a pulley is assumed massless and frictionless and rotates freely about its axle. the blocks have masses m1=40g and a block m2= 20g, and block m1 is pulled to the right by a horizontal force magnitude f=0.03n. find the magnitude of acceleration of a block m2 and the tension in the cord.....?

Answers

Answer 1

The magnitude of acceleration of a block m₂ is 0.05 m/s² and the tension in the cord is 0.01 N.

Given:

mass of block 1, m₁ = 40 gm = 40×10⁻³ kg

mass of block 2, m₂ = 20 gm = 20×10⁻³ kg

Applied force, F = 0.03 N

Calculation:

Consider the free-body diagram of the system as shown below. Using Newton's second law of motion we get:

F = ma

where F is the applied force

            m is the total mass of the system

            a is the acceleration of block 2 (as it is pulled by horizontal force)

From the above equation we get:

0.03 N = (m₁+m₂) a

⇒ a = (0.03 N) / (m₁+m₂)

⇒ a = (0.03 N) / (40×10⁻³ kg + 20×10⁻³ kg)

⇒ a = 0.5 m/s²

Now, from the free-body diagram of block 2 as shown in figure 3, we get:

Balancing the forces along the horizontal:

∑Fₓ = 0

∴ T = m₂ a

where T is tension in the string

           a is the acceleration of block 2

Applying values in the above equation we get:

T = (20×10⁻³ kg) × (0.5 m/s²)

  = 0.01 N

Therefore, the acceleration of block 2 due to the applied horizontal force is 0.5 m/s² and the tension in the cord is 0.01 N.

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A Pulley Is Assumed Massless And Frictionless And Rotates Freely About Its Axle. The Blocks Have Masses
A Pulley Is Assumed Massless And Frictionless And Rotates Freely About Its Axle. The Blocks Have Masses
A Pulley Is Assumed Massless And Frictionless And Rotates Freely About Its Axle. The Blocks Have Masses

Related Questions

20. Q: How long will it take for an apple falling from a 29.4m-tall tree to hit the ground?

A: 1.56 s
B: 2.04 s
C: 2.45 s
D: 3.72 s

Answers

Answer:

2.45s

Explanation:

is explanation needed too?

John is talking to his friend about painting a fence. He states that if he uses a roller brush he will cover the fence faster than if he uses a bristle brush. This is an example of a a. Law b. Belief c. Theory d. Hypothesis​

Answers

Answer:

b

Explanation:

What force is large enough to change the direction of a planet?
A. Gravity
B. Friction
C.Tension
D. Air Resistance

Answers

Answer:

Gravity

Explanation:

The more massive the object is, the higher the gravity

Hence, a massive star, like our sun, has enough gravity to pull on planets and keeping them in orbit

How is a rainbow formed?

Answers

Answer:

easy

Explanation:

it when the sunlight hits a rain droplets ,some of the light is reflected .The electromagnetic spectrum is made of light with many different wavelengths and each is reflected at a different angle . Thus spectrum is seperated producing a rainbow

________ occurs when a person is holding an object that is directly hit or splashed by lightning.

Answers

Contact injury happens when a person is holding an object that is directly hit or splashed by lightning.

To find answer, we need to know more about the lightning and injuries.

What are the injuries caused by lightning?The phenomenon of natural electrical discharge happens in a short time with a bright flash is called lightning.It carries a huge amount of energy.The injuries caused by lightning can be classified as Direct strikes, Side splash and the Contact injury.Direct injuries happens when a person directly hit by lightning.Side splash occurs when a current splashes from a nearby object.Contact injury happens when a person touching an object that is hit by lightning.

Thus, we can conclude that, contact injury occurs when a person is holding an object that is directly hit or splashed by lightning.

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When someone is holding something that has been struck or splashed by lightning, contact damage occurs.

We need additional information concerning lightning and injuries in order to identify the solution.

What types of injuries are brought on by lightning?Lightning is the name for a natural electrical discharge that occurs quickly and with a dazzling flash.It has a tremendous amount of energy.Lightning-related injuries can be divided into three categories: direct strikes, side splashes, and contact injuries.When someone is struck by lightning directly, they can get direct injury.When a current splashes from a neighboring object, it is called a side splash.When someone touches a lightning-hit object, contact harm results.

