Answer:
[tex]2.82x10^{23}molecules[/tex]
Explanation:
Hello.
In this case, given the volume (1cm³=1mL) and density of the bromine we are to firstly compute the mass since it will allow us to compute the representative particles:
[tex]\rho =\frac{m}{V}[/tex]
[tex]m=\rho *V=3.12g/cm^3*24.0cm^3\\\\m=74.88gBr_2[/tex]
Next, since the mass of one mole of diatomic bromine is 159.82 g (one bromine weights 78.91), we can next compute the moles in that sample:
[tex]n=74.88g*\frac{1mol}{159.82g} =0.469molBr_2[/tex]
Finally, via the Avogadro's number we can compute the representative particles of bromine as follows:
[tex]particles=0.469mol*\frac{6.022x10^{23}molecules}{1mol}\\ \\2.82x10^{23}molecules[/tex]
Best regards.
1) The equilibrium constant Kc of the reaction
I2 (g) ⇔ 2I (g)
is 5.6 × 10-12, at 500 K. In a system maintained at 500 K, the concentration of I2 is 0.020 mol / L and that of I is 2.0 × 10-8 mol / L. Is the reaction in balance? If not, in what sense does the reaction advance to reach equilibrium?
2) Given the concentrations below, how much is Q worth?
If Kc = 1.0, which side of the reaction is favored with this value of Q?
CO (g) + H2O (g) ⇄ CO2 (g) + H2 (g)
[CO (g)] = [H2O (g)] = 1.0 M
[CO2 (g)] = [H2 (g)] = 15 M
Explanation:
1) Find the reaction quotient:
Qc = [I]² / [I₂]
Plug in the Kc value and the I₂ concentration.
Q = [2.0×10⁻⁸]² / (0.020)
Q = 2.0×10⁻¹⁴
Since Qc < Kc, the reaction moves to the right (favors the products).
2) Find the reaction quotient:
Qc = [CO₂] [H₂] / ([CO] [H₂O])
Qc = (15) (15) / ((1.0) (1.0))
Qc = 225
Since Qc > Kc, the reaction moves to the left (favors the reactants).
Ammonia is often used as a cleaning fluid. In order to make the strongest possible solution of ammonia, would you use hot water or cold water? Why?
Based on the effect of temperature on reaction rate, to make the strongest possible solution of ammonia, it is best to use hot water.
How does temperature affect the rate of a chemical reaction?The rate of a chemical reaction is increases with increase in temperature.
This increase in rate of reaction is observed because the number of particles with energy greater than or equal to the activation energy increases.
Therefore, to make the strongest possible solution of ammonia, it is best to use hot water.
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A 5.0g sample of O2 is in a container at STP. What volume( liters) is the container? Round to the tenths place
(Need help asap)
A 5.0g sample of O₂ is in a container at STP, then the volume of the container is 3.49 L.
How do we calculate volume?Volume of oxygen sample at STP will be calculated by using the ideal gas equation as:
PV = nRT, where
P = pressure = 1 atm
V = volume of gas = ?
R = universal gas constant = 0.082 L.atm/K.mol
T = temperature = 273K
n is the moles of oxygen sample and it will be calculated as:
n = W/M, where
W = given mass = 5g
M = molar mass of O₂ = 32g/mol
n = 5/32 = 0.156 moles
On putting all values on above equation, we get
V = (0.156)(0.082)(273) / (1)
V = 3.49 L
Hence required volume of gas sample is 3.49 L.
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Which two variables determine the gravitational force between two objects?
A) their densities and the distance separating them
B) their masses and the distance separating them
C) their volumes and magnetic strengths
D) their masses and relative densities
Answer:
B
Explanation:
I did the test
A refrigerator uses_________________________ energy to move the_________________________ through the refrigerator pipes.
Answer:
thermal; coolant
Explanation:
A refrigerator transfers thermal energy from the cool air inside the refrigerator to the warm air in the kitchen. I hope this helps! ^-^
c) If nitrogen diffuses at a rate of 0.0069 m/s, how fast does carbon dioxide diffuse?
