A friend lends you $150 for a week, which you agree to repay with
4% one-time interest. How much will you have to repay?

Answers

Answer 1

Answer:

174

Step-by-step explanation:


Related Questions

3x-8=3(x-3)-2
Is there a answer to this problem? I cant find one

Answers

Answer:

The input is a contradiction: it has no solutions

Rewrite as equivalent rational expressions with denominator (a−7)(a−2)(a+8):

Answers

Answer:

[tex] \dfrac{3(a + 8)}{(a - 7)(a - 2)(a + 8)} [/tex]

[tex] \dfrac{8a(a - 2)}{(a - 7)(a - 2)(a + 8)} [/tex]

Step-by-step explanation:

[tex] \dfrac{3}{a^2 - 9a + 14} = [/tex]

[tex] = \dfrac{3}{(a - 7)(a - 2)} [/tex]

[tex] = \dfrac{3(a + 8)}{(a - 7)(a - 2)(a + 8)} [/tex]

[tex] \dfrac{8a}{a^2 + a - 56} = [/tex]

[tex] = \dfrac{8a}{(a + 8)(a - 7)} [/tex]

[tex] = \dfrac{8a(a - 2)}{(a - 7)(a - 2)(a + 8)} [/tex]

A restaurant decides to test their oven's thermostat to see if it is working properly, that is, if the actual temperature inside the oven is the same as the temperature to which the thermostat was set. Twenty times, the oven was set at 350 degrees and then the temperature was measured with a thermometer. The chef wants to know if the average oven temperature is different from 350, when the thermostat is set at 350. What is the correct null and alternative hypothesis for this test

Answers

Considering the situation described in the exercise, it is found that the correct null and alternative hypothesis for this test are given by, respectively:

[tex]H_0: \mu = 350[/tex]

[tex]H_1: \mu \neq 350[/tex]

What are the hypothesis tested?

At the null hypothesis, it is tested if the mean is of 350 degrees, that is:

[tex]H_0: \mu = 350[/tex]

At the alternative hypothesis, it is tested if the mean is different of 350 degrees, hence:

[tex]H_1: \mu \neq 350[/tex]

More can be learned about the test of an hypothesis at https://brainly.com/question/26454209

Brandon is half of Ella's age. Ella is three times Tristans age. In fifteen years, their combined age will be 89. How old is Brandon?

Answers

Answer:

Step-by-step explanation:

Let Brandon's age be [tex]x[/tex]

Therefore Ella=[tex]2x[/tex]

Tristan= [tex]\frac{2x}{3}[/tex]

Fifteen years time add 15 to each age

Brandon: [tex]x+15[/tex]

Ella: [tex]2x+15[/tex]

Tristan:[tex]\frac{2x}{3} +15[/tex]

All their ages together=89

So: [tex]x+15[/tex] +  [tex]2x+15[/tex] + [tex]\frac{2x}{3} +15[/tex][tex]=89[/tex]

[tex]3\frac{2}{3} x=44[/tex]

[tex]x= \frac{44}{3\frac{2}{3} } =12[/tex]

7+3 express as a difference

Answers

Answer:

  7 - (-3)

Step-by-step explanation:

You want the sum 7 + 3 expressed as a difference.

Difference

The difference of A and B is written A - B. The subtraction operation is involved.

Subtraction is the same as addition of the opposite. Or, addition is the same as subtracting the opposite:

  7 + 3 = 7 - (-3)

__

Additional comment

We can also write the difference as ...

  3 - (-7)

<95141404393>

Multiply: -
2/3 x 6/7
Put your answer in lowest terms.

A. 4/7
B. 4/21
C. 12/21
D. 3/7

Answers

Answer:

It should be -4/7

Step-by-step explanation:

I hope i helped. And If you can, can you help me by subing to my YT. It’s called Not Claz and it is the same profile pick I have on Brainly.

Find the volume of a right rectangular prism if the dimensions of the base are 4 centimeters by 9 centimeters and the height is 11 centimeters.
A 396^3.
B 241^3.
C 144^3.
D 370^3.

Answers

396 cm²

Volume of rectangular prism - -

Formula's :

Length * Width * Height

Base area * Height

Here base area:

Length * Width

4 * 9

36 cm²

Volume:

Base area * Height

36 * 11

396 cm²

a box of 40 chocolates contains 56g of saturated fat. How much saturated fat is there in 1 chocolate

Answers

Divide total fat by number of chocolates


56/40 = 1.4 grams


answer: 1.4 grams

3b. For each differential equation, find the Laplace transform of the solution y:

y'' − y = 5e^−4x + 2x, y(0) = y'(0) = 0.

