When the skydiver jump, the acceleration will start out as -10 m/s^2, but it will eventually equals the air resistance , which is called terminal velocity.
At a point in space an electric force acts vertically upward on an electrion, the directon of the electric field at that point is:____
Answer:
F = Q E force acting on charge Q due to field E
A positive electric field is directed from positive to negative.
An electron will be attracted to the positive terminal.
Thus if the electric force is upwards the direction of the field must be directed downwards, or
if F is positive and Q is negative E must also be negative or downwards.
(taking upwards as positive)
Draw a vector representing the direction of the electric field. The orientation of the vector will be graded. The location and length of the vector will not be graded.
1. E is a vector pointing to the right.
2. E is a vector pointing to the left.
3. E is a vector pointing to the right.
4. E is a vector pointing to the left
What is a Vector ?A vector is an object that has both a magnitude and a direction
Geometrically, we can picture a vector as a directed line segment, whose length is the magnitude of the vector and with an arrow indicating the direction. The direction of the vector is from its tail to its head.Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.Learn more about Vectors here:
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Consider a pipe of length l that is open at both ends. What are the wavelengths of the three lowest-pitch tones produced by this pipe?.
The correct option is D.
The three lowest-pitch tones generated by this pipe have wavelengths of = 2 L, L, 2 L/3
What is meant by wavelength?Measuring a wave's size from one peak to the next is all that is required. The wavelength is only the separation between the crests of the successive waves, if one thinks of a sound wave as being similar to a water wave.
According to the given Information:The length of a pipe with an opening at either end and a length l is given by:
[tex]l=\frac{n \lambda}{2}[/tex]
or
[tex]\lambda=\frac{2 l}{n}[/tex]
Initial pitch tone: n = 1.
[tex]\lambda_{1}=2 l[/tex]
The first pitch tone has n = 2
[tex]\begin{aligned}\lambda_{2} &=\frac{2 l}{2} \\\lambda_{2} &=l\end{aligned}[/tex]
The initial pitch tone has n = 3.
[tex]\begin{aligned}&\lambda_{3}=\frac{2 l}{3} \\&\lambda_{3}=\frac{2 l}{3}\end{aligned}[/tex]
The three lowest-pitch tones generated by this pipe have wavelengths of 2 L, L, and 2 L/3, respectively.
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I understand that the question you are looking for is :
Consider a pipe of length L that is open at both ends. What are the wavelengths of the three lowest-pitch tones produced by this pipe?
Answer
A. 2L, L, L/2
B. 2L, L, L/2
C. 4L, 2L, L
D. 2L, L, 2L/3
E. 4L, 4L/3, 4L/5
A construction worker pushes a 25 kg load in a wheelbarrow for a distance of 5.0 m, using a horizontal force of 50.0 N. How much work is done by the worker on the wheelbarrow?
Group of answer choices
a. 55 J
b. 250 J
c. 1250 J
d. 10 J
B. The amount of work done by the worker on the wheelbarrow is 250 J.
Work done by the workerThe amount of work done by the worker on the wheelbarrow is calculated as follows;
W = Fd
where;
F is applied forced is displacementW = 50 x 5
W = 250 J
Thus, the amount of work done by the worker on the wheelbarrow is 250 J.
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A 1500 pound car is stopped in traffic on a hill that is at an incline of 10. Determine the force that is required to keep the car from rolling down the hill.
A 1500 pound car is stopped in traffic on a hill that is at an incline of 10. The force that is required to keep the car from rolling down the hill will be 1133.53 N.
When all the forces that act upon an object are balanced, then the object is said to be in equilibrium motion. The forces are considered to be balanced if the rightward forces are balanced by the leftward forces and the upward forces are balanced by the downward forces.
