a diffraction grating has 300 lines per mm. if light of frequency 4.76 × 1014 hz is sent through this grating, at what angle does the first order maximum occur? (c = 3.00 × 108 m/s)

Answers

Answer 1

The first-order maximum occurs at an angle of 11.0°

To find the angle at which the first-order maximum occurs, we can use the equation:

sinθ = mλ/d

where θ is the angle of diffraction, m is the order of the maximum (in this case, m = 1 for the first order), λ is the wavelength of light, and d is the distance between adjacent lines on the grating.

First, we need to find the wavelength of light with a frequency of 4.76 × [tex]10^{14}[/tex] Hz. We can use the equation:

c = λf

where c is the speed of light (3.00 × [tex]10^{8}[/tex] m/s) and f is the frequency of light. Rearranging this equation, we get:

λ = c/f

Plugging in the values, we get:

λ = 3.00 × [tex]10^8[/tex] m/s / 4.76 × [tex]10^{14}[/tex] Hz
λ ≈ 6.30 × [tex]10^{-7}[/tex] m

Next, we need to find the distance between adjacent lines on the grating. Since the grating has 300 lines per mm, there are 300 x 10^3 lines per meter. Thus, the distance between adjacent lines is:

d = 1 / (300 x [tex]10^3[/tex]) m
d = 3.33 × [tex]10^{-6}[/tex] m

Now we can plug in these values to find the angle of diffraction:

sinθ = (1)(6.30 × [tex]10^{-7}[/tex] m) / (3.33 × [tex]10^{-6}[/tex] m)
sinθ ≈ 0.189
θ ≈ 11.0°

Therefore, the first-order maximum occurs at an angle of approximately 11.0°.

Know more about First-order maximum here :

https://brainly.com/question/31329426

#SPJ11


Related Questions

a dolphin that just manage to keep up with a speeding boat for a distance of 2km for a period of 3h in (answer in km/h)​

Answers

Answer:

6km

Explanation:

3hours X 2km = 6 kilometres

3. Gather data: Use the values above to fill in the first row of the table. Then run your own experiments to fill
in the last two rows.
f
d.
d,
h.
h,
ร”
S
d
de
2.0
h;
h.
2.0
s.
2.0
S
f
2.0
15
10
30

Answers

Answer:

urjshsus uevus e survey dydvd dydvdyd d dgdv gdyr yrgdvv yth yrhvthr

Explanation:

ydgdydvd yd dv ydvr dyve dysdvdyr gdvr

Two objects, A and B, are in contact with one another. Initially, the temperature of A is 50 °C and the temperature of B is 100 °C. 1. **The particles of which object (A or B) initially have a greater average kinetic energy? How do you know?​

Answers

Answer:

B

Explanation:

because kinetic energy is directly proportional to temperature so the hottor the object, the more kinetic energy.

A 2 kg ball is thrown down with 50J of energy from a height of 10m, what is its velocity before it strikes the ground (neglect air resistance).

Answers

Answer:

V=14

Explanation:

PE=KE

mgh=1/2mv^2

(2)(9.8)(10)=1/2(2)v^2

(radical) 196=(radical) v

V=14

1. Compare the speed that light waves travel in air to the speed that sound waves travel in the air. How many times faster do light waves travel in air in comparison to sound waves in air?
Water-1500 meters per second
steel-5000 meters per second
Air-335 meters per second

Answers

Answer:

895522 times faster.

Explanation:

From the question given above, the following data were obtained:

Speed of sound in air (v) = 335 m/s

Speed of light in air (c) = 3×10⁸ m/s

How many times faster =.?

To obtain how many times faster light travels in air than sound, do the following

c : v => 3×10⁸ : 335

c/v = 3×10⁸ / 335

c/v = 895522

Cross multiply

c = 895522 × v

From the illustrations made above, we can see that the speed of the light in air (c) is 895522 times the speed of sound in air.

Thus, light travels 895522 times faster than sound in air.

A que profundidad esta nadando una persona dentro de una alberca si la presión absoluta sobre ésta es de 156kPa?

Answers

Answer:

La persona está nadando en la alberca a una profundida de 5.575 metros.