Answers

Answer:

[tex]y(x)=-2x-\frac{11}{6}e^{-x}+\frac{3}{2}e^x+\frac{1}{3}e^{-4x}[/tex]

Step-by-step explanation:

[tex]y''-y=5e^{-4x}+2x,\: y(0)=y'(0)=0\\\\\mathcal{L}\{y''\}-\mathcal{L}\{y\}=\mathcal{L}\{5e^{-4x}\}+\mathcal{L}\{2x\}\\\\s^2Y(s)-sy(0)-y'(0)-Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\s^2Y(s)-Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\(s^2-1)Y(s)=\frac{5}{s+4}+\frac{2}{s^2}\\ \\Y(s)=\frac{5}{(s+4)(s^2-1)}+\frac{2}{s^2(s^2-1)}\\ \\Y(s)=\frac{5s^2+2(s+4)}{s^2(s+4)(s^2-1)}\\ \\Y(s)=\frac{5s^2+2s+8}{s^2(s-1)(s+1)(s+4)}[/tex]

Perform the partial fraction decomposition

[tex]\frac{5 s^{2} + 2 s + 8}{s^{2} \left(s - 1\right) \left(s + 1\right) \left(s + 4\right)}=\frac{A}{s}+\frac{B}{s^{2}}+\frac{C}{s + 1}+\frac{D}{s - 1}+\frac{E}{s + 4}\\\\5 s^{2} + 2 s + 8=s^{2} \left(s - 1\right) \left(s + 1\right) E + s^{2} \left(s - 1\right) \left(s + 4\right) C + s^{2} \left(s + 1\right) \left(s + 4\right) D + s \left(s - 1\right) \left(s + 1\right) \left(s + 4\right) A + \left(s - 1\right) \left(s + 1\right) \left(s + 4\right) B[/tex]

[tex]5 s^{2} + 2 s + 8=s^{4} A + s^{4} C + s^{4} D + s^{4} E + 4 s^{3} A + s^{3} B + 3 s^{3} C + 5 s^{3} D - s^{2} A + 4 s^{2} B - 4 s^{2} C + 4 s^{2} D - s^{2} E - 4 s A - s B - 4 B\\\\5 s^{2} + 2 s + 8=s^{4} \left(A + C + D + E\right) + s^{3} \left(4 A + B + 3 C + 5 D\right) + s^{2} \left(- A + 4 B - 4 C + 4 D - E\right) + s \left(- 4 A - B\right) - 4 B[/tex]

Solve for each constant

[tex]\begin{cases} A + C + D + E = 0\\4 A + B + 3 C + 5 D = 0\\- A + 4 B - 4 C + 4 D - E = 5\\- 4 A - B = 2\\- 4 B = 8 \end{cases}[/tex]

[tex]-4B=8\\B=-2[/tex]

[tex]-4A-B=2\\-4A-(-2)=2\\-4A+2=2\\-4A=0\\A=0[/tex]

[tex]A+C+D+E=0\\C+D+E=0\\E=-C-D[/tex]

[tex]-A+4B-4C+4D-E=5\\4(-2)-4C+4D-(-C-D)=5\\-8-4C+4D+C+D=5\\-3C+5D=13\\5D=13+3C[/tex]

[tex]4A+B+3C+5D=0\\4(0)+(-2)+3C+13+3C=0\\-2+6C+13=0\\11+6C=0\\6C=-11\\C=-\frac{11}{6}[/tex]

[tex]5D=13+3C\\5D=13+3(-\frac{11}{6})\\5D=13-\frac{33}{6}\\5D=\frac{15}{2}\\D=\frac{15}{10}\\D=\frac{3}{2}[/tex]

[tex]E=-C-D\\E=-(-\frac{11}{6})-(\frac{3}{2})\\E=\frac{11}{6}-\frac{3}{2}\\E=\frac{2}{6}\\E=\frac{1}{3}[/tex]

Take the inverse transform and solve for the IVP

[tex]Y(s)=\frac{0}{s}+\frac{-2}{s^2}+\frac{-\frac{11}{6}}{s+1}+\frac{\frac{3}{2}}{s-1}+\frac{\frac{1}{3}}{s+4}\\ \\y(x)=-2x-\frac{11}{6}e^{-x}+\frac{3}{2}e^x+\frac{1}{3}e^{-4x}[/tex]

Round 14,465 to the nearest ten thousands place:

Answers

Answer:

10,000 is the answer

Step-by-step explanation:

14 465

round up the 4 which is 0 then your answer would be 10000

Find the the slope of the line that contain 5,3 and -1,4

Answers

Answer:

-1/6

Step-by-step explanation:

the equation to do this is y2-y1/x2-x1

therefore you set it up as 4-3/-1-5

then when you simplify it it would be 1/-6

therefore the slope is -1/6

FIRST TO ANSWER GETS MARKED BRAINLEST! please look at picture. The probability that a student guesses the correct answer to a four-choice multiple choice question is P(correct) = 0.25. How many correct answers should a student expect to guess on a test with 56 four-choice multiple choice questions?
A student should expect to guess_______correct answers.