Answer:
it defuse at a rate of 0.0002 m/s
who knows this......
The convergence of two oceanic plates can give rise to deep sea trenches, island arcs, and tall folded mountains, each of which is a distinctive geological feature resulting from the complex interplay of subduction, volcanic activity, and crustal compression. options A,C and D are correct.
When two oceanic plates converge, several geological features can develop as a result of the collision. One common feature is the formation of deep sea trenches. As the denser oceanic plate subducts beneath the other plate, it creates a deep trench in the ocean floor. The subduction process leads to the downward bending of the oceanic plate, forming a trench that can extend for hundreds or thousands of kilometers.
Another feature that can develop is the formation of island arcs. As the subducting oceanic plate sinks into the mantle, it releases water and volatiles, which cause the overlying mantle to melt. This molten material rises through the Earth's crust, creating a chain of volcanic islands known as an island arc. These islands are often characterized by active volcanism and can be seen in regions such as the Pacific Ring of Fire.
Additionally, the convergence of two oceanic plates can result in the formation of tall folded mountains. As the leading edge of one plate is compressed and pushed upwards, it forms a range of folded mountains. The collision and compression forces can cause the sedimentary layers to buckle and fold, leading to the creation of prominent mountain ranges. options A,C and D are correct.
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if a gas is held in 3.60 L, 298 K AND 800. mmHg, what is the new pressure of the gas if the volume us decreased by half and the tempature is decreased to 250. K
Answer:
Explanation:
By Ideal Gas Law, P1*V1 / T1 = P2*V2 / T2
So new pressure = (P1*V1 / T1) / (V2 / T2)
= P1*V1*T2 / T1*V2
= 800*3.6*298 / 250*1.8
= 1907.2 mmHg
Apply combine gas law
[tex]\\ \rm\Rrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}[/tex]
[tex]\\ \rm\Rrightarrow P2=\dfrac{P1V1T2}{V2T1}[/tex]
[tex]\\ \rm\Rrightarrow P2=\dfrac{800(3.6)(250)}{1.8(298)}[/tex]
[tex]\\ \rm\Rrightarrow P2=720000/536.4[/tex]
[tex]\\ \rm\Rrightarrow P2=1341.7 mmHg[/tex]
Select the statements that are TRUE about dilution. Note: You must select ALL the statements to earn credit. Partial answers will not receive partial credit. Group of answer choices The number of moles of substance remains the same during a dilution. Dilution is a process of decreasing the solution's concentration by the addition of a solvent. The diluted solution will have a higher concentration than the stock solution. In the dilution formula, M1V1
The statement that are true about dilution are:
The number of moles of substance remains the same during a dilution,Dilution is a process of decreasing the solution's concentration by the addition of a solventThe properties of dilutionDilution of a solution is the process by which more solvent that makes up a solution is added to the solution to decrease it's concentration.
The properties of a solution that is diluted include the following:
The boiling point of the solution is elevatedThe is decrease in the freezing pointThere is decrease of osmotic pressure.In dilution, the amount of solute does not change, the number of moles are the same before and after dilution.
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how do i draw these lines?
bro is that genius cast that's an easy line
I can easily draw that
An atomic scientist was studying an atom which through experimentation found that the total negative charge of the area surrounding the nucleus is -9. which statement corretly describes this atom? A.the atom has 9 clouds. B.the atom has 9 electrons C.the atom has 9 neutrons. D.the atom has 9 protons.
Answer:
The answer is B
Explanation:
The area surrounding the nucleus is called the electron cloud which holds the electrons, so with the power of deduction its B. 0-0
What is a strong electrolyte?
What is a weak electrolyte?
Provide examples of each one of these categories.
Answer:
An electrolyte is medium containing ions that is electrically conducting through the movement but not conducting electrons . Strong electrolytes are electrolytes that completely ionizes in a solution . Weak electrolytes that partially ionize in a solution .