In light of this, we can say that contact injuries happen when a person is holding an object that has been struck by lightning or splashed by it.

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The pressure due to the atmosphere is very large, why are we not crushed?

Answers

Answer:

It is because of the blood pressure balances with our atmospheric pressure

A proton exits the cyclotron 1. 0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1. 0 ms ?.

Answers

The diameter of the largest orbit just before the protons exit the cyclotron is 39 cm.

The number of orbits completed by the proton during this 1.0 ms is 14000 revolutions.

The kinetic energy for the protons can be computed by using the formula:

   K.E = 1/2mv²

mv² = 2 K.E

v = sqrt( 2*KE / M)

the kinetic energy of the medical isotopes = 6.5 MeV

substituting the values,

v = sqrt( 2* 6.5* 1.6* 10^-13 / 1.67* 10^-27 )

v = 3.53 × 10⁷ m/s

The radius of the orbit can be estimated by using the formula:

mv² / R = qvB

r = q*v / mv²

r = ( 1.67* 10^-27 * 3.53 × 10⁷ ) / ( 1.9* 1.6* 10^-19 )

r = 0.19415 m

Since diameter (D) = 2r,

D= 2(0.19415  m)

D= 0.39 m

D≅ 39 cm

The time period to complete a revolution around the spiral trajectory is:

T = 2πr / v

T = 2*3.14* 0.1941 / 3.53*10^7

T = 0.7 × 10⁻⁷ s

Finally, the number of orbits that the proton does to complete the revolution in 1 ms is:

n = t / T

n = 10^-3 / (0.7*10^-7)

n = 14285.71

n ≅ 14000 revolutions

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Your question is incomplete, but most probably full question was:

A medical cyclotron used in the production of medical isotopes accelerates protons to 6.5 MeV. The magnetic field in the cyclotron is 1.9 T.

(a) What is the diameter of the largest orbit, just before the protons exit the cyclotron? Express your answer with the appropriate units. d = 57 cm Previous

(b) A proton exits the cyclotron 1.0 ms after starting its spiral trajectory in the center of the cyclotron. How many orbits does the proton complete during this 1.0 ms?

what is kinematics ?
explain ~

[tex] \\ \\ [/tex]
tysm! :)​

Answers

Answer:

Kinematics is the study of the motion of mechanical points, bodies and systems without consideration of their associated physical properties and the forces acting on them. The study is often referred to as the geometry of motion, and it models these motions mathematically using algebra

Answer:

the branch of mechanics concerned with the motion of objects without reference to the forces which cause the motion is kinematics

A velocity-time graph is shown below:

Answers

The average acceleration in the first 10 seconds of the journey is 2 m/s²; option B.

What is acceleration?

Acceleration is the rate of change of velocity with time.

Acceleration = change in velocity/time

From the graph;

Acceleration in first  seconds = 20 - 0/5 = 4 m/s²

Acceleration in second 5 seconds = 0

Average acceleration = 4 + 0/2

Average acceleration = 2 m/s²

In conclusion, average acceleration is the average of the final and initial acceleration.

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Two 5000-kg passenger cars roll without friction (one at 1 m/s, the other at 2 m/s) toward one another on a level track. They collide, couple, and roll away together with a combined momentum of

Answers

The combined momentum of the passengers is 5000 kgm/s.

Combined momentum of the passenger

The combined momentum of the passengers is calculated as follows;

P = mv1 + mv2

where;

m is mass of the passengersv1 is velocity of the first passengerv2 is velocity of the second passenger

P = m(v1 + v2)

P = 5000(-1 + 2)

P = 5000 kgm/s

Thus, the combined momentum of the passengers is 5000 kgm/s.

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A fireworks shell is accelerated from rest to a velocity of 60.0 m/s over a distance of 0.200 m. How long did the acceleration last

Answers

The acceleration lasted for 0.007s.

To find the answer, we need to know about the Newton's equation of motion.

What's the Newton's equation of motion that relates initial velocity, final velocity, acceleration, time and distance?

