A horse pulls a wagon with 2000N of at constant velocity. What is the friction acting on the wagon?
0N
1000N
1500N
2000N

Answers

Answer 1

Answer:

f = 0 N

Explanation:

It is given that,

A horse pulls a wagon with 2000N of at constant velocity.

We need to find the friction acting on the wagon.

As the wagon is pulled with a constant velocity. If its velocity is constant, it means its acceleration is 0. As a result friction force is 0.

Hence, the correct option is (a).


Related Questions

How has the magnet affected the block of material next to it?
A. The domains in the end of the block farthest from the magnet are aligned with its magnetic field.
B. The domains in the end of the block closest to the magnet are aligned with its magnetic field.
C. The domains in the center of the block are aligned with the magnetis magnetic field
D. The domains in the entire block are aligned with the magnets magnetic field​

Answers

Answer: (APE X) B

Explanation: I am taking it and I just got it right

The magnetic characteristics of a substance are determined by the magnetic moments of its atoms,  the domains which are closest to the magnet are aligned with its magnetic field, hence option b is correct.

What is the effect of a magnet?  

Long-range alignments of magnetic moments in ferromagnetic materials, known as domains, include magnetic moments that all point in the same direction.

This indicates that the atoms' individual magnetic moments are lined up with one another and pointing in the same general direction.

Therefore, a magnetic substance will get magnetized if it is placed close to a magnet. Magnetism is the name for this kind of electricity, hence option b is correct.      

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hello what is a major theme of this speech?

Answers

you didn’t attach the speech ?

An apple (mass = 0.25 kg) on a string 1 m in length is whirled above a student's head in a circle. The apple has a tangential speed of 12 m/s. What is the magnitude of the centripetal force on the apple?

Answers

Answer:

36N

Explanation:

Given parameters:

Mass of apple  = 0.25kg

length of string  = 1m

tangential speed  = 12m/s

Unknown:

magnitude of centripetal force = ?

Solution:

The centripetal force keeps a body moving along a circular path.

It is mathematically derived using the expression below;

      F = [tex]\frac{mv^{2} }{r}[/tex]

F is the centripetal force

m is the mass

v is the tangential speed

r is the radius

  Now insert the parameters and solve;

     F = [tex]\frac{0.25 x 12^{2} }{1}[/tex]  = 36N

A microscope using ultraviolet light is used to study bacteria. If the aperture diameter is 1.5 cm and it is desired to distinguish features with an angular size 0.036 arc seconds, what maximum wavelength can be used

Answers

Given :

A microscope using ultraviolet light is used to study bacteria. If the aperture diameter is 1.5 cm.

Angular size is 0.036 arc seconds.

To Find :

The maximum wavelength that can be used.

Solution :

Converting given angle into radians :

[tex]\theta = \dfrac{0.036}{3600}\times \dfrac{\pi}{180}\\\\\theta = 1.745\times 10^{-7}\ radians[/tex]

Now, we know maximum wavelength is given by :

[tex]\lambda = \dfrac{\theta \times D}{1.22}\\\\\lambda = \dfrac{1.745\times 10^{-7} \times 0.015}{1.22}\ m\\\\\lambda =2.145 \times 10^{-7}\ m[/tex]

Hence, this is the required solution.

An object in space has altitude of 2210 km, velocity of 7000 m/s and flight path angle of 20 degrees. Find the eccentricity, semi-major axis, angular momentum/mass, and kinetic and potential energies/mass

Answers

Answer:

Eccentricity = 0.0557

Semi-major axis = 9,095 km

Angular momentum/mass = 60,116 [tex]\frac{km^{2} }{Sec}[/tex]

Kinetic energies/mass = 24,500 KJ

Potential energies/mass = 21,673 KJ

Explanation:

Eccentricity

To find the eccentricity use the following formula

Eccentricity = [ Altitude from the earth x ( [tex]Velocity^{2}[/tex] / Gravitational parameter for the Earth ) ] - 1

Where

Altitude from the earth radius = Radius of the earth + Altitude of the earth from radius = 6,378 km + 2,210 km = 8,588 km

Velocity = 7,000 m/s

Gravitational parameter for the Earth = 3.986004418 × [tex]10^{14}[/tex]

Eccentricity = ?

