A line is perpendicular to y=2/3x+2/3 and intersects the point (-2,4). What is the equation of this perpendicular line?

Answer:

It depends on the equations and the variables.

Example of an equation in 2 variables with infinitely many solutions:

sin2x - cos2y + cos2x - sin2y = 0

Example of an equation in 1 variable with 2 solutions:

(x - 1)(x - 2) = 0

Example of 2 equations in 2 variables with no solution:

The intersection of the lines given by

y = 3x + 1

y = 3x + 2

Example of an equation in 1 variable with 1 solution:

5x - 4 = 15

Example of an equation in 1 variable with no real solution:

x2 + 49 = 0

We can go on and on with examples like this. The question is way too general.

Step-by-step explanation:

please mark as brainliest

please mark as brainliest

Answer:

Does this seem right to you?

Answer:

yes im am gydyd6rrfxjdjsjwjejwhwwehebrhrhhrrhrhrhdhrhehrhehrhrhdhdhdhdhddhdgdgdhr

Answer:

definantly 3/2

Step-by-step explanation:

perpendicular means same slope

9514 1404 393

Answer:

  D'(4, 0)

Step-by-step explanation:

  (x, y) ⇒ (x +3, y -2)

  D(1, 2) ⇒ D'(1+3, 2-2) = D'(4, 0)

Answer:

b

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.

∠ 1 is an exterior angle of the triangle , then

∠ 1 = 30° + 39° = 69°

Answer:

option b:  69°

Step-by-step explanation:

the sum of the interior angles of a triangle is 180c.

that is, 39 + 30 + x = 180

                          x = 180 - 39 - 30

                          x = 111°

∠ 1 + x = 180°            [ straight line angles ]

∠1 + 111° = 180°

∠1 = 180 - 111 = 69°

Answer:

C and G

Step-by-step explanation:

Given

(x - 2)² = - 3x + 6 ← expand left side using FOIL

x² - 4x + 4 = - 3x + 6 ( subtract - 3x + 6 from both sides )

x² - x - 2 = 0 ← in standard form

(x - 2)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 2 = 0 ⇒ x = 2 → G

x + 1 = 0 ⇒ x = - 1 → C

Answer:

cube

Step-by-step explanation:

prisms are 3d figures just like cubes are

the other options are just 2d figures

[tex]\huge\tt\pink{Answer}[/tex]

C. Cube or Cuboid

A cuboid is a solid that has six rectangular faces--think of a typical box. All faces are either parallel or perpendicular to each other. Further, a cuboid is a right rectangular prism. A cuboid with six square faces is a cube, whereas a cuboid with at least two square faces is known as a square cuboid.

Answer:

Chemistry Books- 203 and Biology Books- 158

Step-by-step explanation:

I'm not sure myself how I did it since I don't have an exact method but I can guarantee that the answer is correct. (Quick sum-up of what I kinda did though. Divide both numbers by 2, then added (22, about half of 45), add 180 (about half of 361) and then subtracted 202 from 361. Realized that it was one off so I just made it 203 and 158)

Sorry for the mess of an explanation but hope it helps!

I am math lover .Before I am also not too fond of math , but if you practiced it will be easy and you loves to do maths and your interest will increase .Sorry for late Answer of attachment will be 5190.

hope it is helpful to you

Answer:

your answer will be 5,190

Step-by-step explanation:

fist you have to subtract 80 from 599 and u will get 519 then you multiply to get the answer

I am also not so good in Math so I still try to help u

Answer:

5.348

Step-by-step explanation:

5 + 0.3 + 0.04 + 0.008

If you find this difficult to calculate put zeroes in Hundredths place and thousandths place

=> 5.000 + 0.300 + 0.040 + 0.008

=>5.348

Given:

Focus of the parabola = [tex]\left(-\dfrac{1}{4},-\dfrac{2}{3}\right)[/tex]

Directrix of the parabola is [tex]y=\dfrac{3}{4}[/tex].

To find:

The equation of the parabola.

Solution:

The equation of the parabola is:

[tex](x-h)^2=4p(y-k)[/tex]             ...(i)

Where, (h,k) is vertex, (h,k+p) is focus and [tex]y=k-p[/tex] is the directrix.

It is given that the focus of the parabola is at [tex][/tex].