Newton's equations are

V²-U²= 2aSV²-U²= 2aSV= U+at

V= final velocity, U= initial velocity, a= acceleration, t= time and S = distance

What's the acceleration, if the fireshell is accelerated from rest to a velocity of 60.0 m/s over a distance of 0.200 m?Here, U= 0m/s, V= 60.0 m/s, S= 0.200 m

60²-0= 2a×0.2= 0.4a

a= 3600/0.4= 9000m/s²What's the time taken by the fireshell to achieve 60m/s with 9000m/s² acceleration from rest?Here, U= 0m/s, V = 60.0 m/s, a= 9000m/s²60= 0+9000tt= 60/9000= 0.007 s

Thus, we can conclude that the acceleration of the fireshell lasted for 0.007s.

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Based on illustrations of magnetic field lines, where could an object be placed so it would not experience a magnetic force

Answers

Halfway between the like poles of two magnets, because the field lines bend away and do not enter this area.

How does a magnetic field diagram show where the field is strongest?

The magnetic field lines do not ever cross. The lines include arrowheads to indicate the direction of the force exerted by a magnetic north pole. The closer the lines are to the poles, the stronger the magnetic field (thus the magnetic field from a bar magnet is highest closest to the poles).

Where is magnetic field the strongest and weakest on a magnet?

The bar magnet's magnetic field is strongest at its core and weakest between its two poles. The magnetic field lines are densest immediately outside the bar magnet and least dense in the core.

Which two locations on the magnet would have the greatest attractive forces?

Inside the magnet itself, the field lines run from the south pole to the north pole. The magnetic field is strongest in areas of greatest density of magnetic field lines, or areas of the greatest magnetic flux density.

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question is down below

Answers

The vertical components of velocity is 10.35 m/s and the horizontal component of velocity is 38.6 m/s

What are the components of velocity?

We know that velocity is a vector quantity, a vector often can be resolved into its components. The vertical components is V sinθ while the horizontal component is vcosθ.

Hence;

Vertical component = 40 m/s sin 15 degrees = 10.35 m/s

Horizontal component = 40 cos 15 degrees = 38.6 m/s

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Which type of galaxy is likely to contain only o-spectral type stars?

Answers

The answer is Spiral

When operating an aircraft at cabin pressure altitudes above 12,500 feet msl up to and including 14,000 feet msl, supplemental oxygen shall be used during?

Answers

Supplemental oxygen shall be used in that flight time in excess of 30 minutes at those altitudes.

Most plane cabins are pressurized to 8,000 feet above sea level, an altitude that lowers the amount of oxygen inside the blood by approximately 4 percentage points, researchers say.

The higher the altitude, the less oxygen there is in the air and the lower the overall air pressure is. If flights were not pressurized, passengers could be prone to various physiological illnesses. Because of this, federal policies require that all commercial flights over 8,000 feet be pressurized.

The flight crew must use supplemental oxygen for the entire duration of flight operations above a cabin pressure altitude of 14,000 feet MSL.

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What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10^4v ?

Answers

What is the strength of the electric field between two parallel conducting plates separated by 1.00 cm and having a potential difference (voltage) between them of 1.50×10^4v ?

An engine has an input of heat energy of 10,750 J and does 2,420 J of work. Which of the following is the heat loss?
Group of answer choices

a. 13,200 J

b. 8,330 J

c. 4.44 J

c. 0.225 J

Answers

B. The heat loss by the heat engine is 8,330 J.

Heat loss by the heat engine

The heat loss by the heat engine is calculated as follows;

H = E - W

where;

H is heat lossE is input energyW is work done

H = 10,750 J - 2,420 J

H = 8,330 J

Thus, the heat loss by the heat engine is 8,330 J.

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How much power will be required to force a current of 4.13 amps to flow through a conductor whose resistance is 113 ohms? Use two decimals for your answer. Round your answer to two decimals.

Answers

The power required to force the current of 4.13 A to flow through the conductor is 1927.43 watts

What is power?

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = square current (I²)× resistancet (R)

P = I²R

How to determine the powerCurrent (I) = 4.13 AResistance (R) = 113 ohmsPower (P) =?