Placing values in the formula

Eccentricity = [ ( 8,588 km x 1000 ) x ( [tex]7000^{2}[/tex] / 3.986004418 × [tex]10^{14}[/tex]   ) ] - 1

Eccentricity = 0.0557

Semi-major axis

Total Distance = Semi-major axis x ( 1 - Eccentricity )

Where

Total Distance = 8,588 km

Eccentricity = 0.0557

8,588 x 1,000 m = Semi-major axis x ( 1 - 0.0557 )

8,588,000 m = Semi-major axis x 0.9443

Semi-major axis = 8,588,000 m / 0.9443

Semi-major axis = 9,094,567.40 m

Semi-major axis = 9,094.56740 km

Semi-major axis = 9,095 km

Angular momentum/mass

L = MVR

L/M = VR

Where

V = Velocity = [tex]\frac{7,000 m/s}{1000}[/tex] = 7 km/s

R = Total Radius = Radius of Earth + Altitude = 6,378 km + 2,210 km = 8,588 km

Placing values in the formula

L/M = 7 km/s x 8,588 km = 60,116 [tex]\frac{km^{2} }{Sec}[/tex]

Kinetic energies/mass

Ke = I [tex]W^{2}[/tex]

Ke = [tex]\frac{1}{2} mr^{2}[/tex] [tex]W^{2}[/tex] ( Where I = [tex]mr^{2}[/tex] )

[tex]\frac{ke}{m}[/tex] = [tex]\frac{r^2}{2}[/tex] [tex]W^{2}[/tex]

[tex]\frac{ke}{m}[/tex] = [tex]\frac{r^2}{2}[/tex] [tex]\frac{V^2}{r^2}[/tex] ( [tex]W^{2}[/tex] = [tex]\frac{V^2}{r^2}[/tex] )

[tex]\frac{ke}{m}[/tex] = [tex]\frac{V^2}{2}[/tex]

[tex]\frac{ke}{m}[/tex] = [tex]\frac{7000^2}{2}[/tex]

[tex]\frac{ke}{m}[/tex] = 24,500,000 J

[tex]\frac{ke}{m}[/tex] = 24,500 KJ

Potential energies/mass

PE = mgh

[tex]\frac{PE}{m}[/tex] = gh

Where

g = 9.807 [tex]\frac{m}{s^2}[/tex]

h = 2,210 km x 1,000 = 2,210,000 m

Placing values in the formula

[tex]\frac{PE}{m}[/tex] = 9.807 [tex]\frac{m}{s^2}[/tex]  x 2,210,000 m

[tex]\frac{PE}{m}[/tex] = 21,673,470 J

[tex]\frac{PE}{m}[/tex] = 21,673.470 KJ

[tex]\frac{PE}{m}[/tex] = 21,673 KJ

it is difficult to smooth floor why​

Answers

Complete question is:

It's is difficult to walk on a wet floor than a smooth floor. Why?

Answer:

Because friction on wet floor is far lesser than on a smooth floor

Explanation:

On wet surfaces, the friction is far lesser than on smooth surfaces and thus the grip between the bottom of your shoes/feet and the ground is very very small and as such walking on the wet surface becomes more difficult. Whereas on Smooth surfaces, there is plenty of friction and as a result, there is enough grip between the bottom of your shoes/feet and the ground thereby making walking far easier.

Click to review the online content. Then answer the question(s) below, using complete sentences. Scroll down to view aditional
questions
Cause and Effect Graphic Organizers
Describe how T-charts and Star Charts can be used to organize information into cause and effect relationships.
I

Answers

Answer:

A T-chart is used comparing two sides of a topic for example pros and cons or cause and effect. A star diagram is used for organizing the characteristics of a single topic, a central space is used for displaying the topic, with each point showing or listing an attribute about the topic.

A 15 N force is applied to a 12 kg box for 6 s. The box is initially at rest. What is the speed of the box at the end of the 6 s interval

Answers

Answer:

The speed of the box at the end of the 6 s interval is 7.5 m/s.

Explanation:

Given;

magnitude of the force, f = 15 N

mass of the box, m = 12 kg

initial velocity of the box, u = 0

time of the box motion, t = 6s

The applied force on the box is given by Newton's second law of motion;

f = ma

where;

a is the acceleration of the box

a = f / m

a = (15) / (12)

a = 1.25 m/s²

The final velocity of the box is calculated as;

v = u + at

v = 0 + (1.25 x 6)

v = 7.5 m/s.

Therefore, the speed of the box at the end of the 6 s interval is 7.5 m/s.

