A plastic ball in a liquid is acted upon by its weight and by a buoyant force. The weight of the ball is 4 N. The buoyant force has a magnitude of 5 N and acts vertically upward. When the ball is released from rest, what is it's acceleration and direction? [2 pts] for a Free Body Diagram correctly labeled.​

Answer:

MgS

Explanation:

Answer:

in my opinion i would say that at home cares of more effective because half of the time your child is safe and sound but in child care programs sometimes you have no idea what is going on when you are not around

Explanation:

work=force×distance this is the formula

since the car moves, the force needed to move is greater than the frictional forces opposing it

a = 3.17m/s²

The acceleration of the car with a mass of 1300 kg which starts from rest generating a force of 4400 N and having a frictional force of 280 N is 3.17 m/s²

Force (F) = 4400 N

Frictional force (Fբ) = 280 N

Fₙ = F – Fբ

Fₙ = 4400 – 280

Thus, the net force acting on the car is 4120 N

Mass (m) = 1300 Kg

Net force (F) = 4120 N

Force = Mass × Acceleration

4120 = 1300 × a

Divide both side by 1300

[tex]a = \frac{4120}{1300}\\\\[/tex]

Therefore, the acceleration of the car is 3.17 m/s².

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Answer:

planet that is farthest away is planet X

kepler's third law

Explanation:

For this exercise we can use Kepler's third law which is an application of Newton's second law to the case of the orbits of the planets

          T² = ([tex]\frac{4\pi ^2}{ G M_s}[/tex] a³ = K_s a³

Let's apply this equation to our case

          a = [tex]\sqrt[3]{ \frac{T^2}{K_s} }[/tex]

for this particular exercise it is not necessary to reduce the period to seconds

Plant W

             10² = K_s  [tex]a_{w}^3[/tex]

             a_w = [tex]\sqrt[3]{ \frac{100}{ K_s} }[/tex]

             a_w = [tex]\frac{1}{ \sqrt[3]{K_s} }[/tex]  4.64

Planet X

             a_x = [tex]\sqrt[3]{ \frac{640^3}{K_s} }[/tex]

             a_x = \frac{1}{ \sqrt[3]{K_s} } 74.3

Planet Y

              a_y = [tex]\sqrt[3]{ \frac{80^2}{K_s} }[/tex]

              a_y = \frac{1}{ \sqrt[3]{K_s} } 18.6

Planet z

              a_z = [tex]\sqrt[3]{ \frac{270^2}{K_s} }[/tex]

              a_z = \frac{1}{ \sqrt[3]{K_s} } 41.8

From the previous results we see that planet that is farthest away is planet X

where we have used kepler's third law

Answer:

Gravitational potential energy is the greatest

Explanation

It is the highest point of a roller coaster.

Answer:

Chemical.

Explanation:

Weathering can be defined as the physical and chemical breakdown of rock into smaller pieces called sediment. Weathering can be classified into two categories namely;

I. Physical weathering : it is the process of breaking rocks into pieces without affecting its chemical composition e.g temperature, abrasion and frost action.

II. Chemical weathering : it is the process of breaking rocks into pieces by chemical action which leads to changes in its chemical composition e.g carbonation, hydration, plant acid and oxidation.

In this scenario, Lichen grows on the surface of hornblende granite and causes it to breakdown at a faster rate. Thus, this is an example of chemical weathering

Answer:

465 grams of sugar.

Explanation:

I'm not sure this is true: is the relationship linear?

If it is then 300 grams of water should be able told 3*155 grams of sugar

3 * 155 = 465  grams of sugar in 300 grams of water.

Answer:

The value 0.51

Explanation:

Answer:

B. holding a coffee mug

Explanation:

Something must move a distance for work to be done.

Answer:

There isnt enough in your question to answer the question bro, like we need a picture or something bro.