Explanation:

La presión absoluta ([tex]P_{tot}[/tex]) experimentada por la persona es la suma de la presión atmosférica ([tex]P_{atm}[/tex]) y la presión hidrostática de la columna de agua de la alberca ([tex]P_{h}[/tex]), medidas en kilopascales. Es decir,

[tex]P_{tot} = P_{atm}+P_{h}[/tex] (1)

[tex]P_{tot} = P_{atm} + \frac{\rho\cdot g \cdot z}{1000}[/tex] (2)

Donde:

[tex]\rho[/tex] - Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.

[tex]g[/tex] - Aceleración gravitacional, medida en metros por segundo al cuadrado.

[tex]z[/tex] - Profundidad de la persona en la alberca, medida en metros.

Si sabemos que [tex]P_{atm} = 101.325\,kPa[/tex], [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] y [tex]P_{tot} = 156\,kPa[/tex], entonces la profundidad de la persona en la alberca es:

[tex]156 = 101.325 +\frac{(1000)\cdot (9.807)\cdot z}{1000}[/tex]

[tex]54.675 = 9.807\cdot z[/tex]

[tex]z = 5.575\,m[/tex]

La persona está nadando en la alberca a una profundida de 5.575 metros.

write any four importance of pressure​

Answers

Answer:

Here is your ans

Explanation:

hope it helps you tq

state and explain the joules law​

Answers

Answer:

Joule’s law of heating states that when a current ‘i ' passes through a conductor of resistance ‘r’ for time ‘t’ then the heat developed in the conductor is equal to the product of the square of the current, the resistance and time.

H = i 2 rt

The reason behind the heat produced is the collision of the free electrons with the lattice ions or atoms while accelerating in presence of the external electric field.

we know that

volt= work done/ total charge or v = w/q

from this we get w= vq

we know that current i = q / t

so q = it

putting this in prev equation

we get w = vit

from ohms law v = ir

putting it in prev eq we get

w = irit = i2rt joule as work is stored as heat soH = I2RT Joules

if a current carrying conductor having resistance (r) gets heated by to passing of current (i) for time (t) and the heat thereby produced be H

joules law states that

H propotional to i^ 2 when r and t are constant

H propotional to r when I and t are constant

H propotional to t when r and I constant

The electromagnetic spectrum is divided into regions by Group of answer choices a.wavelengths and frequencies b.the way they are used c.speed d.colors

Answers

Answer:

Generally, by wavelengths and frequencies.

Colors only occur for a narrow portion of the spectrum.

The speed for these waves is c the speed of light regardless of wavelength.

The way they are used seems somewhat irrelevant.

The electromagnetic spectrum is divided into regions by wavelengths and frequencies. The spectrum is arranged in the order of increasing frequency.

What is electromagnetic spectrum ?

The electromagnetic spectrum is the arrangement of waves in  the  order increasing frequency or decreasing wavelength. The order of the spectra starts from radio waves, microwaves, infrared, visible light, ultraviolet, x -rays and gamma rays.

The visible light that we can see is in between IR and UV rays. Hence, visible light has a frequency greater than IR rays but shorter than IR. Similarly visible light is longer than UV- rays but less frequency than UV rays.

Gamma  rays are the most energetic and shorter waves in the electromagnetic spectrum with smaller wavelength and greater frequency. Hence, options a is correct.

Find more on electromagnetic waves:

brainly.com/question/25559554

#SPJ6

the Himalayas are the highest mountain in the world (positive)​. grammar question

Answers

Answer:

positive degree:

No other peak of the Himalayas is as high as Mount everest

Please help (choose a b or c)
(the image is attached)

In the adjacent circuit, the voltage across the terminals of the dry cell is equal to 12 V.
The value displayed by the voltmeter is:

a- 0 V
b- 12 V
c- -12 V

The two terminals that correspond to the correct connection of a voltmeter in a circuit are:

a- A and COM
b- A and V
c- V and COM​

Answers

I GEUSS A and COM is correct answer to this question

Answer:

1. (a) =0

2.(c) = v and COM

6. Suppose the resistance of your body between your right and left hands is 500,000 N. What
would be the current flowing through your body if you touched the plus and minus terminals of
a 120 V battery? The threshold of sensation for electric current through your body is about
300 PA. Would you feel the current?