Answers

Answer:

14 answers  

Step-by-step explanation:

since there is 1/4 of a chance to get a question right by guessing you need to see what 1/4 of 56 is, which is 14

The length of a rectangular parking lot is 32 meters and the width is 20 meters. The parking lot is surrounded by a sidewalk that is x meters wide. Find the expression that represents the area of the parking lot, including the sidewalk.

Answers

The expression is:
32 X 20 + x

Hope that will help :)

A triangle has two sides of lengths 4 and 15. What value could the length of
the third side be? Check all that apply.

Answers

sqrt(209) or sqrt(241), assuming it’s a right triangle. Are there answer choices?

F(x)=2x^2-5x g(x)=-3x^2 find f(2)

Answers

F(x)= 2(2)^2-5(2)= -2 that’s it

Solve the equation P=KTV for the letter K.

Answers

Answer:

K = [tex]\frac{P}{TV}[/tex]

Step-by-step explanation:

P = KTV

Divide both sides by TV

(P/TV) = K

i just need someone to tell me i can do it. i know this is wasting someone, somewheres time but i need someone to tell me i can this work done. im so far behind on edgenuity and i feel worthless. ​

Answers

You got this I believe in you. I know it feels hard right now and like the world is ending but keep trying. I promise the outcome is worth it. Take breaks from your work, drink water, eat a healthy meal, get proper sleep. You are an amazing person who can accomplish anything even if you don’t feel like it right now.

Select the expression that will calculate how many eighths are in 2 bars? Use the model to help you.
a. 2÷ 8
b. 8÷ 2
c. 2÷ 1/8
d. 8 ÷ 1/2

Answers

Answer:

4

Step-by-step explanation:

4*2=8

and 4/8 also equals four anyway you simplify the question it will equal 4

Which number belongs to solution set of the inequality 11>x

A.11
B.15
C.12
D.4

Answers

D. 4 because it’s the only one less than 11

What is -86 + x = - 4x + 29

Answers

Answer:

x = 23

Step-by-step explanation:

Add 4x to the left and add 86 to the right.

5x = 115

Now, divide 5 on both sides to get x.

x = 23.

The result is 23.

Answer:

x= – 115/3

Step-by-step explanation:

I don’t know what exact form you want so I’ll give you mixed number form.

x + 3y=9
x + y = 21
Solve it algebraically

Answers

Answer:

[tex]x=27[/tex]

[tex]y=-6[/tex]

Step-by-step explanation:

substitute in values

[tex]x=21-y[/tex]

[tex](21-y)+3y=9[/tex]

[tex]21+2y=9[/tex]

[tex]2y=-12[/tex]

[tex]y=-6[/tex]

[tex]x+(-6)=21[/tex]

[tex]x=27[/tex]

Convert 63° to radians.

Answers

Answer:

1.1025rad

Step-by-step explanation:

1°=0.0175rad

63°=0.0175rad*63=1.1025rad

(-5xy)(-9xy) (-2xy) =
Simplify

Answers

Answer:

-90x^3y^3

Step-by-step explanation:

PLSSSS THIS IS 20 POINTS AND U GET BRAINLIEST!!! Are the lines x = 2 and y = 5 parallel? Are the perpendicular? Explain.

Answers

it shud be perpendicular as the line is on x and y , they might cross each other while parallel dont

∠A and ∠B are complementary. The measure of ∠A is 21°.

What is the measure of ∠B?

Enter your answer in the box.
point theif = ban

Answers

Answer:

69°

Step-by-step explanation:

Complementary angles sum to 90°.

We have the measure of one angle, find the missing one as below.

m∠A + m∠B = 90°21° + m∠B = 90°m∠B = 90° - 21°m∠B = 69°
<B be x

Complementary angles have sum 90°

[tex]\\ \sf\longmapsto x+21=90[/tex]

[tex]\\ \sf\longmapsto x=90-21[/tex]

[tex]\\ \sf\longmapsto x=69[/tex]

In a recent study on world​ happiness, participants were asked to evaluate their current lives on a scale from 0 to​ 10, where 0 represents the worst possible life and 10 represents the best possible life. The mean response was with a standard deviation of . ​(a) What response represents the ​percentile? ​(b) What response represents the ​percentile? ​(c) What response represents the ​quartile? ​(a) The response that represents the percentile is nothing. ​(Round to two decimal places as​ needed.) ​(b) The response that represents the percentile is nothing. ​(Round to two decimal places as​ needed.) ​(c) The response that represents the quartile is nothing. ​(Round to two decimal places as​ needed.)