Explanation:
Strong electrolytes fully dissociate In a solution such as NH4Cl , KOH(Potassium hydroxide) and HCl ( Hydrochloric acid)
Weak electrolytes partially dissociate In a solution such as HC2H3O2 (acetic acid), H2CO3 (carbonic acid), NH3 (ammonia), and H3PO4 (phosphoric acid) .
An element that is considered to be unreactive
because it has a filled outer energy level is
1. silver.
2. hydrogen.
3. helium.
4. lithium.
Answer:
3
helium
Explanation:
Among all the given options, the correct option is option 3. An element that is considered to be unreactive because it has a filled outer energy level is helium.
What is element?Any compound that cannot be broken down into simpler chemicals by regular chemical processes is referred to as a chemical element or element. The building blocks of which every matter is made are called elements.
There are 118 chemical elements that are currently recognized. About 20% of them have only been created synthetically in the lab and are only known because they do never exist in nature or are only present in trace levels. An element that is considered to be unreactive because it has a filled outer energy level is helium.
Therefore, among all the given options, the correct option is option 3.
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Two bulbs are connected by a stopcock. The large bulb, with a volume of 6.00 L, contains nitric oxide at a pressure of 0.850 atm, and the small bulb, with a volume of 1.50 L, contains oxygen at a pressure of 2.50 atm. The temperature at the beginning and the end of the experiment is 22∘C .
After the stopcock is opened, the gases mix and react.
2NO(g)+O2(g)→2NO2(g)
1. Which gases are present at the end of the experiment?
2. What are the partial pressures of the gases? If the gas was consumed completely, put 0 for the answer.
Answer:
(I). The gases are present at the end of the experiment are O₂ and NO₂
(II). The pressure of O₂ is 0.158 atm.
The pressure of NO₂ is 0.681 atm
The Pressure of NO is zero.
Explanation:
Given that,
Volume of large bulb = 6.00 L
Pressure = 0.850 atm
Volume of small bulb = 1.50 L
Pressure = 2.50 atm
Temperature = 22°C = 295 K
We need to calculate the moles in NO
Using formula of moles
[tex]n=\dfrac{PV}{RT}[/tex]
Put the value into the formula
[tex]n=\dfrac{0.850\times6.00}{0.0821\times295}[/tex]
[tex]n=0.211\ moles[/tex]
We need to calculate the moles in O
Using formula of moles
[tex]n=\dfrac{PV}{RT}[/tex]
Put the value into the formula
[tex]n=\dfrac{2.50\times1.50}{0.0821\times295}[/tex]
[tex]n=0.155\ moles[/tex]
The balance equation for the reaction is
[tex]2NO+O_{2}\Rightarrow 2NO_{2}[/tex]
So, The gases are present at the end of the experiment are O₂ and NO₂
We need to calculate the remaining moles of O₂
Using formula for remaining moles
Moles of O₂ remaining = [tex]0.155-\dfrac{0.211}{2}[/tex]
[tex]Moles\ of \ O_{2}\ remaining =0.049\ moles[/tex]
Moles of NO₂ = 0.211 moles
Total volume [tex]V=V_{l}+V_{s}[/tex]
Put the value into the formula
[tex]V=6.00+1.50[/tex]
[tex]V=7.5\ V[/tex]
(2). If the gas was consumed completely
We need to calculate the pressure of O₂
Using formula of pressure
[tex]P=\dfrac{moles\times R\times T}{V}[/tex]
Put the value into the formula
[tex]P=\dfrac{0.049\times0.0821\times295}{7.5}[/tex]
[tex]P=0.158\ atm[/tex]
We need to calculate the pressure of NO₂
Using formula of pressure
[tex]P=\dfrac{moles\times R\times T}{V}[/tex]
Put the value into the formula
[tex]P=\dfrac{0.211\times0.0821\times295}{7.5}[/tex]
[tex]P=0.681\ atm[/tex]
If the gas was consumed completely
Then, Pressure of NO is zero.
Hence, (I). The gases are present at the end of the experiment are O₂ and NO₂
(II). The pressure of O₂ is 0.158 atm.
The pressure of NO₂ is 0.681 atm
The Pressure of NO is zero.
