A projectile is shot at an angle of 45 degrees with velocity components Vx and Vy both equal to 5 m/s. What is the magnitude of the initial velocity? Round to nearest tenth.

Answers

Answer 1

Answer:

7.1 m/s

Explanation:

Explanation is attached

A Projectile Is Shot At An Angle Of 45 Degrees With Velocity Components Vx And Vy Both Equal To 5 M/s.

Related Questions

Numerical

What mass must be suspended from a steel wire 2m long and 1mm diameter to stretch it by 1mm
By young’s theory

Answers

Answer:

Thus, 4 kg mass must be suspended from a steel wire 2 m long and 1 mm diameter to stretch it by 1 mm.

Explanation:

Each box weighs 10lb. The coefficient of static friction between box A and box B is 0.24, and the coefficient of static friction between box B and the inclined surface is 0.3. What is the largest angle for which box B will not slip​

Answers

The largest angle for which box B will not slip​ is 16.7⁰.

The given parameters:

weight of box, W = 10 lbcoefficient of static friction between box A and box B, [tex]\mu_s_1[/tex] = 0.24coefficient of static friction between box B and the inclined surface, [tex]\mu_s_2[/tex] = 0.3

The frictional force between box A and box B is calculated as;

[tex]F_f_1= \mu_s_1 (mg)[/tex]

The frictional force between box B and inclined surface is calculated as;

[tex]F_f = \mu_s_2 (2mg) cos(\theta)[/tex]

The net force on the boxes that results in no movement is calculated as;

[tex](2mg) sin(\theta) - F_f= 0\\\\(2mg) sin(\theta) = F_f\\\\(2mg) sin(\theta) = \ \mu_s_2 (2mg) cos(\theta)\\\\ sin(\theta) = \mu_s_2 cos(\theta)\\\\\mu_s_2 = \frac{sin(\theta)}{cos(\theta)} \\\\\mu_s_2 = tan(\theta)\\\\\theta = tan^{-1} (\mu_s_2)\\\\\theta = tan^{-1} (0.3)\\\\\theta = 16.7 \ ^ 0[/tex]

Thus, the largest angle for which box B will not slip​ is 16.7⁰.

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What are the two factors that affect the gravitational pull between two objects?

Answers

Answer:

hen dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance.

Explanation:

A length of organ pipe is closed at one end. If the speed of sound is 344 m/s, what length of pipe is needed to obtain a fundamental frequency of 63 hz?.

Answers

Answer:

Node-Antinode       for a pipe closed at one end (fundamental)

The length of such a pipe would be wavelength / 4

lambda (wavelength) = speed / frequency = 344 m/s / 63 / sec = 5.46 m

The pipe would have to be 5.46 / 4 = 1.36 m

What happens if you drop a chicken wing from the top of the Eiffel Tower

Answers

Answer:

I think it will brake or squashed

Around the time that _______ burning finishes, the inert core of ________ in very massive stars will collapse and the star will explode as a supernova.

Answers

The Sun can explode in a supernova. Around the time that sun (massive star) burning finishes, the inert core of Iron in very massive stars will collapse and the star will explode as a supernova.

When the sun explode, their inert iron cores often collapse into an extremely dense neutron star.

In a massive star, hydrogen fusion in the core is accompanied by other different fusion reactions involving heavier elements.

When the core of a massive star dies during a supernova, The supergiant will explodes as a supernova.

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Why can't we observe the image of a distant object in a concave mirror, but we can observe in a convex mirror? Both images are diminished.​

Answers

Answer:

Light

Explanation:

The way a concave mirror works is that since it's concave, the light bounces off of each other. a convex mirror, it curved the opposite, and the mirror has no way to bounce off of itself.


1. A 12 kilogram block is sitting on a platform 24 m high. How much Potential energy does
it contain?

Answers

The amount of potential energy the block contains is 2,822.4 Joules

Given the following data:

Mass of block = 12 kgHeight of platform = 24 meters.

