A reaction of 58.1 g of Na and 54.9 g of Br2 yields 67.8 g of NaBr . What is the percent yield?

Explanation:

s=2

p=6

d=10

f=14

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Answer:

The answer is B

Explanation:

The area surrounding the nucleus is called the electron cloud which holds the electrons, so with the power of deduction its B. 0-0

Answer:

2.83 grams NaHCO₃ in the 4.25g Sample.

Explanation:

Given 4.25g Sample is 66.5% NaHCO₃

=> mass of NaHCO₃ = 0.665(4.25g) =2.83grams NaHCO₃.

The mass of NaHCO₃ in 4.25 g of the sample is 2.83 g

From the question given above, the following data were obtained:

Mass of sample = 4.25 g

Percentage by mass of NaHCO₃ = 66.5%

[tex]Percentage = \frac{mass of substance}{total mass} X 100[/tex]

66.5% = [tex]\frac{Mass of NaHCO_{3} }{4.25}\\\\[/tex]

Cross multiply

Mass of NaHCO₃ = 66.5% × 4.25

Mass of NaHCO₃ = 0.665 × 4.25

Therefore, the mass of NaHCO₃ in 4.25 g of the sample is 2.83 g

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Answer:

A protein is just a long chain of amino acids. So, one could say that the monomer of a protein is an amino acid. Here is a diagram of a protein and amino acid for reference:

Since lighter molecules are moving faster, they escape from an atmosphere more often than more massive ones.

The escape velocity is the velocity that an object must be given in order to escape from the gravitational field of the earth. We must know that a less massive molecule moves faster than a more massive molecule.

Hence, less massive molecules tend to escape from an atmosphere more often than more massive ones because they are moving faster.

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when a circuit is open the electricity fails to pass through any of the wire causing all the lights to go out. If the lights are in a straight line each light is on its own circuit to the power source.

Answer:

(I). The gases are present at the end of the experiment  are O₂ and NO₂

(II).  The pressure of O₂ is 0.158 atm.

The pressure of NO₂ is 0.681 atm

The Pressure of NO is zero.

Explanation:

Given that,

Volume of large bulb = 6.00 L

Pressure = 0.850 atm

Volume of small bulb = 1.50 L

Pressure = 2.50 atm

Temperature = 22°C = 295 K

We need to calculate the moles in NO

Using formula of moles

[tex]n=\dfrac{PV}{RT}[/tex]

Put the value into the formula

[tex]n=\dfrac{0.850\times6.00}{0.0821\times295}[/tex]

[tex]n=0.211\ moles[/tex]

We need to calculate the moles in O

Using formula of moles

[tex]n=\dfrac{PV}{RT}[/tex]

Put the value into the formula

[tex]n=\dfrac{2.50\times1.50}{0.0821\times295}[/tex]

[tex]n=0.155\ moles[/tex]

The balance equation for the reaction is

[tex]2NO+O_{2}\Rightarrow 2NO_{2}[/tex]

So, The gases are present at the end of the experiment  are O₂ and NO₂

We need to calculate the remaining moles of O₂

Using formula for remaining moles

Moles of  O₂ remaining = [tex]0.155-\dfrac{0.211}{2}[/tex]

[tex]Moles\ of \ O_{2}\ remaining =0.049\ moles[/tex]

Moles of NO₂ = 0.211 moles

Total volume [tex]V=V_{l}+V_{s}[/tex]

Put the value into the formula

[tex]V=6.00+1.50[/tex]

[tex]V=7.5\ V[/tex]

(2). If the gas was consumed completely

We need to calculate the pressure of O₂

Using formula of pressure

[tex]P=\dfrac{moles\times R\times T}{V}[/tex]

Put the value into the formula

[tex]P=\dfrac{0.049\times0.0821\times295}{7.5}[/tex]

[tex]P=0.158\ atm[/tex]

We need to calculate the pressure of NO₂

Using formula of pressure

[tex]P=\dfrac{moles\times R\times T}{V}[/tex]

Put the value into the formula

[tex]P=\dfrac{0.211\times0.0821\times295}{7.5}[/tex]

[tex]P=0.681\ atm[/tex]

If the gas was consumed completely

Then, Pressure of NO is zero.

Hence, (I). The gases are present at the end of the experiment  are O₂ and NO₂

(II).  The pressure of O₂ is 0.158 atm.

The pressure of NO₂ is 0.681 atm

The Pressure of NO is zero.

The gases that remained at the end of the experiment are nitrogen dioxide and nitric oxide. The partial pressure of nitric oxide has been 0.43 atm, nitrogen dioxide has been 1 atm, and oxygen has been 0 atm.

The balanced chemical equation has been given that, 2 moles of NO reacts completely with 1 mole of oxygen.

(1) According to the ideal gas equation:

PV nRT

n = [tex]\rm \dfrac{PV}{RT}[/tex]

NO = [tex]\rm \dfrac{0.850\;atm\;\times\;6\;L}{0.0821\;L.atm/mol.K\;\times\;295\;K}[/tex]

Moles of NO = 0.211 moles

Oxygen = [tex]\rm \dfrac{2.50\;atm\;\times\;1.50\;L}{0.0821\;L.atm/mol.K\;\times\;295\;K}[/tex]

Moles of oxygen = 0.155 moles.

