The tension in the rope while the blocks are falling, before either hits the ground is zero and it would be the same even if she had been holding the lighter block initially.
Given the mass of light block = m
The mass of heavy block = M
acceleration due to gravity = g
Let the tension in the rope be T
From Newtons second law of motion we know that F = ma where a is acceleration of the system.
In that situation, gravity is the sole external force that is important to us. Fnet = Fg = m(sys)a
The total mass of system = m+M. Then
(m+M)g = (m+M)a
Therefore, the blocks must be falling with the acceleration of free fall at a = g. Here, the lighter system is fastened to a heavy block. Gravity pulls it lower as it falls, so any strain would be upward.
Fnet = Fg - T = ma where m is the mass of the lighter block.
mg - T = ma. This is only accurate if T = 0. The string is therefore not under any tension.
Hence the tension will not change even if the order of blocks is reversed.
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under what condition will you and a friend share the same realm of spacetime?
These two situations will allow you and a friend to share the same region of spacetime: you are both side by side and travelling at constant speed; or you are both side by side and at rest.
A particle gains constant velocity when it crosses an equal-length linear path multiple times at regular intervals. The uniform speed of a particle travelling in a straight line at a constant speed is another definition. This means that the particle will move along a straight line at constant speed. In physics, the concept of spacetime refers to a mathematical model that unifies an inertial reference frame of space and time (x, y) with a non-inertial reference frame of space and time (x', t') to create a four-dimensional model that connects a position to the field.
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A 67-kg skier grips a moving rope that is powered by an engine and is pulled at constant speed to the top of a 23∘ hill. The skier is pulled a distance x = 300 m along the incline and it takes 2.0 min to reach the top of the hill.
If the coefficient of kinetic friction between the snow and skis is μk = 0.10, what horsepower engine is required if 30 such skiers (max) are on the rope at one time?
Express your answer using two significant figures.
The required horsepower engine is 32 horsepower.
What is the force of the 30 skier?The force of the 30 skiers is calculated as follows:
Force = mass * accelerationMass of the skiers = 30 * 67kg = 2010 kg
Net force acting on the skiers along the x-axis
Fx = mgsinθ + f --- (1)where f is the frictional force
The kinetic frictional force, f = μN
where
μ = The coefficient of the kinetic friction
N = normal reaction
Net force acting on the skiers along y axis, the
Fy = ma
N = mg cos θ
Substituting for N above
f = μk mg cos θ
Substituting for f in (1)
F = mg sin θ + μk mg cos θ
F = mg(sinθ + μk cos θ)
Work done by the engine in pilling up the skiers, W = Fx
W = mg ( sinθ + μk cos θ)x
x = 300 m
W = (2010 kg) (9.81 m/s²) (sin 23° + (0.10) cos 23°) (300 m)
Work done, W = 2.86 * 10⁶ J
Time taken, t = 2.0 * 60sec = 120 s
Power = Work done/time taken1 horsepower = 746 W
Power = 2.86 * 10⁶/ 120 * 1/746
Power = 31.9 horsepower
In conclusion, the power of the engine is the ratio of the work done and time taken.
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I AM OFFERING 100 POINTS!!! I REALLY NEED HELP!!!!!!
Part C
Now prepare the cold sand and cold water samples from part A:
Fill a 100-milliliter container with 50 grams of sand. Fill a 100-milliliter container with 50 grams of cold tap water. Fill the last 100-milliliter container with 100 grams of cold tap water. Use the scale to measure the masses.
*Image should be there*
2. Pour all the ice cubes into a tub, and fill it with cool tap water to a depth of 2 inches. Place the sand and water samples in the ice water. Cover the entire tub.
*Image should be there*
3. Every 15 minutes, remove the cover and check the temperatures of the samples using the three thermometers. Wait 30 seconds before recording the thermometer reading. Once the temperatures of the three samples are no more than a degree apart, record the temperatures.
*Image should be there
Answer:
Every 15 minutes, remove the cover and check the temperatures of the samples using the three thermometers. Wait 30 seconds before recording the thermometer reading. Once the temperatures of the three samples are no more than a degree apart, record the temperatures.