We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex].

To determine the amount of potential energy the block contains:

Mathematically, potential energy (P.E) is given by the formula;

[tex]P.E = mgh[/tex]

Where:

m is the mass of object.g is the acceleration due to gravity.h is the height of an object.

Substituting the parameters into the formula, we have;

[tex]P.E = 12 \times 9.8 \times 24[/tex]

Potential energy (P.E) = 2,822.4 Joules

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When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of the balloon represent?

Answers

Answer:  When we use an analogy that represents the expanding universe with the surface of an expanding balloon, what does the inside of the balloon represent? The inside of the balloon does not represent any part of our universe.

A community plans to build a facility to convert solar radiation to electrical power. The community requires 1.00 MW of power, and the system to be installed has an efficiency of 30.0% (that is, 30.0% of the solar energy incident on the surface is converted to useful energy that can power the community). Assuming sunlight has a constant intensity of 1 000 W/m2, what must be the effective area of a perfectly absorbing surface used in such an installation?

Answers

We will find that the effective area that must be used to get the desired power is 3,333.33 m^2

The information we have is:

power needed = 1.00 MW = 1,000,000 watts

Energy of the Sun = 1,000 W/m^2

We know that the system has an efficiency of 30%, then per meter square, the energy converted is:

E = 0.3*1,000 W/m^2 = 300 W/m^2

Now we need to find the area (in meters squared) such that:

A*E  = 1,000,000 watts

A*(300 W/m^2) =  1,000,000 watts

A = (1,000,000 watts)/(300 W/m^2) = 3,333.33 m^2

So the effective area that must be used is A =  3,333.33 m^2

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A 5.77 kg object is tied to the end of a cord and whirled in a horizontal circle of radius 355 cm. The object completes 4.4 revolutions every 6.94E-3 hours. What is the centripetal force exerted on the object?

Answers

The centripetal force exerted on the object is 25.24 N.

The given parameters:

mass of the object, m = 5.77 kgradius of the circle, r = 355 cm = 3.55 mnumber of revolutions, N = 4.4 rev for 6.9 x 10⁻³ hours

The angular speed of the object is calculated as follows;

[tex]\omega = \frac{4.4 \ rev}{6.9 \times 10^{-3} \ h} \times \frac{1 \ h}{3600 \ s} \times \frac{2 \ \pi \ rad}{1 \ rev} = 1.11 \ rad/s[/tex]

The centripetal force exerted on the object is calculated as follows;

[tex]F =m \omega ^2 r\\\\F = 5.77 \times (1.11)^2 \times 3.55\\\\F = 25.24 \ N[/tex]

Thus, the centripetal force exerted on the object is 25.24 N.

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How are typhoons formed?
Need help! ​

Answers

Answer:

typhoon forms when winds blow into areas of the ocean where the water is warm. These winds collect moisture and rise, while colder air moves in below. This creates pressure, which causes the winds to move very quickly. The winds rotate, or spin, around a center called an eye.

A particular roller coaster has a mass of 3500 kg, a height of 4.0, and a velocity of 12m/s. What is the potential energy? If needed, use g=10.m/s^2

Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Gravitational Potential Energy of an object is calculated by formula ~

[tex] \large\boxed{\sf P = mgh}[/tex]

where,

m = mass of the object = 3500 kg

g = Acceleration due to gravity = 12 m/s²

h = height attained by the object = 4 m

Now, let's calculate its potential energy ~

[tex]3500 \times 10 \times 4[/tex]

[tex]140000 \: \: joules[/tex]

[tex]140 \: \: kj[/tex]

Answer:

Potential Energy of an object is calculated by formula:

Potential Energy (P.E)=m×g×h

Where,

m=mass of bodyg=acceleration due to gravityh=height from the earth surface

Now, let's solve the question.