It can be observed from the diagram that in order resist the car to rolling down the hill we need to apply an equal and opposite force against the inclined force( that is mgsin(x)) to form an equilibrium position because rolling is associated with horizontal forces hence we need to apply force against the force which can drive down the car .
mass = 1500 pound = 680.39 kg
sin(10) = 0.17
F (counter force ) = m*g*sin(x)
= 680.39 * 9.8 * 0.17
= 1133.53 N
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an interplantetary speedcarft moving at 20000m/s.how far will it travell in one day?(give your answer in km)
Explanation:
Step I: 1 day means 24 hours * 60 minutes * 60 seconds.
So 1 day have 86400 seconds.
Step I:
Now,
To calculate the travel distance 20,000m/s* 84600 is 1728000000m
Step Ill:
Now convert the meter in kilometer
Because 1 km = 1000 m
So, = 1728000000/1000 = 172800OKm
d. e. Study the given diagram and calculate the following: i. work done by load ii. work done by effort iii. M.A iv. V.R v. efficiency [Friction is neglected]
i. The work done by the load is load x distance moved by load.
ii. The work done by effort is effort applied x distance moved by effort.
iii. The mechanical advantage of the simple machine is Load/effort.
iv. The velocity ratio of the simple machine is 2.
v. The efficiency of the machine is M.A/V.R x 100%.
Work done by the loadThe work done by the load is the product of the load and the distance through which the load is moved. The magnitude is calculated as follows;
Work done by the load = load x distance moved by load
Work done by effortThe work done by the effort is the product of the effort and the distance through which the effort is applied. The magnitude is calculated as follows;
Work done by effort = effort applied x distance moved by effort
Mechanical advantage of the simple machineM.A = Load/Effort
Velocity ratio of the simple machineV.R = distance moved by effort / distance moved by load
V.R = 30 cm/15 cm
V.R = 2
Efficiency of the machineE = (M.A/V.R) x 100%
Thus, the work done by the load is load x distance moved by load.
The work done by effort is effort applied x distance moved by effort.
The mechanical advantage of the simple machine is Load/effort.
The velocity ratio of the simple machine is 2.
The efficiency of the machine is M.A/V.R x 100%.
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A 540 gram object is attached to a vertical spring, causing the spring’s length to change from 70 cm to 110 cm.
What is the change in the object’s gravitational potential energy?
Group of answer choices
-2.1 J
-0.84 J
2.1 J
0.84 J
The change in the object’s gravitational potential energy is 2.11 J.
Change in the object's gravitational potential
ΔP.E = mg(hf - hi)
where;
m is mass of the objecthf is final height hi is initial heightΔP.E = 0.54 x 9.8(1.1 - 0.7)
ΔP.E = 2.11 J
Thus, the change in the object’s gravitational potential energy is 2.11 J.
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For vibrational motion, what term denotes the maximum displacement from the equilibrium position?.
For vibrational motion, the amplitude denotes the maximum displacement from the equilibrium position.
What is vibrational motion?
The motion in which there are some vibrations about the fixed position called mean position is termed vibrational motion. For example, the motion of a wave on the string has perpendicular vibration.
What is amplitude?
The amplitude is defined as the maximum displacement of the vibration from its mean position. For vibrational motion, the mean position is the equilibrium position. So amplitude is the term that denotes the maximum displacement from the equilibrium position. For example, the displacement of the string wave from its equilibrium position is the amplitude of the string wave.
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The galaxy M33 is the third largest galaxy in the Local Group after M31 and the Milky Way. The galaxy M33 has a moderate-sized central bulge and two spiral arms that emerge directly out of the bulge and wrap around in rather poorly defined arcs with many cross-connections between the arms. Thus, M33 is classified as a _____ normal spiral.
Galaxy M33 is classified as a Triangulum normal spiral.
The galaxy M33 is the third largest galaxy in the Local Group after M31 and the Milky Way. The galaxy M33 has a moderate-sized central bulge and two spiral arms that emerge directly out of the bulge and wrap around in rather poorly defined arcs with many cross-connections between the arms.
This spiral galaxy is located in the triangle shaped constellation earning a pet name as triangular galaxy. This galaxy star formation rate is ten times higher than average found in Andromeda galaxy. It has relatively bright apparent. This galaxy was given by Charles Messier and he classified it as Triangulum normal spiral.
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