(three 100-milliliter containers (each with a thermometer) in an ice bath inside an uncovered basin, with one container holding 50 grams of sand, one holding 50 grams of cold water, and one holding 100 grams of cold water)
Next, prepare the hot water.
-Fill each of the three 200-milliliter containers with 100 grams of hot tap water. Measure the mass using the mass scale.
(100 grams of hot water in a 200-milliliter container atop a mass scale)
-Prepare a hot-water bath by boiling water in a pot. Use the heat mitts to pour the hot water from the pot into the second tub. Fill the tub to a depth of about 2 inches. Carefully place the three containers of hot water into the bath without submerging them. Cover and wait for five minutes until the temperatures stabilize.
(three 200 mL containers (each holding 100 grams hot water) in a covered tub containing 2 inches of boiling water)
Prepare to mix the cold samples with hot water:
-Have three empty 300-milliliter mixing containers and three thermometers ready. Timing is important. Uncover the cold-water bath, and pour each cold sample into a different mixing container.
(three 300-milliliter containers (each with a thermometer), one holding 50 grams of sand, one holding 50 grams of cold water, and one holding 100 grams of cold water)
-Uncover the hot-water bath, and use a heat mitt to remove the three containers of hot water from the hot-water bath. Pour 100 grams of hot water into each mixing container.
(three 300 mL containers (each with a thermometer), one holding a 150-gram mixture of sand and hot water, one holding a 150-gram mixture of cold water and hot water, and one holding a 200-gram mixture of cold water and hot water)
Explanation:
A 1.0 mal sample of an ideal pas is kept at 0.0°c during an expansion from Bradba xa 3.0 litre to 10.0 litre a) How much work is done on the pas during the expansion? b) How much everly transfer by heat occurs with the surroundings in this Process?
The work done during expansion is 2.73×10³J and the heat transferred to the surrounding is -2.73×10³ J
What is isothermal process ?The thermodynamic process which takes place in constant temperature of the system is called isothermal process.
What is work done in isothermal process?Due to change in volume of the system at constant temperature, some work is done .As, the temperature of gas is fixed. This process is isothermal.Now, work done (W) = nRT ln ( V2/V1)where W = work done by the systemn= number of moles
R= universal gas constant
V2= volume of the system after expansion
V1= volume of the system before expansion
W= (1)(8.31)(273)ln ( 10/3)= 2.73×10³ J.
Also in isothermal process the amount of work done by the system = -( the amount of heat transferred to the surrounding)So the amount of heat transferred is -2.73×10³ JThus, we can conclude that a) the amount of work done is 2.73×10³J and b) the amount of heat transferred to the surrounding is -(2.73×10³J).
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A person has a reasonable chance of surviving a car crash if the deceleration is no more than 30 'g's (g=9.8m/s2). Calculate the force on a 70 kg person undergoing this acceleration. What distance is travelled if the person is brought to rest at this rate from 100 km/h?
Thus, the distance traveled by automobile is [tex]=1.31m[/tex]
How do you find the distance traveled by automobile?Newton's second law can be used to compute the force being applied to the subject. The force is calculated as the product of the vehicle's acceleration and the person's mass. Newton's third law can be used to calculate the distance driven by a car.The mass of the person is [tex]m=65kg[/tex]
The deceleration of the automobile is [tex]a=30g[/tex]
The acceleration due to gravity is [tex]g=9.81m/s.[/tex]
The initial velocity of the automobile is [tex]v_{i}=100 km/h*\frac{1m/s}{3.6km/h} =27.78m/s[/tex]
Determination of the force exerted on the person:
The force applied to the person can be calculated using Newton's second law as follows:
[tex]F=ma[/tex]
[tex]30g[/tex]Here, m denotes the person's mass, while a denotes the car's acceleration. Because the driver is moving at 30g, the car's acceleration is assumed to be positive.
Substitute the values as 70 kg for [tex]m,(30g)[/tex] for a, and[tex]9.81m/s^{2}[/tex]
for g in the above equation.
