A polynomial function has zeros at 5/2 (multiplicity 2), 3 (multiplicity 1), and 0 (multiplicity 4). Write a function in standard form that could represent this function

the answer is 3p

hope it helps!

Answer: 3p

Step-by-step explanation:

5 − 3 + =

3

Answer:

( x + 8 ) ^2+ y^2= 36

Step-by-step explanation:

Answer:

4(3) - 7 = 4(3 - 1) - 3

12 - 7 = 4(2) - 3

5 = 8 - 3

= 5

They are equivalent because when they are both simplified they have the same answer 5

Answer: 3y + 5 cm

Step-by-step explanation: The perimeter of a triangle

is just the distance around the outside of the figure.

So just add up all the sides.

So we have y + y + y + 5 and we get 3y + 5.

Answer: $200

Step-by-step explanation:

On the X axis, it shows the kilograms. Since the problem asks for how much money she makes for 60 kg, go to the point on the X axis that represents 60 kg and then go up to the corresponding y or dollar value, which is 200.

Answer:

2000 minutes on 16 miles

Answer:

168.75 minutes

Step-by-step explanation:

Francine's speed (the unit rate) is (16 miles) / (45 minutes), or 16/45 miles/min.

Recalling that distance = speed times time, we recognize that

time = distance / speed

which here is  

(60 miles) / (16/45) miles/min = 168.75 minutes, or 168 min 45 sec

Answer:soultion

Step-by-step explanation:      solution

Answer:

x = 29

angles are 90 degrees, 56 degrees, and 34 degrees

Step-by-step explanation:

90 + (2X-2) + (X+5) = 180

3X + 93 = 180

3X = 87

X = 29

Answer:

a) 0.1151 = 11.51% probability that an individual distance is greater than 210.00 cm.

b) 0.883 = 88.3% probability that the mean for 20 randomly selected distances is greater than 197.80 cm.

c) The distribution of the population is normal, which means that the sample size does not need to exceed 30.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The overhead reach distances of adult females are normally distributed with a mean of 200 cm and a standard deviation of 8.3 cm.

This means that [tex]\mu = 200, \sigma = 8.3[/tex]

a. Find the probability that an individual distance is greater than 210.00 cm.

This is 1 subtracted by the pvalue of Z when X = 210. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{210 - 200}{8.3}[/tex]

[tex]Z = 1.2[/tex]

[tex]Z = 1.2[/tex] has a pvalue of 0.8849

1 - 0.8849 = 0.1151

0.1151 = 11.51% probability that an individual distance is greater than 210.00 cm.

b. Find the probability that the mean for 20 randomly selected distances is greater than 197.80 cm

Now [tex]n = 20, s = \frac{8.3}{\sqrt{20}} = 1.8559[/tex]

This probability is 1 subtracted by the pvalue of Z when X = 197.8. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{197.8 - 200}{1.8559}[/tex]

[tex]Z = -1.19[/tex]

[tex]Z = -1.19[/tex] has a pvalue of 0.117

1 - 0.117 = 0.883

0.883 = 88.3% probability that the mean for 20 randomly selected distances is greater than 197.80 cm.

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The distribution of the population is normal, which means that the sample size does not need to exceed 30.

Answer:

First: 105

Second: 65

Third: 133

Fourth: 129

Fifth: 60

Answer:20 dollars.

not sure

Step-by-step explanation:

Answer:

if t=60, then 6(60)/9-23. (360-198)/9

=18

Answer:

5 inches

Step-by-step explanation:

Hope I helped

Step-by-step explanation:

K=12 if you want explanation i will

Answer:

Josh won all the prizes for the contest

Step-by-step explanation:

Answer:

0.20

Step-by-step explanation:

Answer:

18n+9

Step-by-step explanation:

9(2n+1)

18n+9

Answer:

thanks have a nice day can you please mark me brainliest im trying to rank up and i  need 2 more brainlys

Step-by-step explanation:

Answer:

120 and 40

Step-by-step explanation:

Because when we subtract 80 and 40 is equal 40 or 160 and 40 is 120.

This it the test please do as fast as posible and show work. thank you and sorry

Answer:

-6

Step-by-step explanation:

The equation is y = -7x - 6.

The initial value is found when x = 0.

y = -7(0) - 6

y = 0 - 6

y = -6

Answer:

6

Step-by-step explanation:

14/2 - 3 + 6/3

Divide 14 by 2 to get 7.

7−3+6/3

Subtract 3 from 7 to get 4.

4+6/3

Divide 6 by 3 to get 2.

4+2

Add 4 and 2 to get 6.

6

Answer:

x=1 and y=10 (1,10)

Step-by-step explanation:

2+30=32

10=1+9

Answer:

r < 4

Step-by-step explanation:

r+6<10

r < 4