HELP PLS

Answers

Explain more please (lesson)


Long Answer Type Questions
1 Can you differentiate between opaque, transparent and translucent objects
2 What is reflection of light?
3. What are the conditions for a shadow to be formed?
4. Prove through an experiment that light travels in straight lines.
5. What is pinhole camera? Explain its working with the help of a diagram
6. What are the main differences between a reflected image and shadows?​

Answers

(1).....opaque -object that not allow light to pass through it

we can't look through opaque objects

ex..wall

translucent... objects that all some light to pass through it

we can partially see through it

ex...coloured glass window

transparent... objects that wholly allow light to pass through it

we can clearly see through it

ex...glass of specs

(2)..the bouncing back of light from a smooth polished surface is called reflection of light

(3)/.....there must be a solid ,opaque to block light

there must be a source of light

there must be a surface to have shadow on it..

(6)...reflected images r formed by light reflection from a smooth polished surface while shadows are formed by blockage of light by an solid,opaque object...

Explanation:

we should talk here thanks

Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of 0.32 m?

Answers

Answer:

Average speed=1.5 m/s

Frequency of pendulum=93.75Hz

Explanation:

We are given

Frequency, [tex]f=0.100Hz[/tex]

Average wavelength =[tex]\lambda=15m[/tex]

Speed of pendulum, [tex]v=30m/s[/tex]

Wavelength, [tex]\lambda'=0.32m[/tex]

We have to find the average speed and frequency of pendulum.

We know that

Speed,[tex]v=\lambda f[/tex]

Using the formula

Average speed,[tex]v=15\times 0.1=1.5m/s[/tex]

Hence, the average speed =1.5m/s

Frequency, [tex]f=\frac{v}{\lambda'}[/tex]

Using the formula

[tex]f=\frac{30}{0.32}[/tex]

[tex]f=93.75Hz[/tex]

Hence, the frequency of a pendulum=93.75Hz

The change in frequency of a wave as its source moves in relation to an observer.
A)
Ultrasound
B)
Frequency
C)
Doppler Effect
D)
Echo

Answers

Answer: B) Frequency

Explanation:

If a storm is 7.5 kilometers away, how much time is expected between observations of lightning and thunder?

Answers

Answer. Time taken to hear the thunder is : 7500 / 343 = 21.88 Seconds.

Answer:

≈ 22 seconds

Explanation:

7,5 km = 7500 m

Speed of light 300 000 000 m/s (for lightning)

Speed of sound 343 m/s (for thunder)

time = distance / speed

lightning time = 7500 m / 300 000 000 m/s = 0.000025 s

thunder time = 7500 m / 343 m/s ≈ 22 s

thunder time - lightning time = 22 s - 0.000025 s ≈ 22 s

how you would orient the magnets and what you would do with the magnets to achieve maximum repulsion

Answers

The orientation of the magnets that gives the strongest repulsion because these poles and facing each other that is then leaves highest flux density of the poles for a force of repulsion to be very high

a ball rolled a velocity of 20m/s after 5s it comes to stop what is the acceleration of the ball​

Answers

Answer:

please find the attached pdf

Explanation:

What is the SPEED of a train that travels 15000 meters in 1200 seconds (20 minutes)?

PLEASE SHOW WORK!!!! EASY POINTS!!!!

Answers

Answer:

27.9617 mi/h

Explanation:

Speed= distance/time

S= 15000/1200

True or false. Your weight will change on the moon

Answers

The answer to this is true
hi! i searched online, and it says an object on the moon weighs less than it does on earth, so true.

hope this helps!:)

The ability of a halogen to react with a metals to form a salt is an example of a ________________ property.

Answers

The answer is a CHEMICAL property.

If a girl walks 6km due west changes directions and walk another 5km due north. Find her displacement in both magnitude and direction

Answers

Answer:

the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.