[tex]F=70kg*30g[/tex]
[tex]=70kg*30g*9.81m/s^{2} (\frac{1N}{1kg*m/s^{2} })[/tex]
[tex]=20,601N[/tex]
Thus, the force acting on the person is [tex]=20,601N[/tex]
Determination of the distance traveled by automobile:
The final velocity of the car can be calculated using Newton's third law and represented as follows:
[tex]v_{f} ^{2}=v_{i} ^{2}+2ad[/tex]
[tex]d=\frac{v_{f} ^{2}=v_{i} ^{2}}{2a}[/tex]
Here [tex]v_{f}[/tex] is the final velocity of the automobile. The final velocity of the automobile becomes 0 m/s as the automobile comes to rest. The acceleration is taken to be negative because the automobile is decelerating at [tex]30g[/tex]
Substitute the values as [tex]0 m/s[/tex] for[tex]v_{f} =27.78m/s[/tex], for[tex]v_{i} ,(-30g)[/tex], for a, and [tex]9.81m/s^{2}[/tex]for g in the above equation.
[tex]d=\frac{(0 m/s)^{2} - (27.78m/s)^{2} }{2*(-30)*9.81m/s^{2} }[/tex]
[tex]=1.31m[/tex]
Thus, the distance traveled by automobile is[tex]=1.31m[/tex]
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Find the speed of a satellite in a circular orbit around the Earth with a radius 3.57 times the mean radius of the Earth. (Radius of Earth = 6.37×103 km, mass of Earth = 5.98×1024 kg, G = 6.67×10-11 Nm2/kg2.)
The speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.
Speed of the satellitev = √(GM/r)
where;
G is universal gravitation constantM is mass of Earthr is radius of the satellitev = √(6.67 x 10⁻¹¹ x 5.98 x 10²⁴/3.57 x 6.37x 10³)
v = 1.32 x 10⁵ m/s
Thus, the speed of the satellite in a circular orbit around the Earth is 1.32 x 10⁵ m/s.
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The south pole of a bar magnet is brought toward the current loop of (Figure 1). Part A Does the bar magnet attract, repel, or have no effect on the loop? Explain. Match the words in the left column to the appropriate blanks in the sentences on the right.
Given a current loop, find the direction of the magnetic field using the right-hand rule The magnetic field created by the current loop goes from right to left.
Current travels clockwise (relative to the magnet), so now bend the fingers of your right hand clockwise and point your thumb in the direction of the magnetic field.
This creates a magnetic dipole with the north pole on the left and the south pole on the right.
Now, in a magnet, opposite poles attract and like poles repel, so if we move the magnet towards the loop as shown in the figure, his south pole of the magnet will be repelled by the nearest south pole of the current loop. increase.
Magnetic field in current loopA current in a circular loop creates a magnetic field that is more concentrated in the center of the loop than outside it. Stacking multiple loops further concentrates the field in what is called a solenoid.
What is the magnetic moment of the current loop?The magnetic moment m of a current loop is a vector whose magnitude is equal to the area of the loop times the magnitude of the current flowing through it (m = IA) and whose direction is perpendicular to the plane through which the current flows. .
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The cathode-ray tubes that generated the picture in early color televisions were sources of x rays. If the acceleration voltage in a television tube is 14.6 kV , what are the shortest-wavelength (in nm) x rays produced by the television? (Modern televisions contain shielding to stop these x rays.)
The shortest-wavelength (in nm) x rays produced by the television is when a cathode-ray tubes that generated the picture in early color televisions were sources of x rays is 0.85Å.
Given the accelerating voltage in a television tube (V) = 14.6KV
We know that from energy equation E = eΔV where e is the charge.
Also E = hc/∧ where h is planck's constant, c is the speed of light and ∧ is the wavelength of light.
So by comparing above equations, we say that
eΔV = hc/∧ where hc = 1240eV
e x 14.6 x 10^3 V = 1240/∧ eV
∧ = 1240/14.6 x 10^3 = 8.5 x 10^-2 nm = 0.85Å.
Hence the the shortest-wavelength (in nm) x rays produced by the television is 0.85Å.
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A car drives to 15 KN east and then 45 cam North what is the magnitude of the cars displacement
The resultant displacement of the car can be determined using Pythagorean theorem. The magnitude of car's displacement here is 47.3 Km.