A mixture contains salt, sand, pebbles, and grass. Which part of this mixture is soluble in water?

Grass
Pebbles
Salt
Sand

Answers

Answer:

hey!

the answer is

salt

Explanation:

this is due to sand, grass and pebbles are not soluble (they do not dissolve in water)

pls put brainliest

If you exert a force of 10.0 N to lift a box a distance of 0.75m, how much work do you do?
(4 Points)
0.075 J
7.5 J
10.75 J
75 J

Answers

Work can be calculated with the equation: Work = Force × Distance. The SI unit for work is the joule (J), or Newton • meter (N • m).

Work = Force × Distance.

W = 10 N × 0.75 m

W = 7.5 J

a ray of light parallel to the principal axis of spherical mirror

Answers

Answer:

This question is incomplete but the completed question is below

A ray of light parallel to the principal axis of a spherical mirror passes through its _____ after reflection.

(a) focus (b) pole (c) centre of curvature (d) imaginary centre of curvature

The correct option is (a)

Explanation:

After reflection, a ray of light will usually appear to diverge after they hit a spherical mirror, extending behind the mirror to meet at a point (called the focus or focal point) between the pole and the centre of curvature of this mirror.  Hence, option a is the correct option.

1. Answer the question below. Use the rubric in the materials for help if needed.
Devon drove 50 miles west and then drove 15 miles north. Determine Devon's displacement. Show your work.
I need help

Answers

Answer:

d = 52.20 miles

Explanation:

Given that,

Devon drove 50 miles west and then drove 15 miles north.

We need to find Devon's displacement. Let it is d. It can be calculated as follows :

[tex]d=\sqrt{50^2+15^2} \\\\=52.20\ \text{miles}[/tex]

Hence, Devon's displacement is 52.20 miles.

On what does kinetic energy depend?
a. Mass and velocity b. Gravity and mass c. Gravity and height d.
Velocity and gravity

Answers

Answer:

b

Explanation:

Answer:

Gravity and Mass

Explanation:

Kinetic energy is the energy of something moving. To get a lot of kinetic energy, there has to be a situation where the gravity is moving in the way the object is moving. The heavier the object, the faster it'll move.

A jet aircraft is traveling at 219 m/s in horizontal flight. The engine takes in air at a rate of 77.9 kg/s and burns fuel at a rate of 4.19 kg/s. The exhaust gases are ejected at 934 m/s relative to the aircraft. Find the thrust of the jet engine. Answer in units of N. 019 (part 2 of 2) 10.0 points Find the delivered power. Answer in units of W

Answers

Answer: thrust [tex]-85905.24N[/tex]

delivered power [tex]= -18813247.56W[/tex]

Explanation:

given data:

horizontal speed = 219 m/s

rate of air intake = 77.9 kg/s

fuel combustion rate = 4.19 kg/s.

exhaust gases ejected = 934 m/s

solutuon:

Thrust of the engine

[tex]Fth = Ve * ( Mf - Ma ) - Vj *Ma[/tex]

[tex]= 934 * ( 4.19 - 77.9 ) - 219 *77.9[/tex]

[tex]= -68845.14 - 17060.1[/tex]

=[tex]-85905.24N[/tex]

delivered power

[tex]= Fth * Vj[/tex]

[tex]= -85905.24N * 219[/tex]

[tex]= -18813247.56W[/tex]

The delivered power will be "-18813247.56 W".

Given:

Horizontal speed = 219 m/sRate of air = 44.9 kg/sFuel combustion rate = 4.19 kg/sExhaust gas ejected = 934 m/s

Thrust of the engine will be:

→ [tex]F^{th} = Ve(Mf-Ms)-Vj\times Ma[/tex]

By putting the values, we get

         [tex]= 934(4.19-77.9)-219\times 77.9[/tex]

         [tex]= -68845.14-17060.1[/tex]

         [tex]= -85905.24 \ N[/tex]

hence,

The delivered power will be:

= [tex]F^{th}\times Vj[/tex]

= [tex]-85905.24\times 219[/tex]

= [tex]-18813247.56 \ W[/tex]

Thus the solution above is right.

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Which change to an object would double its potential energy?
OA. Increasing its mass to four times its original value
O B. Reducing its mass to one-half of its original value
OC. Reducing its height to one-half of its original value
OD. Increasing its height to twice its original value

HELPPPPP!!! PLZ

Answers

Answer: The answer is D! Hope this helps!