The gases that remained at the end of the experiment are nitrogen dioxide and nitric oxide. The partial pressure of nitric oxide has been 0.43 atm, nitrogen dioxide has been 1 atm, and oxygen has been 0 atm.
The balanced chemical equation has been given that, 2 moles of NO reacts completely with 1 mole of oxygen.
(1) According to the ideal gas equation:
PV nRT
n = [tex]\rm \dfrac{PV}{RT}[/tex]
The moles of NO;NO = [tex]\rm \dfrac{0.850\;atm\;\times\;6\;L}{0.0821\;L.atm/mol.K\;\times\;295\;K}[/tex]
Moles of NO = 0.211 moles
The moles of Oxygen:Oxygen = [tex]\rm \dfrac{2.50\;atm\;\times\;1.50\;L}{0.0821\;L.atm/mol.K\;\times\;295\;K}[/tex]
Moles of oxygen = 0.155 moles.
For 2 moles NO, 1 mole oxygen is used.
For 0.211 moles, Oxygen has been 0.422 moles.
The oxygen has been in a lesser quantity than requires, thus it has been the limiting reactant.
The gas that presents at the end of the reaction has been NO.
(2) The pressure of the gas has been calculated as:
After the complete consumption of the gas, NO remaining has been:
2 moles oxygen = 1 moles NO
0.155 moles oxygen = 0.0775 moles NO.
The moles of NO remaining = 0.211 - 0.0775 mol
The moles of NO remaining = 0.1335 mol.
The total volume of the solution will be 6 + 1.5 L = 7.5 L.
The moles of Nitrogen dioxide formed :
1 mole oxygen = 2 moles Nitric oxide
0.155 moles oxygen = 0.31 moles nitric oxide.
The partial pressure can be given by:
P = [tex]\rm \dfrac{nRT}{V}[/tex]
The pressure of NO:Pressure of NO = [tex]\rm \dfrac{0.1335\;\times\;0.08206\;\times\;295}{7.5}[/tex]
Pressure of NO = 0.43 atm.
The pressure of Oxygen = 0 atm.
The pressure of Nitrogen dioxide:
Pressure of nitrogen dioxide = [tex]\rm \dfrac{0.31\;\times\;0.08206\;\times\;295}{7.5}[/tex]
Pressure of nitrogen dioxide = 1.00 atm.
The gases that remained at the end of the experiment are nitrogen dioxide and nitric oxide. The partial pressure of nitric oxide has been 0.43 atm, nitrogen dioxide has been 1 atm, and oxygen has been 0 atm.
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how would you separate a mixture of oil,water and sand?plz help
Answer:
1) Filter the mixture, Sand will remain on the filter paper. 2) Then pour the mixture of mustard oil and in separating funnel. Water will settle down at bottom and mustard oil will float on it. Then open the stopcock of the separating funnel and pour out the lower layer of water.
Explanation:
7. The youngest part of the ocean floor is found ____.
a. along deep-sea trenches
b. where ocean sediments are thickest
c. near ocean ridges
d. where Earth’s magnetic field changes polarity
Answer:
The answer is Near The Ocean Ridges.
How many moles are in 34.51 L of C*O_{2} assuming the gas is at STP
Observation
• Use your senses to make an observation about your environment.
Questions
• Create a hypothesis that can be tested in an experiment.
Remember, a hypothesis has a specific "if then" wording. It describes what will happen to the dependent variable
when changes are made to the independent variable. For example, "If a plant is fertilized (independent variable),
then it will grow faster (dependent variable)."
.
Design and plan an experiment.
Be sure to identify an independent variable, a dependent variable, and any controls. Remember, controls are factors
which stay the same. In an experiment designed to test the previously stated hypothesis, one control would be to
use the same kind of plant. Write a complete description of your experiment. Include a list of necessary materials. It
is a good idea to follow a step-by-step procedure format. Think of everything you need to do, then write it down in
the order it must be completed. Your description and procedure should be clear enough that another person could
duplicate your experiment exactly
Answer:
Hi...... I have this same question............