P = I²R

P = 4.13² × 113

P = 1927.43 watts

Thus, the power required is 1927.43 watts

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A certain frictionless simple pendulum having a length l and mass m swings with period t. If both l and m are doubled, what is the new period?.

Answers

If l and m both are doubled then the period becomes √2*T

what is a simple pendulum?

It is the one which can be considered to be a point mass suspended from a string or rod of negligible mass.

A pendulum is a weight suspended from a pivot so that it can swing freely.

Here,

A certain frictionless simple pendulum having a length l and mass m

mass of pendulum = m

length of the pendulum = l

The period of simple pendulum is:

[tex]T = 2\pi \sqrt{\frac{l}{g} }[/tex]

Where k is the constant.

Now the length and mass are doubled,

m' = 2m

l' = 2l

[tex]T' = 2\pi \sqrt{\frac{2l}{g} }[/tex]

[tex]T' = \sqrt{2}* 2\pi \sqrt{\frac{l}{g} }[/tex]

[tex]T' = \sqrt{2} * T[/tex]

Hence,

If l and m both are doubled then the period becomes √2*T

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A mountain skier has begun descending the 30o slope. if the coefficient of kinetic friction is 0.10, what is her acceleration?

Answers

The acceleration of the body is found to be -4.05 m/s^2

What is the acceleration?

We define the acceleration as the rate of change of the velocity with time. Hence, we can write that;

a = (μcosθ - sinθ)g

a = acceleration

μ = coefficient of kinetic friction

θ = angle of inclination

g = acceleration due to gravity

Thus;

a = (0.10cos 30 - sin 30) 9.8

a = -4.05 m/s^2

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Rank in order, from largest to smallest, the magnitudes of the momentum p1x through p5x of the objects presented in (Figure 1). Rank the magnitudes of the momentum from largest to smallest. To rank items as equivalent, overlap them.

Answers

The decreasing order of the momenta are b>a=d=e>c.

What is Momentum?Momentum is the result of a particle's mass and velocity. Being a vector quantity, momentum possesses both magnitude and direction.According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.According to Newton's second law, if a particle is subjected to a constant force for a specific amount of time, the result of the force and time (referred to as the impulse) is equal to the change in momentum. On the other hand, a particle's momentum represents the length of time needed for a consistent force to bring it to rest.

Solution: The momentum of all the options are mentioned below according to the formula:

a. p = 20 × 1 = 20gm/s

b. p = 20 × 2 = 40gm/s

c. p =10 × 1 = 10gm/s

d. p = 10 × 2 = 20 gm/s

e. p =200 × 0.1 = 20gm/s

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Question:

I hope you are trying to ask the question below:

Rank in order, from largest to smallest, the momenta a to e of the objects

a. 20 g & 1 m/s

b. 20 g & 2 m/s

c. 10 g & 1 m/s

d. 10 g & 2 m/s

e. 200 g & 0.1 m/s

The image above shows a crash test dummie's head traveling at -1.005 m/s while striking a headrest from a car traveling 4.524 m/s with a mass of 2005.6 kg. If the crash test dummie's head head bounces off the headrest with a 9.965 m/s and the car continues traveling at 4.487 m/s, calculate the mass of the crash test dummie's head?

Answer:

Answers

From the calculation, the mass of the dummies head is 1647.44 Kg

What is the mass of the crash test dummies head?

We know that the momentum after collision is equal to the momentum before collision.

Mass of the headrest = 2005.6 kg

Initial velocity of the head rest = 4.524 m/s

Final velocity of the head rest =  4.487 m/s

Mass of the dummy = m

Initial velocity of the dummy = -1.005 m/s

Final velocity of the dummy = 9.965 m/s

Then;

(m *  -1.005) + (2005.6 * 4.524 ) = (2005.6 *   4.487) + (m * 9.965)

-1.005m + 9073.33 = 8999.13 + 9.965m

9073.33 - 8999.13  = 9.965m + 1.005m

18072.46 = 10.97m

m = 18072.46/ 10.97

m = 1647.44 Kg

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Although centuries ago, astronomers thought that a nova was a new star, appearing for the first time in the heavens, today we know that it is:

Answers

Astronomers thought that a nova was a new star, appearing for the first time in the heavens, today we know that it is as a binary star system.