For 2 moles NO, 1 mole oxygen is used.

For 0.211 moles, Oxygen has been 0.422 moles.

The oxygen has been in a lesser quantity than requires, thus it has been the limiting reactant.

The gas that presents at the end of the reaction has been NO.

(2) The pressure of the gas has been calculated as:

After the complete consumption of the gas, NO remaining has been:

2 moles oxygen = 1 moles NO

0.155 moles oxygen = 0.0775 moles NO.

The moles of NO remaining = 0.211 - 0.0775 mol

The moles of NO remaining = 0.1335 mol.

The total volume of the solution will be 6 + 1.5 L = 7.5 L.

The moles of Nitrogen dioxide formed :

1 mole oxygen = 2 moles Nitric oxide

0.155 moles oxygen = 0.31 moles nitric oxide.

The partial pressure can be given by:

P = [tex]\rm \dfrac{nRT}{V}[/tex]

Pressure of NO = [tex]\rm \dfrac{0.1335\;\times\;0.08206\;\times\;295}{7.5}[/tex]

Pressure of NO = 0.43 atm.

The pressure of Nitrogen dioxide:

Pressure of nitrogen dioxide = [tex]\rm \dfrac{0.31\;\times\;0.08206\;\times\;295}{7.5}[/tex]

Pressure of nitrogen dioxide = 1.00 atm.

The gases that remained at the end of the experiment are nitrogen dioxide and nitric oxide. The partial pressure of nitric oxide has been 0.43 atm, nitrogen dioxide has been 1 atm, and oxygen has been 0 atm.

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ethane is the compound of the answer you are asking help

Answer:

The pH of a solution with [H+] = 2.3 x 10^-3 is 2.64.

Explanation:

Answer:

it defuse at a rate of 0.0002 m/s

Xenons at the same temperature, will effuse the slowest

The effusion rates is said to be inversely proportional to the square root of the molecular masses of the gases.

At a set temperature, the average kinetic energy of all gaseous molecules is always equal.

Hydrogen gas has the lowest mass out of these gases, it will have the highest average velocity and as such, that it will exit out of the tiny hole at a rate faster than the other gases.

Conclusively, The rate of effusion for a gas is inversely proportional to the square-root of its molecular mass, this is Graham's Law.

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Answer: Bromine

Explanation: The rate of effusion is inversely proportional to the molar mass. Bromine (Br2) has a the highest molar mass of this group, and will therefore be the slowest

Explanation:

a is the answer ok write it easily bye

The correct name of the structure given in the question is 1–bromo–3–chloro benzene (Option A)

The naming of organic compounds follows the standard of the international union of pure and applied chemistry (IUPAC).

To name a compound, we must

Complete question

See attached photo

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Answer:

thermal; coolant

Explanation:

A refrigerator transfers thermal energy from the cool air inside the refrigerator to the warm air in the kitchen. I hope this helps! ^-^

Answer:

PH₃.

Explanation:

Hello.

In this case, among the options:

PH₃, GaF₃, SF₂ and CO₂

We compute their molar masses by adding the atomic masses of the constituting elements by their subscripts:

[tex]M_{PH_3}=m_P+3*m_H=30.97+3*1.01=34.00g/mol\\\\M_{GaF_3}=m_{Ga}+3*m_F=69.72+3*19.00=126.72g/mol\\\\M_{SF_2}=m_{S}+2*m_F=32.07+2*19.00=70.07g/mol\\\\M_{CO_2}=m_{C}+2*m_O=12.01+2*16.00=44.01g/mol[/tex]

Thus, the answer is PH₃.

Best regards.

The convergence of two oceanic plates can give rise to deep sea trenches, island arcs, and tall folded mountains, each of which is a distinctive geological feature resulting from the complex interplay of subduction, volcanic activity, and crustal compression. options A,C and D are correct.

When two oceanic plates converge, several geological features can develop as a result of the collision. One common feature is the formation of deep sea trenches. As the denser oceanic plate subducts beneath the other plate, it creates a deep trench in the ocean floor. The subduction process leads to the downward bending of the oceanic plate, forming a trench that can extend for hundreds or thousands of kilometers.

Another feature that can develop is the formation of island arcs. As the subducting oceanic plate sinks into the mantle, it releases water and volatiles, which cause the overlying mantle to melt. This molten material rises through the Earth's crust, creating a chain of volcanic islands known as an island arc. These islands are often characterized by active volcanism and can be seen in regions such as the Pacific Ring of Fire.

Additionally, the convergence of two oceanic plates can result in the formation of tall folded mountains. As the leading edge of one plate is compressed and pushed upwards, it forms a range of folded mountains. The collision and compression forces can cause the sedimentary layers to buckle and fold, leading to the creation of prominent mountain ranges. options A,C and D are correct.

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Answer:

35ml

Explanation:

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Answer:

Hi...... I have this same question............

Biologists and other scientists use the scientific method to ask questions about. When possible, scientists test their hypotheses using controlled experiments. Test a hypothesis by making predictions about patterns that should be seen in. This variable is independent because it does not depend on what happens in the.