Biologists and other scientists use the scientific method to ask questions about. When possible, scientists test their hypotheses using controlled experiments. Test a hypothesis by making predictions about patterns that should be seen in. This variable is independent because it does not depend on what happens in the.
Explanation:
Can someone please help me? (Answer the question only if you are going to help). Thanks
Explanation:
a is the answer ok write it easily bye
Video Worksheet
Cosmos S1E5 = Hiding in the Light
Answer:
ill try
Explanation:
What is true for ALL of the examples of electromagnetic waves?
Given what we know, we can confirm that the one property listed that is universal for all of the electromagnetic waves listed is that they all move at the same speed in a vacuum.
What are electromagnetic waves?These are a specific type of wave. These waves are the result of interactions between an electric field and a magnetic field. These waves have many properties and can be of many distinct types, however, one universal property of these waves is that all of them will move at the same speed whilst in a vacuum.
Therefore, we can confirm that the one property listed that is universal for all of the electromagnetic waves listed is that they all move at the same speed in a vacuum.
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What is the name of the compound shown here
ethane is the compound of the answer you are asking help
A sample is found to contain 66.5% NaHCO3 by mass. What is the mass of NaHCO3 in 4.25g of the sample?
Answer:
2.83 grams NaHCO₃ in the 4.25g Sample.
Explanation:
Given 4.25g Sample is 66.5% NaHCO₃
=> mass of NaHCO₃ = 0.665(4.25g) =2.83grams NaHCO₃.
The mass of NaHCO₃ in 4.25 g of the sample is 2.83 g
From the question given above, the following data were obtained:
Mass of sample = 4.25 g
Percentage by mass of NaHCO₃ = 66.5%
Mass of NaHCO₃ =?[tex]Percentage = \frac{mass of substance}{total mass} X 100[/tex]
66.5% = [tex]\frac{Mass of NaHCO_{3} }{4.25}\\\\[/tex]
Cross multiply
Mass of NaHCO₃ = 66.5% × 4.25
Mass of NaHCO₃ = 0.665 × 4.25
Mass of NaHCO₃ = 2.83 gTherefore, the mass of NaHCO₃ in 4.25 g of the sample is 2.83 g
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For the reaction shown, calculate how many grams of each product form when the following amounts of reactant completely react to form products. Assume that there is more than enough of the other reactant.
2Al(s)+Fe2O3(s)→Al2O3(s)+2Fe(l)
a) Calculate the mass of Al2O3 formed when 4.1 g of Al completely reacts.
Express your answer using two significant figures.
b)Calculate the mass of Fe formed when 4.1 g Al completely reacts.
Express your answer using two significant figures.
c)Calculate the mass of Fe formed when 4.1 g Fe2O3 completely reacts.
Express your answer using two significant figures.
According to the given balanced equation:
a) 4.1 g of Al form 7.7 g of Al₂O₃.b) 4.1 g of Al form 8.5 g of Fe.c) 4.1 g of Fe₂O₃ form 2.9 g of Fe.We want to calculate the mass of products when certain amounts of reactants react. This is a stoichiometry problem.
What is stoichiometry?Stoichiometry refers to the relationship between the quantities of reactants and products before, during, and following chemical reactions.
Let's consider the following balanced equation.
2 Al(s) + Fe₂O₃(s) → Al₂O₃(s) + 2 Fe(l)
a) Calculate the mass of Al₂O₃ formed when 4.1 g of Al completely reacts.
The mass ratio of Al to Al₂O₃ is 53.96:101.96.
4.1 g Al × 101.96 g Al₂O₃/53.96 g Al = 7.7 g Al₂O₃
b) Calculate the mass of Fe formed when 4.1 g Al completely reacts.
The mass ratio of Al to Fe is 53.96:111.70.
4.1 g Al × 111.70 g Fe/53.96 g Al = 8.5 g Fe
c) Calculate the mass of Fe formed when 4.1 g Fe₂O₃ completely reacts.
The mass ratio of Fe₂O₃ to Fe is 159.69:111.70.
