A person has a mass of 1000g and an acceleration of 20 m/s/s. What is the force on the person

Answers

Answer 1

Answer:

20000

Explanation:

Newtons Second law states that the force acting on an object is equal to its mass times its acceleration, f=ma. To solve for force, plug in your values for m and a, and then solve. f = (1000)*(20) = 20000


Related Questions

It took 50 joules to push a chair 5 meters across the floor. With what force was the chair pushed?

Answers

Answer:

The chair was pushed with 10 N.

Explanation:

The chair was pushed with 50 Joules.  

Work = Force * Distance

50 J = F * 5m  

F = 50 / 5 = 10N  

The chair was pushed with 10 N.

The chair was pushed with 10 N force.

What is Work done?

Work is defined as the measure of energy transfer that occurs when an object is moved over a distance by an external force, at least part of which is applied in the direction of displacement.

If the force is constant then work can be calculated by multiplying the length of the path by the component of the force acting along the path, which is expressed mathematically as work W equal to the force f over a distance d, or W = fd.

So, for above given information,

Work done= 50 joules

Distance covered by the chair = 5m

Then, Force= W/d

=50/5= 10N

Thus, the chair was pushed with 10 N force.

Learn more about Work done, here:

https://brainly.com/question/13662169

#SPJ2

A vector of components (−23, −22) is multiplied by the scalar value of −6. What is the magnitude and direction of the resultant vector?

Answers

Answer:

(1,)

Explanation:

Answer:

magnitude: 21.6; direction: 33.7°

Explanation:

The acceleration of the spacecraft in which the Apollo astronauts took off from the moon was 3.4 m/s2 m / s 2 . On the moon, g g = 1.6 m/s2 m / s 2 . what's the apparent weight

Answers

Complete Question

The acceleration of the spacecraft in which the Apollo astronauts took off from the moon was 3.4 m/s2. On the moon, g = 1.6 m/s2.  What was the apparent weight of a 75 kg astronaut during takeoff?

Answer:

The value is  [tex]N = 375 \ N[/tex]

Explanation:

From the question we are told that

  The acceleration is  [tex]a = 3.4 \ m/s^2[/tex]

   The acceleration due to gravity in the moon is [tex]g = 1.6 m/s^2[/tex]

   The mass of the astronaut is  [tex]m = 75 \ kg[/tex]

   

Generally the apparent weight is mathematically represented as

      [tex]W = ma + mg[/tex]

=>    [tex]W = 3.4 * 75 + 1.6 * 75[/tex]

=>    [tex]W = 375 \ N[/tex]

A studious physics student is interrupted by a swarm of bees and chased off a cliff. Since she has her calculator in hand she quickly punches in numbers to figure out the initial velocity she needs to make it into the lake below. The cliff is 10 m high and the lake is 15 m away from the edge of the cliff. Find the time it takes her to drop. Find her initial velocity,​

Answers

Answer:

The time is 1.4 sec

The initial velocity is 10.7 m/s.

Explanation:

Given that,

Height = 10 m

Distance = 15 m

We need to calculate the time

Using equation of motion

[tex]s=ut-\dfrac{1}{2}gt^2[/tex]

Put the value into the formula

[tex]10=0+\dfrac{1}{2}\times9.8\times t^2[/tex]

[tex]t^2=\dfrac{2\times10}{9.8}[/tex]

[tex]t=\sqrt{\dfrac{2\times10}{9.8}}[/tex]

[tex]t=1.4\ sec[/tex]

We need to calculate the initial velocity

Using formula of velocity

[tex]v=\dfrac{d}{t}[/tex]

Put the value into the formula

[tex]v=\dfrac{15}{1.4}[/tex]

[tex]v=10.7\ m/s[/tex]

Hence, The time is 1.4 sec

The initial velocity is 10.7 m/s.

A car starts from rest and accelerates for 7.2 s with an acceleration of 1.4 m/s2. How far does it travel? Answer in units of m.

Answers

Answer:

xn = 36.28 [m]

Explanation:

To solve this problem we must use the following equation of kinematics, which is ideal for a body that moves with constant acceleration.