Explanation:

Answer:

the amount of matter in an object

The required volume of sodium hydroxide is 15 mL.

The term concentration refers to the amount of substance present. It is the quotient of the number of moles and volume of solution.

We have the reaction; 2HCl(aq) → CaCl2(aq) + H2O(l) + CO2(g)

Number of moles of CaCO3 = 0.205 g / 100.1 g/mol = 0.0020 moles

Number of moles of HCl = 2.00 M * 7.50/1000 = 0.015 moles

Since 2 moles of HCl reacts with 1 mole of CaCO3

x moles of HCl reacts with 0.0020 moles

x = 0.004 moles of HCl

This means that HCl is in excess by the amount 0.011 moles.

Now consider the reaction; NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq)

Concentration of HCl = 0.011 moles/0.125L = 0.088 M

From;

CAVA/CBVB = na/nb

CAVAnb = CBVBna

VB = CAVAnb/CBna

VB = 0.088 M * 10mL * 1/0.058 M * 1

VB = 15 mL

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A 5.0g sample of O₂ is in a container at STP, then the volume of the container is 3.49 L.

Volume of oxygen sample at STP will be calculated by using the ideal gas equation as:
PV = nRT, where

P = pressure = 1 atm

V = volume of gas = ?

R = universal gas constant = 0.082 L.atm/K.mol

T = temperature = 273K

n is the moles of oxygen sample and it will be calculated as:
n = W/M, where

W = given mass = 5g

M = molar mass of O₂ = 32g/mol

n = 5/32 = 0.156 moles

On putting all values on above equation, we get

V = (0.156)(0.082)(273) / (1)

V = 3.49 L

Hence required volume of gas sample is 3.49 L.

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Answer:

3

helium

Explanation:

Among all the given options, the correct option is option 3. An element that is considered to be unreactive because it has a filled outer energy level is helium.

Any compound that cannot be broken down into simpler chemicals by regular chemical processes is referred to as a chemical element or element. The building blocks of which every matter is made are called elements.

There are 118 chemical elements that are currently recognized. About 20% of them have only been created synthetically in the lab and are only known because they do never exist in nature or are only present in trace levels. An element that is considered to be unreactive because it has a filled outer energy level is helium.

Therefore, among all the given options, the correct option is option 3.

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Explanation:

1) Find the reaction quotient:

Qc = [I]² / [I₂]

Plug in the Kc value and the I₂ concentration.

Q = [2.0×10⁻⁸]² / (0.020)

Q = 2.0×10⁻¹⁴

Since Qc < Kc, the reaction moves to the right (favors the products).

2) Find the reaction quotient:

Qc = [CO₂] [H₂] / ([CO] [H₂O])

Qc = (15) (15) / ((1.0) (1.0))

Qc = 225

Since Qc > Kc, the reaction moves to the left (favors the reactants).

Answer:

An electrolyte is medium containing ions that is electrically conducting through the movement but not conducting electrons . Strong electrolytes are electrolytes that completely ionizes in a solution . Weak electrolytes that partially ionize in a solution .

Explanation:

Strong electrolytes fully dissociate In a solution such as NH4Cl , KOH(Potassium hydroxide) and HCl ( Hydrochloric acid)

Weak electrolytes partially dissociate In a solution such as HC2H3O2 (acetic acid), H2CO3 (carbonic acid), NH3 (ammonia), and H3PO4 (phosphoric acid) .

Answer:

Explanation:

By Ideal Gas Law, P1*V1 / T1 = P2*V2 / T2

So new pressure = (P1*V1 / T1) / (V2 / T2)

= P1*V1*T2 / T1*V2

= 800*3.6*298 / 250*1.8

= 1907.2 mmHg

Apply combine gas law

[tex]\\ \rm\Rrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}[/tex]

[tex]\\ \rm\Rrightarrow P2=\dfrac{P1V1T2}{V2T1}[/tex]

[tex]\\ \rm\Rrightarrow P2=\dfrac{800(3.6)(250)}{1.8(298)}[/tex]

[tex]\\ \rm\Rrightarrow P2=720000/536.4[/tex]

[tex]\\ \rm\Rrightarrow P2=1341.7 mmHg[/tex]

The purpose of shaking the petroleum ether-ethanol extract of the leaves with water in a separator funnel is that the shaking process will increase the surface area which is in contact between the two liquids and will allow the equilibrium to be established more rapidly.

This shaking process of petroleum ether-ethanol extract of the leaves with water in a separator funnel form layers of separation.

Shaking the separatory funnel allows the two solvents to mix and provides the opportunity for components dissolved in one of the solvents to be transferred to the other solvent.

Ether extraction is mainly used in the determination of Uranyl nitrate which is also known as Uranium.

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Answer:

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume = 381 mL = 381 cm³

density = 1.11 g/cm³

So we have

mass = 1.11 × 381

We have the final answer as

Hope this helps you

Explanation:

from internet

the act of transferring pollen grains from the male anther of a flower to the female stigma

Answer:

transfer of pollen from anther to stigma.

Explanation:

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