What is displacement ?Displacement is a vector quantity measuring the change in position of an object. It can be used in short term distances. Displacement have both magnitude and direction.
Given , distance to travelled to east = 15 km
to the north = 45 km
then, the two points if connected will form a triangle where we can use the Pythagorean theorem to find the resultant vector.
The resultant displacement = √(45² + 15 ²) = 47.3 km
Therefore, the displacement of the car is 47.3 km.
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Which of the following are properties of mechanical waves?
A. The particles of the medium always move parallel to the wave
motion.
B. Particles of the medium move back and forth, but do not move
with the wave.
C. Wave motion begins with a disturbance in the medium.
D. Waves transport energy from a source outward, away from the
source.
A wave in which the particles of the medium move in the same direction as the wave is a longitudinal wave.
What is longitudinal wave?Longitudinal waves are waves in which individual particles in the medium move parallel to the direction of propagation of the disturbance.Particles do not move from one place to another, they just oscillate back and forth around their rest position.Longitudinal waves are waves in which the displacement of the medium occurs in the same direction as the direction of the traveling wave. The distance between the centers of two successive compression or thinning regions is defined by the wavelength λ.In longitudinal waves, particles move parallel to the direction of wave propagation. An example of a longitudinal wave is compression traveling along a slinky. Horizontal longitudinal waves can be created by pushing or pulling the Slinky horizontally.To learn more about longitudinal wave from the given link:
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if you dip your hand in cold water after having dipped in warm water, will you feel the water colder than it actually is?
Answer:
Yes.
Explanation:
When you move your hand from the cold water to the “warmer” (room temp) water, one hand feels warm.
As you move your hand from the warm water to the “colder” (room temp) water, that hand feels colder.
Although both hands experience the last bowl of water at the same temperature, your brain senses two
separate sensations. So the water feels “warm” or “cold” relative to the water your hand was in previously.
The greater the difference in temperature, the easier it is to sense a difference.
You apply a force on an object that is 100 times its mass. The acceleration of the object will be 100m/s^2. After a while, it perpendicularly hits another object with a mass 10 times smaller than the first object. When they collide, in theory, the momentum of the first object will all get transferred into the small object. And that means, the heavy object will completely be at rest, while the smaller object will have a force applied to it by the big object equal to ma. In real life, it seems that when two objects collide, the bigger object doesn’t completely stop and just pushes the smaller or the same massed object. In real life, it seems that when the collision happens, the first object continues moving towards the other object, and doesn’t completely get at rest right after the collision. Why is that?
The bigger object will move some distance because the initial and final momentum of the colliding particles are not zero.
What is momentum?The term momentum has to do with the product of mass and velocity. We know that during a collision, momentum is conserved. This implies that the momentum before collision is equal to the momentum after collision. Thus, the total momentum of the system is constant.
Given the fact that the initial and final momentum of the colliding particles are not zero, the the big object is not going to stop immediately but must move some distance towards the smaller object.
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The pulley is assumed massless and frictionless and rotates freely about its axle. The
blocks have masses m1 = 40 g and m2 = 20 g, and block m1 is pulled to the right by a
horizontal force of magnitude F = 0.03 N. Find the magnitude of the acceleration of block m2 and the tension in the cord if the surface is frictionless
The magnitude of the acceleration of block m2 is 0.5 m/s² and the tension in the cord if the surface is frictionless is 0.02 N.
Acceleration of block m2
The acceleration of bock m2 is calculated from Net force exerted by the pulley.
F - T = m2a
F - m1a = m2a
F = m2a + m1a
F = a(m2 + m1)
a = F/(m1 + m2)
a = (0.03) / (0.04 + 0.02)
a = 0.5 m/s²
Tension in the cordT = m1a
T = 0.04 x 0.5
T = 0.02 N
Thus, the magnitude of the acceleration of block m2 is 0.5 m/s² and the tension in the cord if the surface is frictionless is 0.02 N.
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A cat runs and jumps from one roof top to another which is 5 meters away and 3 meters below
Answer: 6.45 m/s
Explanation:
Find out the time value
3 = 1/2*a*T^2
6/10 = t^2
t = 0.77 seconds
and the distance is given as 5 m
thus speed,= distance/time.