Given,

mass(m)=3500 kgheight (h)=4mvelocity (v)=10m/s²

Now,

We know that,

Potential Energy (P.E)=mgh

[tex] = 3500 \times 10 \times 4[/tex]

[tex] = 3500 0\times 4[/tex]

[tex] =140000 joules [/tex]

[tex]\mathfrak{\blue{DisneyPrincess29}}[/tex]

Some houses are built with very thick walls. Explain how these walls help to keep the houses
warm in the winter.
Thicker walls provide more materal for .......
to travel through from the inside to outside, so the
is less, keeping the houses warmer.
(2 marks)

Answers

Answer:  It banks night-time cool to bring temperatures down in the day, and warms up over the course of the day and then releases the warmth at night. Thick walls or exposed solid floors can provide thermal mass. The shape of buildings matters too, and the orientation around each other so that the wind moves in particular ways. Hope this helps, tell me if I need to add anything. :))

When did the objects that we now see as asteroids and comets form in the solar system?.

Answers

Answer:

After solid particles condensed from the gas but before the planets finished forming

1
A pencil weighing 1N is sitting on a desk.
Write down all the forces on the desk.
a.
b.
Draw a free body diagram of the desk.
c.
Add up the forces in the x-direction (horizontal) and the y-direction (vertical)

Answers

The force diagram on the desk consists of normal reaction and weight of the pencil.

The net force on the desk in vertical direction is 1 N.

The net force on the desk in horizontal direction is 0.

The given parameters;

weight of the pencil, W = 1 N

The force diagram of the desk is sketched as follows;

                                             ↑ N

                                             ⊕

                                              ↓ W

Where;

N is the normal reaction on the deskW is the weight of the ball

The net force on the desk in vertical direction = 1 N

The net force on the desk in horizontal direction = 0

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Please help! Question is attached!​

Answers

Answer:

1. -6m/s

2. 0m/s

3. 3m/s

4.14.38N

5. 25.9 J

Explanation:

1. point A and C same height means velocity will be the same just in opposite direction,  = -6m/s

2. at max height vertical velocity is 0

3. same as point A

4. Weight is mg = 1.438*10 = 14.38N

5. total energy is KE+PE, which never changes

so TE = 32.4 and KE =6.5J then PE = 32.4-6.5 = 25.9 J

Football players boots have spikes at their sole

Give reason​

Answers

Answer:

it prevents slipping on the grass while playing

Answer:

to keep their grip on the ground so they won't fall

1. Explain why the energy of photoelectrons in XPS depends on energy of x-ray source, while energy of Auger electrons does not.

Answers

Answer:

Only part of the incident energy from an X-ray source may be used by the ejected electron (some of the energy can be used by the exiting photo electron and some of the energy by the exiting photon).

Auger electrons depend on the energy difference between energy levels of an atom and are fixed - so the ejected electron will have a fixed energy depending on the difference of energy levels of the atom. The Auger effect is called a "radiationless" transition because no radiation is detected outside of the atom.

If an object is rolling without slipping, how is the speed of its center related to its angular velocity

Answers

Angular velocity w is directly proportional to its velocity.

Speed of its center will be directly proportional to its angular velocity in the case of rolling without slipping

 

What is rolling without slipping ?

Rolling without slipping is a combination of translation and rotation where the point contact is instantaneously at rest.                                                                                                                                                                                                                                                                                                                                                                

When an object rolls without slipping on an inclined plane , then the velocity of the center of mass will be equal to angular velocity times radius that object.

Vo = angular velocity * radius

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are hotspots active vocanclos

Answers

Answer:

Yes

Explanation:

Thus, as a plate moves over the location of a plume eruption, it carries successively older volcanoes with it. As hotspot volcanoes are transported by plate motion away from the mantle plume, hotspot volcanism ceases. Eventually the hotspot volcanoes become extinct, gradually subside, and are eroded by wave action.