What is the binary star system about?

A binary star system is known to be one where one star is known to be called a white dwarf and there is a mass that is said to be transferred to it

A binary star is known to be a kind of a system that is composed of two stars that are known to be gravitationally held together to and in orbit near each other.

Note that Binary stars in the night sky are ones that are often seen as a single object and thus Astronomers thought that a nova was a new star, appearing for the first time in the heavens, today we know that it is as a binary star system.

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A kettle transfers 6,000j of energy electrically. 1,500j of this is wasted. what is the efficiency of this kettle?

Answers

Answer:75 percent

Explanation:so in order tro fin d thge efficiency i used the forumla ,efficency=useful output energy/input energyx100%,in order to use this formula i needed the output,which i found by subtracting the input energy with wasted energy,that gave me the output,and after founding the output,i put that into the formula,

output energy=input energy - wasted energy

output energy=6000j-1500j

output energy=4500

put that into the formula

efficiency =output energy/input enrgy x100%

efficiency=4500/6000 multiplied by 100%

efficiency=0.75x100%

efficiency=75%

Your best friend weighs 81.5 kg and is a rugby player. In one of his games, he slides to a stop in a phenomenal manner. The coefficient of kinetic friction between the player and the ground is 0.70. His speed at the start of the slide is 8.23 m/s. I a) Calculate his acceleration during the slide. b) How long (in time) does he slide until he stops?​

Answers

A. The acceleration during the slide is 6.86 m/s²

B. The time taken to slide until he stops is 1.2 s

How to determine the force of frictionMass (m) = 81.5 KgCoefficient of friction (μ) = 0.7Acceleration due to gravity (g) = 9.8 m/s²Normal reaction (N) = mg = 81.5 × 9.8 = 798.7 NFrictional force (F) =?

F = μN

F = 0.7 × 798.7

F = 559.09 N

A. How to determine the accelerationMass (m) = 81.5 KgFrictional force (F) = 559.09 NAcceleration (a) =?

a = F / m

a = 559.09 / 81.5

a = 6.86 m/

B. How to determine the time Initial velocity (u) = 8.23 m/sFinal velocity (v) = 0 m/sDecceleration (a) = -6.86 m/s²Time (t) =?

a = (v – u) / t

t = (v – u) / a

t = (0 – 8.23) / -6.86

t = 1.2 s

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A 15.2 kg mass has a gravitational potential energy of -342 J. How high from the ground is it? Group of answer choices GPE cannot be negative 2.3 m 22.5 m 530 m

Answers

A. The height above the ground reached by the mass is 2.3 m.

Height traveled by the mass

P.E = mgh

where;

m is mass h is height reached by the objectg is acceleration due to gravity

h = P.E/mg

h = (342)/(15.2 x 9.8)

h = 2.3 m

Thus, the height above the ground reached by the mass is 2.3 m.

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in the photoelectric effect a photon with an energy of 5.3 * 10^-19 J strikes an electron in a metal

Answers

The velocity of the photo electron is 6.11 × 105 ms

Given :

Supplied energy, Es = 5.3 x 10-19 J

Minimum energy of the electron to escape from the metal, E. = 3.6 x 10-19 J

To Find :

Velocity of photoelectron

Solution : The energy supplied by the photon is equal to the sum of minimum escape energy and the kinetic energy of the escaping electron. So

5.3 × 10^-19 J = 3.6 × 10^-19 J + K

K = 5.3 x 10^-19 - 3.6 x 10^-19

K = 1.7 × 10^-19 J

The formula of kinetic energy is given by:

K = 1/2 mv^2

v = √2K/m

= √2 x 1.7 x 10^-19

√ 9.1 x 10^-31

v = 6.11 x 10^5 m/s

So, the velocity of the photo electron is 6.11 x 10^5 m/s

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A 10 kg box initially at rest is pulled with a 50 N horizontal force for 4 m across a level surface. The force of friction acting on the box is a constant 20 N. How much work is done by the 50 N force?

Answers

The work is done by the 50 N force is 200 J.

Work done by the 50 N force

Work done = Fd

where;

F is Force applied d is the displacement of the object

Work done = 50 N x 4 m = 200 J

Thus, the work is done by the 50 N force is 200 J.