Explanation:

You don't have a image attached

This question is incomplete, the complete question is;

Time Dilation. A group of scientists discover a new, rare isotope and are able to store a small amount of it. They determine that the isotope is unstable and half of their sample will decay in 13.0 months . The scientists need a new laboratory to properly conduct measurements on the isotope. If laboratory is built before half the sample decays there will still be enough of the isotope available for experiments. However, it will take 21.0 months to build the new lab. Fortunately, the scientists can quickly start construction and they have access to a spaceship that can travel at speeds approaching the speed of light c = 3.00 x 10⁸ m/s.

If they place their sample of the isotope on the spaceship, at what speed must it travel in order for the new laboratory to be completed on Earth by the time half of the isotope on the spaceship decays? Assume that it took one month for the scientists to actually start construction and launch the spaceship so half the sample will remain in 12.0 months but it will still take 21.0 months to build the new lab.

Answer:

the required speed is 2.4618 x 10⁸ m/s

Explanation:

Given the data in the question;

Time taken to complete a lab = 21 months  

it took them one one to actually start so

Time remaining so that sample only decays by 1/2 = (13 - 1) = 12 months

we need to find at what speed the spaceship should travel so that time on earth ( = 12 months) become time on spaceship ( = 21 months)

we make use of time dilation equation;

t' = t/√( 1 - v²/c² )

where t is time in rest frame = 12 and t' is time in moving frame = 21

so we substitute

21 = 12/√( 1 - v²/c² )

21√( 1 - v²/c² ) = 12

√( 1 - v²/c² ) = 12/21

we square both side

( 1 - v²/c² ) = ( 12/21 )²

( 1 - v²/c² ) = 0.3265

v²/c² = 1 - 0.3265

v²/c² = 0.6735

v² = 0.6735 × c²

v = √0.6735 × √c²

v = 0.8206 × c

given that speed of light c = 3 x 10⁸ m/s

v = 0.8206 × 3 x 10⁸ m/s

v = 2.4618 x 10⁸ m/s

Therefore, the required speed is 2.4618 x 10⁸ m/s

Answer:

The paper focuses on the biology of stress and resilience and their biomarkers in humans from the system science perspective. A stressor pushes the physiological system away from its baseline state toward a lower utility state. The physiological system may return toward the original state in one attractor basin but may be shifted to a state in another, lower utility attractor basin. While some physiological changes induced by stressors may benefit health, there is often a chronic wear and tear cost due to implementing changes to enable the return of the system to its baseline state and maintain itself in the high utility baseline attractor basin following repeated perturbations. This cost, also called allostatic load, is the utility reduction associated with both a change in state and with alterations in the attractor basin that affect system responses following future perturbations. This added cost can increase the time course of the return to baseline or the likelihood of moving into a different attractor basin following a perturbation. Opposite to this is the system's resilience which influences its ability to return to the high utility attractor basin following a perturbation by increasing the likelihood and/or speed of returning to the baseline state following a stressor. This review paper is a qualitative systematic review; it covers areas most relevant for moving the stress and resilience field forward from a more quantitative and neuroscientific perspective.

Explanation:

During a normal reaction to a stressful event, muscles are moved to their maximum capacity, and sensitivity is increased.

This is defined as the ability of an organism to respond to stimuli such as touch, sensation etc.

During exercise, sensitivity to substances such as insulin when glucose transport wears off helps to balance energy supply.

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Answer:

[tex]a=0.13m/s^2[/tex]

Explanation:

From the question we are told that

Mass of first team man [tex]m_1=64kg[/tex]

Force of man first team man [tex]F_1=1350[/tex]

Mass of second team man [tex]m_2=69kg[/tex]

Force of man second team man [tex]F_2=1367N[/tex]

Generally the equation for net force F_n is mathematically given by

[tex]F_n=9(m_1+m_2)a[/tex]

[tex]9(m_1+m_2)a=9(f_2-f_1)[/tex]

[tex]9(64+69)a=9(1367-1350)[/tex]

[tex]a=\frac{9(1367-1350)}{9(64+69)}[/tex]

[tex]a=0.127819m/s^2[/tex]

Therefore the acceleration is given by

[tex]a=0.13m/s^2[/tex]

Answer:

I think it might be (e

Explanation:

OWA OWA

(a) The original charge on the 40-pF capacitor is [tex]2 .0 \ \times \ 10^{-8} \ C[/tex].