[tex]x=x_{0}+(v_{o} *t)+(\frac{1}{2} )*a*t^{2}[/tex]

where:

x - xo = displacement of the car [m]

Vo = initial velocity = 0

t = time = 7.2 [s]

a = acceleration = 1.4 [m/s^2]

The initial velocity is zero, as the car begins its movement from rest.

xn = (x - xo), Now replacing

xn = (0*7.2) + 0.5*1.4*(7.2^2)

xn = 36.28 [m]

If we assume their arms are each 0.90 m long and their individual masses are 65.0 kg , how hard are they pulling on one another

Answers

Complete Question

On an ice rink two skaters of equal mass grab hands and spin in a mutual circle once every 2.7 s .

If we assume their arms are each 0.90 m long and their individual masses are 65.0 kg , how hard are they pulling on one another?

Answer:

The force is  [tex]F  = 316.8 \  N[/tex]

Explanation:

From the question we are told that

    The period is  T   =  2.7 s

    The radius of the circle formed by their arms  is  r =  0.90 m

      Their individual  mass is  [tex]m =  65.0 \  kg[/tex]

Generally their angular velocity is mathematically represented as

      [tex]w = \frac{2 \pi}{T}[/tex]

=>    [tex]w = \frac{2 *  3.142 }{2.7}[/tex]

=>  [tex]w =2.327 \ rad/ s [/tex]

Generally the pulling force is mathematically represented as

      [tex]F  = m *  w ^2 *  r[/tex]

=>   [tex]F  = 65 *  2.327^2 *  0.90[/tex]

=>   [tex]F  = 316.8 \  N[/tex]

a Venus fly trap is an......... plant.​

Answers

Answer:

A Venus flytrap is a perennial carnivorous plant.

I hope it helps

plant that eats meat

A tightly wound solenoid is 15 cm long, has 350 turns, and carries a current of 4.0 A. If you ignore end effects, you will find that the value of app at the center of the solenoid when there is no core is approximately

Answers

Answer:

The magnetic field at the center of the solenoid is approximately  0.0117 T

Explanation:

Given;

length of the solenoid, L = 15 cm = 0.15 m

number of turns of the solenoid, N = 350 turns

current in the solenoid, I = 4.0 A

The magnetic field at the center of the solenoid is given by;

[tex]B = \mu_o (\frac{N}{L} )I\\\\B = (4 \pi *10^{-7})(\frac{350}{0.15} )(4.0)\\\\B = 0.0117 \ T[/tex]

Therefore, the magnetic field at the center of the solenoid is approximately  0.0117 T.

distance is constant and time increseas

Will Speed increase or decrease?

Answers

Answer:

The speed will be decrease

The speed will decrease

The bandgap of InP semiconductor laser is 1.0 eV. The effective mass of the valence band is ½ of the effective mass of the conduction band. Assuming that electron hole recombination transition occurs at 0.03 eV above the bandgap, calculate the wavelength of this transition.

Answers

Answer: the wavelength of this transition is 1.2039 um

Explanation:

Given that;

the energy level between the transitioning energy gap Eg = 1.0 + 0.03 = 1.03 eV

we know that λ = 1.24 / Eg

so we substitute our Eg into the above equation

λ = 1.24 / 1.03

λ = 1.2039 um

therefore the wavelength of this transition is 1.2039 um  

Notice that the electromagnet in the virtual simulation is made up of a battery and a wire. What item could you add to the electromagnet to make it even stronger?

Answers

Answer:

Explanation:

Have y’all seen steeleflag19 at all on here?

What measurements would you make (assuming you have the money, time, & equipment) to determine a star’s surface temperature? Explain your answer.

Answers

Answer:

use special filters on the telescope

Explanation:

Assuming you have access to a very high-grade telescope you would need to use special filters on the telescope that allows you to view the star's color spectrum. The color spectrum represents different levels of heat that a star is generating. This spectrum ranges from red to blue. Therefore in order to calculate the surface temperature, you would need to apply both a blue and red filter onto the telescope. Once you have these measurements you would need to compare them in order to pinpoint the correct variation of color which would give a close enough estimate of the surface temperature of the star.

