45000 tiles we need to fill a room with area 1080 m²
What is Parallelogram?A parallelogram is a simple quadrilateral with two pairs of parallel sides.
Area of floor =1080m²
Base of parallelogram shaped tile (b) =24 cm
and corresponding height (h)=10 cm
Area of one tile=b×h
=24×10
=240 cm²
=240/10000=24/1000 m²
Number of tiles required=1080/(24/1000)
=1080×1000/24
=45000 tiles
Hence, 45000 tiles we need to fill a room with area 1080 m²
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120 increased by d percent and increased by 25 percent. what is the result?
Using proportions, the expression for the final amount is:
150(1+d).
What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three.
For this problem, we have that:
The increase of d% is equivalent to a multiplication by (1 + d).The increase of 25% is equivalent to a multiplication by 1.25.Hence the equivalent expression is:
120 x 1.25 x (1 + d) = 150(1+d).
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A bagel shop sells coffee in a container shaped like a rectangular prism. A graphic designer who works for the bagel shop drew the net below to create a design for the container.
1598 cm square is the area of the container.
According to the statement
we have given that the container is rectangular prism
And Length of rectangular prism is 34cm
Width of rectangular prism is 17 cm
Height of rectangular prism is 20 cm
we use the below written formula to find the surface area
Surface area formula A=(wl+hl+hw)
To find the surface area of the container.
Substitute the values of Length, width and height in the formula then
A=(wl+hl+hw)
A=((17)(34)+(20)(34)+(20)(17))
After solving the values
A=(578+680+340)
A= 1598
So, 1598 cm square is the area of the container.
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56m² = ____________ GCF =
68m² = ____________ GCF =
The greatest common factor of the expression is 4m⁴.
What is GCF?GCF simply means the greatest common factor.
The greatest common factor (GCF) of a set of numbers is the largest factor that all the numbers share.
Hence,
56m⁵
68m⁴
The greatest common factor of the expression is the largest positive expression that divides evenly into all numbers with zero .
Hence, the greatest common factor is 4m⁴
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In 2012, the population of a city was 6.38million. The exponential growth rate was 2.38% per year.
a) Find the exponential growth function.
b) Estimate the population of the city in 2018.
c) When will the population of the city be 9million?
d) Find the doubling time.
Question content area bottom
Part 1
a) The exponential growth function is P(t)
enter your response here, where t is in terms of the number of years since 2012 and P(t) is the population in millions.
The exponential growth function is P(t) = 6.38 million x (1.0238^t).
The population of the city in 2018 is 7.35 million.
The year the population would be 9 million is 14.46 years.
The doubling time is 29.12 years.
What is the exponential growth function?FV = P (1 + r)^n
FV = Future populationP = Present populationR = rate of growthN = number of years6.38 million x (1.0238^t)
Population in 2018 = 6.38 million x (1.0238^6) = 7.35 million
Number of years when population would be 9 million : (In FV / PV) / r
(In 9 / 6.38) / 0.0238 = 14.46 years
Doubling time = In 2 / 0.0238 = 29.12 years
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Assignment
Slide the green dot from 0 to plot the number at the correct
location.
Plot-1.
-6 -5 4 -3 -2 -1 0 1
2
3 4
5
+
6
Use the interactive number line to find each sum to
complete the table.
A
1
-1
-4
-6
B
2
-2
1
-3
A + B
3
R
S
T
From the number line, the values which completes the sum in the table are:
R = -3.S = -3.T = -9.What is a number line?A number line can be defined as a type of graph with a graduated straight line which contains both positive and negative numerical values that are placed at equal intervals along its length.
How to find each sum?From the table of values (see attachment), the values on the number line are represented as follows:
a + b = a + b
R = -1 - 2
R = -3.
a + b = a + b
S = -4 + 1
S = -3.
a + b = a + b
T = -6 - 3
T = -9.