Putting values,
speed = 5/0.77
= 6.45 m/s
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A boy of mass 30.0 kg is sledding down a 70.0-m slope starting from rest. The slope is angled at 15.0° below the horizontal. After going 28.0 m along the slope, he passes his friend, who hops onto the sled. The friend has a mass of 50.0 kg, and the coefficient of kinetic friction between the sled and the snow is 0.120. Ignoring the mass of the sled, find their speed at the bottom.
In m/s
The speed of the boy and his friend at the bottom of the slope is 16.52 m/s.
Their speed at the bottomApply the principle of conservation of energy,
E(up) - E(friction) = E(bottom)
mg sin(15) + ¹/₂(M + m)u² - μ(M + m)cos 15 = ¹/₂(M + m)v²
[tex]v = \sqrt{2[\frac{mgd \ sin15 \ + \frac{1}{2}(M + m)u^2 \ -\mu (M + m)g cos\ 15 }{M + m}] }[/tex]
where;
u is the speed of the after 28 mu = √2gh
u = √(2gL sin15)
u = √(2 x 9.8 x 28 x sin 15)
u = 11.92 m/s
[tex]v = \sqrt{2[\frac{(30)(9.8)(70) \ sin15 \ + \frac{1}{2}(30 + 50)(11.92)^2 \ - 0.12 (30 + 50)9.8 cos\ 15 }{30 + 50}] }\\\\v = 16.52 \ m/s[/tex]
Thus, the speed of the boy and his friend at the bottom of the slope is 16.52 m/s.
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What word means the same thing as force of gravity?
A. Density
B. Weight
C. Mass
D. Volume
Answer:
B. Weight
Explanation:
Weight is the force of gravity exerted on a body
OR
It's the force exerted on a body by the influence of the earth's gravitational force
Solve the following numerical problems
Answer:
See below
Explanation:
To change C to F°
F = 9/5 C + 32
= 9/5 ( 45) + 32 = 113° F
To change F to C° <= you could use the same equation...or re-earrange to:
C = 5/9 (F-32)
= 5/9 ( 98.6 - 32) = 37° C
Similarly
100 C = 212 ° F
to change C ° to K add 273.15 = 373.15 K
What is it in Einstein's Relativity Theory that made others believe that something like wormholes exists?
Answer: proposing the existence of "bridges" through space-time
Sorry if this isn't helpful.
Explanation:
A tennis player tosses a tennis ball straight up and then catches it after 1.64 s at the same height as the point of release.
(a) What is the acceleration of the ball while it is in flight?
magnitude ______ m/s2
Which direction?
1. Upward
2. Downward
3. The magnitude is zero
(b) What is the velocity of the ball when it reaches its maximum height?
magnitude _______________ m/s
Which direction?
1. Upward
2. Downward
3. The magnitude is zero
(c) Find the initial velocity of the ball.
______m/s upward
(d) Find the maximum height it reaches.
___________m
A. The acceleration of the ball while it is in flight?
magnitude is 0 m/s² (magnitude is zero)
B. The velocity of the ball when it reaches its maximum height is 0 m/s (magnitude is zero)
C. The initial velocity of the ball 8.036 m/s upward
D. The maximum height reached by the ball is 3.29 m
A. How to determine the acceleration in the flightConsidering that the ball came to rest after 1.64s, it means the entire acceleration of the flight is zero as the ball was not moving in any form again.
B. How to determine the velocity at maximum heightAt maximum height, the velocity of the ball is zero as it no longer has magnitude to keep going upwards. Hence the ball begins to ball down.
C. How to determine the initial velocityAcceleration due to gravity (g) = 9.8 m/s²Final velocity (v) = 0 m/sTime of flight (T) = 1.64 sTime to reach maximum height (t) = T / 2 = 1.64 / 2 = 0.82 sInitial velocity (u) =?v = u - gt (since the ball is going against gravity)
0 = u - (9.8 × 0.82)
0 = u - 8.036
Collect like terms
u = 0 + 8.036
u = 8.036 m/s upward
D. How to determine the maximum height reached by the ballTime to reach maximum height (t) = T / 2 = 1.64 / 2 = 0.82 sAcceleration due to gravity (g) = 9.8 m/s²Maximum height (h)h = ½gt²
h = ½ × 9.8 × 0.82²
h = 3.29 m
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what would be the radius of a 23892u nucleus if it had the density of the earth?