2. If a car is accelerating under a net force of 3674 N, what force must the
brakes exert to cause the car to have constant velocity?*

Answers

Answer:

I don't do physics but I think the answer would be -3674

Explanation:

Newton's 2 law of motion

True.or false A railroad track runs southwest to northeast.

Answers

Answer:

ns for high-speed rail in the United States date back to the High Speed Ground Transportation Act of 1965. Various state and federal proposals have followed. Despite being one of the world's first countries to get high-speed trains (the Metroliner service in 1969), it failed to spread. Definitions of what constitutes high-speed rail vary, including a range of speeds over 110 mph (180 km/h) and dedicated rail lines. Inter-city railwith top speeds between 90 and 125 mph (140 and 200 km/h) is sometimes referred to in the United States as higher-speed rail.[1]

Amtrak's Acela Express (reaching 150 mph, 240 km/h), Silver Star, Northeast Regional, Keystone Service, Vermonter and certain MARC Penn Line express trains (all five reaching 125 mph, 201 km/h) are the only high-speed services in the country.

As of 2020, the California High-Speed Rail Authority is working on the California High-Speed Rail project and construction is under way on sections traversing the Central Valley. The Central Valley section is planned to open in 2029 and Phase I is planned for completion in 2031.[2]

Contents

1 Definitions in American context

2 History

2.1 Faster inter-city trains: 1920–1941

2.2 Post-war period: 1945–1960

2.3 First attempts: 1960–1992

2.4 Renewed interest: 1993–2008

2.5 Plans for 2008–2013

3 Current state and regional efforts

3.1 The Northeast

3.1.1 Northeast Corridor: Next Generation High-Speed Rail

3.1.1.1 Proposed routes

3.1.2 Northeast Maglev proposal

3.1.3 New Jersey–New York City upgrades

3.1.4 New York

3.1.5 Pennsylvania

3.2 Western States

3.2.1 California

3.2.2 Pacific Northwest

3.2.3 Arizona

3.3 Mid-Atlantic and the South

3.3.1 Florida

3.3.2 Southeast

3.3.3 Texas

3.4 Midwest

3.4.1 Illinois and the Midwest

3.5 The Southwest

4 Federal high-speed rail initiatives

4.1 American Recovery and Reinvestment Act of 2009

4.1.1 Strategic plan

4.2 2009 federal grant funding

4.3 2010 allocation

4.3.1 Cancellation of funds for Wisconsin, Ohio, and Florida

4.4 2011 and 2012 proposals and rejections of funding

5 See also

6 Notes

7 Further reading

8 External links

Explanation:

How could you separate a mixture of rocks and sand?

Answers

Pour the gravel and sand mixture on top of the screen. Shake the screen to filter the smaller particles. Use your hands to spread the gravel around over the top of the screen. The smaller particles will fall through, leaving the bigger rocks on top.

Hope this helps!

R=(4.7)^2+(6.6)^2-2.(4.7)+(6.6).(180-45)

Answers

Answer:

I have no clue what this means or what the answer is i am just trying to get my points up so i can ask questions

Explanation:

i am going to put something here so it looks like an explanation so yeah this has no meaning whatsoever i am very sorry that i am not able to give you the answer try looking the answer up im very very very very sorry :(

Problem 9.23 A uniform-density 8 kg disk of radius 0.21 m is mounted on a nearly frictionless axle. Initially it is not spinning. A string is wrapped tightly around the disk, and you pull on the string with a constant force of 36 N through a distance of 0.9 m. Now what is the angular speed?

Answers

Answer:

4.63rad/s

Explanation:

The centripetal force is expressed as;

F = mv²/r

M is the mass of the disk = 8kg

v is the linear speed = wr

r is the radius = 0.21m

Force = 36N

Write the force in term of the angular velocity

F = m(wr)²/r

F = mw²r²/r

F = mw²r

36 = 8w²(0.21)

36 = 1.68w²

w² = 36/1.68

w² = 21.43

w = √21.43

w = 4.63rad/s

Hence the angular speed is now 4.63rad/s

1. The uniform seesaw is balanced at its center of mass. The smaller boy on the right has a mass of m = 40.0 kg. What is the mass of his friend?