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Consider the equation x+4=−2x+19. Let f(x)=x+4and g(x)=−2x+19. The graph of each function is shown. Coordinate plane with the graphs of two lines. The horizontal x axis labeled from negative three to nine in increments of one. The vertical y axis labeled from negative two to nineteen. The line f of x passes through ordered pairs zero comma four and two comma six. The line g of x passes through the ordered pairs zero comma nineteen and one comma seventeen. At what point do the graphs intersect? Enter your answer in the box.
The point of intersection of both graphs will have the coordinate (5, 9).
What is the Point of Intersection of the Graph?
We are given the functions;
f(x) = x + 4
g(x) = -2x + 19
Now, the point of intersection of both graphs is when both functions are equal which is at f(x) = g(x). Thus;
x + 4 = -2x + 19
x + 2x = 19 - 4
3x = 15
x = 15/3
x = 5
Thus;
f(x) = 5 + 4 = 9
g(x) = -2(5) + 19 = 9
Thus, the point of intersection of both graphs will have the coordinate (5, 9)
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The current in a stream moves at a rate of 7 mph. If a boat travels 98 miles downstream in the same time that it takes to travel 49 miles upstream, what is the speed of the boat in still water?
The answer is x=21 the explanation is on the picture above I hope I helped
If the current in a stream moves at a rate of 7 mph. If a boat travels 98 miles downstream in the same time that it takes to travel 49 miles upstream then the speed of the boat in still water is 21 miles per hour.
What is speed?Speed is the distance covered by an object in a certain time period. It is also known as velocity. The formula of speed is as follows:
Speed=Distance/ Time.
How to calculate speed?We have been given that the speed of stream is 7miles per hour.
Let v be the speed of the boat, and t the time to travel
98=t*(7+v) (1)
49=t(v-7) (2)
(1)+(2) => 2tv=147
7t+(49+7t)=98
14t+49=98
14t=49
t=49/14
t=7/2
Put the value of t in equation 1 to get the value of v:
98=t(7+v)
98=7/2(7+v)
196/7=7+v
28=7+v
v=28-7
v=21
Hence if the current in a stream moves at a rate of 7 mph. If a boat travels 98 miles downstream in the same time that it takes to travel 49 miles upstream then the speed of the boat in still water is 21 miles per hour.
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14-yard fishing line is cut into two pieces. Three times the length of the longer piece is four times the length of the shorter piece. Find the length of each piece.
(Hint: Let x = smaller piece...)
Answer:
The small piece is 6 yards and the large piece is 8 yards.
Step-by-step explanation:
Let x = small
Let y = large
x + y = 14 3y = 4x
3y = 4x Divide both sides of the equation by 3 to solve for y
y = [tex]\frac{4}{3}[/tex] x Plug [tex]\frac{4}{3}[/tex] x in for y in the first equation above.
x + y = 14
x + [tex]\frac{4}{3}[/tex] x = 14 x and 1 x mean the same thing. Another name for 1 is [tex]\frac{3}{3}[/tex]
[tex]\frac{3}{3}[/tex]x + [tex]\frac{4}{3}[/tex]x = 14
[tex]\frac{7}{3}[/tex]x = 14 Multiple both sides by [tex]\frac{3}{7}[/tex] to solve for x
([tex]\frac{3}{7}[/tex])([tex]\frac{7}{3}[/tex]x) = 14([tex]\frac{3}{7}[/tex]) you can write 14 as [tex]\frac{14}{1}[/tex]([tex]\frac{3}{7}[/tex]) = [tex]\frac{42}{7}[/tex]= 6
x = 6
If x = 6, then y must be 8 because 6 + 8 = 14
find the value of x and y
Pls help me I'm stuck
The measure of the angle BAM is approximately 40.894°.
What is the angle withing a rectangle?
In this problem we proceed to draw the figure representing the entire figure and labeling all known lengths, both from statement and derived from Pythagorean theorem. Since the angle BAM is part of a right triangle, then we can apply the following trigonometric function:
[tex]\tan \theta = \frac{BM}{AB}[/tex]
[tex]\tan \theta = \frac{\frac{\sqrt{3}}{2}\cdot x }{x}[/tex]
[tex]\tan \theta = \frac{\sqrt{3}}{2}[/tex]
θ ≈ 40.894°
The measure of the angle BAM is approximately 40.894°.