Since volume grows as a cube of radius, a planet with a 1.5 earth radius would have a volume that is 1.53, or roughly 3.375 times that of the current Earth.
Given that Earth has a density of 5.513 g/cm3, its new density would be around 1.63 g/cm3 if its radius were doubled by 50% but its mass remained constant. Jupiter has a density of 1.326 g/cm3 as a point of comparison. However, it's possible that you're referring to what would happen if both size and mass were scaled appropriately, making this new Earth identical to existing super-earths with 1.5 earth radii. The density would then be around 6-7 g/cm3.
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Four quantum particles, each with energy E, approach the potential-energy barriers seen in the figure (Figure 1)from the left.
Rank in order, from largest to smallest, the tunneling probabilities (Ptunnel)a to (Ptunnel)d.
Rank from largest to smallest. To rank items as equivalent, overlap them.
Rank from largest to smallest, To rank items as equivalent, overlap them is Pd>Pa>Pb>Pc.
What is quantum particles ?
A quantum particle has a complex wave function that is square-integrable and has the form (x1,... xN), where ||2 is the probability density of finding N particles at positions x1,x2,... xN. These places are taken to be inside a square box of size d, with side length L, periodic boundary conditions, and position V.
What is potential energy ?
Potential energy is a form of energy that can be stored but is affected by the way a system's component elements are assembled. A steel ball is more energetic when it is raised above the ground than when it is lowered.
Therefore, rank from largest to smallest, To rank items as equivalent, overlap them is Pd>Pa>Pb>Pc.
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What is the equation used to find the angle of refraction? Identify each variable. (1 point)
Answer:
pictures please
Explanation:
I need a picture so I can tell you
A block of mass
m = 2.50 kg
is pushed
d = 2.10 m
along a frictionless horizontal table by a constant applied force of magnitude
F = 14.0 N
directed at an angle
= 25.0°
below is a photo of the horizontal as shown in the figure below.
(a) Determine the work done by the applied force.
_____J
(b) Determine the work done by the normal force exerted by the table.
_____J
(c) Determine the work done by the force of gravity.
_____J
(d) Determine the work done by the net force on the block.
_____J
(a) The work done by the applied force is 26.65 J.
(b) The work done by the normal force exerted by the table is 0.
(c) The work done by the force of gravity is 0.
(d) The work done by the net force on the block is 26.65 J.
Work done by the applied force
W = Fdcosθ
W = 14 x 2.1 x cos25
W = 26.65 J
Work done by the normal forceW = Fₙd
W = mg cosθ x d
W = (2.5 x 9.8) x cos(90) x 2.1
W = 0 J
Work done force of gravityThe work done by force of gravity is also zero, since the weight is at 90⁰ to the displacement.
Work done by the net force on the block∑W = 0 + 26.65 J = 26.65 J
Thus, the work done by the applied force is 26.65 J.
The work done by the normal force exerted by the table is 0.
The work done by the force of gravity is 0.
The work done by the net force on the block is 26.65 J.
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also due rn sooo thx
Earth's most recent glacial period ended about 11,500 years ago.
The Great Oxygenation Event began about 2.3 billion years ago.
About 160 years ago carbon dioxide began increasing exponentially to unprecedented levels.
What is the glacial period?A glacial period is described as an interval of time within an ice age that is marked by colder temperatures and glacier advances.
There are three types of continental glaciers, and they include:
ice sheets, ice caps, and outlet.An ice sheet covers an area larger than 50,000 square kilometers. Greenland and Antarctica and are covered by massive ice sheets today.
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The angle of incidence when light travels from air to water of refractive index 4/3 and then to glass of refractive index 1.60 is 60 degrees. Calculate the angle of refraction in the glass.