[tex](h,k+p)=\left(-\dfrac{1}{4},-\dfrac{2}{3}\right)[/tex]

On comparing both sides, we get

[tex]h=-\dfrac{1}{4}[/tex]

[tex]k+p=-\dfrac{2}{3}[/tex]            ...(ii)

Directrix of the parabola is [tex]y=\dfrac{3}{4}[/tex]. So,

[tex]k-p=\dfrac{3}{4}[/tex]             ...(iii)

Adding (ii) and (iii), we get

[tex]2k=-\dfrac{2}{3}+\dfrac{3}{4}[/tex]

[tex]2k=\dfrac{-8+9}{12}[/tex]

[tex]k=\dfrac{1}{12\times 2}[/tex]

[tex]k=\dfrac{1}{24}[/tex]

Putting [tex]k=\dfrac{1}{24}[/tex] in (ii), we get

[tex]\dfrac{1}{24}+p=-\dfrac{2}{3}[/tex]

[tex]p=-\dfrac{2}{3}-\dfrac{1}{24}[/tex]

[tex]p=\dfrac{-16-1}{24}[/tex]

[tex]p=\dfrac{-17}{24}[/tex]

Putting [tex]h=-\dfrac{1}{4},k=\dfrac{1}{24}, p=-\dfrac{17}{24}[/tex] in (i), we get

[tex]\left(x-(-\dfrac{1}{4})\right)^2=4\left(-\dfrac{17}{24}\right)\left(y-\dfrac{1}{24}\right)[/tex]

[tex]\left(x+\dfrac{1}{4}\right)^2=-\dfrac{17}{6}\left(y-\dfrac{1}{24}\right)[/tex]

[tex]x^2+2(x)(\dfrac{1}{4})+(\dfrac{1}{4})^2=-\dfrac{17}{6}\left(y-\dfrac{1}{24}\right)[/tex]

[tex]-\dfrac{6}{17}\left(x^2+\dfrac{1}{2}x+\dfrac{1}{16}\right)=y-\dfrac{1}{24}[/tex]

On further simplification, we get

[tex]-\dfrac{6}{17}(x^2)-\dfrac{6}{17}(\dfrac{1}{2}x)-\dfrac{6}{17}(\dfrac{1}{16})=y-\dfrac{1}{24}[/tex]

[tex]-\dfrac{6}{17}x^2-\dfrac{3}{17}x-\dfrac{3}{136}+\dfrac{1}{24}=y[/tex]

[tex]-\dfrac{6}{17}x^2-\dfrac{3}{17}x+\dfrac{-9+17}{408}=y[/tex]

[tex]-\dfrac{6}{17}x^2-\dfrac{3}{17}x+\dfrac{8}{408}=y[/tex]

[tex]-\dfrac{6}{17}x^2-\dfrac{3}{17}x+\dfrac{1}{51}=y[/tex]

Therefore, the equation of the parabola is [tex]y=-\dfrac{6}{17}x^2-\dfrac{3}{17}x+\dfrac{1}{51}[/tex]. Hence, the correct option is C.

Answer:

AO

Step-by-step explanation:

Answer:

5

Step-by-step explanation:

here,  the highest degree is 5 so the degree of polynomial is also 5.

Answer:

x = 4/5 is the one x value that is not permitted.  The domain of (fog)(x) is

(-infinity, 4/5) ∪ (4/5, infinity)

Step-by-step explanation:

(fog)(x) is the "composition" of f and g.  We start with f(x) and replace x with g(x), which is 5x - 4:

              3

f(x) = x - ------- becomes

               x

                                          3            

f(5x - 4) =     [5x - 4]  -  ------------

                                      [5x - 4]

To identify the domain, consider the value or values of x for which the denominator shown above is zero:  5x - 4 = 0, or 5x = 4, or x = 4/5

The domain of the composite function (f·g)(x) in interval notation is (-∞,0)∪(0,∞).

The domain and range are defined for a relation and they are the sets of all the x-coordinates and all the y-coordinates of ordered pairs respectively.

The given functions are f(x)= x-3/x and g(X)=5x-4.

Now, (f·g)(x)=f(x)×g(x)

= (x-3/x)(5x-4)

(f·g)(x)= 5x²-15-4x+12/x

Find the domain by finding where the expression is defined.

Interval Notation: (-∞,0)∪(0,∞)

Set-Builder Notation:{x|x≠0}

Therefore, the domain of the composite function (f·g)(x) in interval notation is (-∞,0)∪(0,∞).

To learn more about the domain and range visit:

brainly.com/question/28135761.

