The name given to it is "terminal velocity".
In reality, it isn't a velocity, and it doesn't happen in free-fall.
Go figure.
I need help with this someone help me?
¿Qué juegos se practicaban en esa Época? ¿Qué nombre tenían los juegos? ¿En qué consistía cada uno de los juegos? ¿Cómo se iniciaba y finalizaba el juego?
La respuesta correcta para esta pregunta abierta es la siguiente.
A pesar de que se te olvidó especificar el país al que te refieres y a la fecha específica para saber de qué época estás hablando, te podemos ayudar comentando lo siguiente.
¿Qué juegos se practicaban en esa Época?
Anterior al surgimiento de la era digital y la era de los "gammers," los niños y la juventud en general salían a la calle o al parque a realizar diferentes actividades físicas y recreativas. Había juegos de ronda, juegos deportivos, juegos de destreza, y juegos de mesa.
¿Qué nombre tenían los juegos?
Había juegos que se llamaba "Doña Blanca," "La Roña," "Lobo estás ahí," "Las escondidas," "canicas," el yoyo," "el trompo," "el burro castigado," "las cebollitas," "el látigo," además de las "cascaritas" que eran juegos de soccer o futbol americano en las calles y con equipos formados por tus amigos.
¿En qué consistía cada uno de los juegos?
Si jugabas canicas, tenías que golpear una canica con otra para desplazarla y llevarla a cierto lugar. O tenías que meterla en agujeros.
Si jugabas, "Doña Blanca," formabas un círculo entrelazado de las manos. Mientras cantabas la canción de Doña Blanca, alguien que estaba afuera del círculo trataba de romperlo, tratando de soltar algunas de las manos entrelazadas.
La verdad era sumamente divertido, creativo, te reías, mucho, y lo mejor de todo era que hacías ejercicio y no te quedabas sentado todo el día frente a una pantalla de computadora.
Charge is distributed uniformly throughout the volume of an infinitely long solid Cylinder of radius R what is the electric field when r < Select one : O a . Zero O b . E = / 2 € d . E = pr / 2 € O e . E = / 2 €
Solution :
Let us consider the Gaussian surface that is in the form of a cylinder having a radius of r and a length of A which is [tex]$\text{coaxial with the charged cylinder}$[/tex].
The charged enclosed by the cylinder is given by,
[tex]$q=\rho V$[/tex] (here, V = [tex]$\pi r^2l$[/tex] is the volume of the cylinder)
[tex]$=\pi r^2lp$[/tex]
If [tex]$\rho$[/tex] is positive, then the electric field lines moves in the radial outward direction and is normal to Gaussian surface which is distributed uniformly.
Therefore, total flux through Gaussian cylinder is :
[tex]$\phi=EA_{cyl}$[/tex]
[tex]$=E(2\pi rl)$[/tex]
Now using Gauss' law, we get
[tex]$2\pi \epsilon_0rlE = \pi r^2lp$[/tex]
or [tex]$E=\frac{\rho r}{2 \epsilon_0}$[/tex]
Therefore, the electric field is [tex]$E=\frac{\rho r}{2 \epsilon_0}$[/tex]
Hence, option (d) is correct.
When the interval between the stimuli decreases, _______.
A. a second action potential is generated until the interval reaches the absolute refractory period
B. a second action potential is generated regardless of the stimulus and the interval
C. a second action potential is generated until the interval reaches the relative refractory period
D. a second action potential is generated as long as the stimulus is above threshold
Answer:
The correct option is A. a second action potential is generated until the interval reaches the absolute refractory period.
Explanation:
The inter-stimulus interval (ISI) is the temporal interval between two successive stimuli, measured from the offset of the first stimulus to the commencement of the second.
A cell's refractory period is the time during which it is unable to replicate an action potential. Therefore, the absolute refractory period is the amount of time it takes for a second action potential to be initiated, regardless of how large a stimulus is applied repeatedly.
A second action potential is generated when the gap between the stimuli decreases until the interval reaches the absolute refractory period.