The angle of refraction in the glass is 37.51 degree
How can we calculate the angle of refraction in the glass?The angle of incidence when light travels from air to water of refractive index 4/3 and then to glass of refractive index 1.60 is 60 degrees. To calculate the angle of refraction in the glass, we can use Snell's law, which states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the refractive indices of the two materials.
Sin(incident angle) / Sin(refraction angle) = (refractive index of air) / (refractive index of glass)
sin(60) / sin(x) = 1 / 1.60
where x is the angle of refraction in the glass.
Solving for x,
x = sin^-1(sin(60) / 1.60)
= sin^-1(1 / 1.60)
= sin^-1(0.625)
=37.51 degree
Therefore, the angle of refraction in the glass is 37.51 degree.
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Velocity and Acceleration Problem
Answer:
velocity is a hell of a drug treatment classes in the position you are offering to help you with your medical needs and your needs and your needs and your needs and your needs for the future and to be getting your son in a better place for the better of the richest of his family and his life in the world.
Explanation:
no exceptions
in a television picture tube, electrons strike the screen after being accelerated from rest through a potential difference of 24 950 v. the speeds of the electrons are quite large, and for accurate calculations of the speeds, the effects of special relativity must be taken into account. ignoring such effects, find the electron speed just before the electron strikes the screen.
Moving from an area of lower potential to a region of higher potential causes electrons to accelerate. The law of conservation of energy controls the acceleration of the electrons from rest. The final speed can then be determined from the conservation rule by using the electron's speed shortly before it reaches the screen.
What are the electron speed or electricity?The passage of electrons (or other charge carriers) through a conductor in the presence of a potential difference or an electric field is commonly referred to as electricity. There are several interpretations of this flow's pace. While the electrons themselves move far more slowly in common electrical and electronic devices, the signals do so as electromagnetic waves that typically travel between 50% and 99% of the speed of light in a vacuum. For further information, see drift velocity and electron mobility. The speed of an electromagnetic wave flowing along (being steered by) a cable is the pace at which energy or signals go down the wire. In other words, a cable is a type of waveguide. The interaction of the wave with the material(s) inside and around the cable.
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D. A bargain hunter purchases a "gold" crown at a flea market. After she gets home, she hangs it from a scale and finds its weight to be 7.84 N. She then weighs the crown while it is immersed in water, and now the scale reads 6.86 N. Is the crown made of pure gold? Find the density of the crown and compare it to the it to density of the gold.
Answer:
Wc = 7.84 weight of crown
Ww = 7.84 - 6.86 = .98 weight of water displaced
Density = 7.84 / .98 = 8 crown is 8 X that of water
Since gold has a density of 19.3 that of water the crown is certainly not 100 percent (if any) gold
Which statement about alcohol's path through the human body is true?
a.
alcohol is metabolized by the kidneys
b.
no digestion is needed in alcohol absorption
c.
most alcohol is absorbed through the stomach lining
d.
consumption of food will stop alcohol from entering the bloodstream
No digestion is needed in alcohol absorption. Is statement about alcohol's path through the human body .
What is absorption in biology?
Absorption is the process by which the products of digestion are absorbed by the blood to be supplied to the rest of the body. During absorption, the digested products are transported into the blood or lymph through the mucous membrane.
What is meant by adsorption and absorption?
Adsorption and absorption mean quite different things. Absorption is where a liquid is soaked up into something like a sponge, cloth or filter paper. The liquid is completely absorbed into the absorbent material. Adsorption refers to individual molecules, atoms or ions gathering on surfaces.
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An electric motor on a rowboat does 4000 J of work in 1 minutes. What is the Power of the motor in watts
The power of the motor in watts is 4000 W.
Power (P) = Work (W) / Time (t)
P = 4000 J / 1 min
P = 4000 J/s
1 J/s = 1 W
P = 4000 W
What is power?
Power is a measure of energy transfer over time. In physics, it is the rate of energy transfer, usually measured in Watts (W) or Joules per second (J/s). Power is the rate at which work is done or energy is converted from one form to another. It can be calculated by multiplying the force applied to an object by the speed at which it moves. Power is related to work, as work is equal to the amount of energy transferred, divided by time. Power is an important concept in physics as it is used to calculate the energy required to perform a task.
Therefore, The power of the motor in watts is 4000 W.
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