#SPJ7

the answer of course is bobbies

Answer

the answer if b in the above

Answer:

The answer is A - 5×9 I think so..

Answer:

m=-2

Step-by-step explanation:

Answer:

x^2-2x-13

Step-by-step explanation:

f(x) = 2x-5

g(x) = x^2 -4x-8

f(x) +g(x) = 2x-5 +  x^2 -4x-8

Combine like terms

              = x^2+2x-4x-5-8

               =x^2-2x-13

Answer:

1/4 he

Step-by-step explanation:

Answer:

1/4 hour

Step-by-step explanation:

convert 2 km to m

1 km = 1000m

2 km = 2*1000 m

=2000 m

distance                                                            time taken

2000 m                                                                   1 hour

500 m                                                                          let be x

2000/500 = 1/x

do cross multiplication

500*1 = 2000*x

500/2000 = x

1/4 = x

Answer:

D. 9h

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Geometry

Volume of a Cuboid Formula: V = a²h

Step-by-step explanation:

Step 1: Define

Identify variables

a = 3

h = h

Step 2: Find Volume

Answer:

D. 9h

Step-by-step explanation:

Volume of a cube = Length × Width× Height

= 3×3×h

= 9h

Answer:

Step-by-step explanation:

Let one number = x

Let the other number = y

x + y = 124

You can't go any further than that without more information.

The good news is that no number is excluded.

x = 248

y = -124 for example

Answer:

√10 = 3.16

Step-by-step explanation:

using calculator

√10 = 3.162277660168379

Hundredths is the second decimal place.

Since the next decimal place is less than 5

there is no need to round up

√10 = 3.16

Answer:

actually what is this is you is this a geometry, trigonometry I don't know what to call

Answer:

[tex]\huge\boxed{\boxed{\underline{\textsf{\textbf{Answer}}}}}[/tex]

╭⋟───────────────

Sentence ⇻ The product of - 11 & - 7 gives 77.

Equation ⇻ [tex]\boxed{-11(-7)=77}[/tex].

───────────────⋞╯

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

[tex] RainbowSalt2^{2}2^{2}[/tex] ❦

Answer:

-11(-7) = 77

Step-by-step explanation:

"and" = multiplication sign in maths

Answer:

-3x(7x+8)

Step-by-step explanation:

-3x^2-18x^2-24x

-3x(x+6x+8)

-3x(7x+8)

Answer:

πr + (2l + b)

Step-by-step explanation:

The figure is a composite figure, consisting of a semicircle and a rectangle :

The perimeter of a rectangle is the sum of the sides ;

Perimeter of semicircle is the 2πr/2 (Circumference / 2)

For the triangle, we take the sum of 3 sides ;

Length + length + breadth = 2l + b

Hence, the perimeter is :

2πr/2 + 2l + b

πr + (2l + b)

Answer:

379.94 in.²

Step-by-step explanation:

To find the area of a circle, multiply the radius by itself twice, then multiply the product by pi.

[tex]a=\pi r^2[/tex]

In the image, the diameter is shown.

To find the radius of a circle, divide the diameter by 2.

[tex]22/2=11[/tex]

The radius of this circle is 11 inches.

Next, multiply the radius by itself twice.

[tex]11*11=121[/tex]

Lastly, multiply the product by pi (3.14).

[tex]121*3.14=379.94[/tex]

Therefore, the area of this circle is 379.94 inches squared.

Answer:

2nd option

Step-by-step explanation:

Using the power rule

[tex]\frac{d}{dx}[/tex] (a[tex]x^{n}[/tex] ) = na[tex]x^{n-1}[/tex]

Given

f(x) = [tex]\frac{3}{2\sqrt[3]{x} }[/tex] = [tex]\frac{3}{2x^{\frac{1}{3} } }[/tex] = [tex]\frac{3}{2}[/tex] [tex]x^{-\frac{1}{3} }[/tex] , then

f'(x) = - [tex]\frac{1}{3}[/tex] × [tex]\frac{3}{2}[/tex] [tex]x^{-\frac{4}{3} }[/tex]

      = - [tex]\frac{1}{2}[/tex] × [tex]\frac{1}{x^{\frac{4}{3} } }[/tex]

      = - [tex]\frac{1}{2x^{\frac{4}{3} } }[/tex] = - [tex]\frac{1}{2\sqrt[3]{x^4} }[/tex] [ Note there should be a leading negative ]