Therefore, the correct option is A. a second action potential is generated until the interval reaches the absolute refractory period.
That is, when the interval between the stimuli decreases, a second action potential is generated until the interval reaches the absolute refractory period.
what is the speed of a wave with a wavelength of 3.0 m and a period of 0.40 s?
pleaase help me i don't know this !!!
Answer:
coefficient=1.09N/m×g
coefficient=1.09N/0.413g×10m/s square
coefficient=1.09N/4.13N
coefficent=0.263
f= uK
here f is force, u is cofficient of friction , k is normal force
k = mg
f = umg
1.09 = u × 0.41 × 10
u = 1.09 ÷ 4.1
u = 0.26
plz help me yesterdays answer was wrong....
Name the Thermal expansion of fluids such as liquid and gas
Answer:
water
mercury in thermometer
volume gas thermometer
jar lids
power lines
what is rotation and revolution
a car travelled at 50km/hr for 3 hours, how far did the car travel
Answer:
The answer answer is 150 km
Answer:
Explanation:
Distance =Speed×time
Speed=50km/hr
Time=3hours
Hence the Distance will be(50km/hr×3hours)
The answer is 150km
what is the car's average velocity
Answer:
vận tốc bằng quãng đường chia thời gian
Explanation:
v=s/t
A body of mass 5 kg moving with velocity 10m/s attains a velocity of 30m/s in 20 seconds, after applying the force. The amount of force applied will be:
a 10N
b 20N
c 5N
d 15N
Answer↷
c) 5N
➦I hope it seemed helpful to you!
What happens when a negatively charged object A is brought near a neutral object B?
A.
Object B gets a negative charge.
Ο
O o
B.Object B gets a positive charge.
O C.
Object B stays neutral but becomes polarized.
D.
Object A gets a positive charge.
O
E.
Object A loses all its charge.
Reset
Next
Answer:
A.
Explanation:Object b will get a negative charge .
A educação física, enquanto componente curricular da educação básica. Qual a tarefa que educação física?? Alguem me ajuda por fvr ??
Answer:
como assim qual a tarefa que educação física? se você me explicar melhor eu consigo te responder !!
Explanation:
Calculate the power of a train that uses 2MJ of chemical energy in 4
seconds.
Answer:
500 kW
Explanation:
Given that,
Energy of the train, E = 2 MJ = 2×10⁶ J
Time, t = 4 seconds
We need to find the power of the train. We know that,
Power = energy/time
So,
[tex]P=\dfrac{2\times 10^6}{4}\\\\P=500000\ W\\\\or\\\\P=500\ kW[/tex]
So, the power of the train is equal to 500 kW.
A 1500 kg truck travelling north at 60 km/hr collides with a 1200 kg car moving east at 15km/hr. If the two cars remain locked together after impact, with what velocity do they move immediately after the collision.
Answer:
33.33j+6.67i km/hr
Explanation:
From the law of conservation of momentum,
Applying,
mu+m'u' = V(m+m')............... Equation 1
Where m = mass of the truck, m' = mass of the car, u = initial velocity of the truck, u' = initial velocity of the car, V = Final velocity.
Note: let j represent the north, and i represent the east
From the question,
Given: m = 1500 kg, u = 60j, m' = 1200 kg, u' = 15i
Substitute these values into equation 1
1500*60j+1200*15i = V(1500+1200)
90000j+18000i = 2700V
V = (90000j+18000i)/2700
V = 33.33j+6.67i km/hr
Accelaration is a derived quantity .Give reason
Answer:
The accerlation is a derived from the other quantities like change in velocity/time take etc.
which force is responsible for the moon revolving around the sun?
What is the work input to lift a box of 810 with a 50% mechanical efficiency?
