a horizontal pipe with a diameter of 3 cm narrows down to a diameter of 2 cm, where it expels water into the surrounding air at a speed of 32 m/s. what is the gauge pressure in the larger diameter section of the pipe?

Answers

Answer 1

A horizontal pipe with a 3 cm diameter that narrows to a 2 cm diameter at a speed of 32 m/s releases water into the air around it. The pipe's larger diameter section's gauge pressure is 512,000 Pa.

To determine the gauge pressure in the larger diameter section of the pipe, we can apply Bernoulli's principle, which states that the total pressure at any point in a fluid system is the sum of the static pressure and the dynamic pressure.

Given:

Diameter of the larger section (D1) = 3 cm = 0.03 m

Diameter of the smaller section (D2) = 2 cm = 0.02 m

Velocity of water (v) = 32 m/s

We'll assume the flow is steady and the fluid is incompressible. The density of water (ρ) is approximately 1000 kg/m³.

Using Bernoulli's principle, we have:

[tex]P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2[/tex]

Since the larger section of the pipe has a larger diameter, we can assume it has a lower velocity compared to the smaller section.

[tex]P_1 + \frac{1}{2}\rho v_1^2 > P_2 + \frac{1}{2}\rho v_2^2[/tex]

The gauge pressure (P1) in the larger diameter section can be calculated as follows:

[tex]P_1 = P_2 + \frac{1}{2}\rho(v_2^2 - v_1^2)[/tex]

[tex]P_1 = P_2 + \frac{1}{2}\rho(v_2 + v_1)(v_2 - v_1)[/tex]

Since the pipe is open to the surrounding air, we can assume atmospheric pressure (P2) is present in the smaller diameter section.

P2 = 0 (gauge pressure at atmospheric pressure)

Therefore, the gauge pressure in the larger diameter section (P1) is:

[tex]P_1 = \frac{1}{2}\rho(v_2 + v_1)(v_2 - v_1)[/tex]

Plugging in the values, we get:

[tex]P1 = \frac{1}{2} \times 1000 , \text{kg/m}^3 \times (32 , \text{m/s} + 0 , \text{m/s}) \times (32 , \text{m/s} - 0 , \text{m/s})[/tex]

Calculating the expression, we find:

P1 = 512,000 Pa

Therefore, the gauge pressure in the larger diameter section of the pipe is 512,000 Pa.

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Answer:

"Longshore currents are affected by the velocity and angle of a wave. When a wave breaks at a more acute (steep) angle on a beach, encounters a steeper beach slope, or is very high, longshore currents increase in velocity. ... This process, known as “longshore drift,” can cause significant beach erosion."

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when a ray of light is incident normally on a plane mirror the angle between incident and reflected ray is 0 degree or 180 degree

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Generally, Gravity is simply defined as the force that pulls items toward the center of a planet or other entity.

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uses of electromagnetic wave​

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Radio waves - used for communication e.g. radios and TVs

Microwaves - used for cooking food and for satellite communications

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Depending the height your jumping from, if you were jumping from a high structure it's best if you jump and land on knees so you dont sprang your ankles from jumping and landing on your straight legs, you could even pull a muscle if you land on straight legs.

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2, A rectangulv Container of base socmby 30cm is filled
with water to be depth of 5cm. how much is the pressure exerted
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Answers

Correct question is;

2, A rectangular Container of base 50 cm by 30cm is filled with water to be depth of 5cm. how much is the pressure exerted at the base? (take pw= 1000kg /m3 and g=10m/s)​

Answer:

P = 500 N/m²

Explanation:

Pressure exerted at the base is the hydrostatic pressure and it is given by the formula;

P = ρgh

Where;

ρ is density = 1000 kg/m³

g = 10 m/s²

h is depth = 5 cm = 0.05 m

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P = 1000 × 10 × 0.05

P = 500 N/m²

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Answer:

false

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because Oxalic acid is present in spinach

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Answer:

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Answer:

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Rudolf Virchow

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popularized the cell theory in an 1855 essay entitled “Cellular Pathology.” (b) The idea that all cells originate from other cells was first published in 1852 by his contemporary and former colleague Robert Remak (1815–1865).

Explanation:

Rudolf Virchow

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//

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Glucose diffuse from the blood plasma, across the capillary walls to the tissue fluid, and then to the cell.

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The vertical component of the velocity at the starting is 12.5 m/s upwards.

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Answers

Answer:

Minerals to Gemstones

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Answer:

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South ;)

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