4.1 g Fe₂O₃ × 111.70 g Fe/159.69 g Fe₂O₃ = 2.9 g Fe
According to the given balanced equation:
a) 4.1 g of Al form 7.7 g of Al₂O₃.b) 4.1 g of Al form 8.5 g of Fe.c) 4.1 g of Fe₂O₃ form 2.9 g of Fe.Learn more about stoichiometry here: https://brainly.com/question/16060223
How do you write 0.714 in scientific notation
Answer:
0.714 in scientific notation is 7.14 × 10-1.
Answer: m × 10n, where m is a number between 1 and 10 ( 1 ≤ |m| < 10 ) and the exponent n is a positive or negative integer.
Explanation:
1) Move the decimal 1 times to right in the number so that the resulting number, m = 7.14, is greater than or equal to 1 but less than 10
2) Since we moved the decimal to the right the exponent n is negative
n = -1
3) Write in the scientific notation form m × 10n
= 7.14 × 10-1
Therefore,
7.14 × 10-1 is the scientific notation form of 0.714 number and 7.14e-1 is the scientific e-notation form for 0.714
A benzene ring with two substituents, a bromo and chloro substituent. Each substituent is placed on a carbon two carbons away from the other. The parent name is benzene and there is a chloro and bromo substituent. Disubstituted benzenes can be described using the terms ortho, meta and para, depending on their relative distance from each other. The terms are often just abbreviated as o, m and p. In addition, the IUPAC name can use locant numbers instead of the descriptor.
a. 1-bromo-3-chlorobenzene
b. 3-bromo-1-chlorobenzene
c. meta-bromochlorobenzene
d. o-bromochlorobenzene
e. ortho-bromochlorobenzene
f. m-bromochlorobenzene
The correct name of the structure given in the question is 1–bromo–3–chloro benzene (Option A)
How to name organic compoundsThe naming of organic compounds follows the standard of the international union of pure and applied chemistry (IUPAC).
To name a compound, we must
Locate the longest continuous carbon chain and determine the functional group of the compound. This gives the name of the compound. Locate the substituent groups attached Give the substitute group the lowest locate by naming alphabetically Combine the above to obtain the name of the compound. How name the compound The compound is a benzene ringThe substituent groups attached are bromo (Br) and Chloro (Cl) The Br is at carbon 1 while Cl is at carbon 3Therefore, the name of the compound is 1–bromo–3–chloro benzeneComplete question
See attached photo
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True or false is NaOH an example of salt ?
Answer:
Salts of Weak Acids and Strong Bases are slightly basic with a pH of greater than 7 . For Example: NaOH (Sodium Hydroxide) , a strong base , when reacted with a weak acid , H 2 CO 3 (Carbonic acid) , gives a basic salt Na 2 CO 3 (Sodium Carbonate) which has a pH of higher than 7.
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How many ml of ethyl alcohol are presented in 50 ml bottle of an 70%
Answer:
35ml
Explanation:
please give brainliest
calculate the enthalpy change CH3COOH + CH3OH→ CH3COOCH3 + H2O
Answer:
The list is limited to 20 most important contributors or, if less, a number sufficient to account for 90% of the provenance. The listed Reaction acts as a link to the relevant references for the measurement. The Measured Quantity is normaly given in the original units; in cases where we have reinterpreted the original measurement, the listed value may differ from that given by the authors. The quoted uncertainty is the a priori uncertainty used as input when constructing the initial Thermochemical Network, and corresponds either to the value proposed by the original authors or to our estimate; if an additional multiplier is given in parentheses immediately after the prior uncertainty, it corresponds to the factor by which the prior uncertainty needed to be multiplied during the ATcT analysis in order to make that particular measurement consistent with the prevailing knowledge contained in the Thermochemical Network.
Explanation:
Your friend challenged you to a race you know in order to beat him you must run 15 meters within 20 seconds in the northern direction what does your average velocity need to be to win the race
.5 meters per second north
.75meters per second north
1.3meters per second north
300 meters per second north
Answer:
.75 meter north
Explanation:
v = d/t
v = 15/20
v = .75