Answer:
Work input = 1620
Explanation:
Given the following data;
Work output = 810
Efficiency = 50%
To find the work input;
Mathematically, efficiency is given by the formula;
[tex] Efficiency = \frac {Out-put \; work}{In-put \; work} * 100 [/tex]
Substituting into the formula, we have;
[tex] 50 = \frac {810}{WI} * 100 [/tex]
Cross-multiplying, we have;
[tex] 50I = 810 * 100 [/tex]
[tex] 50I = 81000 [/tex]
[tex] WI = \frac {81000}{50} [/tex]
Work input = 1620
1. The electromagnetic spectrum is the range of all types of radiation.
a. index of refraction
b. EM
c. laser
Answer:
EM
Explanation:
The index of refraction is a special property that shows how light travels through different medias. It does not concern itself with the spectrum, only what it will do to that spectrum under laboratory conditions.
Laser light is a very narrow concentrated light form. It is not the entire spectrum, but only a very small part of it.
The answer you want is EM Electromagnetic Radiation
Magnets are formed from iron, nickel, or cobalt when the ______________________ line up in the same direction.
Answer:
electrons
In substances such as iron, cobalt, and nickel, most of the electrons spin in the same direction. When you rub a piece of iron along a magnet, the north-seeking poles of the atoms in the iron line up in the same direction. The force generated by the aligned atoms creates a magnetic field, hence it acts as a magnet.
the materials that can be magnetized this way are called ferromagnetic materials, but it is not permanent and after some times it loses all the magnetic properties.
please if you find this answer helpful mark it as brainliest
Magnets are formed from iron, nickel, or cobalt when the electrons in their atoms' outer energy levels line up in the same direction that is present in Option A, as the alignment creates a magnetic field that can attract or repel other magnets or magnetic materials.
What are magnets?At the atomic level, electrons orbit the nucleus in shells or energy levels, and electrons have a property called spin, which creates a tiny magnetic field around them. Normally, electrons in an atom have random spin directions, so their magnetic fields cancel each other out and the atom has no overall magnetic field. In some materials, such as iron, nickel, and cobalt, the electrons in the outer energy level can line up in the same direction, creating a net magnetic field. This is known as ferromagnetism.
Hence, magnets are formed from iron, nickel, or cobalt when the electrons in their atoms' outer energy levels line up in the same direction that is present in Option A,
Learn more about the magnets here.
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question is incomplete, complete question is below
Magnets are formed from iron, nickel, or cobalt when the ______________________ line up in the same direction.
A)electrons in their atoms' outer energy levels
B)proton explodes
how does an atom change if all of its electons are removed
a. the atom’s volume increases
b. the atom’s mass increases
c. the atom becomes positively charged
d. the atom becomes negatively charged
Answer:
c
Explanation:
Have a nice day
answer is c
(c)
Explanation:
is (c)
it is c
7) List three (3) automobile safety features currently used to minimize the risk of injury to its passengers. Relate these
safety features to your egg drop design.
As you slide a heavy box across the floor, friction applies a force of -100 N
over a distance of 5 m. How much work is done by friction?
A. -500 J
B. -20 j
C. -100 J
D. -95 J
Answer:
A -500J
Explanation:
because W=Fs
100 × 5 = 500
The work done by friction is 500 J.
What is friction?
Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other.There are several types of friction:
Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact. Dry friction is subdivided into static friction ("stiction") between non-moving surfaces, and kinetic friction between moving surfaces. With the exception of atomic or molecular friction, dry friction generally arises from the interaction of surface features, known as asperities
Fluid friction describes the friction between layers of a viscous fluid that are moving relative to each other.
Lubricated friction is a case of fluid friction where a lubricant fluid separates two solid surfaces.Skin friction is a component of drag, the force resisting the motion of a fluid across the surface of a body.
Internal friction is the force resisting motion between the elements making up a solid material while it undergoes deformation.
When surfaces in contact move relative to each other, the friction between the two surfaces converts kinetic energy into thermal energy (that is, it converts work to heat).
Learn more about friction
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I need this now
On the planet Xenos, an astronaut observes that a 2.0 m long pendulum has a period of 2.2 s.