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Some boys and girls are waiting for school buses. 25 girls get on the first bus. The ratio of boys to girls at the stop is now 3:2. 15 boys get on the second bus. There are now the same number of boys and girls at the bus stop. How many students were originally at the bus stop?
Answer:
100
Step-by-step explanation:
Forming algebraic equations and solving:
Let the number of boys originally at the stop = 'x'
Let the number of girls originally at the stop = 'y'
25 girls get on the first bus.
⇒ The number of girls now at the stop = y -25
Ratio of boys to girls:
[tex]\sf \dfrac{x}{y -25}= \dfrac{3}{2}\\\\Cross \ multiply,\\\\2x = 3*(y- 25)\\\\2x = 3y - 3*25\\\\2x = 3y - 75 ------[/tex](I)
15 boys get on the second bus.
Now, the number of boys at the stop = x - 15
Number of girls at the stop = y - 25
Ratio of boys to girls,
[tex]\sf \dfrac{x - 15}{y -25} = \dfrac{1}{1}\\\\Cross \ multiply, \\\\x - 15 = y -25\\\\[/tex]
x = y -25 + 15
x = y - 10
Plugin x = y - 10 in equation (I)
2*(y-10) = 3y -75
2y - 20 = 3y -75
-20 = 3y - 75 - 2y
-20 = y -75
-20 +75 = y
[tex]\sf \boxed{\bf y = 55}[/tex]
Plugin y = 55 in equation (I)
x = 55 -10
[tex]\sf \boxed{\bf x = 45}[/tex]
Number of students originally at the stop = x + y
= 55 + 45
= 100
Question is attached as an image
The general solution of the logistic equation is [tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex].
The particular solution of the logistic equation is [tex]y(t) = \frac{14}{1 + 0.4 \cdot e^{-\frac{14\cdot t}{3} }}[/tex].
What are the general and particular solutions of the logistic equation?
In this question we are before a type of ordinary differential equation known as equation with separable variables, that is to say, that variables t and y can be separated at each side of the expression in order to find a solution:
dy / dt = 3 · y · (1 - y /14)
dy / [(- 3 / 14 ) · y · (y - 14)] = dt
Then, we simplify the expression by partial fractions and integrate the resulting expression:
- (1 / 14) ∫ dy / y + (1 / 14)∫ dy / (y - 14) = - (14 / 3)∫ dt
- (1 / 14) · ㏑ |y| + (1 / 14) · ㏑ |y - 14| = - (14 / 3) · t + C, where C is the integration constant.
㏑ |(y - 14) / y| = - (14 / 3) · t + C
[tex]1 - \frac{14}{y} = C\cdot e^{-\frac{14\cdot t}{3} }[/tex]
[tex]\frac{14}{y} = 1 - C \cdot e^{-\frac{14\cdot t}{3} }[/tex]
[tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex]
The general solution of the logistic equation is [tex]y(t) = \frac{14}{1 - C\cdot e^{-\frac{14\cdot t}{3} }}[/tex].
If y(0) = 10, then the particular solution of the differential equation is:
10 = 14 /(1 - C)
1 - C = 1.4
C = - 0.4
The particular solution of the logistic equation is [tex]y(t) = \frac{14}{1 + 0.4 \cdot e^{-\frac{14\cdot t}{3} }}[/tex].
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I cant figure this one out pls help
The value of x from the given expression is -2
Slope of a lineThe formula for calculating the slope of a line is expressed as:
Slope = y2-y1/x2-x1
Given the following parameters
m = 1
(x1, y1) = (0, 2)
(x2, y2) = (x, 0)
Substitute
1 = x-0/0-2
1 = x/-2
x = -2
Hence the value of x from the given expression is -2
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Question 1 (3 points)
Solve the following linear system:
y = -2x - 5
y = 2/3x + 3
as an ordered pair (x,y)
Answer:
Step-by-step explanation:
hello : y = -2x - 5
y = 2/3x + 3
means : -2x-5 = 2/3 x+3
-6x-15 = 2x +9
-8x=24 so : x = -3
put the value for : x in the first equation :y = -2(-3)-5 =1
the ordered pair (-3;1) is solution
Prove that (- 1 + i)^7 = -8(1 + i)
Convert [tex]-1+i[/tex] to polar form.