Explanation:

Given;

6km due west, and

5km due north

The magnitude of her displacement is calculated by forming a right angled triangle. The hypotenuse side of the triangle is the girl's displacement.

d² = 5² + 6²

d² = 25 + 36

d² = 61

d = √61

d = 7.81 m

The direction of the girl is calculated as;

[tex]tan \ \theta = \frac{6}{5} \\\\tan \ \theta = 1.2\\\\\theta = tan^{-1} (1.2)\\\\\theta = 50.2^0[/tex]

Therefore, the girl's displacement in both magnitude and direction is 7.81 m at 50.2⁰ North west.

All weather stations have to make weather observations at the same time of the day.

True
False

Answers

Answer:

false

Explanation:

Answer:

True

Explanation:

The answer is true do not listen to the other person they will get you wrong just look at the votes between mine and the other person's (hint like my answer and rate 5 stars so other people know what to pick)

5. A car accelerates from 0 to 72 km/hour in 8.0 seconds. What is the car's acceleration?

Answers

Answer:

2.5 m/s

Explanation:

There are calculators online that can help you easily calculate the accerlation.

what's 4 x 5
i need help with this question please

Answers

4 x 5 is equal to 20. Use a calculator it’s way faster :))

Answer:

4 × 5 = 5 + 5 + 5 + 5 = 20

Explanation:

Pick one factor and add it.

Mercury has the most eccentric (least circular) orbit of all the planets in the Solar System. At aphelion it is 0.467 AU from the Sun while at perihelion it is only 0.308 AU from the Sun. What is Mercury's orbital period in Earth-days?

Answers

Answer:

Mercury's orbital period is approximately 88 days

Explanation:

Mercury's orbit parameters given in the question are;

Mercury's aphelion distance, Rₐ = 0.467 AU

Mercury's perihelion distance, [tex]R_p[/tex] = 0.308 AU

Therefore, the average distance from Mercury to the Sun, 'a', is given as follows;

[tex]a = \dfrac{R_a + R_p}{2}[/tex]

By plugging in the values of 'Rₐ' and '[tex]R_p[/tex]', we get;

[tex]a = \dfrac{R_a + R_p}{2} = \dfrac{0.467 \, AU + 0.308 \, AU}{2} = 0.3875 \, AU[/tex]

a = 0.3875 AU

According to Kepler's third law, we have;

P² = k·a³

Where;

P = The orbital period of the plane

a = The average distance from Mercury to the Sun

k = Constant

When k = 1, we have;

P² = a³

∴ P = √(a³)

From which we have;

P = √(0.3875 AU)³ ≈ 0.241216804711 years

P ≈ 0.2412168 years

1 year = 365 days

∴ 0.241216804711 years = 0.241216804711 years × 365 days/year ≈ 88.0441337 days

0.241216804711 years ≈ 88.0441337 days ≈ 88 days

Mercury's orbital period, P ≈ 88 days.

Motion and acceleration may only be used to refer to physical objects moving or changing speed/direction

Answers

Answer:

True

Explanation:

It is TRUE that Motion and acceleration may only be used to refer to physical objects moving or changing speed/direction.

This is because if an object is not moving or changing speed/direction to a determined point of reference, the object is considered to be at rest or motionless, thereby, with no absolute point of reference, absolute motion or acceleration cannot be distinguished.

The electrostatic force between two charged metal spheres is 2N. If the charge on each sphere is doubled, what is the new force between the spheres?

Question 2 options:
A. 2N
B. 4N
C. 1N
D. 8

Answers

Answer:

8 N

Explanation:

The force between two charges is given by :

[tex]F=\dfrac{kq_1q_2}{d^2}[/tex]

Where

k is electrostatic constant

d is the distance between two charges

It means,

[tex]F\propto \dfrac{1}{d^2}[/tex]

When the distance is d, the force is 2 N. If the charge on each sphere is doubled, q₁' = q₂' = 2q₁ = 2q₂. New force will becomes:

[tex]F'=\dfrac{kq_1'q_2'}{d^2}\\\\F'=\dfrac{k2q_1\times 2q_2}{d^2}\\\\F'=4\times \dfrac{kq_1q_2}{d^2}\\\\F'=4\times 2\\\\F'=8\ N[/tex]

So, the new force becomes 8N. Hence, the correct option is (d).

what are the unique characteristics of romantic music which are not present in Original Pilipino Music (OPM)​

Answers

Answer:

ITU Sangat bermanfaaat

14. If 100 grams of sodium nitrate are dissolved in 100 grams of water
at 60 degrees C, is the solution formed saturated, unsaturated, or
supersaturated?