What is the free-fall acceleration on Xenos? *
Answer:
[tex]g=16.31\ m/s^2[/tex]
Explanation:
Given that,
The length of the pendulum, l = 2 m
The period of the pendulum, T = 2.2 s
The formula for the time period of a pendulum is given by :
[tex]T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
or
[tex]T^2=4\pi ^2\dfrac{l}{g}\\\\g=\dfrac{4\pi ^2l}{T^2}\\\\g=\dfrac{4\pi ^2\times 2}{(2.2)^2}\\\\g=16.31\ m/s^2[/tex]
So, the free fall acceleration is [tex]16.31\ m/s^2[/tex].
Difference between cold and warm blooded animal.
Answer:
Cold blooded animals are those animals that cannot regulate their body temperature and their temperature keeps changing according to their environment. ... Warm blooded animals are the animals that have a constant body temperature and can easily adapt to extreme temperatures as they can regulate their body temperature.
In the picture below, a car hits a wall. Using what you know about Newton’s Third Law, which is true?
The force of the wall on the car and the car on the wall are equal
The force of the wall on the car is greatest
The force of the car on the wall is greatest
There is not enough information to tell
Answer:
A...................................
The force of the wall on the car and the car on the wall are equal is true about Newton’s Third Law. Option A is the correct answer.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. This means that if the car hits the wall, there will be a force exerted by the car on the wall, and an equal and opposite force exerted by the wall on the car. Option A is the correct answer.
The forces involved in the interaction between the car and the wall are equal in magnitude but opposite in direction, as dictated by Newton's Third Law. Newton's Third Law of Motion states that for every action, there is an equal and opposite reaction. This means that when an object exerts a force on another object, the second object exerts a force of equal magnitude but in the opposite direction on the first object.
Learn more about Newton here:
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The complete question is, "In the picture below, a car hits a wall. Using what you know about Newton’s Third Law, which is true?
a. The force of the wall on the car and the car on the wall are equal
b. The force of the wall on the car is greatest
c. The force of the car on the wall is greatest
d. There is not enough information to tell"
Which of the following are correct statements about the way an atom is put
together?
Check all that apply.
A. The valence shell is the innermost shell of electrons in an atom.
B. Electrons are found in the nucleus of an atom.
O C. There are two electrons in all electron shells.
O D. Electrons are in layers around the nucleus.
***** multiple choice ******
Answer:
valenc e shell
Explanation:
what is the difference between torque and the moment of a force
Answer:
Torque Of a Force: If The Force has tendency or Bends The Body about Longitudinal axis of the Body it is Torque. Moment Of a Force :If Force has Tendency to or Rotates the Body about Transverse asis the Body It is Moment .
Explanation:
How does Newton's third law explain how a rocket is launched upward?
Answer:
At lift-off, hot burning gas is pushed downwards by the rocket motors. The hot gas pushes back on the rocket in an upwards direction. When this upwards push, or thrust, exceeds the weight of the rocket, the forces acting on the rocket are unbalanced and the rocket accelerates upwards
Explanation:
Answer:
A. Gases from burning fuel are pushed out of the bottom of the rocket, and these gases push back on the rocket with an equal amount of force.
Explanation:
The amount of work required to increase the distance between -6μC and 4μC from 6 cm to 18 cm will be
Answer:
W = 1.8 J
Explanation:
The amount of work required to move the given charges can be found by using the following formula:
[tex]W = \frac{kq_1q_2}{\Delta r} \\\\[/tex]
where,
W = Work done = ?
k = Colomb's constant = 9 x 10⁹ Nm²/C²
q₁ = magnitude of first charge = 6 μC = 6 x 10⁻⁶ C
q₂ = magnitude of second charge = 4 μC = 4 x 10⁻⁶ C
Δr = change in distance = 18 cm - 6 cm = 12 cm = 0.12 m
Therefore,
[tex]W = \frac{(9\ x\ 10^9\ Nm^2/C^2)(6\ x\ 10^{-6}\ C)(4\ x\ 10^{-6}\ C)}{0.12\ m}[/tex]
W = 1.8 J