(b) The charge on each capacitor after the connection is made is [tex]4 .0 \ \times \ 10^{-9} \ C[/tex].

(c)  The potential difference across the plates of each capacitor after the connection is 100 V and 400 V.

The original charge on the 40-pF capacitor is calculated as follows;

[tex]Q = CV\\\\Q = 40 \times 10^{-12} \times 500\\\\Q = 2 .0 \ \times \ 10^{-8} \ C[/tex]

[tex]C = \frac{C_1C_2}{C_1 + C_2} \\\\C = \frac{10 \times 10^{-12} \times 40 \times 10^{-12}}{10\times 10^{-12} \ + \ 40 \times 10^{-12}} \\\\C = 8 \times 10^{-12} \ F[/tex]

[tex]Q = Q_1 = Q_2\\\\Q = 8 \times 10^{-12} \ \times \ 500\\\\Q = 4 \times 10^{-9} \ C[/tex]

The potential difference across the plates of each capacitor after the connection is calculated as follows;

[tex]V = \frac{Q}{C} \\\\V_1 = \frac{Q}{C_1} \\\\V_1 = \frac{4 \times 10^{-9}}{40 \times 10^{-12}} \\\\V_1 = 100 \ V\\\\V_2 = \frac{Q}{C_2} \\\\V_2 = \frac{4 \times 10^{-9}}{10 \times 10^{-12} } \\\\V_2 = 400 \ V[/tex]

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Answer: Ok so We already know that velocity is on the x-axis.

Since acceleration = Force / Mass

Here the Force is downward due to the gravitational pull or we can say it is along y-axis.

Since acceleration is directly proportional to force, so acceleration is also along y-axis. This means that velocity & acceleration are perpendicular to each other.

Example:

Let us assume that an aeroplane is flying parallel to the horizontal plane. The aeroplane will experience the acceleration in several directions. One of them here is the gravitational pull which is perpendicular to the the apparent velocity. So the net velocity & its direction will depend upon the vector sum total of all the forces/acceleration acting on it. Also because of this gravitational pull the aeroplane rotates along with the earth, which is a proof that the force/g experienced by it does not go waste.

Explanation:

Answer:

105 kg*m/s

Explanation:

p=mv

momentum=mass*velocity

momentum=15kg*7m/s

momentum=105kg*m/s

Answer:

C

Explanation:

sin of a right triangle is opposite divided by hypotenuse

in this case, that is 5/8.6 = 0.581395349

you can easily remember the trig functions with this acronym:

SOH-CAH-TOA

S: Sine

O: Opposite

H: Hypotenuse

C: Cosine

A: Adjacent

H: Hypotenuse

T: Tangent

O: Opposite

A: Adjacent

Explanation:

sin = Mp /0P

sin = 5/8,6

sin = 0,58

Answer:

67 kg.

Explanation:

From the question,

Total momentum = (mass of the pilot+ mass of the helicopter)×velocity.

I = (m+M)v............................... Equation 1

Where I = Total momentum of the pilot and the helicopter, m = mass of the pilot, M = mass of the helicopter, v = velocity.

make m the subject of the equation

m = (I/v)-M.............................. Equation 2

Given: I = 7200 kg.m/s, v = 60 m/s, M = 53 kg.

Substitute these values into equation 2

m = (7200/60)-53

m = 120-53

m = 67 kg.

Hence the mass of the pilot is 67 kg

Answer:

why does anyone need to know

Explanation:

1 plus one = 69

Answer:

The Current decreases

Explanation:

HOPE THIS HELPS!

Answer:

9 electrons

Explanation:

The structure has 9 protons and hence the number of electrons equals the number of protons that's why it is said to be electrical neutral

Answer:

P=126W

Explanation:

Sorry if im wrong!

Answer:

125.5 watts

Explanation:

P=work/time

work=F*d

P=(F*d)/t

P=(15*251)/30

P=125.5 watts