[tex]z = -1 + i \implies \begin{cases}|z| = \sqrt{(-1)^2 + 1^2} = \sqrt2 \\\\ \arg(z) = \pi + \tan^{-1}\left(\dfrac1{-1}\right) = \dfrac{3\pi}4 \end{cases}[/tex]
By de Moivre's theorem,
[tex]\left(-1+i\right)^7 = \left(\sqrt2 \, e^{i\,\frac{3\pi}4}\right)^7 \\\\ ~~~~~~~~ = \left(\sqrt2\right)^7 e^{i\,\frac{21\pi}4} \\\\ ~~~~~~~~ = 8\sqrt2 \, e^{-i\,\frac{3\pi}4} \\\\ ~~~~~~~~ = 8\sqrt2 \left(\cos\left(\dfrac{3\pi}4\right) - i \sin\left(\dfrac{3\pi}4\right)\right) \\\\ ~~~~~~~~ = 8\sqrt2 \left(-\dfrac1{\sqrt2} - \dfrac1{\sqrt2}\,i\right) \\\\ ~~~~~~~~ = -8 (1 + i)[/tex]
QED
a cylinder and a cone have the same radius and height. The volume of the cylinder is 534ft3 . what volume of the cone?
Answer: 178 ft^3
Step-by-step explanation:
A cylinder has the formula V=pi radius ^2 height
A cone has the formula V= 1/3 pi radius ^2 height
So 1/3 of the volume of the cylinder is the volume of a cone
1/3 of 534 = 178 ft^3
3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared the insect endangered and transplanted the insect to protected area. The population P(t) (in thousands) of insects in t months after being transplanted is
a. [3 pts] Determine the number of months until the insect population reaches 40 thousand (round to 2 decimal places).
b. [3 pts] What is the limiting factor on the insect population as time progresses? Explain your answer.
c. [3 pts] Sketch a graph of the function using the window and. Be sure to indicated the scale on the graph, label the axes, at least 2 points on the graph, and any asymptotes.
The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.
Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).
(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get
P(t)=40
(50(1+0.05t))/(2+0.01t)=40
Cross multiply both sides, we get
50(1+0.05t)=40(2+0.01t)
Apply the distributive property a(b+c)=ab+ac, we get
50+2.5t=80+0.4t
Subtract 0.4t and 50 from both sides, we get
50+2.5t-0.4t-50=80+0.4t-0.4t-50
2.1t=30
Divide both sides with 2.1, we get
t=14.29 months
(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get
[tex]\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end[/tex]
(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.
Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.
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Calculate the following ratios, correct to 3 decimal places. a. sin 58 = b. cos 26 = c. tan 63=.
Answer: sin(58) = 0.848, cos(26) = 0.898, and tan(63) = 1.962
Step-by-step explanation:
1
Select the correct answer from each drop-down menu.
Ray and Terry work in the same office. They sit across from each other at fixed desks that are separated by a partition, or a short dividing wall,
exactly halfway between them. The distance between the end of each desk and the partition is 35 inches. For both Ray and Terry, the top of the
partition is at an angle of elevation of 30° with respect to the end of the desk. This scenario can be modeled by the given diagram.
Ray has the incorrect reasoning because he incorrectly select the sine function when he should have utilized the tangent.
How to find the height of a right triangle?A right angle triangle is a triangle that has one of its angles as 90 degrees.
The height of the ray can be found using trigonometric ratios.
Therefore,
tan 30 = opposite / adjacent
where
opposite side = height
adjacent side = 35 inches
Therefore,
tan 30° = height / 35
cross multiply
height = 35 tan 30°
height = 20.2072594216
height = 20.21 inches
Therefore, Ray has the incorrect reasoning because he incorrectly select the sine function when he should have utilized the tangent.