Answers

Answer:

Explanation:

Find the complete question attached

Using the principle of moment

Clockwise moment = Anticlockwise moment

AntiClockwise moment = M × 2.0

ACW moment = 2M

Clockwise moment = 40×4

Clockwise moment = 160kgcm

Equate both expression and calculate M

2M = 160

M = 160/2

M = 80kg

Hence the mass of his friend is 80kg

Determine the mass m1m1 of block M1M1 for which the two blocks are in equilibrium (no acceleration).

Answers

This question is incomplete, the complete question is;

Two blocks, M1M1 and M2,M2, are connected by a massless string that passes over a massless pulley as shown in the figure. M2,M2, which has a mass of 25.0 kg,25.0 kg, rests on a long ramp of angle =25.0∘.θ=25.0∘. Friction can be ignored in this problem.

Determine the mass 1m1 of block M1M1 for which the two blocks are in equilibrium (no acceleration).

Answer:

the mass m1m1 of block M1M1 for which the two blocks are in equilibrium (no acceleration) is 10.57 kg

Explanation:

Given that;

m₂ = 25 kg

θ = 25°

Now at equilibrium, T = m₁g ------------------lets say equ 1

and also T = m₂gsinθ

therefore

m₁g = m₂gsinθ

m₁ = m₂sinθ

so we substitute

m₁ = 25 × sin(25)

m₁ = 25 × 0.4226

m₁ = 10.565 ≈ 10.57 kg

therefore the mass m1m1 of block M1M1 for which the two blocks are in equilibrium (no acceleration) is 10.57 kg

At a certain instant, a proton is moving in the positive x direction through a magnetic field in the negative z direction. What is the direction of the magnetic force exerted on the proton

Answers

Answer: positive y direction

Explanation:

we know that direction of velocity is in +x direction

now the magnetic force is in negative z direction

therefore the magnetic force , F = q × ( v × B)

F = ( i × [ - k ] ) direction

F = j direction

so the direction of the magnetic force on the proton is positive y direction.

A "lovesick" individual wants to throw a bag of candy and love notes into the open window of their significant other’s bedroom 10.0 m above. Assuming it just reaches the window, they throw the gift at 60.0o to the ground: At what velocity should they throw the bag? How far from the house are they standing when they throw the bag? (Answer: A. 16.2m/s B. 11.5m)

Answers

Answer:

Explanation:

Let the velocity be v .

vertical component of the velocity = v sin 60 = √3 v /2

it reaches maximum height of 10 m .

v² = 2 gh

( √3 v/2 )² = 2 x 9.8 x 10

3 v² = 196 x 4

v² = 65.33 x 4

v = 16.2  m /s

Let time taken to reach height of 10 m

v = u - gt

v sin 60 = 9.8 t

16.2 x √3  /2 = 9.8 t

t = 1.43 s

horizontal distance covered = v cos 60 x t

16.2 x .5 x 1.43 = 11 .5 m

A balloon is launched straight upward from the edge of a 40 m high cliff with a velocity of 30
m/s. The balloon goes up and barely misses the edge of the cliff on the way down and hits the
ground below.
A.) Determine the overall hang time of the balloon.
B.) How high did the balloon travel above the cliff?
C.) Determine the velocity of the balloon at t = 3 s.
D.) Determine the acceleration of the balloon at t = 3 s.

Answers

Answer:

A)  t = 7.25 sec

B) 45.92 m above the cliff and 85.92 m counting from ground level

C) about 0.6 m/s

D) The only acceleration is always that of gravity : 9.8 m/s^2

Explanation:

The kinematic equation for the position as a function of time is:

y = 40 + 30 * t - (g/2) t^2

The total time the balloon was in the air is calculated for when the final position is y = 0 (when it touches the ground), that is:

0 = 40 + 30 * t - (g/2) t^2

0 = 40 +30 t - 4.9 t^2

which can be solved for "t" using the quadratic formula, and which renders two different times "t", of which we pick the positive answer: t = 7.25 sec.