Explanation:

Answer:

It’s D for ape.x

Explanation:because I’m smarttttttt

come in my free candy van located at Skellerupvej 43, 8600 Silkeborg, Denmark

Answers

Answer:

Did you think you could pull that off-

:I

I live in Japan anyway so.. ウーフ-

If The density of this stainless steel is7.85 g/cm3,specific heatis 0.5 J/g.K, melting pointis 1673K, heat of fusion s0.260J/kg. How much energy is required to re-melt this tube completely from room temperature

Answers

Answer:

[tex]\Delta H=687.4 J[/tex]

Explanation:

Hello!

In this case, for this melting process, we can identify two sub-processes in order to take the stainless steel from solid to liquid:

1. Heat up from 298.15 K to 1673 K.

2. Undergo the phase transition.

Both process have an associated enthalpy as shown below:

[tex]\Delta H_1=1g*0.5\frac{J}{g*K} (1673K-298.15K)=687.4J[/tex]

[tex]\Delta H_2=0.001kg*\frac{0.260J}{kg} =0.00026J[/tex]

Therefore, the required heat is:

[tex]\Delta H=\Delta H_1+\Delta H_2\\\\\Delta H=687.4J+0.00026J\\\\\Delta H=687.4J[/tex]

Notice the problem is not providing neither the mass or volume, that is why we assumed the mass is 1 g; however, it can be changed to the mass you are given.

Best regards!

a rock falls for 4 seconds. How far did it fall

Answers

Answer:

d = 80 m

Explanation:

It is given that,

A rock falls for 4 seconds.

We need to find how far did it fall.

let it cover d distance.

Using equation of motion to find it :

[tex]d=ut+\dfrac{1}{2}at^2[/tex]

Here, u = 0 (at rest initially)

a = g

[tex]d=\dfrac{1}{2}gt^2\\\\d=\dfrac{1}{2}\times 10\times 4^2\\\\d=80\ m[/tex]

It will fall at a distance of 80 m.

pls tell the answer​

Answers

Just flip one of the batteries to connect one's positive terminal to others negative terminal.

Which electromagnetic waves have the shortest wavelength and the highest frequency?
i tried gamma and it said it was inncorect plz help

Answers

It’s supposed to be gamma, what are your other options

Which of the following is a definition of motion?

Answers

Answer:

sorry I don't get it so pls can u repeat the question .

Movement of any object from one position to another position with respect to the observer is called as Motion. Motion Along a Straight Line: When an object moves along a straight line, the motion of the object is called rectilinear motion. For example; motion of a car on highway.

QUESTION:

Which of the following is a definition of motion?

ANSWER:

In physics, motion is the phenomenon in which an object changes its position over time. Motion is mathematically described in terms of displacement, distance, velocity, acceleration, speed, and time.

How is the pressure of a gas related to its concentration of particles?

Answers

Increasing the pressure of gas is like exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume.
Hope this helps!

Answer:

Explanation:

Pressure will expand a gas, enlarging its volume and reducing its density and concentration of particles. Pressure will magnify a gas, developing its volume and multiplying its density and concentration of particles.

Increasing the pressure of a gas is exactly the same as increasing its concentration. If you have a given mass of gas, the way you increase its pressure is to squeeze it into a smaller volume. If you have the same mass in a smaller volume, then its concentration is higher.

The maker of an automobile advertises that it takes 13 seconds to accelerate from 5 kilometers per hour to 65 kilometers per hour. Assuming constant acceleration, compute the acceleration in meters per second per second. Round your answer to three decimal places.

Answers

Answer: the acceleration is 1.282 m/s²

 

Explanation:

Given that;

Time t = 13 sec

Initial velocity U = 5 kmph = (5 × 1000)/(60 × 60) = 1.3888 m/s

final velocity V = 65 kmph = (65 × 1000)/(60 × 60) = 18.0555 m/s

Now we know that;

V = U + at

we substitute

18.0555 = 1.3888 + 13a

18.0555 - 1.3888 = 13a

13a = 16.6667

a = 16.6667 / 13

a = 1.282 m/s²

Therefore the acceleration is 1.282 m/s²

please write the definition of instantaneous speed, velocity and acceleration and solve problems on them please show workings​

Answers

Answer:

instantaneous speed: The instantaneous speed is the speed of an object at a particular moment in time. And if you include the direction with that speed, you get the instantaneous velocity. In other words, eight meters per second to the right was the instantaneously velocity of this person at that particular moment in time.

velocity: the speed of something in a given direction.

acceleration: a vehicle's capacity to gain speed within a short time.

solve problems: Problem solving consists of using generic or ad hoc methods in an orderly manner to find solutions to problems.