Have the best day! :D

Answer:

yes

Explanation:

Thus, as a plate moves over the location of a plume eruption, it carries successively older volcanoes with it. As hotspot volcanoes are transported by plate motion away from the mantle plume, hotspot volcanism ceases. Eventually the hotspot volcanoes become extinct, gradually subside, and are eroded by wave action.

hope this helps!

How do air particles move above a candle flame

Answers

It circulates. As warm air moves up, cooler air rushes in at the bottom of the flame. Once the cooler air is heated, it then rises up (like before) and is replaced by cooler air at the base of the flame.

The horizontal movement of air from an area of high pressure to an area of lower pressure

options:

wind


weather


heat


conduction

Answers

Answer:

Explanation:

A wind is the horizontal movement of air from an area of high pressure to an area of lower pressure. Winds are caused by differences in air pressure. Most differences in air pressure are caused by unequal heating of the atmosphere

An object with a mass of 3 kg has a momentum of 75 kg.m/s. What is its velocity?

Answers

Answer:

25m/s

Explanation:

p=mv

75 = 3v

v = 75/3

v = 25 m/s

If you want to verify your answer, just insert the value of v to the equation.

What is Kepler’s first law?

Answers

Answer:

Kepler's First Law: each planet's orbit about the Sun is an ellipse. The Sun's center is always located at one focus of the orbital ellipse. The Sun is at one focus. The planet follows the ellipse in its orbit, meaning that the planet to Sun distance is constantly changing as the planet goes around its orbit.

Answer:

Explanation:

Kepler 's first law - sometimes referred to as the law of ellipses - explains that planets are orbiting the sun in a path described as an ellipse. An ellipse can easily be constructed using a pencil, two tacks, a string, a sheet of paper and a piece of cardboard. Tack the sheet of paper to the cardboard using the two tacks.

HEEEEEELLLLLLLLPPPPPPPP!!!!!!!!!!

Answers

Answer:

True

True

False (Temperature measures the average kinetic energy of the particles in a substance. Thermal energy measures the total kinetic energy of the particles in a substance.)

False (is true only if both object have the same mass)

False (it's 100°)

True

True

True

True

False (Substances with a high specific heat require a lot of heat to have their temperature raised by one degree. On the other hand, substances with a low specific heat require a smaller amount of heat, like most metals)

A box with a weight of 20 newtons rest at a bottom of a ramp and is pushed to the end of the ramp with a force of 40 newtons. This ramp is an incline of 15 meters long. What is the maximum height of the ramp.

Answers

To move maximum height the friction force can be assumed to be

negligible.

The height of the ramp is 15 meters

Reasons:

The component of the weight acting on the incline, w = m·g·sin(θ)

Length of the ramp = 15 m

Potential energy of the box = 15 × sin(θ) ×20 = 300·sin(θ)

F × 15 = 300·sin(θ)

F = 20·sin(θ)

Work done by net force = Potential energy gained by the box

Work done by net force = (40 - 20·sin(θ)) × 15 = 300·sin(θ)

40 = 20·sin(θ) + 20·sin(θ) = 40·sin(θ)

sin(θ) = 1

θ = arcsin(1) = 90°

The ramp is at an inclination of 90°, therefore, the ramp is oriented vertically

The height of the ramp = The length of the ramp = 15 m

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Lina applies a constant force of 30 N as she pushes a dresser 3 m. How much work did Lina do on the dresser?​

Answers

Answer:

The answer will be 90

Explanation:

30N×3m= 90

helppppp T^T
......
plsssss​

Answers

The ruler's center of mass is located on the vertical line defined by the 50 cm mark.

Explain and give an example of inertia​

Answers

Answer:

Inertia regards objects staying in rest or in motion unless an outside force alters this.  An example would be kicking a soccer ball.  It was originally still (not moving) on the turf, until your kick altered this and set it into motion.  Similarly, the friction of the turf will alter this state of motion by eventually bring the ball to a complete stop.

boom :)

hope this helps!

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