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Answer:
1. Ray
2. Sine
3. Tangent
Step-by-step explanation:
Plato/Edmentum
lim f(x) 2^x-1/x. Find the limit of x as x approaches 0
The limit happens to be the derivative of [tex]2^x[/tex] at [tex]x=0[/tex]:
[tex]\displaystyle f'(c) = \lim_{x\to c}\frac{f(x)-f(c)}{x-c} \implies \lim_{x\to0} \frac{2^x - 1}x = (2^x)'\bigg|_{x=0} = \ln(2)\,2^x \bigg|_{x=0} = \boxed{\ln(2)}[/tex]
What is the solution (1/4)x+1=32
[tex] \frac{1}{4} x + 1 = 32 \\ \frac{1}{4} x = 32 - 1 \\ \frac{1}{4} x = 31 \\ x = 31 \times 4 = 124[/tex]
The answer is 124.
(1/4)x + 1 = 32(1/4)x = 31x = 31(4)x = 124In ΔABC, BC = 13, CA = 20 and AB = 19. Which statement about the angles of ΔABC must be true?
m∠B > m∠ A > m∠C
m∠C > m∠B > m∠A
m∠A > m∠B > m∠C
m∠C > m∠A > m∠B
m∠B > m∠C > m∠A
m∠A > m∠C > m∠B
Answer:
m∠B > m∠C > m∠A
Step-by-step explanation:
The angle opposite the largest side in a triangle is the largest, and the angle opposite the shortest side is the smallest.
Which equation can be used to solve for b?
Triangle A B C is shown. Angle B C A is a right angle and angle C A B is 30 degrees. The length of side B C is 5 centimeters, the length of B A is 10 centimeters, and the length of C A is b.
tan(30o) = StartFraction 5 Over b EndFraction
tan(30o) = StartFraction b Over 5 EndFraction
tan(30o) = StartFraction 10 Over b EndFraction
tan(30o) =
Answer:
[tex]tan(30) = \frac{5}{b} [/tex]
Step-by-step explanation:
Trigonometric Ratios.
To solve for b, we check the parameters that are given in the triangle.
If we're considering 30°, we can see that the opposite is given as 5cm and the adjacent is b.
Applying:
[tex]tan \alpha = \frac{oppsite}{adjacent} \\ \\ tan \: (30) = \frac{5}{b} [/tex]
Answer:
a
Step-by-step explanation:
just did the quiz!!!!
Does this represent a proportional relationship
Answer:
D.
Step-by-step explanation:
the suggested relation can be described as y=15x. Then the correct answer is D) Yes, the points are on the line that passes through the origin.
A 8 gram sample of a substance that's a by-product of fireworks has a k-value of 0.1027. Find the substance's half-life, in days. Round your answer to the nearest tenth
The substance's half - life is 7 days
How to determine the half-life
The formula for finding the half - life is given as;
Half - life = [tex]\frac{0. 693}{k}[/tex]
The k value given is 0.1027
Half - life = [tex]\frac{0. 693}{0.1027}[/tex]
Half - life = 6. 75
Half - life = 7 days in the nearest tenth
Thus, the substance's half - life is 7 days
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In the following activity, write an equation to represent each verbal statement, and use it to find the value of each unknown number. Then, put the solution values in order from smallest to largest. [Note: The smallest solution is "first", and the largest solution is "fifth".]
The solution values in order from smallest to largest are;
-13 - First-10 - Second-3.5 - Third-2 - Fourth-0.75 - FifthUnknown equationlet
the unknown number = x(x - 5)-2 = 14
-2x + 10 = 14
-2x = 14 - 10
-2x = 4
x = 4/-2
x = -2
4x - 5 = -8
4x = -8 + 5
4x = -3
x = -3/4
x = -0.75
(x + 3) / 5 = -2
x + 3 = -2(5)
x + 3 = -10
x = -10 - 3
x = -13
1/2x + 4 = -1
1/2x = -1 - 4
1/2x = -5
x = -5 ÷ 1/2
= -5×2/1
x = -10
x + 2 = 6/-4
-4(x + 2) = 6
-4x - 8 = 6
-4x = 6 + 8
-4x = 14
x = 14/-4
x = -3.5
Therefore, the smallest value is -13 and the largest value is -0.75.