Explanation:

Roughly speaking, the radius of an atom is about 10,000 times greater than that of its nucleus. If an atom were magnified so that the radius of its nucleus became 2.0 cm, about the size of a marble, what would be the radius of the atom in miles

Answers

Answer:

0.124 miles

Explanation:

Since the radius of the atom R = 10000r where r = radius of nucleus. Now, if r = 2.0 cm = 0.02 m,

R = 10000r

= 10000 × 0.02 m

= 200 m

We know that 1 mile = 1609 m.

So the radius of the atom in miles is R = 200 m × 1 mile/ 1609 m = 0.124 miles

So, the radius of the atom in miles is 0.124 miles  

What is the speed of a car that traveled 56 m in 4 seconds?

Answers

Answer:

[tex]\boxed {\boxed {\sf 14 \ meters \ per \ second}}[/tex]

Explanation:

Speed is the rate of motion and can be found by dividing the distance by the time.

[tex]s=\frac{d}{t}[/tex]

The distance covered is 56 meters and the time taken is 4 seconds.

[tex]d= 56 \ m \\t= 4 \ s[/tex]

Substitute the values into the formula.

[tex]s=\frac{56 \ m}{4 \ s}[/tex]

Divide.

[tex]s= 14 \ m/s[/tex]

The speed of the car is 14 meters per second

A 40-kg person is climbing 3 m up a flight of stairs in 6 seconds. How much work did they do climbing the stairs? (acceleration due to gravity = 10 m/sec2)

Answers

Answer:

1200J

Explanation:

W.D=mass×accelerarion due to gravity×distance

W.D=40kg×10m/s²×3m

W.D=1200kgm²/s²

W.D=1200J

A 40 kg person is climbing 3 m up a flight of stairs in 6 seconds, then the work done by the person to climb the stairs is 1200 J.

What is Work done?

When we apply a force called "F" to a block, the body moves with an acceleration or, additionally, its speed changes depending on the force's direction. The system's kinetic energy changes depending on whether the speed increases or decreases.

Energy must be transformed into another form because, as far as we are aware, it cannot be created or destroyed. In this view, it is referred to as work completed.

[tex]Work\ done = Force*Distance[/tex]

and Force = mg

Substitute all the values in the above formula,

W.D = 40 kg × 10 m/s² × 3 m

W.D = 1200 kg m²/s² or,

W.D = 1200 J

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1) A rock is thrown downward from the top of a 40.0-m-tall tower with an initial speed of 12 m/s. Assuming
negligible air resistance, what is the speed of the rock just before hitting the ground?

Answers

Answer:

By using [tex]v^{2}_{f} = v^{2}_{i} + 2a\Delta y[/tex], with [tex]v_{i} = -12m/s[/tex] and [tex]\Delta y = -40m[/tex]:

[tex]v^{2}_{f} = v^{2}_{i} + 2a/Delta y[/tex]

[tex]v^{2} = (-12m/s)^{2} + 2(-9.80m/s^{2})(-40m)[/tex]

[tex]v = -30m/s[/tex]

Explanation:

Hope this helped!

A rock is thrown downward from the top of a 40 m tall tower, with The speed of the rock just before hitting the ground will be equal to -30 m/s.

What is Friction?

Friction is the resistance to a thing moving or rolling over another solid object. Although frictional forces can be advantageous, such as the traction required to walk while slipping, they also provide a significant amount of resistance to motion. In order to overcome frictional resistance in the moving parts, about 20% of an automobile's engine power is used.

The forces of attraction, also referred to as adhesion, between the contact zones of the surface, which are always minutely uneven, seem to be the main contributor to friction between metals.

From the given information in the question,

v²(f) = v²(i) + 2aΔy

v² = (-12 m/s)² + 2(-9.8)(-40)

v = -30 m/s.

Therefore, the velocity of the rock is -30 m/s.

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i need answers
100 points help me nowwww

Answers

Answer:

it is c trust me im smart

Which has a stronger force binding the nucleus together Hydrogen and Helium

Answers

Answer:

Explanation:

Nucleus

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