Answers

Answer:

Unsaturated

Explanation:

the solubility of sodium nitrate is at 60 C is 124g/ml therefore, putting 100 grams will not saturate fully.

Other Questions
What is my favorite color? correct answer will get points! What is the peak wavelength of light coming from a star with a temperature of 4,300 K?(Submit your answer in nanometers. Remember 1nm = 10^-9 m)(CH 6) A 63. 0 kg sprinter accelerates at a rate of 4. 20 m/s2 for 20 m, and then maintains that velocity for the remainder of the 100-m dash, what will be his time for the race? what kind of protein keeps the wnt pathway inactive? The Taguchi quadratic loss function for a part in snow blowing equipment is L(y) 4000(y m2 where y-actual value of critical dimension and m is the nominal value. If m100.00 mm determine the value of loss function for tolerances (a) 0.15 mm and (b) 0.10 mm. Consider R={(0,1),(1,0),(0,2)} on A={0,1,2,3}. Find the reflexive closure, the symmetric closure, the transitive closure, and the reflexive transitive closure. .A Hydrogen atom actually absorbs a photon of unknown energy. The electron is originally in the n=2 energy level. What CANNOT happen next?The electron stays in the n=2 stateThe electron travels to the n=4 stateThe electron travels to the n=1 state, emitting another photonThe electron escapes from the atom entirely, ionizing the atomAll of these are possibilities Bob falls off a building landing on his calcaneus, which bones or structures would most likely be fractured from this fall?A.Carpal, radius, humerus, scapulaB.Coccyx, ischium, pubis, illiumC.Cuboid, fibula, ulna, humerusD.Talus, tibia, femur, fibula (1pts) experimental melting point of recovered benzoic acid (c) saved (2pts) literature melting point of benzoic acid (c) Given a standard Normal Distribution, find the area under the curve which lies? a. to the left of z=1.96 b. to the right of z= -0.79 c. between z= -2.45 and z= -1.32 d. to the left of z= -1.39 e. to the right of z=1.96 f. between z=-2.3 and z=1.74 Please help me :(What is the measure of p in the following diagram?PS: Its in a Chapter 11 Go math book! Maybe... can you help me pls? Much of the data associated with you on the internet is collected without your knowledge, or consent. O True O False Sales related transactions Sayers Co. sold merchandise on account to a customer for $86,000 terms 2/10, n/30. The cost of the goods sold was $63,000. a. Journalize Sayers entries to record the sale. b. Journalize the receipt of payment within the discount period. c. Journalize the entry to record the recaipt of payment beyond the discount period of ten days. FILL IN THE BLANK according to freud, the _____ mind is the part of the mind that contains all the information that you are not currently thinking about, but could easily bring to mind. 26. a person can usually resume normal activity with no limitations when a fracture Let X have a uniform distribution on the interval [a, b]. Obtain an expression for the (100p) th percentile. Compute E(X), V(X), and sigma_2. For n a positive integer, compute E(X^n) Move the descriptions and examples to their correct category to review the four types of hypersensitivity states mmediate sensitivity Type I Type II Type IgG complexes in basement membranes Type IV SLE, rheumatoid arthritis serum sickness IgE-mediated, involving mast cells and basophils mediated Anaphylaxis, allergies asthma Blood group Delayed hypersensitivity T-cell-mediated Contact dermatitis, graft rejection Involve lgG and IgM Reset true/false. a motor-compressor must be protected from overloads and failure to start by a time-delay fuse or inverse-time circuit breaker rated at not more than ____ percent of the rated load current.' Look at the map. Which statement best describes the location of the aridclimate zone? A proton (mass = ) moves with an initial velocity at the origin in a uniform magnetic field . To an observer on the negative x axis the proton appears to spiral:in the ____counter-clockwise clockwise