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just need b1 and b2
brainliest to whoever answers
50 points
Step-by-step explanation:
b1) Any line parallel to the x-axis is horizontal. If we look at the graph of a horizontal line, we see that for any x-value you give, the y-value will be the same. In this case, the y-value is -1. Hence, the equation for the line is [tex]y=-1[/tex], as y will be -1 no matter the x.
The gradient for a horizontal line is 0, as the "rise" of the function is 0. If we use the formula [tex]\frac{rise}{run}[/tex], we would have 0 on the top, which makes the whole fraction 0.
b2) Any line parallel to the y-axis is vertical. If we look at the graph of a vertical line, we see that for any y-value, the x-value will be the same. In this case, the x-value is -1. Hence, the equation for the line is [tex]x=-1[/tex], as x will be -1 no matter the y.
The gradient for a vertical line is undefined, as the "run" of the function is 0. If we use the formula [tex]\frac{rise}{run}[/tex], we would be dividing by 0, which is undefined.
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used
Match each statement with its contrapositive.
Option 4,option 6, and option 2 is the respective contrapositive to the statements given. This can be obtained by understanding what contrapositive is and converting the statements.
What is contrapositive? Contrapositive: A statement which is obtained by interchanging both the hypothesis and conclusion of a given statement after contradicting them. For "if p then q" the contrapositive is "if not-q,then not-p "For example,Statement = If a figure is a square, then it is a quadrilateral.
Contrapositive = If a figure is not a quadrilateral, then it is not a square.
Here,
Statement 1: If two figures are congruent, then their corresponding sides are equal.Contrapositive: If the corresponding sides of two figures aren't equal, then the two figures aren't congruent. (Option 4)
Statement 2: If two numbers are even, then their product is even.Contrapositive: If the product of two numbers isn't even, then the two numbers aren't even. (Option 6)
Statement 3: If a figure is a pentagon, then the sum of its interior angles is 540°.Contrapositive: If the sum of the interior angles of a figure isn't 540°, then the figure isn't a pentagon. (Option 2)
Hence Option 4,option 6, and option 2 is the respective contrapositive to the statements given.
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The following are the ages (years) of 5 people in a room:
14
,
16
,
16
,
13
,
A person enters the room.
The mean age of the 6 people is now 21.
What is the age of the person who entered the room?
Answer:
67 years old. (you only gave 4 people and missed out one person)
Step-by-step explanation:
take all the ages first and put the unknown (age of the person who entered the room) as x.
14, 16, 16, 13, x
all of these numbers added to together would be:
59 + x
Because the question is talking about the mean age, to find mean:
add all the values in the data (ages) and divide by the total number of values on the list. (in your case would be 6 people (following your question) but you gave only 5 people including the x).
then (59 + x) / 6 = 21
21 x 6 = 126
126 = 59 + x
x = 67
A and B are independent events. P(A) = 0.60 and P(B) = 0.30.
What is P(A and B)?
A. 0
B. 0.18
C. 0.90
D. 0.018
Answer: 0.18
Step-by-step explanation:
The probability of the event P(A and B) is equal to 0.18.
The correct option is (C).
What is Probability?A random event's occurrence is the subject of this area of mathematics. The range of the value is 0 to 1. Probability has been introduced in Arithmetic to forecast how likely occurrences are to happen.
As per the given data:
We are given the probability of two events:
P(A) = 0.60 and P(B) = 0.30
We are also given that A and B are independent events.
To find the probability of P(A and B):
The term and is equivalent to the term intersection.
P(A and B) = P(A∩B)
For any 2 independent events A and B the probability P(A∩B) is given by:
= P(A) × P(B)
By substituting the given values in the question
= 0.60 × 0.30
= 0.18
The probability of the event P(A and B) is equal to 0.18.
Hence, The probability of the event P(A and B) is equal to 0.18.
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