For the maximum height, we estimate the time it takes for the balloon to reach the maximum height at which the velocity is zero (changes direction of motion):

vf = vi - g * t

0 = 30 - 9.8 * t

t = 30 / 9.8 = 3.06 seconds

Now we use this value in our position equation and get:

ymax =  40 + 30 (3.06) - 4.9 (3.06)^2

ymax = 85.92 m  (from ground level

Therefore, from the cliff (that is at 40 m height) the height is 85.92 - 40 = 45.92 m.

The velocity of the balloon at t = 3 seconds can be calculated with the velocity expression we have been using:

v(t) = vi - g * t

v(3) = 30 - 9.8 (3) = 0.6  m/s

The only acceleration acting on the balloon is always the acceleration due to gravity (g = 9.8 m/s^2)

A person following a liberal ideology would likely approve of

Answers

i’m
not sure sorry :5

please help asap
You jog for 55 minutes and reach a park that is 4.8 km away. What was your speed?​

Answers

Answer: 59.8 or 299/5​- 55 x 4.8=264

Explanation:

Or if you wish to multiply it then the answer is above with the addition version.

Hope this helped :)

How long would it take you to walk 3,962 km from New York to Los
Angeles?

Answers

Answer:

913 hours ur welcome :)

Write a function to accept a vector of masses (m) from the user and gives the corresponding energy to them. Energy vector is the output of the program. Constant c is the speed of light which is 2.9979 x 108 m/s inside the function.

Answers

Answer:

Written in Python

def energyvector(mass):

    c = 2.9979 * 10**8

    energy = mass * c ** 2

    print(round(energy,2))

Explanation:

This line defines the function

def energyvector(mass):

This line initializes the speed of light

    c = 2.9979 * 10**8

This line calculates the corresponding energy

    energy = mass * c ** 2

This line prints the calculated energy

    print(round(energy,2))

what is the summary for Electrons and protons​

Answers

Explanation:

the link enjoy

A particle is moved along the x-axis by a force that measures 10/(1+x)^2 pounds at a point x feet from the origin. Find the work (in ft-lb) done in moving the particle from the origin to a distance of 9 feet.

Answers

Answer:

9 ft*lb

Explanation:

super simple but you just have to understand that the integral is going with the curve

work = integral a to b of f(x)dx = integral 0 to 9 of 10/(1+x)^2dx = 9ft*lb

Define reflection of sound?​

Answers

The reflection of sound is the movement of sound waves bouncing off of a surface and back into another direction, hope this helped :)

What is the maximum current flow possible through a 12 Ohm resistor from a 120V source?

Answers

Answer:

I=10.0A

Explanation:

V=RI(120)=(12)II=10.0A
Other Questions
The volume of a gas V held at a constant temperature in a closed container varies inversely with its pressure P. If the volume of a gas is 600 cubic centimeters (cc) when the pressure is 300 millimeters of mercury (mm hg) , find the volume when the pressure is 400 mm hg What is the value of name and tell the value of the underline digit. The number is 25,678 the underline digit is 5. Write a poem about life,If you copy from a website I will delete your answer. What is the decomposition of 2LiCIO3 What operation is happening in an additive pattern?? Multiplication Subtraction AdditionDivision Which situation can be modeled by the inequality, 10x + 75 > 6.50x + 120 ? A Membership at Gym A costs $120 down plus $6.50 per month. Gym B charges $10 down plus $75.00 per month. After how many months will Gym A cost less in total than Gym B? B Membership at Gym A costs $120 down plus $6.50 per month. Gym B charges $10 down plus $75 per month. After how many months will Gym B cost less in total than Gym A? C Stephanie has $75.00. Her brother Ricardo has $120. Stephanie saves $10.00 per week. Her brother saves $6.50 per week. After how many weeks will Stephanie have more money than Ricardo? D Stephanie has $75.00. Her brother Ricardo has $120. Stephanie saves $10.00 per week. Her brother saves $6.50 per week. After how many weeks will Stephanie have less money than Ricardo? What relationships are important to justyce , 6,6 1,2. What is the difference between Primary and Secondary Succession? 1. A pile of boxes exerts a force of 500 newtons downward on the floor. The boxes are not in motion. What is the normal force on these boxes?2. Norman drags a stubborn dog by his leash with a force of 200 newtons. The dog is slowly moving towards Norman. What do you know about the force exerted by the dog?3. A baby grand piano sits in a music room. The piano exerts a force of 3500 newtons downward. Isaac tells his friends that he is strong enough to lift the piano off the floor. How much force will he have to use to lift the piano?4. Ms. Holt is dragging a box of assessments across the floor using a force of 70 newtons. The frictional force acting against the box is 50 newtons. What is the net force on the box?5. A bicycle is sitting motionless in the driveway. What is the net force acting on this bike?6. Maria drops a box that exerts of force of 300 newtons downward on a table. The normal force acting on the box from the table is 250 newtons. What will happen to the table and the box? What is the net force of the box?7. Anna is riding her bike, moving at a constant velocity of 3 miles per hour to the south. She is using 200 N of force to pedal her bike. A gust of wind blowing in the same direction she is traveling suddenly exerts a force of 20 Newtons on her. What will happen to her motion? (hint: Use the term accelerate OR decelerate in your answer.)8. Mrs. Fedde is riding her bike, moving at a constant velocity of 5 miles per hour to the north. She is using 300 N of force to pedal her bike. A gust of wind blowing in the opposite direction she is traveling suddenly exerts a force of 50 Newtons on her. What will happen to her motion? (hint: Use the term accelerate OR decelerate in your answer.) If a histogram of a sample of men's ages is skewed, what do you expect to see in the normal quantile plot? Whats the answer to this question During 2020, PC Software Inc. developed a new personal computer database management software package. Total expenditures on the project were $3,000,000, of which 40% occurred after the technological feasibility of the product had been established. The product was completed and offered for sale on January 1, 2021. During 2021, revenues from sales of the product totaled $4,800,000. The package is expected to be successfully marketable for five years, and the total revenues over the life of the product are estimated to be $20,000,000. RequiredA. Prepare the journal entry to account for the development of this product in 2020.B. Prepare the journal entry to record the amortization of capitalized computer software development costs in 2021.C. What disclosures are required in the December 31, 2021, financial statements regarding computer software costs?At December 31, 2021, the unamortized software intangible asset totals ______. This is equal to _____ originally capitalized less amortization in 2021 of _______. The amount charged to expense as amortization of software intangible asset in 2021 was ______. The estimated net realizable value of computer software is greater than the remaining unamortized software intangible asset. A bus makes a stop at 2:30, letting off 11 people and letting on 8. The bus makes another stop ten minutes later to let off 5 more people. How does the number of people on the bus after the second stop compare to the numbers of the people on the bus before the 2:30 stop ? In a fluorine atom, on which energy level are the valence electrons found? YO SOMEONE HELP ME 1. Obtain your maximum heart rate (MHR) 220 by subtracting your age from 220. 2. At what percent of maximum heart rate do you wish to train? The lower limit is 60% for training effect, and the safe upper limit is 90%. 3. Multiply Step 2 times the value of Step 1. HRR X 50% and HRR x 85%4. A is results lower limit of target heart rate zone for training effect, and B is the safe upper limit. A model of a rectangular patio and is a landscaping business will be enlarged by a scale factor of 2 when is installed in the customers backyard. The area of the new and larger I know they want to see square feet which is the area of the landscapers model Help me solve this problem please A girls club held a fundraiser last year and raised $600 for the local soup kitchen. This year they raised $960. What is the percent change in the total amount raised by the girls club?The percent change is 0.38%.The percent change is 0.6%.The percent change is 38%.The percent change is 60%. (1,9)Write the interval as an inequality.