Answers

Answer:

(a) 8.35

(b) 5.98

(c) 3.86

Step-by-step explanation:

The complete question is:

In a recent study on world​ happiness, participants were asked to evaluate their current lives on a scale from 0 to​ 10, where 0 represents the worst possible life and 10 represents the best possible life. The mean response was 5.4 with a standard deviation of 2.3. ​(a) What response represents the 90th ​percentile? ​(b) What response represents the ​60th percentile? ​(c) What response represents the ​first quartile? ​

Solution:

Assume that the world​ happiness ratings follows a Normal distribution with parameters μ = 5.4 and σ = 2.3.

(a)

Compute the response representing the 90th ​percentile as follows:

P (X < x) = 0.90

⇒ P (Z < z) = 0.90

The value of z for the above probability is, z = 1.282.

Compute the value of x as follows:

[tex]x=\mu+z\sigma[/tex]

   [tex]=5.4+(1.282\times 2.3)\\\\=5.4+2.9486\\\\=8.3486\\\\\approx 8.35[/tex]

Thus, the response representing the 90th ​percentile is 8.35.

(b)

Compute the response representing the 60th ​percentile as follows:

P (X < x) = 0.60

⇒ P (Z < z) = 0.60

The value of z for the above probability is, z = 0.25.

Compute the value of x as follows:

[tex]x=\mu+z\sigma[/tex]

   [tex]=5.4+(0.25\times 2.3)\\\\=5.4+0.575\\\\=5.975\\\\\approx 5.98[/tex]

Thus, the response representing the 60th ​percentile is 5.98.

(c)

Compute the response representing the first quartile of the 25th percentile as follows:

P (X < x) = 0.25

⇒ P (Z < z) = 0.25

The value of z for the above probability is, z = -0.67.

Compute the value of x as follows:

[tex]x=\mu+z\sigma[/tex]

   [tex]=5.4+(-0.67\times 2.3)\\\\=5.4-1.541\\\\=3.859\\\\\approx 3.86[/tex]

Thus, the response representing the first quartile is 3.86.

A skating rink charges $5 per hour plus $3 to rent skates. A second skating rink charges $6 per game plus $2 to rent skates. How many games would person have to play for the two skating rinks to cost the same amount?

Answers

Answer:

Each of them would play 2 games to get the same cost amount

Step-by-step explanation:

for example

#1) $5 + $3 = $8 x 2 = $16

#2) $6 + $2 = $8 x 2 = $16

how many different simple random samples of size 5 can be obtained from a population whose size is 45
?​

Answers

Answer: 1,221,759

This value is slightly over 1.2 million

========================================================

How I got that answer:

We have 45*44*43*42*41 = 146,611,080 different permutations. I started with 45 and counted down by 1 until I had 5 values multiplied out.

If order mattered, then we would stop here. But order doesn't matter. All that matters is the group overall rather than any particular individual or how they rank in the group.

There are 5! = 5*4*3*2*1 = 120 different ways to arrange a five item set, so the very large result we got earlier is overcounting by a factor of 120.

To fix this, we divide by 120 to get

(146,611,080)/120 = 1,221,759

This represents the number of combinations in which we're selecting 5 members from a pool of 45 total.

You could use the nCr formula

[tex]_nC_r = \frac{n!}{r!*(n-r)!}[/tex]

with n = 45 and r = 5 to get the same answer in bold above.

Using the principle of Combination, the number of different random samples of size five which can be obtained form a population of 45 is 1221759

Using the principle of combination, which is defined as :

nCr = n! ÷ (n-r)!r! n = 45 r = 5

Hence,

45C5 = 45! ÷ (45 - 5)!5!

45C5 = 45! ÷ 40!5!

45C5 = (45 × 44 × 43 × 42 × 41) / (5 × 4 × 3 × 2 × 1)

45C5 = 1221759

Therefore, there are 1221759 ways of making a selection of 5 samples from a population of size 45.

Learn more :https://brainly.com/question/10699405?referrer=searchResults

write an equation of the line below​

Answers

Answer:

y=3x

Step-by-step explanation:

6 6 small bricks have the same mass as 5 large bricks. The mass of one small brick is 2.5 kg. What is the mass of one large brick?​

Answers

Since 6 small bricks have the same mass as 5 large bricks and the mass of one small brick is 2.5 kg, the mass of one of the large bricks is 3 kg

What is mass?

Mass is the quantity of matter in a physical body.

6 small bricks have the same mass as 5 large bricks.

let

the total mass of the small or large bricks = x

Therefore,

6 × 2.5 = x

x = 15 kg

Therefore, the mass of each large bricks can be calculated as follows:

let the mass of each large bricks  = y

15 = 5y

divide both sides by 6

y = 15 / 5

y = 3 kg

Therefore, the mass of one of the large bricks is 3 kg

.learn more on mass here: https://brainly.com/question/895643

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