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1. A 500 g piece of silver at 250°C is submerged in 1000 g of water at 5°C to be cooled. Determine the
final temperature of the silver and water. Given Cwater = 4180 J/kg°C and Csilver = 240 J/kg°C.

Answers

Taking into account the definition of calorimetry,  the final temperature of the silver and water is 11.84 °C.

Calorimetry

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m. c is the specific heat substance. ΔT is the temperature variation.

Final temperature of the silver and water

In this case, you know:

For silver:Mass of silver= 500 g= 0.5 kg (being 1000 g= 1 kg)Initial temperature of silver= 250 °CFinal temperature of silver= ?Specific heat of silver= 240 [tex]\frac{J}{kgC}[/tex] For water:Mass of water = 1000 g= 1 kgInitial temperature of water= 5 ºCFinal temperature of water= ?Specific heat of water = 4180 [tex]\frac{J}{kgC}[/tex]

Replacing in the expression to calculate heat exchanges:

For silver: Qsilver= 240 [tex]\frac{J}{kgC}[/tex]× 0.5 kg× (Final temperature of silver - 250 C)

For water: Qwater= 4180 [tex]\frac{J}{kgC}[/tex] × 1 kg× (Final temperature of water - 5 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the silver gives up will be equal to the heat that the water receives. Therefore:

- Qsilver = + Qwater

And the final temperature of the silver is equal to the temperature of the water (Final temperature of silver= Final temperature of water= Final temperature). Then:

- 240 [tex]\frac{J}{kgC}[/tex]× 0.5 kg× (Final temperature - 250 C)= 4180 [tex]\frac{J}{kgC}[/tex] × 1 kg× (Final temperature - 5 C)

Solving:

- 120 [tex]\frac{J}{C}[/tex]× (Final temperature - 250 C)= 4180 [tex]\frac{J}{C}[/tex]× (Final temperature - 5 C)

120 [tex]\frac{J}{C}[/tex]× (250 C - Final temperature) = 4180 [tex]\frac{J}{C}[/tex]× (Final temperature - 5 C)

120 [tex]\frac{J}{C}[/tex]×250 C - 120 [tex]\frac{J}{C}[/tex]×Final temperature = 4180 [tex]\frac{J}{C}[/tex]×Final temperature - 4180 [tex]\frac{J}{C}[/tex]×5 C

30,000 J - 120 [tex]\frac{J}{C}[/tex]×Final temperature = 4180 [tex]\frac{J}{C}[/tex]×Final temperature - 20,900 J

50,900 J= 4300 [tex]\frac{J}{C}[/tex]×Final temperature

50,900 J÷ 4300 [tex]\frac{J}{C}[/tex]= Final temperature

11.84 °C= Final temperature

Finally,  the final temperature of the silver and water is 11.84 °C.

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As the electric potential near the ground increases during a thunderstorm, a positive charge current can move up pointed objects, such as masts of ships, producing a luminous halo or glow known as ____.

Answers

Answer:

St. Elmo's Fire - well known to old time sailors

Other Questions
Discuss the narrative descriptions in thischapter. Even though they are just waitingand hiding, what words and phrases helpmake the scene so suspenseful? Discussthe emotional effect each description has. Maze Runner Read the poem.A Poison Treeby William BlakeI was angry with my friend:I told my wrath, my wrath did end.I was angry with my foe:I told it not, my wrath did grow.And I watered it in fearsNight and morning with my tears,And I sunned it with smilesAnd with soft deceitful wiles.And it grew both day and night,Till it bore an apple bright,And my foe beheld it shine,And he knew that it was mine,And into my garden stoleWhen the night had veiled the pole;In the morning, glad, I seeMy foe outstretched beneath the tree.Read these lines from the second stanza from "A Poison Tree."And I sunned it with smilesAnd with soft deceitful wiles.What is the meaning of the figurative language in these lines? A. Being in the sunshine makes the speaker's wrath worse. B. The speaker's soft, deceitful wiles help to lessen his wrath. C. Smiling makes the speaker forget his wrath. D. The speaker covers up his wrath with lies and smiles. What is information that CANNOT be measured and expressed in numbers? Question 1 options: Personal Information Target Market Data Qualitative data Quantitative data The Statue of Liberty changing from Copper to Green is an example of... Group of answer choicesA: Temperature ChangeB: Gas FormationC: Color ChangeD: Precipitate i need ur help guys please. 50 pts Consider points a, b, and c in the graph. Determine which of these points is relative minima on the interval x = 1 and x = 2 in the graph.Options:1.)B2.)A and B3.)C4.)A What are the half lives for uranium-235 and uranium-238?a.The half-life of uranium-235 is 713 seconds, the half-life of uranium-238 is 4.5 minutesc.The half-life of uranium-235 is 713,000,000 years, the half-life of uranium-238 is 4,500,000,000 yearsb.The half-life of uranium-235 is 713 days, the half-life of uranium-238 is 450 daysd.None of the above The astronaut's ears hurt from the loud explosion that happened outside of the space station. Is this statement scientifically possible? help will give brainliest Represente en nmeros romanos, los aos que han transcurrido desde la Declaracin de Independencia hasta nuestros das. Neeed help please... Line AB is definited by the equation ax+by=c where a=0, b=1, and c=-2 graph line AB Were the penalties (punishment ) for crimes in a ancient Babylonia harsher than today ? ( PLS HELP ME ) Find the value of x.3015xA. 4B. 10C. 12D. 2 A proud new Jaguar owner drives her car at a speed of 35 m/s into a corner. The coefficients of friction between the road and the tires are 0.70 (static) and 0.40 (kinetic). What is the minimum radius of curvature for the corner in order for the car not to skid Which diagram best shows how the actions of the British government helped lead to the creation of the Constitution? Cause Effect led to A. British soldiers could search colonists' homes. The Fourth Amendment says the government cannot search people's homes without cause. Cause Effect led to B. The British government collected taxes from the colonists The Constitution prevents the federal government from collecting taxes. Cause Effect led to Colonists were forced to house British soldiers. The Constitution prevents the existence of a standing army Cause Effect led to D. British Parliament did not include any colonial representatives The Constitution outlaws trade with the British. E PREVIOUS 25. estarUsteden Paris. 6. PART B: Which quote from the text best supports theanswer to Part A?OA "These emotions can transform into behaviors thatmay lead you to avoid situations or into defensemechanisms that may obscure the recognition ofreality, and consequently they have beenunderstood as keys to the dynamics of emotionalillness" ( Paragraph 1)OB anxiety is a general state of distress that is longerlasting than fear and usually is triggered bysomething that is not specific, even though itproduces physiological arousal, such as nervousnessand apprehension" ( Paragraph 3)OC "Thus, the presence of avoidance behaviors wouldindicate fear, in contrast to anxiety where a personmay be very much on the alert but does not avoidthe situation." ( Paragraph 3)OD "where anxiety is foreboding and puts you on alertto a future threat, fear immediately leads to an urgeto defend yourself with escape from an impendingdisaster" ( Paragraph 3) Mon ami est comedein que j'ai vule mieuxle moins bienle meilleurle plus bien On January 1, 2021, Teal Corp. had 502,000 shares of common stock outstanding. During 2021, it had the following transactions that affected the Common Stock account. February 1 Issued 125,000 shares March 1 Issued a 10% stock dividend May 1 Acquired 98,000 shares of treasury stock June 1 Issued a 3-for-1 stock split October 1 Reissued 58,000 shares of treasury stockThe weighted-average number of shares outstanding. Assume that Indigo Corp. earned net income of $3,605,000 during 2021. In addition, it had 104,000 shares of 9%, $100 par nonconvertible, noncumulative preferred stock outstanding for the entire year. Because of liquidity considerations, however, the company did not declare and pay a preferred dividend in 2021. Compute earnings per share for 2018, using the weighted-average number of shares. Assume that Indigo Corp. earned net income of $3,605,000 during 2021. In addition, it had 104,000 shares of 9%, $100 par nonconvertible, noncumulative preferred stock outstanding for the entire year. Because of liquidity considerations, however, the company did not declare and pay a preferred dividend in 2021. Compute earnings per share for 2018, using the weighted-average number of shares determined in part (a).